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  • How can I generate a list of appendices with LaTeX, seperate from table of contents (toc)

    - by None
    LaTeX' appendix environment formats sections differently and uses a different enumeration in the table of contents: \begin{appendix} \section{superuser} \dots{} .... Shows up as       A       superuser            11 in the \tableofcontents. Unfortunately, I have to use a different style: the appendix is not to show up in the table of contents, but in a seperate listing right before the appendix. I see the following options to solve this: suppress output in tableofcontents and somehow recreate the part on a different page generate a custom listing of specified / the following section manually create a list with the same formatting of the tableofcontents I use scrartcl as document class. PS: appedix / appendices is not a tag yet

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  • who delete my files?

    - by akalter
    I have some linux server. on two of our server we have mysql. we have daily backup on both machine. but the script different. i saw both scripts. on one of them i saw the "delete older files" algorithm, but in the other this is happening but not from the script. i trying to know who dletes my files, because of that i want to use same script on both machine because of that in the script with the deletion i also copy the files to the another server, and i want to do that in both servers. Who have an idea who delete my older backups? Thank you!

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  • who deleted my files?

    - by akalter
    I have some linux servers. On two of our server we have MySQL. We have daily backup on both machine. But the scripts are different. I saw both scripts. On one of them I saw the "delete older files" algorithm, but in the other this is happening but not from the script. I am trying to discover who deletes my files, because of that I want to use same script on both machine because of that in the script with the deletion I also copy the files to the another server, and I want to do that in both servers. Who have an idea who deleted my older backups? Thank you!

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  • Accessing large log files on a unix machine with textpad

    - by Jason
    Hi, I'm interested to access large log files on a unix server with textpad. (textpad for history reasons, i personally prefer ofcourse less awk grep etc) but I have many personal who rather be using textpad they have years of experience with it and can tweak it to do whatever they want. The problem is that if i connect for example with winscp to get the log files to textpad it first fetches the full log and user needs to wait and it bloats etc. I would rather the textpad to somehow access the unix machine and get only the relevant segment of the log file (large log files could be GB) anyone knows how can this be achieved?

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  • Too many files open issue (in CentOS)

    - by Ram
    Recently I ran into this issue in one of our production machines. The actual issue from PHP looked like this: fopen(dberror_20110308.txt): failed to open stream: Too many open files I am running LAMP stack along with memcache in this machine. I also run a couple of Java applications in this machine. While I did increase the limit on the number of files that can be opened to 10000 (from 1024), I would really like to know if there is an easy way to track this (# of files open at any moment) as a metric. I know lsof is a command which will list the file descriptors opened by processes. Wondering if there is any other better (in terms of report) way of tracking this using say, nagios.

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  • Implementation ideas to store multiple files within a single file for faster access?

    - by eminemence
    My requirement is to store a large number of files within a single file.The files stored could be anything like images, videos or simple text files as well. I want some ideas to implement the same. I am thinking of implementing a file system within a file, but am not sure if its a good idea. The main area of concern here is the access time. Also I want to provide encryption for this single file. Any suggestions are welcome.

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  • Problem with implementing removeAll for List of custom object

    - by Jay
    Hello everyone, I have a scenario in my code where I need to compare two Lists and remove from the first list, objects which are present in the second list. Akin to how the "removeAll" object works for List. Since my List is created on a custom object, the removeAll method won't work for me. I have tried various methods to make this work: - implemented equals() and hashCode for the custom object comprising the list - implemented the Comparable Interface for the custom object - implemented the Comparator Interface for the custom object I've even tried using the Apache Common's CollectionUtils and ListUtils methods (subtract, intersect, removeAll). None seem to work. I understand I will perhaps need to write some custom removal code. But not sure how to go about doing that. Any pointers helping me move in the right direction will be really appreciated. Thanks, Jay

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  • Convert a List of Options to an Option of List using Scalaz

    - by Rafael de F. Ferreira
    The following function transforms a list of Option[T] into a list of Some[T], in the case where all members are Some's, or None, in the case where there is at least one None member. I guess the code is clearer that this explanation: def lo2ol[T](lo: List[Option[T]]): Option[List[T]] = { lo.foldRight[Option[List[T]]](Some(Nil)){(o, ol) => (o, ol) match { case (Some(x), Some(xs)) => Some(x :: xs); case _ => None : Option[List[T]]; }}} I remember seeing somewhere a similar example, but using Scalaz to simplify the code. How would it look like?

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  • converting a matrix to a list

    - by andrewj
    Suppose I have a matrix foo as follows: foo <- cbind(c(1,2,3), c(15,16,17)) > foo [,1] [,2] [1,] 1 15 [2,] 2 16 [3,] 3 17 I'd like to turn it into a list that looks like [[1]] [1] 1 15 [[2]] [1] 2 16 [[3]] [1] 3 17 You can do it as follows: lapply(apply(foo, 1, function(x) list(c(x[1], x[2]))), function(y) unlist(y)) I'm interested in an alternative method that isn't as complicated. Note, if you just do apply(foo, 1, function(x) list(c(x[1], x[2]))), it returns a list within a list, which I'm hoping to avoid.

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  • Header file-name as argument

    - by Alphaneo
    Objective: I have a list of header files (about 50 of them), And each header-file has few arrays with constant elements. I need to write a program to count the elements of the array. And create some other form of output (which will be used by the hardware group). My solution: I included all the 50 odd files and wrote an application. And then I dumped all the elements of the array into the specified format. My environment: Visual Studio V6, Windows XP My problem: Each time there is a new set of Header files, I am now changing the VC++ project settings to point to the new set of header files, and then rebuild. My question: A bit in-sane though, Is there any way to mention the header from some command line arguments or something? I just want to avoid re-compiling the source every time...

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  • sharepoint list relationship question

    - by Korey
    I have two custom lists in sharepoint with a one to many relationship on a column in both lists. So list A has text column 1 and list B has a lookup column 1' on list A's column 1. I want to display the rows in list A, where column 1 has a match on column 1' and a 2nd column in list B with a specific text string. I have Sharepoint Designer and am fumbling along with linked sources described here http://office.microsoft.com/en-us/sharepointdesigner/HA100991441033.aspx, but can't get exactly what I'm looking for.

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  • Upgrading a SharePoint list instance that was deployed via feature

    - by Goldmember
    I'm curious how others address this issue. Using VSEWSS 1.3, I have created a site content type, a list definition (w event receivers), and a list instance. All of them are in the same WSP solution and each is activated individually via features. Now let's assume that all the features have been activated for some time, and the list instance contains a number of items (that can't be deleted). Now suppose I need to make a change to the schema.xml (inject some javascript, modify views, whatever) of the list. Is it even possible to "upgrade" the schema of the existing list instance? Otherwise I would think I'm stuck creating a new instance and copying items over.

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  • Fill a array with List data with one more element

    - by marionmaiden
    Hello, By a question that I made, I figured out that tho copy elements from one list to an array I just need to use the method toArray() for this. But let's suppose I have a List with n objects. I want to copy then into a array sized n+1 and add into the first position another object and in the other n positions the n data of the list. This is the way I'm doing it for now, but I'm just wondering if there is a better way for do that: Object array[] = new Object[list.size() + 1]; Object chk = new Object(); array[0] = chk; for(int i = 1; i < array.length; i++){ array[i] = list.get(i); }

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  • How do I rename my old Program Files folder?

    - by SteveJ
    I installed a new SSD as my boot drive (C:), installed a fresh version of Windows 7 64-bit, and kept my existing SATA drive in the system (D:). I want to keep using my D: drive for file storage (no sense filling up the SSD with stuff that isn't performance critical) and I haven't formatted the D: drive because there's stuff on there I want to keep. I also want to create a new "D:\Program Files" folder so I can install apps that aren't performance-critical there. So I decided I'd rename the existing "D:\Program Files" from my old Windows install to "D:\Old Program Files" and then create a new "D:\Program Files" directory. Easy, right? I can see "D:\Program Files" just fine in Explorer. I right click, select Rename, and type "Old Program Files." I get the alert that says I need Admin permission to do this, so I press the confirm button with the shield. But the folder still appears as "Program Files" in Explorer. I jump out to the command line, and it appears as "Old Program Files" when I do a dir. I can even do mkdir "Program Files" and when I do a dir they both appear. But in the Explorer GUI, it looks like I have two "Program Files" folders. This will be confusing during app installation because I won't be able to tell which one is which. I've tried poking around in the properties tab of the old folder, but can't find anything that would explain what's causing the issue. How do I rename the old Program Files folder?

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  • just-in-time list

    - by intuited
    I'd like to know if there is a class available, either in the standard library or in pypi, that fits this description. The constructor would take an iterator. It would implement the container protocol (ie _getitem_, _len_, etc), so that slices, length, etc., would work. In doing so, it would iterate and retain just enough values from its constructor argument to provide whatever information was requested. So if jitlist[6] was requested, it would call self.source.next() 7 times, save those elements in its list, and return the last one. This would allow downstream code to use it as a list, but avoid unnecessarily instantiating a list for cases where list functionality was not needed, and avoid allocating memory for the entire list if only a few members ended up being requested. It seems like a pretty easy one to write, but it also seems useful enough that it's likely that someone would have already made it available in a module.

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  • Python: Repeat elements in a list comprehension?

    - by User
    I have the following list comprehension which returns a list of coordinate objects for each location. coordinate_list = [Coordinates(location.latitude, location.longitude) for location in locations] This works. Now suppose the location object has a number_of_times member. I want a list comprehension to generate n Coordinate objects where n is the number_of_times for the particular location. So if a location has number_of_times = 5 then the coordinates for that location will be repeated 5 times in the list. (Maybe this is a case for a for-loop but I'm curious if it can be done via list comprehensions)

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  • python conditional list creation from 2D lists

    - by dls
    Say I've got a list of lists. Say the inner list of three elements in size and looks like this: ['apple', 'fruit', 1.23] The outer list looks like this data = [['apple', 'fruit', 1.23], ['pear', 'fruit', 2.34], ['lettuce', 'vegetable', 3.45]] I want to iterate through the outer list and cull data for a temporary list only in the case that element 1 matches some keyword (aka: 'fruit'). So, if I'm matching fruit, I would end up with this: tempList = [('apple', 1.23), ('pear', 2.34)] This is one way to accomplish this: tempList = [] for i in data: if i[1] == 'fruit': tempList.append(i[0], i[2]) is there some 'Pythonic' way to do this in fewer lines?

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  • Display/Hide part of a list

    - by superexsl
    Hi I have an (unordered)list (generated by a repeater) of items. However, I'd like to show the first three items, and have the rest hidden by the main content div. When a button is pressed, I would like the list's div to expand, pushing the main content div down and showing the rest of the list. I was thinking of using slideDown(), but that closes the entire div ( and I would like to show the first 3 items of the list). What would be the best way to achieve an effect like this? Is there a plugin that can easily show X items of a list and the display the rest upon request? Thanks

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  • Fastest way to check a List<T> for a date

    - by fishhead
    I have a list of dates that a machine has worked on, but it doesn't include a date that machine was down. I need to create a list of days worked and not worked. I am not sure of the best way to do this. I have started by incrementing through all the days of a range and checking to see if the date is in the list by iterating through the entire list each time. I am looking for a more efficient means of finding the dates. class machineday { datetime WorkingDay; } class machinedaycollection : List<machineday> { }

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  • Best way to implement a List(Of) with a maximum number of items

    - by Ben
    I'm trying to figure out a good way of implementing a List(Of) that holds a maximum number of records. e.g. I have a List(Of Int32) - it's being populated every 2 seconds with a new Int32 item. I want to store only the most current 2000 items. How can I make the list hold a maximum of 2000 items, then when the 2001'th item is attempted to be added, the List drops the 2000'th item (resulting in the current total being 1999). Thing is, I need to make sure I'm dropping only the oldest item and adding a new item into the List. Ben

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  • Trim email list into domain list

    - by hanjaya
    The function below is part of a script to trim email list from a file into domain list and removes duplicates. /* define a function that can accept a list of email addresses */ function getUniqueDomains($list) { // iterate over list, split addresses and add domain part to another array $domains = array(); foreach ($list as $l) { $arr = explode("@", $l); $domains[] = trim($arr[1]); } // remove duplicates and return return array_unique($domains); } What does $domains[] = trim($arr[1]); mean? Specifically the $arr[1]. What does [1] mean in this context? How come variable $arr becomes an array variable?

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  • Using a Loop to add objects to a list(python)

    - by Will
    Hey guys so im trying to use a while loop to add objects to a list. Heres bascially what i want to do: (ill paste actually go after) class x: blah blah choice = raw_input(pick what you want to do) while(choice!=0): if(choice==1): Enter in info for the class: append object to list (A) if(choice==2): print out length of list(A) if(choice==0): break ((((other options)))) as im doing this i can get the object to get added to the list, but i am stuck as to how to add multiple objects to the list in the loop. Here is my actual code i have so far... print "Welcome to the Student Management Program" class Student: def init (self, name, age, gender, favclass): self.name = name self.age = age self.gender = gender self.fac = favclass choice = int(raw_input("Make a Choice: " )) while (choice !=0): if (guess==1): print("STUDENT") namer = raw_input("Enter Name: ") ager = raw_input("Enter Age: ") sexer = raw_input("Enter Sex: ") faver = raw_input("Enter Fav: ") elif(guess==2): print "TESTING LINE" elif(guess==3): print(len(a)) guess=int(raw_input("Make a Choice: ")) s = Student(namer, ager, sexer, faver) a =[]; a.append(s) raw_input("Press enter to exit") any help would be greatly appreciated!

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  • Java, searching within a list of objects?

    - by Rick
    I'm a bit lost on the way to make this happen the fastest. I have a large list of objects that have basic variable attributes (with getters / setters) and I need to do a search in this list to find the objects within the list that match a given parameter I have found how to do a regular list search but I need to, for example search for the value of the result of doing a call getName() for each object in the list and get objects that have a result that matches my input. Something like below where the third argument is the result of the method call and the second is what I am trying to find. int index = Collections.binarySearch(myList, "value", getName()); Any advice is appreciated

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  • C++ Generic List Assignment

    - by S73417H
    I've clearly been stuck in Java land for too long... Is it possible to do the C++ equivalent of the following Java code: // Method List<Bar> getBars() { return new LinkedList<Bar>(); } // Assignment statement. List<Foo> stuff = getBars(); Where Foo is a sub-class of Bar. So in C++.... std::list<Bar> & getBars() { std::list<Bar> bars; return bars; } std::list<Foo> stuff = getBars(); Hope that makes sense....

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  • Linked List Inserting in sorted format

    - by user2738718
    package practise; public class Node { public int data; public Node next; public Node (int data, Node next) { this.data = data; this.next = next; } public int size (Node list) { int count = 0; while(list != null){ list = list.next; count++; } return count; } public static Node insert(Node head, int value) { Node T; if (head == null || head.data <= value) { T = new Node(value,head); return T; } else { head.next = insert(head.next, value); return head; } } } This work fine for all data values less than the first or the head. anything greater than than doesn't get added to the list.please explain in simple terms thanks.

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