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  • On Android, app jumps back to default Page on orientation change

    - by SteAp
    I tested my Xamarin.Forms app on iOS and Android and found this difference when I change the orientation of the mobile device: On iOS, the app keeps the current page On Android, the app seems to restart using the default page (or probably pop all pages except the first one). Since I've never seen this behavior in another Android app, I'd like to disable it. Moreover, I don't think that this behavior is Android default. Which property do I need to set the make the Android target behave as the iOS target?

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  • WPF/INotifyPropertyChanged, change the value of txtA, the txtB and txtC should change automatically?

    - by user1033098
    I supposed, once i change the value of txtA, the txtB and txtC would change automatically, since i have implemented INotifyPropertyChanged for ValueA. But they were not updated on UI. txtB was always 100, and txtC was always -50. I don't know what's the reason. My Xaml.. <Window x:Class="WpfApplicationReviewDemo.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="MainWindow" Height="350" Width="525"> <StackPanel> <TextBox Name="txtA" Text="{Binding ValueA}" /> <TextBox Name="txtB" Text="{Binding ValueB}" /> <TextBox Name="txtC" Text="{Binding ValueC}" /> </StackPanel> </Window> My code behind... public partial class MainWindow : Window { public MainWindow() { InitializeComponent(); this.DataContext = new Model(); } } public class Model : INotifyPropertyChanged { private decimal valueA; public decimal ValueA { get { return valueA; } set { valueA = value; PropertyChanged(this, new PropertyChangedEventArgs("ValueA")); } } private decimal valueB; public decimal ValueB { get { valueB = ValueA + 100; return valueB; } set { valueB = value; PropertyChanged(this, new PropertyChangedEventArgs("ValueB")); } } private decimal valueC; public decimal ValueC { get { valueC = ValueA - 50; return valueC; } set { valueC = value; PropertyChanged(this, new PropertyChangedEventArgs("ValueC")); } } #region INotifyPropertyChanged Members public event PropertyChangedEventHandler PropertyChanged; #endregion } After i add code to the set method of ValueA property, it works. public decimal ValueA { get { return valueA; } set { valueA = value; PropertyChanged(this, new PropertyChangedEventArgs("ValueA")); PropertyChanged(this, new PropertyChangedEventArgs("ValueB")); PropertyChanged(this, new PropertyChangedEventArgs("ValueC")); } } But I supposed it should be automatically refresh/updated for txtB and txtC. Please advise.

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  • change all the label icon in a panel

    - by Josh
    I have a panel with several JLabel, I would like to change all their Icon, String path = System.getProperty("user.dir"); for (int x=0;x< 21;x++) { javax.swing.JLabel lab = boardPanel.getComponent(x).; lab.setIcon(new ImageIcon(path + "\\image\\blank.jpg")); } it gives me an error of incompatible type, all inside the boardPanel are JLabel, im using netbeans 6.8.

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  • file_get_contents to image and change quality

    - by Chris
    Hey I have some code that downloads an image from a remote server $data = file_get_contents("$rURL"); I want to then change the quality of this image, but do not want to save it out to a file first, how do I convert $data into an image that I can then use in imagecopyresampled? Thanks

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  • Change List Settings

    - by Carpentar
    Hello all, I wonder how would I go about doing this. I want to change a behavior for a list. When a list is added into sharepoint site, you can see 'Add New Item' underneath the list. When the user adds a new item, it should be replaced with 'Edit Item' How can I achieve this? Many thanks,

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  • Android - Dealing with a Dialog on Screen Orientation change

    - by Donal Rafferty
    I am overriding the onCreateDialog and onPrepareDialog methods or the Dialog class. I have followed the example from Reto Meier's Professional Android Application Development book, Chapter 5 to pull some XML data and then use a dialog to display the info. I have basically followed it exactly but changed the variables to suit my own XML schema as follows: @Override public Dialog onCreateDialog(int id) { switch(id) { case (SETTINGS_DIALOG) : LayoutInflater li = LayoutInflater.from(this); View settingsDetailsView = li.inflate(R.layout.details, null); AlertDialog.Builder settingsDialog = new AlertDialog.Builder(this); settingsDialog.setTitle("Provisioned Settings"); settingsDialog.setView(settingsDetailsView); return settingsDialog.create(); } return null; } @Override public void onPrepareDialog(int id, Dialog dialog) { switch(id) { case (SETTINGS_DIALOG) : String afpunText = " "; if(setting.getAddForPublicUserNames() == 1){ afpunText = "Yes"; } else{ afpunText = "No"; } String Text = "Login Settings: " + "\n" + "Password: " + setting.getPassword() + "\n" + "Server: " + setting.getServerAddress() + "\n"; AlertDialog settingsDialog = (AlertDialog)dialog; settingsDialog.setTitle(setting.getUserName()); tv = (TextView)settingsDialog.findViewById(R.id.detailsTextView); if (tv != null) tv.setText(Text); break; } } It works fine until I try changing the screen orientation, When I do this onPrepareDialog gets call but I get null pointer exceptions on all my variables. The error still occurs even when I tell my activity to ignore screen orientation in the manifest. So I presume something has been left out of the example in the book do I need to override another method to save my variables in or something?

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  • how can i change the back arrow in navigation toolbar function

    - by jackrobert
    hi i have developed simple web application using jsp... Step 1 : I have one login page : (contains username ,password and sumbit button) Step2 : I have one logout page : it has one link (Go to login page), just u click this link go to login page.. step3 : And i have some pages like (page1,page2,page3, page4.....) Normal application working following way : after login comes page1.. Then click some action and it will go to page2 Then i click some action and it will goto page3 Then i click some action and it will goto page4 So now i am in page4... now click back arrow in navigation toolbar in browser, generally go to previous page (page3). For example... If u seeing gmail inbox msg... that time u click back arrow..then automatically go to previous page.. But i need , if click back arrow in navigation toolbar (from any page in my application) ,then go to logout page... For example.... Suppose i am in page4... here i click backarrow in browser then i want to go logout page, don't go to page3 how to acheive this... Is there any possible....Any javascript or any otherway pls help me...

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  • TimeZone change to UTC while updating the Appointment

    - by Firoz Ansari
    I am using EWS 1.2 to send appointments. On creating new Appointments, TimeZone is showing properly on notification mail, but on updating the same appointment, it's TimeZone reset to UTC. Could anyone help me to fix this issue? Here is sample code to replicate the issue: ExchangeService service = new ExchangeService(ExchangeVersion.Exchange2010_SP1, TimeZoneInfo.FindSystemTimeZoneById("Eastern Standard Time")); service.Credentials = new WebCredentials("ews_calendar", PASSWORD, "acme"); service.Url = new Uri("https://acme.com/EWS/Exchange.asmx"); Appointment newAppointment = new Appointment(service); newAppointment.Subject = "Test Subject"; newAppointment.Body = "Test Body"; newAppointment.Start = new DateTime(2012, 03, 27, 17, 00, 0); newAppointment.End = newAppointment.Start.AddMinutes(30); newAppointment.RequiredAttendees.Add("[email protected]"); //Attendees get notification mail for this appointment using (UTC-05:00) Eastern Time (US & Canada) timezone //Here is the notification content received by attendees: //When: Tuesday, March 27, 2012 5:00 PM-5:30 PM. (UTC-05:00) Eastern Time (US & Canada) newAppointment.Save(SendInvitationsMode.SendToAllAndSaveCopy); // Pull existing appointment string itemId = newAppointment.Id.ToString(); Appointment existingAppointment = Appointment.Bind(service, new ItemId(itemId)); //Attendees get notification mail for this appointment using UTC timezone //Here is the notification content received by attendees: //When: Tuesday, March 27, 2012 11:00 PM-11:30 PM. UTC existingAppointment.Update(ConflictResolutionMode.AlwaysOverwrite, SendInvitationsOrCancellationsMode.SendToAllAndSaveCopy);

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  • Open a dialog box in same window on selectOneMenu change

    - by Pravingate
    I have a jsf page where I have a selectOneMenu and , I want to open a dialog box on selectOneMenu changes. As a example if user selects a value ="passive" from jsf selectOneMenu it should open a dialog box or a light box on same page where I want to display a small jsf form like as here done. http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf and I also want save that submitted data in my backing bean somewhere so I can store it in to database later. I dont know how to open a dialog box or light box from backing bean in same window,as we will identify value change using valueChangeListener event or by using ajax event. I am able to identify which value is selected from selectOneMenu(DropdownMenu), but dont know how to open a dialog box on selecting particular value. <h:outputLabel value="* Country: "/> <h:selectOneMenu id="someSelect" value="#{testController.countryName}" required="true"> <f:selectItem itemLabel="Select Country" itemValue=""/> <f:selectItems value="#{testController.countryNamesSelectItems}"/> </h:selectOneMenu> Supoose we have 2 options in selectItems as India and Austrlia, then If a user choose India a dialog box should open on same page where a user need to fill some information and need to submit if he is from india (like here in example http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf user will put his username and password and submits data) Hope this helps How can I achieve that by using jsf or javascript or ajax or by any else way?

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  • Can Google Employees See My Saved Google Chrome Passwords?

    - by Jason Fitzpatrick
    Storing your passwords in your web browser seems like a great time saver, but are the passwords secure and inaccessible to others (even employees of the browser company) when squirreled away? Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-driven grouping of Q&A web sites. The Question SuperUser reader MMA is curious if Google employees have (or could have) access to the passwords he stores in Google Chrome: I understand that we are really tempted to save our passwords in Google Chrome. The likely benefit is two fold, You don’t need to (memorize and) input those long and cryptic passwords. These are available wherever you are once you log in to your Google account. The last point sparked my doubt. Since the password is available anywhere, the storage must in some central location, and this should be at Google. Now, my simple question is, can a Google employee see my passwords? Searching over the Internet revealed several articles/messages. Do you save passwords in Chrome? Maybe you should reconsider: Talks about your passwords being stolen by someone who has access to your computer account. Nothing mentioned about the central storage security and vulnerability. There is even a response from Chrome browser security tech lead about the first issue. Chrome’s insane password security strategy: Mostly along the same line. You can steal password from somebody if you have access to the computer account. How to Steal Passwords Saved in Google Chrome in 5 Simple Steps: Teaches you how to actually perform the act mentioned in the previous two when you have access to somebody else’s account. There are many more (including this one at this site), mostly along the same line, points, counter-points, huge debates. I refrain from mentioning them here, simply carry a search if you want to find them. Coming back to my original query, can a Google employee see my password? Since I can view the password using a simple button, definitely they can be unhashed (decrypted) even if encrypted. This is very different from the passwords saved in Unix-like OS’s where the saved password can never be seen in plain text. They use a one-way encryption algorithm to encrypt your passwords. This encrypted password is then stored in the passwd or shadow file. When you attempt to login, the password you type in is encrypted again and compared with the entry in the file that stores your passwords. If they match, it must be the same password, and you are allowed access. Thus, a superuser can change my password, can block my account, but he can never see my password. So are his concerns well founded or will a little insight dispel his worry? The Answer SuperUser contributor Zeel helps put his mind at ease: Short answer: No* Passwords stored on your local machine can be decrypted by Chrome, as long as your OS user account is logged in. And then you can view those in plain text. At first this seems horrible, but how did you think auto-fill worked? When that password field gets filled in, Chrome must insert the real password into the HTML form element – or else the page wouldn’t work right, and you could not submit the form. And if the connection to the website is not over HTTPS, the plain text is then sent over the internet. In other words, if chrome can’t get the plain text passwords, then they are totally useless. A one way hash is no good, because we need to use them. Now the passwords are in fact encrypted, the only way to get them back to plain text is to have the decryption key. That key is your Google password, or a secondary key you can set up. When you sign into Chrome and sync the Google servers will transmit the encrypted passwords, settings, bookmarks, auto-fill, etc, to your local machine. Here Chrome will decrypt the information and be able to use it. On Google’s end all that info is stored in its encrpyted state, and they do not have the key to decrypt it. Your account password is checked against a hash to log in to Google, and even if you let chrome remember it, that encrypted version is hidden in the same bundle as the other passwords, impossible to access. So an employee could probably grab a dump of the encrypted data, but it wouldn’t do them any good, since they would have no way to use it.* So no, Google employees can not** access your passwords, since they are encrypted on their servers. * However, do not forget that any system that can be accessed by an authorized user can be accessed by an unauthorized user. Some systems are easier to break than other, but none are fail-proof. . . That being said, I think I will trust Google and the millions they spend on security systems, over any other password storage solution. And heck, I’m a wimpy nerd, it would be easier to beat the passwords out of me than break Google’s encryption. ** I am also assuming that there isn’t a person who just happens to work for Google gaining access to your local machine. In that case you are screwed, but employment at Google isn’t actually a factor any more. Moral: Hit Win + L before leaving machine. While we agree with zeel that it’s a pretty safe bet (as long as your computer is not compromised) that your passwords are in fact safe while stored in Chrome, we prefer to encrypt all our logins and passwords in a LastPass vault. Have something to add to the explanation? Sound off in the the comments. Want to read more answers from other tech-savvy Stack Exchange users? Check out the full discussion thread here.     

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  • JavaOne Session Report: “50 Tips in 50 Minutes for GlassFish Fans”

    - by Janice J. Heiss
    At JavaOne 2012 on Monday, Oracle’s Engineer Chris Kasso, and Technology Evangelist Arun Gupta, presented a head-spinning session (CON4701) in which they offered 50 tips for GlassFish fans. Kasso and Gupta alternated back and forth with each presenting 10 tips at a time. An audience of about (appropriately) 50 attentive and appreciative developers was on hand in what has to be one of the most information-packed sessions ever at JavaOne!Aside: I experienced one of the quiet joys of JavaOne when, just before the session began, I spotted Java Champion and JavaOne Rock Star Adam Bien sitting nearby – Adam is someone I have been fortunate to know for many years.GlassFish is a freely available, commercially supported Java EE reference implementation. The session prioritized quantity of tips over depth of information and offered tips that are intended for both seasoned and new users, that are meant to increase the range of functional options available to GlassFish users. The focus was on lesser-known dimensions of GlassFish. Attendees were encouraged to pursue tips that contained new information for them. All 50 tips can be accessed here.Below are several examples of more elaborate tips and a final practical tip on how to get in touch with these folks. Tip #1: Using the login Command * To execute a remote command with asadmin you must provide the admin's user name and password.* The login command allows you to store the login credentials to be reused in subsequent commands.* Can be logged into multiple servers (distinguish by host and port). Example:     % asadmin --host ouch login     Enter admin user name [default: admin]>     Enter admin password>     Login information relevant to admin user name [admin]     for host [ouch] and admin port [4848] stored at     [/Users/ckasso/.asadminpass] successfully.     Make sure that this file remains protected.     Information stored in this file will be used by     asadmin commands to manage the associated domain.     Command login executed successfully.     % asadmin --host ouch list-clusters     c1 not running     Command list-clusters executed successfully.Tip #4: Using the AS_DEBUG Env Variable* Environment variable to control client side debug output* Exposes: command processing info URL used to access the command:                           http://localhost:4848/__asadmin/uptime Raw response from the server Example:   % export AS_DEBUG=true  % asadmin uptime  CLASSPATH= ./../glassfish/modules/admin-cli.jar  Commands: [uptime]  asadmin extension directory: /work/gf-3.1.2/glassfish3/glassfish/lib/asadm      ------- RAW RESPONSE  ---------   Signature-Version: 1.0   message: Up 7 mins 10 secs   milliseconds_value: 430194   keys: milliseconds   milliseconds_name: milliseconds   use-main-children-attribute: false   exit-code: SUCCESS  ------- RAW RESPONSE  ---------Tip #11: Using Password Aliases * Some resources require a password to access (e.g. DB, JMS, etc.).* The resource connector is defined in the domain.xml.Example:Suppose the DB resource you wish to access requires an entry like this in the domain.xml:     <property name="password" value="secretp@ssword"/>But company policies do not allow you to store the password in the clear.* Use password aliases to avoid storing the password in the domain.xml* Create a password alias:     % asadmin create-password-alias DB_pw_alias     Enter the alias password>     Enter the alias password again>     Command create-password-alias executed successfully.* The password is stored in domain's encrypted keystore.* Now update the password value in the domain.xml:     <property name="password" value="${ALIAS=DB_pw_alias}"/>Tip #21: How to Start GlassFish as a Service * Configuring a server to automatically start at boot can be tedious.* Each platform does it differently.* The create-service command makes this easy.   Windows: creates a Windows service Linux: /etc/init.d script Solaris: Service Management Facility (SMF) service * Must execute create-service with admin privileges.* Can be used for the DAS or instances* Try it first with the --dry-run option.* There is a (unsupported) _delete-serverExample:     # asadmin create-service domain1     The Service was created successfully. Here are the details:     Name of the service:application/GlassFish/domain1     Type of the service:Domain     Configuration location of the service:/work/gf-3.1.2.2/glassfish3/glassfish/domains     Manifest file location on the system:/var/svc/manifest/application/GlassFish/domain1_work_gf-3.1.2.2_glassfish3_glassfish_domains/Domain-service-smf.xml.     You have created the service but you need to start it yourself. Here are the most typical Solaris commands of interest:     * /usr/bin/svcs  -a | grep domain1  // status     * /usr/sbin/svcadm enable domain1 // start     * /usr/sbin/svcadm disable domain1 // stop     * /usr/sbin/svccfg delete domain1 // uninstallTip #34: Posting a Command via REST* Use wget/curl to execute commands on the DAS.Example:  Deploying an application   % curl -s -S \       -H 'Accept: application/json' -X POST \       -H 'X-Requested-By: anyvalue' \       -F id=@/path/to/application.war \       -F force=true http://localhost:4848/management/domain/applications/application* Use @ before a file name to tell curl to send the file's contents.* The force option tells GlassFish to force the deployment in case the application is already deployed.* Use wget/curl to execute commands on the DAS.Example:  Deploying an application   % curl -s -S \       -H 'Accept: application/json' -X POST \       -H 'X-Requested-By: anyvalue' \       -F id=@/path/to/application.war \       -F force=true http://localhost:4848/management/domain/applications/application* Use @ before a file name to tell curl to send the file's contents.* The force option tells GlassFish to force the deployment in case the application is already deployed.Tip #46: Upgrading to a Newer Version * Upgrade applications and configuration from an earlier version* Upgrade Tool: Side-by-side upgrade– GUI: asupgrade– CLI: asupgrade --c– What happens ?* Copies older source domain -> target domain directory* asadmin start-domain --upgrade* Update Tool and pkg: In-place upgrade– GUI: updatetool, install all Available Updates– CLI: pkg image-update– Upgrade the domain* asadmin start-domain --upgradeTip #50: How to reach us?* GlassFish Forum: http://www.java.net/forums/glassfish/glassfish* [email protected]* @glassfish* facebook.com/glassfish* youtube.com/GlassFishVideos* blogs.oracle.com/theaquariumArun Gupta acknowledged that their method of presentation was experimental and actively solicited feedback about the session. The best way to reach them is on the GlassFish user forum.In addition, check out Gupta’s new book Java EE 6 Pocket Guide.

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  • Rails & combo box change event: Help make this obtrusive javascript unobtrusive

    - by DJTripleThreat
    Ok so a friend of mine gave some help with a prototype/obtrusive solution to this but its not quite there. Also, I want to make this unobtrusive instead of using the observe_field function that rails gives me. I don't want to use prototype either because I'm more familiar with JQuery. Here's my problem: I have an Event that can have multiple ServiceTypes and a ServiceType can belong to many Events. A many-to-many relationship between these two exists as an OfferedService. When creating an event, I have a drop down with a list of TimeAllotments that are something like 10 minutes, 12 minutes, 15 minutes, 20 minutes, 30 minutes etc. When the user selects one of these choices, I want a div tag to be filled with a list of ServiceTypes that are associated with this TimeAllotment. So for example, the user selects "10 minutes" and then the div repopulates with services that last 10 minutes. Here is what I have so far: ... some erb code etc and then <fieldset> <legend><%= f.label :time_allotment, "Size of the Appointment Slots:" %></legend> <div> <span class="field-group"> <div> <!-- TimeAllotment is a tabless model which is why this is done like so... --> <%= select("event_service", "time_allotment", TimeAllotment.all.collect {|ta| [ta.title, ta.value]}, {:prompt => true}) %> </div> </span> </div> <div style="clear:both;"></div> Services: <div> <span class="field-group"> <!-- this div right here needs to be repopulated when the above select changes. --> <div id="services"> <% for service_type in ServiceType.all %> <div> <%= check_box_tag "event_service[service_type_ids][]", service_type.id, false %> <%=h service_type.title %> </div> <% end %> </div> </span> </div> <div class="clear"></div> </fieldset> ok so right now ALL of the services are there to be chosen from. I want them to change based on what is selected in the combobox event_service_time_allotment. Can someone help me get pointed in the right direction? I have looked at Ryan's rails casts for using JQuery but its not helpful because he deals with ajax calls for the create action. This would be for the new or edit action. I have a new.js.erb but it doesn't get loaded when calling the new action. I'm super lost as far as getting JQuery to work with my application. I think that if someone can just show me how to make an alert pop up when I change the combo box, and how to return a dataset using ajax the right now, I think I can figure out the rest. Thanks, I know this is super complicated so any helpful answers will get an upvote.

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  • Binding a property to change the listbox items foreground individually for each item

    - by Eyal-Shilony
    I'm trying to change the foreground color of the items in the ListBox individually for each item, I've already posted a similar question but this one is more concrete. I hoped that the state of the color is reserved for each item added to the ListBox, so I tried to create a property (in this case "HotkeysForeground"), bind it and change the color when the items are added in the "HotkeyManager_NewHotkey" event, the problem it's changing the foreground color for all the items in the ListBox. How can I do that per item ? Here is the ViewModel I use. namespace Monkey.Core.ViewModel { using System; using System.Collections.ObjectModel; using System.Windows.Media; using Monkey.Core.SystemMonitor.Accessibility; using Monkey.Core.SystemMonitor.Input; public class MainWindowViewModel : WorkspaceViewModel { private readonly FocusManager _focusManager; private readonly HotkeyManager _hotkeyManager; private readonly ObservableCollection<string> _hotkeys; private Color _foregroundColor; private string _title; public MainWindowViewModel() { _hotkeys = new ObservableCollection<string>(); _hotkeyManager = new HotkeyManager(); _hotkeyManager.NewHotkey += HotkeyManager_NewHotkey; _focusManager = new FocusManager(); _focusManager.Focus += FocusManager_Focus; } public Color HotkeysForeground { get { return _foregroundColor; } set { _foregroundColor = value; OnPropertyChanged(() => HotkeysForeground); } } public ReadOnlyObservableCollection<string> Hotkeys { get { return new ReadOnlyObservableCollection<string>(_hotkeys); } } public string Title { get { return _title; } set { _title = value; OnPropertyChanged(() => Title); } } protected override void OnDispose() { base.OnDispose(); _hotkeyManager.Dispose(); _focusManager.Dispose(); } private void FocusManager_Focus(object sender, FocusManagerEventArgs e) { Title = e.Title; } private void HotkeyManager_NewHotkey(object sender, EventArgs eventArgs) { HotkeysForeground = _hotkeys.Count <= 2 ? Colors.Blue : Colors.Brown; _hotkeys.Clear(); foreach (var hotkey in _hotkeyManager.GetHotkeys()) { _hotkeys.Add(hotkey); } } } } Here is the view. <Window x:Class="Monkey.View.MainWindow" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:System="clr-namespace:System;assembly=mscorlib" Title="{Binding Mode=OneWay, Path=Title, UpdateSourceTrigger=PropertyChanged}" Height="200" Width="200" ShowInTaskbar="False" WindowStyle="ToolWindow" Topmost="True" ResizeMode="CanResizeWithGrip" AllowsTransparency="False"> <Window.Resources> <SolidColorBrush Color="{Binding HotkeysForeground}" x:Key="HotkeysBrush"/> </Window.Resources> <ListBox Canvas.Left="110" Canvas.Top="74" Name="HotkeyList" Height="Auto" Width="Auto" HorizontalContentAlignment="Left" BorderThickness="0" ScrollViewer.CanContentScroll="False" ScrollViewer.HorizontalScrollBarVisibility="Disabled" ScrollViewer.VerticalScrollBarVisibility="Disabled" ItemsSource="{Binding Path=Hotkeys}" VerticalAlignment="Stretch" VerticalContentAlignment="Center" FontSize="20"> <ListBox.ItemContainerStyle> <Style TargetType="ListBoxItem"> <Setter Property="IsEnabled" Value="False" /> </Style> </ListBox.ItemContainerStyle> <ListBox.ItemTemplate> <DataTemplate> <Label Content="{Binding}" Foreground="{StaticResource HotkeysBrush}"/> </DataTemplate> </ListBox.ItemTemplate> </ListBox> </Window> Thank you in advance.

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  • Change ListView background - strage behaviour

    - by Beasly
    Hi again, I have a problem with changing the background of a view in a ListView. What I need: Change the background image of a row onClick() What actually happens: The background gets changed (selected) after pressing e.g. the first entry. But after scrolling down the 8th entry is selected too. Scroll back to the top the first isn't selected anymore. The second entry is selected now. Continue scrolling and it continues jumping... What i'm dong in the Code: I have channels, and onClick() I toggle an attribute of channel boolean selected and then I change the background. I'm doing this only onClick() thats why I don't get why it's actuelly happening on other entries too. One thing I notices is: It seems to be only the "drawing"-part because the item which get selected "by it self" has still the selected value on false I think it seems to have something to do with the reuse of the views in the custom ListAdapters getView(...) Code of onClick() in ListActivity: @Override protected ViewHolder createHolder(View v) { // createHolder will be called only as long, as the ListView is not // filled TextView title = (TextView) v .findViewById(R.id.tv_title_channel_list_adapter); TextView content = (TextView) v .findViewById(R.id.tv_content_channel_list_adapter); ImageView icon = (ImageView) v .findViewById(R.id.icon_channel_list_adapter); if (title == null || content == null || icon == null) { Log.e("ERROR on findViewById", "Couldn't find Title, Content or Icon"); } ViewHolder mvh = new MyViewHolder(title, content, icon); // We make the views become clickable // so, it is not necessary to use the android:clickable attribute in // XML v.setOnClickListener(new ChannelListAdapter.OnClickListener(mvh) { public void onClick(View v, ViewHolder viewHolder) { // we toggle the enabled state and also switch the the // background MyViewHolder mvh = (MyViewHolder) viewHolder; Channel ch = (Channel) mvh.data; ch.setSelected(!ch.getSelected()); // toggle if (ch.getSelected()) { v.setBackgroundResource(R.drawable.row_blue_selected); } else { v.setBackgroundResource(R.drawable.row_blue); } // TESTING Log.d("onClick() Channel", "onClick() Channel: " + ch.getTitle() + " selected: " + ch.getSelected()); } }); return mvh; } Code of getView(...): @Override public View getView(int position, View view, ViewGroup parent) { ViewHolder holder; // When view is not null, we can reuse it directly, there is no need // to reinflate it. // We only inflate a new View when the view supplied by ListView is // null. if (view == null) { view = mInflater.inflate(mViewId, null); // call own implementation holder = createHolder(view); // TEST // we set the holder as tag view.setTag(holder); } else { // get holder back...much faster than inflate holder = (ViewHolder) view.getTag(); } // we must update the object's reference holder.data = getItem(position); // call the own implementation bindHolder(holder); return view; } I really would appreciate any idea how to solve this! :) If more information is needed please tell me. Thanks in advance!

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  • Change style display for cells with Javascript

    - by Ronny
    Hi, I want to do something like this: user selects one radio button (lock,delete or compare). I want to show to him only the relevant column from the table. (each option has different column). The table is ajax. I guess i need to change the display style for every cell but i don't know how. Here is example: Here i want to change the display of the cells function ButtonForTbl(value) { var x=document.getElementById("audithead").rows[0].cells; if (value == "lock"){ document.getElementById('lock').checked = true; //something like for(...)lockCell.style.display='' //something like for(...)deleteCell.style.display='none' //something like for(...)compareCell.style.display='none' } else if(value == "delete"){ document.getElementById('delete').checked = true; //something like for(...)lockCell.style.display='none' //something like for(...)deleteCell.style.display='' //something like for(...)compareCell.style.display='none' } else{ document.getElementById('compare').checked = true; } } I guess i need something like that: for (i = 0; i < deleteCell.length; i++) deleteCell[i].style.display='' = true ; The table: oCell = oRow.insertCell(-1); oCell.setAttribute('id','comCell' ); oCell.setAttribute('align', 'center'); oCell.innerHTML = "<input type='checkbox' id='com' value='"+ ind + "'name='com[]'>"; oCell = oRow.insertCell(-1); oCell.setAttribute('id','lockCell' ); oCell.setAttribute('align', 'center'); oCell.innerHTML = "<input type='checkbox' id='lock' value='"+ ind + "'name='lock[]'>"; Radio buttons: <input type="radio" value="compare" id="compare" name="choose" onclick="ButtonForTbl(this.value)"/> Compare&nbsp; <input type="radio" value="delete" id="delete" name="choose" onclick="ButtonForTbl(this.value)"/> Delete&nbsp; <input type="radio" value="lock" id="lock" name="choose" onclick="ButtonForTbl(this.value)"/> Lock<br/> The table html: <table class="auditable"> <thead id="audithead"> <tr><td></td></tr> </thead> <tbody id="auditTblBody"> </tbody> </table> EDIT: Full row is like that: <tr> <td align="center" id="lockCell" style="display: none;"> <input type="checkbox" onclick="" name="lock[]" value="1500" id="lock"></td> <td align="center" id="delCell" style="display: none;"> <input type="checkbox" name="del[]" value="1500"></td> <td align="center" id="comCell"> <input type="checkbox" onclick="setChecks(this)" name="com[]" value="1500" id="com"></td> <td width="65px">100% 1/1</td><td width="105px">2011-01-10 17:47:37</td> </tr> Thank you so much!

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  • Change a dropdown depending on another dropdown

    - by Eric Evans
    I'm trying to create a three select dropdowns that represent a persons birthday. I'm taking into consideration that there are 4 months with 30 days, 7 with 31 ,and 1 with 28 or 29 depending if it's a leap year or not. I would like the days dropdown to show the number of days depending on which month is chosen in the month dropdown. Here's what I have now. Here's the html for the select <!Doctype html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Birthday validation</title> <script src="jquery-1.11.1.min.js"></script> <script src="birthday_drop.js"></script> <link href="style.css" rel="stylesheet /> </head> <body> <h2>Birthday</h2> <fieldset class="birthday-picker"> <select class="birth-month" name="birth[month]"><option>Month</option></select> <select class="birth-day" name="birth[day]"><option>Day</option></select> <select class="birth-year" name="birth[year]"><option>Year</option></select> </fieldset> </body> </html> Here's the jquery that populates the dropdowns and my attempt to use the change function /** * Created by Eric Evans on 8/19/14. */ $(document).ready(function(){ var months = ['January','February','March','April','May','June','July','August','September','October','November','December']; for(i=0; i < months.length; i++){ $("<option value=' + months[i] + '>" + months[i] + "</option>").appendTo('.birth-month'); } for(i=0; i <= 31; i++){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-day'); } var myYear = new Date().getFullYear(); for(i=myYear; i >= 1950; i--){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-year'); } $('.birth-month').change(function(){ if($(this).val() == 'April'){ for(i=0; i <= 30; i++){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-day'); } } }); }); Any help would be greatly appreciated

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  • Can't get SSH public key authentication to work

    - by Trey Parkman
    My server is running CentOS 5.3. I'm on a Mac running Leopard. I don't know which is responsible for this: I can log on to my server just fine via password authentication. I've gone through all of the steps for setting up PKA (as described at http://www.centos.org/docs/5/html/Deployment_Guide-en-US/s1-ssh-beyondshell.html), but when I use SSH, it refuses to even attempt publickey verification. Using the command ssh -vvv user@host (where -vvv cranks up verbosity to the maximum level) I get the following relevant output: debug2: key: /Users/me/.ssh/id_dsa (0x123456) debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug3: start over, passed a different list publickey,gssapi-with-mic,password debug3: preferred keyboard-interactive,password debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password followed by a prompt for my password. If I try to force the issue with ssh -vvv -o PreferredAuthentications=publickey user@host I get debug2: key: /Users/me/.ssh/id_dsa (0x123456) debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug3: start over, passed a different list publickey,gssapi-with-mic,password debug3: preferred publickey debug3: authmethod_lookup publickey debug3: No more authentication methods to try. So, even though the server says it accepts the publickey authentication method, and my SSH client insists on it, I'm rebutted. (Note the conspicuous absence of an "Offering public key:" line above.) Any suggestions?

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  • Passwordless SSH not working - keys copied and permissions set

    - by Comcar
    I know this question has been asked, but I'm certain I've done what all the other answers suggest. Machine A: used keygen -t rsa to create id_rsa.pub in ~/.ssh/ copied Machine A's id_rsa.pub to Machine B user's home directory Made the file permissions of id_rsa.pub 600 Machine B added Machine A's pub key to authorised_keys and authorised_keys2: cat ~/id_rsa.pub ~/.ssh/authorised_keys2 made the file permissions of id_rsa.pub 600 I've also ensured both the .ssh directories have the permission 700 on both machine A and B. If I try to login to machine B from machine A, I get asked for the password, not the ssh pass phrase. I've got the root users on both machines to talk to each other using password-less ssh, but I can't get a normal user to do it. Do the user names have to be the same on both sides? Or is there some setting else where I've missed. Machine A is a Ubuntu 10.04 virtual machine running inside VirtualBox on a Windows 7 PC, Machine B is a dedicated Ubuntu 9.10 server UPDATE : I've run ssh with the option -vvv, which provides many many lines of output, but this is the last few commands: debug3: check_host_in_hostfile: filename /home/pete/.ssh/known_hosts debug3: check_host_in_hostfile: match line 1 debug1: Host '192.168.1.19' is known and matches the RSA host key. debug1: Found key in /home/pete/.ssh/known_hosts:1 debug2: bits set: 504/1024 debug1: ssh_rsa_verify: signature correct debug2: kex_derive_keys debug2: set_newkeys: mode 1 debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug3: Wrote 16 bytes for a total of 1015 debug2: set_newkeys: mode 0 debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug3: Wrote 48 bytes for a total of 1063 debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: /home/pete/.ssh/identity ((nil)) debug2: key: /home/pete/.ssh/id_rsa (0x7ffe1baab9d0) debug2: key: /home/pete/.ssh/id_dsa ((nil)) debug3: Wrote 64 bytes for a total of 1127 debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-keyex,gssapi-with-mic,gssapi,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Trying private key: /home/pete/.ssh/identity debug3: no such identity: /home/pete/.ssh/identity debug1: Offering public key: /home/pete/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug3: Wrote 368 bytes for a total of 1495 debug1: Authentications that can continue: publickey,password debug1: Trying private key: /home/pete/.ssh/id_dsa debug3: no such identity: /home/pete/.ssh/id_dsa debug2: we did not send a packet, disable method debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password

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  • Odd log entries when starting up PotgreSQL

    - by Shadow
    When restarting pgSQL, I get the following log entries: 2010-02-10 16:08:05 EST LOG: received smart shutdown request 2010-02-10 16:08:05 EST LOG: autovacuum launcher shutting down 2010-02-10 16:08:05 EST LOG: shutting down 2010-02-10 16:08:05 EST LOG: database system is shut down 2010-02-10 16:08:07 EST LOG: database system was shut down at 2010-02-10 16:08:05 EST 2010-02-10 16:08:07 EST LOG: autovacuum launcher started 2010-02-10 16:08:07 EST LOG: database system is ready to accept connections 2010-02-10 16:08:07 EST LOG: connection received: host=[local] 2010-02-10 16:08:07 EST LOG: incomplete startup packet 2010-02-10 16:08:07 EST LOG: connection received: host=[local] 2010-02-10 16:08:07 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:08 EST LOG: connection received: host=[local] 2010-02-10 16:08:08 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:08 EST LOG: connection received: host=[local] 2010-02-10 16:08:08 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:09 EST LOG: connection received: host=[local] 2010-02-10 16:08:09 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:09 EST LOG: connection received: host=[local] 2010-02-10 16:08:09 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:10 EST LOG: connection received: host=[local] 2010-02-10 16:08:10 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:10 EST LOG: connection received: host=[local] 2010-02-10 16:08:10 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:11 EST LOG: connection received: host=[local] 2010-02-10 16:08:11 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:11 EST LOG: connection received: host=[local] 2010-02-10 16:08:11 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST FATAL: password authentication failed for user "postgres" 2010-02-10 16:08:12 EST LOG: connection received: host=[local] 2010-02-10 16:08:12 EST LOG: incomplete startup packet My question regarding a potential consequence of this is posted here: http://stackoverflow.com/questions/2238954/mdb2-says-connection-failed-db-logs-say-otherwise , but I didn't realize this was happening when I asked that question, and I figured this [part of the] problem is for SF. Edit: I can connect to the database and manipulate things normally with the psql CLI and the postgres user.

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  • Recieving a 500 Internal Server error after login success?

    - by Jeremy Quick
    I created my first member login form which takes the typical username and password and then sends it to the code below: checklogin.php: mysql_connect($db_host, $db_username, $db_password) or die(mysql_error()); mysql_select_db($db_database) or die(mysql_error()); $username=$_POST['username']; $password=$_POST['password']; $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM users WHERE username='$username' and password='$password'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count == 1) //ERROR APPEARS TO TAKE PLACE HERE { session_start(); $_SESSION['username'] = $username; $_SESSION['password'] = $password; header('login_success.php'); } else { header("location:login_fail.php"); } If I type in the wrong information everything works properly so I know the error appears to be taking effect in the marked if statement. I have been searching the internet now looking for solutions but none seem to match mine or I am overlooking them. I've made a few changes which brought me to this point, before I was receiving deprecation warnings. Also, I have checked the logs and they are empty of errors relating to this.

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  • how to change ruby path from /usr/bin/ruby to /usr/local/bin/ruby

    - by HelloWorld
    reading around the various ruby install tutorials it's required to change path from /usr/bin/ruby to /usr/local/bin/ruby but i cant seem to be able to do it. Ultimately i want to install Ruby 1.9.2, should i uninstall 1.8.7 or what? i tried to install Ruby 1.9.2 with macports, the installation seemed to go ok, but i cant find the new version, i seem to be stuck with 1.8.7 iMac:~ rebel$ which ruby /usr/bin/ruby rebel$ ruby -v ruby 1.8.7 (2009-06-12 patchlevel 174) [universal-darwin10.0] .profile export PATH=/opt/local/bin:/opt/local/sbin:$PATH export PATH="/usr/local/bin:/usr/local/sbin:/usr/local/mysql/bin:$PATH"

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  • [Android] Change language settings (locale) for the device

    - by raychenon
    Hi, I know it's possible to have multiple languages in a single application through the res/string and depending on Locale. Here is a case http://stackoverflow.com/questions/2078289/android-controling-the-user-language Now how can I change the language in the phone ? Like I'd do by Menu Settings Language & Keyboard Select locale languages Is there some real code to access to these settings ? Or should I create intent for a shortcut to the language settings. Please post some code Edit : With Locale class developer.android.com/intl/fr/reference/java/util/Locale.html The constructor is at least Locale(String language) The input is language. How can you retrieve the current language used on the device ?

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