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• Is it possible to have two HDD's, and both be primary?

  - by qwerty2

  Here is my configuration: C: - system/Windows XP HDD D: - empty I just added a new hard drive (D) and formatted it and made it a primary HDD. Since then Windows hasn't been able to boot. Is the computer able to have both the system and the new HDD as primary? If not, then that is why Windows isn't booting. If it IS possible, then I have no idea what the problem is. Any help or thoughts would be fantastic! thanks!

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• JavaScript: One ID, two functions. How can I do this with minimal code duplication?

  - by user1775598

  I've got an ID and I'd like to assign two functions to it. Here's what it currently looks like: document.getElementById(this.config.dragArea).addEventListener("drop", this._dropFiles, false); document.getElementById(this.config.dragArea).addEventListener("drop", this._handleFileDrop, false); How can I rewrite this file without so much duplication? I tried doing document.getElementById(this.config.dragArea).addEventListener("drop", this._dropFiles, this._handleFileDrop, false); and document.getElementById(this.config.dragArea).addEventListener("drop", function(){this._dropFiles; this._handleFileDrop}, false); All to no avail :(

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• Howto synchronize two folders (on different servers) after an (classic) ASP upload.

  - by MaxBlack

  hi I'm using a customized backend to upload images on a server. The issue is that the client has a load balanced server so I need to synchronize the upload folders on both server. I'm not able to know which server is executing on the backend. I'm just wondering which is the best way to compare and synchronize the folders on two servers? An FTP script using the windows "cron-job"? A shell script activated by ASP? Aa ASP script that uses FTP commands? thanks

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• How to determine if two strings are sufficiently close?

  - by A.06

  We say that we can "hop" from the word w1 to the word w2 if they are "sufficiently close". We define w2 to be sufficiently close to w1 if one of the following holds: w2 is obtained from w1 by deleting one letter. w2 is obtained from w1 by replacing one of the letters in w1 by some letter that appears to its right in w1 and which is also to its right in alphabetical order. I have no idea how to check if 2. is fulfilled. To check if 1. is possible this is my function: bool check1(string w1, string w2){ if(w2.length - w1.length != 1){ return false; } for(int i = 0,int j = 0;i < w2.length;i++;j++){ if(w2[i] == w1[j]){//do nothing } else if(i == j){ j++; } else{ return false; } } return true; } Given two words w1 and w2, how do we check if we can 'hop' from w1 to w2?

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• Begin the Clone Wars Have!

  - by Antony Reynolds

  Creating a New Virtual Machine from an Existing Virtual Disk In previous posts I described how I set up an OEL6 machine under VirtualBox that can run an 11gR2 database and FMW 11.1.1.5.  That is great if you want the DB and FMW running in the same virtual image and it has served me well for some proof of concepts and also for some testing of different JVMs.  However I also wanted to run some testing of FMW with the database running on a separate physical machine.  So in this post I will show how to take a VirtualBox image and create a new image based on the disks from that original image. What are my Options? There is more than one way to skin a cat, or in this case to create two separate VMs that can run on different hardware.  Some of the options include: Create new virtual disk images for each new VM. Clone the existing disk images and point the new VM at the cloned images. Point the new VM at the existing snapshots. #1 is too much like hard work, install OEL twice, install a database again, install FMW again, run RCU again!  Life is too short! #2 is probably the safest way of doing things.  VirtualBox allows you to clone a disk image for use in a separate machine.  However this of course duplicates the disk and means that it is now occupying 3 times the space, once for the original disk and twice more for the two clones I would need. #3 is the most space efficient way of doing things.  It does mean however that I can only run the new “cloned” images if I have access to the original image because that is where the base snapshots reside.  However this is not a problem for me as long as I remember to keep all threee images together.  So this is the approach we will follow. Snapshot, What Snapshot? As we are going to create new virtual machines based on existing snapshots we need to figure out which snapshot to use.  We do this by opening the “Media Manager” from within VirtualBox and moving the mouse over the snapshot images until we find the snapshots we want – the snapshot name is identified in the “Attached to:” comment.  In my case I wanted the FMW installed snapshot because that had a database configured for FMW alongside the FMW software.  I made a note of the filename of that snapshot (actually I just noted the first 5 characters as that was all that was needed to uniquely identify the snapshot file). When we create the new machines we will point them at the snapshot filename we have just checked. Network or NotWork? Because we want the two new machines to communicate with each other when hosted in different physical machines we can’t use the default NAT networking mode without a lot of hassle.  But at the same time we need them to have fixed IP addresses relative to each other so that they can see each other whilst also being able to see the outside world. To achieve all these requirements I created two network adapters for each machine.  Adapter 1 was a standard NAT mapping.  This will allow each machine to get a dynamic IP address (10.0.2.15 by default) that can be used to access the external world through the VBox provided NAT gateway.  This is the same as the existing configuration. The second adapter I created as a bridged adapter.  This gives the virtual machine direct access to the host network card and by using fixed IP addresses each machine can see the other.  It is important to choose fixed IP addresses that are not routable across your internal network so you don’t get any clashes with other machines on your network.  Of course you could always get proper fixed IP addresses from your network people, but I have serveral people using my images and as long as I don’t have two instances of the same VM on the same network segment this is easier and avoids reconfiguring the network every time someone wants a copy of my VM.  If it is available I would suggest using the 10.0.3.* network as 10.0.2.* is the default NAT network.  You can check availability by pinging 10.0.3.1 and 10.0.3.2 from your host machine.  If it times out then you are probably safe to use that. Creating the New VMs Now that I had collected the data that I needed I went ahead and created the new VMs. When asked for a “Boot Hard Disk” I used the “Choose a virtual hard disk file…” link to find the snapshot I had previously selected and set that to be the existing hard disk.  I chose the previously existing SOA 11.1.1.5 install for both the new DB and FMW machines because that snapshot had the database with the RCU completed that I wanted for my DB machine and it had the SOA software installed which I wanted for my FMW machine. After the initial creation of the virtual machine go into the network setting section and enable a second adapter which will be bridged.  Make a note of the MAC addresses (the last four digits should be sufficient) of the two adapters so that you can later set the bridged adapter to use fixed IP and the NAT adapter to use DHCP. We are now ready to start the VMs and reconfigure Linux. Reconfiguring Linux Because I now have two new machines I need to change their network configuration.  In particular I need to change the hostname, update the hosts file and change the network settings. Changing the Hostname I renamed both hosts by running the hostname command as root: hostname vboxfmw.oracle.com I also edited the /etc/sysconfig file and set the correct hostname in there. HOSTNAME=vboxfmw.oracle.com Changing the Network Settings I needed to change the network configuration to give the bridged network a fixed IP address.  I first explicitly set the MAC addresses of the two adapters, because the order of the virtual adapters in the VirtualBox Manager is not necessarily the same as the order of the adapters in the guest OS.  So I went in to the System->Preferences->Network Connections screen and explicitly set the “Device MAC address” for the two adapters. Having correctly mapped the Linux adapters to the VirtualBox adapters I then set the Bridged adapter to use fixed IP addressing rather than DHCP.  There is no need for additional routing or default gateways because we expect the two machine to be on the same LAN segment. Updating the Hosts File Having renamed the machines and reconfigured the network I then updated the /etc/hosts file to refer to the new machine name add a new line to the hosts file to provide an additional IP address for my server (the new fixed IP address) add a new line for the fixed IP address of the other virtual machine 10.0.3.101      vboxdb.oracle.com       vboxdb  # Added by NetworkManager 10.0.2.15       vboxdb.oracle.com       vboxdb  # Added by NetworkManager 10.0.3.102      vboxfmw.oracle.com      vboxfmw # Added by NetworkManager 127.0.0.1       localhost.localdomain   localhost ::1     vboxdb.oracle.com       vboxdb  localhost6.localdomain6 localhost6 To make sure everything takes effect I restarted the server. Reconfiguring the Database on the DB Machine Because we changed the hostname the listener and the EM console no longer start so I need to modify the listener.ora to use the new hostname and I also need to rebuild the EM configuration because it also relies on the hostname. I edited the $ORACLE_HOME/network/admin/listener.ora and changed the listening address to the new hostname:       (ADDRESS = (PROTOCOL = TCP)(HOST = vboxdb.oracle.com)(PORT = 1521)) After changing the listener.ora I was able to start the listener using: lsnrctl start I also had to reconfigure the EM database control.  I first deconfigured it using the command: emca -deconfig dbcontrol db -repos drop This drops the repository and removes any existing registered dbcontrols. I then re-configured it using the following command: emca -config dbcontrol db -repos create This creates the EM repository and then configures and starts dbcontrol. Now my database machine is ready so I can close it down and take a snapshot. Disabling the Database on the FMW Machine I set up the database to start automatically by creating a service called “dbora”.  On the FMW machine I do not need the database running so I can prevent it auto-starting by running the following command: chkconfig –del dbora Note that because I am using a snapshot it is not a waste of disk space to have the DB installed but not used.  As long as I don’t run it, it won’t cost me anything. I can now close the FMW machine down and take a snapshot. Creating a New Domain The FMW machine is now ready to create a new domain.  When creating the domain I can point it at the second machine which is running the database.  I can potentially run these machines on two separate physical machines as long as I have the original virtual machine available to both of the physical machines. Gotchas in Snapshotting VirtualBox does not support the concept of linked machines in a network like some virtualization technologies so when creating a snapshot it is a good idea to shut both VMs down and then take a snapshot on both of them.  This is because we want to keep the database in sync with the middleware.  One way to make sure that this happens would be to place all the domain configuration files on the database server via an NFS share, this would mean that all we would need to snapshot would be the database machine because that would hold all the state and configuration. The Sky’s the Limit We have covered a simple case of having just two machines.  I have a more complicated configuration in which two machine run a RAC database off the same base OS image, and two more machines run a SOA cluster based on the same OS image.  Just remember what machine holds state and what are the consequences of taking a snapshot.

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• How does Google Analytics aggregate the Count of Visits (Frequency & Recency Report)?

  - by Brian Dant

  Here's my simple understanding of Count of Visits: Each person that comes to my site gets one "count" for each visit. They are put into a bucket of people with the same number of total counts -- if you visit twice, you are in the two bucket, if you visit six times, you are in the six bucket. From there, a report (Frequency & Recency) makes a line for each bucket and reaches into the bucket and totals the number of people in that bucket, putting that total in the second column. My Question: Will a two month report automatically put someone into two buckets, and put them on two separate lines in the Count of Visits table? This explaination makes it seem like a two-month long report will put the same person into a bucket twice, one bucket for each month. The two-month report will then show that person's visits on two different lines, instead of aggregating them. Example for Clarification: Bob comes to my site three times in January and seven times in February. I run a report for Jan 1 -- Feb 28. Will Bob be on both the Three Count line and the Seven Count line, or will he be on the Ten Count line?

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• Moving objects colliding when using unalligned collision avoidance (steering)

  - by James Bedford

  I'm having trouble with unaligned collision avoidance for what I think is a rare case. I have set two objects to move towards each other but with a slight offset, so one of the objects is moving slightly upwards, and one of the objects is moving slightly downwards. In my unaligned collision avoidance steering algorithm I'm finding the points on the object's forward line and the other object's forward line where these two lines are the closest. If these closest points are within a collision avoidance distance, and if the distance between them is smaller than the two radii of the two object's bounding spheres, then the objects should steer away in the appropriate direction. The problem is that for my case, the closest points on the lines are calculated to be really far away from the actual collision point. This is because the two forward lines for each object are moving away from each other as the objects pass. The problem is that because of this, no steering takes place, and the two objects partially collide. Does anyone have any suggestions as to how I can correctly calculate the point of collision? Perhaps by somehow taking into account the size of the two objects?

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• Microsoft JScript runtime error: Sys.InvalidOperationException: Two components with the same id.

  - by Irwin

  I'm working in ASP .NET dynamic data. In one of my edit controls I wanted to allow the user to add records from a related table to the current page. (Literally, if you are on the orders page, you would be allowed to add a new customer to the system on this page as well, and then associate it with that order). So, I have a DetailsView set to InsertMode, nested inside of an UpdatePanel, which is shown by a ModalPopupExtender which is invoked when 'add new' is clicked. This doohickey works the first time i execute this process, that is, a customer is added (and i update the dropdown list as well). However, I realized it didn't work (properly) again until I refreshed the entire page. When I attached my debugger, my worst fears were realized (ok, not really). But an exception was being thrown: "Microsoft JScript runtime error: Sys.InvalidOperationException: Two components with the same id." Which seemed to be complaining about a Calendar Extender Control that is part of the details view. Any guidance on what's going on here would be great. Thanks.

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• How to display two series via Google Chart API?

  - by Chris

  I can't get the two series of numbers to scale together. Here is sample code that you can paste into... http://code.google.com/intl/en/apis/chart/docs/chart_playground.html cht=lxy chs=400x300 chd=t:20,30,40|1,4,2|24,34,44|3,7,1 chds=20,40,1,4,24,44,1,7 chxr=0,20,54,2|1,0,7,1 chxt=x,y chxs=0,ff0000,12,0,lt 1,0000ff,10,1,lt chco=FF0000,00FF00 chdl=Apples Oranges chtt=Some+Values chts=0000ff,24 Translated: chd=t:s,e,r,i,e,s,1|s,e,r,i,e,s,2|...ors:series1,series2,...ore:series1,series2,... chds=<series_1_min>,<series_1_max>,... chxr=<axis_index>,<start_val>,<end_val>,<step>|... The three varying parameters in question are: chd=t:20,30,40|1,4,2|24,34,44|3,7,1 chds=20,40,1,4,24,44,1,7 chxr=0,20,54,2|1,0,7,1 Can anyone get this simple example working? The chart supports multiple series but for some reason I can't scale it so that the values are displayed within scale. Any help appreciated, Chris

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• Can the public ssh key from my local machine be used to access two different users on a remote serve

  - by Nick

  I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from ..*.* I then copied the authorized_keys file remote_server/home/user1/.ssh/authorized_keys to remote_server/home/user2/.shh/authorized_keys and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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• Can the same ssh key be used to access two different users on the same server?

  - by Nick

  I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key to authorized_keys in /home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 86.141.61.197 I then copied the authorized_keys file to /home/user2/.shh/ and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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• How to pass binary data between two apps using Content Provider?

  - by Viktor

  I need to pass some binary data between two android apps using Content Provider (sharedUserId is not an option). I would prefer not to pass the data (a savegame stored as a file, small in size < 20k) as a file (ie. overriding openFile()) since this would necessitate some complicated temp-file scheme to cope with concurrency with several content provider accesses and a running game. I would like to read the file into memory under a mutex lock and then pass the binary array in the simplest way possible. How do I do this? It seems creating a file in memory is not a possibility due to the return type of openFile(). query() needs to return a Cursor. Using MatrixCursor is not possible since it applies toString() to all stored objects when reading it. What do I need to do? Implement a custom Cursor? This class has 30 abstract methods. Do I read the file, put it in a SQLite db and return the cursor? The complexity of this seemingly simple task is mindboggling.

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• How to display two grids in same page using jquery?

  - by kumar

  hello friends, I have this code to display jquery grid <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JQGrid1") %> </div> Server side I have this code.. using System; using System.Collections.Generic; using System.Linq; using System.Web; using Trirand.Web.Mvc; using System.Web.UI.WebControls; namespace JQGridMVCExamples.Models { public class OrdersJqGridModel { public OrdersJqGridModel() { OrdersGrid = new JQGrid { Columns = new List<JQGridColumn>() { new JQGridColumn { DataField = "OrderID", Width = 50 }, new JQGridColumn { DataField = "OrderDate", Width = 100, DataFormatString = "{0:d}" }, new JQGridColumn { DataField = "CustomerID", Width = 100 }, new JQGridColumn { DataField = "Freight", Width = 75 }, new JQGridColumn { DataField = "ShipName" } }, Width = Unit.Pixel(640) }; OrdersGrid.ToolBarSettings.ShowRefreshButton = true; } public JQGrid OrdersGrid { get; set; } } } This is displaying only one grid... I I want to display two grids that Is how to display other grid in Same page? that is can I do like this? <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JQGrid1") %> </div> <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JQGrid2") %> </div> in the same page.. if yes how to handle the Sever side grid? bec Server side grid columns are differnt from jqGrid1 and Jqgrid2,,,, On Row Click on JQGrid1 I need to display JqGrid2. Please can anyone help me out about this.. Thanks

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• In git, how can I get the diff between two dates?

  - by Weidenrinde

  Basically, I am looking for something equivalent to cvs diff -D"1 day ago" -D"2010-02-29 11:11". While collecting more and more information, I found a solution. I paste it here, for others that might have similar problems. Things I have tried: In git, how can I get the diff between all the commits that occured between two dates? was ansered here with: git whatchanged --since="1 day ago" -p But this gives a diff for each commit, even if there are multiple commits in one file. I know that "date" is a bit of a loose concept in git, I thought there must be some way to do this. git diff 'master@{1 day ago}..master gives some warning warning: Log for 'master' only goes back to Tue, 16 Mar 2010 14:17:32 +0100. and does not show old diffs. git format-patch --since=yesterday --stdout does not give anything. revs=$(git log --pretty="format:%H" --since="1 day ago");git diff $(echo "$revs"|tail -n1) $(echo "$revs"|head -n1) works somehow, but seems complicated and does not restrict to the current branch. git diff $(git rev-list -n1 --before="1 day ago" master) seems to work and a default way to do similar things, although more complicated than I thought. Funnily, git-cvsserver does not support "cvs diff -D" (without that it is documented somewhere).

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• Why is graphviz drawing two arrows, and using a weird order?

  - by dmd

  Why is graphviz drawing two arrows from uncap_spike to peel, and why is it drawing peel to the right of hang? I want uncap_spike - peel - hang - spike, in that order, with one edge between each. digraph hangers { compound=true fontname="Gill Sans" node [fontname="Gill Sans" shape=box fillcolor=white style="rounded, filled"] edge [fontname="Gill Sans"] subgraph cluster_prep { style="filled" label=Prep gather [shape=Mrecord label="{gather | EtOH swab\nvented tubing}"] uncap_bottle [label="uncap bottle"] uncap_spike [label="uncap spike"] swab [shape=Mrecord label="{swab EtOH | wait 30 seconds for sterility}"] gather -> uncap_bottle -> swab -> uncap_spike {rank=same gather uncap_bottle swab uncap_spike} } subgraph cluster_hang { style=filled label=Hang {rank=same peel hang} } {rank=same uncap_spike -> peel -> hang -> spike -> prime} hang -> rip [color=firebrick] rip [label="eyelet\nripped" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] swab -> not_sterile [color=firebrick] not_sterile [label="not\nsterile" style="filled" shape=octagon regular fontcolor=white fontsize=10 width=.5 fixedsize color=firebrick fillcolor=firebrick ] }

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• verilog / systemverilog -- What is the behavior of blocking statements across two always blocks?

  - by miles.sherman

  I am wondering about the behavior of the below code. There are two always blocks, one is combinational to calculate the next_state signal, the other is sequential which will perform some logic and determine whether or not to shutdown the system. It does this by setting the shutdown_now signal high and then calling state <= next_state. My question is if the conditions become true that the shutdown_now signal is set (during clock cycle n) in a blocking manner before the state <= next_state line, will the state during clock cycle n+1 be SHUTDOWN or RUNNING? In other words, does the shutdown_now = 1'b1 line block across both state machines since the state signal is dependent on it through the next_state determination? enum {IDLE, RUNNING, SHUTDOWN} state, next_state; logic shutdown_now; // State machine (combinational) always_comb begin case (state) IDLE: next_state <= RUNNING; RUNNING: next_state <= shutdown ? SHUTDOWN : RUNNING; SHUTDOWN: next_state <= SHUTDOWN; default: next_state <= SHUTDOWN; endcase end // Sequential Behavior always_ff @ (posedge clk) begin // Some code here if (/*some condition) begin shutdown_now = 1'b0; end else begin shutdown_now = 1'b1; end state <= next_state; end

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• Can I combine two functions into one using Javascript?

  - by Melissa

  I have the following code that I would like to simplify. With javascript and jQuery is there an easy way that I could combine these two functions? Most of the code is the same but I am not sure how I could create a single function that works differently depending on what is clicked. $(document).ready(function () { $('#ListBooks').click(ListBooks); $('#Create').click(Create); }); function Create() { var dataSourceID = $('#DataSourceID').val(); var subjectID = $('#SubjectID').val(); var contentID = $('#ContentID').val(); if (dataSourceID && dataSourceID != '00' && subjectID && subjectID != "00" && contentID && contentID != "00") { var e = encodeURIComponent, arr = ["dataSourceID=" + e(dataSourceID), "subjectID=" + e(subjectID), "contentID=" + e(contentID)]; window.location.href = '/Administration/Books/Create?' + arr.join("&"); } else { alert('Datasource, Subject and Content must be selected.'); } return false; } function ListBooks() { var dataSourceID = $('#DataSourceID').val(); var subjectID = $('#SubjectID').val(); var contentID = $('#ContentID').val(); if (dataSourceID && dataSourceID != '00' && subjectID && subjectID != "00" && contentID && contentID != "00") { var e = encodeURIComponent, arr = ["dataSourceID=" + e(dataSourceID), "subjectID=" + e(subjectID), "contentID=" + e(contentID)]; window.location.href = '/Administration/Books/ListBooks?' + arr.join("&"); } else { alert('Datasource, Subject and Content must be selected.'); } return false; }

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• Ruby script/console and Ruby script/server using two different DBs?

  - by aronchick

  Has anyone seen where script/console and script/server load two different databases (though both report using the same)? Here's the first output $ script/server => Booting WEBrick => Rails 2.3.5 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server [2010-03-21 15:54:05] INFO WEBrick 1.3.1 [2010-03-21 15:54:05] INFO ruby 1.8.7 (2010-01-10) [i386-mingw32] [2010-03-21 15:54:05] INFO WEBrick::HTTPServer#start: pid=7148 port=3000 No errors. I then run my standard code for entering a form - no problems. Checking the Dev Database (.yml at bottom): mysql> select * from books; [...] | 712 | Book | Book Name | 2010-03-21 22:29:22 | 2010-03-21 22:29:22 | [...] 712 rows in set (0.00 sec) The code CLEARLY saved it seconds ago And now here's the output of script/console: $ script/console Loading development environment (Rails 2.3.5) >> Books.all => [] Nothing. Further, upon further inspection, it's using the production database, but I can't figure out why. Any thoughts here? All consoles have been closed and reopened. UPDATE: Requested .yml file (can't see how it'd be helpful (user name and password are all the same for each)) - development: adapter: mysql database: BooksDBdev username: <user name> password: <long string> timeout: 5000 # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql database: BooksDBtest username: <user name> password: <long string> timeout: 5000 production: adapter: mysql database: BooksDB username: <user name> password: <long string> timeout: 5000

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• I have two choices of Master's classes this fall. Which is the most useful?

  - by ahplummer

  (For background purposes and context): I am a Software Engineer, and manage other Software Engineers currently. I kind of wear two hats right now: one of a programmer, and one as a 'team lead'. In this regard, I've started going back to school to get my Master's degree with an emphasis in Computer Science. I already have a Bachelor's in Computer Science, and have been working in the field for about 13 years. Our primary development environment is a Windows environment, writing in .NET, Delphi, and SQL Server. Choice #1: CST 798 DATA VISUALIZATION Course Description: Basically, this is a course on the "Processing" language: http://processing.org/ Choice #2: CST 711 INFORMATICS Course Description: (From catalog): Informatics is the science of the use and processing of data, information, and knowledge. This course covers a variety of applied issues from information technology, information management at a variety of levels, ranging from simple data entry, to the creation, design and implementation of new information systems, to the development of models. Topics include basic information representation, processing, searching, and organization, evaluation and analysis of information, Internet-based information access tools, ethics and economics of information sharing.

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• How do I pass a LuaTable between two Lua states using LuaInterface?

  - by user316675

  I've been trying to pass a LuaTable class between two Lua states, like so: LuaManager L1 = new Lua(); LuaManager L2 = new Lua(); LuaTable table = L1.DoString("return {apple = 25}")[0]; L2["tbl"] = table; double results = L2.DoString("return tbl[\"apple\"]")[0]; Assert.AreEqual(25.0, results); The above test fails; I receive a return value of nil. Using the Immediate Window confirms that "table" is a non-null object, and that table["apple"] returns 25; it's something that's being lost in translation to L2. Interestingly, when the object is loaded back into the same state, the test works, like so: //Succeeds LuaManager lua = new Lua(); LuaTable table = lua.DoString("return {apple = 25}")[0]; lua["tbl"] = table; double results = lua.DoString("return tbl[\"apple\"]")[0]; Assert.AreEqual(25.0, results); How can I safely pass the LuaTables without hassles? Thanks in advance!

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• How do I combine two arrays in PHP based on a common key?

  - by Eoghan O'Brien

  Hi, I'm trying to join two associative arrays together based on an entry_id key. Both arrays come from individual database resources, the first stores entry titles, the second stores entry authors, the key=value pairs are as follows: array ( 'entry_id' => 1, 'title' => 'Test Entry' ) array ( 'entry_id' => 1, 'author_id' => 2 I'm trying to achieve an array structure like: array ( 'entry_id' => 1, 'author_id' => 2, 'title' => 'Test Entry' ) Currently, I've solved the problem by looping through each array and formatting the array the way I want, but I think this is a bit of a memory hog. $entriesArray = array(); foreach ($entryNames as $names) { foreach ($entryAuthors as $authors) { if ($names['entry_id'] === $authors['entry_id']) { $entriesArray[] = array( 'id' => $names['entry_id'], 'title' => $names['title'], 'author_id' => $authors['author_id'] ); } } } I'd like to know is there an easier, less memory intensive method of doing this?

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• In JSF - What is the correct way to do this? Two dropdown lists with dependency.

  - by Ben

  Hi, I'm making two dropdown lists in JSF which are dependent. Specifically, one list has all the languages and the second list contains values that are displayed in the currently selected language. I've implemented this by having the second list use information from a Hash and rebuilding that Hash in the setter of the currently selected language. JSF Code Bit: <rich:dropDownMenu value="#{bean.currentlySelectedLanguage}" id="languageSelector"> ... (binding to languages hash) ... <rich:dropDownMenu value="#{bean.currentlySelectedScript}" id="ScriptPullDown"> ... (binding to scripts hash) ... Backing Bean Code Bit: setCurrentlySelectedLanguage(String lang){ this.currentlySelectedLanguage = lang; rebuildScriptNames(lang); } I'm wondering if that's a good way of doing this or if theres a better method that I am not aware of. Thank you! EDIT - Adding info.. I used a a4j:support that with event="onchange" and ReRender="ScriptPullDown" to rerender the script pull down. I could probably add an action expression to run a method when the value changes. But is there a benefit to doing this over using code in the setter function?

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• How do I assert that two arbitrary type objects are equivalent, without requiring them to be equal?

  - by Tomas Lycken

  To accomplish this (but failing to do so) I'm reflecting over properties of an expected and actual object and making sure their values are equal. This works as expected as long as their properties are single objects, i.e. not lists, arrays, IEnumerable... If the property is a list of some sort, the test fails (on the Assert.AreEqual(...) inside the for loop). public void WithCorrectModel<TModelType>(TModelType expected, string error = "") where TModelType : class { var actual = _result.ViewData.Model as TModelType; Assert.IsNotNull(actual, error); Assert.IsInstanceOfType(actual, typeof(TModelType), error); foreach (var prop in typeof(TModelType).GetProperties()) { Assert.AreEqual(prop.GetValue(expected, null), prop.GetValue(actual, null), error); } } If dealing with a list property, I would get the expected results if I instead used CollectionAssert.AreEquivalent(...) but that requires me to cast to ICollection, which in turn requries me to know the type listed, which I don't (want to). It also requires me to know which properties are list types, which I don't know how to. So, how should I assert that two objects of an arbitrary type are equivalent? Note: I specifically don't want to require them to be equal, since one comes from my tested object and one is built in my test class to have something to compare with.

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• How can I find out if two arguments are instances of the same, but unknown class?

  - by Ingmar

  Let us say we have a method which accepts two arguments o1 and o2 of type Object and returns a boolean value. I want this method to return true only when the arguments are instances of the same class, e.g.: foo(new Integer(4),new Integer(5)); Should return true, however: foo(new SomeClass(), new SubtypeSomeClass()); should return false and also: foo(new Integer(3),"zoo"); should return false. I believe one way is to compare the fully qualified class names: public boolean foo(Object o1, Object o2){ Class<? extends Object> c1 = o1.getClass(); Class<? extends Object> c2 = o2.getClass(); if(c1.getName().equals(c2.getName()){ return true;} return false; } An alternative conditional statement would be : if (c1.isAssignableFrom(c2) && c2.isAssignableFrom(c1)){ return true; } The latter alternative is rather slow. Are there other alternatives to this problem?

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• SQL Query: How to determine "Seen during N hour" if given two DateTime time stamps?

  - by efess

  Hello all. I'm writing a statistics application based off a SQLite database. There is a table which records when users Login and Logout (SessionStart, SessionEnd DateTimes). What i'm looking for is a query that can show what hours user have been logged in, in sort of a line graph way- so between the hours of 12:00 and 1:00AM there were 60 users logged in (at any point), between the hours of 1:00 and 2:00AM there were 54 users logged in, etc... And I want to be able to run a SUM of this, which is why I can't bring the records into .NET and iterate through them that way. I've come up with a rather primative approach, a subquery for each hour of the day, however this approach has proved to be slow and slow. I need to be able to calculate this for a couple hundred thousand records in a split second.. SELECT case when (strftime('%s',datetime(date(sessionstart), '+0 hours')) > strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+0 hours')) < strftime('%s',sessionend)) OR (strftime('%s',datetime(date(sessionstart), '+1 hours')) > strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+1 hours')) < strftime('%s',sessionend)) OR (strftime('%s',datetime(date(sessionstart), '+0 hours')) < strftime('%s',sessionstart) AND strftime('%s',datetime(date(sessionstart), '+1 hours')) > strftime('%s',sessionend)) then 1 else 0 end as hour_zero, ... hour_one, ... hour_two, ........ hour_twentythree FROM UserSession I'm wondering what better way to determine if two DateTimes have been seen durring a particular hour (best case scenario, how many times it has crossed an hour if it was logged in multiple days, but not necessary)? The only other idea I had is have a "hour" table specific to this, and just tally up the hours the user has been seen at runtime, but I feel like this is more of a hack than the previous SQL. Any help would be greatly appreciated!

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