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  • How can I join this 2 queries?(A select query with join and An unpivot query)

    - by MANG KANOR
    Here are my two queries SELECT EWND.Position, NKey = CASE WHEN ISNULL(Translation.Name, '') = '' THEN EWND.Name ELSE Translation.Name END, Unit = EW_N_DEF.Units FROM EWND INNER JOIN EW_N_DEF ON EW_N_DEF.Nutr_No = EWND.Nutr_No LEFT JOIN Translation ON Translation.CodeMain = EWND.Nutr_no WHERE Translation.CodeTrans = 1 ORDER BY EWND.Position And this is the unpivot one SELECT * FROM (SELECT N1,N2,N3,N4,N5,N6,N7,N8,N9,N10,N11,N12,N13,N14,N15,N16,N17,N18,N19,N20,N21,N22,N23,N24,N25,N26,N27,N28,N29,N30,N31,N32,N33,N34 FROM EWNVal WHERE Code=6035) Test UNPIVOT (Value FOR NUTCODE IN (N1,N2,N3,N4,N5,N6,N7,N8,N9,N10,N11,N12,N13,N14,N15,N16,N17,N18,N19,N20,N21,N22,N23,N24,N25,N26,N27,N28,N29,N30,N31,N32,N33,N34) )AS test Both Queries put out same number of rows but not columns, Is it possible to join this two? I tried the union but it has problems that I cant solve Thanks in advance!

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  • SQL-Join with NULL-columns

    - by tstenner
    I'm having the following tables: Table a +-------+------------------+------+-----+ | Field | Type | Null | Key | +-------+------------------+------+-----+ | bid | int(10) unsigned | YES | | | cid | int(10) unsigned | YES | | +-------+------------------+------+-----+ Table b +-------+------------------+------+ | Field | Type | Null | +-------+------------------+------+ | bid | int(10) unsigned | NO | | cid | int(10) unsigned | NO | | data | int(10) unsigned | NO | +-------+------------------+------+ When I want to select all rows from b where there's a corresponding bid/cid-pair in a, I simply use a natural join SELECT b.* FROM b NATURAL JOIN a; and everything is fine. When a.bid or a.cid is NULL, I want to get every row where the other column matches, e.g. if a.bid is NULL, I want every row where a.cid=b.cid, if both are NULL I want every column from b. My naive solution was this: SELECT DISTINCT b.* FROM b JOIN a ON ( ISNULL(a.bid) OR a.bid=b.bid ) AND (ISNULL(a.cid) OR a.cid=b.cid ) Is there any better way to to this?

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  • MySQL LEFT JOIN issue with three WHERE statements

    - by jhat
    I am building a note taking app for myself with tag filtering functions, but am having an issue when trying to grab notes with the tags. The tag filter needs to use AND not IN, because it will help better narrow down what I am looking for. My tables are configured like this: + notes note_id | note_title | note_uid + tags tag_id | tag_title + notes_tags nt_id | nt_note_id | nt_tag_id The notes_tags table keeps track of all notes' tags. I am not worried about returning any information about tags, so here is an example LEFT JOIN I am using currently to only get notes with only 1 tag. SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 This query runs perfect, it grabs all of the notes with that single tag. However, I am having issues "pinpointing" my notes using a query like this: SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 AND nt_tag_id = 11 What am I doing wrong with the syntax?

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  • Django query - join on the same table

    - by dana
    i have a mini blog app, and a 'timeline' . there i want to be displayed all the posts from all the friends of a user, plus the posts of that user himself. For that, i have to make some kind of a 'join' between the results of two queries (queries on the same table) , so that the final result will be the combination of the user - posesor of the account, and all his friends. My query looks like this: blog = New.objects.filter(created_by = following,created_by = request.user) By that ',' i wanted to make a 'join' -i found something like this on a doc- but this method is not correct- i'm getting an error. How else could be done this 'join' ? Thanks!

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  • Displaying Data from a Join in Codeigniter

    - by Brad
    I am using a simple join to pull data from two databases. This is the join in the model function com_control(){ $this->db->select('*'); $this->db->from('comments'); $this->db->join('posts', 'comments.entry_id = posts.id'); $query = $this->db->get(); return $query->result; } My desired method of display is going to be in a table so I am starting out to use like this foreach($comm_control as $row){ $this->table->add_row( $row->entry_id, $row->comments.id, $row->comment, $row->title ); }//end of foreach My problem is the display of data from comments.id. What is the proper format to add the comment.id into the table rows? I need the ID from both tables for display, edit and delete further on in the table. The only display I get at this time for "comment.id" is the word id. The Any help would be appreciated.

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  • Recover lost NTFS partition on SSD

    - by Emil
    Hello, About 2 month ago I upgraded my Dell Latitude E6500 laptop with a Corsair Force F120 SSD drive. Everything worked well until about a week or so back. I started the computer and was faced with a beep and a message saying "No boot sector on Internal HDD (IRRT). No bootable devices". Since I figured that the boot sector had somehow got corrupt I tried booting from the Windows 7 dvd in order to repair the boot sector. But the Windows 7 installation program only found a blank drive with 111GB of unallocated space. I panicked and brought the drive with me to work to let a colleague have a look at it. We made a disk image of the entire drive and ran the drive through Testdisk in Linux. Testdisk did not find any partitions. It appears that the drive has been completely erased... What has happened? What is causing this behavior on an SSD?

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  • partition alignment on fresh windows 2003 ent server

    - by Datapimp23
    Hi, I have this server which has it's physical disks in RAID 5 controlled by a 3com raid controller. size of the stripe unit is unknown for the moment (Can check tomorrow in the office). I need to install windows server 2003 ENT and create 2 partitions (OS, Data). I'd like to create the partitions before the installation on windows server. They have to be aligned properly. I have the newest version of gparted on a disc but I have no clue if this is the right tool. Can someone point me in the right direction? Thanks

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  • df shows partition as full, but du shows it as only 25% full

    - by Jakobud
    I have a humble linux server to do some stuff for me. I only have an old 16gig drive in it. df -h Filesystem Size Used Avail Use% Mounted on /dev/md1 16G 16G 0 100% / /dev/md0 121M 14M 101M 13% /boot tmpfs 502M 0 502M 0% /dev/shm but when I do: du -sh / 3.5G / So one says that my 16G drive is full. The other says only 3.5G is used. Why the discrepancy? I cannot write any new files as it says the drive is indeed full. But if I can't find the files taking up all the space on the file-system, how can I delete them to free up space?

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  • Unable to create system partition or locate existing system partition during Windows-7 installation

    - by glenneroo
    I have Windows XP 32-bit installed on an ASUS A8N-SLI Deluxe with 2x 500gb drives in RAID1 using the NV RAID controller. On this there are 3 partitions (XP, XP backup and DATA) There are also 4x 500gb drives in RAID10 using the Silicon Image 3114R RAID controller. I just purchased a Windows 7 64-bit as an ISO download upgrade version which I promptly burned to DVD and attempted to perform an upgrade installation. Here is the error message I am getting: Firstly, where are these "Setup log files" located? Second, does this mean I need to find compatible (64-bit?) drivers for the Mainboard and put them on floppy? EDIT: As suggested on another forum, I tried downloading the nVidia Mainboard RAID drivers for Windows 2003 64-bit. I loaded the drivers successfully using the Load Driver button, but pressing NEXT still returns this error.

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  • Moving Bootcamp partition to another drive

    - by Xster
    Hi, I don't know how sketch this is. I currently have Bootcamp with Windows 7 on my internal along with my Snow Leopard. I'm moving to a bigger harddrive. I'm reinstalling Snow Leopard but I would like to keep my Bootcamp. How do I migrate the data from one drive to another? Any suggestions? I'm not willing to spend money on this

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  • Root partition full? CentOS

    - by Joao Heleno
    Hi! I'm running CentOS 5.4 and my / is full. I wanted to install gparted but in order to do that I must install Priorities and it's when I get an error saying / is full so I can't go forward. Here's some output: fdisk -l Disk /dev/sda: 250.0 GB, 250000000000 bytes 255 heads, 63 sectors/track, 30394 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Device Boot Start End Blocks Id System /dev/sda1 * 1 2611 20972826 83 Linux /dev/sda2 2612 3251 5140800 82 Linux swap / Solaris /dev/sda3 3252 30394 218026147+ 83 Linux df Filesystem 1K-blocks Used Available Use% Mounted on /dev/sda1 20315812 19365152 0 100% / /dev/sda3 211196248 49228164 151066780 25% /home tmpfs 1552844 0 1552844 0% /dev/shm I'm not using LVM. Please advise. Thanks

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  • re-partition a disk

    - by veggiemexicalidog
    I have one disk partitioned into 2 logical drives, C and D. There is no unallocated space. I need to add space to C: so I want to use some space from D (plenty available). How can I do this without losing data on D:? Edit: This is a Windows machine.

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  • Resizing an existing linux partition during Ubuntu install

    - by Richard100
    Hello All, I have Fedora Core 10 installed on a PC, occupying the whole disk (no free space). I want to add Ubuntu 10.04 desktop edition. Does Ubuntu 10.04 allow you to resize existing partitions during the installation process in order to free up some space for the Ubuntu installation? Without losing or trashing existing data, obviously. Thanks.

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  • Cause of lost partition replaced by 2 Raw partitions

    - by DwightSampsonite
    Hi, I had a curious problem over the weekend... My 500gb WD hard drive all of a sudden could not be discovered by xp, then when I plugged in again via USB it was being discovered as 2 separate Raw partitions that were asking to be formatted. I have never modified partitions on this drive before. I was scratching my head for about this for 20mins or so when my second 1TB external hard drive did the exact same thing(with the same sized raw partitions as the 500gb). I have since recovered the original partitions and data using Testdisk . I am more curious on the cause.... I suspect this could be a virus, however my machine hadn’t been online in a few days and AVG didn’t detect anything. Has anyone seen this before?

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  • What is the use of "Partition" keyword in MySQL?

    - by chandru_cp
    As I am a MySQL newbie. What does PARTITION mean in this MySQL statement? CREATE TABLE employees ( id INT NOT NULL, fname VARCHAR(30), lname VARCHAR(30), hired DATE NOT NULL DEFAULT '1970-01-01', separated DATE NOT NULL DEFAULT '9999-12-31', job_code INT NOT NULL, store_id INT NOT NULL ) PARTITION BY RANGE (store_id) ( PARTITION p0 VALUES LESS THAN (6), PARTITION p1 VALUES LESS THAN (11), PARTITION p2 VALUES LESS THAN (16), PARTITION p3 VALUES LESS THAN (21) );

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  • How to get partition information from non-booting server?

    - by gravyface
    Need to manually rebuild a mirrored array on a server and am in the process of reinstalling SBS 2003 on it. However, it's a Dell server, and know that there's the Dell FAT32 diagnostics partition, a system partition, and a data partition, but do not know the size of each. Planning on reinstalling SBS 2003, all applications on the server, and then doing a System State restore, but figured that not having the correct partitions will cause some grief: am I right? Almost thinking that the size of the partitions shouldn't matter, but not positive. Question: should I care about the size of the partition? If so, how can I get this partition information from a non-booting drive? We have an Acronis image of the one working disk and the partitions are mounted/viewable in Explorer on a workstation, but I'm not sure where the Logical Disk Manager/Disk Management data is stored and/or if there's a way to retrieve it without having a working Windows installation.

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  • How to perform Cross Join with Linq

    - by berthin
    Cross join consists to perform a Cartesian product of two sets or sequences. The following example shows a simple Cartesian product of the sets A and B: A (a1, a2) B (b1, b2) => C (a1 b1,            a1 b2,            a2 b1,            a2, b2 ) is the Cartesian product's result. Linq to Sql allows using Cross join operations. Cross join is not equijoin, means that no predicate expression of equality in the Join clause of the query. To define a cross join query, you can use multiple from clauses. Note that there's no explicit operator for the cross join. In the following example, the query must join a sequence of Product with a sequence of Pricing Rules: 1: //Fill the data source 2: var products = new List<Product> 3: { 4: new Product{ProductID="P01",ProductName="Amaryl"}, 5: new Product {ProductID="P02", ProductName="acetaminophen"} 6: }; 7:  8: var pricingRules = new List<PricingRule> 9: { 10: new PricingRule {RuleID="R_1", RuleType="Free goods"}, 11: new PricingRule {RuleID="R_2", RuleType="Discount"}, 12: new PricingRule {RuleID="R_3", RuleType="Discount"} 13: }; 14: 15: //cross join query 16: var crossJoin = from p in products 17: from r in pricingRules 18: select new { ProductID = p.ProductID, RuleID = r.RuleID };   Below the definition of the two entities using in the above example.   1: public class Product 2: { 3: public string ProductID { get; set; } 4: public string ProductName { get; set; } 5: } 1: public class PricingRule 2: { 3: public string RuleID { get; set; } 4: public string RuleType { get; set; } 5: }   Doing this: 1: foreach (var result in crossJoin) 2: { 3: Console.WriteLine("({0} , {1})", result.ProductID, result.RuleID); 4: }   The output should be similar on this:   ( P01   -    R_1 )   ( P01   -    R_2 )   ( P01   -    R_3 )   ( P02   -    R_1 )   ( P02   -    R_2 )   ( P02   -    R_3) Conclusion Cross join operation is useful when performing a Cartesian product of two sequences object. However, it can produce very large result sets that may caused a problem of performance. So use with precautions :)

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  • creating extended partition

    - by SidhuHarry
    this is my current hard disk status(Running linux Mint LIVE CD) i have- Ubuntu 12.04 on 206 GB partition at dev/sda1. dev/sda2 system reserved. Windows 7 on 90GB partition at dev/sda3 and linux swap in extended partition. what i want to do- I want to install Linux mint KDE on my system for that i want to create a new partition of 30GB(by shrinking the free space available at dev/sda1), i can't create that because i can create only 4 Primary partitions which are already there. so do i have to delete the Swap partition? and if i did how to force Mint KDE and Ubuntu 12.04 to use/share same swap space in new logical partition?

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  • Linq, double left join and double count

    - by Fabian Vilers
    Hi! I'm looking to translate this SQL statement to a well working & performant LINQ command. I've managed to have the first count working using the grouping count and key members, but don't know how to get the second count. select main.title, count(details.id) as details, count(messages.id) as messages from main left outer join details on main.id = details.mainid left outer join messages on details.id = messages.detailid group by main.title Any advice is welcome! Fabian

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  • JPA : optimize EJB-QL query involving large many-to-many join table

    - by Fabien
    Hi all. I'm using Hibernate Entity Manager 3.4.0.GA with Spring 2.5.6 and MySql 5.1. I have a use case where an entity called Artifact has a reflexive many-to-many relation with itself, and the join table is quite large (1 million lines). As a result, the HQL query performed by one of the methods in my DAO takes a long time. Any advice on how to optimize this and still use HQL ? Or do I have no choice but to switch to a native SQL query that would perform a join between the table ARTIFACT and the join table ARTIFACT_DEPENDENCIES ? Here is the problematic query performed in the DAO : @SuppressWarnings("unchecked") public List<Artifact> findDependentArtifacts(Artifact artifact) { Query query = em.createQuery("select a from Artifact a where :artifact in elements(a.dependencies)"); query.setParameter("artifact", artifact); List<Artifact> list = query.getResultList(); return list; } And the code for the Artifact entity : package com.acme.dependencytool.persistence.model; import java.util.ArrayList; import java.util.List; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.UniqueConstraint; @Entity @Table(name = "ARTIFACT", uniqueConstraints={@UniqueConstraint(columnNames={"GROUP_ID", "ARTIFACT_ID", "VERSION"})}) public class Artifact { @Id @GeneratedValue @Column(name = "ID") private Long id = null; @Column(name = "GROUP_ID", length = 255, nullable = false) private String groupId; @Column(name = "ARTIFACT_ID", length = 255, nullable = false) private String artifactId; @Column(name = "VERSION", length = 255, nullable = false) private String version; @ManyToMany(cascade=CascadeType.ALL, fetch=FetchType.EAGER) @JoinTable( name="ARTIFACT_DEPENDENCIES", joinColumns = @JoinColumn(name="ARTIFACT_ID", referencedColumnName="ID"), inverseJoinColumns = @JoinColumn(name="DEPENDENCY_ID", referencedColumnName="ID") ) private List<Artifact> dependencies = new ArrayList<Artifact>(); public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getGroupId() { return groupId; } public void setGroupId(String groupId) { this.groupId = groupId; } public String getArtifactId() { return artifactId; } public void setArtifactId(String artifactId) { this.artifactId = artifactId; } public String getVersion() { return version; } public void setVersion(String version) { this.version = version; } public List<Artifact> getDependencies() { return dependencies; } public void setDependencies(List<Artifact> dependencies) { this.dependencies = dependencies; } } Thanks in advance. EDIT 1 : The DDLs are generated automatically by Hibernate EntityMananger based on the JPA annotations in the Artifact entity. I have no explicit control on the automaticaly-generated join table, and the JPA annotations don't let me explicitly set an index on a column of a table that does not correspond to an actual Entity (in the JPA sense). So I guess the indexing of table ARTIFACT_DEPENDENCIES is left to the DB, MySQL in my case, which apparently uses a composite index based on both clumns but doesn't index the column that is most relevant in my query (DEPENDENCY_ID). mysql describe ARTIFACT_DEPENDENCIES; +---------------+------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +---------------+------------+------+-----+---------+-------+ | ARTIFACT_ID | bigint(20) | NO | MUL | NULL | | | DEPENDENCY_ID | bigint(20) | NO | MUL | NULL | | +---------------+------------+------+-----+---------+-------+ EDIT 2 : When turning on showSql in the Hibernate session, I see many occurences of the same type of SQL query, as below : select dependenci0_.ARTIFACT_ID as ARTIFACT1_1_, dependenci0_.DEPENDENCY_ID as DEPENDENCY2_1_, artifact1_.ID as ID1_0_, artifact1_.ARTIFACT_ID as ARTIFACT2_1_0_, artifact1_.GROUP_ID as GROUP3_1_0_, artifact1_.VERSION as VERSION1_0_ from ARTIFACT_DEPENDENCIES dependenci0_ left outer join ARTIFACT artifact1_ on dependenci0_.DEPENDENCY_ID=artifact1_.ID where dependenci0_.ARTIFACT_ID=? Here's what EXPLAIN in MySql says about this type of query : mysql explain select dependenci0_.ARTIFACT_ID as ARTIFACT1_1_, dependenci0_.DEPENDENCY_ID as DEPENDENCY2_1_, artifact1_.ID as ID1_0_, artifact1_.ARTIFACT_ID as ARTIFACT2_1_0_, artifact1_.GROUP_ID as GROUP3_1_0_, artifact1_.VERSION as VERSION1_0_ from ARTIFACT_DEPENDENCIES dependenci0_ left outer join ARTIFACT artifact1_ on dependenci0_.DEPENDENCY_ID=artifact1_.ID where dependenci0_.ARTIFACT_ID=1; +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ | 1 | SIMPLE | dependenci0_ | ref | FKEA2DE763364D466 | FKEA2DE763364D466 | 8 | const | 159 | | | 1 | SIMPLE | artifact1_ | eq_ref | PRIMARY | PRIMARY | 8 | dependencytooldb.dependenci0_.DEPENDENCY_ID | 1 | | +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ EDIT 3 : I tried setting the FetchType to LAZY in the JoinTable annotation, but I then get the following exception : Hibernate: select artifact0_.ID as ID1_, artifact0_.ARTIFACT_ID as ARTIFACT2_1_, artifact0_.GROUP_ID as GROUP3_1_, artifact0_.VERSION as VERSION1_ from ARTIFACT artifact0_ where artifact0_.GROUP_ID=? and artifact0_.ARTIFACT_ID=? 51545 [btpool0-2] ERROR org.hibernate.LazyInitializationException - failed to lazily initialize a collection of role: com.acme.dependencytool.persistence.model.Artifact.dependencies, no session or session was closed org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.acme.dependencytool.persistence.model.Artifact.dependencies, no session or session was closed at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationException(AbstractPersistentCollection.java:380) at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationExceptionIfNotConnected(AbstractPersistentCollection.java:372) at org.hibernate.collection.AbstractPersistentCollection.readSize(AbstractPersistentCollection.java:119) at org.hibernate.collection.PersistentBag.size(PersistentBag.java:248) at com.acme.dependencytool.server.DependencyToolServiceImpl.createArtifactViewBean(DependencyToolServiceImpl.java:93) at com.acme.dependencytool.server.DependencyToolServiceImpl.createArtifactViewBean(DependencyToolServiceImpl.java:109) at com.acme.dependencytool.server.DependencyToolServiceImpl.search(DependencyToolServiceImpl.java:48) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:527) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:166) at com.google.gwt.user.server.rpc.RemoteServiceServlet.doPost(RemoteServiceServlet.java:86) at javax.servlet.http.HttpServlet.service(HttpServlet.java:637) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:729) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.handler.RequestLogHandler.handle(RequestLogHandler.java:49) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:647) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:205) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488)

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  • INNER JOIN syntax for mySQL using phpmyadmin

    - by David van Dugteren
    SELECT Question.userid, user.uid FROM `question` WHERE NOT `userid`=2 LIMIT 0, 60 INNER JOIN `user` ON `question`.userid=`user`.uid ORDER BY `question`.userid returns Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN User ON question.userid=user.uid ORDER BY question.userid' at line 5 Can't for the life of me figure out what I'm doing wrong here.

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  • self join- how to use the aggregate functions

    - by Ranjana
    self join- how to use the aggregate functions select a.tablename, b.TableName,b.UserName from Employee a inner join Employee b on a.ColumnValue=b.ColumnValue and and a.TableName <> b.TableName and a.UserName=b.UserName and also to check whether the same user has count of records i.e Employee a = count of records of Employee b. how to add count function over here

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