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  • Using jQuery to Insert a New Database Record

    - by Stephen Walther
    The goal of this blog entry is to explore the easiest way of inserting a new record into a database using jQuery and .NET. I’m going to explore two approaches: using Generic Handlers and using a WCF service (In a future blog entry I’ll take a look at OData and WCF Data Services). Create the ASP.NET Project I’ll start by creating a new empty ASP.NET application with Visual Studio 2010. Select the menu option File, New Project and select the ASP.NET Empty Web Application project template. Setup the Database and Data Model I’ll use my standard MoviesDB.mdf movies database. This database contains one table named Movies that looks like this: I’ll use the ADO.NET Entity Framework to represent my database data: Select the menu option Project, Add New Item and select the ADO.NET Entity Data Model project item. Name the data model MoviesDB.edmx and click the Add button. In the Choose Model Contents step, select Generate from database and click the Next button. In the Choose Your Data Connection step, leave all of the defaults and click the Next button. In the Choose Your Data Objects step, select the Movies table and click the Finish button. Unfortunately, Visual Studio 2010 cannot spell movie correctly :) You need to click on Movy and change the name of the class to Movie. In the Properties window, change the Entity Set Name to Movies. Using a Generic Handler In this section, we’ll use jQuery with an ASP.NET generic handler to insert a new record into the database. A generic handler is similar to an ASP.NET page, but it does not have any of the overhead. It consists of one method named ProcessRequest(). Select the menu option Project, Add New Item and select the Generic Handler project item. Name your new generic handler InsertMovie.ashx and click the Add button. Modify your handler so it looks like Listing 1: Listing 1 – InsertMovie.ashx using System.Web; namespace WebApplication1 { /// <summary> /// Inserts a new movie into the database /// </summary> public class InsertMovie : IHttpHandler { private MoviesDBEntities _dataContext = new MoviesDBEntities(); public void ProcessRequest(HttpContext context) { context.Response.ContentType = "text/plain"; // Extract form fields var title = context.Request["title"]; var director = context.Request["director"]; // Create movie to insert var movieToInsert = new Movie { Title = title, Director = director }; // Save new movie to DB _dataContext.AddToMovies(movieToInsert); _dataContext.SaveChanges(); // Return success context.Response.Write("success"); } public bool IsReusable { get { return true; } } } } In Listing 1, the ProcessRequest() method is used to retrieve a title and director from form parameters. Next, a new Movie is created with the form values. Finally, the new movie is saved to the database and the string “success” is returned. Using jQuery with the Generic Handler We can call the InsertMovie.ashx generic handler from jQuery by using the standard jQuery post() method. The following HTML page illustrates how you can retrieve form field values and post the values to the generic handler: Listing 2 – Default.htm <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Add Movie</title> <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> </head> <body> <form> <label>Title:</label> <input name="title" /> <br /> <label>Director:</label> <input name="director" /> </form> <button id="btnAdd">Add Movie</button> <script type="text/javascript"> $("#btnAdd").click(function () { $.post("InsertMovie.ashx", $("form").serialize(), insertCallback); }); function insertCallback(result) { if (result == "success") { alert("Movie added!"); } else { alert("Could not add movie!"); } } </script> </body> </html>     When you open the page in Listing 2 in a web browser, you get a simple HTML form: Notice that the page in Listing 2 includes the jQuery library. The jQuery library is included with the following SCRIPT tag: <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> The jQuery library is included on the Microsoft Ajax CDN so you can always easily include the jQuery library in your applications. You can learn more about the CDN at this website: http://www.asp.net/ajaxLibrary/cdn.ashx When you click the Add Movie button, the jQuery post() method is called to post the form data to the InsertMovie.ashx generic handler. Notice that the form values are serialized into a URL encoded string by calling the jQuery serialize() method. The serialize() method uses the name attribute of form fields and not the id attribute. Notes on this Approach This is a very low-level approach to interacting with .NET through jQuery – but it is simple and it works! And, you don’t need to use any JavaScript libraries in addition to the jQuery library to use this approach. The signature for the jQuery post() callback method looks like this: callback(data, textStatus, XmlHttpRequest) The second parameter, textStatus, returns the HTTP status code from the server. I tried returning different status codes from the generic handler with an eye towards implementing server validation by returning a status code such as 400 Bad Request when validation fails (see http://www.w3.org/Protocols/rfc2616/rfc2616-sec10.html ). I finally figured out that the callback is not invoked when the textStatus has any value other than “success”. Using a WCF Service As an alternative to posting to a generic handler, you can create a WCF service. You create a new WCF service by selecting the menu option Project, Add New Item and selecting the Ajax-enabled WCF Service project item. Name your WCF service InsertMovie.svc and click the Add button. Modify the WCF service so that it looks like Listing 3: Listing 3 – InsertMovie.svc using System.ServiceModel; using System.ServiceModel.Activation; namespace WebApplication1 { [ServiceBehavior(IncludeExceptionDetailInFaults=true)] [ServiceContract(Namespace = "")] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class MovieService { private MoviesDBEntities _dataContext = new MoviesDBEntities(); [OperationContract] public bool Insert(string title, string director) { // Create movie to insert var movieToInsert = new Movie { Title = title, Director = director }; // Save new movie to DB _dataContext.AddToMovies(movieToInsert); _dataContext.SaveChanges(); // Return movie (with primary key) return true; } } }   The WCF service in Listing 3 uses the Entity Framework to insert a record into the Movies database table. The service always returns the value true. Notice that the service in Listing 3 includes the following attribute: [ServiceBehavior(IncludeExceptionDetailInFaults=true)] You need to include this attribute if you want to get detailed error information back to the client. When you are building an application, you should always include this attribute. When you are ready to release your application, you should remove this attribute for security reasons. Using jQuery with the WCF Service Calling a WCF service from jQuery requires a little more work than calling a generic handler from jQuery. Here are some good blog posts on some of the issues with using jQuery with WCF: http://encosia.com/2008/06/05/3-mistakes-to-avoid-when-using-jquery-with-aspnet-ajax/ http://encosia.com/2008/03/27/using-jquery-to-consume-aspnet-json-web-services/ http://weblogs.asp.net/scottgu/archive/2007/04/04/json-hijacking-and-how-asp-net-ajax-1-0-mitigates-these-attacks.aspx http://www.west-wind.com/Weblog/posts/896411.aspx http://www.west-wind.com/weblog/posts/324917.aspx http://professionalaspnet.com/archive/tags/WCF/default.aspx The primary requirement when calling WCF from jQuery is that the request use JSON: The request must include a content-type:application/json header. Any parameters included with the request must be JSON encoded. Unfortunately, jQuery does not include a method for serializing JSON (Although, oddly, jQuery does include a parseJSON() method for deserializing JSON). Therefore, we need to use an additional library to handle the JSON serialization. The page in Listing 4 illustrates how you can call a WCF service from jQuery. Listing 4 – Default2.aspx <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Add Movie</title> <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> <script src="Scripts/json2.js" type="text/javascript"></script> </head> <body> <form> <label>Title:</label> <input id="title" /> <br /> <label>Director:</label> <input id="director" /> </form> <button id="btnAdd">Add Movie</button> <script type="text/javascript"> $("#btnAdd").click(function () { // Convert the form into an object var data = { title: $("#title").val(), director: $("#director").val() }; // JSONify the data data = JSON.stringify(data); // Post it $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "MovieService.svc/Insert", data: data, dataType: "json", success: insertCallback }); }); function insertCallback(result) { // unwrap result result = result["d"]; if (result === true) { alert("Movie added!"); } else { alert("Could not add movie!"); } } </script> </body> </html> There are several things to notice about Listing 4. First, notice that the page includes both the jQuery library and Douglas Crockford’s JSON2 library: <script src="Scripts/json2.js" type="text/javascript"></script> You need to include the JSON2 library to serialize the form values into JSON. You can download the JSON2 library from the following location: http://www.json.org/js.html When you click the button to submit the form, the form data is converted into a JavaScript object: // Convert the form into an object var data = { title: $("#title").val(), director: $("#director").val() }; Next, the data is serialized into JSON using the JSON2 library: // JSONify the data var data = JSON.stringify(data); Finally, the form data is posted to the WCF service by calling the jQuery ajax() method: // Post it $.ajax({   type: "POST",   contentType: "application/json; charset=utf-8",   url: "MovieService.svc/Insert",   data: data,   dataType: "json",   success: insertCallback }); You can’t use the standard jQuery post() method because you must set the content-type of the request to be application/json. Otherwise, the WCF service will reject the request for security reasons. For details, see the Scott Guthrie blog post: http://weblogs.asp.net/scottgu/archive/2007/04/04/json-hijacking-and-how-asp-net-ajax-1-0-mitigates-these-attacks.aspx The insertCallback() method is called when the WCF service returns a response. This method looks like this: function insertCallback(result) {   // unwrap result   result = result["d"];   if (result === true) {       alert("Movie added!");   } else {     alert("Could not add movie!");   } } When we called the jQuery ajax() method, we set the dataType to JSON. That causes the jQuery ajax() method to deserialize the response from the WCF service from JSON into a JavaScript object automatically. The following value is passed to the insertCallback method: {"d":true} For security reasons, a WCF service always returns a response with a “d” wrapper. The following line of code removes the “d” wrapper: // unwrap result result = result["d"]; To learn more about the “d” wrapper, I recommend that you read the following blog posts: http://encosia.com/2009/02/10/a-breaking-change-between-versions-of-aspnet-ajax/ http://encosia.com/2009/06/29/never-worry-about-asp-net-ajaxs-d-again/ Summary In this blog entry, I explored two methods of inserting a database record using jQuery and .NET. First, we created a generic handler and called the handler from jQuery. This is a very low-level approach. However, it is a simple approach that works. Next, we looked at how you can call a WCF service using jQuery. This approach required a little more work because you need to serialize objects into JSON. We used the JSON2 library to perform the serialization. In the next blog post, I want to explore how you can use jQuery with OData and WCF Data Services.

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  • Cant deploy "war" file from Virtual Hosts, see a directory listing.

    - by Kaustubh P
    This is my httpd.conf configured with Virtual hosts: NameVirtualHost *:80 <VirtualHost *:80> ServerName http://foo.baz.in DocumentRoot /var/www/foo/ </VirtualHost> <VirtualHost *:80> ServerName http://bar.baz.in DocumentRoot /var/www/ </VirtualHost> The second virtual host is a Wordpress blog, configured with .htaccess, and index.php in the root i.e. /var/www, and rest of the files in wordpress's own folder. However, the first virtual host is a "war" file, and when I goto foo.baz.in, I see the directory listing, containing the war. I also tried changing the DocumentRoot to /var/www/foo/foo.war` but I get an error Restarting web server: apache2Warning: DocumentRoot [/var/www/foo/foo.war] does not exist I also changed the owner and permission of the war to www-data:www-data and changed the permissions to 755, but to no avail. How do I make apache deploy my "war"? Thanks.

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  • Apache DS fails to list users

    - by CuriousMind
    Apache ds fails to list the users INFO | jvm 1 | 2012/03/28 15:54:04 | java.lang.Error: ERR_546 CRITICAL: page header magic for block 59 not OK 0 INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.PageHeader.(PageHeader.java:95) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.PageHeader.getView(PageHeader.java:124) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.PageManager.getNext(PageManager.java:234) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.PageCursor.next(PageCursor.java:104) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.PhysicalRowIdManager.fetch(PhysicalRowIdManager.java:158) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.BaseRecordManager.fetch(BaseRecordManager.java:324) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.recman.CacheRecordManager.fetch(CacheRecordManager.java:262) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.btree.BPage.loadBPage(BPage.java:899) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.btree.BPage.childBPage(BPage.java:890) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.btree.BPage.find(BPage.java:284) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.btree.BPage.find(BPage.java:285) INFO | jvm 1 | 2012/03/28 15:54:04 | at jdbm.btree.BTree.find(BTree.java:408) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.partition.impl.btree.jdbm.JdbmTable.get(JdbmTable.java:395) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.partition.impl.btree.jdbm.JdbmMasterTable.get(JdbmMasterTable.java:155) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.partition.impl.btree.jdbm.JdbmStore.lookup(JdbmStore.java:1332) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.partition.impl.btree.jdbm.JdbmStore.lookup(JdbmStore.java:70) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.xdbm.search.impl.EqualityEvaluator.evaluate(EqualityEvaluator.java:126) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.xdbm.search.impl.AndCursor.matches(AndCursor.java:234) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.xdbm.search.impl.AndCursor.next(AndCursor.java:143) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.xdbm.search.impl.AndCursor.next(AndCursor.java:139) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.partition.impl.btree.ServerEntryCursorAdaptor.next(ServerEntryCursorAdaptor.java:178) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.core.filtering.BaseEntryFilteringCursor.next(BaseEntryFilteringCursor.java:499) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.SearchHandler.readResults(SearchHandler.java:314) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.SearchHandler.doSimpleSearch(SearchHandler.java:749) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.SearchHandler.handleIgnoringReferrals(SearchHandler.java:978) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.SearchHandler.handleIgnoringReferrals(SearchHandler.java:78) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.ReferralAwareRequestHandler.handle(ReferralAwareRequestHandler.java:83) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.ReferralAwareRequestHandler.handle(ReferralAwareRequestHandler.java:57) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.LdapRequestHandler.handleMessage(LdapRequestHandler.java:208) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.handlers.LdapRequestHandler.handleMessage(LdapRequestHandler.java:58) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.handler.demux.DemuxingIoHandler.messageReceived(DemuxingIoHandler.java:232) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.directory.server.ldap.LdapProtocolHandler.messageReceived(LdapProtocolHandler.java:193) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.filterchain.DefaultIoFilterChain$TailFilter.messageReceived(DefaultIoFilterChain.java:713) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.filterchain.DefaultIoFilterChain.callNextMessageReceived(DefaultIoFilterChain.java:434) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.filterchain.DefaultIoFilterChain.access$1200(DefaultIoFilterChain.java:46) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.filterchain.DefaultIoFilterChain$EntryImpl$1.messageReceived(DefaultIoFilterChain.java:793) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.filterchain.IoFilterEvent.fire(IoFilterEvent.java:71) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.core.session.IoEvent.run(IoEvent.java:63) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.filter.executor.UnorderedThreadPoolExecutor$Worker.runTask(UnorderedThreadPoolExecutor.java:480) INFO | jvm 1 | 2012/03/28 15:54:04 | at org.apache.mina.filter.executor.UnorderedThreadPoolExecutor$Worker.run(UnorderedThreadPoolExecutor.java:434) INFO | jvm 1 | 2012/03/28 15:54:04 | at java.lang.Thread.run(Thread.java:619) INFO | jvm 1 | 2012/03/28 15:54:04 | [15:54:04] WARN [org.apache.directory.server.ldap.LdapProtocolHandler] - Null LdapSession given to cleanUpSession. INFO | jvm 1 | 2012/03/28 15:55:20 | [15:55:20] WARN [org.apache.directory.server.ldap.LdapProtocolHandler] - Unexpected exception forcing session to close: sending disconnect notice to client.

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  • Is there a ".d" directory to use to load modules at boot time, opposed to /etc/modules?

    - by gertvdijk
    I am automating some configurations on my systems using Puppet. For a group of machines I want to load a kernel module at boot time. The most elegant way seems to edit /etc/modules and add one on an individual line. However, I would like to use separate files in a ".d" directory structure for easier maintainability. For modprobe and specifying the options for modules, there's /etc/modprobe.d/, but what's the most elegant way for actually loading modules at boot time using a single new file? Basically, I'm looking for the non-existing /etc/modules.d/ directory. Any suggestions?

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  • In which directory to write game save files/data?

    - by Klaim
    I need a definite list of directories, one or more per platform, where to put game save files and other game generated data. Either based no the OS developer specification, or because it is common usage if there is no recommandation. Please provide one answer per platform, with different directories. Also, example of how to get the directory location in C++ or C is best, as it's the language you'll have more hard time. Locations: Player's game data (saved games, config). Shared game data (like high-score or config for all computer users). Temporary game data (aka cache directory).

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  • how to fix fatal error jvmti.h No such file or directory compilation terminated on c code ubuntu? [on hold]

    - by Blue Rose
    how to fix fatal error jvmti.h No such file or directory compilation terminated c code ubuntu? my c code is: #include "jvmti.h" JNIEXPORT jint JNICALL Agent_OnLoad(JavaVM *jvm, char *options, void *reserved) { /* We return JNI_OK to signify success */ printf("\nBushra Za'areer,\n\n"); return JNI_OK; } JNIEXPORT void JNICALL Agent_OnUnload(JavaVM *vm) { } type this command in terminal: gcc -Wall -W -Werror first_agent.c -o firstagent first_agent.c:1:19: fatal error: jvmti.h: No such file or directory compilation terminated. where java jdk version javac 1.7.0_25 where gcc version gcc version 4.7.3 (Ubuntu/Linaro 4.7.3-2ubuntu4) here should update gcc version to 4.8?

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  • install barnyard2 ubuntu 12.04

    - by Muhammad Ardiansyah
    I trying to install barnyard2 in ubuntu 12.04 32-bit I'm configure using syntax: ./configure --with-mysql-libraries=/usr/lib/x86_64-linux-gnu and when I trying to compile daq-1.1.1 using a makefile, I encountered the following errors: make[3]: Leaving directory /root/snortinstall/barnyard2/src' make[2]: Leaving directory/root/snortinstall/barnyard2/src' Making all in etc make[2]: Entering directory /root/snortinstall/barnyard2/etc' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/etc' Making all in doc make[2]: Entering directory/root/snortinstall/barnyard2/doc' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/doc' Making all in rpm make[2]: Entering directory /root/snortinstall/barnyard2/rpm' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/rpm' Making all in schemas make[2]: Entering directory/root/snortinstall/barnyard2/schemas' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/schemas' Making all in m4 make[2]: Entering directory /root/snortinstall/barnyard2/m4' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/m4' make[2]: Entering directory /root/snortinstall/barnyard2' make[2]: Nothing to be done for all-am'. make[2]: Leaving directory/root/snortinstall/barnyard2' make[1]: Leaving directory `/root/snortinstall/barnyard2'

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  • Is it possible to mod_rewrite BASED on the existence of a file/directory and uniqueID?

    - by JM4
    My site currently forces all non www. pages to use www. Ultimately, I am able to handle all unique subdomains and parse correctly but I am trying to achieve the following: (ideally with mod_rewrite): when a consumer visits www.site.com/john4, the server processes that request as: www.site.com?Agent=john4 Our requirements are: The URL should continue to show www.site.com/john4 even though it was redirected to www.site.com?index.php?Agent=john4 If a file (of any extension OR a directory) exists with the name, the entire process stops an it tries to pull that file instead: for example: www.site.com/file would pull up (www.site.com/file.php if file.php existed on the server. www.site.com/pages would go to www.site.com/pages/index.php if the pages directory exists). Thank you ahead of time. I am completely at a crapshot right now.

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  • What has 'rm -r ~' done to my home directory?

    - by GUI Junkie
    gedit creates hidden backup files ending with '~'. I wanted to do a recursive cleanup of my directory tree. The command rm *~ will delete all local files ending with '~' I thought rm -r *~ . would delete all files in the whole tree, but I typo-ed rm -r ~. There was a message some directory could not be deleted and I quit the command. The question is: What have I been deleting? I did notice that my Filezilla configuration was gone. Does this command delete all hidden directories from the home dir?

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  • How to get my localhost with a different directory to my index working)?

    - by blade19899
    I can't get my apache configuration to open my index.html I edited my /etc/apache2/apache2.conf and added the following at the bottom. <VirtualHost *:80> DocumentRoot /media//DATA/directory/to/my/index-file/ ServerName host-test.com </VirtualHost> Then I restarted my entire pc, but when I open localhost I get the: It works! This is the default web page for this server. The web server software is running but no content has been added, yet. Page and not the code written in my index.html? How to get my localhost with a different directory to my index working in Ubuntu 12.10(amd64)?

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  • Microsoft met à jour Windows Azure Web Sites et Azure Active Directory pour la gestion d'identité et l'hébergement Web dans le Cloud

    Microsoft met à jour Windows Azure Web Sites et Azure Active Directory pour l'hébergement Web et la gestion d'identité dans le Cloud Microsoft par la voix de Scott Guthrie, Vice-président de la division serveur et Business Tools, vient d'annoncer une mise à jour de Windows Azure Web Sites ainsi que du service Windows Azure Active Directory (WAAD). [IMG]http://ftp-developpez.com/gordon-fowler/windowsazurelogo.jpg[/IMG] Azure Web Sites est une plateforme d'hébergement des sites et applications Web dans le Cloud Azure. L'objectif de l'infrastructure Azure Web Sites est de rendre l'hébergement disponible à la fois sur le Cloud et en local sur les serv...

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  • Why does my code fail to create a directory in "C:\Program Files" under Windows 7?

    - by sunil.nishad87
    I am using Windows 7 and I have to run one program in that windows but that program working in Windows XP. This is a Visual C++ program and I am using Visual Studio 2008 for this. When I am running my application, it does not throw any errors, but it does not create a directory in "c:\program files\". So can anyone help me to create directory and exe file? This is the code I am using: char szAppPath[MAX_PATH]; char szFileName[MAX_PATH]; DWORD dwResult; WIN32_FIND_DATA FindFileData; HANDLE hFind; dwResult = ExpandEnvironmentStrings( NULL, szAppPath, MAX_PATH); // "%ProgramFiles%" // do same for NSim directory strcat(szAppPath,"\\NSim"); hFind = FindFirstFile(szAppPath, &FindFileData); if (hFind == INVALID_HANDLE_VALUE) { //Directory Does't Exists create New if(!CreateDirectory(szAppPath,NULL)) //Throw Error { MessageBox("Unable to Create N-SIM directory","NSim Installer"); return ; } } else { //check if is directory or not if(!(FindFileData.dwFileAttributes & FILE_ATTRIBUTE_DIRECTORY)) { MessageBox("Can't Create N-SIM directory\n Another file with same name exists","NSim Installer"); return ; } FindClose(hFind); } //***************************************N-SIM Application**************************** strcpy(szFileName, szAppPath); HRSRC hRes; if( bRegister == FALSE) { strcat(szFileName,"\\NSim.exe"); //make same name of the Client & Server in program file hRes = FindResource(NULL, MAKEINTRESOURCE(IDR_LANSIMSERVER),RT_RCDATA); if(flagUpgrade ==0) { CString trial = installationDate(); //----- Detemine Expiry Date ----- setRegistry(trial); } }

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  • How do you get the solution directory in C# (VS 2008) in code?

    - by IsaacB
    Hi, Got an annoying problem here. I've got an NHibernate/Forms application I'm working through SVN. I made some of my own controls, but when I drag and drop those (or view some form editors where I have already dragged and dropped) onto some of my other controls, Visual studio decides it needs to execute some of the code I wrote, including the part that looks for hibernate.cfg.xml. I have no idea why this is, but (sometimes!) when it executes the code during my form load or drag and drop it switches the current directory to C:\program files\vs 9.0\common7\ide, and then nhibernate throws an exception that it can't find hibernate.cfg.xml, because I'm searching for that in a relative path. Now, I don't want to hard code the location of hibernate.cfg.xml, or just copy hibernate.cfg.xml to the ide directory (which will work). I want a solution that gets the solutions directory while the current directory is common7\ide. Something that will let someone view my forms in the designer on a fresh checkout to an arbitrary directory on an arbitrary machine. And no, I'm not about to load the controls in code. I have so many controls within controls that it is a nightmare to line everything up without it. I tried a pre build event that made a file that has the solution directory in it, but of course how can I find that from common7\ide? All the projects files need to be in the solution directory because of svn. Thanks for your help guys, I've already spent a few hours fiddling with this in vain.

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  • Du tells me it can't find the current directory?

    - by C. Ross
    I'm on AIX, and in some directories I can't use the du command. I get the follow error message: du: 0653-175 Cannot find the current directory. Obviously the current directory exists, and I have permissions to it. I can list the directory and create files in it, both before and after I ran du. What could possibly be wrong here? The du command works just fine in my home directory. A quick google search turns up a bunch of forum posts of the same problem, but no clear answers.

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  • Maximum number of files in one ext3 directory while still getting acceptable performance?

    - by knorv
    I have an application writing to an ext3 directory which over time has grown to roughly three million files. Needless to say, reading the file listing of this directory is unbearably slow. I don't blame ext3. The proper solution would have been to let the application code write to sub-directories such as ./a/b/c/abc.ext rather than using only ./abc.ext. I'm changing to such a sub-directory structure and my question is simply: roughly how many files should I expect to store in one ext3 directory while still getting acceptable performance? What's your experience? Or in other words; assuming that I need to store three million files in the structure, how many levels deep should the ./a/b/c/abc.ext structure be? Obviously this is a question that cannot be answered exactly, but I'm looking for a ball park estimate.

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  • Why is .htaccess not allowed in a directory but is allowed in another?

    - by JD Isaacks
    I have apache2 installed on ubuntu 10.4 inside my var/www/ directory [amung others] I have a cakephp and a dvdcatalog directories. Each of which have CakePHP 1.3 installed. I can access them both via localhost/cakephp and localhost/dvdcatalog But the dvdcatalog shows up with no css styling. They both have these files: /var/www/cakephp/app/webroot/css/cake.generic.css /var/www/dvdcatalog/app/webroot/css/cake.generic.css But when I go to http://localhost/cakephp/css/cake.generic.css it sees the file but it does not see the file when I go to http://localhost/dvdcatalog/css/cake.generic.css I think this means the cakephp folder is able to use .htaccess and the dvdcatalog is not. I setup the cakephp directory last month when I was following in the blog tutorial. I am setting up the dvdcatalog directory now for a different tutorial. So I am not sure if I am missing a step. in my /etc/apache2/apache2.conf file I have this: <Directory "/var/www/*"> Order allow,deny Allow from all AllowOverride All </Directory> Which I thought gave .htaccesss to all. Does anyone have any ideas what the problem is?

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  • How can I tell SELinux to give vsftpd write access in a specific directory?

    - by Arcturus
    Hello. I've set up vsftpd on my Fedora 12 server, and I'd like to have the following configuration. Each user should have access to: his home directory (/home/USER); the web directory I created for him (/web/USER). To achieve this, I first configured vsftpd to chroot each user to his home directory. Then, I created /web/USER with the correct permissions, and used mount --bind /web/USER /home/USER/Web so that the user may have access to /web/USER through /home/USER/Web. I also turned on the SELinux boolean ftp_home_dir so that vsftpd is allowed to write in users' home directories. This works very well, except that when a user tries to upload or rename a file in /home/USER/Web, SELinux forbids it because the change must also be done to /web/USER, and SELinux doesn't give vsftpd permission to write anything to that directory. I know that I could solve the problem by turning on the SELinux boolean allow_ftpd_full_access, or ftpd_disable_trans. I also tried to use audit2allow to generate a policy, but what it does is generate a policy that gives ftpd write access to directories of type public_content_t; this is equivalent to turning on allow_ftpd_full_access, if I understood it correctly. I'd like to know if it's possible to configure SELinux to allow FTP write access to the specific directory /web/USER and its contents, instead of disabling SELinux's FTP controls entirely.

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  • How to make new file permission inherit from the parent directory?

    - by Wai Yip Tung
    I have a directory called data. Then I am running a script under the user id 'robot'. robot writes to the data directory and update files inside. The idea is data is open for both me and robot to update. So I setup the permission and owner group like this drwxrwxr-x 2 me robot-grp 4096 Jun 11 20:50 data where both me and robot belongs to the 'robot-grp'. I change the permission and the owner group recursively like the parent directory. I regularly upload new files into the data directory using rsync. Unfortunately, new files uploaded does not inherit the parent directory's permission as I hope. Instead it looks like this -rw-r--r-- 1 me users 6 Jun 11 20:50 new-file.txt When robot tries to update new-file.txt, it fails due to lack of file permission. I'm not sure if setting umask helps. In anycase the new files does not really follow it. $ umask -S u=rwx,g=rx,o=rx I'm often confounded by Unix file permission. Do I even have a right plan? I'm using Debian lenny.

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  • Directory directive: AuthType None but still need an AuthProvider?

    - by Steffen Winkler
    For now I just need the server to let me download files from one specific folder (in my case I chose /opt/myFolder for that task) Distribution is Debian 6.0 *edit_start* Apache version is 2.4, according to their official documentation, the Order/Allow clauses are deprecated and should not be used anymore I'm an idiot: Apache version is 2.2. *edit_end* My directory directives in apache2.conf look like this: <IfModule dir_module> DirectoryIndex index.html index.htm index.php </IfModule> ServerRoot "/etc/apache2" DocumentRoot "/opt/myFolder" <Directory /> Options FollowSymLinks AuthType None AllowOverride None Require all denie </Directory> <Directory "/opt/myFolder/*"> Options FollowSymLinks MultiViews AllowOverride None AuthType None Require all allow </Directory> When I try to access a file inside that folder (http://myserver.de/aTestFile.zip) I get an Internal Server Error. Also Apache writes the following error into it's log: configuration error: couldn't check user. Check your authn provider!: /aTestFile.zip Why would I need an authn provider if I don't want any authentication? Also I hope someone can explain to me what kind of AuthenticationProvider I'd need for that. Everytime I search for those things I get pointed at people asking how to protect files/directories with passwords or restrict access to some IP addresses, which doesn't really help me. ok, since I've Apache version 2.2, here is the error I get when using the Order/Deny/Allow commands instead of AuthType/Require: Invalid command 'Order', perhaps misspelled or defined by a module not included in the server configuration.

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  • How do I correct a directory incorrectly copied into itself?

    - by Peter Boughton
    Given the following situation... <path>/mydir1/mydir2 ...where mydir2 should have overwritten mydir1, but was instead placed inside, and both directories actually have the same filename. How is that fixed? Attempting to do mv <path>/mydir/mydir/* <path>/mydir/ or mv <path>/mydir <path>/ results in: mv: cannot move `<path>/mydir/mydir` to a subdirectory of itself, `<path>/mydir` This seems stupidly simple, but it's late here and I can't figure it out. There are seventeen such directories to fix (path differs for each, but same mydir name). To confirm, the error message can be caused with this: # cd /path/to/directory # mv mydir/mydir ./ mv: cannot move `mydir/mydir' to a subdirectory of itself, `./mydir' Also tried: # mv mydir/mydir/* mydir/ mv: cannot move `mydir/mydir/otherdir1' to a subdirectory of itself, `mydir/otherdir1' mv: cannot move `mydir/mydir/otherdir2' to a subdirectory of itself, `mydir/otherdir2' and... # mv /path/to/directory/mydir/mydir/otherdir1 /path/to/directory/mydir/ mv: cannot move `/path/to/directory/mydir/mydir/otherdir1' to a subdirectory of itself, `/path/to/directory/mydir/otherdir1' and using a temporary directory: # mv mydir/mydir ./mydir-temp # mv mydir-temp/* mydir/ mv: cannot move `mydir-temp/otherdir1' to a subdirectory of itself, `mydir/otherdir1' mv: cannot move `mydir-temp/otherdir2' to a subdirectory of itself, `mydir/otherdir2' I found a similar question "How to recursively move all files (including hidden) in a subfolder into a parent folder in *nix?" which suggested that mv bar/{,.}* . would do this. But this also gives the same errors, as well as confusingly picking up . and .. from somewhere. # cd mydir # mv mydir/{,.}* . mv: cannot move `mydir/otherdir1' to a subdirectory of itself, `./otherdir1' mv: cannot move `mydir/otherdir2' to a subdirectory of itself, `./otherdir2' mv: cannot move `mydir/.' to `./.': Device or resource busy mv: cannot move `mydir/..' to `./..': Device or resource busy mv: overwrite `./.file'? y Another similar question "linux mv command weirdness" suggests that mv doesn't overwrite and a copy is required. # cd mydir # cp -rf ./mydir/* ./ cp: overwrite `./otherdir1/file1'? y cp: overwrite `./otherdir1/file2'? y cp: overwrite `./otherdir1/file3'? This appears to be working... except there's a lot of files (and dirs) - I don't want to confirm every one! Isn't the f there supposed to prevent this? Ok, so cp was aliased to cp -i (which I found out with type cp), and bypassed by using \cp -rf ./mydir/* ./ which seems to have worked. Although I've solved the problem of getting dirs/files from one place to another, I'm still curious as to what's going on with the mv stuff - is this really a deliberate feature as suggested by Warner?

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  • How to make new file permission inherit from the parent directory?

    - by Wai Yip Tung
    I have a directory called data. Then I am running a script under the user id 'robot'. robot writes to the data directory and update files inside. The idea is data is open for both me and robot to update. So I setup the permission and owner group like this drwxrwxr-x 2 me robot-grp 4096 Jun 11 20:50 data where both me and robot belongs to the 'robot-grp'. I change the permission and the owner group recursively like the parent directory. I regularly upload new files into the data directory using rsync. Unfortunately, new files uploaded does not inherit the parent directory's permission as I hope. Instead it looks like this -rw-r--r-- 1 me users 6 Jun 11 20:50 new-file.txt When robot tries to update new-file.txt, it fails due to lack of file permission. I'm not sure if setting umask helps. In anycase the new files does not really follow it. $ umask -S u=rwx,g=rx,o=rx I'm often confounded by Unix file permission. Do I even have a right plan? I'm using Debian lenny.

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  • How do I create an ISO image from a directory structure on CentOS?

    - by tom smith
    I'm trying to figure out the exact mkisofs cmd to create the ISO with the following directory and file structure. I've tried different commands, but when I mount the ISO that is created the directory tree has not been reproduced. The initial directory tree is: master.iso:: mount -o loop /apps/vmware/master.iso /mnt/vmtest ls /mnt/vmtest isolinux ks.cfg upgra32 upgra64 upgrade.sh ls /mnt/vmtest/isolinux boot.cat initrd.img isolinux.bin isolinux.cfg vmlinuz I've used different variations of the following mkisofs command without success: mkisofs -o '/foo/test.iso' -b 'isolinux.bin' -c 'boot.cat' -no-emul-boot -boot-load-size 4 -boot-info-table 'isolinux' How do I make an ISO that captures a directory's exact structure?

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  • Why is .htaccess not allowed in a directory but is allowed in another?

    - by John Isaacks
    I have apache2 installed on ubuntu 10.4 inside my var/www/ directory [amung others] I have a cakephp and a dvdcatalog directories. Each of which have CakePHP 1.3 installed. I can access them both via localhost/cakephp and localhost/dvdcatalog But the dvdcatalog shows up with no css styling. They both have these files: /var/www/cakephp/app/webroot/css/cake.generic.css /var/www/dvdcatalog/app/webroot/css/cake.generic.css But when I go to http://localhost/cakephp/css/cake.generic.css it sees the file but it does not see the file when I go to http://localhost/dvdcatalog/css/cake.generic.css I think this means the cakephp folder is able to use .htaccess and the dvdcatalog is not. I setup the cakephp directory last month when I was following in the blog tutorial. I am setting up the dvdcatalog directory now for a different tutorial. So I am not sure if I am missing a step. in my /etc/apache2/apache2.conf file I have this: <Directory "/var/www/*"> Order allow,deny Allow from all AllowOverride All </Directory> Which I thought gave .htaccesss to all. Does anyone have any ideas what the problem is?

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  • How to figure out which directory is web server root?

    - by matt
    I want to view websites hosted on my Mac when running Windows VMware Fusion. I have an entry in the Windows hosts file to enable the routing: #ip of my mac domain i use on the VM to access it 192.168.1.70 mymac However, it resolves to an empty directory as a 404 is generated. I can see the access log on my Mac that everything is OK access wise. Firefox on VMware states the following response headers: Server Apache/2.2.14 (Unix) mod_ssl/2.2.14 OpenSSL/0.9.8l DAV/2 PHP/5.3.1 Any ideas how I can figure out what directory is being served? I am lost in a maze of twisty httpd.conf passages. localhost on my Mac resolves to my ~/Sites directory. 192.168.1.70 resolves to the same empty directory/404. Thanks.

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  • How can I set up an FTP user with a home directory inside another user's home folder?

    - by simon180
    Hi I have an Ubuntu (Hardy) server which I am using to host multiple websites. All of the sites are stored in subfolders of a public_html folder for my main login to the server and accessed via a single SSH account. I now have a website user who wants FTP (or similar) access to enable them to upload various files etc to the directory where their website is situated, however I still need the SSH account to have access to this directory as I may need to make changes using my master account. Basically I want to create an FTP account (I have VSFTPD installed) for a user with the home directory inside my own user account but they should only be able to read/write to this folder or its subfolders but not go further up the directory tree. How can I achieve this? Thanks

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