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  • create variable from array actionscript 3

    - by steve
    I'm currently trying to make a dynamic menu via an array and a loop. So when someone clicks on the first item of the array, "menu_bag_mc" it will link to the content "menu_bag_mc_frame" (or some name that will be unique to this array) that is another movieclip that will load. Below is the code I have so far: //right here, i need to make a variable that I can put in the "addchild" so that //for every one of the list items clicked, it adds a movieclip child with //the same name (such as menu_bag_mc from above) with "_frame" appended. //I tried the next line out, but it doesn't really work. var framevar:MovieClip = menuList[i] += "_frame"; function createContent(event:MouseEvent):void { if(MovieClip(root).currentFrame == 850) { while(MovieClip(root).numChildren > 1) { MovieClip(root).removeChild(MovieClip(root).getChildAt(MovieClip(root).numChildren - 1)); } //Here is where the variable would go, to add a child directly related //to whichever array item was clicked (here, "framevar") MovieClip(root).addChild (framevar); MovieClip(root).addChild (closeBtn); } else { MovieClip(root).addChild (framevar); MovieClip(root).addChild (closeBtn); MovieClip(root).gotoAndPlay(806); } } Is there a way to make a unique variable (whatever it is) from the array so that I can name a movieclip after it so it will load the new movieclip? Thanks

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  • Create MVC 5 Combo Box from CRM Entities?

    - by SpaceCowboy74
    I am working on an MVC 5 App that pulls data from Dynamics CRM 5. The Data I am getting back is an IQueryable of type Account (The CRM Entity class auto generated by CrmSvcUtil). I am retrieving all of the items and can loop through them with code like this: @foreach (var item in Model.ToList()) { <tr> <td> @item.AccountId </td> <td> @Html.DisplayFor(modelItem => item.Name) </td> </tr> } The problem is, I would like to instead put them in a drop down list. I can't figure out what the syntax is to put these in a DropDown is. Any suggestions?

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  • Create top ten list

    - by newtech
    I'm trying to build an iPhone app where I have a list of names, and can search by year to find the top ten names for that year. How would I need to set that up in xcode?

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  • Create Macro With Several Variables

    - by Daniel
    I have several worksheets with similar code, so I'd like to turn it into a macro. My only problem is that there are several variables. So at certain points the code looks like this: Dim Msg_1 As String Dim Msg_2 As String Public Sub ListBox1_LostFocus() ListBox1.Height = 15 With ListBox1 Msg1 = "'" For i = 0 To .ListCount - 1 If .Selected(i) Then Msg1 = Msg1 & .List(i) & "','" End If Next i End With Msg1 = Left(Msg1, Len(Msg1) - 2) Sheets("Sheet1").Range("R3", "R3") = Msg1 End Sub and so on. How can I pass in a new value for Msg1, Msg2, Msg3 for each worksheet?

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  • How to create HTML tables from MySQL?

    - by Chris
    Hi Guys, I'm building a part of a system where the user can define "views" from a mysql database. I want some way of generating simple HTML tables/reports from the data, but not just plain output of sql queries- simple joins probably isn't enough. Any ideas?

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  • Create a custom button

    - by Beppi Menozzi
    Sorry if this is too basic. I created a new class that extends Button: public class MyButton extends Button { private Context ctx; public MyButton(Context context) { super(context); ctx = context; } private void click() { // DO WHAT I NEED (FOR EXAMPLE CHANGE BACKGROUND) } } How can make it possible that, when I setOnClickListener() from another class where I instantiated this object, the click() method is called automatically? Thanks.

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  • Best way to create 100% width middle column with css

    - by nick
    Hey everyone, I have a pretty standard css layout where I use a container div that is 980px wide to hold everything. The only problem is that I want to have a 1900px wide banner half way down the page that is centered in the middle and is 100% width of the page. Is there any way to do this without getting rid of the container div? so I am wanting ____________________ | | | | | | | | | | | | |___| |___| | | | | |___ ___| | | | | | | | | | | | | | | | | |___|___________|___| < 980px > container < 100% page width > Anyone know how to get that 1900px banner centered in the middle without deleting my container div? THANKS!!

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  • How to create many div's with 100% height?

    - by ChrisBenyamin
    I need a html document, that contains multiple div's with 100% height (screen filling) one below the other. I have tried to apply every element a height of 100%, but that won't work seamless nor clean. Maybe there is a option with JavaScript? I don't have an idea. Please suggest me your solutions. chris

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  • Where can I find fellow developers who are looking for help to create a startup?

    - by Jeremy Child
    Where can I find fellow developers who are looking for help to create a startup? Are there any collaboration websites whereby people pitch ideas and a group of people 'join' the project in an effort to create some kind of prototype? Edit: @Vitor Braga - Seriously i'm not looking to make money, just finding developers who are interested in making a trivial little app with someone else. Edit: It may be worthy to explain that I live in a remote area of Australia.

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  • How to create a user with root privileges in bash?

    - by George Edison
    I have run the following commands: sudo groupadd -r testgroup sudo useradd -g testgroup -M -r testuser Notice the -r option, which according to the man page: -r     Create a system account. Assuming I have a user account with root privileges, I then run: sudo -u testuser cat /dev/input/mouse0 However, I get: cat: /dev/input/mouse0: Permission denied Running the same command as root provides the expected output (garbled output from the mouse driver). How can I create a user with root privileges?

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  • Script to create or drop all primary keys now on TechNet Wiki.

    - by John Paul Cook
    I posted my script to create or drop all primary keys on the TechNet Wiki. You can find it at http://social.technet.microsoft.com/wiki/contents/articles/script-to-create-or-drop-all-primary-keys.aspx . I first published the script here in 2009 and I've always wanted a way for the community to enhance it or correct it. The TechNet Wiki makes that possible. Visit the Wiki and see if you like this approach to publishing scripts....(read more)

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  • When is it reasonable to create my own programming language?

    - by Daniel Rikowski
    Are there types of killer applications, classes of algorithmic problems, etc., where it is better, in the long run, to create my own language? PS: Just to be sure, I mean a new programming language and a compiler, not a new compiler for an existing language. EDIT: Thank you for the answers. Can you provide some examples, where it is absolutly unnecessary to create a DSL or cases in which a DSL might be a good idea?

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  • How to create conditional If / Else logic in a BizTalk map.

    How to create conditional logic in a BizTalk map using out of the box functoids. Example takes in a Xml file containing Films and their receipts and create a destination file whose structure id dependent on the incoming data.  read moreBy BiZTech KnowDid you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • How to create a wifi hotspot in ubuntu 12.04 and use it on WP7.5?

    - by VPCEB14EN
    I have been trying for many days to create a wifi hotspot with my laptop running ubuntu 12.04 and connect it to my windows phone7.5 based HTC Mozart. I have gone through many articles related to this, but none of them help. I create a wifi hotspot as suggested by some experts, but it isn't detected either by my phone or on other laptops. My laptop is Sony Vaio VPCEB14EN with these specifications .

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  • MySQL Privileges required to GRANT EVENT, EXECUTE, LOCK TABLES, and TRIGGER

    - by Brad
    I have an account, user_a, and I would like to grant all available permissions on some_db to user_b. I have tried the following query: GRANT ALTER, ALTER ROUTINE, CREATE, CREATE ROUTINE, CREATE TEMPORARY TABLES, CREATE VIEW, DELETE, DROP, EVENT, EXECUTE, INDEX, INSERT, LOCK TABLES, REFERENCES, SELECT, SHOW VIEW, TRIGGER, UPDATE ON `some_db`.* TO 'user_b'@'%' WITH GRANT OPTION The result: Access denied for user 'user_a'@'%' to database 'some_db' Some experimentation has shown me that the only permissions my account (user_a) is unable to grant are EVENT, EXECUTE, LOCK TABLES, and TRIGGER. What privileges are required for my account to GRANT these privileges to another user? If I run SHOW GRANTS, I get this output: "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, SHOW DATABASES, SUPER, CREATE TEMPORARY TABLES, REPLICATION SLAVE, REPLICATION CLIENT, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE, CREATE USER ON *.* TO 'user_a'@'%' IDENTIFIED BY PASSWORD '1234567890abcdef' WITH GRANT OPTION" "GRANT SELECT, INSERT, UPDATE, DELETE, EXECUTE ON `some_other_unrelated_db`.* TO 'user_a'@'%'" "GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, REFERENCES, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES, EXECUTE, CREATE ROUTINE, ALTER ROUTINE ON `another_unrelated_db`.* TO 'user_a'@'%' WITH GRANT OPTION"

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  • Raid1+0: create stripe over two /dev/mdx on partition or not?

    - by Chris
    Given that I haven't found a way to define how a Raid10 is created with mdadm, i went the Raid1+0 solution. How to display/define Mirror/Stripping pairs with mdadm mdadm --create /dev/md0 --level=1 --raid-devices=2 /dev/sda1 /dev/sdf1 mdadm --create /dev/md1 --level=1 --raid-devices=2 /dev/sdg1 /dev/sdh1 mdadm --create /dev/md10 --level=0 --raid-devices=2 /dev/md0 /dev/md1 My question is about the stripe. For the mirror I create a primary partition over the full HD and set partition type to FD. So, should I do the same for the Stripe? Create partition on /dev/md0 and /dev/md1 (primary over full 'HDD', set partition type correctly) and then do the stripe on the partition? Is there a correct way here or are there any advantages/disadvantages to a solution? Thank you

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  • After creating a mysql user with all privileges, the user cannot create databases in phpMyAdmin and only sees information_schema table

    - by GHarping
    This is a recurring problem for some reason... Using mysql 5.5, I am simply trying to create a user that can connect to the database remotely, have access to all databases, and create databases. I have created a user using: create user 'dev'@'%' identified by 'abcdefg'; then granted all permissions using: GRANT ALL ON *.* to 'dev'@'192.168.%' IDENTIFIED BY 'abcdefg' WITH GRANT OPTION; and the result is that the user cannot create databases, and can only see information_schema database for some reason. Databases Create database: Documentation No Privileges Database Ascending information_schema Total: 1 Does anyone know why this might be happening?

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  • Using a WPF ListView as a DataGrid

    - by psheriff
    Many people like to view data in a grid format of rows and columns. WPF did not come with a data grid control that automatically creates rows and columns for you based on the object you pass it. However, the WPF Toolkit can be downloaded from CodePlex.com that does contain a DataGrid control. This DataGrid gives you the ability to pass it a DataTable or a Collection class and it will automatically figure out the columns or properties and create all the columns for you and display the data.The DataGrid control also supports editing and many other features that you might not always need. This means that the DataGrid does take a little more time to render the data. If you want to just display data (see Figure 1) in a grid format, then a ListView works quite well for this task. Of course, you will need to create the columns for the ListView, but with just a little generic code, you can create the columns on the fly just like the WPF Toolkit’s DataGrid. Figure 1: A List of Data using a ListView A Simple ListView ControlThe XAML below is what you would use to create the ListView shown in Figure 1. However, the problem with using XAML is you have to pre-define the columns. You cannot re-use this ListView except for “Product” data. <ListView x:Name="lstData"          ItemsSource="{Binding}">  <ListView.View>    <GridView>      <GridViewColumn Header="Product ID"                      Width="Auto"               DisplayMemberBinding="{Binding Path=ProductId}" />      <GridViewColumn Header="Product Name"                      Width="Auto"               DisplayMemberBinding="{Binding Path=ProductName}" />      <GridViewColumn Header="Price"                      Width="Auto"               DisplayMemberBinding="{Binding Path=Price}" />    </GridView>  </ListView.View></ListView> So, instead of creating the GridViewColumn’s in XAML, let’s learn to create them in code to create any amount of columns in a ListView. Create GridViewColumn’s From Data TableTo display multiple columns in a ListView control you need to set its View property to a GridView collection object. You add GridViewColumn objects to the GridView collection and assign the GridView to the View property. Each GridViewColumn object needs to be bound to a column or property name of the object that the ListView will be bound to. An ADO.NET DataTable object contains a collection of columns, and these columns have a ColumnName property which you use to bind to the GridViewColumn objects. Listing 1 shows a sample of reading and XML file into a DataSet object. After reading the data a GridView object is created. You can then loop through the DataTable columns collection and create a GridViewColumn object for each column in the DataTable. Notice the DisplayMemberBinding property is set to a new Binding to the ColumnName in the DataTable. C#private void FirstSample(){  // Read the data  DataSet ds = new DataSet();  ds.ReadXml(GetCurrentDirectory() + @"\Xml\Product.xml");    // Create the GridView  GridView gv = new GridView();   // Create the GridView Columns  foreach (DataColumn item in ds.Tables[0].Columns)  {    GridViewColumn gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.ColumnName);    gvc.Header = item.ColumnName;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   // Setup the GridView Columns  lstData.View = gv;  // Display the Data  lstData.DataContext = ds.Tables[0];} VB.NETPrivate Sub FirstSample()  ' Read the data  Dim ds As New DataSet()  ds.ReadXml(GetCurrentDirectory() & "\Xml\Product.xml")   ' Create the GridView  Dim gv As New GridView()   ' Create the GridView Columns  For Each item As DataColumn In ds.Tables(0).Columns    Dim gvc As New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.ColumnName)    gvc.Header = item.ColumnName    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   ' Setup the GridView Columns  lstData.View = gv  ' Display the Data  lstData.DataContext = ds.Tables(0)End SubListing 1: Loop through the DataTable columns collection to create GridViewColumn objects A Generic Method for Creating a GridViewInstead of having to write the code shown in Listing 1 for each ListView you wish to create, you can create a generic method that given any DataTable will return a GridView column collection. Listing 2 shows how you can simplify the code in Listing 1 by setting up a class called WPFListViewCommon and create a method called CreateGridViewColumns that returns your GridView. C#private void DataTableSample(){  // Read the data  DataSet ds = new DataSet();  ds.ReadXml(GetCurrentDirectory() + @"\Xml\Product.xml");   // Setup the GridView Columns  lstData.View =      WPFListViewCommon.CreateGridViewColumns(ds.Tables[0]);  lstData.DataContext = ds.Tables[0];} VB.NETPrivate Sub DataTableSample()  ' Read the data  Dim ds As New DataSet()  ds.ReadXml(GetCurrentDirectory() & "\Xml\Product.xml")   ' Setup the GridView Columns  lstData.View = _      WPFListViewCommon.CreateGridViewColumns(ds.Tables(0))  lstData.DataContext = ds.Tables(0)End SubListing 2: Call a generic method to create GridViewColumns. The CreateGridViewColumns MethodThe CreateGridViewColumns method will take a DataTable as a parameter and create a GridView object with a GridViewColumn object in its collection for each column in your DataTable. C#public static GridView CreateGridViewColumns(DataTable dt){  // Create the GridView  GridView gv = new GridView();  gv.AllowsColumnReorder = true;   // Create the GridView Columns  foreach (DataColumn item in dt.Columns)  {    GridViewColumn gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.ColumnName);    gvc.Header = item.ColumnName;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   return gv;} VB.NETPublic Shared Function CreateGridViewColumns _  (ByVal dt As DataTable) As GridView  ' Create the GridView  Dim gv As New GridView()  gv.AllowsColumnReorder = True   ' Create the GridView Columns  For Each item As DataColumn In dt.Columns    Dim gvc As New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.ColumnName)    gvc.Header = item.ColumnName    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   Return gvEnd FunctionListing 3: The CreateGridViewColumns method takes a DataTable and creates GridViewColumn objects in a GridView. By separating this method out into a class you can call this method anytime you want to create a ListView with a collection of columns from a DataTable. SummaryIn this blog you learned how to create a ListView that acts like a DataGrid. You are able to use a DataTable as both the source of the data, and for creating the columns for the ListView. In the next blog entry you will learn how to use the same technique, but for Collection classes. NOTE: You can download the complete sample code (in both VB and C#) at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "WPF ListView as a DataGrid" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free eBook on "Fundamentals of N-Tier".

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