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  • Storing MySQL GUID/UUIDs

    - by thr
    This is the best way I could come up with to convert a MySQL GUID/UUID generated by UUID() to a binary(16): UNHEX(REPLACE(UUID(),'-','')) And then storing it in a BINARY(16) Are there any implications of doing it this way that I should know of?

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  • seperated mysql statement query in php

    - by stone
    So, I can run the following statements from within mysql itself successfully. SET @fname = 'point1'; SELECT * FROM country WHERE name=@fname;` But when I try to pass the query through php like this and run it, I get an error on the second line $query = "SET @fname = 'point1';"; $query .= "SELECT * FROM country WHERE name=@fname;";

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  • how to activate trigger after all the bulk insert(s) in mysql

    - by JPro
    I am using mysql and there are bulk inserts that goes on to my table. My doubt is if I create a trigger specifying after insert, then the trigger will get activated for every insert after, which I do not want to happen. Is there any way to activate a trigger after all the bulk inserts are completed? Any advice? Thanks.

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  • What Mysql query will return this result?

    - by Lost_in_code
    I have two tables A,B which are related to each other (simplified): A: +-------+---------+ | id | type | +-------+---------+ | 1 | apple | | 2 | orange | | 3 | banana | +-------+---------+ B: +-------+---------+-----------+ | id | a_id | rank | +-------+---------+-----------+ | 1 | 1 | 0.0 | | 2 | 1 | 7.7 | | 3 | 2 | 3.3 | | 4 | 2 | 8.8 | | 5 | 2 | 1.1 | | 6 | 3 | 3.3 | | 7 | 3 | 5.5 | | 8 | 1 | 9.5 | +-------+---------+-----------+ What mysql query will return the following result? Result +-------+---------+-----------+ | id | type | rank | +-------+---------+-----------+ | 1 | apple | 9.5 | | 2 | orange | 1.1 | | 3 | banana | 5.5 | +-------+---------+-----------+

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  • MySQL: Digits (1.75) to Friendly Time (1 hour and 45 minutes)

    - by Nick
    In my MySQL database, I have a float field named "HoursSpent" with values like "0.25", "1.75", "2.5", etc. Is there a way that I can have my SELECT statement format those values in a friendly format like this?: 0.25 = 15 minutes 1.75 = 1 hour and 45 minutes 2.5 = 2 hours and 30 minutes The "HoursSpent" field is supposed to only have values in 0.25 increments, but if somebody were to put something random like 0.16, it would be nice if the SELECT statement handled that by rounding it up to the nearest 0.25 (so in this case 0.16 would become 0.25, or 15 minutes).

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  • MySQL INSERT IGNORE not working

    - by gAMBOOKa
    Here's my table with some sample data a_id | b_id ------------ 1 225 2 494 3 589 When I run this query INSERT IGNORE INTO table_name (a_id, b_id) VALUES ('4', '230') ('2', '494') It inserts both those rows when it's supposed to ignore the second value pair (2, 494) No indexes defined, neither of those columns are primary. What don't I know?

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  • Optimize SELECT DISTINCT CONCAT query in MySQL

    - by L. Cosio
    Hello! I'm running this query: SELECT DISTINCT CONCAT(ALFA_CLAVE, FECHA_NACI) FROM listado GROUP BY ALFA_CLAVE HAVING count(CONCAT(ALFA_CLAVE, FECHA_NACI)) > 1 Is there any way to optimize it? Queries are taking 2-3 hours on a table with 850,000 rows. Adding an index to ALFA_CLAVE and FECHA_NACI would work? Thanks in advanced

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  • GROUP BY and SUM distinct date across 2 tables

    - by kenitech
    I'm not sure if this is possible in one mysql query so I might just combine the results via php. I have 2 tables: 'users' and 'billing' I'm trying to group summed activity for every date that is available in these two tables. 'users' is not historical data but 'billing' contains a record for each transaction. In this example I am showing a user's status which I'd like to sum for created date and deposit amounts that I would also like to sum by created date. I realize there is a bit of a disconnect between the data but I'd like to some all of it together and display it as seen below. This will show me an overview of all of the users by when they were created and what the current statuses are next to total transactions. I've tried UNION as well as LEFT JOIN but I can't seem to get either to work. Union example is pretty close but doesn't combine the dates into one row. ( SELECT created, SUM(status) as totalActive, NULL as totalDeposit FROM users GROUP BY created ) UNION ( SELECT created, NULL as totalActive, SUM(transactionAmount) as totalDeposit FROM billing GROUP BY created ) I've also tried using a date lookup table and joining on the dates but the SUM values are being added multiple times. note: I don't care about the userIds at all but have it in here for the example. users table (where status of '1' denotes "active") (one record for each user) created | userId | status 2010-03-01 | 10 | 0 2010-03-01 | 11 | 1 2010-03-01 | 12 | 1 2010-03-10 | 13 | 0 2010-03-12 | 14 | 1 2010-03-12 | 15 | 1 2010-03-13 | 16 | 0 2010-03-15 | 17 | 1 billing table (record created for every instance of a billing "transaction" created | userId | transactionAmount 2010-03-01 | 10 | 50 2010-03-01 | 18 | 50 2010-03-01 | 19 | 100 2010-03-10 | 89 | 55 2010-03-15 | 16 | 50 2010-03-15 | 12 | 90 2010-03-22 | 99 | 150 desired result: created | sumStatusActive | sumStatusInactive | sumTransactions 2010-03-01 | 2 | 1 | 200 2010-03-10 | 0 | 1 | 55 2010-03-12 | 2 | 0 | 0 2010-03-13 | 0 | 0 | 0 2010-03-15 | 1 | 0 | 140 2010-03-22 | 0 | 0 | 150 Table dump: CREATE TABLE IF NOT EXISTS `users` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `status` smallint(6) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `users` (`created`, `userId`, `status`) VALUES ('2010-03-01', 10, 0), ('2010-03-01', 11, 1), ('2010-03-01', 12, 1), ('2010-03-10', 13, 0), ('2010-03-12', 14, 1), ('2010-03-12', 15, 1), ('2010-03-13', 16, 0), ('2010-03-15', 17, 1); CREATE TABLE IF NOT EXISTS `billing` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `transactionAmount` int(11) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `billing` (`created`, `userId`, `transactionAmount`) VALUES ('2010-03-01', 10, 50), ('2010-03-01', 18, 50), ('2010-03-01', 19, 100), ('2010-03-10', 89, 55), ('2010-03-15', 16, 50), ('2010-03-15', 12, 90), ('2010-03-22', 99, 150);

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  • MySQL 5 left join unknown column

    - by NP
    I had the below query working in mysql 4.1, but does not in 5.0: SELECT * FROM email e, event_email ee LEFT JOIN member m on m.email=e.email WHERE ee.email_id = e.email_id The error: 1054 (Unknown column 'e.email' in 'on clause')

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  • Mysql query to fetch data

    - by hnihar
    i have a table "request" with 4 columns namely: 1.recId :long primary key 2.interactionId:long 3.requestedBy:boolean 4.requestedType:boolean and data is as follows: VALUES (185,455699,0,5), (186,455746,0,1), (187,455746,1,1), (188,455752,0,1), (189,455753,0,1), (190,455753,1,1), (191,455754,1,1) i want a query to fetch all the rows where interactionId is same and having requestedBy both 1 and 0 values and requestType=1; regards, Nihar

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  • mysql join table - selecting the newest row

    - by cmancre
    Hi, I have the following two MySQL tables TABLE NAMES NAME_ID NAME 1 name1 2 name2 3 name3 TABLE STATUS STATUS_ID NAME_ID TIMESTAMP 1 1 2010-12-20 12:00 2 2 2010-12-20 10:00 3 3 2010-12-20 10:30 4 3 2010-12-20 14:00 I would like to select all info from table NAMES and add most recent correspondent TIMESTAMP column from table STATUS RESULT NAME_ID NAME TIMESTAMP 1 name1 2010-12-20 12:00 2 name2 2010-12-20 10:00 3 name3 2010-12-20 14:00 Am stuck on this one. How do I left join only on the newer timestamp?

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  • Efficiently store last X items in an MySQL Database

    - by Saif Bechan
    I want to store the last 3 items in an MySQL database in an efficient way. So when the 4th item is stored the first should be deleted. The way I do this not is first run a query getting the items. Than check what I should do then insert/delete. There has to be a better way to do this. Any suggestions?

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  • Conditional sorting in MySQL?

    - by serg555
    I have "tasks" table with 3 fields: date priority (0,1,2) done (0,1) What I am trying to achieve is with the whole table sorted by done flag, tasks that are not done should be sorted by priority, while tasks that are done should be sorted by date: Select * from tasks order by done asc If done=0 additionally order by priority desc If done=1 additionally order by date desc Is it possible to do this in MySQL without unions? Thanks.

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  • multiple updation using single mysql query

    - by Ajith
    I need to update multiple rows with different values.Is it possible to do in mysql? ie,some thing like this UPDATE landing_page SET (rotation_slot_begin='0',rotation_slot_end='0.333333333333' where landing_pageid=265),(rotation_slot_begin='0.333333333333',rotation_slot_end='0.666666666667' where landing_pageid=267),(rotation_slot_begin='0.666666666667',rotation_slot_end='1' where landing_pageid=268) but this query is not working.I think something like this.Anybody can help me please

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