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  • Planning and coping with deadlines in SCRUM

    - by John
    From wikipedia: During each “sprint”, typically a two to four week period (with the length being decided by the team), the team creates a potentially shippable product increment (for example, working and tested software). The set of features that go into a sprint come from the product “backlog,” which is a prioritized set of high level requirements of work to be done. Which backlog items go into the sprint is determined during the sprint planning meeting. During this meeting, the Product Owner informs the team of the items in the product backlog that he or she wants completed. The team then determines how much of this they can commit to complete during the next sprint. During a sprint, no one is allowed to change the sprint backlog, which means that the requirements are frozen for that sprint. After a sprint is completed, the team demonstrates the use of the software. I was reading this and two questions immediately popped into my head: 1)If a sprint is only a couple of weeks, decided in a single meeting, how can you accurately plan what can be achieved? High-level tasks can't be estimated accurately in my experience, and can easily double what seems reasonable. As a developer, I hate being pushed into committing what I can deliver in the next month based on a set of customer requirements, this goes against everything I know about generating reliable estimates rather than having to roughly estimate and then double it! 2)Since the requirements are supposed to be locked and a deliverable product available at the end, what happens when something does take twice as long? What if this feature is only 1/2 done at the end of the sprint? The wiki article goes on to talk about Sprint planning, where things are broken down into much smaller tasks for estimation (<1 day) but this is after the Sprint features are already planned and the release agreed, isn't it? kind of like a salesman promising something without consulting the developers.

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  • How Optimize sql query make it faster

    - by user502083
    Hello every one : I have a very simple small database, 2 of tables are: Node (Node_ID, Node_name, Node_Date) : Node_ID is primary key Citation (Origin_Id, Target_Id) : PRIMARY KEY (Origin_Id, Target_Id) each is FK in Node Now I write a query that first find all citations that their Origin_Id has a specific date and then I want to know what are the target dates of these records. I'm using sqlite in python the Node table has 3000 record and Citation has 9000 records, and my query is like this in a function: def cited_years_list(self, date): c=self.cur try: c.execute("""select n.Node_Date,count(*) from Node n INNER JOIN (select c.Origin_Id AS Origin_Id, c.Target_Id AS Target_Id, n.Node_Date AS Date from CITATION c INNER JOIN NODE n ON c.Origin_Id=n.Node_Id where CAST(n.Node_Date as INT)={0}) VW ON VW.Target_Id=n.Node_Id GROUP BY n.Node_Date;""".format(date)) cited_years=c.fetchall() self.conn.commit() print('Cited Years are : \n ',str(cited_years)) except Exception as e: print('Cited Years retrival failed ',e) return cited_years Then I call this function for some specific years, But it's crazy slowwwwwwwww :( (around 1 min for a specific year) Although my query works fine, it is slow. would you please give me a suggestion to make it faster? I'd appreciate any idea about optimizing this query :) I also should mention that I have indices on Origin_Id and Target_Id, so the inner join should be pretty fast, but it's not!!!

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  • How to improve Visual C++ compilation times?

    - by dtrosset
    I am compiling 2 C++ projects in a buildbot, on each commit. Both are around 1000 files, one is 100 kloc, the other 170 kloc. Compilation times are very different from gcc (4.4) to Visual C++ (2008). Visual C++ compilations for one project take in the 20 minutes. They cannot take advantage of the multiple cores because a project depend on the other. In the end, a full compilation of both projects in Debug and Release, in 32 and 64 bits takes more than 2 1/2 hours. gcc compilations for one project take in the 4 minutes. It can be parallelized on the 4 cores and takes around 1 min 10 secs. All 8 builds for 4 versions (Debug/Release, 32/64 bits) of the 2 projects are compiled in less than 10 minutes. What is happening with Visual C++ compilation times? They are basically 5 times slower. What is the average time that can be expected to compile a C++ kloc? Mine are 7 s/kloc with vc++ and 1.4 s/kloc with gcc. Can anything be done to speed-up compilation times on Visual C++?

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  • Symfony 1.4 - Don't save a blank password on a executeUpdate action.

    - by Twelve47
    I have a form to edit a UserProfile which is stored in mysql db. Which includes the following custom configuration: public function configure() { $this->widgetSchema['password']=new sfWidgetFormInputPassword(); $this->validatorSchema['password']->setOption('required', false); // you don't need to specify a new password if you are editing a user. } When the user tries to save the executeUpdate method is called to commit the changes. If the password is left blank, the password field is set to '', but I want it to retain the old password instead of overwriting it. What is the best (/most in the symfony ethos) way of doing this? My solution was to override the setter method on the model (which i had done anyway for password encryption), and ignore blank values. public function setPassword( $password ) { if ($password=='') return false; // if password is blank don't save it. return $this->_set('password', UserProfile ::encryptPassword( $password )); } It seems to work fine like this, but is there a better way? If you're wondering I cannot use sfDoctrineGuard for this project as I am dealing with a legacy database, and cannot change the schema.

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  • How can I rewrite the history of a published git branch in multiple steps?

    - by Frerich Raabe
    I've got a git repository with two branches, master and amazing_new_feature. The latter branch contains the work on, well, an amazing new feature. A colleague and me are both working on the same repository, and the two of us commit to both branches. Now the work on the amazing new feature finished, and a bit more than 100 commits were accumulated in the amazing_new_feature branch. I'd like to clean those commits up a bit (using git rebase -i) before merging the work into master. The issue we're facing is that it's quite a pain to rewrite/reorder all 100 commits in one go. Instead, what I'd like to do is: Rewrite/merge/reorder the first few commits in the amazing_new_feature branch and put the result into a dedicated branch which contains the 'cleaned up' history (say, a amazing_new_feature_ready_for_merge branch). Rebase the remaining amazing_new_feature branch on the amazing_new_feature_ready_for_merge branch. Repeat at 1. My idea is that at some point, all the work from amazing_new_feature should be in amazing_new_feature_ready_for_merge and then I can merge the latter into master. Is this a sensible approach, or are there better/easier/more fool-proff solutions to this problem? I'm especially scared about the second step of the above algorithm since it means rebasing a published branch. IIRC it's a dangerous thing to do.

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  • Django ManyToMany Membership errors making associations

    - by jmitchel3
    I'm trying to have a "member admin" in which they have hundreds of members in the group. These members can be in several groups. Admins can remove access for the member ideally in the view. I'm having trouble just creating the group. I used a ManytoManyField to get started. Ideally, the "member admin" would be able to either select existing Users OR it would be able to Add/Invite new ones via email address. Here's what I have: #views.py def membership(request): group = Group.objects.all().filter(user=request.user) GroupFormSet = modelformset_factory(Group, form=MembershipForm) if request.method == 'POST': formset = GroupFormSet(request.POST, request.FILES, queryset=group) if formset.is_valid(): formset.save(commit=False) for form in formset: form.instance.user = request.user formset.save() return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) else: formset= GroupFormSet(queryset=group) return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) #models.py class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(User, related_name='community_members', through='Membership') user = models.ForeignKey(User, related_name='community_creator', null=True) def __unicode__(self): return self.name class Membership(models.Model): member = models.ForeignKey(User, related_name='user_membership', blank=True, null=True) group = models.ForeignKey(Group, related_name='community_membership', blank=True, null=True) date_joined = models.DateField(auto_now=True, blank=True, null=True) class Meta: unique_together = ('member', 'group') Any ideas? Thank you for your help.

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • Managing Many to Many relationships in asp.net Wizard Control

    - by Luis
    Say I have this entity with a lot of attributes. In the input form I have decided to implement a wizard control so I can collect information about this entity in several steps. The problem is that I need to collect information that has been modeled has many to many relationships. I am planning to use a telerik gridview to manage this (add/edit/delete), the problem is where do I store that data since the entity in a insert form is not created on the database yet. OK so I can store all that info in temporary lists residing in the viewstate, waiting for the final submit where I dump all that in the DB, but one of the steps I am collecting files...now storing files in the viewstate is out of the question, same as as storing them in the session... I have been thinking of implementing in a way that the user has to submit some info first (say first 3 steps), commit the data to the database creating the parent entity and then start inserting all the childs entities...but this will get weird as it's confusing since on the first steps you not saving the data to the DB and on the next ones you are commiting directly... Anyone has any thoughts on this? Thanks

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  • NHibernate.MappingException on table insertion.

    - by Suja
    The table structure is : The controller action to insert a row to table is public bool CreateInstnParts(string data) { IDictionary myInstnParts = DeserializeData(data); try { HSInstructionPart objInstnPartBO = new HSInstructionPart(); using (ISession session = Document.OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { objInstnPartBO.DocumentId = Convert.ToInt32(myInstnParts["documentId"]); objInstnPartBO.InstructionId = Convert.ToInt32(myInstnParts["instructionId"]); objInstnPartBO.PartListId = Convert.ToInt32(myInstnParts["part"]); objInstnPartBO.PartQuantity = Convert.ToInt32(myInstnParts["quantity"]); objInstnPartBO.IncPick = Convert.ToBoolean(myInstnParts["incpick"]); objInstnPartBO.IsTracked = Convert.ToBoolean(myInstnParts["istracked"]); objInstnPartBO.UpdatedBy = User.Identity.Name; objInstnPartBO.UpdatedAt = DateTime.Now; session.Save(objInstnPartBO); transaction.Commit(); } return true; } } catch (Exception ex) { Console.Write(ex.Message); return false; } } This is throwing an exception NHibernate.MappingException was caught Message="No persister for: Hexsolve.Data.BusinessObjects.HSInstructionPart" Source="NHibernate" StackTrace: at NHibernate.Impl.SessionFactoryImpl.GetEntityPersister(String entityName) at NHibernate.Impl.SessionImpl.GetEntityPersister(String entityName, Object obj) at NHibernate.Event.Default.AbstractSaveEventListener.SaveWithGeneratedId(Object entity, String entityName, Object anything, IEventSource source, Boolean requiresImmediateIdAccess) at NHibernate.Event.Default.DefaultSaveOrUpdateEventListener.SaveWithGeneratedOrRequestedId(SaveOrUpdateEvent event) at NHibernate.Event.Default.DefaultSaveEventListener.SaveWithGeneratedOrRequestedId(SaveOrUpdateEvent event) at NHibernate.Event.Default.DefaultSaveOrUpdateEventListener.EntityIsTransient(SaveOrUpdateEvent event) at NHibernate.Event.Default.DefaultSaveEventListener.PerformSaveOrUpdate(SaveOrUpdateEvent event) at NHibernate.Event.Default.DefaultSaveOrUpdateEventListener.OnSaveOrUpdate(SaveOrUpdateEvent event) at NHibernate.Impl.SessionImpl.FireSave(SaveOrUpdateEvent event) at NHibernate.Impl.SessionImpl.Save(Object obj) at HexsolveMVC.Controllers.InstructionController.CreateInstnParts(String data) in F:\Project\HexsolveMVC\Controllers\InstructionController.cs:line 1342 InnerException: Can anyone help me solve this??

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  • Rails: Can't set or update tag_list using a text field with acts_as_taggable_on

    - by Josh
    Hey everyone, I'm trying to add tagging to a rails photo gallery system I'm working on. It works from the back-end, but if I try to set or change it in the form view, it doesn't work. I added acts_as_taggable to the photo model and did the migrations. My gallery builder is programmed to add one tag automatically to each photo it creates. This works fine, just as if it were setting it for the console. However, I can't seem to set tags using a text_field in the photo form. Here's the code I added to my photo form: <p> <%= f.label :tag_list %><br /> <%= f.text_field :tag_list %> </p> Now, that's pretty trivial, and since :tag_list supports single-string comma-separated assignment (e.g. tag_list = "this, that, the other" #= ['this', 'that', 'the other']), I don't see why using a text field doesn't work. And to make even less sense, if a tag list has already been populated, the list will still show up in the text field when editing the photo. I just can't seem to commit any changes to the list. The documentation on their github page doesn't appear to give any information on how to set these values from the view. Any ideas? Oh, and I'm using the Rails 3 gem version.

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  • Error when creating an image from a UIView

    - by Raphael Pinto
    Hi, I'm creating an image from a view whith the folowing code : UIGraphicsBeginImageContext(myView.bounds.size); [myView.layer renderInContext:UIGraphicsGetCurrentContext()]; UIImage *viewImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); UIImageWriteToSavedPhotosAlbum(viewImage, nil, nil, nil); The image is created in the user album but in the consol I get this : 2010-05-11 10:17:17.974 myApp[3875:1807] sqlite error 8 [attempt to write a readonly database] 2010-05-11 10:17:18.014 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3d87f 0x34e3b029 0x34e3b22b 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 0x3034a12c) 2010-05-11 10:17:18.077 myApp[3875:1807] sqlite error 8 [attempt to write a readonly database] 2010-05-11 10:17:18.087 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3b053 0x34e3b22b 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 0x3034a12c) 2010-05-11 10:17:18.091 myApp[3875:1807] sqlite error 8 [attempt to write a readonly database] 2010-05-11 10:17:18.095 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3b085 0x34e3b22b 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 0x3034a12c) 2010-05-11 10:17:18.111 myApp[3875:1807] sqlite error 1 [SQL logic error or missing database] 2010-05-11 10:17:18.115 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3d87f 0x34e3b029 0x34e3b4dd 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 0x3034a12c) 2010-05-11 10:17:18.120 myApp[3875:1807] sqlite error 1 [SQL logic error or missing database] 2010-05-11 10:17:18.124 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3b053 0x34e3b4dd 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 0x3034a12c) 2010-05-11 10:17:18.129 myApp[3875:1807] sqlite error 1 [cannot commit - no transaction is active] 2010-05-11 10:17:18.133 myApp[3875:1807] Backtrace for sqlite error: (0x34e3a909 0x34e3b085 0x34e3b4dd 0x34e2f48b 0x34e2dccb 0x34e2d2f7 0x34e2d3bb 0x34e4dcd3 0x34e50515 0x34e51351 0x34e51681 0x34e513f5 0x34e511e3 0x303af57c 0x34e51163 0x303b06e8 0x303ac8e0 0x303ac6d8 0x303ac8c8 0x303aca80 0x30350d55 I don't know where the problem come from. Can you help me?

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  • Subversion freaking out on me!

    - by Malfist
    I have two copies of a site, one is the production copy, and the other is the development copy. I recently added everything in the production to a subversion repository hosted on our linux backup server. I created a tag of the current version and I was done. I then copied the development copy overtop of the production copy (on my local machine where I have everything checked out). There are only 10-20 files changed, however, when I use tortoise SVN to do a commit, it says every file has changed. The diff file generated shows subversion removing everything, and replacing it with the new version (which is the exact same). What is going on? How do I fix it? An example diff: Index: C:/Users/jhollon/Documents/Visual Studio 2008/Projects/saloon/trunk/components/index.html =================================================================== --- C:/Users/jhollon/Documents/Visual Studio 2008/Projects/saloon/trunk/components/index.html (revision 5) +++ C:/Users/jhollon/Documents/Visual Studio 2008/Projects/saloon/trunk/components/index.html (working copy) @@ -1,4 +1,4 @@ -<html> -<body bgcolor="#FFFFFF"> -</body> +<html> +<body bgcolor="#FFFFFF"> +</body> </html> \ No newline at end of file

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  • Help me understand WebDAV and Autoversioning

    - by Malfist
    I just read the WebDAV Appendex in the O'Reilly Subversion book. I don't quite understand it. It talked about users being able to "mount" WebDAV directories (trees) and manipulate the files like they would normally and on saves the server would automagically create a new revision. The way it explained it, it sounded like it would work for any program, but then at the end of the appendix, it listed a series of programs that worked with WebDAV servers, which leads me to think that maybe it doesn't work like it originally described it. My question is this: How exactly do you interact with a WebDAV repository? Can I do this for example: Copy a file locally via ftp, edit it with notepad++, and then upload it via ftp to the server and have the server do a commit and create a new revision with the file I just edited and uploaded. Also, if that is possible, what happens if two people edit the file locally (on their machines) and uploaded two reversions to the server? With webDAV will I be able to replace Dreamweaver's "Oops, someone edited this before you" with simple ftp uploads and subversion conflict resolutions?

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  • Access DB Transaction on insert or updating

    - by Raju Gujarati
    I am going to implement the database access layer of the Window application using C#. The database (.accdb) is located to the project files. When it comes to two notebooks (clients) connecting to one access database through switches, it throws DBConcurrency Exception Error. My target is to check the timestamp of the sql executed first and then run the sql . Would you please provide me some guidelines to achieve this ? The below is my code protected void btnTransaction_Click(object sender, EventArgs e) { string custID = txtID.Text; string CompName = txtCompany.Text; string contact = txtContact.Text; string city = txtCity.Text; string connString = ConfigurationManager.ConnectionStrings["CustomersDatabase"].ConnectionString; OleDbConnection connection = new OleDbConnection(connString); connection.Open(); OleDbCommand command = new OleDbCommand(); command.Connection = connection; OleDbTransaction transaction = connection.BeginTransaction(); command.Transaction = transaction; try { command.CommandText = "INSERT INTO Customers(CustomerID, CompanyName, ContactName, City, Country) VALUES(@CustomerID, @CompanyName, @ContactName, @City, @Country)"; command.CommandType = CommandType.Text; command.Parameters.AddWithValue("@CustomerID", custID); command.Parameters.AddWithValue("@CompanyName", CompName); command.Parameters.AddWithValue("@ContactName", contact); command.Parameters.AddWithValue("@City", city); command.ExecuteNonQuery(); command.CommandText = "UPDATE Customers SET ContactName = @ContactName2 WHERE CustomerID = @CustomerID2"; command.CommandType = CommandType.Text; command.Parameters.AddWithValue("@CustomerID2", custIDUpdate); command.Parameters.AddWithValue("@ContactName2", contactUpdate); command.ExecuteNonQuery(); adapter.Fill(table); GridView1.DataSource = table; GridView1.DataBind(); transaction.Commit(); lblMessage.Text = "Transaction successfully completed"; } catch (Exception ex) { transaction.Rollback(); lblMessage.Text = "Transaction is not completed"; } finally { connection.Close(); } }

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  • Update Input Value With jQuery, Old Value Submitted to Form

    - by Tyler DeWitt
    I've got a form with an input with id/name league_id <form accept-charset="UTF-8" action="/user" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="?"><input name="authenticity_token" type="hidden" value="bb92urX83ivxOZZJzWLJMcr5ZSuamowO9O9Sxh5gqKo="></div> <input id="league_id" name="league_id" type="text" value="11"> <select class="sport_selector" id="sport_type_id" name="sport_type_id"><option value="5" selected="selected">Football</option> <option value="25">Women's Soccer</option> <option value="30">Volleyball</option> <option value="10">Men's Soccer</option></select> <input name="commit" type="submit" value="Save changes"> </form> In another part of my page, I have a drop down that, when changed, clears the value of league_id $("#sport_type_id").change -> $("#league_id").val(null) $(this).parents('form:first').submit() If I debug this page, I can see the value get wiped from the text box, but when the form is submitted, my controller always gets the old value. I tried changing the name of the input and got the same results.

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  • NHibernate + Fluent long startup time

    - by PaRa
    Hi all, am new to NHibernate. When performing below test took 11.2 seconds (debug mode) i am seeing this large startup time in all my tests (basically creating the first session takes a tone of time) setup = Windows 2003 SP2 / Oracle10gR2 latest CPU / ODP.net 2.111.7.20 / FNH 1.0.0.636 / NHibernate 2.1.2.4000 / NUnit 2.5.2.9222 / VS2008 SP1 using System; using System.Collections; using System.Data; using System.Globalization; using System.IO; using System.Text; using System.Data; using NUnit.Framework; using System.Collections.Generic; using System.Data.Common; using NHibernate; using log4net.Config; using System.Configuration; using FluentNHibernate; [Test()] public void GetEmailById() { Email result; using (EmailRepository repository = new EmailRepository()) { results = repository.GetById(1111); } Assert.IsTrue(results != null); } public class EmailRepository : RepositoryBase { public EmailRepository():base() { } } In my RepositoryBase public T GetById(object id) { using (var session = sessionFactory.OpenSession()) using (var transaction = session.BeginTransaction()) { try { T returnVal = session.Get(id); transaction.Commit(); return returnVal; } catch (HibernateException ex) { // Logging here transaction.Rollback(); return null; } } } The query time is very small. The resulting entity is really small. Subsequent queries are fine. Its seems to be getting the first session started. Has anyone else seen something similar?

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  • Exit and rollback everything in script on error

    - by Jan W.
    Hey guys ! I'm in a bit of a pickle here. I have a TSQL script that does a lot of database structure adjustments but it's not really safe to just let it go through when something fails. to make things clear: using MS SQL 2005 it's NOT a stored procedure, just a script file (.sql) what I have is something in the following order BEGIN TRANSACTION ALTER Stuff GO CREATE New Stuff GO DROP Old Stuff GO IF @@ERROR != 0 BEGIN PRINT 'Errors Found ... Rolling back' ROLLBACK TRANSACTION RETURN END ELSE PRINT 'No Errors ... Committing changes' COMMIT TRANSACTION just to illustrate what I'm working with ... can't go into specifics now, the problem ... When I introduce an error (to test if things get rolled back), I get a statement that the ROLLBACK TRANSACTION could not find a corresponding BEGIN TRANSACTION. This leads me to believe that something when REALLY wrong and the transaction was already killed. what I also noticed is that the script didn't fully quit on error and thus DID try to execute every statement after the error occured. (I noticed this when new tables showed up when I wasn't expecting them because it should have rollbacked) any help in this department is welcome if more speficics are needed, ask! greetz

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  • SQL Server race condition issue with range lock

    - by Freek
    I'm implementing a queue in SQL Server (please no discussions about this) and am running into a race condition issue. The T-SQL of interest is the following: set transaction isolation level serializable begin tran declare @RecordId int declare @CurrentTS datetime2 set @CurrentTS=CURRENT_TIMESTAMP select top 1 @RecordId=Id from QueuedImportJobs with (updlock) where Status=@Status and (LeaseTimeout is null or @CurrentTS>LeaseTimeout) order by Id asc if @@ROWCOUNT> 0 begin update QueuedImportJobs set LeaseTimeout = DATEADD(mi,5,@CurrentTS), LeaseTicket=newid() where Id=@RecordId select * from QueuedImportJobs where Id = @RecordId end commit tran RecordId is the PK and there is also an index on Status,LeaseTimeout. What I'm basically doing is select a record of which the lease happens to be expired, while simultaneously updating the lease time with 5 minutes and setting a new lease ticket. So the problem is that I'm getting deadlocks when I run this code in parallel using a couple of threads. I've debugged it up to the point where I found out that the update statement sometimes gets executing twice for the same record. Now, I was under the impression that the with (updlock) should prevent this (it also happens with xlock btw, not with tablockx). So it actually look like there is a RangeS-U and a RangeX-X lock on the same range of records, which ought to be impossible. So what am I missing? I'm thinking it might have something to do with the top 1 clause or that SQL Server does not know that where Id=@RecordId is actually in the locked range? Deadlock graph: Table schema (simplified):

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  • SQLAlchemy sessions - DetachedInstanceError?

    - by benjaminhkaiser
    I have a function that attempts to take a list of usernames, look each one up in a user table, and then add them to a membership table. If even one username is invalid, I want the entire list to be rolled back, including any users that have already been processed. I thought that using sessions was the best way to do this but I'm running into a DetachedInstanceError: DetachedInstanceError: Instance <Organization at 0x7fc35cb5df90> is not bound to a Session; attribute refresh operation cannot proceed Full stack trace is here. The error seems to trigger when I attempt to access the user (model) object that is returned by the query. From my reading I understand that it has something to do with there being multiple sessions, but none of the suggestions I saw on other threads worked for me. Code is below: def add_members_in_bulk(organization_eid, users): """Add users to an organization in bulk - helper function for add_member()""" """Returns "success" on success and id of first failed student on failure""" session = query_session.get_session() session.begin_nested() users = users.split('\n') for u in users: try: user = user_lookup.by_student_id(u) except ObjectNotFoundError: session.rollback() return u if user: membership.add_user_to_organization( user.entity_id, organization_eid, '', [] ) session.flush() session.commit() return 'success' here's the membership.add_user_to_organization: def add_user_to_organization(user_eid, organization_eid, title, tag_ids): """Add a User to an Organization with the given title""" user = user_lookup.by_eid(user_eid) organization = organization_lookup.by_eid(organization_eid) new_membership = OrganizationMembership( organization_eid=organization.entity_id, user_eid=user.entity_id, title=title) new_membership.tags = [get_tag_by_id(tag_id) for tag_id in tag_ids] crud.add(new_membership) and here is the lookup by ID query: def by_student_id(student_id, include_disabled=False): """Get User by RIN""" try: return get_query_set(include_disabled).filter(User.student_id == student_id).one() except NoResultFound: raise ObjectNotFoundError("User with RIN %s does not exist." % student_id)

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  • DataReader is not returning results from a MySQL Stored Proc

    - by Glenn Slaven
    I have a stored proc in MySQL (5.5) that I'm calling from a C# application (using MySQL.Data v6.4.4.0). I have a bunch of other procs that work fine, but this is not returning any results, the data reader says the result set is empty. The proc does a couple of inserts & an update inside a transaction then selects 2 local variables to return. The inserts & update are happening, but the select is not returning. When I run the proc manually it works, gives a single row with the two fields, but the data reader is empty. This is the proc: CREATE DEFINER=`root`@`localhost` PROCEDURE `File_UpdateFile`(IN siteId INT, IN fileId INT, IN description VARCHAR(100), IN folderId INT, IN fileSize INT, IN filePath VARCHAR(100), IN userId INT) BEGIN START TRANSACTION; SELECT MAX(v.versionNumber) + 1 INTO @versionNumber FROM `file_version` v JOIN `file` f ON (v.fileId = f.fileId) WHERE v.fileId = fileId AND f.siteId = siteId; INSERT INTO `file_version` (fileId, versionNumber, description, fileSize, filePath, uploadedOn, uploadedBy, fileVersionState) VALUES (fileId, @versionNumber, description, fileSize, filePath, NOW(), userId, 0); INSERT INTO filehistory (fileId, `action`, userId, createdOn) VALUES (fileId, 'UPDATE', userId, NOW()); UPDATE `file` f SET f.checkedOutBy = NULL WHERE f.fileId = fileId; COMMIT; SELECT fileId, @versionNumber `versionNumber`; END$$ I'm calling the proc using Dapper, but I've debugged into the SqlMapper class and I can see that the reader is not returning anything.

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • How do I prevent a branch from being pushed to another branch in BZR?

    - by cabbey
    We use a dev-test-prod branching scheme with bzr 2. I'd like to setup a bzr hook on the prod branch that will reject a push from the test branch. Looking at the bzr docs, this looks doable, but I'm kinda surprised that my searches don't turn up any one having done it, at least not via any of the keywords I've thought to search by. I'm hoping someone has already gotten this working and can share their path to success. My current thought is to use the pre_change_branch_tip hook to check for the presence of a file on the test branch. If it's present, fail the commit. You may ask, why test for a file, why not just test the branch name? Because I actually need to handle the case where our developers have branched their devel branch, pulled in the shared test branch and are now (erroneously) pushing that test branch to production instead of pushing their feature branch to production. And it seems a billion times easier to look for a file in the new branch than to try to interrogate the sending branch's lineage. So has someone done this? seen it done? or do I get to venture out into the uncharted wasteland that is hook development with bzr? :)

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Efficient update of SQLite table with many records

    - by blackrim
    I am trying to use sqlite (sqlite3) for a project to store hundreds of thousands of records (would like sqlite so users of the program don't have to run a [my]sql server). I have to update hundreds of thousands of records sometimes to enter left right values (they are hierarchical), but have found the standard update table set left_value = 4, right_value = 5 where id = 12340; to be very slow. I have tried surrounding every thousand or so with begin; .... update... update table set left_value = 4, right_value = 5 where id = 12340; update... .... commit; but again, very slow. Odd, because when I populate it with a few hundred thousand (with inserts), it finishes in seconds. I am currently trying to test the speed in python (the slowness is at the command line and python) before I move it to the C++ implementation, but right now this is way to slow and I need to find a new solution unless I am doing something wrong. Thoughts? (would take open source alternative to SQLite that is portable as well)

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  • VisualSVN How to roll back the revision number ?

    - by Ita
    The company I work in has suffered a major server failure. During this failure the SVN Repository was lost. But there is still hope ! We have an old backup of the repository which I've managed to successfully restore using VisualSVN. The problem I'm facing now is that I can't update / commit pre-failure checkedout folders. The reason for this problem is that for instance: a local folder has a revision number of 2361, while the repository itself holds a revision number of 2290, which is older. Is there a way to deal with this issue ? Can I some how change the revision numbers on either the local copy or the server copy? A few points: I'm using TortoiseSVN 1.6.6. I can checkout folders from the repo and the connection is active. I've picked one of my folders and used the Relocate option on it. This helped me see that there is something wrong with the revision number I've experimented a bit with the merge option but this lead me now where special. (I'm open for suggestions ) Thank you for your time, Ita

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