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  • Ruby On Rails - Contact form not sending email via localhost

    - by anonymousxxx
    similar problem Rails contact form not working guides: https://github.com/thomasklemm/email_form_rails rails 3.2.x app\models\message.rb class Message include ActiveAttr::Model include ActiveModel::Validations attribute :name attribute :email attribute :subject attribute :body attr_accessible :name, :email, :subject, :body validates_presence_of :name validates_presence_of :email validates :email, email_format: { message: "is not looking like a valid email address"} validates_presence_of :subject validates_length_of :body, maximum: 500 end app\mailers\contact_form.rb class ContactForm < ActionMailer::Base default from: "[email protected]" default to: "[email protected]" def email_form(message) @message = message mail subject: "#{message.subject} #{message.name}" mail body: "#{message.body}" end end development.rb config.action_mailer.delivery_method = :smtp config.action_mailer.perform_deliveries = true config.action_mailer.smtp_settings = { :address => "smtp.gmail.com", :port => 587, :domain => "mydomain.com", :user_name => "[email protected]", :password => "mypassword", :authentication => :plain, :enable_starttls_auto => true } config.action_mailer.default_url_options = { :host => "localhost:3000" } output in command Started POST "/email" for 127.0.0.1 at 2012-09-04 22:10:40 +0700 Processing by HomeController#send_email_form as HTML Parameters: {"utf8"="v", "authenticity_token"="w39BLqCrjTMm4RRi/Sm5hZoEpcw46 npyRy/RS0h48x0=", "message"={"name"="anonymousxxx", "email"="[email protected]", "subject"="Test", "body"="send email"}, "commit"="Create Message"} Redirected to localhost:3000/home/contact Completed 302 Found in 1ms (ActiveRecord: 0.0ms) but email (message) no receive my email,..

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  • When iterating over values, why does typeof(value) return "string" when value is a number? Javascrip

    - by Mark
    I'm using Google Chrome for this test: Contrary to intuition, the first loop alerts "string" 3 times, while the second loop alerts "number" 3 times. numarray = [1, 2, 3]; //for-each loop for(num in numarray) alert(typeof(num)); //standard loop for(i=0; i<numarray.length; i++) alert(typeof(numarray[i])); I was expecting both loops to alert "number" 3 times. How is the first loop implemented in Javascript? In other words, if the for-each is syntactic sugar, what is its equivalent using a standard loop? Also, is there some way to iterate over an object's namespace using a standard loop? I'm looking to touch every one of some object's methods and attributes using a loop of the second kind. I'm new to Javascript and any help is highly appreciated, thanks.

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  • How to check that a regular expression fall into infty loop or not?

    - by Sorush Rabiee
    I'm trying to learn and hopefully use regular expression with Qt. I found that some patterns cause handler to fall into loop. for example searching \b\b in a text, never will terminate. and number of these expressions is infinite (\b\b\b,\b\b\b\b and so on). I'd like to determine and control all invalid expressions. Is there an algorithm to distinguish valid and invalid expressions? If not, how can I prevent my program from falling into an infinite loop?

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  • Functions without arguments, with unit as argument in scala

    - by scout
    def foo(x:Int, f:Unit=>Int) = println(f()) foo(2, {Unit => 3+4} //case1 def loop:Int = 7 foo(2, loop) //does not compile changing loop to //case 2 def loop():Int = 7 foo(2, loop) // does not compile changing loop to //case 3 def loop(x:Unit): Int = 7 //changing according to Don's Comments foo(2,loop) // compiles and works fine should'nt case 1 and case 2 also work? why are they not working? defining foo as def foo(x:Int, y:()=>Int) then case 2 works but not case 1. Arent they all supposed to work, defining the functions either way. //also i think ()=Int in foo is a bad style, y:=Int does not work, comments??

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  • Java - Can i have a faster performance for this loop ?

    - by Brad
    I am reading a book and deleting a number of words from it. My problem is that the process takes long time, and i want to make its performance better(Less time), example : Vector<String> pages = new Vector<String>(); // Contains about 1500 page, each page has about 1000 words. Vector<String> wordsToDelete = new Vector<String>(); // Contains about 50000 words. for( String page: pages ) { String pageInLowCase = page.toLowerCase(); for( String wordToDelete: wordsToDelete ) { if( pageInLowCase.contains( wordToDelete ) ) page = page.replaceAll( "(?i)\\b" + wordToDelete + "\\b" , "" ); } // Do some staff with the final page that does not take much time. } This code takes around 3 minutes to execute. If i skipped the loop of replaceAll(...) i can save more than 2 minutes. So is there a way to do the same loop with a faster performance ?

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  • why this httaccess code results into a redirect loop?

    - by user3606997
    Here I am stuck with my htaccess code. I have been trying to figure it out for the last 11 hours why am I getting a redirect loop for the below code. Options -Indexes +FollowSymLinks RewriteEngine on #Check for no www or www RewriteCond %{HTTP_HOST} ^dummysite.com$ [or] RewriteCond %{HTTP_HOST} ^www.dummysite.com$ [NC] RewriteRule . - [E=FIRSTPART:true] # IE 6 RewriteCond %{HTTP_USER_AGENT} !MSIE\s6 RewriteCond %{ENV:FIRSTPART} true RewriteRule ^(.*)$ https://www.dummysite.com/$1 [R=302,L] Why the above code results into a redirect loop? EDIT: What I actually want is that if the user is from IE6 then he should be redirected to http version with www as prefix no matter if he types www or not in the url. And on the other hand if the user is from any other browsers then he should be redirected to a https version with www as prefix no matter if he types www in the url or not.

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  • How to get the class of an input inside a jQuery each loop?

    - by Paul Atkins
    Hi, I have function which appends inputs inside a list item when a link is clicked. I then loop through these inputs using an each loop using the code below. It is working correctly as shown, however instead of using field.name I want to use the class of the input as the array key but when i try to do this the class is shown as undefined. Here is the code I am currently using: var values = {}; $.each($('li :input').serializeArray(), function(i, field) { values[field.name] = field.value; }); Here is the code I have inside the list item once I have appended the hidden inputs using jQuery append: <li><input type="hidden" name="group" class="group" value="2"/><input type="hidden" name="condition" class="condition" value="isany"/><input type="hidden" name="value" class="value" value="1,2"/></li> I can get the name attribute fine but class is always undefined. Could anybody help with this?

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  • Trying to use a list iterator to print out entire linked list in Java. Infinite loop for some reaso

    - by Matt
    I created my list: private static List list = new LinkedList(); and my iterator: ListIterator itr = list.listIterator(); and use this code to try to print out the list... Only problem is, it never comes out of the loop. When it reaches the tail, shouldn't it come out of the loop, because there is no next? Or is it going back to the head like a circular linked list? It is printing so quickly and my computer locks up shortly after, so I can't really tell what is going on. while (itr.hasNext()) System.out.println(itr.next());

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  • How to yield a single element from for loop in scala?

    - by Julio Faerman
    Much like this question: Functional code for looping with early exit Say the code is def findFirst[T](objects: List[T]):T = { for (obj <- objects) { if (expensiveFunc(obj) != null) return /*???*/ Some(obj) } None } How to yield a single element from a for loop like this in scala? I do not want to use find, as proposed in the original question, i am curious about if and how it could be implemented using the for loop. * UPDATE * First, thanks for all the comments, but i guess i was not clear in the question. I am shooting for something like this: val seven = for { x <- 1 to 10 if x == 7 } return x And that does not compile. The two errors are: - return outside method definition - method main has return statement; needs result type I know find() would be better in this case, i am just learning and exploring the language. And in a more complex case with several iterators, i think finding with for can actually be usefull. Thanks commenters, i'll start a bounty to make up for the bad posing of the question :)

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  • Parallelism in .NET – Part 3, Imperative Data Parallelism: Early Termination

    - by Reed
    Although simple data parallelism allows us to easily parallelize many of our iteration statements, there are cases that it does not handle well.  In my previous discussion, I focused on data parallelism with no shared state, and where every element is being processed exactly the same. Unfortunately, there are many common cases where this does not happen.  If we are dealing with a loop that requires early termination, extra care is required when parallelizing. Often, while processing in a loop, once a certain condition is met, it is no longer necessary to continue processing.  This may be a matter of finding a specific element within the collection, or reaching some error case.  The important distinction here is that, it is often impossible to know until runtime, what set of elements needs to be processed. In my initial discussion of data parallelism, I mentioned that this technique is a candidate when you can decompose the problem based on the data involved, and you wish to apply a single operation concurrently on all of the elements of a collection.  This covers many of the potential cases, but sometimes, after processing some of the elements, we need to stop processing. As an example, lets go back to our previous Parallel.ForEach example with contacting a customer.  However, this time, we’ll change the requirements slightly.  In this case, we’ll add an extra condition – if the store is unable to email the customer, we will exit gracefully.  The thinking here, of course, is that if the store is currently unable to email, the next time this operation runs, it will handle the same situation, so we can just skip our processing entirely.  The original, serial case, with this extra condition, might look something like the following: foreach(var customer in customers) { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) break; customer.LastEmailContact = DateTime.Now; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Here, we’re processing our loop, but at any point, if we fail to send our email successfully, we just abandon this process, and assume that it will get handled correctly the next time our routine is run.  If we try to parallelize this using Parallel.ForEach, as we did previously, we’ll run into an error almost immediately: the break statement we’re using is only valid when enclosed within an iteration statement, such as foreach.  When we switch to Parallel.ForEach, we’re no longer within an iteration statement – we’re a delegate running in a method. This needs to be handled slightly differently when parallelized.  Instead of using the break statement, we need to utilize a new class in the Task Parallel Library: ParallelLoopState.  The ParallelLoopState class is intended to allow concurrently running loop bodies a way to interact with each other, and provides us with a way to break out of a loop.  In order to use this, we will use a different overload of Parallel.ForEach which takes an IEnumerable<T> and an Action<T, ParallelLoopState> instead of an Action<T>.  Using this, we can parallelize the above operation by doing: Parallel.ForEach(customers, (customer, parallelLoopState) => { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) parallelLoopState.Break(); else customer.LastEmailContact = DateTime.Now; } }); There are a couple of important points here.  First, we didn’t actually instantiate the ParallelLoopState instance.  It was provided directly to us via the Parallel class.  All we needed to do was change our lambda expression to reflect that we want to use the loop state, and the Parallel class creates an instance for our use.  We also needed to change our logic slightly when we call Break().  Since Break() doesn’t stop the program flow within our block, we needed to add an else case to only set the property in customer when we succeeded.  This same technique can be used to break out of a Parallel.For loop. That being said, there is a huge difference between using ParallelLoopState to cause early termination and to use break in a standard iteration statement.  When dealing with a loop serially, break will immediately terminate the processing within the closest enclosing loop statement.  Calling ParallelLoopState.Break(), however, has a very different behavior. The issue is that, now, we’re no longer processing one element at a time.  If we break in one of our threads, there are other threads that will likely still be executing.  This leads to an important observation about termination of parallel code: Early termination in parallel routines is not immediate.  Code will continue to run after you request a termination. This may seem problematic at first, but it is something you just need to keep in mind while designing your routine.  ParallelLoopState.Break() should be thought of as a request.  We are telling the runtime that no elements that were in the collection past the element we’re currently processing need to be processed, and leaving it up to the runtime to decide how to handle this as gracefully as possible.  Although this may seem problematic at first, it is a good thing.  If the runtime tried to immediately stop processing, many of our elements would be partially processed.  It would be like putting a return statement in a random location throughout our loop body – which could have horrific consequences to our code’s maintainability. In order to understand and effectively write parallel routines, we, as developers, need a subtle, but profound shift in our thinking.  We can no longer think in terms of sequential processes, but rather need to think in terms of requests to the system that may be handled differently than we’d first expect.  This is more natural to developers who have dealt with asynchronous models previously, but is an important distinction when moving to concurrent programming models. As an example, I’ll discuss the Break() method.  ParallelLoopState.Break() functions in a way that may be unexpected at first.  When you call Break() from a loop body, the runtime will continue to process all elements of the collection that were found prior to the element that was being processed when the Break() method was called.  This is done to keep the behavior of the Break() method as close to the behavior of the break statement as possible. We can see the behavior in this simple code: var collection = Enumerable.Range(0, 20); var pResult = Parallel.ForEach(collection, (element, state) => { if (element > 10) { Console.WriteLine("Breaking on {0}", element); state.Break(); } Console.WriteLine(element); }); If we run this, we get a result that may seem unexpected at first: 0 2 1 5 6 3 4 10 Breaking on 11 11 Breaking on 12 12 9 Breaking on 13 13 7 8 Breaking on 15 15 What is occurring here is that we loop until we find the first element where the element is greater than 10.  In this case, this was found, the first time, when one of our threads reached element 11.  It requested that the loop stop by calling Break() at this point.  However, the loop continued processing until all of the elements less than 11 were completed, then terminated.  This means that it will guarantee that elements 9, 7, and 8 are completed before it stops processing.  You can see our other threads that were running each tried to break as well, but since Break() was called on the element with a value of 11, it decides which elements (0-10) must be processed. If this behavior is not desirable, there is another option.  Instead of calling ParallelLoopState.Break(), you can call ParallelLoopState.Stop().  The Stop() method requests that the runtime terminate as soon as possible , without guaranteeing that any other elements are processed.  Stop() will not stop the processing within an element, so elements already being processed will continue to be processed.  It will prevent new elements, even ones found earlier in the collection, from being processed.  Also, when Stop() is called, the ParallelLoopState’s IsStopped property will return true.  This lets longer running processes poll for this value, and return after performing any necessary cleanup. The basic rule of thumb for choosing between Break() and Stop() is the following. Use ParallelLoopState.Stop() when possible, since it terminates more quickly.  This is particularly useful in situations where you are searching for an element or a condition in the collection.  Once you’ve found it, you do not need to do any other processing, so Stop() is more appropriate. Use ParallelLoopState.Break() if you need to more closely match the behavior of the C# break statement. Both methods behave differently than our C# break statement.  Unfortunately, when parallelizing a routine, more thought and care needs to be put into every aspect of your routine than you may otherwise expect.  This is due to my second observation: Parallelizing a routine will almost always change its behavior. This sounds crazy at first, but it’s a concept that’s so simple its easy to forget.  We’re purposely telling the system to process more than one thing at the same time, which means that the sequence in which things get processed is no longer deterministic.  It is easy to change the behavior of your routine in very subtle ways by introducing parallelism.  Often, the changes are not avoidable, even if they don’t have any adverse side effects.  This leads to my final observation for this post: Parallelization is something that should be handled with care and forethought, added by design, and not just introduced casually.

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  • Delphi: EReadError with message ‘Property PageNr does Not Exist’.

    - by lyborko
    Hi, I get SOMETIMES error message: EReadError with message 'Property PageNr does Not exist', when I try to run my own project. I am really desperate, because I see simply nothing what is the cause. The devilish is that it comes up sometimes but often. It concerns of my own component TPage. Here is declaration TPage = class(TCustomControl) // private FPaperHeight, FPaperWidth:Integer; FPaperBrush:TBrush; FPaperSize:TPaperSize; FPaperOrientation:TPaperOrientation; FPDFDocument: TPDFDocument; FPageNr:integer; procedure PaintBasicLayout; procedure PaintInterior; procedure SetPapersize(Value: TPapersize); procedure SetPaperHeight(Value: Integer); procedure SetPaperWidth(Value: Integer); procedure SetPaperOrientation(value:TPaperOrientation); procedure SetPaperBrush(Value:TBrush); procedure SetPageNr(Value:Integer); protected procedure CreateParams(var Params:TCreateParams); override; procedure AdjustClientRect(var Rect: TRect); override; public constructor Create(AOwner: TComponent);override; destructor Destroy;override; // function GetChildOwner:TComponent; override; procedure DrawControl(X,Y :integer; Dx,Dy:Double; Ctrl:TControl;NewCanvas:TCanvas); // procedure GetChildren(Proc:TGetChildProc; Root:TComponent); override; procedure Loaded; override; procedure MouseDown(Button: TMouseButton; Shift: TShiftState; X, Y: Integer); override; procedure Paint; override; procedure PrintOnCanvas(X,Y:integer; rX,rY:Double; ACanvas:TCanvas); procedure PrintOnPDFCanvas(X,Y:integer); procedure PrintOnPrinterCanvas(X,Y:integer); procedure Resize; override; procedure SetPrintKind(APrintKind:TPrintKind; APrintGroupindex:Integer); published property PageNr:integer read FPageNr write SetPageNr; property PaperBrush: TBrush read FPaperBrush write SetPaperBrush; property PaperHeight: integer read FPaperHeight write SetPaperHeight; property PaperWidth: integer read FPaperWidth write SetPaperWidth; property PaperSize: TPaperSize read FPaperSize write SetPaperSize; property PaperOrientation:TPaperOrientation read FPaperOrientation write SetPaperOrientation; property PDFDocument:TPDFDocument read FPDFDocument write FPDFDocument; property TabOrder; end; I thoroughly read the similar topic depicted here: Delphi: EReadError with message 'Property Persistence does Not exist' But here it is my own source code. No third party. Interesting: when I delete PageNr property in my dfm file (unit1.dfm), then pops up : EReadError with message 'Property PaperHeight does Not exist'. when I delete PaperHeight then it will claim PaperWidth and so on... Here is piece of dfm file: object pg1: TPage Left = 128 Top = 144 Width = 798 Height = 1127 PageNr = 0 PaperHeight = 1123 PaperWidth = 794 PaperSize = psA4 PaperOrientation = poPortrait TabOrder = 0 object bscshp4: TBasicShape Left = 112 Top = 64 Width = 105 Height = 105 PrintKind = pkNormal PrintGroupIndex = 0 Zooming = 100 Transparent = False Repeating = False PageRepeatOffset = 1 ShapeStyle = ssVertical LinePosition = 2 end object bscshp5: TBasicShape Left = 288 Top = 24 Width = 105 Height = 105 PrintKind = pkNormal PrintGroupIndex = 0 Zooming = 100 Transparent = False What the hell happens ??????? I have never seen that. I compiled the unit several times... Encoutered no problem. Maybe the cause is beyond this. I feel completely powerless.

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  • Exchange 2010: Receiving "You can't send a message on behalf of this user..." error when trying to configure delegate access

    - by Beaming Mel-Bin
    I am trying to give someone (John Doe) delegate access to another account (Jane Doe) in our test environment. However, I receive the following error from Exchange: *Subject:* Undeliverable: You have been designated as a delegate for Jane Dow *To:* Jane Dow Delivery has failed to these recipients or groups: John Doe You can't send a message on behalf of this user unless you have permission to do so. Please make sure you're sending on behalf of the correct sender, or request the necessary permission. If the problem continues, please contact your helpdesk. Diagnostic information for administrators: Generating server: /O=UNIONCO/OU=EXCHANGE ADMINISTRATIVE GROUP (FYD132341234)/CN=RECIPIENTS/CN=jdoe #MSEXCH:MSExchangeIS:/DC=local/DC=unionco:MAILBOX-1[578:0x000004DC:0x0000001D] #EX# Can someone help me troubleshoot this?

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  • What's the largest message size modern email systems generally support?

    - by Phil Hollenback
    I know that Yahoo and Google mail support 25MB email attachments. I have an idea from somewhere that 10MB email messages are generally supported by modern email systems. So if I'm sending an email between two arbitrary users on the internet, what's the safe upper bound on message size? 1MB? 10MB? 25MB? I know that one answer is 'don't send big emails, use some sort of drop box'. I'm looking for a guideline if you are limited to only using regular smtp email.

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  • How to tell httpd to preserve the proxied error message?

    - by ZNK - M
    I have an httpd server proxying the requests to 2 different tomcat servers. One of my server handles the authentication and returns a specific http error code 521 when the user already have a running session. My issue is httpd automatically maps this 521 error code to a 500 (internal server error) and then my client can not handle it properly. I have tried to disable ProxyErrorOverride, to remove the /error/HTTP_INTERNAL_SERVER_ERROR.html.var but it does not changes anything. How can I ask httpd to not change anything to the proxied message? <IfModule proxy_module> ProxyPass /context1 http://127.0.0.1:8001/context1 ProxyPass /context2 http://127.0.0.1:8002/context2 ProxyPreserveHost Off ProxyErrorOverride Off </IfModule> Thanks in advance httpd 2.2.22 (Win32) mod_ssl tomcat 7.25 windows 7 64-bits

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  • Is there a way to set up message moderation in Exchange 2007?

    - by Nate Pinchot
    Is there a way to get a feature in Exchange 2007 similar to message moderation in Exchange 2010 through the use of third party tools or otherwise? I've Googled things like "exchange 2007 outbound email approval" to no avail. We are working on getting Exchange 2010 implemented but I need an interim solution if at all possible. The reason for this is from a customer service perspective. I am willing to use a small process to be a smart host if needed. I would appreciate any suggestions or advice. Edit: My apologies, I should have been more clear that I am trying to moderate/approve outgoing email from certain users, not moderate/approve email sent to a distribution group.

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  • How do I get rid of the Cisco CP one-time user message on a Cisco 2901 router?

    - by user65712
    I get this message on a new 2901 Cisco router: Cisco Configuration Professional (Cisco CP) is installed on this device and it provides the default username "cisco" for one-time use. If you have already used the username "cisco" to login to the router and your IOS image supports the "one-time" user option, then this username has already expired. You will not be able to login to the router with this username after you exit this session. It is strongly suggested that you create a new username with a privilege level of 15 using the following command. username <myuser> privilege 15 secret 0 <mypassword> Replace and with the username and password you want to use. It appears every time I login and everytime I show run. I already set up my username. How do I turn it off?

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  • I tried installing Ubuntu 10.04 and I got this message - any ideas on what to do?

    - by vette982
    No root file system defined. Please correct this from the partition menu. This message shows up when I first boot into Ubuntu after the installation. I installed it by mounting the ISO with Daemon Tools, and I just did the default Wubi installation. I keep reading everywhere that I need to choose my installation directory, but I don't get any option to do that. These are all the options I get for installation directory. I have a C and D partition on my drive, and I tried installing it on both and no luck either way. Any ideas?

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  • putty 0.61 : why do I see "Access Denied" message after I enter my login id?

    - by anjanbacchu
    I use putty to login to my RHEL 5.3 server. I'm prompted to enter my login as "login as " and I enter my login Id. as soon as I press ENTER, I see a "Access Denied" message following which I'm prompted with password. I successfully enter password and I'm through -- no problems. I tried the same with putty 0.60(as opposed to above putty 0.61) but in this version, I don't get any "access denied" error. What should I make of this ? Is putty 0.61 version buggy ? P.S : If I login using ssh.exe(from cygwin), then I'm fine -- I don't get any "access denied" errors. Thank you,

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  • I tried installing Ubuntu 10.04 and I got this message - any ideas on what to do?

    - by user41926
    No root file system defined. Please correct this from the partition menu. This message shows up when I first boot into Ubuntu after the installation. I installed it by mounting the ISO with Daemon Tools, and I just did the default Wubi installation. I keep reading everywhere that I need to choose my installation directory, but I don't get any option to do that. These are all the options I get for installation directory. I have a C and D partition on my drive, and I tried installing it on both and no luck either way. Any ideas?

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  • Outlook or OWA: How can I convert an e-mail message to a draft?

    - by Beaming Mel-Bin
    There's an option in Thunderbird called Edit as new... which converts a message to a draft. I am looking for something similar in Exchange. Reasoning: We migrated old e-mail of a user from an IMAP server to Exchange. The user had many drafts saved. According to exchange though, the messages are not drafts anymore. My hunch is that, if we find a similar procedure as Thunderbird's Edit as new..., that should do the trick.

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  • Motherboard Dying? AHCI Drive Init and boot loop intermittent failure

    - by Adam Heath
    My computer is now intermittently failing to boot up. For the last couple of days, when I turn it on it hangs on "AHCI Drive Init...", and when powered off and on again, it booted up fine. Today, it did the same but failed in a few other ways too, seemingly at random: Hangs on "AHCI Drive Init..." Boot loop (after "AHCI Drive Init..." appears for a split second (no drives listed)) Black screen (after "AHCI Drive Init..." appears for a split second, a black screen with all fans still running) The interesting part is that the above is not affected by what drives are connected, or what to. I have tried both disks, each disk individually and no disks (along with trying the primary and secondary SATA controllers), none of this has any effect on what happens. After about 20+ attempts of different combinations, it suddenly decided it would boot up into Windows, and I hadn't touched anything for about 2 cycles. Motherboard: Gigabyte GA-870A-USB3 Processor: Amd Phoenom II x6 1090T RAM: 8GB Corsair 1600 Primary Disk: Plextor 128GB SSD Secondary Disk: Western Digital Black 1TB OS: Windows 8.1 Is this my motherboard dying? Or could something else be the cause? Thanks!

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  • "Windows failed to start" loop with 0xc0000225. No install discs, EasyRE/USB iso hasn't worked

    - by mvidaure
    I've been suffering from this "Windows failed to start" loop with 0xc0000225 for 3 days now and I still can't fix it. The major problem is that I don't have any sort of installation disc. However, I have tried EasyRE via both CD and USB but both result in the same problem.  I try to perform an 'Automated Repair' on my computer and I get in red text "The selected partition is corrupted and could not be accessed or repaired. Please select a different drive to continue." It is also labeled as NO under Active. Since I do not have a the installation discs, I made a USB with a Windows_7_Recovery_Disc  iso (as shown here http://www.sevenforums.com/tutorials/31541-windows-7-usb-dvd-download-tool.html) but it also doesn't work. I get a blue screen that says "RECOVERY You pc needs to be repaired. The application or operating system could not be uploaded because a required file is missing or contains errors... File:\WINDOWS\system32\winload.efi Error code: 0xc0000225 You'll need to use the recovery tools on your installation media. If you don't have any installation media, contact your system administrator or PC manufacturer." Thanks in advance! Miguel

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  • Mulitple lines in make

    - by Navi
    I am trying to store a multiline string in a variable in make var=$(shell cat <<End-of-message \ -------------------------------------\ This is line 1 of the message.\ This is line 2 of the message.\ This is line 3 of the message.\ This is line 4 of the message.\ This is the last line of the message.\ -------------------------------------\ End-of-message) printit: @echo ${var} This doesn't work, so I am wondering if this is possible at all. I need to preserve the newlines here and shell is converting them in spaces. Any suggestions?

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  • closing MQ connection

    - by OakvilleWork
    Good afternoon, I wrote a project to Get Park Queue Info from the IBM MQ, it has producing an error when attempting to close the connection though. It is written in java. Under application in Event Viewer on the MQ machine it displays two errors. They are: “Channel program ended abnormally. Channel program ‘system.def.surconn’ ended abnormally. Look at previous error messages for channel program ‘system.def.surconn’ in the error files to determine the cause of the failure. The other message states: “Error on receive from host rnanaj (10.10.12.34) An error occurred receiving data from rnanaj (10.10.12.34) over tcp/ip. This may be due to a communications failure. The return code from tcp/ip recv() call was 10054 (X’2746’). Record these values.” This must be something how I try to connect or close the connection, below I have my code to connect and close, any ideas?? Connect: _logger.info("Start"); File outputFile = new File(System.getProperty("PROJECT_HOME"), "run/" + this.getClass().getSimpleName() + "." + System.getProperty("qmgr") + ".txt"); FileUtils.mkdirs(outputFile.getParentFile()); Connection jmsConn = null; Session jmsSession = null; QueueBrowser queueBrowser = null; BufferedWriter commandsBw = null; try { // get queue connection MQConnectionFactory MQConn = new MQConnectionFactory(); MQConn.setHostName(System.getProperty("host")); MQConn.setPort(Integer.valueOf(System.getProperty("port"))); MQConn.setQueueManager(System.getProperty("qmgr")); MQConn.setChannel("SYSTEM.DEF.SVRCONN"); MQConn.setTransportType(JMSC.MQJMS_TP_CLIENT_MQ_TCPIP); jmsConn = (Connection) MQConn.createConnection(); jmsSession = jmsConn.createSession(false, Session.AUTO_ACKNOWLEDGE); Queue jmsQueue = jmsSession.createQueue("PARK"); // browse thru messages queueBrowser = jmsSession.createBrowser(jmsQueue); Enumeration msgEnum = queueBrowser.getEnumeration(); commandsBw = new BufferedWriter(new FileWriter(outputFile)); // String line = "DateTime\tMsgID\tOrigMsgID\tCorrelationID\tComputerName\tSubsystem\tDispatcherName\tProcessor\tJobID\tErrorMsg"; commandsBw.write(line); commandsBw.newLine(); while (msgEnum.hasMoreElements()) { Message message = (Message) msgEnum.nextElement(); line = dateFormatter.format(new Date(message.getJMSTimestamp())) + "\t" + message.getJMSMessageID() + "\t" + message.getStringProperty("pkd_orig_jms_msg_id") + "\t" + message.getJMSCorrelationID() + "\t" + message.getStringProperty("pkd_computer_name") + "\t" + message.getStringProperty("pkd_subsystem") + "\t" + message.getStringProperty("pkd_dispatcher_name") + "\t" + message.getStringProperty("pkd_processor") + "\t" + message.getStringProperty("pkd_job_id") + "\t" + message.getStringProperty("pkd_sysex_msg"); _logger.info(line); commandsBw.write(line); commandsBw.newLine(); } } Close: finally { IO.close(commandsBw); if (queueBrowser != null) { try { queueBrowser.close();} catch (Exception ignore) {}} if (jmsSession != null) { try { jmsSession.close();} catch (Exception ignore) {}} if (jmsConn != null) { try { jmsConn.stop();} catch (Exception ignore) {}} }

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  • Having trouble understanding some code (Ruby on Rails)

    - by user284194
    I posted a question awhile ago asking how I could limit the rate at which a form could be submitted from a rails application. I was helped by a very patient user and their solution works great. The code was for my comments controller, and now I find myself wanting to add this functionality to another controller, my Messages controller. I immediately tried reusing the working code from the comments controller but I couldn't get it to work. Instead of asking for the working code, could someone please help me understand my working comment controller code? class CommentsController < ApplicationController #... before_filter :post_check def record_post_time cookies[:last_post_at] = Time.now.to_i end def last_post_time Time.at((cookies[:last_post_at].to_i rescue 0)) end MIN_POST_TIME = 2.minutes def post_check return true if (Time.now - last_post_time) > MIN_POST_TIME flash[:warning] = "You are trying to reply too fast." @message = Message.find(params[:message_id]) redirect_to(@message) return false end #... def create @message = Message.find(params[:message_id]) @comment = @message.comments.build(params[:comment]) if @comment.save record_post_time flash[:notice] = "Replied to \"#{@message.title}\"" redirect_to(@message) else render :action => "new" end end def update @message = Message.find(params[:message_id]) @comment = Comment.find(params[:id]) if @comment.update_attributes(params[:comment]) record_post_time redirect_to post_comment_url(@message, @comment) else render :action => "edit" end end #... end My Messages controller is pretty much a standard rails generated controller with a few before filters and associated private methods for DRYing up the code and a redirect for non existent pages. I'll explain how much of the code I understand. When a comment is created, a cookie is created with a last_post_time value. If they try to post another comment, the cookie is checked if the last one was made in the last two minutes. If it was a flash warning is displayed and no comment is recorded. What I don't really understand is how the post_check method works and how I can adapt it for my simpler posts controller. I thought I could reuse all the code in the message controller with the exception of the line: @message = Message.find(params[:message_id]) # (don't need the redirect code) in the post_check method. But it trips up on the "record_post_time" in the create action/method. I really want to understand this. Can someone explain why this doesn't work? I greatly appreciate you reading my lengthy question.

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