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  • Deleting first item of a $_COOKIE array

    - by Mike Burke
    if I add an item to the $_COOKIE array as such: setcookie("favorites[]", "value", time()+3600); I can delete any item from the $_COOKIE[favorites] array like this: setcookie("favorites[$deletekey]", "", time()+3600); EXCEPT the first one added so this does not work: setcookie("favorites[0]", "", time()+3600*24); How can I delete the first one and leave others intact?

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  • WPF ItemsControl binding and the item order

    - by user109534
    I have ItemsControl in a WPF application, which is bind to an array of objects. And I am using ItemTemplate to render the list. I want to display for each item in the list the item order, like for example Customer 1 Name : xxxxx Age: 9999 Customer 2 Name : yyyy Age: 8888 Any idea how to do it Thanks

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  • Troubles with list "dropdowns" and which list item gets the dropdown

    - by Andrew
    I'm working on a project for an MMO "guild" that gives members of the guild randomly generated tasks for the game. They can "block" three tasks from being assigned. The lists will look something like this: <ul> <li class="blocked">Task that is blocked</li> <li class="blocked-open">Click to block a task</li> <li class="blocked-open">Click to block a task</li> </ul> The blocked-open class means they haven't chosen a task to block yet. The blocked task means they've already blocked a task. When they click the list item, I want this to appear: <ul class="tasks-dropdown no-display"> <li><h1>Click a Task to Block</h1></li> <ul class="task-dropdown-inner"> <?php //output all tasks foreach($tasks as $task) { echo '<li class="blocked-option"><span id="'.$task.'">'.$task.'</span></li>'; } ?> <br class="clear" /> </ul> </ul> I don't quite know how, when the user clicks the .blocked-open line-item, to show that dropdown under only the one they clicked. My jQuery looked like this before I became confused. $("li.blocked-open").click(function() { $("ul.no-display").slideToggle("900"); }); $(".blocked-option span").click(function() { var task = $(this).attr('id'); alert("You have blocked: " + task); location.reload(true); }); I tested it by putting the dropdown under a line item in the code, and it worked fine, but when I have more than one dropdown in the code, clicking on one line item toggles all the dropdowns. I'm not sure what to do. :-p.

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  • How to keep an item selected? - ListView

    - by Dodi300
    Hello. I would like to keep an item selected, on a ListView, when the user clicks on a space which has no item. For example, the space below the items, but still on the ListView component. I've change the ListView property "HideSelection" to false, but that only works when the focus is changed to another component; not when the user clicks on the ListView itself. Thanks!

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  • Set item.selected in ASP.NET Menu Control

    - by BillB
    ASP.NET newbie here. When on a page I'd like to set the corresponding menu item to selected. My approach is this: On Home.aspx.cs: Menu menu = (Menu)Master.FindControl("Menu1"); if (menu.Items.Count > 0) { menu.FindItem("Home").Selected = true; } Trouble is, menu.item.count == 0. My menu is bound to a sitemap, if that matters. Thanks, Bill

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  • In App Billing: Item not found

    - by hunterp
    I have followed the steps for in app billing: Installed demo app Published an in-app product NOT published the app itself Although I CAN buy the item, there is a curious warning "item not found" that I have to dismiss before I can go to the buy screen. AND this log error: E/Volley(1384): [157] BasicNetwork.performRequest: Unexpected response code 500 for https://android.clients.google.com/fdfe/details?doc=subs:com.testorooney.testo:sword_001

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  • Check item in CheckedListBox without selecting

    - by Dmi
    How can I allow the user to click to check an item in CheckedListBox in one click? The default behaviour is the first click selects the item, the second click allows you to toggle the check. I don't want to toggle the check on select either, I'm looking for the behavior of the ListView control where I can click directly on check boxes to toggle them without selecting their items first.

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  • SharePoint Add New Item Button on Home Page

    - by ifunky
    I'm building a bulletin board site (in 2010) and I'm sure this must be simple but again it doesn't seem so. Anyway on my default page I have a query webpart showing the latest items and what I need is just a button at the top of the page "Add new item" which would show the popup and allow users to complete the form just like it works on the display list items form. I've looked at AllItems.aspx but can't even see the "Add new item" button to copy! Any ideas? Thanks Dan

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  • To Make an item wiggle and delete

    - by gbf.sara
    I need to delete/remove an item in my Iphone application. For that i should make tat item wiggle(shake) when i give long press. And then it should ask for an alert to delete or not??? Can anyone guide me plz??? It ll be more helpful if u help me with a source code Tanx in advance

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  • Problem with Copy-Item -force

    - by andemt
    Hi, This is part of my image-copy-script: Get-Childitem | where {$.Extension -eq ".png" -or $.Extension -eq ".gif" -or $_.Extension -eq ".jpg"} | Copy-Item -destination $dest -force It works fine, and it can overwrite files. Well, it can overwrite if the existing file have attribute R or A. Not when its blanked. Error in red text: "Copy-Item : The file '\server\d$\path\thumbs\007487l.jpg' already exists." Why?

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  • WPF ListView Show selected item

    - by Jeffrey
    hi, i want to show the selected item in a list view automatically(it isn't possible to show all items without scrolling). this.listView.SelectedIndex = 999; selects of course an item, but it doesn't show it. what can i use to show it automatically ? kind regards, jeff

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  • Python: concatenate generator and item

    - by TarGz
    I have a generator (numbers) and a value (number). I would like to iterate over these as if they were one sequence: i for i in tuple(my_generator) + (my_value,) The problem is, as far as I undestand, this creates 3 tuples only to immediately discard them and also copies items in "my_generator" once. Better approch would be: def con(seq, item): for i in seq: yield seq yield item i for i in con(my_generator, my_value) But I was wondering whether it is possible to do it without that function definition

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