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• Simple addition calculator in python

  - by Krysten

  I built a very simple addition calculator in python: #This program will add two numbers entered in by the user print "Welcome!" num1 = input("Please enter in the first number to be added.") num2 = input("Please enter in the second number to be added.") sum = num1 + num2 print "The sum of the two numbers entered is: ", sum I haven't setup python yet, so I'm using codepad.org (an online compiler). I get the following error: Welcome! Please enter in the first number to be addeded.Traceback (most recent call last): Line 5, in num1 = input("Please enter in the first number to be addeded.") EOFError

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• Best approach for using Scanner Objects in Java?

  - by devjeetroy

  Although I'm more of a C++/ASM guy, I have to work with java as a part of my undergrad course at college. Our teacher taught us input using Scanner(System.in), and told us that if multiple functions are were taking user input, it would be advisable that a single Scanner object is passed around so as to reduce chances of the input stream getting screwed up. Now using this approach has gotten me into a situation where I'm trying to use a Scanner.nextLine(), and this statement does not wait for user input. It just moves on to the following statement. I figured there may be some residual cr/lf or other characters in the Scanner that might not have been retrieved are causing the problem. Here is the code. while(lineScanner.hasNext()) { if(isPlaceHolder(temp = lineScanner.next())) { temp = temp.replace("<",""); temp = temp.replace(">", ""); System.out.print("Enter "+aOrA(temp.charAt(0)) +" " +temp + " : "); temp = consoleInput.nextLine(); } outputFileStream.print(temp + " "); } All of the code is inside a function which receives a Scanner object consoleInput. Ok, so what happens when i run it is that when the program enters the if() the first time, It carries out theSystem.out.print, does not wait for user input, and moves on to the second time that it enters the 'if' block. This time, it takes the input and the rest of the program operates normally. What is even more surprising is that when i check the output file created by the program, it is perfect, just as i want to be. Almost as if the first time input using the scanner is correct. I have solved this problem by creating a new system.in Scanner in the function itself, instead of receiving the Scanner object as a parameter. But I am still very curious to know what the hell is happening and why it couldn't be solved using a simple Scanner.reset(). Would it be better to just simply create a Scanner Object for each function? Thanks, Devjeet PS. Although I know how to take input using fileinputstreams and the like, we are not supposed to use it with the homework.

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• Assign variable with variable in function

  - by freakazo

  Let's say we have def Foo(Bar=0,Song=0): print(Bar) print(Song) And I want to assign any one of the two parameters in the function with the variable sing and SongVal: Sing = Song SongVal = 2 So that it can be run like: Foo(Sing=SongVal) Where Sing would assign the Song parameter to the SongVal which is 2. The result should be printed like so: 0 2 So should I rewrite my function or is it possible to do it the way I want to? (With the code above you get an error saying Foo has no parameter Sing. Which I understand why, any way to overcome this without rewriting the function too much? Thanks in advance!

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• How to use Scanner to accept only valid int as input

  - by John

  I'm trying to make a small program more robust and I need some help with that. Scanner kb = new Scanner(System.in); int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also I want the program to automatically check and ignore if the user enters a character instead of a number. Because right now when a user enters for example r instead of a number the program just exits.

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• Adding to arrays and printing arrays in Java

  - by nfoggia

  I need help figuring out how to get the user to input a number of integers no more than 10, and then add them to an array and print them out from the array. The code I have below, when run, asks the user for the integers and then runs forever and doesn't work. What am I doing wrong? public static void main(String[] args) { Scanner input = new Scanner(System.in); // create a new scanner System.out.print("Enter integers between 1 and 100\n "); int[] nextNumber = new int[10]; int i = 0; int number = input.nextInt(); while (i < nextNumber.length){ i++; nextNumber[i] = number; number = input.nextInt(); } int a = 0; while (a < nextNumber.length){ a++; System.out.println(nextNumber[a]); }

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• Can a rake task know about the other tasks in the invocation chain?

  - by andrewdotnich

  Rake (like make) is able to have many targets/tasks specified on invocation. Is it possible for a rake task to access the list of tasks the user invoked, in order to do its job? Scenario: Consider a Rake-based build tool. A help task would like to know what tasks were also specified in order to print their usage and halt the build process. The benefit of this as opposed to rake-style parameter passing are cleaner syntax (rake help build instead of rake help task=build) and chaining (rake help build run_tests would print usage for both).

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• Python subprocess.Popen hangs in 'for l in p.stdout' until p terminates, why?

  - by Albert

  I have that code: #!/usr/bin/python -u localport = 9876 import sys, re, os from subprocess import * tun = Popen(["./newtunnel", "22", str(localport)], stdout=PIPE, stderr=STDOUT) print "** Started tunnel, waiting to be ready ..." for l in tun.stdout: sys.stdout.write(l) if re.search("Waiting for connection", l): print "** Ready for SSH !" break The "./newtunnel" will not exit, it will constantly output more and more data to stdout. However, that code will not give any output and just keeps waiting in the tun.stdout. When I kill the newtunnel process externally, it flushes all the data to tun.stdout. So it seems that I can't get any data from the tun.stdout while it is still running. Why is that? How can I get the information? Note that the default bufsize for Popen is 0 (unbuffered). I can also specify bufsize=0 but that doesn't change anything.

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• PHP Global variable in class is reset

  - by Robert

  I have a web form that manipulates records in a MySQL database. I have a method for displaying an edit interface for both creating new records and editing them if ($_POST['new_page']) { print "<h2>Create new page</h2>\n"; $isNew=1; $this->EditForm(); } else if($_POST['edit']){ print "<h2>Edit page</h2>\n"; $isNew=0; $this->EditForm(); } I am trying to use the global variable $isNew to determine where a record is to be added or updated. However, whenever my SaveChanges() function is run, $isNew is always 0. $isNew is declared immediately after the class declaration, outside all of the functions. class Editor{ public $isNew;

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• Interrupting `while loop` with keyboard in Cython

  - by linello

  I want to be able to interrupt a long function with cython, using the usual CTRL+C interrupt command. My C++ long function is repeatedly called inside a while loop from Cython code, but I want to be able, during the loop, to send an "interrupt" and block the while loop. The interrupt also should wait the longFunction() to finish, so that no data are lost or kept in unknown status. This is one of my first implementation, which obviously doesn't work: computed=0; print "Computing long function..." while ( computed==0 ): try: computed = self.thisptr.aLongFunction() except (KeyboardInterrupt, SystemExit): computed=1 print '\n! Received keyboard interrupt.\n' break; (p.s. self.thisptr is the pointer to the current class which implements aLongFunction() )

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• Ruby: rules for implicit hashes

  - by flyer

  Why second output shows me only one element of Array? Is it still Array or Hash already? def printArray(arr) arr.each { | j | k, v = j.first printf("%s %s %s \n", k, v, j) } end print "Array 1\n" printArray( [ {kk: { 'k1' => 'v1' }}, {kk: { 'k2' => 'v2' }}, {kk: { 'k3' => 'v3' }}, ]) print "Array 2\n" printArray( [ kk: { 'k1' => 'v1' }, kk: { 'k2' => 'v2' }, kk: { 'k3' => 'v3' }, ]) exit # Output: # # Array 1 # kk {"k1"=>"v1"} {:kk=>{"k1"=>"v1"}} # kk {"k2"=>"v2"} {:kk=>{"k2"=>"v2"}} # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}} # Array 2 # kk {"k3"=>"v3"} {:kk=>{"k3"=>"v3"}}

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• Why are my \n not working in PHP?

  - by Doug

  I'm playing with SAX and noticed it's not line breaking properly. I have no iea why. function flush_data() { global $level, $char_data; $char_data = trim($char_data); if( strlen( $char_data ) > 0 ) { print "\n"; $data = split("\n", wordwrap($char_data, 76 - ($level*2))); foreach($data as $line) { print str_repeat(' ', ($level +1)) . "[".$line."]"."\n"; } } $char_data = ''; }

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• Java program runtime error

  - by Sam

  public class BooksTestDrive { public static void main(String[] args) { Books [] myBooks = new Books[3]; int x=0; myBooks[0].title = "The Grapes of Jave"; myBooks[1].title = "The Java Gatsby"; myBooks[2].title = "The Java Cookbook"; myBooks[0].author = "bob"; myBooks[1].author = "sue"; myBooks[2].author = "ian"; while (x < 3) { System.out.print(myBooks[x].title); System.out.print("by"); System.out.println(myBooks[x].author); x = x+1; } } } This code compiles but while runtime, its giving nullpointer exception.

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• Strange pattern matching with functions instancing Show

  - by Sean D

  So I'm writing a program which returns a procedure for some given arithmetic problem, so I wanted to instance a couple of functions to Show so that I can print the same expression I evaluate when I test. The trouble is that the given code matches (-) to the first line when it should fall to the second. {-# OPTIONS_GHC -XFlexibleInstances #-} instance Show (t -> t-> t) where show (+) = "plus" show (-) = "minus" main = print [(+),(-)] returns [plus,plus] Am I just committing a motal sin printing functions in the first place or is there some way I can get it to match properly? edit:I realise I am getting the following warning: Warning: Pattern match(es) are overlapped In the definition of `show': show - = ... I still don't know why it overlaps, or how to stop it.

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• listing objects from ManyToManyField

  - by Noam Smadja

  i am trying to print a list of all the Conferences and for each conference, print its 3 Speakers. in my template i have: {% if conferences %} <ul> {% for conference in conferences %} <li>{{ conference.date }}</li> {% for speakers in conference.speakers %} <li>{{ conference.speakers }}</li> {% endfor %} {% endfor %} </ul> {% else %} <p>No Conferences</p> {% endif %} in my views.py file i have: from django.shortcuts import render_to_response from youthconf.conference.models import Conference def manageconf(request): conferences = Conference.objects.all().order_by('-date')[:5] return render_to_response('conference/manageconf.html', {'conferences': conferences}) there is a model named conference. which has a class named Conferences with a ManyToManyField named speakers i get the error: Caught an exception while rendering: 'ManyRelatedManager' object is not iterable with this line: {% for speakers in conference.speakers %}

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• Python: Time a code segment for testing performance (with timeit)

  - by Mestika

  Hi, I've a python script which works just as it should but I need to write the time for the execution. I've gooled that I should use timeit but I can't seem to get it to work. My Python script looks like this: import sys import getopt import timeit import random import os import re import ibm_db import time from string import maketrans myfile = open("results_update.txt", "a") for r in range(100): rannumber = random.randint(0, 100) update = "update TABLE set val = %i where MyCount >= '2010' and MyCount < '2012' and number = '250'" % rannumber #print rannumber conn = ibm_db.pconnect("dsn=myDB","usrname","secretPWD") for r in range(5): print "Run %s\n" % r ibm_db.execute(query_stmt) query_stmt = ibm_db.prepare(conn, update) myfile.close() ibm_db.close(conn) What I need it the time it takes the execution of the query and written to the file "results_update.txt". The purpose is to test an update statement for my database with different indexes and tuning mechanisms. Sincerely Mestika

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• C# Reflection - How can I tell if object o is of type KeyValuePair and then cast it?

  - by Logan

  Hi All I'm currently trying to write a Dump() method from LinqPad equivalent iin C# for my own amusment. I'm moving from Java to C# and this is an exercise rather than a business requirement. I've got almost everything working except for Dumping a Dictionary. The problem is that KeyValuePair is a Value type. For most other Value types I simply call the ToString method but this is insufficient as the KeyValuePair may contain Enumerables and other objects with undesirable ToString methods. So I need to work out if it's a KeyValuePair and then cast it. In Java I could use wildcard generics for this but I don't know the equivalent in C#. Your quest, given an object o, determine if it's a KeyValuePair and call Print on its key and value. Print(object o) { ... } Thanks!

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• python win32api registery key change

  - by user340495

  Hi, I am trying to trigger an event every time a registry value is being modified. import win32api import win32event import win32con import _winreg key = _winreg.OpenKey(_winreg.HKEY_CURRENT_USER,'Control Panel\Desktop',0,_winreg.KEY_READ) sub_key = _winreg.CreateKey(key,'Wallpaper') evt = win32event.CreateEvent(None,0,0,None) win32api.RegNotifyChangeKeyValue(sub_key,1,win32api.REG_NOTIFY_CHANGE_ATTRIBUTES,evt,True) ret_code=win32event.WaitForSingleObject(evt,3000) if ret_code == win32con.WAIT_OBJECT_0: print "CHANGED" if ret_code == win32con.WAIT_TIMEOUT: print "TIMED" my problem is that this is never triggered , the event always time-out. (the reg key I am trying to follow is the wallpaper) [ please note I trigger the event by 1) manually changing the registry value in regedit 2) an automated script which run this : from ctypes import windll from win32con import * windll.user32.SystemParametersInfoA(SPI_SETDESKWALLPAPER, 0,"C:\wall.jpg",SPIF_UPDATEINIFILE | SPIF_SENDWININICHANGE) ] Thanks for any help in advance :) EDIT:: sorry about formatting

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• Android , Read in binary data and write it to file

  - by Shpongle

  Hi all , Im trying to read in image file from a server , with the code below . It keeps going into the exception. I know the correct number of bytes are being sent as I print them out when received. Im sending the image file from python like so #open the image file and read it into an object imgfile = open (marked_image, 'rb') obj = imgfile.read() #get the no of bytes in the image and convert it to a string bytes = str(len(obj)) #send the number of bytes self.conn.send( bytes + '\n') if self.conn.sendall(obj) == None: imgfile.flush() imgfile.close() print 'Image Sent' else: print 'Error' Here is the android part , this is where I'm having the problem. Any suggestions on the best way to go about receiving the image and writing it to a file ? //read the number of bytes in the image String noOfBytes = in.readLine(); Toast.makeText(this, noOfBytes, 5).show(); byte bytes [] = new byte [Integer.parseInt(noOfBytes)]; //create a file to store the retrieved image File photo = new File(Environment.getExternalStorageDirectory(), "PostKey.jpg"); DataInputStream dis = new DataInputStream(link.getInputStream()); try{ os =new FileOutputStream(photo); byte buf[]=new byte[1024]; int len; while((len=dis.read(buf))>0) os.write(buf,0,len); Toast.makeText(this, "File recieved", 5).show(); os.close(); dis.close(); }catch(IOException e){ Toast.makeText(this, "An IO Error Occured", 5).show(); } EDIT: I still cant seem to get it working. I have been at it since and the result of all my efforts have either resulted in a file that is not the full size or else the app crashing. I know the file is not corrupt before sending server side. As far as I can tell its definitely sending too as the send all method in python sends all or throws an exception in the event of an error and so far it has never thrown an exception. So the client side is messed up . I have to send the file from the server so I cant use the suggestion suggested by Brian .

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• How can I interpolate the result of a function in a Perl here doc?

  - by Zerobu

  I was wondering if it was possible to call a function inside a perl here doc sub Function { } print<<HERE; Function() HERE

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• What do I need to distribute (keys, certs) for Python w/ SSL-socket connection?

  - by fandingo

  I'm trying to write a generic server-client application that will be able to exchange data amongst servers. I've read over quite a few OpenSSL documents, and I have successfully setup my own CA and created a cert (and private key) for testing purposes. I'm stuck with Python 2.3, so I can't use the standard "ssl" library. Instead, I'm stuck with PyOpenSSL, which doesn't seem bad, but there aren't many documents out there about it. My question isn't really about getting it working. I'm more confused about the certificates and where they need to go. Here are my two programs that do work: Server: #!/bin/env python from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER|SSL.VERIFY_FAIL_IF_NO_PEER_CERT, verify_cb) # ?????? ctx.use_privatekey_file('./Dmgr-key.pem') ctx.use_certificate_file('Dmgr-cert.pem') # ?????? ctx.load_verify_locations('./CAcert.pem') server = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) server.bind(('', 50000)) server.listen(3) a, b = server.accept() c = a.recv(1024) print(c) Client: from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER, verify_cb) # ?????????? ctx.use_privatekey_file('/home/justin/code/work/CA/private/Dmgr-key.pem') ctx.use_certificate_file('/home/justin/code/work/CA/Dmgr-cert.pem') # ????????? ctx.load_verify_locations('/home/justin/code/work/CA/CAcert.pem') sock = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) sock.connect(('10.0.0.3', 50000)) a = Tester(2, 2) b = pickle.dumps(a) sock.send("Hello, world") sock.flush() sock.send(b) sock.shutdown() sock.close() I found this information from ftp://ftp.pbone.net/mirror/ftp.pld-linux.org/dists/2.0/PLD/i586/PLD/RPMS/python-pyOpenSSL-examples-0.6-2.i586.rpm which contains some example scripts. As you might gather, I don't fully understand the sections between the " # ????????." I don't get why the certificate and private key are needed on both the client and server. I'm not sure where each should go, but shouldn't I only need to distribute one part of the key (probably the public part)? It undermines the purpose of having asymmetric keys if you still need both on each server, right? I tried alternating removing either the pkey or cert on either box, and I get the following error no matter which I remove: OpenSSL.SSL.Error: [('SSL routines', 'SSL3_READ_BYTES', 'sslv3 alert handshake failure'), ('SSL routines', 'SSL3_WRITE_BYTES', 'ssl handshake failure')] Could someone explain if this is the expected behavior for SSL. Do I really need to distribute the private key and public cert to all my clients? I'm trying to avoid any huge security problems, and leaking private keys would tend to be a big one... Thanks for the help!

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• File::Find and $_ in nested subroutines.

  - by zedoo

  When running the following code, the filenames of all files below C:\Test are printed. Why doesn't it print just Hello (n times, depending on how many files are processed)? Does this imply that I cannot rely on shift to reliably assign to $_? Imagine a coworker implements the wtf function and doesn't know that it's called from a File::Find wanted sub. I run this code with Strawberry Perl 5.12 use strict; use warnings; use File::Find; find(\&wanted, "C:\\test"); sub wanted{ wtf("Hello"); } sub wtf { shift; print; #expecting Hello }

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• Ruby time in 2009-02-17T05:00-07:00 format?

  - by viatropos

  How do I print out a ruby time using the date-time format: 2009-02-17T05:00-07:00 Like Time.now.to_datetime_s

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• Java exercise - display table with 2d array

  - by TheHacker66

  I'm struggling to finish a java exercise, it involves using 2d arrays to dinamically create and display a table based on a command line parameter. Example: java table 5 +-+-+-+-+-+ |1|2|3|4|5| +-+-+-+-+-+ |2|3|4|5|1| +-+-+-+-+-+ |3|4|5|1|2| +-+-+-+-+-+ |4|5|1|2|3| +-+-+-+-+-+ |5|1|2|3|4| +-+-+-+-+-+ What i have done so far: public static void main(String[] args) { int num = Integer.parseInt(args[0]); String[][] table = new String[num*2+1][num]; int[] numbers = new int[num]; int temp = 0; for(int i=0; i<numbers.length; i++) numbers[i] = i+1; // wrong for(int i=0; i<table.length; i++){ for(int j=0; j<num;j++){ if(i%2!=0){ temp=numbers[0]; for(int k=1; k<numbers.length; k++){ numbers[k-1]=numbers[k]; } numbers[numbers.length-1]=temp; for(int l=0; l<numbers.length; l++){ table[i][j] = "|"+numbers[l]; } } else table[i][j] = "+-"; } } for(int i=0; i<table.length; i++){ for(int j=0; j<num; j++) System.out.print(table[i][j]); if(i%2==0) System.out.print("+"); else System.out.print("|"); System.out.println();} } This doesn't work, since it prints 1|2|3|4 in every row, which isn't what i need. I found the issue, and it's because the first for loop changes the array order more times than needed and basically it returns as it was at the beginning. I know that probably there's a way to achieve this by writing more code, but i always tend to nest as much as possible to "optimize" the code while i write it, so that's why i tried solving this exercise by using less variables and loops as possible. Thanks in advance for your help!

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• Searching for duplicate records within a text file where the duplicate is determined by only two fie

  - by plg

  First, Python Newbie; be patient/kind. Next, once a month I receive a large text file (think 7 Million records) to test for duplicate values. This is catalog information. I get 7 fields, but the two I'm interested in are a supplier code and a full orderable part number. To determine if the record is dupliacted, I compress all special characters from the part number (except . and #) and create a compressed part number. The test for duplicates becomes the supplier code and compressed part number combination. This part is fairly straight forward. Currently, I am just copying the original file with 2 new columns (compressed part and duplicate indicator). If the part is a duplicate, I put a "YES" in the last field. Now that this is done, I want to be able to go back (or better yet, at the same time) to get the previous record where there was a supplier code/compressed part number match. So far, my code looks like this: Compress Full Part to a Compressed Part and Check for Duplicates on Supplier Code and Compressed Part combination import sys import re import time ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ start=time.time() try: file1 = open("C:\Accounting\May Accounting\May.txt", "r") except IOError: print sys.stderr, "Cannot Open Read File" sys.exit(1) try: file2 = open(file1.name[0:len(file1.name)-4] + "_" + "COMPRESSPN.txt", "a") except IOError: print sys.stderr, "Cannot Open Write File" sys.exit(1) hdrList="CIGSUPPLIER|FULL_PART|PART_STATUS|ALIAS_FLAG|ACQUISITION_FLAG|COMPRESSED_PART|DUPLICATE_INDICATOR" file2.write(hdrList+chr(10)) lines_seen=set() affirm="YES" records = file1.readlines() for record in records: fields = record.split(chr(124)) if fields[0]=="CIGSupplier": continue #If incoming file has a header line, skip it file2.write(fields[0]+"|"), #Supplier Code file2.write(fields[1]+"|"), #Full_Part file2.write(fields[2]+"|"), #Part Status file2.write(fields[3]+"|"), #Alias Flag file2.write(re.sub("[$\r\n]", "", fields[4])+"|"), #Acquisition Flag file2.write(re.sub("[^0-9a-zA-Z.#]", "", fields[1])+"|"), #Compressed_Part dupechk=fields[0]+"|"+re.sub("[^0-9a-zA-Z.#]", "", fields[1]) if dupechk not in lines_seen: file2.write(chr(10)) lines_seen.add(dupechk) else: file2.write(affirm+chr(10)) print "it took", time.time() - start, "seconds." ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ file2.close() file1.close() It runs in less than 6 minutes, so I am happy with this part, even if it is not elegant. Right now, when I get my results, I import the results into Access and do a self join to locate the duplicates. Loading/querying/exporting results in Access a file this size takes around an hour, so I would like to be able to export the matched duplicates to another text file or an Excel file. Confusing enough? Thanks.

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• Calculating the null space of a matrix

  - by Ainsworth

  I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

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