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  • Create PDF in memory instead of physical file

    - by acadia
    How do one create PDF in memorystream instead of physical file using itextsharp. The code below is creating actual pdf file. Instead how can I create a byte[] and store it in the byte[] so that I can return it through a function using iTextSharp.text; using iTextSharp.text.pdf; Document doc = new Document(iTextSharp.text.PageSize.LETTER, 10, 10, 42, 35); PdfWriter wri = PdfWriter.GetInstance(doc, new FileStream("c:\\Test11.pdf", FileMode.Create)); doc.Open();//Open Document to write Paragraph paragraph = new Paragraph("This is my first line using Paragraph."); Phrase pharse = new Phrase("This is my second line using Pharse."); Chunk chunk = new Chunk(" This is my third line using Chunk."); doc.Add(paragraph); doc.Add(pharse); doc.Add(chunk); doc.Close(); //Close document

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  • How do i have 4GB of video memory with a 1GB video card?

    - by Tomas Spc Yaczik
    I ran the direct X diagnostic tool to take a look at my graphics capabilities and its telling me that the approximate video memory is clocked in at 4096MB. That doesn't make any sense, how is that possible? The only things that i can think of were that DirectX was inaccurate so i looked at the graphics statistics of my computer on CPU-Z which was included with the motherboard and that's telling me i have "negative" 1988MB. Not only is that not 4096MB, but its giving me a negative number and i know for a fact that you can't have a negative amount of memory???!!! The only things i can think of that would be amplifying my video memory output is the PCIe 3.0 bus, or that the motherboard is somehow including the on board video chip set with the video card which only then is only 2GB of video memory, which still has to be being amplified by something. Any suggestions?

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  • Create PDF in memory instead of physical file using C#

    - by acadia
    Hello, How do one create PDF in memorystream instead of physical file using itextsharp. The code below is creating actual pdf file. Instead how can I create a byte[] and store it in the byte[] so that I can return it through a function using iTextSharp.text; using iTextSharp.text.pdf; Document doc = new Document(iTextSharp.text.PageSize.LETTER, 10, 10, 42, 35); PdfWriter wri = PdfWriter.GetInstance(doc, new FileStream("c:\\Test11.pdf", FileMode.Create)); doc.Open();//Open Document to write Paragraph paragraph = new Paragraph("This is my first line using Paragraph."); Phrase pharse = new Phrase("This is my second line using Pharse."); Chunk chunk = new Chunk(" This is my third line using Chunk."); doc.Add(paragraph); doc.Add(pharse); doc.Add(chunk); doc.Close(); //Close document

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  • argv Memory Allocation

    - by Joshua Green
    I was wondering if someone could tell me what I am doing wrong that I get this Unhandled Exception error message: 0xC0000005: Access violation reading location 0x0000000c. with a green pointer pointing at my first Prolog code (fid_t): Here is my header file: class UserTaskProlog { public: UserTaskProlog( ArRobot* r ); ~UserTaskProlog( ); protected: int cycles; char* argv[ 1 ]; term_t tf; term_t tx; term_t goal_term; functor_t goal_functor; ArRobot* robot; void logTask( ); }; And here is my main code: UserTaskProlog::UserTaskProlog( ArRobot* r ) : robot( r ), robotTaskFunc( this, &UserTaskProlog::logTask ) { cycles = 0; argv[ 0 ] = "libpl.dll"; argv[ 1 ] = NULL; PL_initialise( 1, argv ); PlCall( "consult( 'myPrologFile.pl' )" ); robot->addSensorInterpTask( "UserTaskProlog", 50, &robotTaskFunc ); } UserTaskProlog::~UserTaskProlog( ) { robot->remSensorInterpTask( &robotTaskFunc ); } void UserTaskProlog::logTask( ) { cycles++; fid_t fid = PL_open_foreign_frame( ); tf = PL_new_term_ref( ); PL_put_integer( tf, 5 ); tx = PL_new_term_ref( ); goal_term = PL_new_term_ref( ); goal_functor = PL_new_functor( PL_new_atom( "factorial" ), 2 ); PL_cons_functor( goal_term, goal_functor, tf, tx ); int fact; if ( PL_call( goal_term, NULL ) ) { PL_get_integer( tx, &fact ); cout << fact << endl; } PL_discard_foreign_frame( fid ); } int main( int argc, char** argv ) { ArRobot robot; ArArgumentParser argParser( &argc, argv ); UserTaskProlog talk( &robot ); } Thank you,

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  • daynamic 2d array in c++ and memory leaks

    - by SepiDev
    Hi guys, i wrote this code, it runs ok, but when i check it under Valgrind it catches 2 problems, since i can not interpret valgrind's messages i will appreciate if anyone explain me more and tell me where is the problem!!! here is the code: #include <iostream> #define width 70000 #define height 10000 using namespace std; int main(void) { int** pint; pint = new int*[height]; for(int i = 0; i < height; i++) pint[i] = new int[width]; for(int i = 0; i < height; i++){ delete[] pint[i]; pint[i] = NULL; } delete[] pint; pint = NULL; return 1; }

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  • how can we find that this processor supports how much memory?????

    - by Zia ur Rahman
    I have just started the Assembly language programming and in the first lecture our teacher told us about intel 8080 and intel 8085 and he said there was 64k memory with these processor. Now i want to know that how we find this amount of memory with specific processor, for example i have a processor 1.8 Ghz , now how i can find out the amount of memory that can be used with this processor. what i am trying to ask is tell me the method how we can find out this amount of memory?

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  • Best Processor for MediaSmart Server?

    - by Kent Boogaart
    I'm trying to figure out what the best possible processor is that I can stick in my HP MediaSmart server. I'm clueless when it comes to correlating CPUs to motherboards. I suspect it's the socket type I care about, but I worry that there's more to it. CPU-Z gives me (excerpt): Processors Information ------------------------------------------------------------------------- Processor 1 ID = 0 Number of cores 1 (max 1) Number of threads 1 (max 1) Name AMD Sempron LE-1150 Codename Sparta Specification AMD Sempron(tm) Processor LE-1150 Package Socket AM2 (940) CPUID F.F.1 Extended CPUID F.7F Brand ID 1 Core Stepping DH-G1 Technology 65 nm Core Speed 1000.0 MHz Multiplier x FSB 5.0 x 200.0 MHz HT Link speed 800.0 MHz Stock frequency 2000 MHz Instructions sets MMX (+), 3DNow! (+), SSE, SSE2, SSE3, x86-64 L1 Data cache 64 KBytes, 2-way set associative, 64-byte line size L1 Instruction cache 64 KBytes, 2-way set associative, 64-byte line size L2 cache 256 KBytes, 16-way set associative, 64-byte line size FID/VID Control yes Max FID 10.0x Max VID 1.350 V P-State FID 0x2 - VID 0x12 (5.0x - 1.100 V) P-State FID 0xA - VID 0x0C (9.0x - 1.250 V) P-State FID 0xC - VID 0x0A (10.0x - 1.300 V) K8 Thermal sensor yes K8 Revision ID 6.0 Attached device PCI device at bus 0, device 24, function 0 Attached device PCI device at bus 0, device 24, function 1 Attached device PCI device at bus 0, device 24, function 2 Attached device PCI device at bus 0, device 24, function 3 Chipset ------------------------------------------------------------------------- Northbridge SiS 761GX rev. 02 Southbridge SiS 966 rev. 59 Graphic Interface AGP AGP Revision 3.0 AGP Transfer Rate 8x AGP SBA supported, enabled Memory Type DDR2 Memory Size 2048 MBytes Channels Single Memory Frequency 200.0 MHz (CPU/5) CAS# latency (CL) 5.0 RAS# to CAS# delay (tRCD) 5 RAS# Precharge (tRP) 5 Cycle Time (tRAS) 15 Bank Cycle Time (tRC) 21 Command Rate (CR) 1T DMI ------------------------------------------------------------------------- DMI BIOS vendor Phoenix Technologies, LTD version R03 date 05/08/2008 DMI System Information manufacturer HP product MediaSmart Server version unknown serial CN68330DGH UUID A482007B-B0CC7593-DD11736A-407B7067 DMI Baseboard vendor Wistron model SJD4 revision A.0 serial unknown DMI System Enclosure manufacturer HP chassis type Desktop chassis serial unknown DMI Processor manufacturer AMD model AMD Sempron(tm) Processor LE-1150 clock speed 2000.0 MHz FSB speed 200.0 MHz multiplier 10.0x DMI Memory Controller correction 64-bit ECC Max module size 4096 MBytes DMI Memory Module designation A0 size 2048 MBytes (double bank) DMI Memory Module designation A1 DMI Memory Module designation A2 DMI Memory Module designation A3 DMI Port Connector designation PS/2 Mouse (internal) port type Mouse Port connector PS/2 connector PS/2 DMI Port Connector designation USB0 (external) port type USB DMI Physical Memory Array location Motherboard usage System Memory correction None max capacity 16384 MBytes max# of devices 4 DMI Memory Device designation A0 format DIMM type unknown total width 64 bits data width 64 bits size 2048 MBytes DMI Memory Device designation A1 format DIMM type unknown total width 64 bits data width 64 bits DMI Memory Device designation A2 format DIMM type unknown total width 64 bits data width 64 bits DMI Memory Device designation A3 format DIMM type unknown total width 64 bits data width 64 bits How do I figure out what options I have for an upgrade?

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  • Slow insert speed in Postgresql memory tablespace

    - by Prashant
    Hi, I have a requirement where I need to store the records at rate of 10,000 records/sec into a database (with indexing on a few fields). Number of columns in one record is 25. I am doing a batch insert of 100,000 records in one transaction block. To improve the insertion rate, I changed the tablespace from disk to RAM.With that I am able to achieve only 5,000 inserts per second. I have also done the following tuning in the postgres config: Indexes : no fsync : false logging : disabled Other information: - Tablespace : RAM - Number of columns in one row : 25 (mostly integers) - CPU : 4 core, 2.5 GHz - RAM : 48 GB I am wondering why a single insert query is taking around 0.2 msec on average when database is not writing anything on disk (as I am using RAM based tablespace). Is there something I am doing wrong? Help appreciated. Prashant

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  • Database which only holds indexes and last X records in memory?

    - by Xeoncross
    I'm looking for a data store that is very memory efficient while still allowing many object changes per second and disregarding ACID compliance for the last X records. I need this database for a server with not much memory and I can make a key-value store, document, or SQL database work. The idea is that indexes/keys are the only thing I need in memory and all the actual values/objects/rows can be saved on disk do to the low read rate (I just want index/key lookup to be fast). I also don't want records constantly being flushed to disk, so I would like the last X number of records to be held in memory so that 100 or so of them can all be written at once. I don't care if I lose the last 10 seconds worth of objects/values. I do care if the database as a whole is in danger of becoming corrupt. Is there a data-store like this?

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  • In-Memory SQL-CE

    - by harley.333
    Is there a way to connect to a SQL-CE database as a stream? Specifically, our ASP.Net application builds small SDF at runtime for off-line needs. When the user is done with his off-line duties, he uploads the SDF and the application imports the new and updated data. No problems there. Currently, we're saving the uploaded SDF to the web-server's hard-drive and connecting to the file. Can we connect to the uploaded SDF without saving it to the hard-drive? We are using the DbProviderFactory.CreateConnection method, but we're open to suggestions.

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  • Memory leak in Qt signal and slots

    - by Ajay
    Hello, I am running valgrind on my Qt code,and even on successful exit of the application, get the following report from valgrind 8,832 bytes in 92 blocks are still reachable in loss record 12 of 12 at 0x4025390: operator new(unsigned int) (vg_replace_malloc.c:214) ==3339== by 0x4B75F05: QMutex::QMutex(QMutex::RecursionMode) (qmutex.cpp:123) ==3339== by 0x4B77602: QMutexPool::get(void const*) (qmutexpool.cpp:137) ==3339== by 0x4CA0EC2: signalSlotLock(QObject const*) (qobject.cpp:112) ==3339== by 0x4CA3939: QMetaObjectPrivate::connect(QObject const*, int, QObject const*, int, int, int*) (qobject.cpp:2900) ==3339== by 0x4CA5C00: QObject::connect(QObject const*, char const*, QObject const*, char const*, Qt::ConnectionType) (qobject.cpp:2599) I disconnect all signal connections and also delete the objects. The above mentioned leak increases if i increase the amount of signal and slot connections? Can anybody help with this?

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  • Memory leak problem. iPhone SDK

    - by user326375
    Hello, i've got a problem, i cannot solve it, just recieving error: Program received signal: “0”. The Debugger has exited due to signal 10 (SIGBUS).The Debugger has exited due to signal 10 (SIGBUS). Here is some method, if i comment it out, problem goes aways - (void)loadTexture { const int num_tex = 10; glGenTextures(num_tex, &textures[0]); //TEXTURE #1 textureImage[0] = [UIImage imageNamed:@"wonder.jpg"].CGImage; //TEXTURE #2 textureImage[1] = [UIImage imageNamed:@"wonder.jpg"].CGImage; //TEXTURE #3 textureImage[2] = [UIImage imageNamed:@"wall_eyes.jpg"].CGImage; //TEXTURE #4 textureImage[3] = [UIImage imageNamed:@"wall.jpg"].CGImage; //TEXTURE #5 textureImage[4] = [UIImage imageNamed:@"books.jpg"].CGImage; //TEXTURE #6 textureImage[5] = [UIImage imageNamed:@"bush.jpg"].CGImage; //TEXTURE #7 textureImage[6] = [UIImage imageNamed:@"mushroom.jpg"].CGImage; //TEXTURE #8 textureImage[7] = [UIImage imageNamed:@"roots.jpg"].CGImage; //TEXTURE #9 textureImage[8] = [UIImage imageNamed:@"roots.jpg"].CGImage; //TEXTURE #10 textureImage[9] = [UIImage imageNamed:@"clean.jpg"].CGImage; for(int i=0; i<num_tex; i++) { NSInteger texWidth = CGImageGetWidth(textureImage[i]); NSInteger texHeight = CGImageGetHeight(textureImage[i]); GLubyte *textureData = (GLubyte *)malloc(texWidth * texHeight * 4); CGContextRef textureContext = CGBitmapContextCreate(textureData, texWidth, texHeight, 8, texWidth * 4, CGImageGetColorSpace(textureImage[i]), kCGImageAlphaPremultipliedLast); CGContextDrawImage(textureContext, CGRectMake(0.0, 0.0, (float)texWidth, (float)texHeight), textureImage[i]); CGContextRelease(textureContext); glBindTexture(GL_TEXTURE_2D, textures[i]); glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, texWidth, texHeight, 0, GL_RGBA, GL_UNSIGNED_BYTE, textureData); glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR); glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR); free(textureData); } } anyone can help me with releasing/deleting objects in this method? Thanks.

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  • Memory leak at Autorelease pool in Iphone sdk

    - by monish
    Hi guys, I am getting leak at [pool release]; My code here is: #pragma mark UISearchBarDelegate delegate methods - (void)performSearch:(UISearchBar *)aSearchBar { NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; artistName= [aSearchBar.text stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]; if ([artistName length] > 0) { [UIApplication sharedApplication].networkActivityIndicatorVisible = YES; LyricsAppDelegate* appDelegate = (LyricsAppDelegate*) [ [UIApplication sharedApplication] delegate]; artistsList=[appDelegate doSearch:artistName ]; [theTableView reloadData]; [UIApplication sharedApplication].networkActivityIndicatorVisible = NO; [UIApplication sharedApplication].networkActivityIndicatorVisible = NO; [aSearchBar resignFirstResponder]; } else { [aSearchBar resignFirstResponder]; } [NSThread exit]; [pool release]; } - (void)searchBarSearchButtonClicked:(UISearchBar *)aSearchBar { @try { [NSThread detachNewThreadSelector:@selector(performSearch:) toTarget:self withObject:aSearchBar]; [aSearchBar resignFirstResponder]; } @catch (NSException * e) { NSLog(@"\n caught an exception"); } @finally { } } Here I am getting leak at [pool release]; in performSearch method. How can I solve this. Anyone's help will be much appreciated. Thank you, Monish.

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  • Redis, it's memory limit and persistance question?

    - by Kirzilla
    Hello, I'm rather new to Redis and before using it I'd like to learn some important (as for me) details on it. So.... Redis is using RAM and HDD for storing data. RAM is used as fast read/write storage, HDD is used to make this data persistant. When Redis is started it loads all data from HDD to RAM or it loads only often queried data to the RAM? What if I have 500Mb Redis storage on HDD, but I have only 100Mb or RAM for Redis. Where can I read about it? Thank you PS: Sorry for my English

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  • Read vector into CUDA shared memory

    - by Ben
    I am new to CUDA and programming GPUs. I need each thread in my block to use a vector of length ndim. So I thought I might do something like this: extern __shared__ float* smem[]; ... if (threadIddx.x == 0) { for (int d=0; d<ndim; ++d) { smem[d] = vector[d]; } } __syncthreads(); ... This works fine. However, I seems wasteful that a single thread should do all loading, so I changed the code to if (threadIdx.x < ndim) { smem[threadIdx.x] = vector[threadIdx.x]; } __syncthreads(); which does not work. Why? It gives different results than the above code even when ndim << blockDim.x.

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  • Why does Google Reader use up so much memory?

    - by Ivo
    I'm running the dev version of Chrome and just found out I could see the memory usage of every tab (press shift + ESC to find out yourself). Turns out the Shockwave Flash plugin uses 240 MB of memory and 27% of CPU while having open Google Reader. Killing this page brings it down to 50 MB. I reckon it builts up after reading through about 100 feeds. So my question is: why does it take up so much memory and what should I do to diminish it? Why I care? I often don't restart my browser (or laptop for that matter) and keep the Google Reader tab open for long periods of time. The memory does start to add up that way. Plus I have the feeling, perhaps incorrect, that it slows things down as well looking at the CPU usage. Side note: using Chrome 4 on Windows 7 (32 bit)

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  • Objective-C Memory Question

    - by Winder
    Is it a leak if I have a view controller and allocate the view like this: self.view = [[UIView alloc] initWithFrame:frame]; Do I need to do something like this: UIView *v = [[UIView alloc] initWithFrame:frame]; self.view = v; [v release];

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  • imageWithCGImage and memory

    - by Adam Ernst
    If I use [UIImage imageWithCGImage:], passing in a CGImageRef, do I then release the CGImageRef or does UIImage take care of this itself when it is deallocated? The documentation isn't entirely clear. It says "This method does not cache the image object." Originally I called CGImageRelease on the CGImageRef after passing it to imageWithCGImage:, but that caused a malloc_error_break warning in the Simulator claiming a double-free was occurring.

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  • Memory over-release problem when I am animating UIView

    - by Sheehan Alam
    I have enabled NSZombie's and I am getting the following message in my console when I am running my application: *** -[UIViewAnimationState release]: message sent to deallocated instance 0xf96d7e0 Here is the method that is performing the animation -(void)loadAvatar:(STObject*)st { NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; avatar.alpha = 0; avatar.frame = avatarRectSmall; avatar.image = [ImageCache getMemoryCachedImageAtUrl:st.avatar_url]; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:.50]; avatar.frame = avatarRectNormal; [avatar setAlpha:1]; [UIView commitAnimations]; [pool release]; pool = nil; } I don't always get a crash, only sometimes. I'm wondering what is getting released?

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  • calling concurrently Graphics.Draw and new Bitmap from memory in thread take long time

    - by Abdul jalil
    Example1 public partial class Form1 : Form { public Form1() { InitializeComponent(); pro = new Thread(new ThreadStart(Producer)); con = new Thread(new ThreadStart(Consumer)); } private AutoResetEvent m_DataAvailableEvent = new AutoResetEvent(false); Queue<Bitmap> queue = new Queue<Bitmap>(); Thread pro; Thread con ; public void Producer() { MemoryStream[] ms = new MemoryStream[3]; for (int y = 0; y < 3; y++) { StreamReader reader = new StreamReader("image"+(y+1)+".JPG"); BinaryReader breader = new BinaryReader(reader.BaseStream); byte[] buffer=new byte[reader.BaseStream.Length]; breader.Read(buffer,0,buffer.Length); ms[y] = new MemoryStream(buffer); } while (true) { for (int x = 0; x < 3; x++) { Bitmap bmp = new Bitmap(ms[x]); queue.Enqueue(bmp); m_DataAvailableEvent.Set(); Thread.Sleep(6); } } } public void Consumer() { Graphics g= pictureBox1.CreateGraphics(); while (true) { m_DataAvailableEvent.WaitOne(); Bitmap bmp = queue.Dequeue(); if (bmp != null) { // Bitmap bmp = new Bitmap(ms); g.DrawImage(bmp,new Point(0,0)); bmp.Dispose(); } } } private void pictureBox1_Click(object sender, EventArgs e) { con.Start(); pro.Start(); } } when Creating bitmap and Drawing to picture box are in seperate thread then Bitmap bmp = new Bitmap(ms[x]) take 45.591 millisecond and g.DrawImage(bmp,new Point(0,0)) take 41.430 milisecond when i make bitmap from memoryStream and draw it to picture box in one thread then Bitmap bmp = new Bitmap(ms[x]) take 29.619 and g.DrawImage(bmp,new Point(0,0)) take 35.540 the code is for Example 2 is why it take more time to draw and bitmap take time in seperate thread and how to reduce the time when processing in seperate thread. i am using ANTS performance profiler 4.3 public Form1() { InitializeComponent(); pro = new Thread(new ThreadStart(Producer)); con = new Thread(new ThreadStart(Consumer)); } private AutoResetEvent m_DataAvailableEvent = new AutoResetEvent(false); Queue<MemoryStream> queue = new Queue<MemoryStream>(); Thread pro; Thread con ; public void Producer() { MemoryStream[] ms = new MemoryStream[3]; for (int y = 0; y < 3; y++) { StreamReader reader = new StreamReader("image"+(y+1)+".JPG"); BinaryReader breader = new BinaryReader(reader.BaseStream); byte[] buffer=new byte[reader.BaseStream.Length]; breader.Read(buffer,0,buffer.Length); ms[y] = new MemoryStream(buffer); } while (true) { for (int x = 0; x < 3; x++) { // Bitmap bmp = new Bitmap(ms[x]); queue.Enqueue(ms[x]); m_DataAvailableEvent.Set(); Thread.Sleep(6); } } } public void Consumer() { Graphics g= pictureBox1.CreateGraphics(); while (true) { m_DataAvailableEvent.WaitOne(); //Bitmap bmp = queue.Dequeue(); MemoryStream ms= queue.Dequeue(); if (ms != null) { Bitmap bmp = new Bitmap(ms); g.DrawImage(bmp,new Point(0,0)); bmp.Dispose(); } } } private void pictureBox1_Click(object sender, EventArgs e) { con.Start(); pro.Start(); }

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  • exchanging 2 memory positions

    - by Jordi
    I am working with OpenCV and Qt, Opencv use BGR while Qt uses RGB , so I have to swap those 2 bytes for very big images. There is a better way of doing the following? I can not think of anything faster but looks so simple and lame... int width = iplImage->width; int height = iplImage->height; uchar *iplImagePtr = (uchar *) iplImage->imageData; uchar buf; int limit = height * width; for (int y = 0; y < limit; ++y) { buf = iplImagePtr[2]; iplImagePtr[2] = iplImagePtr[0]; iplImagePtr[0] = buf; iplImagePtr += 3; } QImage img((uchar *) iplImage->imageData, width, height, QImage::Format_RGB888);

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  • Possible memory leak problem

    - by MaiTiano
    I write two pieces of c programs like following, during memcheck process using Valgrind, a lot of mem leak information is given. int GetMemory(int framewidth, int frameheight, int SR/*, int blocksize*//*,int ALL_REF_NUM*/) { //int i,j; int memory_size = 0; //int refnum = ALL_REF_NUM; int input_search_range = SR; memory_size += get_mem2D(&curFrameY, frameheight, framewidth); memory_size += get_mem2D(&curFrameU, frameheight>>1, framewidth>>1); memory_size += get_mem2D(&curFrameV, frameheight>>1, framewidth>>1); memory_size += get_mem3D(&prevFrameY, refnum, frameheight, framewidth);// to allocate reference frame buffer accoding to the reference frame number memory_size += get_mem3D(&prevFrameU, refnum, frameheight>>1, framewidth>>1); memory_size += get_mem3D(&prevFrameV, refnum, frameheight>>1, framewidth>>1); memory_size += get_mem2D(&mpFrameY, frameheight, framewidth); memory_size += get_mem2D(&mpFrameU, frameheight>>1, framewidth>>1); memory_size += get_mem2D(&mpFrameV, frameheight>>1, framewidth>>1); memory_size += get_mem2D(&searchwindow, input_search_range*2 + blocksize, input_search_range*2 + blocksize);// to allocate search window according to the searchrange /*memory_size +=*/ get_mem1D(/*&SAD_cost, height, width*/); // memory_size += get_mem2D(&searchwindow, 80, 80);// if searchrange is 32, then only 32+1+32+15 pixels is needed in each row and col, therefore the range of // search window is enough to be set to 80 ! memory_size += get_mem2Dint(&all_mv, height/blocksize, width/blocksize); return 0; } void FreeMemory(int refno) { free_mem2D(curFrameY); free_mem2D(curFrameU); free_mem2D(curFrameV); free_mem3D(prevFrameY,refno); free_mem3D(prevFrameU,refno); free_mem3D(prevFrameV,refno); free_mem2D(mpFrameY); free_mem2D(mpFrameU); free_mem2D(mpFrameV); free_mem2D(searchwindow); free_mem1D(); free_mem2Dint(all_mv); } void free_mem1D() { free(SAD_cost); } Now I hope to make sure where are the possible problems in my program? Here I may post some valgrind information to let you know about the actual error information. ==29105== by 0x804A906: main (me_search.c:1480) ==29105== ==29105== ==29105== HEAP SUMMARY: ==29105== in use at exit: 124,088 bytes in 18 blocks ==29105== total heap usage: 37 allocs, 21 frees, 749,276 bytes allocated ==29105== ==29105== 272 bytes in 1 blocks are still reachable in loss record 1 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x804885E: GetMemory (me_search.c:117) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 352 bytes in 1 blocks are still reachable in loss record 2 of 18 ==29105== at 0x4024F20: malloc (vg_replace_malloc.c:236) ==29105== by 0x409537E: __fopen_internal (iofopen.c:76) ==29105== by 0x409544B: fopen@@GLIBC_2.1 (iofopen.c:107) ==29105== by 0x804A660: main (me_search.c:1439) ==29105== ==29105== 584 bytes in 1 blocks are still reachable in loss record 3 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x8048724: GetMemory (me_search.c:106) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 584 bytes in 1 blocks are still reachable in loss record 4 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x8048747: GetMemory (me_search.c:107) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 584 bytes in 1 blocks are still reachable in loss record 5 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x8048809: GetMemory (me_search.c:114) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 584 bytes in 1 blocks are still reachable in loss record 6 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x804882C: GetMemory (me_search.c:115) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 584 bytes in 1 blocks are definitely lost in loss record 7 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x804A4F8: get_mem3D (me_search.c:1393) ==29105== by 0x804879B: GetMemory (me_search.c:110) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 584 bytes in 1 blocks are definitely lost in loss record 8 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x804A4F8: get_mem3D (me_search.c:1393) ==29105== by 0x80487C9: GetMemory (me_search.c:111) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 1,168 bytes in 1 blocks are still reachable in loss record 9 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x8048701: GetMemory (me_search.c:105) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 1,168 bytes in 1 blocks are still reachable in loss record 10 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x80487E6: GetMemory (me_search.c:113) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 1,168 bytes in 1 blocks are definitely lost in loss record 11 of 18 ==29105== at 0x402425F: calloc (vg_replace_malloc.c:467) ==29105== by 0x804A296: get_mem2D (me_search.c:1315) ==29105== by 0x804A4F8: get_mem3D (me_search.c:1393) ==29105== by 0x804876D: GetMemory (me_search.c:109) ==29105== by 0x804A757: main (me_search.c:1456) ==29105== ==29105== 6,336 bytes in 1 blocks are definitely lost in loss record 12 of 18 ==29105== at 0x4024F20: malloc (vg_replace_malloc.c:236) ==29105== by 0x804A25C: get_mem1D (me_search.c:1295) ==29105== by 0x8048866: GetMemory (me_search.c:119) ==29105== by 0x804A757: main (me_search.c:1456)

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