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  • Custom Display Form with Custom Workflow button

    - by Ifi
    I have created a new custom list form that will show 4 fields on the page from a Custom List called "Shipment". I have added Form Action button that I would like to run a custom action that is set inside of a Workflow. Currently, the form displays the fields for "Manifest Number", "Pickup Location", "Delivery Location", & "Scheduled Pickup Time". When the user clicks the Form Action button, what I want the Workflow to do is go to the ID field of the displayed content in the Form and change the value of the "Picked Up" column from No to Yes. The problem I am having is passing the ID of the displayed information from the Form to the Workflow as a variable. I can get the "Picked Up" column to update if I specify the value in the "Update List Item" window under the "Find the List Item" section, but I cannot figure out how to do this dynamically from the Form

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  • Cakephp 1.3 Form Alignment?

    - by Sham Ali
    Hi Fellwos i am new at cakephp 1.3, i am trying to create a Edit User Form with Form Helper in Cakephp 1.3. i am unable to make a customize alignments of the form elements. for example echo $this-Form-create('Model', array('action' = 'edit_users','id' = 'UserForm')); echo $this-Form-input('First Name',array('style'='width:100px','label'='First Name:')); echo $this-Form-input('Last Name',array('style'='width:100px','label'='Last Name:')); echo $this-Form-input('Position',array('style'='width:100px','label'='Position:')); i want first two input fields in single line and 3rd input field in 2nd line, i have tried it with div false, but its not working. if anybody can help me, thanks in advance

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  • jQuery validate + ajaxSubmit on multiple forms

    - by demogar
    Hello there. I'm trying to validate multiple forms in one single page with the jQuery validation plugin but it validates only the first form in the page. Here is my code: $('form.reply_form').validate({ submitHandler: function(form) { $(form).ajaxSubmit(optionsReplies); return false; } }); Is for a list of reply forms in the page (image facebook). If I try to use the third form, for example, it validates the first one and if the first one is blank it wont submit. Thank you in advance.

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  • Submitting a form on 'Enter' with jQuery?

    - by b. e. hollenbeck
    I have a bog-standard login form - an email text field, a password field and a submit button on an AIR project that's using HTML/jQuery. When I hit Enter on the form, the entire form's contents vanish, but the form isn't submitted. Does anyone know if this is a Webkit issue (Adobe AIR uses Webkit for HTML), or if I've bunged things up? I tried: $('.input').keypress(function(e){ if(e.which == 13){ $('form#login').submit(); } }); But that neither stopped the clearing behavior, or submitted the form. There's no action associated with the form - could that be the issue? Can I put a javascript function in the action?

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  • Property in a Windows Forms form class only accessable after Load event

    - by Spooky2010
    I'm instantiating and calling Form B from Form A. FormB has some custom properties, to allow me to pass it things like sqlAdaptors and dataset instances. When i instantiate and show Form B from Form A as a dialog form with a Using statement, it all works fine, but i find the properties i pass are not available in Form B until after the form_load event has fired. I was under the impression the properties when passed to a instantiated class should be available from a constructor, but this is not the case. If it try to access the properties before the form load event i get a null reference exception. Is this correct behavior ?

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  • Help submitting an asp.net form with jquery

    - by batman_man
    I'm trying to post the entire asp.net form to a certain url. I have tried: $.post("http://www.someaddress.com", $("form").serialize()); I have also tried: $.ajax({ type:"POST", url:"http://www.someaddress.com", data: $('form').serialize(), success: function(){ alert('yay'); } }); In both cases the submit is fine but no data is passed along with it. When i test the form.serialize() in firebug console, this shows my form serialized just fine. When i view the submit in fiddler, i can see that the data part is not set. Maybe im not understanding the data part, but every single tutorial shows this as the way to go - serialize the form and set that as data. What must i do to get my serialized form as the data in my request? What am i missing? Also - why does the NET tab in firebug show all these requests as method OPTIONS?

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  • How to make form validation in Django dynamic?

    - by Oli
    I'm trying to make a form that handles the checking of a domain: the form should fail based on a variable that was set earlier in another form. Basically, when a user wants to create a new domain, this form should fail if the entered domain exists. When a user wants to move a domain, this form should fail if the entered domain doesn't exist. I've tried making it dynamic overload the initbut couldn't see a way to get my passed variabele to the clean function. I've read that this dynamic validation can be accomplished using a factory method, but maybe someone can help me on my way with this? Here's a simplified version of the form so far: #OrderFormStep1 presents the user with a choice: create or move domain class OrderFormStep2(forms.Form): domain = forms.CharField() extension = forms.CharField() def clean(self): cleaned_data = self.cleaned_data domain = cleaned_data.get("domain") extension = cleaned_data.get("extension") if domain and extension: code = whoislookup(domain+extension); #Raise error based on result from OrderFormStep1 #raise forms.ValidationError('error, domain already exists') #raise forms.ValidationError('error, domain does not exist') return cleaned_data

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  • Stop an input field in a form from being submitted

    - by Acorn
    I'm writing some javascript that will insert some input fields into a form on a website. The thing is, I don't want those input fields to affect the form in any way, I don't want them to be submitted when the form is submitted, I only want my javascript to have access to their values. Is there some way I could add some input fields into the middle of a form and not have them submitted when the form is submitted? Obviously the ideal thing would be for the input fields to not be in the form element, but I want the layout of my resulting page to have my inserted input fields appear between elements of the original form.

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  • Javascript: Perform function on form submit

    - by flight643
    Hopefully this is a pretty simple question! I've got the code working in jQuery to listen for a specific form on a page to be submitted and perform an alert when it is.. I.e.: The form itself doesn't have a name so I am targetting the form within a specific form ID. $("#content form").submit(function() { alert("lorem ipsum dolor?"); }); What would be the syntax for performing this in javascript alone without using jquery? For example, I have this code (below) and just am unsure of how to listen for the form to be submitted to perform an action.. var submitform = document.getElementById("content").getElementsByTagName("form"); Thanks!

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  • Perform function on form submit

    - by flight643
    Hopefully this is a pretty simple question! I've got the code working in jQuery to listen for a specific form on a page to be submitted and perform an alert when it is.. I.e.: The form itself doesn't have a name so I am targetting the form within a specific form ID. $("#content form").submit(function() { alert("lorem ipsum dolor?"); }); What would be the syntax for performing this in javascript alone without using jquery? For example, I have this code (below) and just am unsure of how to listen for the form to be submitted to perform an action.. var submitform = document.getElementById("content").getElementsByTagName("form"); Thanks!

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  • form data posted using linq-to-sql not showing until I refresh the page

    - by PeteShack
    I have an asp.net mvc app with a form. When you submit the form, it adds records to the sql database with linq-to-sql. After adding the records, the controller displays the form again, and should show those new values on the form. But, when it displays the form, the values are blank, until you refresh the page. While tracing through the code, I can see the records being added to the database when they are submitted, but the view doesnt display them, unless I refresh. The view is not the problem, it just displays the view model, which is missing the new records immediately after the post. I know this is kind of vague, but wasnt sure what parts of code to include here. Could this have something to do with data context life cycle? Basically, there is a data context created when the form is posted, then a different data context is created in the method that displays the form. Any suggestions on what might be causing this?

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  • Dynamic web widget

    - by user1824996
    My vendor offers a widget creation service where I can login to their page, set initial values of a search form, after the save button is clicked, I can copy & paste the script code on my website to display a product search result widget. I am thinking to change this static widget to a dynamic one. Since my programming knowledge is limited, can experts tell me if it's possible to login https remotely (using cURL) and set search form values equal to values on my page (every time my page content changes, it will change the form value), then save the form. So the widget script I pasted on my page will always be refreshed to new search result. So the issue will involve cross domain, form submission & server/browser communication. I know a little jQuery, PHP, Ajax, cURL but so far I stuck with just having an idea but not really sure how to implement it.

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  • curl multipart/form-data help

    - by user253530
    Hi am trying to post some data on a website using CURL. The posting process has 3 steps. 1. enter a URL, submit and get to the 2nd step with some fields already completed 2. submit again, after you entered some more data and preview the form. 3. submit the final data. The problem is that after the second step, the form data looks like this POSTDATA =-----------------------------12249266671528 Content-Disposition: form-data; name="title" Filme 2010, filme 2009, filme noi, programe TV, program cinema, premiere cinema, trailere filme - CineMagia.ro -----------------------------12249266671528 Content-Disposition: form-data; name="category" 3 -----------------------------12249266671528 Content-Disposition: form-data; name="tags" filme, programe tv, program cinema -----------------------------12249266671528 Content-Disposition: form-data; name="bodytext" Filme 2010, filme 2009, filme noi, programe TV, program cinema, premiere cinema, trailere filme -----------------------------12249266671528 Content-Disposition: form-data; name="trackback" -----------------------------12249266671528 Content-Disposition: form-data; name="url" http://cinemagia.ro -----------------------------12249266671528 Content-Disposition: form-data; name="phase" 2 -----------------------------12249266671528 Content-Disposition: form-data; name="randkey" 9510520 -----------------------------12249266671528 Content-Disposition: form-data; name="id" 17753 -----------------------------12249266671528-- I am stuck trying to devise an algorithm that will generate this kind of POST data for the second step. Just to mention the URL of the form never changes. It is always: http://www.xxx.com/submit. There is only a hidden input called "phase" that changes according to the step i am currently on (phase = 1, phase = 2, phase = 3). Any help, be it either code, pseudo-code or just guidance would be greatly appreciated. My code so far: function postBlvsocialbookmarkingcom($curl,$vars) { extract($vars); $baseUrl = "http://www.blv-socialbookmarking.com/"; //step 1: login $curl->setRedirect(); $page = $curl->post ($baseUrl.'login.php?return=/index.php', array ('username' => $username, 'password' => $password, 'processlogin' => '1', 'return' => '/index.php')); if ($err = $curl->getError ()) { return $err; } //post step 1---- //get random key $page = $curl->post($baseUrl.'/submit', array()); $randomKey = explode('<input type="hidden" name="randkey" value="',$page); $randKey = explode('"',$randomKey[1]); //------------------------------------- $page = $curl->post($baseUrl.'/submit', array('url'=>$address,'phase'=>'1','randkey'=>$randKey[0],'id'=>'c_1')); if ($err = $curl->getError ()) { return $err; } //echo $page; // //post step 2 $page = $curl->post ($baseUrl.'/submit', array ('title' => $title, 'category'=>'1', 'tags' => $tags, 'bodytext' => $description, 'phase' => '2')); if ($err = $curl->getError ()) { return $err; } echo $page; //post step 3 $page = $curl->post ($baseUrl.'/submit', array ('phase' => '3')); if ($err = $curl->getError ()) { return $err; } echo $page; }

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  • VBA WinHTTPRequest and submitting forms

    - by Hazerider
    Hi. I spent all day yesterday trying to figure out how to submit a form using WinHTTPRequest. I can do it pretty easily with an InternetExplorer object, but the problem is that I need to save a PDF file that gets returned, and I am not sure how to do this with the IE object. Here is the relevant HTML code snippet: <div class="loginHome-left"> <fieldset> <h3>Log in Using</h3> <form> <label for="standardLogin" accesskey="s"> <input name="useLogin" id="standardLogin" value="standard" type="radio" checked="true">Standard Login</label> &nbsp; <label for="rsaSecurID" accesskey="r"> <input name="useLogin" value="rsaSecur" type="radio" id="rsaSecurID" onclick="redirectLogin('ct_logon_securid');return false;">RSA SecurID</label> &nbsp; <label for="employeeNTXP" accesskey="e"> <input name="useLogin" id="employeeNTXP" value="employee" type="radio" onclick="redirectLogin('ct_logon_external_nt');return false; "> Employee Windows Login<br></label> </form> <br> <div class="error">Error: ...</div><br> <form onSubmit="if(validate(this)) {formSubmit();} return false;" name="passwdForm" method="post" action="/UAB/ct_logon"> <input value="custom" name="pageId" type="hidden"> <input value="custom" name="auth_mode" type="hidden"> <input value="/UAB/ct_logon" name="ct_orig_uri" type="hidden"> <INPUT VALUE="" NAME="orig_url" TYPE="hidden"> <input value="" name="lpSp" type="hidden"> <label for="user"> <strong>Username</strong> </label> <input autocomplete="off" name="user" type="text" value="" class="txtFld" onkeypress="return handleEnter(this, event);"> <br> <label for="EnterPassword"> <strong>Password</strong>&nbsp;&nbsp;(<a tabindex="-1" href="/UAB/BCResetWithSecrets">Forgot Your Password?</a>) </label> <input autocomplete="off" name="password" type="password" class="txtFld" onkeypress="return handleEnter(this, event);"> <INPUT id="rememberLogin" name="lpCookie" type="checkbox"> <label for="rememberLogin">Remember My Login Information</label><br> </form> <div class="right"> <br> <input type="image" src="/BC_S/images/bclogin/btn_login.gif" name="" value="Submit" onClick="if(validate(document.forms['passwdForm'])){formSubmit();}return false;"> </div> <div class="clearfix"></div> </fieldset> </div> In order to log in through InternetExplorer, I do the following: Sub TestLogin() Dim ie As InternetExplorer, doc As HTMLDocument, form As HTMLFormElement, inp As Variant Set ie = New InternetExplorer ie.Visible = True ie.navigate "https://URL of the login page" Do Until ie.readyState = READYSTATE_COMPLETE Loop Set doc = ie.document For Each form In doc.forms If InStr(form.innerText, "Password") <> 0 Then form.elements("user").Value = "my_name" form.elements("password").Value = "my_password" Exit For Else End If Next 'This is the unnamed input with an image that is used to submit the form' doc.all(78).Click ie.navigate "https://url of the PDF" Do Until ie.readyState = READYSTATE_COMPLETE Loop Dim filename As String, filenum As Integer filename = "somefile.pdf" filenum = FreeFile Open filename For Binary Access Write As #filenum Write #filenum, doc.DocumentElement.innerText Close #filenum ie.Quit Debug.Print Set ie = Nothing End Sub What I really would like to do is something along the lines of the following: Sub TestLogin3() Dim whr As New WinHttpRequest, postData As String whr.Open "POST", "https://live.barcap.com/UAB/ct_logon", False whr.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)" whr.setRequestHeader "Connection", "Keep-Alive" whr.Send whr.WaitForResponse postData = "user=paschom1&password=change01" 'Or the following?' postData = "user=paschom1&password=change01&orig_url=&pageId=custom&auth_mode=custom&ct_orig_uri=/BC/dispatcher&lpSp=&lpCookie=off" whr.Send postData whr.WaitForResponse Debug.Print whr.responseText End Sub It just refuses to work though. Not sure if I need to use more setRequestHeader with Content-Form or something similar, and if I do, not sure what exactly I am supposed to pass it. If anyone has any advice regarding this, it would be hugely appreciated. I could probably use a perl module to do it, but I would rather keep it all in VBA if possible. Thanks, Marc.

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  • XHR readyState = 4 but Status = 0 in Google Chrome Browser

    - by Jay
    Hello i'v got a strange Problem with an AJAX call on my site. I make a simple AJAX call to a Script on my site. But the AJAX call fails with readState=4 and Staus = 0. There's no cross domain problem because the script i want to call is on my server. $.ajax({ type:"GET", url: 'http://mydomain.com/test.php', success : function(response){ console.log(response); }, error : function(XHR){ console.log(arguments); } }); I 've googled a lot of sites but there seems to be no solution for that!

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  • Ajaxing a link in a table

    - by Colin Desmond
    I have a table of results in an ASP.Net MVC page where the last column is an View Details link. I want to have the user click the View Details link and an AJAX method be called to open the results in floating dialog. What I am struggling with is how to link the AJAX call to the link in the results table. I was using a link which embedded the ~/ControllerName/ViewDetails/InstanceId link directly in it. Clicking it took the user to a new page and it is this behaviour I want to replace with an AJAX call and a dialog window. Now I want to attach a jQuery handler to the link to trigger the AJAX call and I can't see how to do this other than write an jQuery handler for each row in the results table. There must be a way to mark the link as an ViewDetails link (using a class?) and attach the jQuery click handler to all instances of type class ViewDetails.

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  • Comments show up in database, but only show up on my index page after a refresh.

    - by Truong
    Hi, I have AJAX, PHP, jquery, and mySQL in this very simple website I'm trying to make. All there is is a text area that sends data to the database and uses ajax\jquery to display that data onto the index page. For some reason though, I press submit and the data goes to the database, but I have to refresh the page myself to see that data on the page. I'm assuming that the problem has to do with my AJAX JQuery or even some mistake in the index. Also, when I type the text into the text area and press submit, the text remains in the textarea until I refresh the page. Haha, sorry if this is such a noob question.. I'm trying to learn. Thanks so much Here is the AJAX: <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript"> $(function() { $(".submit").click(function() { var comment = $("#comment").val(); var post_id = $("#post").val(); var dataString = '&comment=' + comment if(comment=='') { alert('Fill something in please!'); } else { $("#flash").show(); $("#flash").fadeIn(400).html('<img src="noworries.jpg" /> '); $.ajax({ type: "POST", url: "commentajax.php", data: dataString, cache: false, success: function(html){ $("ol#update").append(html); $("ol#update li:last").fadeIn("slow"); $("#flash").hide(); } }); }return false; }); }); </script> Here is the index\form area: <body> <div id="container"><img src="banner.jpg" width="890" height="150" alt="title" /></div> <id="update" class="timeline"> <div id="flash"></div> <div id="container"> <form action="#" method="post"> <textarea name="comment" id="comment" cols="35" rows="4"></textarea><br /> <input name="submit" type="submit" class="submit" id="submit" value=" Submit Comment " /><br /> </form> </div> <id="update" class="timeline"> <?php include('config.php'); //$post_id value comes from the POSTS table $prefix="I'm happy when"; $sql=mysql_query("select * from comments order by com_id desc"); while($row=mysql_fetch_array($sql)) { $comment=$row['com_dis']; ?> <!--Displaying comments--> <div id="container"> <class="box"> <?php echo "$prefix $comment"; ?> </div> <?php } ?> Here is my commentajax.php <?php include('config.php'); if($_POST) { $comment=$_POST['comment']; $comment=mysql_real_escape_string($comment); mysql_query("INSERT INTO comments(com_id,com_dis) VALUES ('NULL', '$comment')"); } ?> <li class="box"><br /> <?php echo $comment; ?> </li> I'm sorry for so much code but I just started learning this four days ago and this is probably one of the last bugs until the website is functional.

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  • Submitting AjaxForm with jQuery in ASP.NET MVC

    - by Hadi Eskandari
    I have an ajax form in asp.net mvc which is as simple as this: <% using (this.Ajax.BeginForm("LatestBlogPosts", "Blog", null, new AjaxOptions { UpdateTargetId = "blogPostPanel" }, new { id = "BlogPostForm" })) { %> <div class="panel" id="blogPostPanel"> <img src="/images/ajax-loader.gif" alt="ajax-loader" /> </div> <% } %> I want to invoke the form submit when document is loaded. This should supposedly, call the controller's action and return a result that should be replaced with the placeholder DIV. If I add a SUBMIT button to the form, it works perfectly, but when I invoke the submit via jQuery, the whole page is refreshed, and the content returned by the server is displayed in the newly displayed page. Here's my jQuery code: <script type="text/javascript"> $(document).ready(function() { $("#BlogPostForm").submit(); }); </script> Anyway to do this?

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  • Safari/Chrome problem with ajaxsubmit?

    - by Jan
    Hi I'm currently having some weird issues with ajaxsubmit (http://jquery.malsup.com/form/#ajaxSubmit), which I'm currently using in a project. I have a flow where I need to open a form into a modal window. I'm using fancybox for that and it works like a charm. When the form has been forced to open in the fancybox window there can happen two things. 1) If the user who is about to submit the form is logged in she should see a confirmation in the modal box, that her input was succesfully submitted 2)If the user is not logged in there should be loaded a login form once she hits the submit button 2.1) When the user has logged in she should receive a confirmation in the modal box. This is also working like a charm in Firefox, IE8 and IE7 but not in Safari or Chrome. The weird part is that it seems like safari and chrome are completely ignoring my ajaxsubmit form. To force the first form to be opened I use the follwoing script - this part is working in both Safari and Chrome. $(".klikEnPrisForm").ajaxForm({ success: function(data){ $.fancybox({'content':data}); } }); My ajaxsubmit form scrip looks like this var options = { url: '/?altTemplate=XmlProxyKlikEnPris', dataType: 'xml', data: $(this).serializeArray(), success: function(data) { if ($(data).find('loggetind').text() == 'true') { $("#klikenpris").hide(); $('<div id="fancybox-inner-klik"></div>').appendTo('#fancybox-inner'); $('#fancybox-inner-klik').load('/KlikEnPrisAccept?tilKvittering=1&sagsno=' + $(data).find('sagsnummer').text() + '&pris=' + $(data).find('pris').text() + '&klik-comment=' + $(data).find('kommentar').text() + '&klik-telefon=' + $(data).find('tlf').text() + '&klik-maeglerkontakt=' + $(data).find('maakontakte').text()).stop(true, true); } else { $("#klikenpris").hide(); $("#fancybox-wrap").css({ 'width': '480px', 'height': '220px' }); $("#fancybox-inner").css({ 'width': '460px', 'height': '220px' }); $('<div id="fancybox-inner-klik"></div>').appendTo('#fancybox-inner'); $('#fancybox-inner-klik').load('/login.aspx?loginklikpris=0&klikpris=1&sagsno=' + $(data).find('sagsnummer').text() + '&pris=' + $(data).find('pris').text() + '&klik-comment=' + $(data).find('kommentar').text() + '&klik-telefon=' + $(data).find('tlf').text() + '&klik-maeglerkontakt=' + $(data).find('maakontakte').text()).stop(true, true); } } }; // bind to the form's submit event $('#klikenprisform').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit(options); // !!! Important !!! // always return false to prevent standard browser submit and page navigation return false; }); I have tried inserting an alert in the succes callback function but it's never being called it seems. It seems like the default action is not being overruled by the link written in the "url" in ajaxsubmit. I'm really puzzled about this, since it's working nicely in other browsers and I'm completely lost on how I should approach the debugging in safari/chrome. I hope all the above makes sense and I'm looking forward to hear any suggestions. Cheers!

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  • Remote File upload in grails

    - by BlackPanther
    I am creating a webapplication using grails which uses lot of ajax.I want to implement file upload using ajax.I dont know how to use ajax for file upload.My sample GSP code is : <!-- code for file upload form--> <div id="updateArea"> </div> I tried with and .After uploading I want to update the 'updateArea' with the result.In result I am planning to show details of the uploaded file.

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  • Ajaxifying Struts2 application

    - by scotty
    I just started working on an application that is build on the Struts2 framework. I am coming from a .Net application with lot of Ajax features like dimming the rest of the site and show dialog box 'please wait while X is happening' ...auto complete and such other ajax features. I searched google for Ajax plugins for Struts2 but did not find anything that looks like it would be worth it. Is my only option to use jquery and its plugins? Is this a pattern that some of you have seen also? Hopefully Java applications are not dead soon because of its inability to cope with ajax...compared to .Net

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  • Jquery tabs and forms

    - by Lee
    Hi, this may be a weird problem but I’m not sure the best way to go about it.. I am using JQuery ajax tabs. The tab section is dynamic so multiple tabs can be added, as the content is loaded via Ajax the same content can be loaded into different tabs. The other important detail is that i am using the Cache option so the tabs maintain state. Now problems arise when more than one tab has been loaded. It looks like HTML items such as forms and divs now have duplicated id's within the DOM, so Ajax queries can no longer distinguish between the elements.. The result is that any JavaScript/Ajax breaks. Does anyone have any suggestions for way to tackle such a problem? Thanks in advance..

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  • generate html select element by previous selected value using jquery

    - by FredS104
    i've a first html select element which generate a second html select element using a first Ajax Function and it will work correctly. This second html element will generate my third html select element but when i do this code for generating my third selector it don't work. i'm looking to made it anyone could help me? here is the code: $("#SystemNameSelection").on('change',function () { var SystemName = $("#SystemNameSelection").text(); if (SystemName === "Value1") { $.ajax({url:"MyFile1.php",success:function(result) { $("#MyElementToPutTheSelector").html(result); } }); } else if (SystemName === "Value2") { $.ajax({url:"MyFile2.php",success:function(result) { $("#MyElementToPutTheSelector").html(result); } }); } else if (SystemName === "Value3") { $.ajax({url:"MyFile3.php",success:function(result) { $("#MyElementToPutTheSelector").html(result); } }); } }); Myfile1, Myfile2 and MyFile3 contain three different html select element. I've tried also with the .change() method and it's didn't work too.

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  • Is it possible to route a Webmethod?

    - by Philip
    I have a .aspx page with some Webmethods that I use for jQuery ajax calls. [WebMethod] public static string HelloWorld(string s) { return "Hello"+ s; } And call this with Url: /ajax/Test.aspx/HelloWorld I wonder if it is possible to route this method to another url like /ajax/helloworld/?

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  • Button with image and loading element id when clicked

    - by Diego Correa
    Hello guys, I've made an application that makes full use of ajax, and what I need to do is: I want a button with a description + image that when clicked is disabled and instead of the original image in the button, appears the ajax loading element id inside the button. And when the ajax loading is complete, the original image of the button returns to the normal. Is there any good source on how to do something like this? What do you guys suggest?

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