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  • how to set multiple white spaces (ex: tabs) as delimiters in bash's `cut`

    - by Idlecool
    I want to retrieve the cpu usage/free percentage from mpstat output. The bash cut can be used to retrieve such details but i dont know what should be the delimiter viz. [idlecool@archbitch proc]$ mpstat | grep "all" | cut -d '$x' -f11 what should be $x so that i can skip white spaces and select value corresponding to %idle? Output of mpstat: [idlecool@archbitch proc]$ mpstat Linux 2.6.36-ARCH (archbitch) 01/14/11 _i686_ (2 CPU) 19:58:53 CPU %usr %nice %sys %iowait %irq %soft %steal %guest %idle 19:58:53 all 5.51 0.01 2.96 0.84 0.00 0.01 0.00 0.00 90.66

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  • Gettings the `which application` output in Bash

    - by Prudnikov
    Here is my original question at StackOverflow.com This is the script I wrote #!/usr/bin/env bash GP=`/usr/bin/which git` PWD=`pwd` echo "PATH IS: ${GP}" echo "PWD IS: ${PWD}" and output is PATH IS: PWD IS: /Users/user/tmp So the question is how to get which git output? I'm running it on Mac OS X 10.6.2.

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  • Bash or Zsh - which one and why?

    - by Andrew
    So, the question pretty much says it all. I'm on Snow Leopard, and I do a lot of web development, particularly in Rails 3 which makes heavy use of the console. I've seen some notable bloggers etc. mention Zsh as their preference over Bash, but I don't know what difference it would make. Could anyone give me a good comparison of what difference there is and what might make one prefer one option or the other? Thanks!

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  • send process straight to bg in bash

    - by ItsNannerpuss
    I find I frequently use the combination of Suspend (^Z) then send to background (bg) in bash. Ideally I would like an alternate keyboard shortcut that negates the need to follow ^Z with the bg command, and just send the active process straight to background. Does this exist? Edit: I should have been more specific, but appending & to the command is not sufficient, as they often require interaction (stdin) between launch and backgrounding. So: launch interact background

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  • Given a date range how to calculate the number of weekends partially or wholly within that range?

    - by andybak
    Given a date range how to calculate the number of weekends partially or wholly within that range? (A few definitions as requested: take 'weekend' to mean Saturday and Sunday. The date range is inclusive i.e. the end date is part of the range 'wholly or partially' means that any part of the weekend falling within the date range means the whole weekend is counted.) To simplify I imagine you only actually need to know the duration and what day of the week the initial day is... I darn well now it's going to involve doing integer division by 7 and some logic to add 1 depending on the remainder but I can't quite work out what... extra points for answers in Python ;-) Edit Here's my final code. Weekends are Friday and Saturday (as we are counting nights stayed) and days are 0-indexed starting from Monday. I used onebyone's algorithm and Tom's code layout. Thanks a lot folks. def calc_weekends(start_day, duration): days_until_weekend = [5, 4, 3, 2, 1, 1, 6] adjusted_duration = duration - days_until_weekend[start_day] if adjusted_duration < 0: weekends = 0 else: weekends = (adjusted_duration/7)+1 if start_day == 5 and duration % 7 == 0: #Saturday to Saturday is an exception weekends += 1 return weekends if __name__ == "__main__": days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'] for start_day in range(0,7): for duration in range(1,16): print "%s to %s (%s days): %s weekends" % (days[start_day], days[(start_day+duration) % 7], duration, calc_weekends(start_day, duration)) print

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  • JQuery Validation [migrated]

    - by user41354
    Im trying to get my form to validate...so basically its working, but a little bit too well, I have two text boxes, one is a start date, the other an end date in the format of mm/dd/yyyy if the start date is greater than the end date...there is an error if the end date is less than the start date...there is an error if the start date is less than today's date...there is an error The only thing is when I correct the error, the error warning is still there...here is my code: dates.change(function () { var testDate = $(this).val(); var otherDate = dates.not(this).val(); var now = new Date(); now.setHours(0, 0, 0, 0); // Pass Dates if (testDate != '' && new Date(testDate) < now) { addError($(this)); $('.flightDateError').text('* Dates cannot be earlier than today.'); isValid = false; return; } // Required Text if ($(this).hasClass("FromCal") && testDate == '') { addError($(this)); $('.flightDateError').text('* Required'); isValid = false; return; } // Validate Date if (!isValidDate(testDate)) { // $(this).addClass('validation_error_input'); addError($(this)); $('.flightDateError').text('* Invalid Date'); isValid = false; return; } else { // $(this).removeClass('validation_error_input'); removeError($(this)); if (!dates.not(this).hasClass('validation_error_input')) $('.flightDateError').text(' '); } // Validate Date Ranges if ($(this).val() != '' && dates.not(this).val != '') { if ($(this).hasClass("FromCal")) { if (new Date(testDate) > new Date(otherDate)) { addError($(this)); $('.flightDateError').text('* Start date must be earlier than end date.'); isValid = false; return; } } else{ if (new Date(testDate) < new Date(otherDate)) { addError($(this)); $('.flightDateError').text('* End date must be later than start date.'); return; } } } }); The main Issue is this part, I believe // Validate Date Ranges if ($(this).val() != '' && dates.not(this).val != '') { if ($(this).hasClass("FromCal")) { if (new Date(testDate) > new Date(otherDate)) { addError($(this)); $('.flightDateError').text('* Start date must be earlier than end date.'); isValid = false; return; } } else{ if (new Date(testDate) < new Date(otherDate)) { addError($(this)); $('.flightDateError').text('* End date must be later than start date.'); return; } } } testDate is the start date otherDate is the end date Thanks in advanced, J

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  • Check if date is allowed weekday in php?

    - by moogeek
    Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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  • How to overwrite the data in a file with bash

    - by Stefan Liebenberg
    I'm writing a bash script that encrypts the data of a folder or file #!/bin/bash file_name=$1 tmp_file=/tmp/tmpfile.tar # tar compress file tar -cf $tmp_file $file_name; # encrypt file gpg -c $tmp_file # remove temp file rm -rf $tmp_file $file_name # mv encrypted file to orignal place mv ${tmp_file}.gpg $file_name but the data will still be recoverable by using photorec or similar methods... Is there a way to ensure the absolute deletion of the original file in bash? Thank You Stefan

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  • How to automatically add user account *and* password with a Bash script

    - by ModernCarpentry
    I need to have the ability to create user accounts on my Linux ( Fedora 10 ) and automatically assign a password via a bash script ( or otherwise, if need be ). It's easy to create the user via Bash eg: [whoever@server ]# /usr/sbin/useradd newuser But is it possible to assign a password in Bash, something functionally similar to this (but automated): [whoever@server ]# passwd newuser Changing password for user testpass. New UNIX password: Retype new UNIX password: passwd: all authentication tokens updated successfully. [whoever@server ]#

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  • bash script to check running process

    - by elasticsecurity
    I wrote a bash-script to check if a process is running. It doesn't work since the ps command always returns exit code 1. When I run the ps command from the command-line, the $? is correctly set, but within the script it is always 1. Any idea? #!/bin/bash SERVICE=$1 ps -a | grep -v grep | grep $1 > /dev/null result=$? echo "exit code: ${result}" if [ "${result}" -eq "0" ] ; then echo "`date`: $SERVICE service running, everything is fine" else echo "`date`: $SERVICE is not running" fi Bash version: GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)

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  • Quicker searching in JScript using the Bash

    - by gentlesea
    I am using the following JScript code to search for a string inside a file: var myFile = aqFile.OpenTextFile(fileToSearchIn, aqFile.faRead, aqFile.ctANSI); while(!myFile.IsEndOfFile()) { s = myFile.ReadLine(); if (aqString.Find(s, searchString) != -1) Log.Checkpoint(searchString + " found.", s); } myFile.Close(); This is rather slow. I was thinking about using bash commands in order to speed up the search in file process: var WshShell = new ActiveXObject("WScript.Shell"); var oExec = WshShell.Exec("C:\\cygwin\\bin\\bash.exe -c 'cat \"" + folderName + "/" + fileName + "\"'"); while (!oExec.StdOut.AtEndOfStream) Log.Checkpoint(oExec.StdOut.ReadLine()); while (!oExec.StdErr.AtEndOfStream) Log.Error(oExec.StdErr.ReadLine()); Since every time bash.exe is started a new window opens the searching is not faster than before. Is there a possibility to have the bash run in the background using another switch?

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  • Unable to modify git bash Windows shortcut

    - by netgirlk
    Under Windows 7 I'd like to change the settings for the Git Bash Here shell extension command window, e.g. width, height and font. But when I do this, I get an error "Unable to modify the shortcut". I can modify the shortcut for Git Bash in the Start menu by using "Run as administrator..." This works, but only for Bash windows opened from the Start menu. It doesn't work for the "Git Bash Here" shell extension and there's no "Run as administrator..." option on right-click context menu. How do you do it?

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  • Bash script to log in over SSH

    - by user1042928
    Sorry if this seems like a dumb question but I am just learning bash scripting. For a school project we need to code an RTX that runs in Unix. It runs as a process in terminal and takes in user input and then prints it to the screen. I want to write a bash script to test that it can respond to lots of quick user input without overflowing or failing. My main problem is that once the RTX starts the bash script will stop on that line until the RTX terminates and only then print the loop to the terminal (instead of printing it to the RTX prompt as I intend it to). I have tried running the RTX in the background but that didn't work. I need to find a way to redirect input to the RTX while it is still running with a bash script. Google searches didn't come up with examples that I understood/could adapt. Any help is appreciated. #!/bin/bash # declare STRING variable STRING="RTX Worked =D" #Start the rtx in a new process, stuck on this line until rtx terminates. ./main #Somehow redirect io to the rtx. for i in `seq 1 100`; do echo $i echo " \n" done echo $STRING

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  • Bash sourcing of functions in other languages

    - by ABach
    This is, perhaps, a silly question, but it's something that I've wondered about: is it possible to, say, define a Ruby/Python/Perl/etc. function in some file and then source it in Bash (to make it available anywhere in the current shell)? At the moment, I "source" scripts/functions in other languages by creating a bash alias that executes that script... But I wonder if it's possible for Bash to interpret those other functions directly? Thanks. :)

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  • Bash can't start a programme that's there and has all the right permissions

    - by Rory
    This is a gentoo server. There's a programme prog that can't execute. (Yes the execute permission is set) About the file $ ls prog $ ./prog bash: ./prog: No such file or directory $ file prog prog: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), for GNU/Linux 2.2.5, dynamically linked (uses shared libs), not stripped $ pwd /usr/local/bin $ /usr/local/bin/prog bash: /usr/local/bin/prog: No such file or directory $ less prog | head ELF Header: Magic: 7f 45 4c 46 01 01 01 00 00 00 00 00 00 00 00 00 Class: ELF32 Data: 2's complement, little endian Version: 1 (current) OS/ABI: UNIX - System V ABI Version: 0 Type: EXEC (Executable file) Machine: Intel 80386 Version: 0x1 I have a fancy less, to show that it's an actual executable, here's some more data: $ xxd prog |head 0000000: 7f45 4c46 0101 0100 0000 0000 0000 0000 .ELF............ 0000010: 0200 0300 0100 0000 c092 0408 3400 0000 ............4... 0000020: 0401 0a00 0000 0000 3400 2000 0700 2800 ........4. ...(. 0000030: 2600 2300 0600 0000 3400 0000 3480 0408 &.#.....4...4... 0000040: 3480 0408 e000 0000 e000 0000 0500 0000 4............... 0000050: 0400 0000 0300 0000 1401 0000 1481 0408 ................ 0000060: 1481 0408 1300 0000 1300 0000 0400 0000 ................ 0000070: 0100 0000 0100 0000 0000 0000 0080 0408 ................ 0000080: 0080 0408 21f1 0500 21f1 0500 0500 0000 ....!...!....... 0000090: 0010 0000 0100 0000 40f1 0500 4081 0a08 ........@...@... and $ ls -l prog -rwxrwxr-x 1 1000 devs 725706 Aug 6 2007 prog $ ldd prog not a dynamic executable $ strace ./prog 1249403877.639076 execve("./prog", ["./prog"], [/* 27 vars */]) = -1 ENOENT (No such file or directory) 1249403877.640645 dup(2) = 3 1249403877.640875 fcntl(3, F_GETFL) = 0x8002 (flags O_RDWR|O_LARGEFILE) 1249403877.641143 fstat(3, {st_mode=S_IFCHR|0620, st_rdev=makedev(136, 0), ...}) = 0 1249403877.641484 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x2b3b8954a000 1249403877.641747 lseek(3, 0, SEEK_CUR) = -1 ESPIPE (Illegal seek) 1249403877.642045 write(3, "strace: exec: No such file or dir"..., 40strace: exec: No such file or directory ) = 40 1249403877.642324 close(3) = 0 1249403877.642531 munmap(0x2b3b8954a000, 4096) = 0 1249403877.642735 exit_group(1) = ? About the server FTR the server is a xen domU, and the programme is a closed source linux application. This VM is a copy of another VM that has the same root filesystem (including this programme), that works fine. I've tried all the above as root and same problem. Did I mention the root filesystem is mounted over NFS. However it's mounted 'defaults,nosuid', which should include execute. Also I am able to run many other programmes from that mounted drive /proc/cpuinfo: processor : 0 vendor_id : GenuineIntel cpu family : 15 model : 4 model name : Intel(R) Xeon(TM) CPU 3.00GHz stepping : 1 cpu MHz : 2992.692 cache size : 1024 KB fpu : yes fpu_exception : yes cpuid level : 5 wp : yes flags : fpu tsc msr pae mce cx8 apic mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm syscall nx lm constant_tsc pni monitor ds_cpl cid cx16 xtpr bogmips : 5989.55 clflush size : 64 cache_alignment : 128 address sizes : 36 bits physical, 48 bits virtual power management: Example of a file that I can run I can run other programmes on that mounted filesystem on that server. For example: $ ls -l ls -rwxr-xr-x 1 root root 105576 Jul 25 17:14 ls $ file ls ls: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), for GNU/Linux 2.6.9, dynamically linked (uses shared libs), stripped $ ./ls attr cat cut echo getfacl ln more ... (you get the idea) ... rmdir sort tty $ less ls | head ELF Header: Magic: 7f 45 4c 46 02 01 01 00 00 00 00 00 00 00 00 00 Class: ELF64 Data: 2's complement, little endian Version: 1 (current) OS/ABI: UNIX - System V ABI Version: 0 Type: EXEC (Executable file) Machine: Advanced Micro Devices X86-64 Version: 0x1

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  • segfault when cd-ing into certain directories in bash

    - by user84207
    I have noticed this very strange behavior recently. After cd into certain directories, I get a segfault on the terminal. --- SIGSEGV (Segmentation fault) @ 0 (0) --- --- SIGSEGV (Segmentation fault) @ 0 (0) --- +++ killed by SIGSEGV (core dumped) +++ segmentation fault (core dumped) I proceeded to strace a bash session in which I cd into the target directory, and was able to reproduce the problem. I attached the log to this pastebin: I paste below the few lines from the read of "cd stumpwm", which is the directory in question, until the segfault. I included a few of the repetitions of calls to "rt_sigprocmask" and "brk" to give a glimpse of the pattern, which occurs for most of the strace, read(0, cd stumpwm "c", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "d", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, " ", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "s", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "t", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "u", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "m", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "p", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "w", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "m", 1) = 1 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 read(0, "\n", 1) = 1 rt_sigprocmask(SIG_BLOCK, [INT], [], 8) = 0 ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig -icanon -echo ...}) = 0 ioctl(0, SNDCTL_TMR_STOP or TCSETSW, {B38400 opost isig icanon -echo ...}) = 0 ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig icanon -echo ...}) = 0 rt_sigprocmask(SIG_SETMASK, [], NULL, 8) = 0 rt_sigaction(SIGINT, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, {0x49edc0, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTERM, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGQUIT, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGALRM, {0x457f50, [HUP INT ILL TRAP ABRT BUS FPE USR1 SEGV USR2 PIPE ALRM TERM XCPU XFSZ VTALRM SYS], SA_RESTORER, 0x7ffff76254a0}, {0x49edc0, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTSTP, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTTOU, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGTTIN, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, {SIG_IGN, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGWINCH, {0x457920, [], SA_RESTORER, 0x7ffff76254a0}, {0x49e6e0, [], SA_RESTORER|SA_RESTART, 0x7ffff76254a0}, 8) = 0 rt_sigaction(SIGINT, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, {0x457d50, [], SA_RESTORER, 0x7ffff76254a0}, 8) = 0 brk(0xa9a000) = 0xa9a000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9b000) = 0xa9b000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9c000) = 0xa9c000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9d000) = 0xa9d000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9e000) = 0xa9e000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xa9f000) = 0xa9f000 brk(0xaa0000) = 0xaa0000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0xaa1000) = 0xaa1000 brk(0xaa2000) = 0xaa2000 (pattern of rt_sigprocmask, brk continues ...) rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0x1d5b000) = 0x1d5b000 brk(0x1d5c000) = 0x1d5c000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 brk(0x1d5d000) = 0x1d5d000 brk(0x1d5e000) = 0x1d5e000 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 rt_sigprocmask(SIG_BLOCK, NULL, [], 8) = 0 --- SIGSEGV (Segmentation fault) @ 0 (0) --- --- SIGSEGV (Segmentation fault) @ 0 (0) --- +++ killed by SIGSEGV (core dumped) +++ segmentation fault (core dumped) How can I debug this? Is this likely to be a bash problem? The error does not occur with another shell, such as eshell. I have also run an fschk, although I haven't been able to see the output because of this bug.

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  • In GNU Screen, Recalled bash history command displays one character position to the left of actual location

    - by vergueishon
    I am running Red Hat 5 32-bit (2.6.18-194.26.1.el5). The issue is that when I recall any previous command in bash's history, the first character in the command is displayed immediately after the shell prompt, without any intervening space, likeso: \[me@mymachine tmp]$man mysql If I enter a Ctrl-C, and retype the command, it looks likeso: \[me@mymachine tmp]$ man mysql This makes recalling a command and editing it before re-entering a real pain. Basically, if I try to edit a recalled command, my changes occur one character position to the left (I believe) of what I see on the screen. It's a bit tedious to describe, and appears to only happen with commands with a large number of arguments. UPDATE: The contents of /etc/sysconfig/bash-prompt-screen, 1 #!/bin/bash 2 echo -n $'\033'"_${USER}@${HOSTNAME%%.*}:${PWD/#$HOME/~}"$'\033\\\\' and the contents of /etc/bashrc, 24 screen) 25 if [ -e /etc/sysconfig/bash-prompt-screen ]; then 26 PROMPT_COMMAND=/etc/sysconfig/bash-prompt-screen 27 else 28 PROMPT_COMMAND='echo -ne "\033_${USER}@${HOSTNAME%%.*}:${PWD/#$HOME/~}"; echo -ne "\033\\"' 29 fi 30 ;; I've disable bash-prompt-screen by renaming it--this fixed it. It's entirely possible that there is a fix to the bash-prompt-screen prompt line in the latest version of screen for RHEL 5. The error is seen under Screen version 4.00.03 (FAU) 23-Oct-06. (I noticed an update in the queue, which is installing as I write this.)

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  • Proper way to let user enter password for a bash script using only the GUI (with the terminal hidden)

    - by MountainX
    I have made a bash script that uses kdialog exclusively for interacting with the user. It is launched from a ".desktop" file so the user never sees the terminal. It looks 100% like a GUI app (even though it is just a bash script). It runs in KDE only (Kubuntu 12.04). My only problem is handling password input securely and conveniently. I can't find a satisfactory solution. The script was designed to be run as a normal user and to prompt for the password when a sudo command is first needed. In this way, most commands, those not requiring sudo rights, are run as the normal user. What happens (when the script is run from the terminal) is that the user is prompted for their password once and the default sudo timeout allows the script to finish, including any additional sudo commands, without prompting the user again. This is how I want it to work when run behind the GUI too. The main problem is that using kdesudo to launch my script, which is the standard GUI way, means that the entire script is executed by the root user. So file ownerships get assigned to the root user, I can't rely upon ~/ in paths, and many other things are less than ideal. Running the entire script as the root user is just a very unsatisfactory solution and I think it is a bad practice. I appreciate any ideas for letting a user enter the sudo password just once via GUI while not running the whole script as root. Thanks.

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  • getting bash to load my PATH over SSH

    - by Eli Bendersky
    This problem comes up with me trying to make svnserve (Subversion server) available on a server through SSH. I compiled SVN and installed it in $HOME/bin. Local access to it (not through SSH) works fine. Connections to svn+ssh fail due to: bash: svnserve: command not found Debugging this, I've found that: ssh user@server "which svnserve" says: which: no svnserve in (/usr/bin:/bin) This is strange, because I've updated the path to $HOME/bin in my .bashrc, and also added it in ~/.ssh/environment. However, it seems like the SSH doesn't read it. Although when I run: ssh user@server "echo $PATH" It does print my updated path! What's going on here? How can I make SSH find my svnserve? Thanks in advance

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  • CentOS Backup BASH Script

    - by user1062058
    I just wrote this script for backing up everything into a tar.gz file. Does it look okay? How can I get the tar file to transfer itself over to another server after executing? FTP from itself? I'm going to put this script into a weekly cron. #!/bin/bash rm ~/backup.tar.gz #removes old backup BACKUP_DIRS=$HOME #$HOME is builtin, it goes to /home/ and all child dirs tar -cvzf backup.tar.gz $BACKUP_DIRS # run tar -zxvf to extract backup.tar.gz Thanks.

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  • Improper output in SSH session on OSX using FreeSSHd on Windows with cygwin bash/sh shell

    - by Tyler Clendenin
    I am testing out running an SSH server on a local Windows VM. I have installed FreeSSHd and set the command shell to "c:\cygwin\bin\sh --login -i" (bash as well) with "Use new console engine" unchecked. (When it was enabled no output would show through the ssh connection anyway) The shell seems to work, but when connecting from my OS-X terminal using ssh all of the shell results comes out ill formatted. $ ls -al total 17 drwxr-xr-x+ 1 SYSTEM Administrators 4096 Feb 2 01:00 . drwxrwxrwt+ 1 Administrator Administrators 0 Feb 2 01:01 .. -rw------- 1 SYSTEM Administrators 128 Feb 2 01:30 .bash_history -rwxr-xr-x 1 SYSTEM Administrators 1150 Feb 2 00:55 .bash_profile -rwxr-xr-x 1 SYSTEM Administrators 3754 Feb 2 00:55 .bashrc -rwxr-xr-x 1 SYSTEM Administrators 1461 Feb 2 00:55 .inputrc Any ideas on why this is happening, how I can fix this?

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  • Bash - read as a fallback to $@

    - by user137369
    I have a working bash script (working on OSX) that takes files and directories as input and does something like for inputFile in $@ do [someStuff] done but I want to provide a “fallback”, meaning, if the script is started with no arguments (double-clicked, for example), it can take input at that time, by letting the user drop the files directly on the terminal (possibly through read but not mandatory, I'm open to better/different solutions). I'm guessing I should use some kind of if statement, but I'm not sure how. I'd like to not have to essentially duplicate the script's size by two by repeating [someStuff] for each case. Thank you.

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  • Bash color prompt and long commands

    - by Eric J.
    I'm colorizing parts of my bash prompt using ANSI escape sequences. This works great, until the command I'm currently typing in is long enough that it has to wrap. Instead of the rest of the command displaying on the next line, it wraps back to column 1 of the current line, overwriting the beginning of the prompt. I get that behavior with this prompt: export PS1="[\u][\033[0;32;40mdemo \033[0;33;40m1.5.40.b\033[0;37;40m] \w> \033[0m" but it works correctly with the same prompt, ANSI sequences remove: export PS1="[\u][demo 1.5.40.b] \w> " I'm connecting using the current version of Putty, with default Putty settings. The OS is Ubuntu 8.10.

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  • (svh+ssh) getting bash to load my PATH over SSH

    - by Eli Bendersky
    This problem comes up with me trying to make svnserve (Subversion server) available on a server through SSH. I compiled SVN and installed it in $HOME/bin. Local access to it (not through SSH) works fine. Connections to svn+ssh fail due to: bash: svnserve: command not found Debugging this, I've found that: ssh user@server "which svnserve" says: which: no svnserve in (/usr/bin:/bin) This is strange, because I've updated the path to $HOME/bin in my .bashrc, and also added it in ~/.ssh/environment. However, it seems like the SSH doesn't read it. Although when I run: ssh user@server "echo $PATH" It does print my updated path! What's going on here? How can I make SSH find my svnserve? Thanks in advance

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