Simplest way to get current time in current timezone using boost::date_time ?
- by timday
If I do date +%H-%M-%S on the commandline (Debian/Lenny), I get a user-friendly (not UTC, not DST-less, the time a normal person has on their wristwatch) time printed.
What's the simplest way to obtain the same thing with boost::date_time ?
If I do this:
std::ostringstream msg;
boost::local_time::local_date_time t =
boost::local_time::local_sec_clock::local_time(
boost::local_time::time_zone_ptr()
);
boost::local_time::local_time_facet* lf(
new boost::local_time::local_time_facet("%H-%M-%S")
);
msg.imbue(std::locale(msg.getloc(),lf));
msg << t;
Then msg.str() is an hour earlier than the time I want to see. I'm not sure whether this is because it's showing UTC or local timezone time without a DST correction (I'm in the UK).
What's the simplest way to modify the above to yield the DST corrected local timezone time ? I have an idea it involves boost::date_time:: c_local_adjustor but can't figure it out from the examples.
