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How to improve performance of opening Microsoft Word when automated from c#?

- by Abdullah BaMusa

I have Microsoft Word template that I automated filling it’s fields from my application, and when the user request print I open this template. but creating word application every time user request print after filling fields is very expensive and lead to some delay while opening the template, so I choose to cache the reference to Word then just open the new filled template. that solve the performance issue as opening file is less expensive than recreating Word each time, but this work while the user just close the document not the entire Word application which when happened my reference to Word become invalid and return with exception says: “The RPC server is unavailable” next time request opening template . I tried to subscribe to BeforClosing event but his trigger for Quitting Word as well as Closing documents. My question is how to know if the word is closing document or quit the entire application so I take the proper action, or any hint for another direction of thinking about improve performance of opening word template.

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Strange pattern matching with functions instancing Show

- by Sean D

So I'm writing a program which returns a procedure for some given arithmetic problem, so I wanted to instance a couple of functions to Show so that I can print the same expression I evaluate when I test. The trouble is that the given code matches (-) to the first line when it should fall to the second. {-# OPTIONS_GHC -XFlexibleInstances #-} instance Show (t -> t-> t) where show (+) = "plus" show (-) = "minus" main = print [(+),(-)] returns [plus,plus] Am I just committing a motal sin printing functions in the first place or is there some way I can get it to match properly? edit:I realise I am getting the following warning: Warning: Pattern match(es) are overlapped In the definition of `show': show - = ... I still don't know why it overlaps, or how to stop it.

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PHP create page as a string after PHP runs

- by John

I'm stuck on how to write the test.php page result (after php has run) to a string: testFunctions.php: <?php function htmlify($html, $format){ if ($format == "print"){ $html = str_replace("<", "<", $html); $html = str_replace(">", ">", $html); $html = str_replace(" ", "&nbsp;", $html); $html = nl2br($html); return $html; } }; $input = <<<HTML <div style="background color:#959595; width:400px;">  <br> input <b>text</b> <br>  </div> HTML; function content($input, $mode){ if ($mode =="display"){ return $input; } else if ($mode =="source"){ return htmlify($input, "print"); }; }; function pagePrint($page){ $a = array( 'file_get_contents' => array($page), 'htmlify' => array($page, "print") ); foreach($a as $func=>$args){ $x = call_user_func_array($func, $args); $page .= $x; } return $page; }; $file = "test.php"; ?> test.php: <?php include "testFunctions.php"; ?> <br><hr>here is the rendered html:<hr> <?php $a = content($input, "display"); echo $a; ?> <br><hr>here is the source code:<hr> <?php $a = content($input, "source"); echo $a; ?> <br><hr>here is the source code of the entire page after the php has been executed:<hr> <div style="margin-left:40px; background-color:#ebebeb;"> <?php $a = pagePrint($file); echo $a; ?> </div> I'd like to keep all the php in the testFunctions.php file, so I can place simple function calls into templates for html emails. Thanks!

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Selenium selected option in dropdown not displayed correctly

- by luckyfool

I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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Globals across modules

- by Coder1

Wow, this seems so basic, but I can't get it to work. All I need to do is store a global dict which can be accessed and modified from other modules & threads. What's the "best practices" way of achieving this? test.py import testmodule class MyClassA(): def __init__(self, id): self.id = id if __name__ == '__main__': global classa_dict classa_dict = {} classa_dict[1] = MyClassA(1) classa_dict[2] = MyClassA(2) testing = testmodule.TestModule() testmodule.py class TestModule(): def __init__(self): global classa_dict print classa_dict[2] output $ python test.py Traceback (most recent call last): File "test.py", line 13, in <module> testing = testmodule.TestModule() File "/path/to/project/testmodule.py", line 4, in __init__ print classa_dict[2] NameError: global name 'classa_dict' is not defined

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Searching for duplicate records within a text file where the duplicate is determined by only two fie

- by plg

First, Python Newbie; be patient/kind. Next, once a month I receive a large text file (think 7 Million records) to test for duplicate values. This is catalog information. I get 7 fields, but the two I'm interested in are a supplier code and a full orderable part number. To determine if the record is dupliacted, I compress all special characters from the part number (except . and #) and create a compressed part number. The test for duplicates becomes the supplier code and compressed part number combination. This part is fairly straight forward. Currently, I am just copying the original file with 2 new columns (compressed part and duplicate indicator). If the part is a duplicate, I put a "YES" in the last field. Now that this is done, I want to be able to go back (or better yet, at the same time) to get the previous record where there was a supplier code/compressed part number match. So far, my code looks like this: Compress Full Part to a Compressed Part and Check for Duplicates on Supplier Code and Compressed Part combination import sys import re import time ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ start=time.time() try: file1 = open("C:\Accounting\May Accounting\May.txt", "r") except IOError: print sys.stderr, "Cannot Open Read File" sys.exit(1) try: file2 = open(file1.name[0:len(file1.name)-4] + "_" + "COMPRESSPN.txt", "a") except IOError: print sys.stderr, "Cannot Open Write File" sys.exit(1) hdrList="CIGSUPPLIER|FULL_PART|PART_STATUS|ALIAS_FLAG|ACQUISITION_FLAG|COMPRESSED_PART|DUPLICATE_INDICATOR" file2.write(hdrList+chr(10)) lines_seen=set() affirm="YES" records = file1.readlines() for record in records: fields = record.split(chr(124)) if fields[0]=="CIGSupplier": continue #If incoming file has a header line, skip it file2.write(fields[0]+"|"), #Supplier Code file2.write(fields[1]+"|"), #Full_Part file2.write(fields[2]+"|"), #Part Status file2.write(fields[3]+"|"), #Alias Flag file2.write(re.sub("[$\r\n]", "", fields[4])+"|"), #Acquisition Flag file2.write(re.sub("[^0-9a-zA-Z.#]", "", fields[1])+"|"), #Compressed_Part dupechk=fields[0]+"|"+re.sub("[^0-9a-zA-Z.#]", "", fields[1]) if dupechk not in lines_seen: file2.write(chr(10)) lines_seen.add(dupechk) else: file2.write(affirm+chr(10)) print "it took", time.time() - start, "seconds." ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ file2.close() file1.close() It runs in less than 6 minutes, so I am happy with this part, even if it is not elegant. Right now, when I get my results, I import the results into Access and do a self join to locate the duplicates. Loading/querying/exporting results in Access a file this size takes around an hour, so I would like to be able to export the matched duplicates to another text file or an Excel file. Confusing enough? Thanks.

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How to call a Zend lucene search function?

- by stef

I inherited a Zend project devoid of comments and I didn't get to talk to the previous developer. Since I have no Zend experience I'm having some issues :) I'd like to print out some variables inside an function that indexes items from the site using Zend_Search_Lucene because I think something is going wrong here. From what I've read, ::create creates a new index and ::open updates it. So it's in this ::open function I'd like to print out some variables. The name and params of the function are below. Does anyone have any idea how this function can be called so I can run some tests? private function search($category,$string,$page = 1,$itemsByPage = 5) EDIT: OR, is there a way I can nuke the existing index and force it to be rebuilt completely, for example by deleting the index files on the FS and then performing some searches?

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Why are these strings escaping from my regular expression in python?

- by dohkoxar

In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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Basic Python While loop compound conditional evaluation

- by dbjohn

In Python IDLE Shell it seems I cannot use a compound conditional expression and a while loop. I tried it within brackets too. k=0 m=0 while k<10 & m<10: print k k +=1 m+=1 If I write while k<10: print k k+=1 This does work. Is there a way I could achieve the first block of code with the "and" operator. I have done it in Java. Do I just need to put together "if" statements to achieve the same functionality in Python?

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php cron jobs overlapping

- by naveen gupta

Hi I wrote few months back a script in perl for checking overlapping of jobs use Fcntl ':flock'; INIT { my $waitcount=12; # possible attemtps to run script my $waitseconds=300; # wait for $waitseconds each attempt my $lockstatus=0;#no lock was attained while ($waitcount > 0){ if (open LH, $0){ while ($waitcount > 0){ if (flock LH, LOCK_EX|LOCK_NB){ $waitcount=0;#signal end of waiting $lockstatus=1;#lock was attained } else{ --$waitcount;#decrement waitcount print "waiting to be able to lock $0\n"; sleep $waitseconds; }#end else }#end while }#end if else{ --$waitcount;#decrement waitcount print "waiting to be able to open $0\n"; sleep $waitseconds; }#end else }#end while if ($lockstatus == 0){ die "no lock was attained\n"; }#end if } I wanted to know if we can do similar thing in php .. How to integrate with your current php code which is running a part of php jobs?

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perl: added hash entry in a subroutine is lost

- by hansi

Why is the hash empty on the second call of printHash? my %hash = (); addToHash(\%hash); printHash(\%hash); sub addToHash { my %hash = %{$_[0]}; $hash{"test"} = "test"; printHash(\%hash); } sub printHash { print "printHash: \n"; my %hash = %{$_[0]}; foreach my $key (keys %hash) { print "key: $key, value: $hash{$key}\n"; } } Output: printHash: key: test, value: test printHash:

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AWK: how to reuse a result NR-times without removing END?

- by HH

How can I get all differences, not just one? I want to use the calculated result for each item in the third column. The dilemma is that if I remove END I can print $3 but cannot have ave. If I leave END I have ave but not all differences. awk '{sum+=$3} END {ave=sum/NR} END {print $3-ave}' coriolis_data -0.00964 // I want to see the rest differences, how? coriolis_data .105 0.005 0.9766 0.0001 0.595 0.005 .095 0.005 0.9963 0.0001 0.595 0.005 .115 0.005 0.9687 0.0001 0.595 0.005 .105 0.005 0.9693 0.0001 0.595 0.005 .095 0.005 0.9798 0.0001 0.595 0.005 .105 0.005 0.9798 0.0001 0.595 0.005 .095 0.005 0.9711 0.0001 0.595 0.005 .110 0.005 0.9640 0.0001 0.595 0.005 .105 0.005 0.9704 0.0001 0.595 0.005 .090 0.005 0.9644 0.0001 0.595 0.005

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can i changed for loop index variable inside the loop in Matlab???

- by shawana

hi every one. i need to change my loop variable inside the iterationa as ihave to acces array elements in the loop which is changing w.r.t size inside the loop. ashort piece of code is that: que=[]; que=[2,3,4]; global len; len=size(que,2) x=4; for i=1:len if x<=10 que(x)= 5; len=size(que,2) x=x+1; end end que array should print like: 2 3 4 5 5 5 5 5 5 5 but it is printed in such a way: 2 3 4 5 5 5. how shuould it be accomplished in matlab? in visual c++ it happen correctly and print whole array of 10 elements which increases at run time plz reply me if have any ideaabout this as i m new into matlab

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Wait until a webpage finished loading to load the next one in a list

- by envy

Hi! I'm using PyQT webView to visit some webpages I have stored on a dictionary the code is something like this: def loadLink(self, url): manager = QNetworkAccessManager() request = QNetworkRequest(QUrl(url)) self.ui.webView.load(QUrl(visitar)) def readUnreadLinks(self): print "Links to read: " + str(len(self.unreadLinks)) for link in self.unreadLinks: print "link-> " + str(link) self.loadLink(link) the problem is it doesn't wait until finished loading the web page and starts loading the next one. I want to load a webpage, wait until it finished loading and then load the next one. Thanks, this is driving me crazy :)

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kmeans based on mapreduce by python

- by user3616059

I am going to write a mapper and reducer for the kmeans algorithm, I think the best course of action to do is putting the distance calculator in mapper and sending to reducer with the cluster id as key and coordinates of row as value. In reducer, updating the centroids would be performed. I am writing this by python. As you know, I have to use Hadoop streaming to transfer data between STDIN and STOUT. according to my knowledge, when we print (key + "\t"+value), it will be sent to reducer. Reducer will receive data and it calculates the new centroids but when we print new centroids, I think it does not send them to mapper to calculate new clusters and it just send it to STDOUT and as you know, kmeans is a iterative program. So, my questions is whether Hadoop streaming suffers of doing iterative programs and we should employ MRJOB for iterative programs?

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How can I mix command line arguments and filenames for <> in Perl?

- by Jimmeh

Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input; I run it from a terminal like: perl myprog.pl sample_argument And get this error: Can't open sample_argument: No such file or directory at myprog.pl line 5. Any ideas why this is? When it gets to the < is it trying to read from the (non-existent) file, "sample_argument" or something? And why?

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Replacing backslashes in Python strings

- by user323659

I have some code to encrypt some strings in Python. Encrypted text is used as a parameter in some urls, but after encrypting, there comes backslashes in string and I cannot use single backslash in urllib2.urlopen. I cannot replace single backslash with double. For example: print cipherText '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' print cipherText.replace('\\','\\\\') '\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb' Also putting r in front of \ in replace statement did not worked. All I want to do is calling that kind of url: http://awebsite.me/main?param="\t3-@\xab7+\xc7\x93H\xdc\xd1\x13G\xe1\xfb" And also this url can be successfully called: http://awebsite.me/main?param="\\t3-@\\xab7+\\xc7\\x93H\\xdc\\xd1\\x13G\\xe1\\xfb" Any idea will be appreciated.

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Windows Service Printing Behaviour

- by Andre

Alright, I was tasked to develop a Windows Service that listens to a directory for files that are dropped in it, read them, delete them and print out a report. I installed the service on my work laptop (Win 7 x86) and a test machine (XP x86) under a User account at first. It would do everything as it should except the print the report. No errors, nothing. Then I made it run under Local System and it produced a "No printers found" exception. Converting the app to a Console Application and running on these machines gave the desired result. OK, so now I was assuming that there are security "stuff" involved. Then I installed the service on a Server 2008 x64 machine (under Local System) and it just worked. Can anybody explain to me why this is happening? Why does the service allow printing from Server OS but not from a Desktop OS or am I missing something very obvious?

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Using methods on 2 input files - 2nd is printing multiple times - Java

- by Aaa

I have the following code to read in text, store in a hashmap as bigrams (with other methods to sort them by frequency and do v. v. basic additive smoothing. I had it working great for one language input file (english) and then I want to expand it for the second language input file (japanese - doens;t matter what it is I suppose) using the same methods but the Japanese bigram hashmap is printing out 3 times in a row with diff. values. I've tried using diff text in the input file, making sure there are no gaps in text etc. I've also put print statements at certain places in the Japanese part of the code to see if I can get any clues but all the print statements are printing each time so I can't work out if it is looping at a certain place. I have gone through it with a fine toothcomb but am obviously missing something and slowly going crazy here - any help would be appreciated. thanks in advance... package languagerecognition2; import java.lang.String; import java.io.InputStreamReader; import java.util.*; import java.util.Iterator; import java.util.List.*; import java.util.ArrayList; import java.util.AbstractMap.*; import java.lang.Object; import java.io.*; import java.util.Enumeration; import java.util.Arrays; import java.lang.Math; public class Main { /** public static void main(String[] args) { //training English ----------------------------------------------------------------- File file = new File("english1.txt"); StringBuffer contents = new StringBuffer(); BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(file)); String test = null; //test = reader.readLine(); // repeat until all lines are read while ((test = reader.readLine()) != null) { test = test.toLowerCase(); char[] charArrayEng = test.toCharArray(); HashMap<String, Integer> hashMapEng = new HashMap<String, Integer>(bigrams(charArrayEng)); LinkedHashMap<String, Integer> sortedListEng = new LinkedHashMap<String, Integer>(sort(hashMapEng)); int sizeEng=sortedListEng.size(); System.out.println("Total count of English bigrams is " + sizeEng); LinkedHashMap<String, Integer> smoothedListEng = new LinkedHashMap<String, Integer>(smooth(sortedListEng, sizeEng)); //print linkedHashMap to check values Set set= smoothedListEng.entrySet(); Iterator iter = set.iterator ( ) ; System.out.println("Beginning English"); while ( iter.hasNext()) { Map.Entry entry = ( Map.Entry ) iter.next ( ) ; Object key = entry.getKey ( ) ; Object value = entry.getValue ( ) ; System.out.println( key+" : " + value); } System.out.println("End English"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader != null) { reader.close(); } } catch (IOException e) { e.printStackTrace(); } } //End training English----------------------------------------------------------- //Training japanese-------------------------------------------------------------- File file2 = new File("japanese1.txt"); StringBuffer contents2 = new StringBuffer(); BufferedReader reader2 = null; try { reader2 = new BufferedReader(new FileReader(file2)); String test2 = null; //repeat until all lines are read while ((test2 = reader2.readLine()) != null) { test2 = test2.toLowerCase(); char[] charArrayJap = test2.toCharArray(); HashMap<String, Integer> hashMapJap = new HashMap<String, Integer>(bigrams(charArrayJap)); //System.out.println( "bigrams stage"); LinkedHashMap<String, Integer> sortedListJap = new LinkedHashMap<String, Integer>(sort(hashMapJap)); //System.out.println( "sort stage"); int sizeJap=sortedListJap.size(); //System.out.println("Total count of Japanese bigrams is " + sizeJap); LinkedHashMap<String, Integer> smoothedListJap = new LinkedHashMap<String, Integer>(smooth(sortedListJap, sizeJap)); System.out.println( "smooth stage"); //print linkedHashMap to check values Set set2= smoothedListJap.entrySet(); Iterator iter2 = set2.iterator(); System.out.println("Beginning Japanese"); while ( iter2.hasNext()) { Map.Entry entry2 = ( Map.Entry ) iter2.next ( ) ; Object key = entry2.getKey ( ) ; Object value = entry2.getValue ( ) ; System.out.println( key+" : " + value); }//end while System.out.println("End Japanese"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader2 != null) { reader2.close(); } } catch (IOException e) { e.printStackTrace(); } } //end training Japanese--------------------------------------------------------- } //end main (inner)

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im writing this code so the user would enter his/her name and followed by his/her marks to get the a

- by WM

What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

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Assistance with regular expressions in Python

- by da5id

I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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how could it works if function is called before it is defined in python?

- by user2131316

I was wondering what does if __name__ == "__main__": really do in python, I have the following code in python3: def main(): test(); def test(): print("hello world " + __name__); if __name__ == "__main__": main(); we know that we have to declare a function before we use it, so function call inside of if part works fine, the main() is defined before it is called inside of if statement, but what about the test() function, it is defined after it is called and there is no errors: def main(): test(); def test(): print("hello world " + __name__); so how could it works if the test() function is defined after it is called?

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How to calculate median of a Map<Int,Int>?

- by Chris

For a map where the key represents a number of a sequence and the value the count how often this number appeared in the squence, how would an implementation of an algorithm in java look like to calculate the median? For example: 1,1,2,2,2,2,3,3,3,4,5,6,6,6,7,7 in a map: Map<Int,Int> map = ... map.put(1,2) map.put(2,4) map.put(3,3) map.put(4,1) map.put(5,1) map.put(6,3) map.put(7,2) double median = calculateMedian(map); print(median); would result in: > print(median); 3 > So what i am looking for is a java implementation of calculateMedian.

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How to test a regex password in Python?

- by jCuga

Using a regex in Python, how can I verify that a user's password is: At least 8 characters Must be restricted to, though does not specifically require any of: uppercase letters: A-Z lowercase letters: a-z numbers: 0-9 any of the special characters: @#$%^&+= Note, all the letter/number/special chars are optional. I only want to verify that the password is at least 8 chars in length and is restricted to a letter/number/special char. It's up to the user to pick a stronger / weaker password if they so choose. So far what I have is: import re pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$" password = raw_input("Enter string to test: ") result = re.findall(pattern, password) if (result): print "Valid password" else: print "Password not valid"

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Does template class/function specialization improves compilation/linker speed?

- by Stormenet

Suppose the following template class is heavily used in a project with mostly int as typename and linker speed is noticeably slower since the introduction of this class. template <typename T> class MyClass { void Print() { std::cout << m_tValue << std::endl;; } T m_tValue; } Will defining a class specialization benefit compilation speed? eg. void MyClass<int>::Print() { std::cout << m_tValue << std::endl; }

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