Search Results

Search found 6811 results on 273 pages for 'tree navigation'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 13/273 | < Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >

  • navigation framework in silverlight 3 skipping constructor when usercontrol is of a derived type

    - by tarren
    Hi: I am using the NavigationFramework in Silverlight 3, and am running into issues where the constructor of the UserControl in the xaml I am loading is not being called, and I believe this is because the UserControl in the xaml I am calling is actually derived from another user control. I have stepped through the debugger with specific break points and the constructor is being ignored completey. I have MyWindowBlue which is of type uctrlBaseMyWindow. The constructor for uctrlBaseMyWindow is being called when the xaml is 'navigated to' but the constructor for MyWindowBlue is being ignored. This is not the case if I add the user control via markup directly. Anyone else have this issue? The code I am using to navigate to the MyWindowBlue is this.MyContentFrame.Navigate(new Uri("/Controls/uctrlMyWindowBlue.xaml", UriKind.Relative)); Has anyone run into this or could offer any help? Thanks

    Read the article

  • Silverlight Not Rendering On Navigation

    - by Azmath
    I'm trying to create a site that requires login. Its entirely designed in silverlight. So my first page, home.xaml loads in mysite.aspx and it basically has a login page. AFter login, the user is redirected to another page user.aspx. in that page, i've embedded another silverlight control called nav.xaml. so now when user.aspx loads it is supposed to load a silverlight control. i've programmed app.xaml.vb such that it loads nav.xaml in the rootlayout when the page requesting is user.aspx. but for some reason its not working. my app.xaml.vb code: Private Sub Application_Startup(ByVal o As Object, ByVal e As StartupEventArgs) Handles Me.Startup If e.InitParams.ContainsKey("ReqPage") Then If e.InitParams("ReqPage") = "userpage" Then Me.RootVisual = New Nav() End If Else Me.RootVisual = New Home() End If End Sub in IE, half of the nav.xaml is rendered. but in firefox nothing is rendered. so wats going on exactly? pls help!

    Read the article

  • Nested <ul><li> navigation menu using a recursive Python function

    - by Alex
    Hi. I want to render this data structure as an unordered list. menu = [ [1, 0], [2, 1], [3, 1], [4, 3], [5, 3], [6, 5], [7,1] ] [n][0] is the key [n][1] references the parent key The desired output is: <ul> <li>Node 1</li> <ul> <li>Node 2</li> <li>Node 3</li> <ul> <li>Node 4</li> <li>Node 5</li> <ul> <li>Node 6</li> </ul> </ul> <li>Node 7</li> </ul> </ul> I could probably do this without recursion but that would be no fun. Unfortunately, I am having problems putting it all together. I don't have much experience with recursion and this is proving to be very difficult for me to build and debug. What is the most efficient way to solve this problem in Python? Thanks!

    Read the article

  • Android reset activity component state on navigation back

    - by Aure77
    I have 2 activities in my application. In activity1, I set some configuration and I modify the state of some component (ex: set button state disabled). And I navigate to activity2. In activity2 I do some stuff and at end, I finish this activity and come back to activity1. But In activity1, my components state are the same when I leave this activity. How to reset the components state with valuesdeclared in XML file (layout) ?

    Read the article

  • iphone navigation

    - by Rona
    function handleClickEvent(event) { var linkFrom = $(event.target); if (typeof linkFrom.attr("href") == 'undefined') { linkFrom = $(event.target).parent(); } var targetPage = linkFrom.attr("href"); if (linkFrom.hasClass('submit')) { handleSubmitEvent(event); // if we want to stop processing: return false; } if (linkFrom.hasClass('backbutton')) { targetPage = historyStack.pop(); if (historyStack.length == 0) { lastPage = "index.html"; } } else { historyStack.push(lastPage); } lastPage = targetPage; $(event.target).css({ 'background-color': '#194fdb', 'color': '#ffffff' }); loadingWindowON(); // Add new unique div prevPageId = "page" + pageIdCounter; pageIdCounter = parseInt(pageIdCounter) + 1 nextPageId = "page" + pageIdCounter; nextPageDiv = "<div id='" + nextPageId + "' class='nextpage' /></div>"; $("body").append(nextPageDiv); if (linkFrom.attr("target") != "_blank") { event.preventDefault(); document.getElementById(nextPageId).addEventListener('webkitAnimationEnd', function () { // remove prev div element = document.getElementById(prevPageId); if (element) { element.parentNode.removeChild(element); } // set next div as current document.getElementById(nextPageId).className = 'currentpage'; }, false); document.getElementById(nextPageId).className += ' slideleftIn'; document.getElementById(prevPageId).className += ' slideleftOut'; loadContent(targetPage, nextPageId); } I use this javascript with a twitter app I had to do and when I click a button, instead of sliding the new page from the side it adds it to the existing page at the bottom. It works fine when i open it on my computer using google chrome but when I try to open it with my iphone it doesn't work. Any ideas?

    Read the article

  • Generate syntax tree for simple math operations

    - by M28
    I am trying to generate a syntax tree, for a given string with simple math operators (+, -, *, /, and parenthesis). Given the string "1 + 2 * 3": It should return an array like this: ["+", [1, ["*", [2,3] ] ] ] I made a function to transform "1 + 2 * 3" in [1,"+",2,"*",3]. The problem is: I have no idea to give priority to certain operations. My code is: function isNumber(ch){ switch (ch) { case '0': case '1': case '2': case '3': case '4': case '5': case '6': case '7': case '8': case '9': case '.': return true; break; default: return false; break; } } function generateSyntaxTree(text){ if (typeof text != 'string') return []; var code = text.replace(new RegExp("[ \t\r\n\v\f]", "gm"), ""); var codeArray = []; var syntaxTree = []; // Put it in its on scope (function(){ var lastPos = 0; var wasNum = false; for (var i = 0; i < code.length; i++) { var cChar = code[i]; if (isNumber(cChar)) { if (!wasNum) { if (i != 0) { codeArray.push(code.slice(lastPos, i)); } lastPos = i; wasNum = true; } } else { if (wasNum) { var n = Number(code.slice(lastPos, i)); if (isNaN(n)) { throw new Error("Invalid Number"); return []; } else { codeArray.push(n); } wasNum = false; lastPos = i; } } } if (wasNum) { var n = Number(code.slice(lastPos, code.length)); if (isNaN(n)) { throw new Error("Invalid Number"); return []; } else { codeArray.push(n); } } })(); // At this moment, codeArray = [1,"+",2,"*",3] return syntaxTree; } alert('Returned: ' + generateSyntaxTree("1 + 2 * 3"));

    Read the article

  • How can a B-tree node be represented?

    - by chronodekar
    We're learning B-trees in class and have been asked to implement them in code. The teacher has left choice of programming language to us and I want to try and do it in C#. My problem is that the following structure is illegal in C#, unsafe struct BtreeNode { int key_num; // The number of keys in a node int[] key; // Array of keys bool leaf; // Is it a leaf node or not? BtreeNode*[] c; // Pointers to next nodes } Specifically, one is not allowed to create a pointer to point to the structure itself. Is there some work-around or alternate approach I could use? I'm fairly certain that there MUST be a way to do this within the managed code, but I can't figure it out. EDIT: Eric's answer pointed me in the right direction. Here's what I ended up using, class BtreeNode { public List<BtreeNode> children; // The child nodes public static int MinDeg; // The Minimum Degree of the tree public bool IsLeaf { get; set; } // Is the current node a leaf or not? public List<int> key; // The list of keys ... }

    Read the article

  • OutOfMemoryError creating a tree recursively?

    - by Alexander Khaos Greenstein
    root = new TreeNode(N); constructTree(N, root); private void constructTree(int N, TreeNode node) { if (N > 0) { node.setLeft(new TreeNode(N-1)); constructTree(N-1, node.getLeft()); } if (N > 1) { node.setMiddle(new TreeNode(N-2)); constructTree(N-2, node.getMiddle()); } if (N > 2) { node.setRight(new TreeNode(N-3)); constructTree(N-3, node.getRight()); } Assume N is the root number, and the three will create a left middle right node of N-1, N-2, N-3. EX: 5 / | \ 4 3 2 /|\ 3 2 1 etc. My GameNode class has the following variables: private int number; private GameNode left, middle, right; Whenever I construct a tree with an integer greater than 28, I get a OutOfMemoryError. Is my recursive method just incredibly inefficient or is this natural? Thanks!

    Read the article

  • ZF2: How to get Zend\Navigation inside custom router?

    - by Katan87
    I have custom router and I have to get access to Zend\Navigation inside this custom router. I was googling, asking and searching and no results :/ All I need is to find nodes with 'link' param using Zend\Navigation in my AliasSegment::match function. Here is my module.config.php: 'navigation' => array( // The DefaultNavigationFactory we configured in (1) uses 'default' as the sitemap key 'default' => array( // And finally, here is where we define our page hierarchy 'account' => array( 'label' => 'Account', 'route' => 'node', 'pages' => array( 'home' => array( 'label' => 'Dashboard', 'route' => 'node', 'params' => array( 'id' => '1', 'link' => '/about/gallery' ), ), 'login' => array( 'label' => 'Sign In', 'route' => 'node', 'params' => array( 'id' => '1', 'link' => '/signin' ), ), 'logout' => array( 'label' => 'Sign Out', 'route' => 'node', ), ), ), ), ), [...] 'service_manager' => array( 'factories' => array( 'translator' => 'Zend\I18n\Translator\TranslatorServiceFactory', 'Navigation' => 'Zend\Navigation\Service\DefaultNavigationFactory', ), ), [...] And here is my AliasSegment class: namespace Application\Controller; use Traversable; use Zend\Mvc\Router\Exception; use Zend\Stdlib\ArrayUtils; use Zend\Stdlib\RequestInterface as Request; use Zend\Mvc\Router\Http; class AliasSegment extends \Zend\Mvc\Router\Http\Segment { public function match(Request $request, $pathOffset = null) { //Here i need to have access to Zend\Navigation return parent::match($request, $pathOffset); } }

    Read the article

  • How to reload Ext.tree.TreePanel on demand?

    - by Sergei Stolyarov
    I want to create Ext.tree.TreePanel component and periodically load content from the external URl. So I've written something like new Ext.tree.TreePanel({ root: { nodeType: 'async', text: 'asdasd', draggable: false, id: 'folders-tree-root' }, loader: new Ext.tree.TreeLoader() }); And now I want to reload this tree, so I write: tree.loader.dataUrl = 'folders-sample.json'; tree.root.reload(); And nothing happens. add: The only way I've found is set some invalid value to dataUrl param on TreeLoader creation: new Ext.tree.TreePanel({ root: { nodeType: 'async', text: 'asdasd', draggable: false, id: 'folders-tree-root' }, loader: new Ext.tree.TreeLoader(dataUrl: 'something') });

    Read the article

  • Binary Tree in C Insertion Error

    - by Paul
    I'm quite new to C and I'm trying to implement a Binary Tree in C which will store a number and a string and then print them off e.g. 1 : Bread 2 : WashingUpLiquid etc. The code I have so far is: #include <stdio.h> #include <stdlib.h> #define LENGTH 300 struct node { int data; char * definition; struct node *left; struct node *right; }; struct node *node_insert(struct node *p, int value, char * word); void print_preorder(struct node *p); int main(void) { int i = 0; int d = 0; char def[LENGTH]; struct node *root = NULL; for(i = 0; i < 2; i++) { printf("Please enter a number: \n"); scanf("%d", &d); printf("Please enter a definition for this word:\n"); scanf("%s", def); root = node_insert(root, d, def); printf("%s\n", def); } printf("preorder : "); print_preorder(root); printf("\n"); return 0; } struct node *node_insert(struct node *p, int value, char * word) { struct node *tmp_one = NULL; struct node *tmp_two = NULL; if(p == NULL) { p = (struct node *)malloc(sizeof(struct node)); p->data = value; p->definition = word; p->left = p->right = NULL; } else { tmp_one = p; while(tmp_one != NULL) { tmp_two = tmp_one; if(tmp_one->data > value) tmp_one = tmp_one->left; else tmp_one = tmp_one->right; } if(tmp_two->data > value) { tmp_two->left = (struct node *)malloc(sizeof(struct node)); tmp_two = tmp_two->left; tmp_two->data = value; tmp_two->definition = word; tmp_two->left = tmp_two->right = NULL; } else { tmp_two->right = (struct node *)malloc(sizeof(struct node)); tmp_two = tmp_two->right; tmp_two->data = value; tmp_two->definition = word; tmp_two->left = tmp_two->right = NULL; } } return(p); } void print_preorder(struct node *p) { if(p != NULL) { printf("%d : %s\n", p->data, p->definition); print_preorder(p->left); print_preorder(p->right); } } At the moment it seems to work for the ints but the description part only prints out for the last one entered. I assume it has something to do with pointers on the char array but I had no luck getting it to work. Any ideas or advice? Thanks

    Read the article

  • How-to read data from selected tree node

    - by Frank Nimphius
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} By default, the SelectionListener property of an ADF bound tree points to the makeCurrent method of the FacesCtrlHierBinding class in ADF to synchronize the current row in the ADF binding layer with the selected tree node. To customize the selection behavior, or just to read the selected node value in Java, you override the default configuration with an EL string pointing to a managed bean method property. In the following I show how you change the selection listener while preserving the default ADF selection behavior. To change the SelectionListener, select the tree component in the Structure Window and open the Oracle JDeveloper Property Inspector. From the context menu, select the Edit option to create a new listener method in a new or an existing managed bean. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} For this example, I created a new managed bean. On tree node select, the managed bean code prints the selected tree node value(s) import java.util.List; import javax.el.ELContext; import javax.el.ExpressionFactory; import javax.el.MethodExpression; import javax.faces.application.Application; import javax.faces.context.FacesContext; import java.util.Iterator; import oracle.adf.view.rich.component.rich.data.RichTree; import oracle.jbo.Row; import oracle.jbo.uicli.binding.JUCtrlHierBinding; import oracle.jbo.uicli.binding.JUCtrlHierNodeBinding; import org.apache.myfaces.trinidad.event.SelectionEvent; import org.apache.myfaces.trinidad.model.CollectionModel; import org.apache.myfaces.trinidad.model.RowKeySet; import org.apache.myfaces.trinidad.model.TreeModel; public class TreeSampleBean { public TreeSampleBean() {} public void onTreeSelect(SelectionEvent selectionEvent) { //original selection listener set by ADF //#{bindings.allDepartments.treeModel.makeCurrent} String adfSelectionListener = "#{bindings.allDepartments.treeModel.makeCurrent}";   //make sure the default selection listener functionality is //preserved. you don't need to do this for multi select trees //as the ADF binding only supports single current row selection     /* START PRESERVER DEFAULT ADF SELECT BEHAVIOR */ FacesContext fctx = FacesContext.getCurrentInstance(); Application application = fctx.getApplication(); ELContext elCtx = fctx.getELContext(); ExpressionFactory exprFactory = application.getExpressionFactory();   MethodExpression me = null;   me = exprFactory.createMethodExpression(elCtx, adfSelectionListener,                                           Object.class, newClass[]{SelectionEvent.class});   me.invoke(elCtx, new Object[] { selectionEvent });     /* END PRESERVER DEFAULT ADF SELECT BEHAVIOR */   RichTree tree = (RichTree)selectionEvent.getSource(); TreeModel model = (TreeModel)tree.getValue();  //get selected nodes RowKeySet rowKeySet = selectionEvent.getAddedSet();   Iterator rksIterator = rowKeySet.iterator();   //for single select configurations,this only is called once   while (rksIterator.hasNext()) {     List key = (List)rksIterator.next();     JUCtrlHierBinding treeBinding = null;     CollectionModel collectionModel = (CollectionModel)tree.getValue();     treeBinding = (JUCtrlHierBinding)collectionModel.getWrappedData();     JUCtrlHierNodeBinding nodeBinding = null;     nodeBinding = treeBinding.findNodeByKeyPath(key);     Row rw = nodeBinding.getRow();     //print first row attribute. Note that in a tree you have to     //determine the node type if you want to select node attributes     //by name and not index      String rowType = rw.getStructureDef().getDefName();       if(rowType.equalsIgnoreCase("DepartmentsView")){      System.out.println("This row is a department: " +                          rw.getAttribute("DepartmentId"));     }     else if(rowType.equalsIgnoreCase("EmployeesView")){      System.out.println("This row is an employee: " +                          rw.getAttribute("EmployeeId"));     }        else{       System.out.println("Huh????");     }     // ... do more useful stuff here   } } -------------------- Download JDeveloper 11.1.2.1 Sample Workspace

    Read the article

  • Find all paths from root to leaves of tree in Scheme

    - by grifaton
    Given a tree, I want to find the paths from the root to each leaf. So, for this tree: D / B / \ A E \ C-F-G has the following paths from root (A) to leaves (D, E, G): (A B D), (A B E), (A C F G) If I represent the tree above as (A (B D E) (C (F G))) then the function g does the trick: (define (g tree) (cond ((empty? tree) '()) ((pair? tree) (map (lambda (path) (if (pair? path) (cons (car tree) path) (cons (car tree) (list path)))) (map2 g (cdr tree)))) (else (list tree)))) (define (map2 fn lst) (if (empty? lst) '() (append (fn (car lst)) (map2 fn (cdr lst))))) But this looks all wrong. I've not had to do this kind of thinking for a while, but I feel there should be a neater way of doing it. Any ideas for a better solution (in any language) would be appreciated.

    Read the article

  • How to reduce redundant code when adding new c++0x rvalue reference operator overloads

    - by Inverse
    I am adding new operator overloads to take advantage of c++0x rvalue references, and I feel like I'm producing a lot of redundant code. I have a class, tree, that holds a tree of algebraic operations on double values. Here is an example use case: tree x = 1.23; tree y = 8.19; tree z = (x + y)/67.31 - 3.15*y; ... std::cout << z; // prints "(1.23 + 8.19)/67.31 - 3.15*8.19" For each binary operation (like plus), each side can be either an lvalue tree, rvalue tree, or double. This results in 8 overloads for each binary operation: // core rvalue overloads for plus: tree operator +(const tree& a, const tree& b); tree operator +(const tree& a, tree&& b); tree operator +(tree&& a, const tree& b); tree operator +(tree&& a, tree&& b); // cast and forward cases: tree operator +(const tree& a, double b) { return a + tree(b); } tree operator +(double a, const tree& b) { return tree(a) + b; } tree operator +(tree&& a, double b) { return std::move(a) + tree(b); } tree operator +(double a, tree&& b) { return tree(a) + std::move(b); } // 8 more overloads for minus // 8 more overloads for multiply // 8 more overloads for divide // etc which also has to be repeated in a way for each binary operation (minus, multiply, divide, etc). As you can see, there are really only 4 functions I actually need to write; the other 4 can cast and forward to the core cases. Do you have any suggestions for reducing the size of this code? PS: The class is actually more complex than just a tree of doubles. Reducing copies does dramatically improve performance of my project. So, the rvalue overloads are worthwhile for me, even with the extra code. I have a suspicion that there might be a way to template away the "cast and forward" cases above, but I can't seem to think of anything.

    Read the article

  • Resources for creating a turn-by-turn navigation system

    - by benwad
    I'm trying to create a kind of turn-by-turn satellite navigation system using the iOS SDK. I get the directions from the server and draw them on the map, then I keep getting location updates from the iPhone's GPS chip. Currently I start by finding the nearest turning point then, each time the user comes within a certain distance of the next turning point, a verbal cue is given and the turning point index is incremented. This is a delicate system and I'd like to make it more robust so I can tell when the user is going the wrong direction etc. Basically I'm looking for some literature about turn-by-turn navigation, in terms of tracking the user's progress and whether they're going the right direction. I'd have thought there's a lot of research out there but I can't seem to find anything apart from simple tutorials on how to use a given SDK or directions API. Can anyone direct me to a good run-through of the various techniques used in software such as TomTom or Google Maps Navigation?

    Read the article

  • Simple dependency tree diagram generator

    - by foampile
    I have a need to produce a simple dependency tree diagram. The input data would be in the following simple format: ITEM_NAME DEPENDENCY ---------------------------- ITEM_101 ITEM_75 ITEM_102 ITEM_77 ITEM_102 ITEM_61 ITEM_102 ITEM_11 This means that ITEM_101 depends on ITEM_75 and ITEM_102 depends on items ITEM_77, ITEM_61 and ITEM_11. So the diagram would have items ITEM_77, ITEM_61 and ITEM_11 in one vertical level and ITEM_102 would be below it with a line connecting each of the three dependencies to ITEM_102. The same would be for ITEM_101, ITEM_75 would be somewhere above it and there would be a line connecting it. In the real world this tree represents a hierarchy of scheduling jobs. We have a very extensive workload automation hierarchy in Autosys and I have heard that its front end utility has something like this tree visual representation, however, for some reason, that utility has been disabled by admins. My business users want to see this hierarchy in an easy-to-consume format. I was hoping that I won't have to program something like this from scratch because it seems like quite a common reporting requirement and the input data is simply formatted. My question is: is there a FOSS tool that takes standardized data input and produces such a hierarchical tree? Thanks

    Read the article

  • Count function on tree structure (non-binary)

    - by Spevy
    I am implementing a tree Data structure in c# based (largely on Dan Vanderboom's Generic implementation). I am now considering approach on handling a Count property which Dan does not implement. The obvious and easy way would be to use a recursive call which Traverses the tree happily adding up nodes (or iteratively traversing the tree with a Queue and counting nodes if you prefer). It just seems expensive. (I also may want to lazy load some of my nodes down the road). I could maintain a count at the root node. All children would traverse up to and/or hold a reference to the root, and update a internally settable count property on changes. This would push the iteration problem to when ever I want to break off a branch or clear all children below a given node. Generally less expensive, and puts the heavy lifting what I think will be less frequently called functions. Seems a little brute force, and that usually means exception cases I haven't thought of yet, or bugs if you prefer. Does anyone have an example of an implementation which keeps a count for an Unbalanced and/or non-binary tree structure rather than counting on the fly? Don't worry about the lazy load, or language. I am sure I can adjust the example to fit my specific needs. EDIT: I am curious about an example, rather than instructions or discussion. I know this is not technically difficult...

    Read the article

  • How to Create tree type CVL in Content server(UCM)

    - by rajeev.y.ranjan-oracle
    Steps to create tree choice list:1)Create a table "tblStates" with column "stateID" and "stateName". Click on "ADD Recommended".2) Create another table "tblCities with columns "cityID", "stateID" and "cityName".3)Then create two views on these tables namely "tblstateview" and "tblcityview".3)In "StateView" added two rows with values as JH and MH in stateID column.Jharkhand and Maharastra in stateName.4)Similarly in tblcityview added two rows with values as:BO and RA in cityID column.JH and MH in stateID columnBokaro and Mumbai in cityname column.5)Created relationship with Parentinfo "tblStates" and stateID and  childinfo with tblCities and stateID.6)Created metadata by name "Newtest"Enable option list,go to the configure ,Select use tree,Click on go edit definition 7)Tree Definition at level 1: a)Choose" tblstateView"b)Choose relation "newstatecity"At Level2:a)Choose cityView.Log out of the NativeUI and ContentUI and test the tree created by name "Newtest".

    Read the article

  • FIlling a Java Bean tree structure from a csv flat file

    - by Clem
    Hi, I'm currently trying to construct a list of bean classes in Java from a flat description file formatted in csv. Concretely : Here is the structure of the csv file : MES_ID;GRP_PARENT_ID;GRP_ID;ATTR_ID M1 ; ;G1 ;A1 M1 ; ;G1 ;A2 M1 ;G1 ;G2 ;A3 M1 ;G1 ;G2 ;A4 M1 ;G2 ;G3 ;A5 M1 ; ;G4 ;A6 M1 ; ;G4 ;A7 M1 ; ;G4 ;A8 M2 ; ;G1 ;A1 M2 ; ;G1 ;A2 M2 ; ;G2 ;A3 M2 ; ;G2 ;A4 It corresponds to the hierarchical data structure : M1 ---G1 ------A1 ------A2 ------G2 ---------A3 ---------A4 ---------G3 ------------A5 ------G4 ---------A7 ---------A8 M2 ---G1 ------A1 ------A2 ---G2 ------A3 ------A4 Remarks : A message M can have an infinite number of groups G and attributes A A group G can have an infinite number of attributes and an infinite number of under-groups each of them having under-groups too That beeing said, I'm trying to read this flat csv decription to store it in this structure of beans : Map<String, MBean> messages = new HashMap<String, Mbean>(); == public class MBean { private String mes_id; private Map<String, GBean> groups; } public class GBean { private String grp_id; private Map<String, ABean> attributes; private Map<String, GBean> underGroups; } public class ABean { private String attr_id; } Reading the csv file sequentially is ok and I've been investigating how to use recursion to store the description data, but couldn't find a way. Thanks in advance for any of your algorithmic ideas. I hope it will put you in the mood of thinking about this ... I've to admit that I'm out of ideas :s

    Read the article

  • jquery Tree Traversal prev() problem.

    - by Guido Lemmens
    Hello, I like to click a label and check the previous checkbox. I've tried the next code, but this is not working. I have tried for 2 hours, but what am i missing? JQUERY jQuery(document).ready(function() { $('.profilename').live('click', function() { if ($(this).prev("input:checked").val() != null) { $(this).prev("input").removeAttr("checked"); } else { $(this).prev("input").attr("checked","checked"); } }); }); HTML <input type="checkbox" class="check" name="example"> <label class="namelabel">John Doe</label> Who can help me to solve this question? Many thanks! p.s. I know i can easy solve this with the <label for=""> tag, but that is not the question.

    Read the article

  • Implementing the tree with reference to the root for each leaf

    - by AntonAL
    Hi, i implementing a products catalog, that looks, like this: group 1 subgroup 1 subgroup 2 item 1 item 2 ... item n ... subgroup n group 2 subgroup 1 ... subgroup n group 3 ... group n The Models: class CatalogGroup < ActiveRecord::Base has_many: catalog_items has_many :catalog_items_all, :class_name => "CatalogItem", :foreign_key => "catalog_root_group_id" end class CatalogItem < ActiveRecord::Base belongs_to :catalog_group belongs_to :catalog_root_group, :class_name => "CatalogGroup" end Migrations: class CreateCatalogItems < ActiveRecord::Migration def self.up create_table :catalog_items do |t| t.integer :catalog_group_id t.integer :catalog_root_group_id t.string :code t.timestamps end end For convenience, i referenced each CatalogItem to it's top-most CatalogGroup and named this association "catalog_root_group". This will give us the simple implementation of search request, like "show me all items in group 1". We will have a deal only with CatalogModel.catalog_root_group The problem is - this association does't work. I always get "catalog_root_group" equals to nil Also, i have tried to overcome the using of reference to root group ("catalog_root_group"), but i cannot construct appropriate search request in ruby ... Do you know, how to do it ?

    Read the article

  • Parse tree and grammars information

    - by fuzzylogikk
    Do anyone know where to find good online resources with examples how to make grammars and parsetrees? Preferebly introductary materials. Info that is n00b friendly, haven't found anything good with google myself. edit: I'm thinking about theory, not a specific parser software.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >