Search Results

Search found 5065 results on 203 pages for 'django rss'.

Page 13/203 | < Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >

  • django admin app error (Model with property field): global name 'full_name' is not defined

    - by rxin
    This is my model: class Author(models.Model): first_name = models.CharField(max_length=200) last_name = models.CharField(max_length=200) middle_name = models.CharField(max_length=200, blank=True) def __unicode__(self): return full_name def _get_full_name(self): "Returns the person's full name." if self.middle_name == '': return "%s %s" % (self.first_name, self.last_name) else: return "%s %s %s" % (self.first_name, self.middle_name, self.last_name) full_name = property(_get_full_name) Everything is fine except when I go into admin interface, I see TemplateSyntaxError at /bibbase2/admin/bibbase2/author/ Caught an exception while rendering: global name 'full_name' is not defined It seems like the built-in admin app doesn't work with a property field. Is there something wrong with my code?

    Read the article

  • Django many to many annotations and filters

    - by dl8
    So I have two models, Person and Film where they're in a many to many relationship. My goal is to grab a film, and output the persons that have also appeared in at least 10 films. For example I can get the count individually by: >>> Person.objects.get(short__istartswith = "Matt Damon").film_set.count() 71 However, if I try to filter all the actors of a particular film out: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film')).filter(film_count__gte=10) [] it returns an empty set since if I manually look at everyone's film_count it's 1, even though an actor such as Matt Damon (as seen above) has been in 71 films in my db. As you can see with this query, the annotation doesn't work: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_count 1 >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_set.count() 7 and I can't seem to figure out a way to filter it by the film_set.count()

    Read the article

  • django generic view update/create: update works but create raises IntegrityError

    - by smarber
    I'm using CreateView and UpdateView directely into urls.py of my application whose name is dydict. In the file forms.py I'm using ModelForm and I'm exluding a couple of fields from being shown, some of which sould be set when either creating or updating. So, as mentioned in the title, update part works but create part doesn't which is obvious because required fields that I have exluded are sent empty which is not allowed in my case. So the question here is, how should I do to fill exluded fields into the file forms.py so that I don't have to override CreateView? Thanks in advance.

    Read the article

  • Django admin.py missing field error

    - by user782400
    When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

    Read the article

  • querying for timestamp field in django

    - by Hulk
    In my views i have the date in the following format s_date=20090106 and e_date=20100106 The model is defined as class Activity(models.Model): timestamp = models.DateTimeField(auto_now_add=True) how to query for the timestamp filed with the above info. Activity.objects.filter(timestamp>=s_date and timestamp<=e_date) Thanks.....

    Read the article

  • Django templates tag error

    - by Hulk
    def _table_(request,id,has_permissions): dict = {} dict.update(get_newdata(request,rid)) return render_to_response('home/_display.html',context_instance=RequestContext(request,{'dict': dict, 'rid' : rid, 'has_permissions' : str(has_permissions)})) In templates the code is as, {% if has_permissions == "1" %} <input type="button" value="Edit" id="edit" onclick="javascript:edit('{{id}}')" style="display:inline;"/>&nbsp;&nbsp;&nbsp;&nbsp; {% endif %} There is a template error in has_permissions line. Can any 1 tell me what is wrong here. has_permissions has the value 1 or 0.

    Read the article

  • Creating a QuerySet based on a ManyToManyField in Django

    - by River Tam
    So I've got two classes; Picture and Tag that are as follows: class Tag(models.Model): pics = models.ManyToManyField('Picture', blank=True) name = models.CharField(max_length=30) # stuff omitted class Picture(models.Model): name = models.CharField(max_length=100) pub_date = models.DateTimeField('date published') tags = models.ManyToManyField('Tag', blank=True) content = models.ImageField(upload_to='instaton') #stuff omitted And what I'd like to do is get a queryset (for a ListView) given a tag name that contains the most recent X number of Pictures that are tagged as such. I've looked up very similar problems, but none of the responses make any sense to me at all. How would I go about creating this queryset?

    Read the article

  • Django templates check condition

    - by Hulk
    If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

    Read the article

  • Django - calling full_clean() inside of clean() equivalent?

    - by orokusaki
    For transaction purposes, I need all field validations to run before clean() is done. Is this possible? My thinking is this: @transaction.commit_on_success def clean(self): # Some fun stuff here. self.full_clean() # I know this isn't correct, but it illustrates my point. but obviously that's not correct, because it would be recursive. Is there a way to make sure that everything that full_clean() does is done inside clean()?

    Read the article

  • Google crawled all our RSS links - how do I remove these from their index? [closed]

    - by ElHaix
    Possible Duplicate: How to Remove URLs from Google Search Engine We added a RSS link to our site for our content. Since then, our site visits have diminished. If a user is viewing the RSS feed, the link itself does not go to the actual article/content. Instead, each link goes to a main index - where the content may have changed, and the article they clicked on COULD be on that page, depending on its age. The RSS link structure is as follows: www.oursite.com/[search term]/rsslink/[title of the rss link they clicked on] I'm not trying to do anything black-hat here, but wondering if we're getting penalized for this somehow. If this is the case, could I do something like permanently-removed on all /rsslink/ pages?

    Read the article

  • Debugging "Premature end of script headers" - WSGI/Django [migrated]

    - by Marcin
    I have recently deployed an app to a shared host (webfaction), and for no apparent reason, my site will not load at all (it worked until today). It is a django app, but the django.log is not even created; the only clue is that in one of the logs, I get the error message: "Premature end of script headers", identifying my wsgi file as the source. I've tried to add logging to my wsgi file, but I can't find any log created for it. Is there any recommended way to debug this error? I am on the point of tearing my hair out. My WSGI file: import os import sys from django.core.handlers.wsgi import WSGIHandler import logging logger = logging.getLogger(__name__) os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' os.environ['CELERY_LOADER'] = 'django' virtenv = os.path.expanduser("~/webapps/django/oneclickcosvirt/") activate_this = virtenv + "bin/activate_this.py" execfile(activate_this, dict(__file__=activate_this)) # if 'VIRTUAL_ENV' not in os.environ: # os.environ['VIRTUAL_ENV'] = virtenv sys.path.append(os.path.dirname(virtenv+'oneclickcos/')) logger.debug('About to run WSGIHandler') try: application = WSGIHandler() except (Exception,), e: logger.debug('Exception starting wsgihandler: %s' % e) raise e

    Read the article

  • Disabling email-style usernames in Django 1.2 with django-registration

    - by shacker
    Django 1.2 allows usernames to take the form of an email address. Changed in Django 1.2: Usernames may now contain @, +, . and - characters I know that's a much-requested feature, but what if you don't want the new behavior? It makes for messy usernames in profile URLs and seems to break django-registration (if a user registers an account with an email-style username, the link in the django-registration activation email returns 404). Does anyone have a recipe for restoring the old behavior and disabling email-style usernames?

    Read the article

  • Does Django cache url regex patterns somehow?

    - by Emre Sevinç
    I'm a Django newbie who needs help: Even though I change some urls in my urls.py I keep on getting the same error message from Django. Here is the relevant line from my settings.py: ROOT_URLCONF = 'mydjango.urls' Here is my urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^mydjango/', include('mydjango.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: #(r'^admin/doc/', include(django.contrib.admindocs.urls)), # (r'^polls/', include('mydjango.polls.urls')), (r'^$', 'mydjango.polls.views.homepage'), (r'^polls/$', 'mydjango.polls.views.index'), (r'^polls/(?P<poll_id>\d+)/$', 'mydjango.polls.views.detail'), (r'^polls/(?P<poll_id>\d+)/results/$', 'mydjango.polls.views.results'), (r'^polls/(?P<poll_id>\d+)/vote/$', 'mydjango.polls.views.vote'), (r'^polls/randomTest1/', 'mydjango.polls.views.randomTest1'), (r'^admin/', include(admin.site.urls)), ) So I expect that whenever I visit http://mydjango.yafz.org/polls/randomTest1/ the mydjango.polls.views.randomTest1 function should run because in my polls/views.py I have the relevant function: def randomTest1(request): # mainText = request.POST['mainText'] return HttpResponse("Default random test") However I keep on getting the following error message: Page not found (404) Request Method: GET Request URL: http://mydjango.yafz.org/polls/randomTest1 Using the URLconf defined in mydjango.urls, Django tried these URL patterns, in this order: 1. ^$ 2. ^polls/$ 3. ^polls/(?P<poll_id>\d+)/$ 4. ^polls/(?P<poll_id>\d+)/results/$ 5. ^polls/(?P<poll_id>\d+)/vote/$ 6. ^admin/ 7. ^polls/randomTest/$ The current URL, polls/randomTest1, didn't match any of these. I'm surprised because again and again I check urls.py and there is no ^polls/randomTest/$ in it, but there is ^polls/randomTest1/' It seems like Django is somehow storing the previous contents of urls.py and I just don't know how to make my latest changes effective. Any ideas? Why do I keep on seeing some old version of regexes when I try to load that page even though I changed my urls.py?

    Read the article

  • force delete row on django app after migration

    - by unsorted
    After a migration with south, I ended up deleting a column. Now the current data in one of my tables is screwed up and I want to delete it, but attempts to delete just result in an error: >>> d = Degree.objects.all() >>> d.delete() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 440, in d elete for i, obj in izip(xrange(CHUNK_SIZE), del_itr): File "C:\Python26\lib\site-packages\django\db\models\query.py", line 106, in _ result_iter self._fill_cache() File "C:\Python26\lib\site-packages\django\db\models\query.py", line 760, in _ fill_cache self._result_cache.append(self._iter.next()) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 269, in i terator for row in compiler.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 67 2, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\compiler.py", line 72 7, in execute_sql cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 15, in e xecute return self.cursor.execute(sql, params) File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 200, in execute return Database.Cursor.execute(self, query, params) DatabaseError: no such column: students_degree.abbrev >>> Is there a simple way to just force a delete? Do I drop the table and then rerun manage.py schemamigration to recreate the table in south?

    Read the article

  • 2-step user registration with Django

    - by David S
    I'm creating a website with Django and want a fairly common 2-step user registration. What I mean by this is that the user fills in the some basic user information + some application specific information (sort of like a coupon value). Upon submit, an email is sent to ensure email address is valid. This email should contain a link to click on to "finish" the registration. When the link is clicked, the user is marked as validated and they are directed to a new page to complete optional "user profile" type information. So, pretty basic stuff. I have done some research and found django-registration by James Bennett. I do know who James is and have seen him at PyCons and DjanoCons in the past. There is obviously very few people in the world that know Django better than James (so, I know the quality of the code/app is good). But, it almost seems like a bit of over kill. I've read through the docs and was a bit confused (maybe I'm just being a bit dense today). I believe that if I do use django-registration, I will need to have some custom forms, etc. Is there anything else out there I should evaluate? Or are there any good tutorials or videos on using django-registration? I've done a bit of googling, but haven't found anything. But, I suspect that it might be a case of a lot of very common words that don't really find what you are looking for (django user registration tutorial/example). Or is just a case where it would be just about as easy to build your own solution with Django forms, etc? Here is the tech stack I'm using: Python 2.7.2 Django 1.3.1 PostgreSQL 9.1 psycopg2 2.4.1 Twitter Bootstrap 2.0.2

    Read the article

  • error in implementing static files in django

    - by POOJA GUPTA
    my settings.py file:- STATIC_ROOT = '/home/pooja/Desktop/static/' # URL prefix for static files. STATIC_URL = '/static/' # Additional locations of static files STATICFILES_DIRS = ( '/home/pooja/Desktop/mysite/search/static', ) my urls.py file:- from django.conf.urls import patterns, include, url from django.contrib.staticfiles.urls import staticfiles_urlpatterns from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', url(r'^search/$','search.views.front_page'), url(r'^admin/', include(admin.site.urls)), ) urlpatterns += staticfiles_urlpatterns() I have created an app using django which seraches the keywords in 10 xml documents and then return their frequency count displayed as graphical representation and list of filenames and their respective counts.Now the list has filenames hyperlinked, I want to display them on the django server when user clicks them , for that I have used static files provision in django. Hyperlinking has been done in this manner: <ul> {% for l in list1 %} <li><a href="{{STATIC_URL}}static/{{l.file_name}}">{{l.file_name}}</a{{l.frequency_count</li> {% endfor %} </ul> Now when I run my app on the server, everything is running fine but as soon as I click on the filename, it gives me this error : Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^search/$ ^admin/ ^static\/(?P<path>.*)$ The current URL, search/static/books.xml, didn't match any of these. I don't know why this error is coming, because I have followed the steps required to achieve this. I have posted my urls.py file and it is showing error in that only. I'm new to django , so Please help

    Read the article

  • How to make a model instance read-only after saving it once?

    - by Ryszard Szopa
    One of the functionalities in a Django project I am writing is sending a newsletter. I have a model, Newsletter and a function, send_newsletter, which I have registered to listen to Newsletter's post_save signal. When the newsletter object is saved via the admin interface, send_newsletter checks if created is True, and if yes it actually sends the mail. However, it doesn't make much sense to edit a newsletter that has already been sent, for the obvious reasons. Is there a way of making the Newsletter object read-only once it has been saved? Edit: I know I can override the save method of the object to raise an error or do nothin if the object existed. However, I don't see the point of doing that. As for the former, I don't know where to catch that error and how to communicate the user the fact that the object wasn't saved. As for the latter, giving the user false feedback (the admin interface saying that the save succeded) doesn't seem like a Good Thing. What I really want is allow the user to use the Admin interface to write the newsletter and send it, and then browse the newsletters that have already been sent. I would like the admin interface to show the data for sent newsletters in an non-editable input box, without the "Save" button. Alternatively I would like the "Save" button to be inactive.

    Read the article

  • django internationalization doesn't work

    - by xRobot
    I have: * created translation strings in the template and in the application view. * run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created * translated strings in the django.po file. * run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES * set this in settings.py: LANGUAGE_CODE = 'it' TEMPLATE_CONTEXT_PROCESSORS = ( "django.core.context_processors.auth", "django.core.context_processors.debug", "django.core.context_processors.i18n", "django.core.context_processors.media", ) USE_I18N = True MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.middleware.locale.LocaleMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', ) but.... translation doesn't work !! I always see english text. Why ?

    Read the article

  • Is there any way to synchronize Outlook RSS Feeds with BlackBerry?

    - by nvuono
    Does anyone know how I can view the contents of my Outlook 2007 RSS Feeds from a corporate-issued BlackBerry? Our Inbox and Calendar are already integrated with corporate exchange servers but it looks like nobody cares too much about the RSS Feeds. Is there some setting on my Blackberry or in Outlook I could possibly tweak to include these updates? I know there are many standalone RSS readers available for blackberry (Google Reader for example) but I mention Outlook RSS Feeds specifically in my question because I am subscribing to a number of RSS feeds I've setup on my intranet for various version control systems that would be inaccessible to an external RSS reader. It seems like I might have to setup some sort of email commit notifications if I want anything from my blackberry but I much prefer the 'pull' method of an RSS feed viewer over receiving streams of emails. Please feel free to suggest any alternatives! Edit: I've additionally tried moving my "SVN Repository" folder directly into my Mailbox instead of keeping it as a child of the RSS Feeds folder. This allows me to view the SVN Repository folder on my blackberry where previously the RSS Feeds folder and all children were hidden but unfortunately it never seems to get populated with the items that are displaying in Outlook. I've even made a fresh commit to make sure that the SVN Repository folder still works correctly in Outlook from outside the RSS Feeds folder but no luck on the BlackBerry end of things. BlackBerry Model Details: BlackBerry 8310 smartphone (EDGE) v4.2.2.170 Platform 2.5.0.30

    Read the article

  • What RSS Reader can handle item-updating (JIRA search) feeds?

    - by Stephen
    Thunderbird is a good rss reader in terms of being able to connect successfully to jira authenticated search feeds (where evolution-rss and Liferea can't), but really sucks when it comes to updating. A Jira search feed will give a link id to http://jira/browse/[ticket no], and if that ticket/feed-item is updated, thunderbird refuses to update it - it already has it! (even though the item date does not match). Also, if you delete the ticket update, it will never show up again for that news account. Has anybody found an RSS reader that can work with JIRA/updating RSS items? Note: this is not the same as Jira activity feeds - those work great, as each update has a unique item id To replicate: Grab a search (any search) Get it into your rss reader Read an item, modify the linked ticket Update rss and see if the ticket bumps to most recent and unread or, generically: Get an rss feed (from your hard drive?) Modify an item in the middle changing the content, the date, and moving it to the top Update rss and see if the ticket bumps to most recent and unread

    Read the article

  • rss downloader script

    - by The Digital Ninja
    I have a Synology NAS that is powered by linux at my house. I'm looking to set up a cron script to check a group of rss feeds and auto download new video podcasts to a shared folder. I can do most of the scripting, such as deleting files older than 3 weeks and the wget parts. But I'm not sure how to parse the rss feed and check dates to only grab the latest. I figured its best not to re-invent the wheel and surly someone out there has a command line rss downloader or some such script. Any ideas?

    Read the article

  • preloading RSS contents in thunderbird, before actually reading them

    - by Berry Tsakala
    i have thunderbird 3.x, and i'm subscribed to several RSS feeds. How can I tell thunderbird to load/download any new RSS items in the background? The usual behavior with RSS feeds is that it download the headrs, or few introductory lines from the contents, but only when i'm clicking a feed item it starts loading "for real". I really want to receive the feeds and not to wait for them to load, the same way i receive emails in any email client - all messages are fully downloaded at once. there could be several reasons, BTW. - e.g. if i have short connection time, i'd rather connect, sync everything at once, and read it later. - or if i have a slow wifi connection, it's annoying to wait for each and every message, but the computer is idle while reading.. thanks

    Read the article

  • Access Your favorite RSS Feeds in Windows Media Center

    - by Mysticgeek
    There are a lot of apps out there that help you organize and view your favorite RSS feeds. If you subscribe to a lot, sitting at a computer to view them all can be overwhelming. Today we take a look at accessing them from the couch with WMC. Using Media Center RSS Feeds To get RSS feeds to work with this plugin you need to subscribe to them through Internet Explorer.   The first thing you’ll need to do is activate Media Center RSS Reader (link below) on their site. Next install the Media Center RSS Reader plugin (link below). Installation is easy, just select the defaults when going through the wizard. Now when you open Media Center you’ll see the RSS icon in the main menu under Accessories. You can also find it in the Extras section. Enter in the username and activation code you received when you activated the plugin earlier. After activation you’ll see a list of the RSS feeds you currently subscribed through Internet Explorer. Click on the site feed you want to read and you’ll get a list of the different items available. Next you get and overview of the contents for the item you selected. From there you can show the page of the website containing that item. For any audio or video feeds you subscribe to, at the overview screen, click on Play to watch it. Then just sit back and watch your favorite video RSS feeds on WMC.   Media Center RSS Reader plugin will work with Vista and Windows 7. If you’re looking for a way to check out your RSS feeds in WMC this is a cool plugin for it. Download Media Center RSS Reader –You can activate it here as well. Similar Articles Productive Geek Tips Using Netflix Watchnow in Windows Vista Media Center (Gmedia)Integrate Boxee with Media Center in Windows 7Integrate Hulu Desktop and Windows Media Center in Windows 7Add Color Coding to Windows 7 Media Center Program GuideSchedule Updates for Windows Media Center TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional 15 Great Illustrations by Chow Hon Lam Easily Sync Files & Folders with Friends & Family Amazon Free Kindle for PC Download Stretch popurls.com with a Stylish Script (Firefox) OldTvShows.org – Find episodes of Hitchcock, Soaps, Game Shows and more Download Microsoft Office Help tab

    Read the article

  • Programmatically specifying Django model attributes

    - by mojbro
    Hi! I would like to add attributes to a Django models programmatically, at run time. For instance, lets say I have a Car model class and want to add one price attribute (database column) per currency, given a list of currencies. What is the best way to do this? I had an approach that I thought would work, but it didn't exactly. This is how I tried doing it, using the car example above: from django.db import models class Car(models.Model): name = models.CharField(max_length=50) currencies = ['EUR', 'USD'] for currency in currencies: Car.add_to_class('price_%s' % currency.lower(), models.IntegerField()) This does seem to work pretty well at first sight: $ ./manage.py syncdb Creating table shop_car $ ./manage.py dbshell shop=# \d shop_car Table "public.shop_car" Column | Type | Modifiers -----------+-----------------------+------------------------------------------------------- id | integer | not null default nextval('shop_car_id_seq'::regclass) name | character varying(50) | not null price_eur | integer | not null price_usd | integer | not null Indexes: "shop_car_pkey" PRIMARY KEY, btree (id) But when I try to create a new Car, it doesn't really work anymore: >>> from shop.models import Car >>> mycar = Car(name='VW Jetta', price_eur=100, price_usd=130) >>> mycar <Car: Car object> >>> mycar.save() Traceback (most recent call last): File "<console>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 410, in save self.save_base(force_insert=force_insert, force_update=force_update) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/base.py", line 495, in save_base result = manager._insert(values, return_id=update_pk) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/manager.py", line 177, in _insert return insert_query(self.model, values, **kwargs) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/query.py", line 1087, in insert_query return query.execute_sql(return_id) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/subqueries.py", line 320, in execute_sql cursor = super(InsertQuery, self).execute_sql(None) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) ProgrammingError: column "price_eur" specified more than once LINE 1: ...NTO "shop_car" ("name", "price_eur", "price_usd", "price_eur... ^

    Read the article

< Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >