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  • Removing PDF attachments via itext

    - by r00fus
    I'm trying to remove attachments from a number of my pdf files (I can extract via pdftk, so preserving them is not an issue). I coded the following based on an example found from a google search: import java.io.FileOutputStream; import java.io.IOException; import com.lowagie.text.*; import com.lowagie.text.pdf.*; class pdfremoveattachment { public static void main(String[] args) throws IOException, DocumentException { if (args.length < 2) { System.out.println("Usage: java PDFremoveAttachments source.pdf target.pdf"); System.exit(1); } PdfReader sourcePDF = new PdfReader(args[0]); removeAttachments(sourcePDF); FileOutputStream targetFOS = new FileOutputStream(args[1]); PdfStamper targetPDF = new PdfStamper(sourcePDF,targetFOS); targetPDF.close(); } public static void removeAttachments(PdfReader reader) { PdfDictionary catalog = reader.getCatalog(); // System.out.println(catalog.getAsDict(PdfName.NAME)); // this would print "null" PdfDictionary names = (PdfDictionary)PdfReader.getPdfObject(catalog.get(PdfName.NAMES)); // System.out.println(names.toString()); //this returns NPE if( names != null) { PdfDictionary files = (PdfDictionary) PdfReader.getPdfObject(names.get(PdfName.FILEATTACHMENT)); if( files!= null ){ for( Object key : files.getKeys() ){ files.remove((PdfName)key); } files = (PdfDictionary) PdfReader.getPdfObject(names.get(PdfName.EMBEDDEDFILES)); } if( files!= null ){ for( Object key : files.getKeys() ){ files.remove((PdfName)key); } reader.removeUnusedObjects(); } } } } If anyone knows how I might be able to remove attachments, I'd greatly appreciate a reply.

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  • image not displaying in midlet

    - by user316843
    Hello all,am new here. i have a slight problem; PLease look at the following code and tell me if am doing something wrong because the image is not displaying. i have made it really small so it should fit but its not displaying. i have images displaying in other screens but this main midlet would not. Here is the code: import java.io.IOException; import javax.microedition.midlet.*; import javax.microedition.lcdui.*; /** * @author jay */ public class WShop extends MIDlet implements CommandListener { /* Declare display variables*/ private Form mainForm; private Display display; private Command OK,Exit,wView, mView, myView; /* */ Categories categories = new Categories(this); Image image; public WShop() { /* initialize Screen and Command buttons that will be used when the application starts in the class constructor*/ mainForm = new Form("Wind Shopper"); OK = new Command("OK", Command.OK, 2); Exit = new Command("Exit", Command.EXIT, 0); wview= new Command("wview", Command.OK, 0); mview= new Command("mview", Command.OK, 0); try { /* retrieving the main image of the application*/ image = Image.createImage("/main.png"); } catch (IOException ex) { ex.printStackTrace(); } mainForm.addCommand(OK); mainForm.addCommand(Exit); mainForm.addCommand(wView); mainForm.addCommand(mView); mainForm.setCommandListener(this); } public void startApp() { /* checks to see if the display is currently empty and then sets it to the current screen */ if (display == null) { display = Display.getDisplay(this); } display.setCurrent(mainForm); } /* paused state of the application*/ public void pauseApp() { } /* Destroy Midlet state*/ public void destroyApp(boolean unconditional) { } Thanks in advance.

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  • Spring MVC- several parts/views from a controller

    - by leeeroy
    i'm looking into using Spring MVC - how would I structure the fact that a page can be composed of several different views Consider a controller that's basically: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); return new ModelAndView("posts", "posts", posts); } However, I decide that on every page, I'd also want a side "pane" that shows data based on some logic. That "pane" would just be a .jsp that gets included from the above "posts" view, and I could change my controller to: public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Post> posts = repository.getNewPosts(); List<Items> items= repository.getItems(); return new ModelAndView("model", "model", new MyCommonViewModel(posts,items)); } But then I'd have to change every controller to also do List<Items> items= repository.getItems(); , and change everything again the next time I come up with something new. This seems messy. How do I structure this ? `

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  • java - codesprint2 programming contest answer

    - by arya
    I recently took part in Codesprint2. I was unable to submit the solution to the following question. http://www.spoj.pl/problems/COINTOSS/ ( I have posted the link to the problem statement at spoj because the codesprint link requires login ) I checked out one of the successful solutions, ( url : http://pastebin.com/uQhNh9Rc ) and the logic used is exactly the same as mine, yet I am still getting "Wrong Answer" I would be very thankful if someone could please tell me what error I have made, as I am unable to find it. Thank you. My code : import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.text.DecimalFormat; import java.util.StringTokenizer; public class Solution { static double solve( int n, int m ) { if( m==n ) return 0; if( m==0 ) return ( Math.pow( 2, n+1 ) - 2 ); else { double res = 1 + ( Double )( solve( n, m+1 ) + solve( n, 0 ))/2; return res; } } public static void main( String[] args ) throws IOException { BufferedReader br = new BufferedReader( new InputStreamReader( System.in )); int n, m; int t = Integer.parseInt( br.readLine() ); StringTokenizer tok; String s; for( int T=0; T<t; T++ ) { s = br.readLine(); tok = new StringTokenizer( s ); n = Integer.parseInt( tok.nextToken() ); m = Integer.parseInt( tok.nextToken() ); DecimalFormat df = new DecimalFormat(); df.setMaximumFractionDigits(2); df.setMinimumFractionDigits(2); System.out.println( df.format ( solve( n, m ) )); } } }

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  • help on ejb stateless datagram and message driven beans

    - by Kemmal
    i have a client thats sending a message to the ejbserver using UDP, i want the server(stateless bean) to echo back this message to the client but i cant seem to do this. or can i implement the same logic by using JMS? please help and enlighten. this is just a test, in the end i want a midp to be sending the message to the ejb using datagrams. here is my code. @Stateless public class SessionFacadeBean implements SessionFacadeRemote { public SessionFacadeBean() { } public static void main(String[] args) { DatagramSocket aSocket = null; byte[] buffer = null; try { while(true) { DatagramPacket request = new DatagramPacket(buffer, buffer.length); aSocket.receive(request); DatagramPacket reply = new DatagramPacket(request.getData(), request.getLength(), request.getAddress(), request.getPort()); aSocket.send(reply); } } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } } and the client: public static void main(String[] args) { DatagramSocket aSocket = null; try { aSocket = new DatagramSocket(); byte [] m = "Test message!".getBytes(); InetAddress aHost = InetAddress.getByName("localhost"); int serverPort = 6789; DatagramPacket request = new DatagramPacket(m, m.length, aHost, serverPort); aSocket.send(request); byte[] buffer = new byte[1000]; DatagramPacket reply = new DatagramPacket(buffer, buffer.length); aSocket.receive(reply); System.out.println("Reply: " + new String(reply.getData())); } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } please help.

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  • How to use log4j for a axis2 webservice

    - by KItis
    I have created a simple axis2 webservice to understand logging functionality in a webservice. in this sample webservice, when a client calls this webservice, first it reads the log4j.property file. then i can see the logs being printed on console. but i have included file appender too into the property file. but i can not file the log file any where in my sample webapplication. i am using tomcat to run the webservice. following is webservice interface method called by client. package test; import java.io.IOException; import java.io.InputStream; import java.util.Properties; import org.apache.log4j.BasicConfigurator; import org.apache.log4j.Logger; import org.apache.log4j.PropertyConfigurator; public class WSInterface { static final Logger logger = Logger.getLogger(WSInterface.class); public String log4jTest(String input){ InputStream inputStream = this.getClass().getClassLoader() .getResourceAsStream(input); Properties properties = new Properties(); System.out.println("InputStream is: " + inputStream); //load the inputStream using the Properties try { properties.load(inputStream); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } PropertyConfigurator.configure(properties); logger.debug("Hello World!"); Class myclass = WSInterface.class; String url = myclass.getResource("WSInterface.class").toString(); String output = ""; return url; } }

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  • Java hangs when trying to close a ProcessBuilder OutputStream

    - by Jeff Bullard
    I have the following Java code to start a ProcessBuilder, open an OutputStream, have the process write a string to an OutputStream, and then close the OutputStream. The whole thing hangs indefinitely when I try to close the OutputStream. This only happens on Windows, never on Mac or Linux. Some of the related questions seem to be close to the same problem I'm having, but I haven't been able to figure out how to apply the answers to my problem, as I am a relative newbie with Java. Here is the code. You can see I have put in a lot of println statements to try to isolate the problem. System.out.println("GenMic trying to get the input file now"); System.out.flush(); OutputStream out = child.getOutputStream(); try { System.out.println("GenMic getting ready to write the input file to out"); System.out.flush(); out.write(intext.getBytes()); System.out.println("GenMic finished writing to out"); System.out.flush(); out.close(); System.out.println("GenMic closed OutputStream"); System.out.flush(); } catch (IOException iox) { System.out.println("GenMic caught IOException 2"); System.out.flush(); String detailedMessage = iox.getMessage(); System.out.println("Exception: " + detailedMessage); System.out.flush(); throw new RuntimeException(iox); } And here is the output when this chunk is executed: GenMic trying to get the input file now GenMic getting ready to write the input file to out GenMic finished writing to out

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  • how to handle out of memory error?

    - by UMMA
    dear friends, i am using following code to display bitmap in my imageview. when i try to load image of size for example bigger than 1.5MB it give me error any one suggest me solution? try { URL aURL = new URL(myRemoteImages[val]); URLConnection conn = aURL.openConnection(); conn.connect(); InputStream is = null; try { is= conn.getInputStream(); }catch(IOException e) { return 0; } int a= conn.getConnectTimeout(); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm; try { bm = BitmapFactory.decodeStream(bis); }catch(Exception ex) { bis.close(); is.close(); return 0; } bis.close(); is.close(); img.setImageBitmap(bm); } catch (IOException e) { return 0; } return 1; Log cat 06-14 12:03:11.701: ERROR/AndroidRuntime(443): Uncaught handler: thread main exiting due to uncaught exception 06-14 12:03:11.861: ERROR/AndroidRuntime(443): java.lang.OutOfMemoryError: bitmap size exceeds VM budget 06-14 12:03:11.861: ERROR/AndroidRuntime(443): at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)

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  • ListView Parsing Persian xml

    - by Namikaze Minato
    I used a tutorial about listview parsing xm from internet and using LasyAdapter shows the items in listview. When I add persian characters in xml (into one of childnodes) the result is some boxes in listview (after showing the text in listview). The format of xml is UTF-8, too. I used typeface too (but didn't work). Besides when I type Pwesian into the application it shows alright but it can't show Persiann content parsed from xml. Thanks in advance. I updated the post with original XMLparser (which was the problem). public String getXmlFromUrl(String url) { String xml = null; try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return xml; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; }

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  • EOFException in ObjectInputStream Only happens with Webstart not by java(w).exe ?!

    - by Houtman
    Hi, Anyone familiar with the differences in starting with Webstart(javaws.exe) compared to starting the app. using java.exe or javaw.exe regarding streams ? This is the exception which i ONLY get when using Webstart : java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source) at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source) at java.io.ObjectInputStream.readStreamHeader(Unknown Source) at java.io.ObjectInputStream.<init>(Unknown Source) at fasttools.jtools.dss.api.core.remoting.thinclient.RemoteSocketChannel.<init>(RemoteSocketChannel.java:77) This is how i setup the connections on both sides //==Server side== //Thread{ Socket mClientSocket = cServSock.accept(); new DssServant(mClientSocket).start(); //} DssServant(Socket socket) throws DssException { try { OutputStream mOutputStream = new BufferedOutputStream( socket.getOutputStream() ); cObjectOutputStream = new ObjectOutputStream(mOutputStream); cObjectOutputStream.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( socket.getInputStream() ); cObjectInputStream = new ObjectInputStream(mInputStream); .. } catch (IOException e) { .. } .. } //==Client side== public RemoteSocketChannel(String host, int port, IEventDispatcher eventSubscriptionHandler) throws DssException { cHost = host; port = (port == 0 ? DssServer.PORT : port); try { cSocket = new Socket(cHost, port); OutputStream mOutputStream = new BufferedOutputStream( cSocket.getOutputStream() ); cObjectOut = new ObjectOutputStream(mOutputStream); cObjectOut.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( cSocket.getInputStream() ); cObjectIn = new ObjectInputStream(mInputStream); } catch (IOException e) { .. } .. } Thanks [EDIT] Webstart console says: Java Web Start 1.6.0_19 Using JRE version 1.6.0_19-b04 Java HotSpot(TM) Client VM Server is running same 1.6u19

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  • Why my inner class DO see a NON static variable?

    - by Roman
    Earlier I had a problem when an inner anonymous class did not see a field of the "outer" class. I needed to make a final variable to make it visible to the inner class. Now I have an opposite situation. In the "outer" class "ClientListener" I use an inner class "Thread" and the "Thread" class I have the "run" method and does see the "earPort" from the "outer" class! Why? import java.io.IOException; import java.net.*; import java.io.BufferedReader; import java.io.InputStreamReader; public class ClientsListener { private int earPort; // Constructor. public ClientsListener(int earPort) { this.earPort = earPort; } public void starListening() { Thread inputStreamsGenerator = new Thread() { public void run() { System.out.println(earPort); try { System.out.println(earPort); ServerSocket listeningSocket = new ServerSocket(earPort); Socket serverSideSocket = listeningSocket.accept(); BufferedReader in = new BufferedReader(new InputStreamReader(serverSideSocket.getInputStream())); } catch (IOException e) { System.out.println(""); } } }; inputStreamsGenerator.start(); } }

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  • commons-exec: hanging when I call executor.execute(commandLine);

    - by Stefan Kendall
    I have no idea why this is hanging. I'm trying to capture output from a process run through commons-exec, and I continue to hang. I've provided an example program to demonstrate this behavior below. import java.io.DataInputStream; import java.io.IOException; import java.io.PipedInputStream; import java.io.PipedOutputStream; import org.apache.commons.exec.CommandLine; import org.apache.commons.exec.DefaultExecutor; import org.apache.commons.exec.ExecuteException; import org.apache.commons.exec.PumpStreamHandler; public class test { public static void main(String[] args) { String command = "java"; PipedOutputStream output = new PipedOutputStream(); PumpStreamHandler psh = new PumpStreamHandler(output); CommandLine cl = CommandLine.parse(command); DefaultExecutor exec = new DefaultExecutor(); DataInputStream is = null; try { is = new DataInputStream(new PipedInputStream(output)); exec.setStreamHandler(psh); exec.execute(cl); } catch (ExecuteException ex) { } catch (IOException ex) { } System.out.println("huh?"); } }

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  • Problem with relative file path

    - by Richard Knop
    So here is my program, which works ok: import java.io.FileReader; import java.io.BufferedReader; import java.io.IOException; import java.util.Scanner; import java.util.Locale; public class ScanSum { public static void main(String[] args) throws IOException { Scanner s = null; double sum = 0; try { s = new Scanner(new BufferedReader(new FileReader("D:/java-projects/HelloWorld/bin/usnumbers.txt"))); s.useLocale(Locale.US); while (s.hasNext()) { if (s.hasNextDouble()) { sum += s.nextDouble(); } else { s.next(); } } } finally { s.close(); } System.out.println(sum); } } As you can see, I am using absolute path to the file I am reading from: s = new Scanner(new BufferedReader(new FileReader("D:/java-projects/HelloWorld/bin/usnumbers.txt"))); The problem arises when I try to use the relative path: s = new Scanner(new BufferedReader(new FileReader("usnumbers.txt"))); I get an error: Exception in thread "main" java.lang.NullPointerException at ScanSum.main(ScanSum.java:24) The file usnumbers.txt is in the same directory as the ScanSum.class file: D:/java-projects/HelloWorld/bin/ScanSum.class D:/java-projects/HelloWorld/bin/usnumbers.txt How could I solve this?

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  • exception in thread "main" java.lang.NoclassDefFoundError: cal/class

    - by Gaurav
    enter import java.io.*; class eval { double add(double a,double b) { return (a+b); } double sub(double a,double b) { return (a-b); } double mul(double a,double b) { return (a*b); } double div(double a,double b) { return (a/b); } } class cal extends eval { public static void main(String args[])throws IOException { eval a1=new eval(); try{ System.out.println("1) Add"); System.out.println("2) Subtract"); System.out.println("3) Multiply"); System.out.println("4) Divide"); System.out.println("5) Enter your choice"); BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int ch;ch=Integer.parseInt(br.readLine()); System.out.println("Enter two number"); double a;a=Integer.parseInt(br.readLine()); double b;b=Integer.parseInt(br.readLine()); switch(ch) { case 1: a1.add(a,b); break; case 2: a1.sub(a,b); break; case 3: a1.mul(a,b); break; case 4: a1.div(a,b); break; } } catch (IOException e) { System.out.println("Error occured, please restart application."); } } }

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  • hadoop implementing a generic list writable

    - by Guruprasad Venkatesh
    I am working on building a map reduce pipeline of jobs(with one MR job's output feeding to another as input). The values being passed around are fairly complex, in that there are lists of different types and hash maps with values as lists. Hadoop api does not seem to have a ListWritable. Am trying to write a generic one, but it seems i can't instantiate a generic type in my readFields implementation, unless i pass in the class type itself: public class ListWritable<T extends Writable> implements Writable { private List<T> list; private Class<T> clazz; public ListWritable(Class<T> clazz) { this.clazz = clazz; list = new ArrayList<T>(); } @Override public void write(DataOutput out) throws IOException { out.writeInt(list.size()); for (T element : list) { element.write(out); } } @Override public void readFields(DataInput in) throws IOException{ int count = in.readInt(); this.list = new ArrayList<T>(); for (int i = 0; i < count; i++) { try { T obj = clazz.newInstance(); obj.readFields(in); list.add(obj); } catch (InstantiationException e) { e.printStackTrace(); } catch (IllegalAccessException e) { e.printStackTrace(); } } } } But hadoop requires all writables to have a no argument constructor to read the values back. Has anybody tried to do the same and solved this problem? TIA.

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  • Check if file is locked or catch error for trying to open

    - by Duncan Matheson
    I'm trying to handle the problem where a user can try to open, with an OpenFileDialog, a file that is open by Excel. Using the simple FileInfo.OpenRead(), it chucks an IOException, "The process cannot access the file 'cakes.xls' because it is being used by another process." This would be fine to display to the user except that the user will actually get "Debugging resource strings are unavailable" nonsense. It seems not possible to open a file that is open by another process, since using FileInfo.Open(FileMode.Open, FileAccess.Read, FileShare.ReadWrite) chucks a SecurityException, "File operation not permitted. Access to path 'C:\whatever\cakes.xls' is denied.", for any file. Rather unhelpful. So it's down to either finding some way of checking if the file is locked, or trying to catch the IOException. I don't want to catch all IOExceptions and assume they're all locked file errors, so I need some sort of way of classifying this type of exception as this error... but the "Debugging resource strings" nonsense along with the fact that that message itself is probably localized makes it tricky. I'm partial trust, so I can't use Marshal.GetHRForException. So: Is there any sensible way of either check if a file is locked, or at least determining if this problem occurred without just catching all IOExceptions?

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Problem with object serialization in Applet-Servlet communication

    - by Bruce
    Hi guys, I spent a lot of time on thinking what is wrong with the following code. I send the object from my applet to servlet and then I read the object from servlet. Everything goes fine till reading serialized object from the servlet - I got IOException. Thank you in advance! Here is the code: Applet: try { URL servletURL = new URL(this.getCodeBase().getProtocol(), this.getCodeBase().getHost(), this.getCodeBase().getPort(), "/MyApplet"); URLConnection servletConnection = servletURL.openConnection(); servletConnection.setDoInput( true ); servletConnection.setDoOutput( true ); servletConnection.setUseCaches( false ); servletConnection.setRequestProperty( "Content-Type", "application/x-java-serialized-object" ); ObjectOutputStream output; output = new ObjectOutputStream( servletConnection.getOutputStream( ) ); output.writeObject( someObject ); output.flush( ); output.close( ); ObjectInputStream input = new ObjectInputStream( servletConnection.getInputStream( ) ); // Here I got the exception myObject = ( SomeObject ) input.readObject( ); } catch (java.io.IOException ioe) { System.err.println(ioe.getStackTrace()); } catch (Exception e) { System.err.println(e.getStackTrace()); } Servlet: response.setContentType("application/x-java-serialized-object"); try { ObjectInputStream inputFromApplet = new ObjectInputStream(request.getInputStream()); SomeObject myObject = (SomeObject) inputFromApplet.readObject(); ObjectOutputStream outputToApplet = new ObjectOutputStream(response.getOutputStream()); outputToApplet.writeObject(myObject); outputToApplet.flush(); } catch(Exception e) { // ... }

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  • Google App Engine how to get an object from the servlet ?

    - by Frank
    I have the following class objects in Google App Engine's dadastore, I can see them from the "Datastore Viewer " : import javax.jdo.annotations.IdGeneratorStrategy; import javax.jdo.annotations.IdentityType; import javax.jdo.annotations.PersistenceCapable; import javax.jdo.annotations.Persistent; import javax.jdo.annotations.PrimaryKey; @PersistenceCapable(identityType=IdentityType.APPLICATION) public class Contact_Info_Entry implements Serializable { @PrimaryKey @Persistent(valueStrategy=IdGeneratorStrategy.IDENTITY) Long Id; public static final long serialVersionUID=26362862L; String Contact_Id="",First_Name="",Last_Name="",Company_Name="",Branch_Name="",Address_1="",Address_2="",City="",State="",Zip="",Country=""; double D_1,D_2; boolean B_1,B_2; Vector<String> A_Vector=new Vector<String>(); public Contact_Info_Entry() { } ...... } How can my java applications get the object from a servlet url ? For instance if have an instance of Contact_Info_Entry who's Contact_Id is "ABC-123", and my App Id is : nm-java When my java program accesses the url : "http://nm-java.appspot.com/Check_Contact_Info?Contact_Id=ABC-123 How will the Check_Contact_Info servlet get the object from datastore and return it to my app ? public class Check_Contact_Info_Servlet extends HttpServlet { static boolean Debug=true; public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException { } ... protected void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException { doGet(request,response); } } Frank

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  • Python Error-Checking Standard Practice

    - by chaindriver
    Hi, I have a question regarding error checking in Python. Let's say I have a function that takes a file path as an input: def myFunction(filepath): infile = open(filepath) #etc etc... One possible precondition would be that the file should exist. There are a few possible ways to check for this precondition, and I'm just wondering what's the best way to do it. i) Check with an if-statement: if not os.path.exists(filepath): raise IOException('File does not exist: %s' % filepath) This is the way that I would usually do it, though the same IOException would be raised by Python if the file does not exist, even if I don't raise it. ii) Use assert to check for the precondition: assert os.path.exists(filepath), 'File does not exist: %s' % filepath Using asserts seems to be the "standard" way of checking for pre/postconditions, so I am tempted to use these. However, it is possible that these asserts are turned off when the -o flag is used during execution, which means that this check might potentially be turned off and that seems risky. iii) Don't handle the precondition at all This is because if filepath does not exist, there will be an exception generated anyway and the exception message is detailed enough for user to know that the file does not exist I'm just wondering which of the above is the standard practice that I should use for my codes.

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  • FileNotFoundException Java

    - by Troels Hansen
    Hi, I'm trying to make a simple highscore system for a minesweeper game. However i keep getting a file not found exception, and i've tried to use the full path for the file aswell. package minesweeper; import java.io.*; import java.util.*; public class Highscore{ public static void submitHighscore(String difficulty) throws IOException{ int easy = 99999; int normal = 99999; int hard = 99999; //int newScore = (int) MinesweeperView.getTime(); int newScore = 10; File f = new File("Highscores.dat"); if (!f.exists()){ f.createNewFile(); } Scanner input = new Scanner(f); PrintStream output = new PrintStream(f); if (input.hasNextInt()){ easy = input.nextInt(); normal = input.nextInt(); hard = input.nextInt(); } output.flush(); if(difficulty.equals("easy")){ if (easy > newScore){ easy = newScore; } }else if (difficulty.equals("normal")){ if (normal > newScore){ normal = newScore; } }else if (difficulty.equals("hard")){ if (hard > newScore){ hard = newScore; } } output.println(easy); output.println(normal); output.println(hard); } //temporary main method used for debugging public static void main(String[] args) throws IOException { submitHighscore("easy"); } }

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  • JSP Upload File Java.lang.NullPointer

    - by newbie123
    I want to develope upload and download file from server. Upload.html <form action="/UploadFile/UploadFile" method="POST" enctype="multipart/form-data">Select a file: <input type="submit" name="button" /> <input type="file" name="first"></form> UploadFile.servlet protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String temp = request.getParameter("first"); System.out.println(temp); File origFile = new File(temp); FileOutputStream out = new FileOutputStream(request.getContextPath() + "pdtImages/" + "FirstFile"); InputStream ins = new FileInputStream(origFile); try { System.out.println(request.getContextPath()); byte[] buf = new byte[1024]; int len; while ((len = ins.read(buf)) > 0) { out.write(buf, 0, len); } out.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } When I submitted the file I got null pointer error message. I not very familiar with jsp can anybody help me? I want to store the file to the server directory.

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  • Scale an image which is stored as a byte[] in Java

    - by Sergio del Amo
    I upload a file with a struts form. I have the image as a byte[] and I would like to scale it. FormFile file = (FormFile) dynaform.get("file"); byte[] fileData = file.getFileData(); fileData = scale(fileData,200,200); public byte[] scale(byte[] fileData, int width, int height) { // TODO } Anyone knows an easy function to do this? public byte[] scale(byte[] fileData, int width, int height) { ByteArrayInputStream in = new ByteArrayInputStream(fileData); try { BufferedImage img = ImageIO.read(in); if(height == 0) { height = (width * img.getHeight())/ img.getWidth(); } if(width == 0) { width = (height * img.getWidth())/ img.getHeight(); } Image scaledImage = img.getScaledInstance(width, height, Image.SCALE_SMOOTH); BufferedImage imageBuff = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); imageBuff.getGraphics().drawImage(scaledImage, 0, 0, new Color(0,0,0), null); ByteArrayOutputStream buffer = new ByteArrayOutputStream(); ImageIO.write(imageBuff, "jpg", buffer); return buffer.toByteArray(); } catch (IOException e) { throw new ApplicationException("IOException in scale"); } } If you run out of Java Heap Space in tomcat as I did, increase the heap space which is used by tomcat. In case you use the tomcat plugin for Eclipse, next should apply: In Eclipse, choose Window Preferences Tomcat JVM Settings Add the following to the JVM Parameters section -Xms256m -Xmx512m

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  • Java: How to make this main thread wait for the new thread to terminate

    - by Jeff Bullard
    I have a java class that creates a process, called child, using ProcessBuilder. The child process generates a lot of output that I am draining on a separate thread to keep the main thread from getting blocked. However, a little later on I need to wait for the output thread to complete/terminate before going on, and I'm not sure how to do that. I think that join() is the usual way to do this but I'm not sure how to do that in this case. Here is the relevant part of the java code. // Capture output from process called child on a separate thread final StringBuffer outtext = new StringBuffer(""); new Thread(new Runnable() { public void run() { InputStream in = null; in = child.getInputStream(); try { if (in != null) { BufferedReader reader = new BufferedReader(new InputStreamReader(in)); String line = reader.readLine(); while ((line != null)) { outtext.append(line).append("\n"); ServerFile.appendUserOpTextFile(userName, opname, outfile, line+"\n"); line = reader.readLine(); } } } catch (IOException iox) { throw new RuntimeException(iox); } } }).start(); // Write input to for the child process on this main thread // String intext = ServerFile.readUserOpTextFile(userName, opname, infile); OutputStream out = child.getOutputStream(); try { out.write(intext.getBytes()); out.close(); } catch (IOException iox) { throw new RuntimeException(iox); } // ***HERE IS WHERE I NEED TO WAIT FOR THE THREAD TO FINISH *** // Other code goes here that needs to wait for outtext to get all // of the output from the process // Then, finally, when all the remaining code is finished, I return // the contents of outtext return outtext.toString();

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  • Just need someone familiar with HTTPClient to check over a piece of code

    - by jax
    here are two little helper methods I have made for downloading files. I have had to mix and match different tutorials of the web to get what I have here. Now is there anything that I have done blatantly wrong here? public static InputStream simplePostRequest(URL url, List<NameValuePair> postData) throws ClientProtocolException, IOException { DefaultHttpClient httpclient = new DefaultHttpClient(); HttpPost postMethod=new HttpPost(url.toExternalForm()); postMethod.setEntity(new UrlEncodedFormEntity(postData, HTTP.UTF_8)); HttpResponse response = httpclient.execute(postMethod); HttpEntity entity = response.getEntity(); return entity.getContent(); } public static InputStream simpleGetRequest(URL url, List<NameValuePair> queryString) throws ClientProtocolException, IOException { Uri.Builder uri = new Uri.Builder(); uri.path(url.getPath()); for(NameValuePair nvp: queryString) { uri.appendQueryParameter(nvp.getName(), nvp.getValue()); } DefaultHttpClient httpClient = new DefaultHttpClient(); HttpHost host = new HttpHost(url.getHost()); HttpResponse response = httpClient.execute(host, new HttpGet(uri.build().toString())); HttpEntity entity = response.getEntity(); return entity.getContent(); }

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