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  • What causes "All-in-one USB Card Reader" to create 6 drives that always appear in Disk Management?

    - by tim11g
    I installed a "All-in-one USB Card Reader" to read SD cards and other media. It has caused six new drives to appear in Disk Management with six new drive letter assignments. These drives and letters are always present, even when there are no cards in the reader. When unused, they are labeled "No Media". Why does this multifunction reader cause these phantom Disks to appear and consume drive letters? Every USB port can (and does) allow removable media to be mounted and assigned a drive letter, and the drive letter assignment "disappears" when the USB drive is removed. Why are these card reader's drives and letters staying allocated permanently? Is there anything that can be done to make the slots work like a typical USB drive? (The reader is in fact connected to USB).

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  • hide taskbar labels completely. no letters no words in the open windows. like windows 7, icons only

    - by Dom
    i posted this question in an answer box, so once person had to tell me to make it a separate question. http://superuser.com/questions/30007/hide-taskbar-labels-without-combining My Question: it shows 1 letter. i just want plain icons. like that of windows 7. no words/letter. only icons. how do u get rid of the letter? btw im using xp, i just want no words no letters on the taskbar. is it possible? answers appreciated(except bashful...)!

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  • Code Golf: Word Search Solver

    - by Maxim Z.
    Note: This is my first Code Golf challenge/question, so I might not be using the correct format below. I'm not really sure how to tag this particular question, and should this be community wiki? Thanks! This Code Golf challenge is about solving word searches! A word search, as defined by Wikipedia, is: A word search, word find, word seek, word sleuth or mystery word puzzle is a word game that is letters of a word in a grid, that usually has a rectangular or square shape. The objective of this puzzle is to find and mark all the words hidden inside the box. The words may be horizontally, vertically or diagonally. Often a list of the hidden words is provided, but more challenging puzzles may let the player figure them out. Many word search puzzles have a theme to which all the hidden words are related. The word searches for this challenge will all be rectangular grids with a list of words to find provided. The words can be written vertically, horizontally, or diagonally. Input/Output The user inputs their word search and then inputs a word to be found in their grid. These two inputs are passed to the function that you will be writing. It is up to you how you want to declare and handle these objects. Using a strategy described below or one of your own, the function finds the specific word in the search and outputs its starting coordinates (simply row number and column number) and ending coordinates. If you find two occurrences of the word, you must output both's set of coordinates. Example Input: A I Y R J J Y T A S V Q T Z E X B X G R Z P W V T B K U F O E A F L V F J J I A G B A J K R E S U R E P U S C Y R S Y K F B B Q Y T K O I K H E W G N G L W Z F R F H L O R W A R E J A O S F U E H Q V L O A Z B J F B G I F Q X E E A L W A C F W K Z E U U R Z R T N P L D F L M P H D F W H F E C G W Z B J S V O A O Y D L M S T C R B E S J U V T C S O O X P F F R J T L C V W R N W L Q U F I B L T O O S Q V K R O W G N D B C D E J Y E L W X J D F X M Word to find: codegolf Output: row 12, column 8 --> row 5, column 1 Strategies Here are a few strategies you might consider using. It is completely up to you to decide what strategy you want to use; it doesn't have to be in this list. Looking for the first letter of the word; on each occurrence, looking at the eight surrounding letters to see whether the next letter of the word is there. Same as above, except looking for a part of a word that has two of the same letter side-by-side. Counting how often each letter of the alphabet is present in the whole grid, then selecting one of the least-occurring letters from the word you have to find and searching for the letter. On each occurrence of the letter, you look at its eight surrounding letters to see whether the next and previous letters of the word is there.

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  • How can I make three partials into just one in rails where the :collection is the same?

    - by Angela
    I have three partials that I'd like to consolidate into one. They share the same collection, but each gets passed its own :local variable. Those variables are used for specific Models, so as a result, I have three different calls to the partial and three different partials. Here's the repetitive code: <% for email in campaign.emails %> <h4><%= link_to email.title, email %> <%= email.days %> days</h4> <% @contacts= campaign.contacts.find(:all, :order => "date_entered ASC" )%> <!--contacts collection--> <!-- render the information for each contact --> <%= render :partial => "contact_email", :collection => @contacts, :locals => {:email => email} %> <% end %> Calls in this Campaign: <% for call in campaign.calls %> <h4><%= link_to call.title, call %> <%= call.days %> days</h4> <% @contacts= campaign.contacts.find(:all, :order => "date_entered ASC" )%> <!--contacts collection--> <!-- render the information for each contact --> <%= render :partial => "contact_call", :collection => @contacts, :locals => {:call => call} %> <% end %> Letters in this Campaign: <% for letter in campaign.letters %> <h4><%= link_to letter.title, letter %> <%= letter.days %> days</h4> <% @contacts= campaign.contacts.find(:all, :order => "date_entered ASC" )%> <!--contacts collection--> <!-- render the information for each contact --> <%= render :partial => "contact_letter", :collection => @contacts, :locals => {:letter => letter} %> <% end %> An example of one of the partials is as follows: < div id="contact_email_partial"> <% if from_today(contact_email, email.days) < 0 %> <% if show_status(contact_email, email) == 'no status'%> <p> <%= full_name(contact_email) %> <% unless contact_email.statuses.empty?%> (<%= contact_email.statuses.find(:last).status%>) <% end %> is <%= from_today(contact_email,email.days).abs%> days overdue: <%= do_event(contact_email, email) %> <%= link_to_remote "Skip Email Remote", :url => skip_contact_email_url(contact_email,email), :update => "update-area-#{contact_email.id}-#{email.id}" %> <span id='update-area-<%="#{contact_email.id}-#{email.id}"%>'> </span> <% end %> <% end %> </div>

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  • How to make this CSS design of words in headings look clean and well desinged? [closed]

    - by kacalapy
    I am trying to get the lipstick on the pig and not wearing my UI developer hat often is making this impossible. Can someone give me nice alternatives to the code below. this is what i have now. <style> .FirstLetter:first-letter{font-family: arial; font-size: 14pt; font-weight: bold;color:White; background:Blue; border:1px black solid; padding-top:8px; padding-left:8px; padding-bottom:3px;} .Spaced{letter-spacing: 5px;font-family: arial; font-size: 14pt; font-weight: bold;} </style> <div class="FirstLetter Spaced headerFont"> Executive Summary </div> Here is the ugly result of the above code- i am lookign to make the header section look better ONLY that's where the first letter is blue:

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  • Why create a Huffman tree per character instead of a Node?

    - by Omega
    For a school assignment we're supposed to make a Java implementation of a compressor/decompresser using Huffman's algorithm. I've been reading a bit about it, specially this C++ tutorial: http://www.cprogramming.com/tutorial/computersciencetheory/huffman.html In my program, I've been thinking about having Nodes that have the following properties: Total Frequency Character (if a leaf) Right child (if any) Left child (if any) Parent (if any) So when building the Huffman tree, it is just a matter of linking a node to others, etc. However, I'm a bit confused with the following quote (emphasis mine): First, every letter starts off as part of its own tree and the trees are ordered by the frequency of the letters in the original string. Then the two least-frequently used letters are combined into a single tree, and the frequency of that tree is set to be the combined frequency of the two trees that it links together. My question: why should I create a tree per letter, instead of just a node per letter and then do the linking later? I have not begun coding, I'm just studying the algorithm first, so I guess I'm missing an important detail. What is it?

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  • How to Create Shortcuts to Programs on USB Drives

    - by Lori Kaufman
    If you work on multiple computers, you probably use a USB drive to take your favorite portable software with you. Portable application suites like PortableApps.com, CodySafe, or Lupo PenSuite, each have a main menu providing access to the programs installed into the suite. However, there may be reasons why you need to create shortcuts to programs on your USB drive. You may be using a program that does not integrate into the suite’s main menu. Or, you may not be using an official portable application suite at all, and just placing portable software in a folder on your USB drive. Maybe you prefer using shortcuts on the root of the USB drive, like a portable desktop. Whatever your reason, you can’t just create a shortcut to an application on the USB drive and place it in the root of the drive. The shortcut will always refer to the full path of the application, including the drive letter. Different computers assign different drive letters to USB flash drives, so you would have to change the drive letter for your shortcuts when it changes. You can assign a static drive letter to the USB drive. However, if you would rather not do that, there is a way to create shortcuts to programs on a USB drive using relative paths. Because Windows does not support relative paths in shortcuts, we will show you how to create a “shortcut” on the root of a USB drive by creating a batch (.bat) file and converting it to an executable (.exe) file. What’s the Difference Between Sleep and Hibernate in Windows? Screenshot Tour: XBMC 11 Eden Rocks Improved iOS Support, AirPlay, and Even a Custom XBMC OS How To Be Your Own Personal Clone Army (With a Little Photoshop)

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  • How important is the uniqueness of your domain name?

    - by Corey
    I've finally come up with a domain name that I like and is available. The name is nonsensical and doesn't translate into anything meaningful in any language, as far as I know. It's something like "FOOBARite". (Don't steal that!) I'm wondering about a few search issues. Results-wise, searching for it in Google currently returns about 15k results, none of which are relevant (dead Twitter pages, various unpopular online handles, and botched french translations). However, Google starts off with a spelling suggestion, which removes a letter. ("Did you mean: FOOBARit?") That returns about 250k results for several different and unrelated websites/organizations by that name. One is some technology provider, another is a sign-language organization, another is the name of a font... None of them seem particularly popular, there's not that much activity on any of those pages. Anyway, the two are pronounced differently, they're just a letter off. Should I go with my idea or is this one-letter variation going to cause me problems? If my site becomes ranked well enough, will Google's spelling suggestion go away? I don't want users to search for my site name and be told they've spelled it wrong.

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  • Why do I get garbage output when printing an int[]?

    - by Kat
    My program is suppose to count the occurrence of each character in a file ignoring upper and lower case. The method I wrote is: public int[] getCharTimes(File textFile) throws FileNotFoundException { Scanner inFile = new Scanner(textFile); int[] lower = new int[26]; char current; int other = 0; while(inFile.hasNext()){ String line = inFile.nextLine(); String line2 = line.toLowerCase(); for (int ch = 0; ch < line2.length(); ch++) { current = line2.charAt(ch); if(current >= 'a' && current <= 'z') lower[current-'a']++; else other++; } } return lower; } And is printed out using: for(int letter = 0; letter < 26; letter++) { System.out.print((char) (letter + 'a')); System.out.println(": " + ts.getCharTimes(file)); } Where ts is a TextStatistic object created earlier in my main method. However when I run my program, instead of printing out the number of how often the character occurs it prints: a: [I@f84386 b: [I@1194a4e c: [I@15d56d5 d: [I@efd552 e: [I@19dfbff f: [I@10b4b2f And I don't know what I'm doing wrong.

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  • powershell / runspace in a thread

    - by Vincent
    Hello ! I'm running the following code : RunspaceConfiguration config = RunspaceConfiguration.Create(); PSSnapInException warning; config.AddPSSnapIn("Microsoft.Exchange.Management.PowerShell.Admin", out warning); if (warning != null) throw warning; Runspace thisRunspace = RunspaceFactory.CreateRunspace(config); thisRunspace.Open(); string alias = usr.AD.CN.Replace(' ', '.'); string letter = usr.AD.CN.Substring(0, 1); string email = alias + "@" + (!usr.Mdph ? Constantes.AD_DOMAIN : Constantes.MDPH_DOMAIN) + "." + Constantes.AD_LANG; string db = "CN=IS-" + letter + ",CN=SG-" + letter + ",CN=InformationStore,CN=" + ((char)letter.ToCharArray()[0] < 'K' ? Constantes.EXC_SRVC : Constantes.EXC_SRVD) + Constantes.EXC_DBMEL; string cmd = "Enable-Mailbox -Identity \"" + usr.AD.CN + "\" -Alias " + alias + " -PrimarySmtpAddress " + email + " -DisplayName \"" + usr.AD.CN + "\" -Database \"" + db + "\""; Pipeline thisPipeline = thisRunspace.CreatePipeline(cmd); thisPipeline.Invoke(); The code is running in a thread created that way : t.WorkThread = new Thread(cu.CreerUser); t.WorkThread.Start(); If I run the code directly (not through a thread), it's working. When in a thread it throws the following exception : ObjectDisposedException "The safe handle has been closed." (Translated from french) I then replaced "Open" wirh "OpenAsync" which helped not getting the previous exception. But when on Invoke I get the following exception : InvalidRunspaceStateException "Unable to call the pipeline because its state of execution is not Opened. Its current state is Opening." (Also translated from french) I'm clueless... Any help welcome !!! Thanks !!!

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  • JAVA Regular Expression Errors

    - by Berkay
    I'm working on a simply password strength checker and i can not success applying regular expressions. In different resources different kinds of regular expressions are defined. i also find javascript regular expressions but had some problems to adapt. First, these are the regular expressions i need for JAVA: at least one lower case letter at least one upper case letter at least one number at least three numbers at least one special character at least two special characters both letters and numbers both upper and lower case letters, numbers, and special characters My goal is not being a regular expression expert i just want to use the parts i need.If you direct me good tutorials which discusses above for java, will be appreciated. Second, in this link some of them are mentioned but i'm getting problems to apply them. here does not catch the lower case letter (my pass: A5677a) if (passwd.matches("(?=.*[a-z])")) // [verified] at least one lower case letter {Score = Score+5;} Also here i'm getting error : illegal escape character. if (passwd.matches("(?=.*\d)")) // [verified] at least one number Finally, are these expressions all different in different kind of programming or script languages?

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  • Problem with logicalOR ( regex ) not greedy

    - by Marin Doric
    This is the part of a string "21xy5". I want to insert " * " surrounded with whitespace between: digit and letter, letter and digit, letter and letter. I use this regex pattern "\d[a-z]|[a-z]\d|[a-z][a-z]" to find indexs where I gona insert string " * ". Problem is that when regex OR(|) in string 21xy5 trays to match 21-x|x-y|y-5, when first condition 21-x success, second x-y is not checked, and third success. So I have 21 * xy * 5 instead 21 * x * y * 5. If input string is like this xy21, then x-y success and then I have x * y21. Problem is that logical OR is not greedy. Regex reg = new Regex(@"\d[a-z]|[a-z]\d|[a-z][a-z]" ); MatchCollection matchC; matchC = reg.Matches(input); int ii = 1; foreach (Match element in matchC) { input = input.Insert(element.Index + ii, " * "); ii += 3; } return input;

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  • Finding specific words in a file (Python language)

    - by Caroline Yi
    I have to write a program in python where the user is given a menu with four different "word games". There is a file called dictionary.txt and one of the games requires the user to input a) the number of letters in a word and b) a letter to exclude from the words being searched in the dictionary (dictionary.txt has the whole dictionary). Then the program prints the words that follow the user's requirements. My question is how on earth do I open the file and search for words with a certain length in that file. I only have a basic code which only asks the user for inputs. I'm am very new at this please help :( this is what I have up to the first option. The others are fine and I know how to break the loop but this specific one is really giving me trouble. I have tried everything and I just keep getting errors. Honestly, I only took this class because someone said it would be fun. It is, but recently I've really been falling behind and I have no idea what to do now. This is an intro level course so please be nice I've never done this before until now :( print print "Choose Which Game You Want to Play" print "a) Find words with only one vowel and excluding a specific letter." print "b) Find words containing all but one of a set of letters." print "c) Find words containing a specific character string." print "d) Find words containing state abbreviations." print "e) Find US state capitals that start with months." print "q) Quit." print choice = raw_input("Enter a choice: ") choice = choice.lower() print choice while choice != "q": if choice == "a": #wordlen = word length user is looking for.s wordlen = raw_input("Please enter the word length you are looking for: ") wordlen = int(wordlen) print wordlen #letterex = letter user wishes to exclude. letterex = raw_input("Please enter the letter you'd like to exclude: ") letterex = letterex.lower() print letterex

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  • Theory: "Lexical Encoding"

    - by _ande_turner_
    I am using the term "Lexical Encoding" for my lack of a better one. A Word is arguably the fundamental unit of communication as opposed to a Letter. Unicode tries to assign a numeric value to each Letter of all known Alphabets. What is a Letter to one language, is a Glyph to another. Unicode 5.1 assigns more than 100,000 values to these Glyphs currently. Out of the approximately 180,000 Words being used in Modern English, it is said that with a vocabulary of about 2,000 Words, you should be able to converse in general terms. A "Lexical Encoding" would encode each Word not each Letter, and encapsulate them within a Sentence. // An simplified example of a "Lexical Encoding" String sentence = "How are you today?"; int[] sentence = { 93, 22, 14, 330, QUERY }; In this example each Token in the String was encoded as an Integer. The Encoding Scheme here simply assigned an int value based on generalised statistical ranking of word usage, and assigned a constant to the question mark. Ultimately, a Word has both a Spelling & Meaning though. Any "Lexical Encoding" would preserve the meaning and intent of the Sentence as a whole, and not be language specific. An English sentence would be encoded into "...language-neutral atomic elements of meaning ..." which could then be reconstituted into any language with a structured Syntactic Form and Grammatical Structure. What are other examples of "Lexical Encoding" techniques? If you were interested in where the word-usage statistics come from : http://www.wordcount.org

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  • How do I find the .max of an attribute value among a group of different Models?

    - by Angela
    Hi, everyone: I am also open to just straight-up refactoring what I'm finding to be pretty repetitive, but to give a baseline of how it's working.... I have for every contact a Campaign, which has_many of three types of Models: Email, Call, and Letter. When an Email (Call or Letter) has been executed for a specific contact, I have a Contact_Email(_or_Call_or_Letter) which belongs to both the Contact and the Model (Email_or_Call_or_Letter). Each Contact_Email for example pairing has a :date_sent attribute. So does each Contact_Call and Contact_Letter. How do I find the latest of all of them? Here is the code I wrote that can find the latest Email and my finding retyping similar code for Call and Letter, but then stuck on how to do a .max on all of them: def last_email(contact) #get campaign the contact belongs to @campaign = Campaign.find_by_id(contact.campaign_id) @last_email = ContactEmail.find(:last, :conditions => "contact_id = #{contact.id}", :order => "date_sent DESC") @last_call = ContactCall.find(:last, :conditions => "contact_id = #{contact.id}", :order => "date_sent DESC") @last_letter = ContactLetter.find(:last, :conditions => "contact_id = #{contact.id}", :order => "date_sent DESC") # how do I get the latest of all of these to display? if @last_sent_email.nil? return "no email sent" else return @last_sent_email.date_sent end end Question 1: With what I have, how can I find effectively @last_event given I can find the last Email, last Call, and last Letter for every contact? Question 2: How can I remove the repetitive code that I have to write for each Model?

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  • Ruby Challenge - efficiently change the last character of every word in a sentence to a capital

    - by emson
    Hi All I recently was challenged to write some Ruby code to change the last character of every word in a sentence into a capital. Such that the string: "script to convert the last letter of every word to a capital" becomes "scripT tO converT thE lasT letteR oF everY worD tO A capitaL" This was my optimal solution however I'm sure you wizards have much better solutions and I would be really interested to hear them. "script to convert the last letter of every word to a capital".split.map{|w|w<<w.slice!(-1).chr.upcase}.join' ' For those interested as to what is going on here is an explanation. split will split the sentence up into an array, the default delimiter is a space and with Ruby you don't need to use brackets here. map the array from split is passed to map which opens a block and process each word (w) in the array. the block slice!(s) off the last character of the word and converts it to a chr (a character not ASCII code) and then capitalises upcase it. This character is now appended << to the word which is missing the sliced last letter. Finally the array of words is now join together with a ' ' to reform the sentence. Enjoy

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  • PHP in_array() can't even match a single character. Strict is set to true.

    - by solefald
    I've seen a million of these threads here already, and read through every single one already. Including some serious time Googling. Nothing complicated. All I have to do is check if a single character in a loop matches my alphabet array. print_r($alphabet); // all 26 letters Array ( [0] => a [1] => b [2] => c ... [23] => x [24] => y [25] => z ) print_r($emptyLetters); // dynamic array. Array ( [0] => b [1] => s ) foreach($alphabet as $letter): { echo $letter . '<br />' // Correctly prints out every letter from $alphabet. if(in_array($letter, $emptyLetters, true)): // $strict is set // do something endif; } What the hell is going on??? I do not understand what i am doing wrong.... I tried every combination and option possible, but for some reason even array_search() is bit working...

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  • How can I find all items beginning with a or â?

    - by Malcolm Frexner
    I have a list of items that are grouped by their first letter. By clicking a letter the user gets alle entries that begin with that letter. This does not work for french. If I choose the letter a, items with â are not returned. What is a good way to return items no matter if they have an accent or not? <% char alphaStart = Char.Parse("A"); char alphaEnd = Char.Parse("Z"); %> <% for (char i = alphaStart; i <= alphaEnd; i++) { %> <% char c = i; %> <% var abcList = Model.FaqList.Where(x => x.CmsHeader.StartsWith(c.ToString())).ToList(); %> <% if (abcList.Count > 0 ) { %> <div class="naviPkt"> <a id="<%= i.ToString().ToUpper() %>" class="naviPktLetter" href="#<%= i.ToString().ToLower() %>"><%= i.ToString().ToUpper() %></a> </div> <ul id="menuGroup<%= i.ToString().ToUpper() %>" class="contextMenu" style="display:none;"> <% foreach (var info in abcList) { %> <li class="<%= info.CmsHeader%>"> <a id="infoId<%= info.CmsInfoId%>" href="#<%= info.CmsInfoId%>" class="abcEntry"><%= info.CmsHeader%></a> </li> <% } %> </ul> <% } %> <% } %>

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  • How can I dynamically define the named route in a :partial in rails?

    - by Angela
    I have the following partial. It can be called from three different times in a view as follows: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => email} %> Second time: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => call} %> Third time: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => letter} %> In each instance, call, email, letter refer to a specific instance of a Model Call, Email, or Letter. Here is the content of the partial "contact_event": <%= link_to_remote "Skip #{event} Remote", :url => skip_contact_email_url(contact_event, event), :update => "update-area-#{contact_event.id}-#{event.id}" %> <span id='update-area-<%="#{contact_event.id}-#{event.id}"%>'> </span> </p> My challenge: skip_contact_email_url only works when the event refers to an email. How can I dynamically define skip_contact_email_url to be skip_contact_letter_url if the local variable is letter? Even better, how can I have a single named route that would do the appropriate action?

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  • How can I dynamically call the named route in a :partial in rails?

    - by Angela
    I have the following partial. It can be called from three different times in a view as follows: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => email} %> Second time: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => call} %> Third time: <%= render :partial => "contact_event", :collection => @contacts, :locals => {:event => letter} %> In each instance, call, email, letter refer to a specific instance of a Model Call, Email, or Letter. Here is what I tried to do and conceptually what I'd like to do: assign the route based on the class name that has been passed to the :event from the :partial. What I did was create what the actual url should be. The 'text' of it is correct, but doesn't seem to recognize it as a named route. <% url = "skip_contact_#{event.class.name.tableize.singularize}_url" % <%= link_to_remote "Skip #{url} Remote", :url = skip_contact_email_url(contact_event, event), :update = "update-area-#{contact_event.id}-#{event.id}" % ' My challenge: skip_contact_email_url only works when the event refers to an email. How can I dynamically define skip_contact_email_url to be skip_contact_letter_url if the local variable is letter? Even better, how can I have a single named route that would do the appropriate action?

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  • iPhone SDK Tableview Datasource singleton error

    - by mrburns05
    I basically followed apple "TheElements" sample and changed "PeriodicElements" .h & .m to my own "SortedItems" .h & .m During compile I get this error: "Undefined symbols: "_OBJC_CLASS_$_SortedItems", referenced from: __objc_classrefs__DATA@0 in SortedByNameTableDataSource.o ld: symbol(s) not found collect2: ld returned 1 exit status " here is my SortedItems.m file #import "SortedItems.h" #import "item.h" #import "MyAppDelegate.h" @interface SortedItems(mymethods) // these are private methods that outside classes need not use - (void)presortItemsByPhysicalState; - (void)presortItemInitialLetterIndexes; - (void)presortItemNamesForInitialLetter:(NSString *)aKey; - (void)presortItemsWithPhysicalState:(NSString *)state; - (NSArray *)presortItemsByNumber; - (NSArray *)presortItemsBySymbol; - (void)setupItemsArray; @end @implementation SortedItems @synthesize statesDictionary; @synthesize itemsDictionary; @synthesize nameIndexesDictionary; @synthesize itemNameIndexArray; @synthesize itemsSortedByNumber; @synthesize itemsSortedBySymbol; @synthesize itemPhysicalStatesArray; static SortedItems *sharedSortedItemsInstance = nil; + (SortedItems*)sharedSortedItems { @synchronized(self) { if (sharedSortedItemsInstance == nil) { [[self alloc] init]; // assignment not done here } } return sharedSortedItemsInstance; // note: Xcode (3.2) static analyzer will report this singleton as a false positive // '(Potential leak of an object allocated') } + (id)allocWithZone:(NSZone *)zone { @synchronized(self) { if (sharedSortedItemsInstance == nil) { sharedSortedItemsInstance = [super allocWithZone:zone]; return sharedSortedItemsInstance; // assignment and return on first allocation } } return nil; //on subsequent allocation attempts return nil } - (id)copyWithZone:(NSZone *)zone { return self; } - (id)retain { return self; } - (unsigned)retainCount { return UINT_MAX; //denotes an object that cannot be released } - (void)release { //do nothing } - (id)autorelease { return self; } // setup the data collection - init { if (self = [super init]) { [self setupItemsArray]; } return self; } - (void)setupItemsArray { NSDictionary *eachItem; // create dictionaries that contain the arrays of Item data indexed by // name self.itemsDictionary = [NSMutableDictionary dictionary]; // physical state self.statesDictionary = [NSMutableDictionary dictionary]; // unique first characters (for the Name index table) self.nameIndexesDictionary = [NSMutableDictionary dictionary]; // create empty array entries in the states Dictionary or each physical state [statesDictionary setObject:[NSMutableArray array] forKey:@"Solid"]; [statesDictionary setObject:[NSMutableArray array] forKey:@"Liquid"]; [statesDictionary setObject:[NSMutableArray array] forKey:@"Gas"]; [statesDictionary setObject:[NSMutableArray array] forKey:@"Artificial"]; MyAppDelegate *ad = (MyAppDelegate *)[[UIApplication sharedApplication]delegate]; NSMutableArray *rawItemsArray = [[NSMutableArray alloc] init]; [rawItemsArray addObjectsFromArray:ad.items]; // iterate over the values in the raw Items dictionary for (eachItem in rawItemsArray) { // create an atomic Item instance for each Item *anItem = [[Item alloc] initWithDictionary:eachItem]; // store that item in the Items dictionary with the name as the key [itemsDictionary setObject:anItem forKey:anItem.title]; // add that Item to the appropriate array in the physical state dictionary [[statesDictionary objectForKey:anItem.acct] addObject:anItem]; // get the Item's initial letter NSString *firstLetter = [anItem.title substringToIndex:1]; NSMutableArray *existingArray; // if an array already exists in the name index dictionary // simply add the Item to it, otherwise create an array // and add it to the name index dictionary with the letter as the key if (existingArray = [nameIndexesDictionary valueForKey:firstLetter]) { [existingArray addObject:anItem]; } else { NSMutableArray *tempArray = [NSMutableArray array]; [nameIndexesDictionary setObject:tempArray forKey:firstLetter]; [tempArray addObject:anItem]; } // release the Item, it is held by the various collections [anItem release]; } // release the raw Item data [rawItemsArray release]; // create the dictionary containing the possible Item states // and presort the states data self.itemPhysicalStatesArray = [NSArray arrayWithObjects:@"something",@"somethingElse",@"whatever",@"stuff",nil]; [self presortItemsByPhysicalState]; // presort the dictionaries now // this could be done the first time they are requested instead [self presortItemInitialLetterIndexes]; self.itemsSortedByNumber = [self presortItemsByNumber]; self.itemsSortedBySymbol = [self presortItemsBySymbol]; } // return the array of Items for the requested physical state - (NSArray *)itemsWithPhysicalState:(NSString*)aState { return [statesDictionary objectForKey:aState]; } // presort each of the arrays for the physical states - (void)presortItemsByPhysicalState { for (NSString *stateKey in itemPhysicalStatesArray) { [self presortItemsWithPhysicalState:stateKey]; } } - (void)presortItemsWithPhysicalState:(NSString *)state { NSSortDescriptor *nameDescriptor = [[NSSortDescriptor alloc] initWithKey:@"title" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)] ; NSArray *descriptors = [NSArray arrayWithObject:nameDescriptor]; [[statesDictionary objectForKey:state] sortUsingDescriptors:descriptors]; [nameDescriptor release]; } // return an array of Items for an initial letter (ie A, B, C, ...) - (NSArray *)itemsWithInitialLetter:(NSString*)aKey { return [nameIndexesDictionary objectForKey:aKey]; } // presort the name index arrays so the items are in the correct order - (void)presortItemsInitialLetterIndexes { self.itemNameIndexArray = [[nameIndexesDictionary allKeys] sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)]; for (NSString *eachNameIndex in itemNameIndexArray) { [self presortItemNamesForInitialLetter:eachNameIndex]; } } - (void)presortItemNamesForInitialLetter:(NSString *)aKey { NSSortDescriptor *nameDescriptor = [[NSSortDescriptor alloc] initWithKey:@"title" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)] ; NSArray *descriptors = [NSArray arrayWithObject:nameDescriptor]; [[nameIndexesDictionary objectForKey:aKey] sortUsingDescriptors:descriptors]; [nameDescriptor release]; } // presort the ItemsSortedByNumber array - (NSArray *)presortItemsByNumber { NSSortDescriptor *nameDescriptor = [[NSSortDescriptor alloc] initWithKey:@"acct" ascending:YES selector:@selector(compare:)] ; NSArray *descriptors = [NSArray arrayWithObject:nameDescriptor]; NSArray *sortedItems = [[itemsDictionary allValues] sortedArrayUsingDescriptors:descriptors]; [nameDescriptor release]; return sortedItems; } // presort the itemsSortedBySymbol array - (NSArray *)presortItemsBySymbol { NSSortDescriptor *symbolDescriptor = [[NSSortDescriptor alloc] initWithKey:@"title" ascending:YES selector:@selector(localizedCaseInsensitiveCompare:)] ; NSArray *descriptors = [NSArray arrayWithObject:symbolDescriptor]; NSArray *sortedItems = [[itemsDictionary allValues] sortedArrayUsingDescriptors:descriptors]; [symbolDescriptor release]; return sortedItems; } @end I followed the sample exactly - don't know where I went wrong. Here is my "SortedByNameTableDataSource.m" #import "SortedByNameTableDataSource.h" #import "SortedItems.h" #import "Item.h" #import "ItemCell.h" #import "GradientView.h" #import "UIColor-Expanded.h" #import "MyAppDelegate.h" @implementation SortedByNameTableDataSource - (NSString *)title { return @"Title"; } - (UITableViewStyle)tableViewStyle { return UITableViewStylePlain; }; // return the atomic element at the index - (Item *)itemForIndexPath:(NSIndexPath *)indexPath { return [[[SortedItems sharedSortedItems] itemsWithInitialLetter:[[[SortedItems sharedSortedItems] itemNameIndexArray] objectAtIndex:indexPath.section]] objectAtIndex:indexPath.row]; } // UITableViewDataSource methods - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *MyIdentifier = @"ItemCell"; ItemCell *itemCell = (ItemCell *)[tableView dequeueReusableCellWithIdentifier:MyIdentifier]; if (itemCell == nil) { itemCell = [[[ItemCell alloc] initWithFrame:CGRectZero reuseIdentifier:MyIdentifier] autorelease]; itemCell = CGRectMake(0.0, 0.0, 320.0, ROW_HEIGHT); itemCell.backgroundView = [[[GradientView alloc] init] autorelease]; } itemCell.todo = [self itemForIndexPath:indexPath]; return itemCell; } - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { // this table has multiple sections. One for each unique character that an element begins with // [A,B,C,D,E,F,G,H,I,K,L,M,N,O,P,R,S,T,U,V,X,Y,Z] // return the count of that array return [[[SortedItems sharedSortedItems] itemNameIndexArray] count]; } - (NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView { // returns the array of section titles. There is one entry for each unique character that an element begins with // [A,B,C,D,E,F,G,H,I,K,L,M,N,O,P,R,S,T,U,V,X,Y,Z] return [[SortedItems sharedSortedItems] itemNameIndexArray]; } - (NSInteger)tableView:(UITableView *)tableView sectionForSectionIndexTitle:(NSString *)title atIndex:(NSInteger)index { return index; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { // the section represents the initial letter of the element // return that letter NSString *initialLetter = [[[SortedItems sharedSortedItems] itemNameIndexArray] objectAtIndex:section]; // get the array of elements that begin with that letter NSArray *itemsWithInitialLetter = [[SortedItems sharedSortedItems] itemsWithInitialLetter:initialLetter]; // return the count return [itemsWithInitialLetter count]; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { // this table has multiple sections. One for each unique character that an element begins with // [A,B,C,D,E,F,G,H,I,K,L,M,N,O,P,R,S,T,U,V,X,Y,Z] // return the letter that represents the requested section // this is actually a delegate method, but we forward the request to the datasource in the view controller return [[[SortedItems sharedSortedItems] itemNameIndexArray] objectAtIndex:section]; } @end

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  • linux grep question

    - by lepricon123
    how do i find a string in files in a directory. And these file names begin with letter a. I also want to get the number of occurrences of this string fromt he grep I run. I tried this cat * | grep -c string but it searches all files. I just want to search files that begin with letter a Thanks

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  • Program to write for you?

    - by Richard Morton
    I need a program that can write what you input in it, and "writing" it back on another process, letter by letter, not copying and pasting it back. Basically, I have a insanely huge file that would take me about a month of non-stop keyboard typing and I can't simply control-C to the other program because it doesn't allow pasting text (go figure). I do realize it's quite an unusual question, but I need this to be done by a machine and not myself. Is there any way to be done?

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  • WinPE, Startnet.CMD and passing variables to second batch file not working

    - by user140892
    I don't know scripting or PowerShell (yes I need to learn something). I'm not an expert batch file maker either. I have a WinPE flash drive which I used to deploy OS images. I have the WIM, drivers and anything needed else outside the WinPE environment to ensure that Updates, changes are easier for me to make. I use the "STARTNET.CMD" batch file which is part of the WinPE. The reason to go through the letter drives is that the WinPE always gets the X letter drive assigned. The flash drive itself can receive a random letter which always changes. My deployment menu is located on the flash drive it self and not inside the WinPE. This is so that if I need to make a change I don't have to re-do the WinPE. I am able to locate the "menu.bat" batch file and launch it. I use a variable to capture the letter drive. I call the second batch file named "menu.bat" and pass the variable to it. When the second batch file loads, I believe that I am calling the variable correctly. If I break out of the batch file I can echo the variable and see the expected reply. The issue is that I can't use the variable to work with anything on the second batch file. In my test, I can get this to work over and over. When it runs from the real USB flash drive it does not work. I removed comments from the second batch file to make it smaller. My issue is that files below all get a message stating that the system cannot find the path specified. Diskpart Imagex.exe bcdboot.exe Why can't I get the varible to properly function when I try to using example "ImageX.exe"? Contents of the Startnet.cmd @echo off for %%p in (a b c d e f g h i j k l m n o p q r s t u v w x y z) do if exist %%p:\Tools\ set w=%%p Set execpatch=%w%\Tools\ call %w%:\Menu.bat \Tools\ Contents of the Menu.BAT @echo off set SecondPath=%1 cls :Start cls Echo. Echo.============================================================== Echo. Windows 7 64 Bit Ent Basic Desktops Echo.============================================================== Echo. Echo A. 790 Windows 7 - Basic Echo. Echo. Echo I. Exit Echo. Echo. set /p choice=Choose your option = if not '%choice%'=='' set choice=%choice:~0,1% if '%choice%'=='a' goto 790_Windows_7_Basic echo "%choice%" is not a valid (answer/command) echo. goto start :790_Windows_7_Basic REM DISKPART /s %SecondPath%BatchFiles\Make-Partition.txt %SecondPath%imagex.exe /apply %SecondPath%Images\Win7-64b-Ent-Basic-SysPreped.wim 1 o:\ /verify %SecondPath%bcdboot.exe o:\Windows /s S: Copy %SecondPath%Unattended\unattend.XML o:\Windows\System32\sysprep\unattend.XML /y xcopy %SecondPath%Drivers\790\*.* o:\Windows\INF\790\ /E /Q /Y MD o:\Windows\Setup\Scripts\ Copy %SecondPath%BatchFiles\SetupComplete.cmd o:\Windows\Setup\Scripts\ /y Goto Done :Done Exit

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  • Specify drive letters during installation

    - by Seva Alekseyev
    Hi all, The hard drive has two partitions. I'm installing Windows 7 on the second one. It automatically gets assigned the drive letter C (and the first partition becomes D). Is there any way to override this assignment during installation? It's a dual-boot system, and I want drive letters to be consistent. On the vanilla drive selection dialog, there's no letter assignment UI.

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