Search Results

Search found 5065 results on 203 pages for 'django rss'.

Page 18/203 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • How to register rss for a website?

    - by domainking
    I am not sure if I ask this question in the right place, because I am new to it. What I want to ask is, do I need to register/create RSS for my website? I have a website, lets say: [http://blog.domain.com] = its a 2.9.2 wordpress blog So, if I want to display the latest content in another subdomain, for example: [news.domain.com], how do I do that? I know a little bit of php and mysql.

    Read the article

  • How To Make RSS Data Accessible

    - by xarzu
    RSS data is nothing more than xml data, right? But is it some sort of special format that a webmaster have to follow inorder to be read from an RSS Reader? How do I make the XML data of my web site formatted for RSS readers?

    Read the article

  • How to promote my Rss feed ?

    - by Ican Zilb
    I started recently this blog about iPhone / Objective-c : www.touch-code-magazine.com and I'm looking for ways to spread the word about my Rss feed. Question is how one promotes an rss feed ? Any of you have good recommendation how to do that? Advice on "best" feed directories or thematic portals which consume rss ... don't know, what do you say ?

    Read the article

  • Parsing atom/rss feed containing multiple <link> tags with Haml on RoR

    - by fenderplayer
    So, firstly, heres an atom feed snippet which i am trying to parse: // http://somelink.com/atom <feed xmlns="http://www.w3.org/2005/Atom"> <entry> <title>Title Here</title> <link href="http://somelink.com/link1&amp;amp;ref=rss" rel="alternate" /> <link href="http://somelink.com/link2&amp;amp;ref=rss" rel="tag:somelink.com/apply_url"/> ... </entry> i pull the atom feed like so, // In controller index method @rss = SimpleRSS.parse open('http://somelink.com/atom') Then i output the response in the view, which i am writing using haml, as follows: - @rss.entries.each do |item| .title-div = item.title .title-link = item.link //outputs the first link I could run a second loop for the links but is there a way to get the second link without it? Like reading the "rel" attribute and outputting the correct link? How do i do this in haml/rails?

    Read the article

  • Asp.net MVC RSS help needed.

    - by coure06
    Following the tutorial at http://www.developerzen.com/2009/01/11/aspnet-mvc-rss-feed-action-result/ My code for the controller is like this, but i am not getting any result from http://www.gadgetfind.com/rss.xml public ActionResult Feed() { SyndicationFeed feed = new SyndicationFeed("Test Feed", "This is a test feed", new Uri("http://www.gadgetfind.com/rss.xml"), "TestFeedID", DateTime.Now); SyndicationItem item = new SyndicationItem("Test Item", "This is the content for Test Item", new Uri("http://www.gadgetfind.com/rss.xml"), "TestItemID", DateTime.Now); List<SyndicationItem> items = new List<SyndicationItem>(); items.Add(item); feed.Items = items; return new RssActionResult() { Feed = feed }; }

    Read the article

  • Can django's auth_user.username be varchar(75)? How could that be done?

    - by perrierism
    Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything? If you were to change auth_user.username to be varchar(75) where would you need to modify django? Is it simply a matter of changing 30 to 75 in the source code?: username = models.CharField(_('username'), max_length=30, unique=True, help_text=_("Required. 30 characters or fewer. Letters, numbers and @/./+/-/_ characters")) Or is there other validation on this field that would have to be changed or any other repercussions to doing so? See comment discussion with bartek below regarding the reason for doing it.

    Read the article

  • Adding links to full change forms for inline items in django admin?

    - by David Eyk
    I have a standard admin change form for an object, with the usual StackedInline forms for a ForeignKey relationship. I would like to be able to link each inline item to its corresponding full-sized change form, as the inline item has inlined items of its own, and I can't nest them. I've tried everything from custom widgets to custom templates, and can't make anything work. So far, the "solutions" I've seen in the form of snippets just plain don't seem to work for inlines. I'm getting ready to try some DOM hacking with jQuery just to get it working and move on. I hope I must be missing something very simple, as this seems like such a simple task! Using Django 1.2.

    Read the article

  • Securing Elmah RSS Feeds in ASP.NET website

    - by olivehour
    I followed the answer to this question http://stackoverflow.com/questions/1245364/securing-elmah-in-asp-net-website to restrict access to the elmah handler. However, it seems that adding an RSS feed to Outlook for the URL elmah.axd/rss or elmah.axd/digestrss bypasses the authentication. What's the point of securing the handler if someone can guess the RSS URL and subscribe to a feed of the error log?

    Read the article

  • How do I flag only one of the formsets in django admin?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). my admin.py has: from django.contrib import admin class OptionInline(admin.TabularInline): model = Option extra = 5 max_num = 5 class QuestionAdmin(admin.ModelAdmin): inlines = [OptionInline, ] admin.site.register(QType) admin.site.register(Question, QuestionAdmin)

    Read the article

  • Serializing data from a RSS feed in ASP.NET/C#

    - by DotnetDude
    I'd like the user to specify a RSS feed address and serialize the information from it. I am not interested in the XML format, but populate a strongly typed object from the XML. My question is, is there a standard that all RSS feeds support (Do all of them have date, title etc)? If so, is there a XSD that describes this. If not, how do I handle serializing a RSS feed to an object in ASP.NET?

    Read the article

  • java library for reading RSS and ATOM feeds

    - by Samuel
    I am looking for libraries which can read RSS / ATOM feeds in my J2EE application (based on JBoss Seam). Is Rome the only application there for reading feeds? I am assuming the Seam RSS integration is only for generating RSS feeds and not for reading feeds.

    Read the article

  • How can I call model methods or properties from Django Admin?

    - by kg
    Is there a natural way to display model methods or properties in the Django admin site? In my case I have base statistics for a character that are part of the model, but other things such as status effects which affect the total calculation for that statistic: class Character(models.Model): base_dexterity = models.IntegerField(default=0) @property def dexterity(stat_name): total = self.base_dexterity total += sum(s.dexterity for s in self.status.all()]) return total It would be nice if I could display the total calculated statistic alongside the field to change the base statistic in the Change Character admin page, but it is not clear to me how to incorporate that information into the page.

    Read the article

  • Rss Feed Java MVC

    - by GigaPr
    Hi, i would like to create some RSS Feeds for my website. I managed to crate the XML file but How do i display it in a nice format like http://newsrss.bbc.co.uk/rss/newsonline_uk_edition/front_page/rss.xml and how do i crate the little icon in the url box? by the way my XML file looks like <?xml version='1.0' encoding='UTF-8'?> <rss version="2.0"> <channel> <title>title</title> <description>desciption</description> <link>LINK</link> <dateCreated>2010-05-31 00:00:00.0</dateCreated> <language>Italian</language> <item> <title>pojpoj</title> <description>pojpojpoj</description> <link>ojpojpoj</link> <dateCreated>2010-06-03 00:00:00.0</dateCreated> <pubDate>2010-06-03 00:00:00.0</pubDate> </item> <item> <title>dfojp</title> <description>pojpojpoj</description> <link>pojpoj</link> <dateCreated>2010-06-03 00:00:00.0</dateCreated> <pubDate>2010-06-03 00:00:00.0</pubDate> </item> </channel> </rss> Thanks

    Read the article

  • Converting XML to RSS

    - by hkw
    I've got an xml feed that will be published in one location of our website, and would like to repurpose that for an RSS feed. A few different pages on the website will also be referencing the same xml - all of those transformations are set up and working. The base xml file (XMLTEST.xml) is using this structure: <POST> <item> <POST_ID>80000852</POST_ID> <POST_TITLE>title</POST_TITLE> <POST_CHANNEL>I</POST_CHANNEL> <POST_DESC>description</POST_DESC> <LINK>http://www...</LINK> <STOC>N</STOC> </item> </POST> I'm trying to transform the xml into an RSS feed using the following setup (feed.xml + rss.xsl) feed.xml: <?xml-stylesheet href="rss.xsl" type="text/xsl"?> <RSSChannels> <RSSChannel src="XMLTEST.xml"/> </RSSChannels> rss.xsl: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" /> <xsl:template match="RSSChannels"> <rss version="2.0"> <channel> <title>site title</title> <link></link> <description>Site description...</description> <xsl:apply-templates /> </channel> </rss> </xsl:template> <xsl:template match="RSSChannel"> <xsl:apply-templates select="document(@src)" /> </xsl:template> <xsl:template match="item"> <xsl:choose> <xsl:when test="STOC = 'Y'"></xsl:when> <xsl:when test="POST_CHANNEL = 'I'"></xsl:when> <xsl:otherwise> <item> <title> <xsl:value-of select="*[local-name()='POST_TITLE']" /> </title> <link> <xsl:value-of select="*[local-name()='LINK']" /> </link> <description> <xsl:value-of select="*[local-name()='POST_DESC']" /> </description> </item> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> When I try to view the output of feed.xml in Firefox, all of the filtering is applied correctly (sorting out items that shouldn't be published in that channel), but the page outputs as plain text, rather than the usual feed-detection that takes place in Firefox. Any ideas on what I'm missing? Thanks for any suggestions you can provide.

    Read the article

  • Naive question about implementing RSS

    - by interstar
    I have a naive question about RSS feeds. I have a series of timed events which appear on my site and that I make available as an RSS feed for other applications to import. Who is typically responsible for truncating this feed? Over the next year, I can see my feed having thousands of items. Should the URL mysite.com/rss always return all items? And leave it to the readers to just show the most recent? Or is it more customary that I only return, say, the top 50? Expecting the readers to cache older items? (And, if so, is there a convention for readers to ask the server for the "next page")? What is the typical behaviour of something like FriendFeed when it pulls in an RSS stream?

    Read the article

  • php count rss entries since a specific date/time

    - by Steven
    can anyone tell me why this code don't work: $q = $_GET['q']; // Load and parse the XML document $rss = simplexml_load_file("http://search.twitter.com/search.atom?lang=en&q=$q&rpp=100&page=1"); $Count1 = 0; while(strtotime($rss->entry->published)>1270833600){ foreach ($rss->entry as $item) { $Count1++; } } print "Total Record: ".$Count1;

    Read the article

  • Sharepoint RSS feed description fields as elements

    - by Jay
    Hello, This is my first time working with RSS but I am fluent with XML/XSL. I have a RSS feed that I am pulling from a list in Sharepoint. The sample XML is below. The RSS description element parses the various columns (Body, Expires, Attachments) that are in the Sharepoint list automatically. I know that from the list I can control which fields are included in the description, but this is not what I am looking to do. Is there any way to force the fields to come through in an XML element format instead of the CDATA that converted to HTML? For example, I may want to check a priority field and if it is important when applying the XSL I would bold red it or something. Since this is in the HTML/CDATA format it makes it messy to parse that field. <rss version="2.0"> <channel> <title>Announcements</title> <link>http://somewebsite/Announcements/Current.aspx</link> <description>RSS feed for the Announcements list.</description> <lastBuildDate>Thu, 13 Aug 2009 17:31:01 GMT</lastBuildDate> <generator>Windows SharePoint Services V3 RSS Generator</generator> <ttl>1</ttl> <image> <title>Announcements</title> <url>/_layouts/images/homepage.gif</url> <link>http://somewebsite/Announcements/Current.aspx</link> </image> <item> <title>Woohoo a post! </title> <link>http://somewebsite/Announcements/DispForm.aspx?ID=36</link> <description> <![CDATA[<div><b>Body:</b> <div> <div>The attached email was sent from chairman and CEO on Tuesday March 3, 2009.</div> <div></div></div></div> <div><b>Expires:</b> 7/30/2009</div> <div><b>Attachments:</b> <a href="http://somewebsite/Woohoo.htm">http://somewebsite/Woohoo.htm</a><br><a href=""></a></div> ]]> </description> <author>Me, Myself and I</author> <pubDate>Thu, 16 Jul 2009 18:38:32 GMT</pubDate> <guid isPermaLink="true">http://somewebsite/Announcements/DispForm.aspx?ID=69</guid> </item> </channel> </rss>

    Read the article

  • Django 1.5 custom User model error. "Manager isn't available; User has been swapped"

    - by bpetit
    I extend the django user model as described in the dev doc. I wan't to keep most of the original User model features so I extend the AbstractUser class. I've defined in settings.py: AUTH_USER_MODEL = 'myapp.CustomUser' My user class: class CustomUser(AbstractUser): custom_field = models.ForeignKey('OtherModel') objects = UserManager() Everything seems to work fine but when I try to make it managed by the admin site: admin.site.register(CustomUser, UserAdmin) I get this error on the admin CustomUser creation page (after validation of the password confirmation form): AttributeError: Manager isn't available; User has been swapped for 'myapp.CustomUser' The point is that I need this model managed by the admin site in order to have the same creation process as with the original User model (two step process with password validation). Thanks for any reply

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >