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  • Search a string in a file and write the matched lines to another file in Java

    - by Geeta
    For searching a string in a file and writing the lines with matched string to another file it takes 15 - 20 mins for a single zip file of 70MB(compressed state). Is there any ways to minimise it. my source code: getting Zip file entries zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while (entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if (entry.isDirectory()) { continue; } searchString(Thread.currentThread(),entry.getName(), new BufferedInputStream (zipFile.getInputStream(entry)), Out_File, search_string, stats); } zipFile.close(); Searching String public void searchString(Thread CThread, String Source_File, BufferedInputStream in, File outfile, String search, String stats) throws IOException { int count = 0; int countw = 0; int countl = 0; String s; String[] str; BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); System.out.println(CThread.currentThread()); while ((s = br2.readLine()) != null) { str = s.split(search); count = str.length - 1; countw += count; //word count if (s.contains(search)) { countl++; //line count WriteFile(CThread,s, outfile.toString(), search); } } br2.close(); in.close(); } -------------------------------------------------------------------------------- public void WriteFile(Thread CThread,String line, String out, String search) throws IOException { BufferedWriter bufferedWriter = null; System.out.println("writre thread"+CThread.currentThread()); bufferedWriter = new BufferedWriter(new FileWriter(out, true)); bufferedWriter.write(line); bufferedWriter.newLine(); bufferedWriter.flush(); } Please help me. Its really taking 40 mins for 10 files using threads and 15 - 20 mins for a single file of 70MB after being compressed. Any ways to minimise the time.

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  • Logging to a file on Android

    - by Greg B
    Is there any way of retrieving log messages from an Android handset. I'm building an application which uses the GPS of my HTC Hero. I can run and debug the application from eclipse but this isn't a good use case of GPS, sat at my desk. When I fire the app up when I am walking around, I get an intermittent exception. Is there anyway I can output these exceptions to a text file on the SD card or output calls to Log.x("") to a text file so that I can see what the exception is. Thanks EDIT : Solution Here is the code I finally went with... Thread.currentThread().setUncaughtExceptionHandler(new Thread.UncaughtExceptionHandler() { @Override public void uncaughtException(Thread thread, Throwable ex) { PrintWriter pw; try { pw = new PrintWriter( new FileWriter(Environment.getExternalStorageDirectory()+"/rt.log", true)); ex.printStackTrace(pw); pw.flush(); pw.close(); } catch (IOException e) { e.printStackTrace(); } } }); I had to wrap the line pw = new PrintWriter(new FileWriter(Environment.getExternalStorageDirectory()+"/rt.log", true)); in a try/catch as Eclipse would not let me compile the app. It kept saying Unhandled exception type IOException 1 quick fix Sorround with try/catch So I did and it all works which is fine by me but it does make me wonder what Eclipse was on about...

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  • JSF, writeAttribute("value", str, null) fails with strings obtained through ValueExpression.getValue

    - by Roma
    Hello, I'm having a somewhat weird problem with custom JSF component. Here's my renderer code: public class Test extends Renderer { public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); System.out.println("Value: " + val); writer.writeAttribute("value", val, null); } writer.endElement("textarea"); writer.flush(); } } The code generates: <textarea name="j_id2:j_id12:j_id19" value=""></textarea> Property binding contains "test" and as it should be, "Value: test" is successfully printed to console. Now, if I change the code to: public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); String str = "new string"; System.out.println("Value1: " + val + ", Value2: " + str); writer.writeAttribute("value", str, null); } writer.endElement("textarea"); writer.flush(); } generated html is: <textarea name="j_id2:j_id12:j_id19" value="new string"></textarea> and console output is "Value1: test, Value2: new string" What's going on here? This doesn't make sense. Why would writeAttribute differentiate between the two strings? Additional info: The component extends UIComponentBase I am using it with facelets

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  • Display HttpResponse (string from Handler) in new WebView

    - by datguywhowanders
    I have the following code in a form's submit button onClickListener: String action, user, pwd, user_field, pwd_field; action = "theURL"; user_field = "id"; pwd_field = "pw"; user = "username"; pwd = "password!!"; List<NameValuePair> myList = new ArrayList<NameValuePair>(); myList.add(new BasicNameValuePair(user_field, user)); myList.add(new BasicNameValuePair(pwd_field, pwd)); HttpParams params = new BasicHttpParams(); HttpClient client = new DefaultHttpClient(params); HttpPost post = new HttpPost(action); HttpResponse end = null; String endResult = null; try { post.setEntity(new UrlEncodedFormEntity(myList)); } catch (UnsupportedEncodingException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { HttpResponse response = client.execute(post); end = response; } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } BasicResponseHandler myHandler = new BasicResponseHandler(); try { endResult = myHandler.handleResponse(end); } catch (HttpResponseException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } How can I take the resulting string (endResult) and start a new activity using an intent that will open webview and load the html?

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  • Android - How can I upload a txt file to a website?

    - by Donal Rafferty
    I want to upload a txt file to a website, I'll admit I haven't looked into it in any great detail but I have looked at a few examples and would like more experienced opinions on whether I'm going in the right direction. Here is what I have so far: DefaultHttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); private String ret; HttpResponse response = null; HttpPost httpPost = null; public String postPage(String url, String data, boolean returnAddr) { ret = null; httpClient.getParams().setParameter(ClientPNames.COOKIE_POLICY, CookiePolicy.RFC_2109); httpPost = new HttpPost(url); response = null; StringEntity tmp = null; try { tmp = new StringEntity(data,"UTF-8"); } catch (UnsupportedEncodingException e) { System.out.println("HTTPHelp : UnsupportedEncodingException : "+e); } httpPost.setEntity(tmp); try { response = httpClient.execute(httpPost,localContext); } catch (ClientProtocolException e) { System.out.println("HTTPHelp : ClientProtocolException : "+e); } catch (IOException e) { System.out.println("HTTPHelp : IOException : "+e); } ret = response.getStatusLine().toString(); return ret; } And I call it as follows: postPage("http://www.testwebsite.com", "data/data/com.testxmlpost.xml/files/logging.txt", true)); I want to be able to upload a file from the device to a website. But when trying this way I get the following response back. HTTP/1.1 405 Method Not Allowed Am I trying the correct way or should I be doing it another way?

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  • How can i fetch the large image from url

    - by Kutbi
    i used below code to fetch the image from url.but its not working for large image.. i missing something to add for that type of image to fetch. imgView = (ImageView)findViewById(R.id.ImageView01); imgView.setImageBitmap(loadBitmap("http://www.360technosoft.com/mx4.jpg")); //imgView.setImageBitmap(loadBitmap("http://sugardaddydiaries.com/wp-content/uploads/2010/12/how_do_i_get_sugar_daddy.jpg")); //setImageDrawable("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg"); //Drawable drawable = LoadImageFromWebOperations("http://www.androidpeople.com/wp-content/uploads/2010/03/android.png"); //imgView.setImageDrawable(drawable); /* try { ImageView i = (ImageView)findViewById(R.id.ImageView01); Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg").getContent()); i.setImageBitmap(bitmap); } catch (MalformedURLException e) { System.out.println("hello"); } catch (IOException e) { System.out.println("hello"); }*/ } protected Drawable ImageOperations(Context context, String string, String string2) { // TODO Auto-generated method stub try { InputStream is = (InputStream) this.fetch(string); Drawable d = Drawable.createFromStream(is, "src"); return d; } catch (MalformedURLException e) { e.printStackTrace(); return null; } catch (IOException e) { e.printStackTrace(); return null; } }

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  • java : how to handle the design when template methods throw exception when overrided method not throw

    - by jiafu
    when coding. try to solve the puzzle: how to design the class/methods when InputStreamDigestComputor throw IOException? It seems we can't use this degisn structure due to the template method throw exception but overrided method not throw it. but if change the overrided method to throw it, will cause other subclass both throw it. So can any good suggestion for this case? abstract class DigestComputor{ String compute(DigestAlgorithm algorithm){ MessageDigest instance; try { instance = MessageDigest.getInstance(algorithm.toString()); updateMessageDigest(instance); return hex(instance.digest()); } catch (NoSuchAlgorithmException e) { LOG.error(e.getMessage(), e); throw new UnsupportedOperationException(e.getMessage(), e); } } abstract void updateMessageDigest(MessageDigest instance); } class ByteBufferDigestComputor extends DigestComputor{ private final ByteBuffer byteBuffer; public ByteBufferDigestComputor(ByteBuffer byteBuffer) { super(); this.byteBuffer = byteBuffer; } @Override void updateMessageDigest(MessageDigest instance) { instance.update(byteBuffer); } } class InputStreamDigestComputor extends DigestComputor{ // this place has error. due to exception. if I change the overrided method to throw it. evey caller will handle the exception. but @Override void updateMessageDigest(MessageDigest instance) { throw new IOException(); } }

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  • How to setPage() a JEditorPane with a localfile which is outside of the .jar file?

    - by Jaguar
    My program has the following path in the .jar file src/test/Program.class and my program is as follow... Program.java package test; import java.io.File; import java.io.IOException; import javax.swing.JEditorPane; import javax.swing.JFrame; public class Program { JEditorPane editorPane; public Program() { File file = new File("temp.htm"); try { file.createNewFile(); editorPane = new JEditorPane(); editorPane.setPage(Program.class.getResource("temp.htm")); } catch (IOException e) { e.printStackTrace(); } } public JEditorPane getEditorPane(){ return editorPane; } public static void main(String[] args) { JFrame frame = new JFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(400, 400); frame.setVisible(true); Program p = new Program(); frame.getContentPane().add(p.getEditorPane()); } } The problem is that I have compiled the program in a .jar file. The file.createNewFile(); creates the temp.htm file outside the .jar file So when editorPane.setPage(Program.class.getResource("temp.htm")); is called the file is not found as it searches for file inside the test package. How to setPage() the temp.htm file whiich is outside the .jar file but in the same folder as the .jar file? As the temp.htm is a localfile and I want a relative path instead of an absolute path. Thanks.

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  • Different results between Android Geocoder and Google Geocoding web service

    - by user3571822
    I am creating an Android application and I need to use the geolocation. I have started by using the Geocoder API from Android (android.location.geocoder) but it causes some issues (timed out waiting for response from server) which seem to be common according to what I have read. To make my application work when this kind of error occurs, I use the Geocoding web service. Now, the application works every time. The problem is that the results returned by the geocoder from API and the geocoder from the web service are not the same. For example the web service returns only 3 addresses with only city name and country whereas the geocoding from the API returns about 8 addresses with the feature name, the thoroughfare, the locality... The question is: is there a way to make the results from the web service exactly the same than the ones from the API? EDIT Here is my MainGeocoder class: public class MainGeocoder { private Geocoder geocoderAPI; private GeocoderRest geocoderRest; public MainGeocoder(Context context) { geocoderAPI = new Geocoder(context); geocoderRest = new GeocoderRest(context); } public List<Address> getFromLocationName(String search, int maxResults) { List<Address> addresses; try { addresses = geocoderAPI.getFromLocationName(search, maxResults); return addresses; } catch (IOException e) { e.printStackTrace(); try { addresses = geocoderRest.getFromLocationName(search, maxResults); return addresses; } catch (IOException e1) { return null; } catch (LimitExceededException e1) { return null; } } } } It basically tries to get the list of addresses from the API Geocoder. If an IO exception is thrown it gets this list from the web service by using the GeocoderRest class which has been pasted from here: http://stackoverflow.com/a/15117087/3571822

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  • Static Logger in seperate thread?

    - by SirLenz0rlot
    Hi all, I've made my Logger, that logs a string, a static class with a static so I can call it from my entire project without having to make an instance of it. quite nice, but I want to make it run in a seperate thread, since accessing the file costs time is that possible somehow and what's the best way to do it? Its a bit of a short discription, but I hope the idea is clear. if not, please let me know. Thanks in advance! btw: any other improvements on my code are welcome as well, i have the feeling not everthing is as efficient as it can be: internal static class MainLogger { internal static void LogStringToFile(string logText) { DateTime timestamp = DateTime.Now; string str = timestamp.ToString("dd-MM-yy HH:mm:ss ", CultureInfo.InvariantCulture) + "\t" + logText + "\n"; const string filename = Constants.LOG_FILENAME; FileInfo fileInfo = new FileInfo(filename); if (fileInfo.Exists) { if (fileInfo.Length > Constants.LOG_FILESIZE) { File.Create(filename).Dispose(); } } else { File.Create(filename).Dispose(); } int i = 0; while(true) { try { using (StreamWriter writer = File.AppendText(filename)) { writer.WriteLine(str); } break; } catch (IOException) { Thread.Sleep(10); i++; if (i >= 8) { throw new IOException("Log file \"" + Constants.LOG_FILENAME + "\" not accessible after 5 tries"); } } } } } enter code here

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  • Line End Problem Reading with Scanner Class in Java

    - by dikbas
    I am not an experienced Java programmer and i'm trying to write some text to a file and then read it with Scanner. I know there are lots of ways of doing this, but i want to write records to file with delimiters, then read the pieces. The problem is so small. When I look the output some printing isn't seen(shown in below). I mean the bold line in the Output that is only written "Scanner". I would be appreciated if anyone can answer why "String: " isn't seen there. (Please answer just what i ask) I couldn't understand if it is a simple printing problem or a line end problem with "\r\n". Here is the code and output: import java.io.FileReader; import java.io.FileWriter; import java.io.IOException; import java.util.Scanner; public class Tmp { public static void main(String args[]) throws IOException { int i; boolean b; String str; FileWriter fout = new FileWriter("test.txt"); fout.write("Testing|10|true|two|false\r\n"); fout.write("Scanner|12|one|true|"); fout.close(); FileReader fin = new FileReader("Test.txt"); Scanner src = new Scanner(fin).useDelimiter("[|\\*]"); while (src.hasNext()) { if (src.hasNextInt()) { i = src.nextInt(); System.out.println("int: " + i); } else if (src.hasNextBoolean()) { b = src.nextBoolean(); System.out.println("boolean: " + b); } else { str = src.next(); System.out.println("String: " + str); } } fin.close(); } } Here is the output: String: Testing int: 10 boolean: true String: two String: false Scanner int: 12 String: one boolean: true

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  • Parsing URL error

    - by user577875
    It didn't seem like there was a post about this, so here goes. I've been working on a simple app to grab my time table from my school, and get it on my phone. Currently I'm working on the port on android but I've hit an issue. I get the error: java.io.IOException: -1 error loading URL urladress. Code: public void updateTimeTable(){ //Get UID and Birthday SharedPreferences prefs = PreferenceManager.getDefaultSharedPreferences(getBaseContext()); String uid = prefs.getString("uid", "000000"); String fods = prefs.getString("fodsdag", "000000"); //Set URL String url = "http://unv1.aalborg-stu.dk/cgi-bin/elevskema.pl?ugen=0&unavn=" + uid + "&fodsdag=" + fods; try { Document doc = Jsoup.connect(url).get(); Elements td = doc.getElementsByTag("td"); //ArrayList<String> tdArray = new ArrayList<String>(); // for (Element tds : td) { // String tdText = tds.text(); // tdArray.add(tdText); //} //String[] data = tdArray.toArray(new String[tdArray.size()]); } catch (IOException e ){ Log.e("Parser", "shite", e); } Context context = getApplicationContext(); CharSequence text = url; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } I've commented some lines out to identify where the issue is, and it seems it's at the actual parsing. Anywho, screenshot of the error I get: Screenshot I got about 4 days worth of Java experience so forgive me if it's something silly. Best Regards

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  • How to build a control programatically?

    - by W_K
    I have custom control written in Java. For the sake of simplicity lets assume that it looks like this: public class HelloworldControl extends UIComponentBase { @Override public void decode(FacesContext context) { String cid = this.getClientId(context); ... super.decode(context); } @Override public void encodeBegin(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.writeText("Hello world!", this); // I want a view!! } @Override public void encodeEnd(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); ... } public void restoreState(FacesContext context, Object state) { Object values[] = (Object[]) state; ... super.restoreState(context, values[0]); } public Object saveState(FacesContext context) { Object values[] = ... } } I would like to add programatically child control to it. For example I would like a child view control to render a view just under the Hellow world text. How can i do this? What is the standard procedure to build dynamically a control? To put it simply - I want programatically build a hierarchy of standard components and I want to attach it to my control.

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  • Unreleased Resource: Streams

    - by Vibhas
    Hi freinds i am getting a warning in the fortify report for the following code: if (null != serverSocket) { OutputStream socketOutPutStream = serverSocket .getOutputStream(); if (null != socketOutPutStream) { oos = new ObjectOutputStream(socketOutPutStream); if (null != oos) { int c; log.info("i am in Step 3 ooss " + oos); while ((c = mergedIS.read()) != -1) { oos.writeByte(c); } } log.info("i am in Step 4 "); } } in the catch block i have mentioned : catch (UnknownHostException e) { //catch exception Vibhas added log.info("UnknownHostException occured"); } catch (IOException e) { //catch exception Vibhas added log.info("IOException occured"); } catch (Exception e) { //catch exception //log.info("error occured in copyFile in utils-->"+e.getMessage()+"file name is-->"+destiFileName); }finally{ if (null != oos){ oos.flush(); oos.close(); } catch (Exception e) { //catch exception } } Warning which i am getting in the fortify report is: Abstract: The function copyFile() in ODCUtil.java sometimes fails to release a system resource allocated by getOutputStream() on line 61. Sink: ODCUtil.java:64 oos = new ObjectOutputStream(socketOutPutStream)() 62 if (null != socketOutPutStream) { 63 64 oos = new ObjectOutputStream(socketOutPutStream); 65 if (null != oos) { 66 int c;

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  • Creating android app Database with big amount of data

    - by Thomas
    Hi all, The database of my application need to be filled with a lot of data, so during onCreate(), it's not only some create table sql instructions, there is a lot of inserts. The solution I chose is to store all this instructions in a sql file located in res/raw and which is loaded with Resources.openRawResource(id). It works well but I face to encoding issue, I have some accentuated caharacters in the sql file which appears bad in my application. This my code to do this : public String getFileContent(Resources resources, int rawId) throws IOException { InputStream is = resources.openRawResource(rawId); int size = is.available(); // Read the entire asset into a local byte buffer. byte[] buffer = new byte[size]; is.read(buffer); is.close(); // Convert the buffer into a string. return new String(buffer); } public void onCreate(SQLiteDatabase db) { try { // get file content String sqlCode = getFileContent(mCtx.getResources(), R.raw.db_create); // execute code for (String sqlStatements : sqlCode.split(";")) { db.execSQL(sqlStatements); } Log.v("Creating database done."); } catch (IOException e) { // Should never happen! Log.e("Error reading sql file " + e.getMessage(), e); throw new RuntimeException(e); } catch (SQLException e) { Log.e("Error executing sql code " + e.getMessage(), e); throw new RuntimeException(e); } The solution I found to avoid this is to load the sql instructions from a huge static final string instead of a file, and all accentutated characters appears well. But Isn't there a more elegant way to load sql instructions than a big static final String attribute with all sql instructions ? Thanks in advance Thomas

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  • String doesn't match regex when read from keyboard.

    - by athspk
    public static void main(String[] args) throws IOException { String str1 = "??123456"; System.out.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")); //??123456-true BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String str2 = br.readLine(); //??123456 same as str1. System.out.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")); //?”??123456-false System.out.println(str1.equals(str2)); //false } The same String doesn't match regex when read from keyboard. What causes this problem, and how can we solve this? Thanks in advance. EDIT: I used System.console() for input and output. public static void main(String[] args) throws IOException { PrintWriter pr = System.console().writer(); String str1 = "??123456"; pr.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str1.length()); String str2 = System.console().readLine(); pr.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str2.length()); pr.println("str1.equals(str2)="+str1.equals(str2)); } Output: ??123456-true-8 ??123456 ??123456-true-8 str1.equals(str2)=true

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  • Servlet that starts a thread only once for every visitor

    - by user858749
    Hey I want to implement a Java Servlet that starts a thread only once for every single user. Even on refresh it should not start again. My last approach brought me some trouble so no code^^. Any Suggestions for the layout of the servlet? public class LoaderServlet extends HttpServlet { // The thread to load the needed information private LoaderThread loader; // The last.fm account private String lfmaccount; public LoaderServlet() { super(); lfmaccount = ""; } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (loader != null) { response.setContentType("text/plain"); response.setHeader("Cache-Control", "no-cache"); PrintWriter out = response.getWriter(); out.write(loader.getStatus()); out.flush(); out.close(); } else { loader = new LoaderThread(lfmaccount); loader.start(); request.getRequestDispatcher("WEB-INF/pages/loader.jsp").forward( request, response); } } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (lfmaccount.isEmpty()) { lfmaccount = request.getSession().getAttribute("lfmUser") .toString(); } request.getRequestDispatcher("WEB-INF/pages/loader.jsp").forward( request, response); } } The jsp uses ajax to regularly post to the servlet and get the status. The thread just runs like 3 minutes, crawling some last.fm data.

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  • Changing brightness in bufferedImage with DataBufferInt

    - by user2958025
    I must read some image and then I have to change brightness and contrast of this image I create main class and constructor where are panels, sliders and other stuff, I added changeListener to slider to take current value. My imagePanel is new Object of that class: public class Obrazek extends JPanel{ public static BufferedImage img = null; public Obrazek() { super(); try { img = ImageIO.read(new File("D:\\ja.jpg")); } catch (IOException e) {} } @Override public void paint(Graphics g) { g.drawImage(img, 0, 0, null); } } This is my load button private void przyciskWczytaj(java.awt.event.ActionEvent evt) { int odpowiedz = jFileChooser1.showOpenDialog(this); if (odpowiedz == jFileChooser1.APPROVE_OPTION) { File file = jFileChooser1.getSelectedFile(); try { BufferedImage im = ImageIO.read(new File(file.getAbsolutePath())); Obrazek.img = im; } catch (IOException ex) { System.out.println("Error"); } } } And now I want to create class where I will change that brightness. I have to use but I don't know how to use that thing: BufferedImage(256, 256, Bufferedmage.TYPE_INT_RGB) and to get each pixel of image I need to do something like: int rgb []=((DataBufferInt)img.getRaster().getDataBuffer()).getData(); And here I is next problem: How can I change the value of each r,g,b and show that new image on my panel

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  • Why do you have to call URLConnection#getInputStream to be able to write out to URLConnection#getOutputStream?

    - by John
    I'm trying to write out to URLConnection#getOutputStream, however, no data is actually sent until I call URLConnection#getInputStream. Even if I set URLConnnection#doInput to false, it still will not send. Does anyone know why this is? There's nothing in the API documentation that describes this. Java API Documentation on URLConnection: http://download.oracle.com/javase/6/docs/api/java/net/URLConnection.html Java's Tutorial on Reading from and Writing to a URLConnection: http://download.oracle.com/javase/tutorial/networking/urls/readingWriting.html import java.io.IOException; import java.io.OutputStreamWriter; import java.net.URL; import java.net.URLConnection; public class UrlConnectionTest { private static final String TEST_URL = "http://localhost:3000/test/hitme"; public static void main(String[] args) throws IOException { URLConnection urlCon = null; URL url = null; OutputStreamWriter osw = null; try { url = new URL(TEST_URL); urlCon = url.openConnection(); urlCon.setDoOutput(true); urlCon.setRequestProperty("Content-Type", "text/plain"); //////////////////////////////////////// // SETTING THIS TO FALSE DOES NOTHING // //////////////////////////////////////// // urlCon.setDoInput(false); osw = new OutputStreamWriter(urlCon.getOutputStream()); osw.write("HELLO WORLD"); osw.flush(); ///////////////////////////////////////////////// // MUST CALL THIS OTHERWISE WILL NOT WRITE OUT // ///////////////////////////////////////////////// urlCon.getInputStream(); ///////////////////////////////////////////////////////////////////////////////////////////////////////// // If getInputStream is called while doInput=false, the following exception is thrown: // // java.net.ProtocolException: Cannot read from URLConnection if doInput=false (call setDoInput(true)) // ///////////////////////////////////////////////////////////////////////////////////////////////////////// } catch (Exception e) { e.printStackTrace(); } finally { if (osw != null) { osw.close(); } } } }

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  • Get Object from memory using memory adresse

    - by Hamza Karmouda
    I want to know how to get an Object from memory, in my case a MediaRecorder. Here's my class: Mymic class: public class MyMic { MediaRecorder recorder2; File file; private Context c; public MyMic(Context context){ this.c=context; } private void stopRecord() throws IOException { recorder2.stop(); recorder2.reset(); recorder2.release(); } private void startRecord() { recorder2= new MediaRecorder(); recorder2.setAudioSource(MediaRecorder.AudioSource.MIC); recorder2.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP); recorder2.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB); recorder2.setOutputFile(file.getPath()); try { recorder2.prepare(); recorder2.start(); } catch (IllegalStateException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } } my Receiver Class: public class MyReceiver extends BroadcastReceiver { private Context c; private MyMic myMic; @Override public void onReceive(Context context, Intent intent) { this.c=context; myMic = new MyMic(c); if(my condition = true){ myMic.startRecord(); }else myMic.stopRecord(); } } So when I'm calling startRecord() it create a new MediaRecorder but when i instantiate my class a second time i can't retrieve my Object. Can i retrieve my MediaRecorder with his addresse

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  • Trouble accessing fields of a serialized object in Java

    - by typoknig
    I have instantized a class that implements Serializable and I am trying to stream that object like this: try{ Socket socket = new Socket("localhost", 8000); ObjectOutputStream toServer = new ObjectOutputStream(socket.getOutputStream()); toServer.writeObject(myObject); } catch (IOException ex) { System.err.println(ex); } All good so far right? Then I am trying to read the fields of that object like this: //This is an inner class class HandleClient implements Runnable{ private ObjectInputStream fromClient; private Socket socket; // This socket was established earlier try { fromClient = new ObjectInputStream(socket.getInputStream()); GetField inputObjectFields = fromClient.readFields(); double myFristVariable = inputObjectFields.get("myFirstVariable", 0); int mySecondVariable = inputObjectFields.get("mySecondVariable", 0); //do stuff } catch (IOException ex) { System.err.println(ex); } catch (ClassNotFoundException ex) { System.err.println(ex); } finally { try { fromClient.close(); } catch (Exception ex) { ex.printStackTrace(); } } } But I always get the error: java.io.NotActiveException: not in call to readObject This is my first time streaming objects instead of primitive data types, what am I doing wrong? BONUS When I do get this working correctly, is the ENTIRE CLASS passed with the serialized object (i.e. will I have access to the methods of the object's class)? My reading suggests that the entire class is passed with the object, but I have been unable to use the objects methods thus far. How exactly do I call on the object's methods? In addition to my code above I also experimented with the readObject method, but I was probably using it wrong too because I couldn't get it to work. Please enlighten me.

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  • When Creating a Reference for an Object Where from where that class is Loaded?

    - by asela38
    When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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  • uploading database file in assets not returning a record

    - by Alexander
    I have a problem with a database file not being read I have added the database file in assets called mydb but when i run my code it says its not being located. It is calling this toast Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); This is being called because no records are being returned. This is an example form Android Application Development book. public class DatabaseActivity extends Activity { /** Called when the activity is first created. */ TextView quest, response1, response2; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); TextView quest = (TextView) findViewById(R.id.quest); try { String destPath = "/data/data/" + getPackageName() + "/databases/MyDB"; File f = new File(destPath); if (!f.exists()) { CopyDB( getBaseContext().getAssets().open("mydb"), new FileOutputStream(destPath)); } } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } DBAdapter db = new DBAdapter(this); //---get a contact--- db.open(); Cursor c = db.getContact(2); if (c.moveToFirst()) DisplayContact(c); else Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); db.close(); } public void CopyDB(InputStream inputStream, OutputStream outputStream) throws IOException { //---copy 1K bytes at a time--- byte[] buffer = new byte[1024]; int length; while ((length = inputStream.read(buffer)) > 0) { outputStream.write(buffer, 0, length); } inputStream.close(); outputStream.close(); } public void DisplayContact(Cursor c) { quest.setText(String.valueOf(c.getString(1))); //quest.setText(String.valueOf("this is a text string")); } }

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  • Getting information from servlet created html

    - by user541597
    I have a servlet that creates an html text box and then redirects to another servlet on submit. How can I access the value of the html text box from the new servlet? I am able to access servlet variables from the new servlet but I am not aware of how to access the value of the html generated code. thanks, Here is the servlet that gets the text input public class ServletB extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); String value = System.getProperty("card"); PrintWriter out = response.getWriter(); out.println("<center><h1>Your preffered method of payment is "+value+"</h1><br />"); out.println("Please Enter Card Number<input type =\"text\" name = \"number\"/><form action=\"http://codd.cs.gsu.edu:9999/cpereyra183/servlet/ServletC\"><input type =\"submit\" value=\"Continue\" /><input type=\"button\" value=\"Cancel\" /></center>"); } }} This is the servlet the first servlet redirects to all I do is try to do is output the text input public class ServletC extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); String value = System.getProperty("card"); PrintWriter out = response.getWriter(); out.println(request.getParameter("number")); } }

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  • What is wrong with this Asynchronus task?

    - by bluebrain
    the method onPostExecute simply was not executed, I have seen 16 at LogCat but I can not see 16 in LogCAT. I tried to debug it, it seemed that it goes to the first line of the class (package line) after return statement. private class Client extends AsyncTask<Integer, Void, Integer> { protected Integer doInBackground(Integer... params) { Log.e(TAG,10+""); try { socket = new Socket(target, port); Log.e(TAG,11+""); oos = new ObjectOutputStream(socket.getOutputStream()); Log.e(TAG,14+""); ois = new ObjectInputStream(socket.getInputStream()); Log.e(TAG,15+""); } catch (UnknownHostException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } Log.e(TAG,16+""); return 1; } protected void onPostExecute(Integer result) { Log.e(TAG,13+""); try { Log.e(TAG,12+""); oos.writeUTF(key); Log.e(TAG,13+""); if (ois.readInt() == OKAY) { isConnected = true; Log.e(TAG,14+""); }else{ Log.e(TAG,15+""); isConnected = false; } } catch (IOException e) { e.printStackTrace(); isClosed = true; } } }

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