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  • Best approach to write huge xml data to file?

    - by Kayes
    Hi. I'm currently exporting a database table with huge data (100000+ records) into an xml file using XmlTextWriter class and I'm writing directly to a file on the physical drive. _XmlTextWriterObject = new XmlTextWriter(_xmlFilePath, null); While my code runs ok, my question is that is it the best approach? Or should I write the whole xml in memory stream first and then write the xml document in physical file from memory stream? And what are the effects on memory/ performance in both cases?

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  • Should XML be used server-side, and JSON client-side?

    - by Michel Carroll
    As a personal project, I'm making an AJAX chatroom application using XML as a server-side storage, and JSON for client-side processing. Here's how it works: AJAX Request gets sent to PHP using GET (chat messages/logins/logouts) PHP fetches/modifies the XML file on the server PHP encodes the XML into JSON, and sends back JSON response Javascript handles JSON information (chat messages/logins/logouts) I want to eventually make this a larger-scale chatroom application. Therefore, I want to make sure it's fast and efficient. Was this a bad design choice? In this case, is switching between XML and JSON ok, or is there a better way?

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  • How can I delete a file created and opened with Perl's IO::File and XML::Writer?

    - by Sho Minamimoto
    So I'm running through a list of things and have code that creates an .xml files with IO::File called $doc, then I make a new writer with XML::Writer(OUTPUT => $doc). More code runs and I build a big XML file with XML::Writer. Then, near the end of the file, I find out if I need this file at all. If I do need it, I just: $writer->end(); $doc->close(); but if I don't need it, what should I enter to just delete all data I've stored/saved and move onto the next file? I tried unlink($docpath) (before and after $doc->close()), the file was not deleted.

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  • Indesign and XML - how to auto flow into multiple pages with differing styles?

    - by MetaDan
    Hi guys, I've got a bit of a problem at the moment. I'm trying to work with indesign (cs3) and xml. Basically i have a template which is has 1 master dps, both pages have the same data (fields 1-5) but one is left aligned, one right - hence mildly different paragraph styles. What i want to be able to do is import xml and have indesign flow the data from the individual nodes into many pages. eg xml format: root day field1 field2 field3 field4 field5 day field1 field2 field3 field4 field5 day ... I can almost make this work by tagging the frames on the master pages, then creating pages and importing the xml, however it only flows the first 2 nodes into the pages reptitively for the total count of all the nodes. I can also almost make it work by creating a page from the untagged masters and then tagging the frames with the field1-5 tags then importing the xml. This populates the first page, however i then can't find a way to make the rest of the data flow into new pages... Am I missing something? Am I being a complete dumbass? If anyone can offer any help it will be greatly appreciated...

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  • Get the ID of a Child in a cascade="all" relationship, while adding it to a collection, in Hibernate

    - by Marco
    Hi, i have two Entities, "Parent" and "Child", that are linked through a bidirectional one-to-many relationship with the cascade attribute set to "all". When adding a Child object to the Parent children collection using the code below, i can't get the ID of the persisted child until i commit the transaction: Parent p = (Parent) session.load(Parent.class, pid); Child c = new Child(); p.addChild(c); // "c" hasn't an ID (is always zero) However, when i persist a child entity by explicitly calling the session.save() method, the ID is created and set immediately, even if the transaction hasn't been committed: Child c = new Child(); session.save(c); // "c" has an ID Is there a way to get the ID of the child entity immediately without calling the session.save() method? Thanks

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  • Is ORM (Linq, Hibernate...) really that useful?

    - by Peter
    I have been playing with some LINQ ORM (LINQ directly to SQL) and I have to admit I like its expressive powers . For small utility-like apps, It also works quite fast: dropping a SQL server on some surface and you're set to linq away. For larger apps however, the DAL never was that big of an issue to me to setup, nor maintain, and more often than not, once it was set, all the programming was not happening there anyway... My, honest - I am an ORM newbie - question : what is the big advantage of ORM over writing a decent DAL by hand? (seems like a double, couldn't find it though) UPDATE : OK its a double :-) I found it myself eventually : ORM vs Handcoded Data Access Layer

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  • How to remove the xmlns:XSI and xmlns:XSD namespaces from the xml output of a webservice in .net fra

    - by Chetan
    HI, This is an old question, i have seen some solutions on this forum itself, but am trying to use webservices for the first time so please bear with me on this one. I have a webservice that returns XML in the following format <subs xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" msisdn="965xxxxxx"> <shortcode label="XXXX"> <channels> <channel> <id>442</id> <name>News</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:11 PM</lastbilling> </channel> <channel> <id>443</id> <name>News2</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:19 PM</lastbilling> </channel> </channels> </shortcode> </subs> I want the same XMl output without the xmlns:xsd and xmlns:xsi tags. I have tried the following solution that was suggested: Public Function GetSubscription(....) As String Dim namespaces As New XmlSerializerNamespaces namespaces.Add(String.Empty, String.Empty) Dim serializer As New XmlSerializer(SubsDetail.GetType) Dim sw As New System.IO.StringWriter Dim writer As New System.Xml.XmlTextWriter(sw) writer.Formatting = Formatting.None serializer.Serialize(writer, SubsDetail, namespaces) writer.Close() Return sw.toString() The result was that I got an xml in the following format: <string> <?xml version="1.0" encoding="utf-16"?><subs msisdn="965xxxx"> <shortcode label="XXXX"> <channels> <channel> <id>442</id> <name>News</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:11 PM</lastbilling> </channel> <channel> <id>443</id> <name>News2</name> <billingperiod>7</billingperiod> <billingamount>3</billingamount> <lastbilling>4/14/2010 1:41:19 PM</lastbilling> </channel> </channels> </shortcode> </subs> </string> Though the format of the xml is correct it is coming as string within the <string> tags. This is really driving me nuts. Can I get the output as xml without the outer string tags?

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  • Can I have an XHTML document with an XML declaration in standards mode for IE6?

    - by user225643
    I've been reading about this for the last half hour, and here's what I understand: IE 6 will render a page in standards mode if there's a valid DTD, but not if there are any comments above the DTD. The XML declaration is a comment that goes above the DTD. If the XML declaration is wrapped in a conditional comment, the page will render in IE 6 in quirks mode but be invalid XHTML. Are there any workarounds to getting valid XHTML with an XML declaration to render in standards mode in IE6? If not, what are the disadvantages of removing the XML declaration entirely? Thanks.

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  • How do I establish table association in JPA / Hibernate with existing database?

    - by Paperino
    Currently I have two tables in my database Encounters and Referrals: There is a one to many relationship between these two tables. Currently they are linked together with foreign keys. Right now I have public class Encounter extends JPASupport implements java.io.Serializable { @Column(name="referralid", unique=false, nullable=true, insertable=true, updatable=true) public Integer referralid; } But what I really want is public class Encounter extends JPASupport implements java.io.Serializable { .......... @OneToMany(cascade=CascadeType.PERSIST) public Set<Referrals> referral; ............ } So that I can eventually do a query like this: List<Encounter> cases = Encounter.find( "select distinct p from Encounter p join p.referrals as t where t.caseid =103" ).fetch(); How do I tell JPA that even though I have non-standard column names for my foreign keys and primary keys that its the object models that I want linked, not simply the integer value for the keys? Does this make sense? I hope so. Thanks in advanced!

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  • Load XML file into object. Best method?

    - by Cypher
    Hello, We are receiving an XML file from our client. I want to load the data from this file into a class, but am unsure about which way to go about it. I have an XSD to defining what is expected in the XML file, so therefore i can easily validate the XML file. Can i use the XSD file to load the data into a POCO, using some sort of serialization? The other way i was thinking was to load the xml into a XMLDocument and use XPath to populate each property in my class. Cheers for any advice

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  • Search Oracle date type column with hibernate, seach by everything in that day - ignore the time.

    - by Setori
    hi there <property name="batchCreatedDate" type="java.util.Date"> <meta attribute="field-description">batch create date</meta> <column name="BATCH_CREATED_DATE" length="7" not-null="true" /> </property> table column type is BATCH_CREATED_DATE DATE NOT NULL With the data in that date column being similar to this '2010-05-13 14:56:36.0' now I want to search for all items within the 24 hours of 2010-05-13, currently my call only returns all items with date "2010-05-13 14:56:36.0" exactly. What would my HQL statement look like to hand this kind of scenario? Thank you so much

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  • Why is hibernate open session in view considered a bad practice?

    - by HeDinges
    And what kind of alternative strategies do you use for avoiding LazyLoadExceptions? I do understand that open session in view has issues with: Layered applications running in different jvm's Transactions are committed only at the end, and most probably you would like the results before. But, if you know that your application is running on a single vm, why not ease your pain by using an open session in view strategy?

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  • How to use linux csplit to chop up massive XML file?

    - by Fred
    Hi everyone, I have a gigantic (4GB) XML file that I am currently breaking into chunks with linux "split" function (every 25,000 lines - not by bytes). This usually works great (I end up with about 50 files), except some of the data descriptions have line breaks, and so frequently the chunk files do not have the proper closing tags - and my parser chokes halfway through processing. Example file: (note: normally each "listing" xml node is supposed to be on its own line) <?xml version="1.0" encoding="UTF-8"?> <listings> <listing><date>2009-09-22</date><desc>This is a description WITHOUT line breaks and works fine with split</desc><more_tags>stuff</more_tags></listing> <listing><date>2009-09-22</date><desc>This is a really annoying description field WITH line breaks that screw the split function</desc><more_tags>stuff</more_tags></listing> </listings> Then sometimes my split ends up like <?xml version="1.0" encoding="UTF-8"?> <listings> <listing><date>2009-09-22</date><desc>This is a description WITHOUT line breaks and works fine with split</desc><more_tags>stuff</more_tags></listing> <listing><date>2009-09-22</date><desc>This is a really annoying description field WITH line breaks ... EOF So - I have been reading about "csplit" and it sounds like it might work to solve this issue. I cant seem to get the regular expression right... Basically I want the same output of ~50ish files Something like: *csplit -k myfile.xml '/</listing>/' 25000 {50} Any help would be great Thanks!

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  • Is there still a place for XML in the future?

    - by David Neale
    Now that many people seem to be moving towards JSON for web communication I am wondering about why XML should continue to be used. I appreciate that XML has many years on JSON, during which time it has been widely adopted. However, the fact that it is so well-adopted appears to be the one decisive reason why it should continue to be used. Is there a good reason why XML should not gradually be phased out in favour of JSON?

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  • Collectable<T> serialization, Root Namespaces on T in .xml files.

    - by Stacey
    I have a Repository Class with the following method... public T Single<T>(Predicate<T> expression) { using (var list = (Models.Collectable<T>)System.Xml.Serializer.Deserialize(typeof(Models.Collectable<T>), FileName)) { return list.Find(expression); } } Where Collectable is defined.. [Serializable] public class Collectable<T> : List<T>, IDisposable { public Collectable() { } public void Dispose() { } } And an Item that uses it is defined.. [Serializable] [System.Xml.Serialization.XmlRoot("Titles")] public partial class Titles : Collectable<Title> { } The problem is when I call the method, it expects "Collectable" to be the XmlRoot, but the XmlRoot is "Titles" (all of object Title). I have several classes that are collected in .xml files like this, but it seems pointless to rewrite the basic methods for loading each up when the generic accessors do it - but how can I enforce the proper root name for each file without hard coding methods for each one? The [System.Xml.Serialization.XmlRoot] seems to be ignored.

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  • Can I cache a ManyToOne hibernate object without it being lazy loaded?

    - by Andrew
    @ManyToOne @JoinColumn(name = "play_template_id", table = "team_play_mapping" ) public Play getPlay() { return play; } public void setPlay( Play play ) { this.play = play; } By default, this is eager loading. Can I get it so that it will read the play object from a cache without making it lazy loading? Am I correct that eager loading will force it to do a join query and hence no caching?

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  • How to get an ordered list parsed by XML parser?

    - by Matthias Doringer
    I am using a xsd schema file; there I specified an ordered list. When parsing an XML node of the kind... <myOrderedList> "element_1" "element_2" "element_3" </myOrderedList> (which is valid XML syntax) ...all XML parsers I know parse this as a single node element. Is there a way to get the XML parser parse this list for me (return it as a list or an array or whatever) or do I always have to parse it myself?

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  • How can i assign xml scripts in to a php variable?

    - by Himel Khan
    I can not assign a xml scripts in to a php variable. My xml text: <?xml version="1.0" encoding="UTF-8" ?><rss version="2.0"><channel> <title>coolajax.net</title> <link>http://www.hotscripts.com/listings/feed</link> <description>Coolajax Scripts Listings Description</description> and I want to assign this text in to $xml_header variable. can anyone help me..

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