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  • Back up a single table in SQL Server

    - by BuckWoody
    SQL Server doesn’t have an easy way to take a table backup, so I often use the bcp (Bulk Copy Program) to accomplish the same goal. I’ve mentioned this before, and someone told me when they tried it they couldn’t restore the table – ah the dangers of telling people half the information! I should have mentioned that you need to have a “format file” ready if the table does not exist at the destination. In my case I already had the table, in this person’s case they did not. The format file can be used to rebuild that table structure before the data is bcp’d in, and you can read more about it here: http://msdn.microsoft.com/en-us/library/ms191516.aspx There’s another way to back up a table, and that’s to create a Filegroup and place the table there. Then you can take a Filegroup backup to back up a single table. Of course, there are other methods of moving a single table’s data in an out, including SQL Server Integration Services and even the older Data Transformation Services, or simply by using hte SQLCMD or PowerShell utilities to run a query and just save the output to a file. In fact, these days I’m using a PowerShell script to build INSERT statements from that query. That could also easily be modified to create the table structure (or modify one if needed) quite easily. Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • Adding Column to a SQL Server Table

    - by Dinesh Asanka
    Adding a column to a table is  common task for  DBAs. You can add a column to a table which is a nullable column or which has default values. But are these two operations are similar internally and which method is optimal? Let us start this with an example. I created a database and a table using following script: USE master Go --Drop Database if exists IF EXISTS (SELECT 1 FROM SYS.databases WHERE name = 'AddColumn') DROP DATABASE AddColumn --Create the database CREATE DATABASE AddColumn GO USE AddColumn GO --Drop the table if exists IF EXISTS ( SELECT 1 FROM sys.tables WHERE Name = 'ExistingTable') DROP TABLE ExistingTable GO --Create the table CREATE TABLE ExistingTable (ID BIGINT IDENTITY(1,1) PRIMARY KEY CLUSTERED, DateTime1 DATETIME DEFAULT GETDATE(), DateTime2 DATETIME DEFAULT GETDATE(), DateTime3 DATETIME DEFAULT GETDATE(), DateTime4 DATETIME DEFAULT GETDATE(), Gendar CHAR(1) DEFAULT 'M', STATUS1 CHAR(1) DEFAULT 'Y' ) GO -- Insert 100,000 records with defaults records INSERT INTO ExistingTable DEFAULT VALUES GO 100000 Before adding a Column Before adding a column let us look at some of the details of the database. DBCC IND (AddColumn,ExistingTable,1) By running the above query, you will see 637 pages for the created table. Adding a Column You can add a column to the table with following statement. ALTER TABLE ExistingTable Add NewColumn INT NULL Above will add a column with a null value for the existing records. Alternatively you could add a column with default values. ALTER TABLE ExistingTable Add NewColumn INT NOT NULL DEFAULT 1 The above statement will add a column with a 1 value to the existing records. In the below table I measured the performance difference between above two statements. Parameter Nullable Column Default Value CPU 31 702 Duration 129 ms 6653 ms Reads 38 116,397 Writes 6 1329 Row Count 0 100000 If you look at the RowCount parameter, you can clearly see the difference. Though column is added in the first case, none of the rows are affected while in the second case all the rows are updated. That is the reason, why it has taken more duration and CPU to add column with Default value. We can verify this by several methods. Number of Pages The number of data pages can be obtained by using DBCC IND command. Though, this an undocumented dbcc command, many experts are ok to use this command in production. However, since there is no official word from Microsoft, use this “at your own risk”. DBCC IND (AddColumn,ExistingTable,1) Before Adding the Columns 637 Adding a Column with NULL 637 Adding a column with DEFAULT value 1270 This clearly shows that pages are physically modified. Please note, a high value indicated in the Adding a column with DEFAULT value  column is also a result of page splits. Continues…

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  • How-to populate different select list content per table row

    - by frank.nimphius
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} A frequent requirement posted on the OTN forum is to render cells of a table column using instances of af:selectOneChoices with each af:selectOneChoice instance showing different list values. To implement this use case, the select list of the table column is populated dynamically from a managed bean for each row. The table's current rendered row object is accessible in the managed bean using the #{row} expression, where "row" is the value added to the table's var property. <af:table var="row">   ...   <af:column ...>     <af:selectOneChoice ...>         <f:selectItems value="#{browseBean.items}"/>     </af:selectOneChoice>   </af:column </af:table> The browseBean managed bean referenced in the code snippet above has a setItems and getItems method defined that is accessible from EL using the #{browseBean.items} expression. When the table renders, then the var property variable - the #{row} reference - is filled with the data object displayed in the current rendered table row. The managed bean getItems method returns a List<SelectItem>, which is the model format expected by the f:selectItems tag to populate the af:selectOneChoice list. public void setItems(ArrayList<SelectItem> items) {} //this method is executed for each table row public ArrayList<SelectItem> getItems() {   FacesContext fctx = FacesContext.getCurrentInstance();   ELContext elctx = fctx.getELContext();   ExpressionFactory efactory =          fctx.getApplication().getExpressionFactory();          ValueExpression ve =          efactory.createValueExpression(elctx, "#{row}", Object.class);      Row rw = (Row) ve.getValue(elctx);         //use one of the row attributes to determine which list to query and   //show in the current af:selectOneChoice list  // ...  ArrayList<SelectItem> alsi = new ArrayList<SelectItem>();  for( ... ){      SelectItem item = new SelectItem();        item.setLabel(...);        item.setValue(...);        alsi.add(item);   }   return alsi;} For better performance, the ADF Faces table stamps it data rows. Stamping means that the cell renderer component - af:selectOneChoice in this example - is instantiated once for the column and then repeatedly used to display the cell data for individual table rows. This however means that you cannot refresh a single select one choice component in a table to change its list values. Instead the whole table needs to be refreshed, rerunning the managed bean list query. Be aware that having individual list values per table row is an expensive operation that should be used only on small tables for Business Services with low latency data fetching (e.g. ADF Business Components and EJB) and with server side caching strategies for the queried data (e.g. storing queried list data in a managed bean in session scope).

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  • Partition Table and Exadata Hybrid Columnar Compression (EHCC)

    - by Bandari Huang
    Create EHCC table CREATE TABLE ... COMPRESS FOR [QUERY LOW|QUERY HIGH|ARCHIVE LOW|ARCHIVE HIGH]; select owner,table_name,compress_for DBA_TAB_SUBPARTITIONS where compression = ‘ENABLED'; Convert Table/Partition/Subpartition to EHCC Compress Table&Partition&Subpartition to EHCC: ALTER TABLE table_name MOVE COMPRESS FOR [QUERY LOW|QUERY HIGH|ARCHIVE LOW|ARCHIVE HIGH] [PARALLEL <dop>]; ALTER TABLE table_name MOVE PARATITION partition_name COMPRESS FOR [QUERY LOW|QUERY HIGH|ARCHIVE LOW|ARCHIVE HIGH] [PARALLEL <dop>]; ALTER TABLE table_name MOVE SUBPARATITION subpartition_name COMPRESS FOR [QUERY LOW|QUERY HIGH|ARCHIVE LOW|ARCHIVE HIGH] [PARALLEL <dop>]; select owner,table_name,compress_for DBA_TAB_SUBPARTITIONS where compression = ‘ENABLED'; select table_owner,table_name,partition_name,compress_for DBA_TAB_PARTITIONS where compression = ‘ENABLED’; select table_owner,table_name,subpartition_name,compress_for DBA_TAB_SUBPARTITIONS where compression = ‘ENABLED’; Rebuild Unusable Index: select index_name from dba_index where status = 'UNUSABLE'; select index_name,partition_name from dba_ind_partition where status = 'UNUSABLE'; select index_name,subpartition_name from dba_ind_partition where status = 'UNUSABLE'; ALTER INDEX index_name REBUILD [PARALLEL <dop>]; ALTER INDEX index_name REBUILD PARTITION partition_name [PARALLEL <dop>]; ALTER INDEX index_name REBUILD SUBPARTITION subpartition_name [PARALLEL <dop>]; Convert Table/Partition/Subpartition from EHCC to OLTP compression or uncompressed format: Uncompress EHCC Table&Partition&Subpartition: ALTER TABLE table_name MOVE [NOCOMPRESS|COMPRESS for OLTP] [PARALLEL <dop>]; ALTER TABLE table_name MOVE PARTITION partition_name [NOCOMPRESS|COMPRESS for OLTP] [PARALLEL <dop>]; ALTER TABLE table_name MOVE SUBPARTITION subpartition_name [NOCOMPRESS|COMPRESS for OLTP] [PARALLEL <dop>]; select owner,table_name,compress_for DBA_TAB_SUBPARTITIONS where compression = ''; select table_owner,table_name,partition_name,compress_for DBA_TAB_PARTITIONS where compression = ''; select table_owner,table_name,subpartition_name,compress_for DBA_TAB_SUBPARTITIONS where compression = ''; Rebuild Unusable Index: select index_name from dba_index where status = 'UNUSABLE'; select index_name,partition_name from dba_ind_partition where status = 'UNUSABLE'; select index_name,subpartition_name from dba_ind_partition where status = 'UNUSABLE'; ALTER INDEX index_name REBUILD [PARALLEL <dop>]; ALTER INDEX index_name REBUILD PARTITION partition_name [PARALLEL <dop>]; ALTER INDEX index_name REBUILD SUBPARTITION subpartition_name [PARALLEL <dop>];

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  • Demantra Partitioning and the First PK Column

    - by user702295
      We have found that it is necessary in Demantra to have an index that matches the partition key, although it does not have to be the PK.  It is ok   to create a new index instead of changing the PK.   For example, if my PK on SALES_DATA is (ITEM_ID, LOCATION_ID, SALES_DATE) and I decide partition by SALES_DATE, then I should add an index starting   with the partition key like this: (SALES_DATE, ITEM_ID, LOCATION_ID).   * Note that the first column of the new index matches the partition key.   It might also be helpful to create a 2nd index with the other PK columns reversed (SALES_DATE, LOCATION_ID, ITEM_ID). Again, the first column   matches the partition key.

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  • DB Schema for ACL involving 3 subdomains

    - by blacktie24
    Hi, I am trying to design a database schema for a web app which has 3 subdomains: a) internal employees b) clients c) contractors. The users will be able to communicate with each other to some degree, and there may be some resources that overlap between them. Any thoughts about this schema? Really appreciate your time and thoughts on this. Cheers! -- -- Table structure for table locations CREATE TABLE IF NOT EXISTS locations ( id bigint(20) NOT NULL, name varchar(250) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Table structure for table privileges CREATE TABLE IF NOT EXISTS privileges ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(255) NOT NULL, resource_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=10 ; -- -- Table structure for table resources CREATE TABLE IF NOT EXISTS resources ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(255) NOT NULL, user_type enum('internal','client','expert') NOT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Table structure for table roles CREATE TABLE IF NOT EXISTS roles ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(255) NOT NULL, type enum('position','department') NOT NULL, parent_id int(11) DEFAULT NULL, user_type enum('internal','client','expert') NOT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Table structure for table role_perms CREATE TABLE IF NOT EXISTS role_perms ( id int(11) NOT NULL AUTO_INCREMENT, role_id int(11) NOT NULL, privilege_id int(11) NOT NULL, mode varchar(250) NOT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Table structure for table users CREATE TABLE IF NOT EXISTS users ( id int(10) unsigned NOT NULL AUTO_INCREMENT, email varchar(255) NOT NULL, password varchar(255) NOT NULL, salt varchar(255) NOT NULL, type enum('internal','client','expert') NOT NULL, first_name varchar(255) NOT NULL, last_name varchar(255) NOT NULL, location_id int(11) NOT NULL, phone varchar(255) NOT NULL, status enum('active','inactive') NOT NULL DEFAULT 'active', PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ; -- -- Table structure for table user_perms CREATE TABLE IF NOT EXISTS user_perms ( id int(11) NOT NULL AUTO_INCREMENT, user_id int(11) NOT NULL, privilege_id int(11) NOT NULL, mode varchar(250) NOT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Table structure for table user_roles CREATE TABLE IF NOT EXISTS user_roles ( id int(11) NOT NULL, user_id int(11) NOT NULL, role_id int(11) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1;

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  • Iterating selected rows in an ADF Faces table

    - by Frank Nimphius
    In OTN Harvest May 2012; http://www.oracle.com/technetwork/developer-tools/adf/learnmore/may2012-otn-harvest-1652358.pdf I wrote about "Common mistake when iterating <af:table> rows". In this entry I showed code to access the row associated with a selected table row from the binding layer to avoid the problem of having to programmatically change the selected table row. As it turns out, my solution only worked fro selected table rows that are in the current iterator query range. So here's a solution that works for all ranges public String onButtonPress() { RowKeySet rks = table.getSelectedRowKeys(); Iterator it = rks.iterator(); while (it.hasNext()) { List selectedRowKeyPath = (List)it.next(); //table is the JSF component reference created using the table's binding //property Row row = ((JUCtrlHierNodeBinding)table.getRowData(selectedRowKeyPath)).getRow(); System.out.println("Print Test: " + row.getAttribute(1)); } return null; }

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  • Partitioning with preseed help

    - by kostasp
    I have a server that has 4 hds inside all in stadalone configurations (no hardware raid). I want using preseed to create a "regular" partition on disk1 on which i ll install ubuntu and create a raid 0 array with the remainning three disks. Is this possible? Can i use partman-auto/method twice inside the preseed file once for regular and once for raid? I need to use this for unattended provisioning so i need to set my disks inside the preseed file. Thanking you all in advance for your time. Costas

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  • /dev/sda2 contains a filesystem with error after partitioning

    - by Private
    I just wanted to create a separate home partition on my Ubuntu 12.10 system. I booted the liveDVD, resized the sda2 partition (28gb of data resized to 30gb based on MiB [originally on a 100gb partition]) and made a new ext4 partition for the home folder. The drive is an SSD drive. I had changed the settings (noatime etc.) for SSD succesfully a week ago. On reboot I get the following error: /dev/sda2 contains a filesystem with errors Inode 74669 has an invalid extent node (blk 6881289) fsd / [953] terminated with status 4 What would you suggest me to do? If I can avoid a clean install that would save me a lot of time (I had just done all the config). I was following this HOWTO, but I did not get to changing any of the files or configs other than those with gparted. I have a (two-week old) SSD Samsung drive which is functioning just fine (other specs see bottom of this question). Other specs: 64bit 12.10, i7, 8gb ram, nvidia.

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  • partitioning ssd +hdd

    - by ALdaperan
    I recently bought an ssd drive 128 gb and i would like yo have your suggestions on partitiong and installing ubuntu 12.10 on it. First of all my drives are : HDD 640 Gb SSD Samsung 830 series 128 Gb Whats the best partitiong for theese drives ? 128 Gb is sure enormous amount of space only for / (root) . Is it a good choice if i make 2 partitions on ssd (20 Gb / and 100 /home) and leave hdd as backub drive for my data (files,movies,music etc) ? In this case what mount point must have hdd ? Can you suggest me the best partitiong for my drives ?

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  • Partitioning set into subsets with respect to equality of sum among subsets

    - by Al.Net
    let say i have {3, 1, 1, 2, 2, 1,5,2,7} set of numbers, I need to split the numbers such that sum of subset1 should be equal to sum of subset2 {3,2,7} {1,1,2,1,5,2}. First we should identify whether we can split number(one way might be dividable by 2 without any remainder) and if we can, we should write our algorithm two create s1 and s2 out of s. How to proceed with this approach? I read partition problem in wiki and even in some articles but i am not able to get anything. Can someone help me to find the right algorithm and its explanation in simple English?

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  • Ubuntu Server Configuration -- Harddrive Partitioning

    - by black_bird
    Currently Ubuntu Server is telling me that when I'm making a new partition for Ubuntu Server on this NTFS 1TB HD that I currently have installed to the hardware, that the partition must be a minimum of 52% of the hard drive space or ~521GB. I'm almost positive that this will run into other data, as I have quite a bit of stuff on the hard drive currently. Can I not make a Ubuntu server partition on that hard drive at like 100GB or something? Why does it require so much?

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  • Archiving SQL Server Data Using Partitioning

    Many companies now have a requirement to keep data for long periods of time. While this data does have to be available if requested, it usually does not need to be accessible by the application for any current transactions. Data that falls into this category are a good candidate for archival. Is your SQL Database under Version Control?SSMS plug-in SQL Source Control connects SVN, TFS, Git, Hg and all others to SQL Server. Learn more.

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  • SQL Azure Federation – Partitioning

    - by simonsabin
    There has been so much news coming out of MS lately and one that does seem to have gone by with very little noise is Federation in SQL Azure http://player.microsoftpdc.com/Session/591d586f-3732-4bff-8ee2-857f27d74df4 This is a fascinating feature that enables you to spread a database across multiple nodes. Sharding is another term for this and is one of the main reasons people like the NOSQL movement. It will be fascinating to see whether this federation will start to appear in the main SQL Server...(read more)

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  • Html table to csv table with image

    - by Joseph
    How to export this html table in to CSV example table: i want this table to be exported to csv .so how to achieve using JQUERY? <html> <body bgcolor="cyan"> <table border="1" align="center" > <br><a href="imp2.csv">Click Here To View In CSV format</a><img src="up.jpg" align="middle" width="39" height="32" /> <tr> <th>ID</th> <th>Name</th> <th>Month</th> <th>Savings</th> </tr> </table> </body> </html> Thanks Joseph

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  • SQL join to grab data from same table via intermediate table

    - by Sergio
    Hi Could someone help me with building the following query. I have a table called Sites, and one called Site_H. The two are joined by a foreign key relationship on page_id. So the Sites table contains pages, and the Site_H table shows which pages any given page is a child of by having another foreign key relation back to the site table with a column called ParentOf. So, a page can be have another page as a parent. Other data is stored in the Site_H table such as position etc, hence why it is separated out. I would like a query that returns the details of a page along with the details of its parent page. I just cant quite think about how to structure the SQL. Thanks

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  • Keep local MS SQL 2008 DB table and remote SQL Azure DB table in sync

    - by Boomerangertanger
    Hi there, I have a dedicated server which hosts a Windows Service which does a lot of very heavy load stuff and populates a number of SQL Server database tables. However, of all the database tables it populates and works with, I want only one to be synchronised with a remote SQL Azure DB table. This is because this table holds what I called Resolved data, which is the end result of the Windows Service's work. I would like to keep a SQL Azure database table in sync with this database table. As far as I understand, my options are: Move everything onto Azure (but that involves a massive development overhead and risk) Have another Windows Service on the dedicated server which essentially looks at changed records since the last update and then manually update the SQL Azure table

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  • Get latest record from second table left joined to first table

    - by codef0rmer
    I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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  • Replace data in MySQL table with data from another table

    - by Oli
    I am trying to modify an existing MySQL database for use in a new application. I have a table of items (table_items), which has multiple fields, including "ItemID" and "ItemName". I have another table (table_list) which has "ItemName" in it, but no ItemID. I need to either update this table to contain ItemID instead of ItemName, or create a new table which imports ItemIDs from table_items as opposed to the ItemName when table_list.ItemName = table_items.ItemName. I have tried the following: UPDATE table_list A, table_items B SET A.ItemName = B.ItemID WHERE A.ItemName = B.ItemName The current table has over 500,000 rows and every time i try this in PHPMyAdmin i get the error "the MySQl server has gone away". Any help greatly appreciated.

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  • SQL Azure table size

    - by user224564
    In mssql2005 when i want to get size of table in MBs, i use EXEC sp_spaceused 'table'. Is there any way to get space used by particular table in SQL Azure using some query or API?

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  • JPA : optimize EJB-QL query involving large many-to-many join table

    - by Fabien
    Hi all. I'm using Hibernate Entity Manager 3.4.0.GA with Spring 2.5.6 and MySql 5.1. I have a use case where an entity called Artifact has a reflexive many-to-many relation with itself, and the join table is quite large (1 million lines). As a result, the HQL query performed by one of the methods in my DAO takes a long time. Any advice on how to optimize this and still use HQL ? Or do I have no choice but to switch to a native SQL query that would perform a join between the table ARTIFACT and the join table ARTIFACT_DEPENDENCIES ? Here is the problematic query performed in the DAO : @SuppressWarnings("unchecked") public List<Artifact> findDependentArtifacts(Artifact artifact) { Query query = em.createQuery("select a from Artifact a where :artifact in elements(a.dependencies)"); query.setParameter("artifact", artifact); List<Artifact> list = query.getResultList(); return list; } And the code for the Artifact entity : package com.acme.dependencytool.persistence.model; import java.util.ArrayList; import java.util.List; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.UniqueConstraint; @Entity @Table(name = "ARTIFACT", uniqueConstraints={@UniqueConstraint(columnNames={"GROUP_ID", "ARTIFACT_ID", "VERSION"})}) public class Artifact { @Id @GeneratedValue @Column(name = "ID") private Long id = null; @Column(name = "GROUP_ID", length = 255, nullable = false) private String groupId; @Column(name = "ARTIFACT_ID", length = 255, nullable = false) private String artifactId; @Column(name = "VERSION", length = 255, nullable = false) private String version; @ManyToMany(cascade=CascadeType.ALL, fetch=FetchType.EAGER) @JoinTable( name="ARTIFACT_DEPENDENCIES", joinColumns = @JoinColumn(name="ARTIFACT_ID", referencedColumnName="ID"), inverseJoinColumns = @JoinColumn(name="DEPENDENCY_ID", referencedColumnName="ID") ) private List<Artifact> dependencies = new ArrayList<Artifact>(); public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getGroupId() { return groupId; } public void setGroupId(String groupId) { this.groupId = groupId; } public String getArtifactId() { return artifactId; } public void setArtifactId(String artifactId) { this.artifactId = artifactId; } public String getVersion() { return version; } public void setVersion(String version) { this.version = version; } public List<Artifact> getDependencies() { return dependencies; } public void setDependencies(List<Artifact> dependencies) { this.dependencies = dependencies; } } Thanks in advance. EDIT 1 : The DDLs are generated automatically by Hibernate EntityMananger based on the JPA annotations in the Artifact entity. I have no explicit control on the automaticaly-generated join table, and the JPA annotations don't let me explicitly set an index on a column of a table that does not correspond to an actual Entity (in the JPA sense). So I guess the indexing of table ARTIFACT_DEPENDENCIES is left to the DB, MySQL in my case, which apparently uses a composite index based on both clumns but doesn't index the column that is most relevant in my query (DEPENDENCY_ID). mysql describe ARTIFACT_DEPENDENCIES; +---------------+------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +---------------+------------+------+-----+---------+-------+ | ARTIFACT_ID | bigint(20) | NO | MUL | NULL | | | DEPENDENCY_ID | bigint(20) | NO | MUL | NULL | | +---------------+------------+------+-----+---------+-------+ EDIT 2 : When turning on showSql in the Hibernate session, I see many occurences of the same type of SQL query, as below : select dependenci0_.ARTIFACT_ID as ARTIFACT1_1_, dependenci0_.DEPENDENCY_ID as DEPENDENCY2_1_, artifact1_.ID as ID1_0_, artifact1_.ARTIFACT_ID as ARTIFACT2_1_0_, artifact1_.GROUP_ID as GROUP3_1_0_, artifact1_.VERSION as VERSION1_0_ from ARTIFACT_DEPENDENCIES dependenci0_ left outer join ARTIFACT artifact1_ on dependenci0_.DEPENDENCY_ID=artifact1_.ID where dependenci0_.ARTIFACT_ID=? Here's what EXPLAIN in MySql says about this type of query : mysql explain select dependenci0_.ARTIFACT_ID as ARTIFACT1_1_, dependenci0_.DEPENDENCY_ID as DEPENDENCY2_1_, artifact1_.ID as ID1_0_, artifact1_.ARTIFACT_ID as ARTIFACT2_1_0_, artifact1_.GROUP_ID as GROUP3_1_0_, artifact1_.VERSION as VERSION1_0_ from ARTIFACT_DEPENDENCIES dependenci0_ left outer join ARTIFACT artifact1_ on dependenci0_.DEPENDENCY_ID=artifact1_.ID where dependenci0_.ARTIFACT_ID=1; +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ | 1 | SIMPLE | dependenci0_ | ref | FKEA2DE763364D466 | FKEA2DE763364D466 | 8 | const | 159 | | | 1 | SIMPLE | artifact1_ | eq_ref | PRIMARY | PRIMARY | 8 | dependencytooldb.dependenci0_.DEPENDENCY_ID | 1 | | +----+-------------+--------------+--------+-------------------+-------------------+---------+---------------------------------------------+------+-------+ EDIT 3 : I tried setting the FetchType to LAZY in the JoinTable annotation, but I then get the following exception : Hibernate: select artifact0_.ID as ID1_, artifact0_.ARTIFACT_ID as ARTIFACT2_1_, artifact0_.GROUP_ID as GROUP3_1_, artifact0_.VERSION as VERSION1_ from ARTIFACT artifact0_ where artifact0_.GROUP_ID=? and artifact0_.ARTIFACT_ID=? 51545 [btpool0-2] ERROR org.hibernate.LazyInitializationException - failed to lazily initialize a collection of role: com.acme.dependencytool.persistence.model.Artifact.dependencies, no session or session was closed org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.acme.dependencytool.persistence.model.Artifact.dependencies, no session or session was closed at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationException(AbstractPersistentCollection.java:380) at org.hibernate.collection.AbstractPersistentCollection.throwLazyInitializationExceptionIfNotConnected(AbstractPersistentCollection.java:372) at org.hibernate.collection.AbstractPersistentCollection.readSize(AbstractPersistentCollection.java:119) at org.hibernate.collection.PersistentBag.size(PersistentBag.java:248) at com.acme.dependencytool.server.DependencyToolServiceImpl.createArtifactViewBean(DependencyToolServiceImpl.java:93) at com.acme.dependencytool.server.DependencyToolServiceImpl.createArtifactViewBean(DependencyToolServiceImpl.java:109) at com.acme.dependencytool.server.DependencyToolServiceImpl.search(DependencyToolServiceImpl.java:48) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:527) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:166) at com.google.gwt.user.server.rpc.RemoteServiceServlet.doPost(RemoteServiceServlet.java:86) at javax.servlet.http.HttpServlet.service(HttpServlet.java:637) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:729) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.handler.RequestLogHandler.handle(RequestLogHandler.java:49) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:647) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:205) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488)

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