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• Windows 7 VM log on lockout

  - by AKa

  My Windows 7 XP Mode virtual machine has just locked me out of password log on. Two years of use and it never required I use a password on wake up, I never asked for that. Suddenly yesterday, password required! I located password and used it successfully a couple of times, but now even that is not good enough! Perhaps (unfairly) because I tried to get to the bottom of the new phenomenon and removed the password from the user accounts? Permissions are still set to ok for all users. I have been all the way through the settings I can access with the VM file hibernated, and have deleted the previously saved log on info, which always previously worked automatically as charged. Now when I attempt to log on it asks me for credentials, seems like progress, but when I offer them, and check the "remember my credentials" box, I still get the splash screen "The system could not log you on. [reminder about caps...]" !! Round and round. Back up and restore point versions of the VM toss me back into the same log on loop. There are no other machines on any network, I am the administrator and sole user. It must be specifically about the log on, a speck of dust corruption ... is there a way around this? I tried creating a new VM but the black inner box gets stuck at one point requesting I insert a boot disc. Thanks for input, AKa

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• Reset disk does not work for different model of computer

  - by dato

  I've created a reset USB disk on my HP computer, with Windows 7 Ultimate 32-bit, and it works fine. However, it does not work for Acer computers (notebooks too), so what is the problem here? I've have created it for the same user named user, and the password is exactly the same as well. Is it possible to show the language bar with a keyboard shortcut at the logon screen in Windows 7? I know I can do it through Control Panel, but I can't log into the system. When I click Reset Passwword, it shows me my USB flash drive and says that the password hint is on this USB drive. Then I click Next and type the new passwword, then confirm this new password, but an error dialog is shown. It says that an error occured when trying to change the password for this user-

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• How to send e-mail to customers using quick campaing?

  - by ripperus

  I have a question/problem. I want sent email to my clients using quick campaing. But in those emails I want to put some information for only this customer. For example: First customer - A - have a information: login: only_for_A and password: only_for_A Second customer - B - have a information: login: only_for_B and password: only_for_B etc. But the passwords are in Excel file. Is there any possibility to automatically add login and password to email?

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• Cannot log-in in the install of phpmyadmin on Ubuntu

  - by Sylario

  I just installed phpmyadmin and i am trying to login in /phpmyadminpath/setup. I am greeted by an invite similar to an apache protected folder (log/password displayed in a browser pop-up, not an html popup) asking for login pass. I cannot login using system password(root) or mysql passsword(also root) I already have rails app using this mysql, and i checked the mysql password in the config files. I cannot run any mysql command in my console because of the following error : ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: NO) What is wrong with phpmyadmin and mysql?

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• SSH connect error

  - by DMDGeeker

  I use a notebook with Ubuntu 12.10 and try to connect a server with Ubuntu 12.04. The server has already installed openssh-server. And allow publick key and password to login. But I connect the server sometime well but after minutes it will be error. First, it will show me these messages:    WARNING: REMOTE HOST IDENTIFICATION HAS CHANGED!    ......    Add correct host key in /home/myname/.ssh/known_hosts to get rid of this message. but I never reinstall system and the openssh-server. Both are never changed! The server nerver shutdown or reboot. Second, after I remove the relative key from my known_hosts and use ssh connect the server again, it will let me type my password. then my nightmare coming... Permission denied (publickey,password) But I typed the correct password! PS: I used password and public key both success. But the problem will appear again after i logout then login.

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• Connect to server via SSH2 [closed]

  - by SaulTigh

  I'm using http://www.hetzner.de/en/. They send me something like that: Your Hetzner-Server is now active. Thank you for choosing Hetzner Online as your Web Hosting partner. You can access your server immediately via SSH2, using following details: IP-Address: *.*.*.* Login: "login" Password: "password" So, I'm trying to connect to this server in this way: ssh login@*.*.*.* Then I input my password, but it gives an error "permission denied". Can anyone tel me why and how can I fix this?

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• Is it possible to allow saved passwords for remote desktop in a domain environment?

  - by user2813274

  I have checked the "remember password" and every single time, even if it connects correctly after I type a password and check the box, it does not allow subsequent logins using the stored password, saying that it is invalid - is it being saved improperly somehow? is it being disabled by some obscure setting somewhere? (which would be very counter-intuitive, seeing as how the check box is available). I have tried both with domain and non-domain (local) admin accounts, and am using the FQDN for the server. edit: as a troubleshooting step, where would one go to find the (hopefully hashed) password?

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• Can't access unprotected .pst file in Outlook 2010

  - by KGraves

  My father has a Windows 7 x64 system with 32-bit Outlook 2010. He asked me to access his archived mail to get to some old mail. When going to open the file I'm asked for a password (he never applied one) and I get a message saying "password is incorrect. Re-Type password". Since he told me that he never set a password I tried opening the .pst with Nucleus, a tool that allows me to view the .pst's. Does anyone know what the deal is? With the free version of Nucleus we can't view the attachments.

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• Twitter Bootstrap modal spans, side-by-side divs and "control-group"?

  - by Federico Stango

  I'm trying my best to have a good looking modal login form but for some reasons it seems that no matter how I nest divs, I cannot obtain the proper shape. What I need is a big "lock" image side-by-side with a username/password form. The best I could do adds a horizontal scroller by the modal bottom and shows the input gadgets fairly distant from the image partly hidden on the right side of the modal canvas. Inspecting with FireBug it seems that the spans in row-fluid are ok but the "control-label" and "controls" class adds way too much space on the left by width (for the labels) and margin-left (for the controls). How would you solve it? Am I doing something wrong with divs and classes nesting? This is the current modal without the main wrapper as it gets added by some js code that loads modal contents through ajax: <form class="form-horizontal" id="login" name="login" method="post" action="<?php echo site_url('user/login'); ?>"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button> <h3>Login</h3> </div> <div class="modal-body"> <?php if ( isset($error) ) { ?> <div class="row"> <div class="alert alert-error"> <strong>Warning!</strong> <?php echo $error; ?> </div> </div> <?php } ?> <div class="row-fluid"> <div class="span4"> <img src="skins/frontend/base/images/lock.png" width="96px" height="96px" /> </div> <div class="span8"> <div class="control-group"> <label class="control-label" for="email">Email</label> <div class="controls"><input type="text" placeholder="Type your email" id="email" name="email" /></div> <?php echo form_error('email', '<div id="error_email" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <label class="control-label" for="password">Password</label> <div class="controls"><input type="password" placeholder="Password" id="password" name="password" /></div> <?php echo form_error('password', '<div id="error_password" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <div class="controls"><label class="checkbox inline"><input type="checkbox" id="remember" name="remember" checked="checked" />&nbsp;Remember Me</label></div> </div> </div> </div> </div> <div class="modal-footer"> <button type="submit" class="btn btn-primary">Login</button> </div> </form> Just don't take into account the php code you see... :) Thanks in advance for all the support you can give! Federico

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• Iphone sdk, How to post data to web server? anybody has example ?

  - by user352385

  Hi, guys, I want to post data to web server, like username and password, on the web server, I used PHP to echo yes or no, I attached all the code. Can anybody help me out, what is wrong with the code. Since it always says incorrect password or username. I tried to test the php code with username and password inside, it is working. So please help me. Thank you. Header file @interface kiksyloginViewController : UIViewController { IBOutlet UITextField *usernameField; IBOutlet UITextField *passwordField; IBOutlet UIButton *loginButton; } @property (nonatomic, retain) UITextField *usernameField; @property (nonatomic, retain) UITextField *passwordField; @property (nonatomic, retain) UIButton *loginButton; (IBAction) login: (id) sender; @end Implementation file #import "kiksyloginViewController.h" @implementation kiksyloginViewController @synthesize usernameField; @synthesize passwordField; @synthesize loginButton; (IBAction) login: (id) sender { NSString *post =[NSString stringWithFormat:@"username=%@&password=%@",usernameField.text, passwordField.text]; NSString *hostStr = @"http://localhost/userlogin.php"; hostStr = [hostStr stringByAppendingString:post]; NSData *dataURL = [NSData dataWithContentsOfURL: [ NSURL URLWithString: hostStr ]]; NSString *serverOutput = [[NSString alloc] initWithData:dataURL encoding: NSASCIIStringEncoding]; if([serverOutput isEqualToString:@"Yes"]){ UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Congrats" message:@"You are authorized " delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil]; [alertsuccess show]; [alertsuccess release]; } else { UIAlertView *alertsuccess = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Username or Password Incorrect" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil, nil]; [alertsuccess show]; [alertsuccess release]; } } (void)didReceiveMemoryWarning { // Releases the view if it doesn’t have a superview. [super didReceiveMemoryWarning]; // Release any cached data, images, etc that aren’t in use. } (void)viewDidUnload { // Release any retained subviews of the main view. // e.g. self.myOutlet = nil; } (void)dealloc { [super dealloc]; } @end PHP file <?php //$Container = new Container ; $u = $_GET['username']; $pw =$_GET['password']; $check = "select username, password from user where username='$u' and password='$pw'"; function myDbconn() { mysql_connect("localhost", "root","") or die(); mysql_select_db("test") or die (mysql_error()); } myDbconn(); $login = mysql_query($check) or die (mysql_error()); //$run = DB()-select($check); if (mysql_num_rows($login)==1){ //$row = DB()-fetch($run); //$row = DB()-fetch($login); $row = mysql_fetch_assoc($login); echo 'yes'; exit; } else { echo 'No'; exit; } ?

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• iphone app: delegate not responding

  - by Fiona

  Hi guys.. So i'm very new to this iphone development stuff.... and i'm stuck. I'm building an app that connects to the twitter api. However when the connectionDidFinishLoading method gets called, it doesn't seem to recognise the delegate. Here's the source code of the request class: import "OnePageRequest.h" @implementation OnePageRequest @synthesize username; @synthesize password; @synthesize receivedData; @synthesize delegate; @synthesize callback; @synthesize errorCallBack; @synthesize contactsArray; -(void)friends_timeline:(id)requestDelegate requestSelector:(SEL)requestSelector{ //set the delegate and selector self.delegate = requestDelegate; self.callback = requestSelector; //Set up the URL of the request to send to twitter!! NSURL *url = [NSURL URLWithString:@"http://twitter.com/statuses/friends_timeline.xml"]; [self request:url]; } -(void)request:(NSURL *) url{ theRequest = [[NSMutableURLRequest alloc] initWithURL:url]; theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self]; if (theConnection){ //Create the MSMutableData that will hold the received data. //receivedData is declared as a method instance elsewhere receivedData=[[NSMutableData data] retain]; }else{ //errorMessage.text = @"Error connecting to twitter!!"; } } -(void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge{ if ([challenge previousFailureCount] == 0){ NSLog(@"username: %@ ",[self username]); NSLog(@"password: %@ ",[self password]); NSURLCredential *newCredential = [NSURLCredential credentialWithUser:[self username] password:[self password] persistence:NSURLCredentialPersistenceNone]; [[challenge sender] useCredential:newCredential forAuthenticationChallenge:challenge]; } else { [[challenge sender] cancelAuthenticationChallenge:challenge]; NSLog(@"Invalid Username or password!"); } } -(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response{ [receivedData setLength:0]; } -(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data{ [receivedData appendData:data]; } -(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error{ [theConnection release]; [receivedData release]; [theRequest release]; NSLog(@"Connection failed. Error: %@ %@", [error localizedDescription], [[error userInfo] objectForKey:NSErrorFailingURLStringKey]); if(errorCallBack){ [delegate performSelector:errorCallBack withObject:error]; } } -(void)connectionDidFinishLoading:(NSURLConnection *)connection{ if (delegate && callback){ if([delegate respondsToSelector:[self callback]]){ [delegate performSelector:[self callback] withObject:receivedData]; }else{ NSLog(@"No response from delegate!"); } } [theConnection release]; [theRequest release]; [receivedData release]; } Here's the .h: @interface OnePageRequest : NSObject { NSString *username; NSString *password; NSMutableData *receivedData; NSURLRequest *theRequest; NSURLConnection *theConnection; id delegate; SEL callback; SEL errorCallBack; NSMutableArray *contactsArray; } @property (nonatomic,retain) NSString *username; @property (nonatomic,retain) NSString *password; @property (nonatomic,retain) NSMutableData *receivedData; @property (nonatomic,retain) id delegate; @property (nonatomic) SEL callback; @property (nonatomic) SEL errorCallBack; @property (nonatomic,retain) NSMutableArray *contactsArray; -(void)friends_timeline:(id)requestDelegate requestSelector:(SEL)requestSelector; -(void)request:(NSURL *) url; @end In the method: connectionDidFinishLoading, the following never gets executed: [delegate performSelector:[self callback] withObject:receivedData]; Instead I get the message: "No response from delegate" Anyone see what I'm doing wrong?! or what might be causing the problem? Regards, Fiona

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• Opinions on Dual-Salt authentication for low sensitivity user accounts?

  - by Heleon

  EDIT - Might be useful for someone in the future... Looking around the bcrypt class in php a little more, I think I understand what's going on, and why bcrypt is secure. In essence, I create a random blowfish salt, which contains the number of crypt rounds to perform during the encryption step, which is then hashed using the crypt() function in php. There is no need for me to store the salt I used in the database, because it's not directly needed to decrypt, and the only way to gain a password match to an email address (without knowing the salt values or number of rounds) would be to brute force plain text passwords against the hash stored in the database using the crypt() function to verify, which, if you've got a strong password, would just be more effort than it's worth for the user information i'm storing... I am currently working on a web project requiring user accounts. The application is CodeIgniter on the server side, so I am using Ion Auth as the authentication library. I have written an authentication system before, where I used 2 salts to secure the passwords. One was a server-wide salt which sat as an environment variable in the .htaccess file, and the other was a randomly generated salt which was created at user signup. This was the method I used in that authentication system for hashing the password: $chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; //create a random string to be used as the random salt for the password hash $size = strlen($chars); for($i = 0; $i < 22; $i++) { $str .= $chars[rand(0, $size - 1)]; } //create the random salt to be used for the crypt $r_blowfish_salt = "$2a$12$" . $str . "$"; //grab the website salt $salt = getenv('WEBSITE_SALT'); //combine the website salt, and the password $password_to_hash = $pwd . $salt; //crypt the password string using blowfish $password = crypt($password_to_hash, $r_blowfish_salt); I have no idea whether this has holes in it or not, but regardless, I moved over to Ion Auth for a more complete set of functions to use with CI. I noticed that Ion only uses a single salt as part of its hashing mechanism (although does recommend that encryption_key is set in order to secure the database session.) The information that will be stored in my database is things like name, email address, location by country, some notes (which will be recommended that they do not contain sensitive information), and a link to a Facebook, Twitter or Flickr account. Based on this, i'm not convinced it's necessary for me to have an SSL connection on the secure pages of my site. My question is, is there a particular reason why only 1 salt is being used as part as the Ion Auth library? Is it implied that I write my own additional salting in front of the functionality it provides, or am I missing something? Furthermore, is it even worth using 2 salts, or once an attacker has the random salt and the hashed password, are all bets off anyway? (I assume not, but worth checking if i'm worrying about nothing...)

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• FTP into a server using specific usernames

  - by user1854765

  I am trying to ftp into a server, once I'm there, I want to get a file, then put it back after sleeping for 5 minutes. I have that part correct, but i added to the code, two variables that will be inputted when the code is executed. The user will input the username they want to connect with. I am having trouble connecting though. When I input the username t14pb, it still goes to the the first if statement, as if I said t14pmds. here is the code: #!/usr/bin/perl use Net::FTP; $host = "fd00p02"; $username = "$ARGV[0]"; $ftpdir = "/"; $file = "$ARGV[1]"; print "$username\n"; print "$file\n"; if ($username == t14pmds) { $password = "test1"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14pb) { $password = "test2"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14pmds_out) { $password = "test3"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14fiserv) { $password = "test4"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; }

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• header() function in php : No any redirection!

  - by jasmine

  I have written a very very very simple!! script in php. header redirection not working. 1- encoding : UTF-8 without BOM 2- with adding ob_start() the problem is countiueing. What is wrong in my code; login.php: <?php session_start(); require_once("funcs.php"); db_connection(); $username = $_POST['username']; $password = $_POST['pwd']; $submit = $_POST['login']; if($submit){ if (!filled_out($_POST)) { echo "please fill all fields"; } else{ $query = "SELECT * FROM users WHERE username ='{$username}' AND password ='{$password}'"; $result = mysql_query($query); if(mysql_num_rows($result) == 1){ $found_user = mysql_fetch_array($result); $_SESSION['id'] = $found_user['id']; $_SESSION['username'] = $found_user['username']; $_SESSION['password'] = $found_user['password']; setcookie(session_name(), '', time()+86400, '/'); header("Location: tst.php"); } else{ echo "incorrect username or password"; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org /TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p> <label for="username">Username:</label> <input type="text" name="username" id="username" /> </p> <p> <label for="textfield">Password</label> <input type="password" name="pwd" id="pwd" /> </p> <p> <input name="login" type="submit" id="login" value="Log in" /> </p> </form> </body> </html> <?php db_disconnect();?> and tst.php: <?php session_start(); require_once("funcs.php"); if (!isset($_SESSION['id'])){ header("Location : login.php"); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <table id="structure"> <tr> <td id="navigation">&nbsp; </td> <td id="page"> <?php echo "welcome"."". $_SESSION['username']; ?> </td> </tr> </table> </body> </html> <?php db_disconnect();?> wthit oppening tst.php directly, header() doesnot redirect to login.php

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• Mount SMB / AFP 13.10

  - by Jeffery

  I cannot seem to get Ubuntu to mount a mac share via SMB or AFP. I've tried the following... AFP: apt-get install afpfs-ng-utils mount_afp afp://user:password@localip/share /mnt/share Error given: "Could not connect, never got a reponse to getstatus, Connection timed out". Which is odd as I can access the share just fine via Mac. SMB: apt-get install cifs-utils nano /etc/fstab added the following line "//localip/share /mnt/share cifs username=user,password=pass,iocharset=utf8,sec=nltm 0 0" mount -a Error given: root@Asrock:~# mount -a -vvv mount: fstab path: "/etc/fstab" mount: mtab path: "/etc/mtab" mount: lock path: "/etc/mtab~" mount: temp path: "/etc/mtab.tmp" mount: UID: 0 mount: eUID: 0 mount: spec: "//10.0.1.3/NAS" mount: node: "/mnt/NAS" mount: types: "cifs" mount: opts: "username=user,password=pass,iocharset=utf8,sec=nltm" mount: external mount: argv[0] = "/sbin/mount.cifs" mount: external mount: argv[1] = "//10.0.1.3/NAS" mount: external mount: argv[2] = "/mnt/NAS" mount: external mount: argv[3] = "-v" mount: external mount: argv[4] = "-o" mount: external mount: argv[5] = "rw,username=user,password=pass,iocharset=utf8,sec=nltm" mount.cifs kernel mount options: ip=10.0.1.3,unc=\\10.0.1.3\NAS,iocharset=utf8,sec=nltm,user=user,pass=* mount error(22): Invalid argument Refer to the mount.cifs(8) manual page (e.g. man mount.cifs) I don't really care which it uses I just want it to work! Am I doing something wrong?

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• How to login as other in ubuntu 12.04

  - by murali

  i have upgraded my ubuntu 11.10 to 12.04. i could not see other login option in the login screen. it shows only Guest login and User login. The User Login ask only password and i had never entered in as User login so that i do not know about password of User login. my problem is how to login as root from the login screen? how can i get Other login option to login as root or some other user? before ask this question i have tried the following: try to add the greeter-show-manual-login=true line at the bottom of /etc/lightdm/lightdm.conf file as Guest login but i get access denied error. i do not know the password of User login (ask only password while login) to purpose of adding above line. from the safe mode login, i could login as root but i could not add the above line the lightdm.conf file . i got read only error so that i tried to change the permission to 777 like the following > chmod 777 lightdm.conf (i am within the /etc/lightdm/). but i got the error the file marked as/is read only in the file system. In 11.10 version i have created 4 users. i can see that the users exist in 12.10 . so i am sure my self users are not removed while upgrate. In short, i need Other login option on my login screen? how to get it? please help me. * Edited Question:* i have add the following line the /etc/lightdm/lighdm.conf file on recovery mode greeter-show-manual-login=true and i saved the file using wq command. now my /etc/lightdm/lighdm.conf file looking as the following: [SeatDefaults] greeter-session=unity-greeter user-session=ubuntu greeter-show-manual-login=true if i commit any mistake please correct me. by this problem i have wasted the two working day and all the works are in pending... please help me.

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• "ldap_add: Naming violation (64)" error when configuring OpenLDAP

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• MVC OnActionExecuting to Redirect

  - by Aligned

  Originally posted on: http://geekswithblogs.net/Aligned/archive/2014/08/12/mvc-onactionexecuting-to-redirect.aspxI recently had the following requirements in an MVC application: Given a new user that still has the default password When they first login Then the user must change their password and optionally provide contact information I found that I can override the OnActionExecuting method in a BaseController class.public class BaseController : Controller { [Inject] public ISessionManager SessionManager { get; set; } protected override void OnActionExecuting(ActionExecutingContext filterContext) { // call the base method first base.OnActionExecuting(filterContext); // if the user hasn't changed their password yet, force them to the welcome page if (!filterContext.RouteData.Values.ContainsValue("WelcomeNewUser")) { var currentUser = this.SessionManager.GetCurrentUser(); if (currentUser.FusionUser.IsPasswordChangeRequired) { filterContext.Result = new RedirectResult("/welcome"); } } } } Better yet, you can use an ActionFilterAttribute (and here) and apply the attribute to the Base or individual controllers./// <summary> /// Redirect the user to the WelcomePage if the FusionUser.IsPasswordChangeRequired is true; /// </summary> public class WelcomePageRedirectActionFilterAttribute : ActionFilterAttribute { [Inject] public ISessionManager SessionManager { get; set; } public override void OnActionExecuting(ActionExecutingContext actionContext) { base.OnActionExecuting(actionContext); // if the user hasn't changed their password yet, force them to the welcome page if (actionContext.RouteData.Values.ContainsValue("WelcomeNewUser")) { return; } var currentUser = this.SessionManager.GetCurrentUser(); if (currentUser.FusionUser.IsPasswordChangeRequired) { actionContext.Result = new RedirectResult("/welcome"); } } }  [WelcomePageRedirectActionFilterAttribute] public class BaseController : Controller { ... } The requirement is now met.

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• Login Screen returns to login screen

  - by AbeFM

  After many many reboots in a couple days while experimenting with BIOS settings effecting the speed Hardbrake runs at, today I find after a reboot that I have to type in password to log in - ordinarily I have this disabled. When I DO enter my password, it goes to a black screen for a bit, then returns. I can log in as guest, which does the same thing (minus the password) and if I use the wrong password, it complains instead of doing the same. Using the install disc, I see three partitions on my drive, a ~200 MB boot sector, and two 32 GB (one extended) which seem to share the rest of the SSD. Running FSCK seems to generate tons of errors. The odd bits: All my background stuff is running - I can access stuff served by Subsonic, and see network shares from my windows machines. I can log in in another terminal and do stuff... I just can't get into the GUI/OS proper. Sort of at a loss where to start. Would be happy to free drive of errors if I could (I've another machine, I could mount drive over USB and check it), but it seems everything else is working? edit: Screensaver also seems to kick on, even from fsck's run from the boot menu. i3-2100t, H67 chipset I believe, 12.10, everything's been working fine for the better part of a year. Seen several similar topics, but either they turn out to be something unrelated (fresh install or known graphics issues) or there are no answers. I'm happy to get any logs/info anyone want.

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• How to Configure OpenLDAP on Ubuntu 10.04 Server

  - by user3215

  I am following the Ubuntu server guide to configure OpenLDAP on an Ubuntu 10.04 server, but can not get it to work. When I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file: # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Can anyone help me?

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• How to configure ldap on ubuntu 10.04 server

  - by user3215

  I am following the link to configure ldap on ubuntu 10.04 server but could not. when I try to use sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif I'm getting the following error: Enter LDAP Password: <entered 'secret' as password> adding new entry "dc=don,dc=com" ldap_add: Naming violation (64) additional info: value of single-valued naming attribute 'dc' conflicts with value present in entry Again when I try to do the same, I'm getting the following error: root@avy-desktop:/home/avy# sudo ldapadd -x -D cn=admin,dc=don,dc=com -W -f frontend.ldif Enter LDAP Password: ldap_bind: Invalid credentials (49) Here is the backend.ldif file # Load dynamic backend modules dn: cn=module,cn=config objectClass: olcModuleList cn: module olcModulepath: /usr/lib/ldap olcModuleload: back_hdb # Database settings dn: olcDatabase=hdb,cn=config objectClass: olcDatabaseConfig objectClass: olcHdbConfig olcDatabase: {1}hdb olcSuffix: dc=don,dc=com olcDbDirectory: /var/lib/ldap olcRootDN: cn=admin,dc=don,dc=com olcRootPW: secret olcDbConfig: set_cachesize 0 2097152 0 olcDbConfig: set_lk_max_objects 1500 olcDbConfig: set_lk_max_locks 1500 olcDbConfig: set_lk_max_lockers 1500 olcDbIndex: objectClass eq olcLastMod: TRUE olcDbCheckpoint: 512 30 olcAccess: to attrs=userPassword by dn="cn=admin,dc=don,dc=com" write by anonymous auth by self write by * none olcAccess: to attrs=shadowLastChange by self write by * read olcAccess: to dn.base="" by * read olcAccess: to * by dn="cn=admin,dc=don,dc=com" write by * read frontend.ldif file: # Create top-level object in domain dn: dc=don,dc=com objectClass: top objectClass: dcObject objectclass: organization o: Example Organization dc: Example description: LDAP Example # Admin user. dn: cn=admin,dc=don,dc=com objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator userPassword: secret dn: ou=people,dc=don,dc=com objectClass: organizationalUnit ou: people dn: ou=groups,dc=don,dc=com objectClass: organizationalUnit ou: groups dn: uid=john,ou=people,dc=don,dc=com objectClass: inetOrgPerson objectClass: posixAccount objectClass: shadowAccount uid: john sn: Doe givenName: John cn: John Doe displayName: John Doe uidNumber: 1000 gidNumber: 10000 userPassword: password gecos: John Doe loginShell: /bin/bash homeDirectory: /home/john shadowExpire: -1 shadowFlag: 0 shadowWarning: 7 shadowMin: 8 shadowMax: 999999 shadowLastChange: 10877 mail: [email protected] postalCode: 31000 l: Toulouse o: Example mobile: +33 (0)6 xx xx xx xx homePhone: +33 (0)5 xx xx xx xx title: System Administrator postalAddress: initials: JD dn: cn=example,ou=groups,dc=don,dc=com objectClass: posixGroup cn: example gidNumber: 10000 Anybody could help me?

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• unable to format usb 1204 [daemon inhibited ]

  - by santosamaru

  i try to format my usb 1st time its work all data gone but i can't save any file at this usb . then i try to check is it working or broken here the report santos@santos:~$ sudo badblocks -v /dev/sdb [sudo] password for santos: Sorry, try again. [sudo] password for santos: Checking blocks 0 to 7824383 Checking for bad blocks (read-only test): 0.00% done, 0:00 elapsed. (0/0/0 errdone Pass completed, 0 bad blocks found. (0/0/0 errors) santos@santos:~$ sudo badblocks -v -w /dev/sdb [sudo] password for santos: Sorry, try again. [sudo] password for santos: /dev/sdb is apparently in use by the system; it's not safe to run badblocks! santos@santos:~$ how to format and fix this issues? i have read this link Formatting Pen Drive causes 'Daemon Is Inhibited' Error and it said like this when i try to move any items from desktop " the destination is read only also in this case i use google and find this http://ubuntuforums.org/showthread.php?t=1955353 article as same its not helped following user13509 suggestion ..

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• Can't login to Guest Session or Standard Account?

  - by Rory

  Thanks in advance for any help. Ubuntu 12.04 Up until recently my mother has been using the Guest Session when she logs on; now, the Guest Session will not login. When I try to login to it, it bounces me back to the login screen. I then tried to login on a Standard account (Alberta) which I made prior to not being able to login to Guest, and it turns out I cannot login - it gives the "Invalid Password" error. So then I tried to change her password from my own account (Rory) which is the master account. Under the Login Options where the Password option is, it says "Account disabled" and it will not let me change this; I try to apply a password, get no error, but it just still says "Account disabled". Then I tried to delete the Alberta account altogether, but got this error: I also tried sudo userdel -r Alberta but got this error: "userdel: cannot lock /etc/shadow; try again later." I don't know what to do now. Any help appreciated.

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• Cannot FTP without simultaneous SSH connection?

  - by Lucas

  I'm trying to set up an old box as a backup server (running 10.04.4 LTS). I intend to use 3rd party software on my PC to periodically connect to my server via FTP(S) and to mirror certain files. For some reason, all FTP connection attempts fail UNLESS I'm simultaneously connected via SSH. For example, if I use putty to test the connection to port 21, the system hangs and times out. I get: 220 Connected to LeServer USER lucas 331 Please specify the password. PASS [password] <cursor> However, when I'm simultaneously logged in (in another session) everything works: 220 Connected to LeServer USER lucas 331 Please specify the password. PASS [password] 230 Login successful. Basically, this means that my software will never be able to connect on its own, as intended. I know that the correct port is open because it works (sometimes) and nmap gives me: Starting Nmap 5.00 ( http://nmap.org ) at 2012-03-20 16:15 CDT Interesting ports on xx.xxx.xx.x: Not shown: 995 closed ports PORT STATE SERVICE 21/tcp open ftp 22/tcp open ssh 53/tcp open domain 139/tcp open netbios-ssn 445/tcp open microsoft-ds Nmap done: 1 IP address (1 host up) scanned in 0.15 seconds My only hypothesis is that this has something to do with iptables. Maybe it's allowing only established connections? I don't think that's how I set it up, but maybe? Here's my iptables rules for INPUT: lucas@rearden:~$ sudo iptables -L INPUT Chain INPUT (policy DROP) target prot opt source destination fail2ban-ssh tcp -- anywhere anywhere multiport dports ssh ufw-before-logging-input all -- anywhere anywhere ufw-before-input all -- anywhere anywhere ufw-after-input all -- anywhere anywhere ufw-after-logging-input all -- anywhere anywhere ufw-reject-input all -- anywhere anywhere ufw-track-input all -- anywhere anywhere ACCEPT tcp -- anywhere anywhere tcp dpt:ftp I'm using vsftpd. Any thoughts/resources on how I could fix this? L

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• WCF Versioning, Naming and Endpoint URL

  - by Vinothkumar VJ

  I have a WCF Service and a Main Lib1. Say, I have a Save Profile Service. WCF gets data (with predefined data contract) from client and pass the same to the Main Class Lib1, generate response and send it back to client. WCF Method : SaveProfile(ProfileDTO profile) Current Version 1.0 ProfileDTO have the following UserName Password FirstName DOB (In string yyyy-mm-dd) CreatedDate (In string yyyy-mm-dd) Next Version (V2.0) ProfileDTO have the following UserName Password FirstName DOB (In UnixTimeStamp) CreatedDate (In UnixTimeStamp) Version 3.0 ProfileDTO have the following (With change in UserName and Password length validation) UserName Password FirstName DOB (In UnixTimeStamp) CreatedDate (In UnixTimeStamp) In simple we have DataContract and Workflow change between each version 1. How do I name the methods in WCF Service and Main Class Lib1? 2. Do I have to go with any specific pattern for ease development and maintenance? 3. Do I have to have different endpoints for different version? In the above example I have a method named “SaveProfile”. Do I have to name the methods like “SaveProfile1.0”, “SaveProfile2.0”, etc. If that is the case when there is no change between Version “3.0” and “4.0” then there will difficult in maintenance. I’m looking for a approach that will help in ease maintenance

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