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  • GParted tells me my partition has 1.30 GiB used space but I cannot access its contents

    - by reprogrammer
    I've a ext4 partition (/dev/sda7) for my Linux. And, another (/dev/sda5) for keeping my data. When I installing Ubuntu 10.04 LTS, I set the mount point of /dev/sda5 to "/" and that of /dev/sda5 to "/data". GParted tells me that 1.30 GiB out of 70.12 GiB of /dev/sda5 has been used up. But, the mounted directory "/data" is empty. So, it looks like that my data is there but I cannot access it. Besides, when I set the mount point, I didn't check the "format" box. So, it shouldn't have been formatted. How can I check whether the partition has been formatted? How can I recover my files?

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  • fdisk -l only displays boot partition

    - by Franklin
    I have a SAN, and it's able to read and write to the 50TB RAID just fine, but when I run fdisk -l it only lists the boot partition of the SAN server, and doesn't display anything about the other partitions on the RAID. I've also tried using parted -l with the same result. Now when I type mount it shows that the partitions are mounted just fine. I've never seen this happen. The box is running Openfiler 2.3 (I know it's old, we're in the process of upgrading all our old equipment). We have another SAN that's configured almost identically, and it's able to display the partition info with either of the two commands I mentioned above.

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  • Booting from a different partition.

    - by Legolas
    I have a question. I run Windows7 on C:\ drive and it is the only operating system. I want to install Windows8 developer installation (iso image), and I have it saved in a new partition I created, which has only this.G:\ I want to boot from this partition G:\ so that I can install Windows 8, but in my boot options I get only Internal Hard Disk, CD ROM, and USB Drive. I don't have a USB drive. How can I boot from G:\ with that iso image ?

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  • Can I split one RAID1 partition in two?

    - by Prosys
    I have a linux box with CentOS 6.2 and a RAID1 (2x 2Tb) configuration: /dev/md1 -> / (10G) /dev/md2 -> /home (1.9T) I want to split the md2 in two different partitions, so I can get the following configuration: /dev/md1 -> / (10G) /dev/md2 -> /home (1T) /dev/md3 -> /example (900G) How can I achieve this? I already know that I can resize the partition, but that doesn't alter the real partition table (only the md device), so how can I do this?

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  • Permissions issue on Fedora with separate home partition

    - by Tres
    I am running Fedora 12 and I've setup a partition separate from my root partition to keep shared files and home directories. Now, I've been having permission issues where it says the user cannot chdir into their home directory (/files/home/*). Now, I fixed this originally by chmodding / to 0755 and the home directories also to 0755. And yes, the user is the owner:group of their home directory. Now get this, I didn't change a thing, rebooted, everything still works. Great, right? I boot the server up a day later, and now same ol issue. This is a home server that wasn't on at all at any point in between the working state and non-working state. Also, nothing else was modified. Any ideas? Thanks!

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  • "Undeleting" partition (NTFS) - recommendations?

    - by kagali-san
    So I have a drive which either suffered from hardware error or, possibly, got a little shock from badly configured Windows unattended install started on the same PC (the drive in question wasn't the install drive..). Quick exam shows that filesystem is seemingly intact, as some data recovery tools work with it (UnFormat rated it as "Excellent"). This may mean that a copy of partition table exists on disk, or a copy of MFT survived whatever happened, or.. Any idea how to restore partition tables/FS header, add a drive letter thus let Windows to mount the filesystem as if nothing happened? (I guess there must be tools of this kind)

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  • Ubuntu: Resize the root LVM(2?) partition

    - by user12259
    I have an Ubuntu virtual machine running in VirtualBox 2.2.4, and I created it on an 8gb virtual disk which is too small. So, I am trying to increase the size of the disk. So far, I have done this: Created a new larger virtual disk Added the 2nd disk to the machine Used CloneZilla to clone the first disk onto the 2nd disk Removed the first disk Booted up off the 2nd (larger disk) But now I'm still stuck with an 8gb partition on my new 100gb virtual disk. Whats the easiest path from here to having a 100gb partition? :) I gather GPart can resize partitions, but it doesn't seem to support LVM2 partitions, which mine seems to be. thx Alex

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • Inner Join with more than a field

    - by Leandro
    Precise to do a select with inner join that has relationship in more than a field among the tables Exemple: DataSet dt = new Select().From(SubConta.Schema) .InnerJoin(PlanoContabilSubConta.EmpSubContaColumn, SubConta.CodEmpColumn) .InnerJoin(PlanoContabilSubConta.FilSubContaColumn, SubConta.CodFilColumn) .InnerJoin(PlanoContabilSubConta.SubContaColumn, SubConta.TradutorColumn) .Where(PlanoContabilSubConta.Columns.EmpContabil).IsEqualTo(cEmp) .And(PlanoContabilSubConta.Columns.FilContabil).IsEqualTo(cFil) .And(PlanoContabilSubConta.Columns.Conta).IsEqualTo(cTrad) .ExecuteDataSet(); But the generated sql is wrong: exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao] FROM [dbo].[SubContas] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta] WHERE EmpContabil = @EmpContabil0 AND FilContabil = @FilContabil1 AND Conta = @Conta2 ',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1' What should be made to generate this sql? exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao] FROM [dbo].[SubContas] INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta] AND [dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta] AND [dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta] WHERE EmpContabil = @EmpContabil0 AND FilContabil = @FilContabil1 AND Conta = @Conta2 ',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1'

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  • Difference b/w putting condition in JOIN clause versus WHERE clause

    - by user244953
    Suppose I have 3 tables. Sales Rep Rep Code First Name Last Name Phone Email Sales Team Orders Order Number Rep Code Customer Number Order Date Order Status Customer Customer Number Name Address Phone Number I want to get a detailed report of Sales for 2010. I would be doing a join. I am interested in knowing which of the following is more efficient and why ? SELECT O.OrderNum, R.Name, C.Name FROM Order O INNER JOIN Rep R ON O.RepCode = R.RepCode INNER JOIN Customer C ON O.CustomerNumber = C.CustomerNumber WHERE O.OrderDate >= '01/01/2010' OR SELECT O.OrderNum, R.Name, C.Name FROM Order O INNER JOIN Rep R ON (O.RepCode = R.RepCode AND O.OrderDate >= '01/01/2010') INNER JOIN Customer C ON O.CustomerNumber = C.CustomerNumber

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  • C# LINQ: Join and Group

    - by Soo
    I have two tables TableA aId aValue TableB bId aId bValue I want to join these two tables via aId, and from there, group them by bValue var result = from a in db.TableA join b in db.TableB on a.aId equals b.aId group b by b.bValue into x select new {x}; My code doesn't recognize the join after the group. In other words, the grouping works, but the join doesn't (or at least I can't figure out how to access all of the data after the join). Any help would be appreciated. I'm a n00b.

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  • Left outer join null using VB.NET and LINQ

    - by jvcoach23
    I've got what I think is a working left outer join LINQ query, but I'm having problems with the select because of null values in the right hand side of the join. Here is what I have so far Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty I want to return all of e and one column from c called tClassCode. I was wondering what the syntax would be. As you can see, I'm using VB.NET. Update... Here is the query doing join where I get the error: _message = "Object reference not set to an instance of an object." Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty Select e, c.tClassCode If I remove the c.tClassCode from the select, the query runs without error. So I thought perhaps I needed to do a select new, but I don't think I was doing that correctly either.

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  • Left Join works with table but fails with query

    - by Frank Martin
    The following left join query in MS Access 2007 SELECT Table1.Field_A, Table1.Field_B, qry_Table2_Combined.Field_A, qry_Table2_Combined.Field_B, qry_Table2_Combined.Combined_Field FROM Table1 LEFT JOIN qry_Table2_Combined ON (Table1.Field_A = qry_Table2_Combined.Field_A) AND (Table1.Field_B = qry_Table2_Combined.Field_B); is expected by me to return this result: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |1 | | | | | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 | | | | +--------+---------+---------+---------+----------------+ [Table1] has 4 records, [qry_Table2_Combined] has 1 record. But it gives me this: +--------+---------+---------+---------+----------------+ |Field_A | Field_B | Field_A | Field_B | Combined_Field | +--------+---------+---------+---------+----------------+ |2 |1 |2 |1 |John, Doe | +--------+---------+---------+---------+----------------+ |2 |2 |2 | |, | +--------+---------+---------+---------+----------------+ Really weird is that the [Combined_Field] has a comma in the second row. I use a comma to concatenate two fields in [qry_Table2_Combined]. If the left join query uses a table created from the query [qry_Table2_Combined] it works as expected. Why does this left join query not give the same result for a query and a table? And how can i get the right results using a query in the left join?

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  • alias some columns names as one field in oracle's join select query

    - by Marecky
    Hi We are developing something like a social networking website. I've got task to do 'follow me' functionality. In our website objects are users, teams, companies, channels and groups (please don't ask why there are groups and teams - it is complicated for me too, but teams are releated to user's talent) Users, teams, channels, companies and groups have all their own tables. I have a query which gets me all the follower's leaders like this select --fo.leader_id, --fo.leader_type, us.name as user_name, co.name as company_name, ch.title as channel_name, gr.name as group_name, tt.name as team_name from follow_up fo left join users us on (fo.leader_id = us.id and fo.leader_type = 'user') left join companies co on (fo.leader_id = co.user_id and fo.leader_type = 'company') left join channels ch on (fo.leader_id = ch.id and fo.leader_type = 'channel') left join groups gr on (fo.leader_id = gr.id and fo.leader_type = 'group') left join talent_teams tt on (fo.leader_id = tt.id and fo.leader_type = 'team') where follower_id = 83 I need to get all fields like: user_name, company_name, channel_name, group_name, team_name as one field in SELECT's product. I have tried to alias them all the same 'name' but Oracle numbered it. Please help :)

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  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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  • Error 5 partition table invalid or corrupt

    - by Clodoaldo
    I'm trying to add a second SSD to a Centos 6 system. But I get the Error 5 partition table invalid or corrupt at boot. The system already has a single SSD (sdb) and a pair of HDDs (sd{a,c}) in a RAID 1 array from where it boots. It is as if the new SSD assumes one of the devices of the RAID array. Is it? How to avoid that or rearrange the setup? # cat fstab UUID=967b4035-782d-4c66-b22f-50244fe970ca / ext4 defaults 1 1 UUID=86fd06e9-cdc9-4166-ba9f-c237cfc43e02 /boot ext4 defaults 1 2 UUID=72552a7a-d8ae-4f0a-8917-b75a6239ce9f /ssd ext4 discard,relatime 1 2 UUID=8000e5e6-caa2-4765-94f8-9caeb2bda26e swap swap defaults 0 0 tmpfs /dev/shm tmpfs defaults 0 0 devpts /dev/pts devpts gid=5,mode=620 0 0 sysfs /sys sysfs defaults 0 0 proc /proc proc defaults 0 0 # ll /dev/disk/by-id/ total 0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:0 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:1 -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:2 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a04d7241:8da6023e:f9004352:107a923a -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a22c43b9:f1954990:d3ddda5e:f9aff3c9 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-f403a2d0:447803b5:66edba73:569f8305 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c500383621ff -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c5003838b2e7 -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5e83a97f592139d6 -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5e83a97f592139d6-part1 -> ../../sdb1 # fdisk -l Disk /dev/sdb: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x79298ec9 Device Boot Start End Blocks Id System /dev/sdb1 1 14594 117219328 83 Linux Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000d99de Device Boot Start End Blocks Id System /dev/sdc1 1 1275 10240000 fd Linux raid autodetect /dev/sdc2 * 1275 1339 512000 fd Linux raid autodetect /dev/sdc3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b3327 Device Boot Start End Blocks Id System /dev/sda1 1 1275 10240000 fd Linux raid autodetect /dev/sda2 * 1275 1339 512000 fd Linux raid autodetect /dev/sda3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/md0: 10.5 GB, 10484641792 bytes 2 heads, 4 sectors/track, 2559727 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Disk /dev/md2: 489.1 GB, 489095557120 bytes 2 heads, 4 sectors/track, 119408095 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/md1: 524 MB, 524275712 bytes 2 heads, 4 sectors/track, 127997 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table # cat /etc/grub.conf default=0 timeout=5 splashimage=(hd2,1)/grub/splash.xpm.gz hiddenmenu title CentOS (2.6.32-220.17.1.el6.x86_64) root (hd2,1) kernel /vmlinuz-2.6.32-220.17.1.el6.x86_64 ro root=UUID=967b4035-782d-4c66-b22f-50244fe970ca rd_MD_UUID=f403a2d0:447803b5:66edba73:569f8305 rd_MD_UUID=a22c43b9:f1954990:d3ddda5e:f9aff3c9 rd_NO_LUKS rd_NO_LVM rd_NO_DM LANG=en_US.UTF-8 SYSFONT=latarcyrheb-sun16 KEYBOARDTYPE=pc KEYTABLE=br-abnt2 crashkernel=auto rhgb quiet initrd /initramfs-2.6.32-220.17.1.el6.x86_64.img

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  • Error 22 no such partition on adding a SSD

    - by Clodoaldo
    I'm trying to add a second SSD to a Centos 6 system. But I get the error 22 no such partition at boot. The system already has a single SSD (sdb) and a pair of HDDs (sd{a,c}) in a RAID 1 array from where it boots. It is as if the new SSD assumes one of the devices of the RAID array. Is it? How to avoid that or rearrange the setup? # cat fstab UUID=967b4035-782d-4c66-b22f-50244fe970ca / ext4 defaults 1 1 UUID=86fd06e9-cdc9-4166-ba9f-c237cfc43e02 /boot ext4 defaults 1 2 UUID=72552a7a-d8ae-4f0a-8917-b75a6239ce9f /ssd ext4 discard,relatime 1 2 UUID=8000e5e6-caa2-4765-94f8-9caeb2bda26e swap swap defaults 0 0 tmpfs /dev/shm tmpfs defaults 0 0 devpts /dev/pts devpts gid=5,mode=620 0 0 sysfs /sys sysfs defaults 0 0 proc /proc proc defaults 0 0 # ll /dev/disk/by-id/ total 0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 ata-ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:0 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:1 -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-name-localhost.localdomain:2 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a04d7241:8da6023e:f9004352:107a923a -> ../../md1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-a22c43b9:f1954990:d3ddda5e:f9aff3c9 -> ../../md0 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 md-uuid-f403a2d0:447803b5:66edba73:569f8305 -> ../../md2 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_OCZ-VERTEX3_OCZ-43DSRFTNCLE9ZJXX-part1 -> ../../sdb1 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3 -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMT49E3-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 scsi-SATA_ST3500413AS_5VMTJNAJ-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c500383621ff -> ../../sdc lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part1 -> ../../sdc1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part2 -> ../../sdc2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c500383621ff-part3 -> ../../sdc3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5000c5003838b2e7 -> ../../sda lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part1 -> ../../sda1 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part2 -> ../../sda2 lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5000c5003838b2e7-part3 -> ../../sda3 lrwxrwxrwx. 1 root root 9 Jun 15 23:50 wwn-0x5e83a97f592139d6 -> ../../sdb lrwxrwxrwx. 1 root root 10 Jun 15 23:50 wwn-0x5e83a97f592139d6-part1 -> ../../sdb1 # fdisk -l Disk /dev/sdb: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x79298ec9 Device Boot Start End Blocks Id System /dev/sdb1 1 14594 117219328 83 Linux Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000d99de Device Boot Start End Blocks Id System /dev/sdc1 1 1275 10240000 fd Linux raid autodetect /dev/sdc2 * 1275 1339 512000 fd Linux raid autodetect /dev/sdc3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b3327 Device Boot Start End Blocks Id System /dev/sda1 1 1275 10240000 fd Linux raid autodetect /dev/sda2 * 1275 1339 512000 fd Linux raid autodetect /dev/sda3 1339 60802 477633536 fd Linux raid autodetect Disk /dev/md0: 10.5 GB, 10484641792 bytes 2 heads, 4 sectors/track, 2559727 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Disk /dev/md2: 489.1 GB, 489095557120 bytes 2 heads, 4 sectors/track, 119408095 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md2 doesn't contain a valid partition table Disk /dev/md1: 524 MB, 524275712 bytes 2 heads, 4 sectors/track, 127997 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/md1 doesn't contain a valid partition table # cat /etc/grub.conf default=0 timeout=5 splashimage=(hd2,1)/grub/splash.xpm.gz hiddenmenu title CentOS (2.6.32-220.17.1.el6.x86_64) root (hd2,1) kernel /vmlinuz-2.6.32-220.17.1.el6.x86_64 ro root=UUID=967b4035-782d-4c66-b22f-50244fe970ca rd_MD_UUID=f403a2d0:447803b5:66edba73:569f8305 rd_MD_UUID=a22c43b9:f1954990:d3ddda5e:f9aff3c9 rd_NO_LUKS rd_NO_LVM rd_NO_DM LANG=en_US.UTF-8 SYSFONT=latarcyrheb-sun16 KEYBOARDTYPE=pc KEYTABLE=br-abnt2 crashkernel=auto rhgb quiet initrd /initramfs-2.6.32-220.17.1.el6.x86_64.img

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  • Excessive use of Inner Join for more than 3 tables

    - by Archangel08
    Good Day, I have 4 tables on my DB (not the actual name but almost similar) which are the ff: employee,education,employment_history,referrence employee_id is the name of the foreign key from employee table. Here's the example (not actual) data: **Employee** ID Name Birthday Gender Email 1 John Smith 08-15-2014 Male [email protected] 2 Jane Doe 00-00-0000 Female [email protected] 3 John Doe 00-00-0000 Male [email protected] **Education** Employee_ID Primary Secondary Vocation 1 Westside School Westshore H.S SouthernBay College 2 Eastside School Eastshore H.S NorthernBay College 3 Northern School SouthernShore H.S WesternBay College **Employment_History** Employee_ID WorkOne StartDate Enddate 1 StarBean Cafe 12-31-2012 01-01-2013 2 Coffebucks Cafe 11-01-2012 11-02-2012 3 Latte Cafe 01-02-2013 04-05-2013 Referrence Employee_ID ReferrenceOne Address Contact 1 Abraham Lincoln Lincoln Memorial 0000000000 2 Frankie N. Stein Thunder St. 0000000000 3 Peter D. Pan Neverland Ave. 0000000000 NOTE: I've only included few columns though the rest are part of the query. And below are the codes I've been working on for 3 consecutive days: $sql=mysql_query("SELECT emp.id,emp.name,emp.birthday,emp.pob,emp.gender,emp.civil,emp.email,emp.contact,emp.address,emp.paddress,emp.citizenship,educ.employee_id,educ.elementary,educ.egrad,educ.highschool,educ.hgrad,educ.vocational,educ.vgrad,ems.employee_id,ems.workOne,ems.estartDate,ems.eendDate,ems.workTwo,ems.wstartDate,ems.wendDate,ems.workThree,ems.hstartDate,ems.hendDate FROM employee AS emp INNER JOIN education AS educ ON educ.employee_id='emp.id' INNER JOIN employment_history AS ems ON ems.employee_id='emp.id' INNER JOIN referrence AS ref ON ref.employee_id='emp.id' WHERE emp.id='$id'"); Is it okay to use INNER JOIN this way? Or should I modify my query to get the results that I wanted? I've also tried to use LEFT JOIN but still it doesn't return anything .I didn't know where did I go wrong. You see, as I have thought, I've been using the INNER JOIN in correct manner, (since it was placed before the WHILE CLAUSE). So I couldn't think of what could've possible went wrong. Do you guys have a suggestion? Thanks in advance.

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  • Re-sizing disk partition linux/vm

    - by Tiffany Walker
    I VM Player running a linux guest and I was wanting to know how do I expand the disk? In the VM player I gave more disk space but I am not sure how to mount/expand/connect the new disk space to the system. My old disk space was 14GB [root@localhost ~]# df -h / Filesystem Size Used Avail Use% Mounted on /dev/mapper/VolGroup-lv_root 14G 4.5G 8.2G 36% / Then I expanded it and now I see sda2 which is the new space? [root@localhost ~]# fdisk -l Disk /dev/sda: 128.8 GB, 128849018880 bytes 255 heads, 63 sectors/track, 15665 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000cd44d Device Boot Start End Blocks Id System /dev/sda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/sda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/VolGroup-lv_root: 14.5 GB, 14537457664 bytes 255 heads, 63 sectors/track, 1767 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/VolGroup-lv_swap: 6408 MB, 6408896512 bytes 255 heads, 63 sectors/track, 779 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Do I need to mount the new space first? resize2fs -p /dev/mapper/VolGroup-lv_root 108849018880 resize2fs 1.41.12 (17-May-2010) The containing partition (or device) is only 3549184 (4k) blocks. You requested a new size of 1474836480 blocks. resize2fs -p /dev/mapper/VolGroup-lv_root 128849018880 resize2fs 1.41.12 (17-May-2010) resize2fs: Invalid new size: 128849018880 [root@localhost ~]# lvextend -L+90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 103.54 GiB Insufficient free space: 23040 extents needed, but only 0 available [root@localhost ~]# lvextend -L90GB /dev/mapper/VolGroup-lv_root Extending logical volume lv_root to 90.00 GiB Insufficient free space: 19574 extents needed, but only 0 available EDIT: So after trying pvcreate/vgextend nothing has so far worked. I'm guessing the new disk space added from VM Player is not showing up? pvscan PV /dev/sda2 VG VolGroup lvm2 [19.51 GiB / 0 free] Total: 1 [19.51 GiB] / in use: 1 [19.51 GiB] / in no VG: 0 [0 ]

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  • disk partition centos

    - by FlourishDNA
    I am setting up server for hosting two WordPress which has size of around 70GB. I have already installed CentOS as OS and I would like to partition the Disk. Is there any tool which can help me or can someone guide me though the process as I am not expert is SSH commands. Here are some output that might help. OS: CentOS release 6.3 fdisk -l Disk /dev/xvdb: 214.7 GB, 214748364800 bytes 255 heads, 63 sectors/track, 26108 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000b91e0 Device Boot Start End Blocks Id System Disk /dev/xvda: 21.5 GB, 21474836480 bytes 255 heads, 63 sectors/track, 2610 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000e542c Device Boot Start End Blocks Id System /dev/xvda1 * 1 64 512000 83 Linux Partition 1 does not end on cylinder boundary. /dev/xvda2 64 2611 20458496 8e Linux LVM Disk /dev/mapper/vg_flourish-lv_root: 16.7 GB, 16718495744 bytes 255 heads, 63 sectors/track, 2032 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/mapper/vg_flourish-lv_swap: 4227 MB, 4227858432 bytes 255 heads, 63 sectors/track, 514 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 df Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/vg_flourish-lv_root 16070076 758184 14495560 5% / tmpfs 958500 0 958500 0% /dev/shm /dev/xvda1 495844 31926 438318 7% /boot df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/vg_flourish-lv_root 16G 741M 14G 5% / tmpfs 937M 0 937M 0% /dev/shm /dev/xvda1 485M 32M 429M 7% /boot Thanks

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  • How can I get Snow Leopard to recognize my third partition?

    - by qntmfred
    I installed Snow Leopard on my Macbook Pro. I then installed Windows 7 in a Boot Camp partition. Then using Windows 7's disk management console, I resized my Windows 7partition and created a 3rd NTFS partition for data, intending for both Windows 7 and Snow Leopard to read/write this partition. I installed MacFuse and NTFS-3G in Snow Leopard, but Snow Leopard still shows I have a single Windows 7 partition. How can I get Snow Leopard to recognize my third partition?

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  • Tools to partition dynamic disk

    - by rangalo
    Hi, I have a 1 TB hard-disk with windows 7 pre-installed. I would like to delete, resize some partition and create ext3/swap partitions to install linux. Which tools are available for this ? I tried gparted, it doesn't work.

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