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  • WPF Listbox - Empty List Display Message

    - by David Ward
    Can anyone suggest the best way to display a Textblock (with a text such as "List Empty") so that it's visibility is bound to the Items.Count. I have tried the following code and can't get it to work, so think that I must be doing it wrong. <ListBox x:Name="lstItems" ItemsSource="{Binding ListItems}"> </ListBox> <TextBlock Margin="4" FontStyle="Italic" FontSize="12" Text="List is empty" Visibility="Collapsed"> <TextBlock.Style> <Style TargetType="{x:Type TextBlock}"> <Style.Triggers> <DataTrigger Binding="{Binding ElementName=lstItems, Path=Items.Count}" Value="0"> <Setter Property="Visibility" Value="Visible" /> </DataTrigger> </Style.Triggers> </Style> </TextBlock.Style> </TextBlock>

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  • jQuery tabs using radio buttons instead of list navigation

    - by caleb
    I'm following a tutorial to create a simple jquery tabs show/hide content. Wondering if there's a way to re-engineer it to use a list of radio buttons instead of a list? Tutorial here: http://www.sohtanaka.com/web-design/simple-tabs-w-css-jquery/ My js: $(".tab_content").hide(); //Hide all content $("ul.tabs li:first").addClass("active").show(); //Activate first tab $(".tab_content:first").show(); //Show first tab content //On Click Event $("ul.tabs li").click(function() { $("ul.tabs li").removeClass("active"); //Remove any "active" class $(this).addClass("active").children("input[@type=radio]").click(); //Add "active" class to selected tab $(".tab_content").hide(); //Hide all tab content var activeTab = "#" + $(this).children("input").attr("value"); //Find the href attribute value to identify the active tab + content $(activeTab).fadeIn(); //Fade in the active ID content return false; }); My HTML: <ul class="tabs"> <li><input type="radio" name="card" id="one" value="gallery" /> <label for="one">gallery</label></li> <li><input type="radio" name="card" id="two" value="submit" /> <label for="two">submit</label></li> <li><input type="radio" name="card" id="three" value="resources" /> <label for="three">resources</label></li> <li><input type="radio" name="card" id="four" value="contact" /> <label for="four">contact</label></li> </ul> <div class="tab_container"> <div id="gallery" class="tab_content"> <h2>Gallery</h2> </div> <div id="submit" class="tab_content"> <h2>Submit</h2> </div> <div id="resources" class="tab_content"> <h2>Resources</h2> </div> <div id="contact" class="tab_content"> <h2>Contact</h2> </div> </div> I'm able to actively select the radio button within the list, but not activate the actual div.

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  • WPF Show Open TabItem Names in a List View

    - by mr justinator
    I'm trying to display a list of open tab names in a listview or listbox (recommendations?). Been going through the different type of binding options and I'm able to bind to a single tab name but it displays vertical instead of horizontal. Here is my XAML: <ListView DockPanel.Dock="Left" Height="352" Name="listView1" Width="132" ItemsSource="{Binding ElementName=RulesTab, Path=Name}" IsSynchronizedWithCurrentItem="True" FlowDirection="LeftToRight" HorizontalAlignment="Left" HorizontalContentAlignment="Left" DataContext="{Binding}"> Any pointers would be greatly appreciated as I'd like to be able to see a list of all the tabs open and then double click on one to bring the tab into focus. Many thanks!

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  • Java List use through use of JSTL <c:forEach>

    - by Mark Lewis
    Hello If I have a JSF backing bean return an object of type ArrayList, I should be able to use to iterate over the elements in the list. Each element contains a map and although the question of how to access the map content through JSTL has been answered here, if I pass an array of such maps, I can't find how to iterate over them and still access the map content using JSTL. There's documentation which refers to simple iterators but not to those whose items are themselves maps. BalusC, I'm not trying to force the issue, just that I've been looking at this all day, and still cannot seem to be able to output the contents of my data structure through jsp (only on the console). This as a separate question still has merit. If anyone can give me a simple example of how a java List is iterated over in JSP I'd be massively appreciative. Mark

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  • How to change font/number/bullet format for the whole list

    - by Nam Gi VU
    Hi, Let's look at a sample word 2010 file here. In this file you can see that the first group of text has their indent modified. The 2nd, 3rd group keep their default format. I want to apply the changed I've made in the group 1st so group 2nd and 3rd and for the new group I'm going to add instead of recieving the default indent. How can I do that? ps. Currently what I have to do is quite boring: Copy group 1 and paste to create new group to get the formatted, then remove the old text, adding new text :(

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  • LINQ OrderBy: best search results at top of results list

    - by p.campbell
    Consider the need to search a list of Customer by both first and last names. The desire is to have the results list sorted by the Customer with the most matches in the search terms. FirstName LastName ---------- --------- Foo Laurie Bar Jackson Jackson Bro Laurie Foo Jackson Laurie string[] searchTerms = new string[] {"Jackson", "Laurie"}; //want to find those customers with first, last or BOTH names in the searchTerms var matchingCusts = Customers .Where(m => searchTerms.Contains(m.FirstName) || searchTerms.Contains(m.LastName)) .ToList(); /* Want to sort for those results with BOTH FirstName and LastName matching in the search terms. Those that match on both First and Last should be at the top of the results, the rest who match on one property should be below. */ return matchingCusts.OrderBy(m=>m); Desired Sort: Jackson Laurie (matches on both properties) Foo Laurie Bar Jackson Jackson Bro Laurie Foo How can I achieve this desired functionality with LINQ and OrderBy / OrderByDescending?

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  • DataSource Control for List<T>

    - by diamandiev
    I know all the data source controls like LinqDataSource, ObjectDataSource etc. They are cool but they are intended to be used in conjunction with a database. I actually need a simple data source control that can work with a plain old List (That supports delete, update, select, insert ofcourse). I was thinking of using the objectdatasource but the select, update... methods are not present in the List. So is there such a control or do i have to roll my own? Should i inherit from the objectdatasource?

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  • List all possible combinations of k integers between 1...n (n choose k)

    - by Asaf R
    Hi, Out of no particular reason I decided to look for an algorithm that produces all possible choices of k integers between 1...n, where the order amongst the k integer doesn't matter (the n choose k thingy). From the exact same reason, which is no reason at all, I also implemented it in C#. My question is: Do you see any mistake in my algorithm or code? And, more importantly, can you suggest a better algorithm? Please pay more attention to the algorithm than the code itself. It's not the prettiest code I've ever written, although do tell if you see an error. EDIT: Alogirthm explained - We hold k indices. This creates k nested for loops, where loop i's index is indices[i]. It simulates k for loops where indices[i+1] belongs to a loop nested within the loop of indices[i]. indices[i] runs from indices[i - 1] + 1 to n - k + i + 1. CODE: public class AllPossibleCombination { int n, k; int[] indices; List<int[]> combinations = null; public AllPossibleCombination(int n_, int k_) { if (n_ <= 0) { throw new ArgumentException("n_ must be in N+"); } if (k_ <= 0) { throw new ArgumentException("k_ must be in N+"); } if (k_ > n_) { throw new ArgumentException("k_ can be at most n_"); } n = n_; k = k_; indices = new int[k]; indices[0] = 1; } /// <summary> /// Returns all possible k combination of 0..n-1 /// </summary> /// <returns></returns> public List<int[]> GetCombinations() { if (combinations == null) { combinations = new List<int[]>(); Iterate(0); } return combinations; } private void Iterate(int ii) { // // Initialize // if (ii > 0) { indices[ii] = indices[ii - 1] + 1; } for (; indices[ii] <= (n - k + ii + 1); indices[ii]++) { if (ii < k - 1) { Iterate(ii + 1); } else { int[] combination = new int[k]; indices.CopyTo(combination, 0); combinations.Add(combination); } } } } I apologize for the long question, it might be fit for a blog post, but I do want the community's opinion here. Thanks, Asaf

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  • Global Address List, Multiple All Address Lists in CN=Address Lists Container

    - by Jonathan
    When my colleges (that was way before my time here) updated Exchange 2000 to 2003 a English All Address Lists appeared in addition to the German variant. The English All Address Lists have German titled GAL below it. This has just been a cosmetic problem for the last few years. Now as we are in the process of rolling out Exchange 2010 this causes some issues. Exchange 2010 picked the wrong i.e. English Address Lists Container to use. In ADSI Editor we see CN=All Address Lists,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain and CN=Alle Adresslisten,CN=Address Lists Container,CN=exchange org,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain. In the addressBookRoots attribute of CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=domain both address lists were stored as values. We removed the English variant from addressBookRoots and restarted all (old and new) Exchange servers. User with mailboxes on the Exchange 2003 now only sees the German variant. Exchange 2010 is still stuck with the English/Mixed variant as are Users on Exchange 2010. Our goal would be to have Outlook display the German title of All Address Lists and get rid of the wrong Address Lists Container.

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  • Accessing A Shared Directory That Has An Account White List

    - by Xan
    I'm on a LAN here at work and I have my desktop sharing some of my project folders. I can access the computer via \\ComputerIP\, but I can't actually open any of the folders. Upon attempting, I get the error: Windowns cannot access \ComputerIP\ProjectFolder You do not have permission to access \ComputerIP\ProjectFolder. Contact your network administrator to request access. For more information about permissions, see Windows Help and Support Now, this is understood considering I've made it so that you had to utilize the "Project" credentials to connect. I have a user account on my main computer hosting these shared folders that gives full access to the folders if you are this "Project" user. I can Remote Desktop the computer just fine from my laptop using either set of credentials. When I try to open these folders it doesn't give me the option to attempt to apply any credentials like it does when I remote desktop. How am I supposed to gain access to these folders?

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  • SVN Authz - Any Subfolder permission or List contents

    - by Jaspa Jones
    Goal Basically I would like SVN users to be able to browse through a directory containing a lot of subfolders without allowing them to read its subfolders. [/] * = r [/Projects] * = # Allow viewing contents, but not reading. At least to be able to see Project1. [/Projects/Project1] my_group = rw Problem The problem is that there are a lot of projects. I could add every other project and make them disappear for the user, but that would be a lot of work to maintain. It would look like this: [/] * = r [/Projects] * = r [/Projects/Project1] my_group = rw [/Projects/Project2] * = [/Projects/Project3] * = [/Projects/Project4] * = [/Projects/Project5] * = It would be nice if I could use this: [/Projects/*] * = Any ideas? Thanks in advance, Jaspa Jones

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  • PySide / PyQt QStyledItemDelegate list in table

    - by danodonovan
    Dear All, I'm trying to create a table of lists in Python with Qt (PySide/PyQt - matters not) and my lists are squashed into the table cells. Is there a way to get the list delegates to 'pop out' of their cells? I've attached a simple code snippet - replace 'PySide' with 'PyQt4' depending on your preference from PySide import QtCore, QtGui class ListDelegate(QtGui.QStyledItemDelegate): def createEditor(self, parent, option, index): editor = QtGui.QListWidget(parent) for i in range( 12 ): editor.addItem('list item %d' % i) return editor if __name__ == '__main__': import sys app = QtGui.QApplication(sys.argv) model = QtGui.QStandardItemModel(2, 2) tableView = QtGui.QTableView() delegate = ListDelegate() tableView.setItemDelegate(delegate) tableView.setModel(model) for row in range(2): for column in range(2): item = QtGui.QStandardItem( 'None' ) model.setItem(row, column, item) tableView.setWindowTitle('example') tableView.show() sys.exit(app.exec_()) If you hadn't guessed I'm pretty new to this Qt lark Thanks in advance, Dan

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  • Comparing multiple entity properties against list of entities

    - by roosteronacid
    Consider this snippet of code: var iList = new List<Entities.Ingredient> { new Entities.Ingredient { Name = "tomato", Amount = 2.0 }, new Entities.Ingredient { Name = "cheese", Amount = 100.0 } }; var matches = new DataContext().Ingredients.Where(i => Comparer(i, iList)); private Boolean Comparer(Entities.Ingredient i, List<Entities.Ingredient> iList) { foreach (var i in iList) { if (i.Name == iList.Name && i.Amount >= iList.Amount) return true; } return false; } Is there a more efficient way of doing this? Preferably without being too verbose; from x in y select z... If thats at all possible.

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  • T-SQL How To: Compare and List Duplicate Entries in a Table

    - by Dan7el
    SQL Server 2000. Single table has a list of users that includes a unique user ID and a non-unique user name. I want to search the table and list out any users that share the same non-unique user name. For example, my table looks like this: ID User Name Name == ========= ==== 0 parker Peter Parker 1 parker Mary Jane Parker 2 heroman Joseph (Joey) Carter Jones 3 thehulk Bruce Banner What I want to do is do a SELECT and have the result set be: ID User Name Name == ========= ==== 0 parker Peter Parker 1 parker Mary Jane Parker from my table. I'm not a T-SQL guru. I can do the basic joins and such, but I'm thinking there must be an elegant way of doing this. Barring elegance, there must be ANY way of doing this. I appreciate any methods that you can help me with on this topic. Thanks! ---Dan---

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  • How to list my blog to google search

    - by messy123
    Hi, i had created a blog in blogspot.com, after few days later i updated. but my blog is not appearing in google search. even if i give the full link of blog its not coming.. i have some other blogs, it works well.. i dont no whats wrong with new one.. can any one know what to do

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  • Can not read and save a number from/into an .plist

    - by Flocked
    Hello, I created a property list with the name propertys.plist. Then I wrote this: NSString *path = [[NSBundle mainBundle] bundlePath]; NSString *finalPath = [path stringByAppendingPathComponent:@"speicherung.plist"]; NSMutableArray *plistData = [[NSMutableArray arrayWithContentsOfFile:finalPath] retain]; int a = [plistData objectAtIndex:1]; NSLog(@"%i", a); // returns 41386032, but the right number is 0 a = a + 1; NSNumber *ff = [NSNumber numberWithInt:a]; [plistData insertObject:ff atIndex:1]; NSLog(@"%@", [plistData objectAtIndex:1]); // returns 41386033 [plistData writeToFile:finalPath atomically:YES]; My app always get the wrong number. Why?

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  • Trying to debug a symfony app showing the list of all the functions called, debug_backtrace() doesn'

    - by user248959
    Hi, im trying to debug a symfony app. I've added a debug_backtrace() calling to this function below. It outputs a list of functions called, but the save() function (that is just before the debug_backtrace() calling) is not that list.. why? any other way to debug that shows more things, in this case the save() calling ? protected function processForm(sfWebRequest $request, sfForm $form) { $form->bind($request->getParameter($form->getName())); if ($form->isValid()) { $sf_guard_user = $form->save(); var_dump(debug_backtrace()); die("fsdgsgsdf"); $this->redirect('guardausuario/edit?id='.$sf_guard_user- >getId()); } } Regards Javi

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  • SSRS/Sharepoint - Reports made in Report Builder not being list in Sharepoint Web Part

    - by Greg_the_Ant
    I followed the steps here to integrate reporting services with sharepoint in native mode. I made a page in Sharepoint with the report explorer web part and everything is working. The issue is when I create a report with the web based report builder tool, it will show up in the report manager page, but not show up in the report explorer web part on the share point page. New reports I upload using report manager do show up. Does anyone have any ideas? I'm really stuck.

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  • List symlinks in specific relative directories

    - by Clinton Blackmore
    I have a server that shares out user home folders over the network. Each user has a Cache folder. Sometimes a symlink is used to redirect this folder to the hard drive of whichever machine they are using (and sometimes that doesn't work and they have a broken symlink [which is a matter for another day].) I'm trying to find out which users have symlinks and which don't. Within the shared folder, to get to the Cache folder you would substitute folders like so: $GRADE/$USERNAME/Library/Caches Right now I'm searching to see which users have symlinks and which do not. I've come up with: cd /path/to/shared/home/folders sudo find . -name "Caches" -exec ls -ld {} \; and get results like this: lrwxr-xr-x@ 1 name0 ES_Students 27 Jan 18 11:05 ./CES_Grade_03/name0/Library/Caches -> /tmp/name0/Library/Caches drwx------ 11 name1 ES_Students 374 Dec 8 15:44 ./CES_Grade_03/name1/Library/Caches lrwxr-xr-x@ 1 name2 ES_Students 27 Feb 23 14:27 ./CES_Grade_03/name2/Library/Caches -> /tmp/name2/Library/Caches drwx------ 17 name3 ES_Students 578 Jan 25 11:13 ./CES_Grade_03/name3/Library/Caches drwx------ 12 name4 ES_Students 408 Mar 22 13:09 ./CES_Grade_03/name4/Library/Caches but it nags at me that there must be a better way. Yes, it is good enough, and a one-off task, but I want to know how to do it right! Surely, I should be able to do something like: cd /path/to/shared/home/folders sudo ls -ld **/**/Library/Caches I'm afraid that I don't know the proper syntax or if there is a recursive folder-replacing wildcard format in bash, and my google-fu failed me. So, how do I properly formulate the search?

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  • Prolog Program for a recordings database

    - by RP
    I have three types of facts: album(code, artist, title, date). songs(code, songlist). musicians(code, list). Example: album(123, 'Rolling Stones', 'Beggars Banquet', 1968). songs(123, ['Sympathy for the Devil', 'Street Fighting Man']). musicians(123, [[vocals, 'Mick Jagger'], [guitar, 'Keith Richards', 'Brian Jones']]. I need to create these 4 rules: together(X,Y) This succeeds if X and Y have played on the same album. artistchain(X,Y) This succeeds if a chain of albums exists from X to Y; two musicians are linked in the chain by 'together'. role(X,Y) This succeeds if X had role Y (e.g. guitar) ever. song(X,Y) This succeeds if artist X recorded song Y. Any help?

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  • List of resources to learn cassandra

    - by Alfred
    Hi all, Lately I have been reading a lot of blog topics about big sites(facebook, twitter, digg, reddit to name a few) using cassandra as their datastore instead of MysqL. I would like to gather a list of resources to learn using cassandra. Hopefully some videos or podcasts explaining how to use cassandra. My list Twissandra - Twissandra is an example project, created to learn and demonstrate how to use Cassandra. Running the project will present a website that has similar functionality to Twitter WTF is a supercolumn - WTF is a SuperColumn? An Intro to the Cassandra Data Model I hope there are resources to watch howto use cassandra. Many thanks, Alfred

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  • Thinkpad Motherboard Component List

    - by Nirmal
    I got an IBM Thinkpad R51 notebook and it's not working. When opened I found that an IC next to the battery has burnt. The worst part is that the IC number is no more present on it due to the burning. Where could I get the schematics of such motherboards? Will the schematics have the part number? Please help. Thank you.

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