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  • Get current user from View

    - by gosu kiwi
    So what I want to do is, in my main layout, have a menu for logged in users, and a different for anon users. THe layout will be used on every page, so I'm not sure how to do this, as I've seen, the Auth Component can only be used in the controller, this would be nice if I had to do this in only one view, but for every view, how can I do this? Do I have to do something on AppController? What I want to do is basically // layout <?php if(logged): ?> Welcome <?php echo $user; ?> <?php else: ?> Welcom anon, Log in? <?php endif; ?>

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  • iPhone - At user event create objects in the view

    - by insaneshow
    Hello, I am new to iPhone programming, so I think part of the problem is that I don't know what I really want to google to find my answer. I am looking for a method that allows a user to draw a line on the screen. There is no guarantee that it will be straight, it can be curved or whatever. I was thinking that I could create some small square image, and then as they draw, place them into a NSset. But I am not really sure how to communicate each new object up to the view. Up to this point, I've just been messing around with objects I put on the view and then assign movement to those, this is my first jump into on-the-fly object creation. It might be that I just need to jump into a class/object type or even a tutorial, any guidance would be great. Thanks!

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  • How to release my view from stack ?

    - by aman-gupta
    Hi, In my application I m using following coding convention to open my default screen :-- AppDelegate *ptrDefaultScreen = (AppDelegate *)[[UIApplication sharedApplication]delegate]; [self.navigationController presentModalViewController:ptrDefaultScreen.FrmFlashScreenLink animated:YES]; but when I move to other screen after default screen ,my default screen is still exists even i used [self dismissModelViewController:YES]; to dimiss default screen from view. where I m wrong I want my default screen will be completely removed from view. Is any other way to call default screen before actual application. Please help me out.Thanks in advance

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  • NoMethodError when using .where (eager fetching)

    - by Ethan Leroy
    I have the following model classes... class Image < ActiveRecord::Base attr_accessible :description, :title has_many :imageTags has_many :tags, :through => :imageTags end class Tag < ActiveRecord::Base attr_accessible :name has_many :imageTags has_many :images, :through => :imageTags end class ImageTag < ActiveRecord::Base attr_accessible :position belongs_to :image belongs_to :tag end And when I use find for getting the Tag with the id 1 t = Tag.find(1); @images = t.images; But when I do the same with where, I get a NoMethodError, with the description undefined method 'images': t = Tag.where(:name => "foo"); @images = t.images; I also tried adding .includes(:images) before the .where statement, but that doesn't work too. So, how can I get all Images that belong to a Tag?

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  • How to move to another view without using a button

    - by Will
    My first view displays an image and action indicator while web-servers and database function are run in that background. I want the application to go to my tab view when the functions have been completed. How do I do this? Here is what the views look like. What I have tried: TabBarViewController *tab = [[TabBarViewController alloc]init]; [self presentViewController:tab animated:NO completion:nil]; and [self performSegueWithIdentifier:@"first" sender:self]; Please can you help my to understand how to do this. I have spent many hours googling this problem and couldn't work out how to do it. Thanks EDIT: Added Code

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • A Map of View instances?

    - by user291701
    Is it possible to keep references to views keyed off of their hashCode? Something like: Map<Integer, View> views; views.put(view1.hashCode(), view1); views.put(view2.hashCode(), view2); views.put(viewN.hashCode(), viewN); I have a few in my view hierarchy and am downloading images for each. I want to be able to iterate over them quickly, or see if I've already previously added one (hence the map).

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  • Developing web apps using ASP.NET MVC 3, Razor and EF Code First - Part 1

    - by shiju
    In this post, I will demonstrate web application development using ASP. NET MVC 3, Razor and EF code First. This post will also cover Dependency Injection using Unity 2.0 and generic Repository and Unit of Work for EF Code First. The following frameworks will be used for this step by step tutorial. ASP.NET MVC 3 EF Code First CTP 5 Unity 2.0 Define Domain Model Let’s create domain model for our simple web application Category class public class Category {     public int CategoryId { get; set; }     [Required(ErrorMessage = "Name Required")]     [StringLength(25, ErrorMessage = "Must be less than 25 characters")]     public string Name { get; set;}     public string Description { get; set; }     public virtual ICollection<Expense> Expenses { get; set; } }   Expense class public class Expense {             public int ExpenseId { get; set; }            public string  Transaction { get; set; }     public DateTime Date { get; set; }     public double Amount { get; set; }     public int CategoryId { get; set; }     public virtual Category Category { get; set; } } We have two domain entities - Category and Expense. A single category contains a list of expense transactions and every expense transaction should have a Category. In this post, we will be focusing on CRUD operations for the entity Category and will be working on the Expense entity with a View Model object in the later post. And the source code for this application will be refactored over time. The above entities are very simple POCO (Plain Old CLR Object) classes and the entity Category is decorated with validation attributes in the System.ComponentModel.DataAnnotations namespace. Now we want to use these entities for defining model objects for the Entity Framework 4. Using the Code First approach of Entity Framework, we can first define the entities by simply writing POCO classes without any coupling with any API or database library. This approach lets you focus on domain model which will enable Domain-Driven Development for applications. EF code first support is currently enabled with a separate API that is runs on top of the Entity Framework 4. EF Code First is reached CTP 5 when I am writing this article. Creating Context Class for Entity Framework We have created our domain model and let’s create a class in order to working with Entity Framework Code First. For this, you have to download EF Code First CTP 5 and add reference to the assembly EntitFramework.dll. You can also use NuGet to download add reference to EEF Code First.    public class MyFinanceContext : DbContext {     public MyFinanceContext() : base("MyFinance") { }     public DbSet<Category> Categories { get; set; }     public DbSet<Expense> Expenses { get; set; }         }   The above class MyFinanceContext is derived from DbContext that can connect your model classes to a database. The MyFinanceContext class is mapping our Category and Expense class into database tables Categories and Expenses using DbSet<TEntity> where TEntity is any POCO class. When we are running the application at first time, it will automatically create the database. EF code-first look for a connection string in web.config or app.config that has the same name as the dbcontext class. If it is not find any connection string with the convention, it will automatically create database in local SQL Express database by default and the name of the database will be same name as the dbcontext class. You can also define the name of database in constructor of the the dbcontext class. Unlike NHibernate, we don’t have to use any XML based mapping files or Fluent interface for mapping between our model and database. The model classes of Code First are working on the basis of conventions and we can also use a fluent API to refine our model. The convention for primary key is ‘Id’ or ‘<class name>Id’.  If primary key properties are detected with type ‘int’, ‘long’ or ‘short’, they will automatically registered as identity columns in the database by default. Primary key detection is not case sensitive. We can define our model classes with validation attributes in the System.ComponentModel.DataAnnotations namespace and it automatically enforces validation rules when a model object is updated or saved. Generic Repository for EF Code First We have created model classes and dbcontext class. Now we have to create generic repository pattern for data persistence with EF code first. If you don’t know about the repository pattern, checkout Martin Fowler’s article on Repository Let’s create a generic repository to working with DbContext and DbSet generics. public interface IRepository<T> where T : class     {         void Add(T entity);         void Delete(T entity);         T GetById(long Id);         IEnumerable<T> All();     }   RepositoryBasse – Generic Repository class public abstract class RepositoryBase<T> where T : class { private MyFinanceContext database; private readonly IDbSet<T> dbset; protected RepositoryBase(IDatabaseFactory databaseFactory) {     DatabaseFactory = databaseFactory;     dbset = Database.Set<T>(); }   protected IDatabaseFactory DatabaseFactory {     get; private set; }   protected MyFinanceContext Database {     get { return database ?? (database = DatabaseFactory.Get()); } } public virtual void Add(T entity) {     dbset.Add(entity);            }        public virtual void Delete(T entity) {     dbset.Remove(entity); }   public virtual T GetById(long id) {     return dbset.Find(id); }   public virtual IEnumerable<T> All() {     return dbset.ToList(); } }   DatabaseFactory class public class DatabaseFactory : Disposable, IDatabaseFactory {     private MyFinanceContext database;     public MyFinanceContext Get()     {         return database ?? (database = new MyFinanceContext());     }     protected override void DisposeCore()     {         if (database != null)             database.Dispose();     } } Unit of Work If you are new to Unit of Work pattern, checkout Fowler’s article on Unit of Work . According to Martin Fowler, the Unit of Work pattern "maintains a list of objects affected by a business transaction and coordinates the writing out of changes and the resolution of concurrency problems." Let’s create a class for handling Unit of Work   public interface IUnitOfWork {     void Commit(); }   UniOfWork class public class UnitOfWork : IUnitOfWork {     private readonly IDatabaseFactory databaseFactory;     private MyFinanceContext dataContext;       public UnitOfWork(IDatabaseFactory databaseFactory)     {         this.databaseFactory = databaseFactory;     }       protected MyFinanceContext DataContext     {         get { return dataContext ?? (dataContext = databaseFactory.Get()); }     }       public void Commit()     {         DataContext.Commit();     } }   The Commit method of the UnitOfWork will call the commit method of MyFinanceContext class and it will execute the SaveChanges method of DbContext class.   Repository class for Category In this post, we will be focusing on the persistence against Category entity and will working on other entities in later post. Let’s create a repository for handling CRUD operations for Category using derive from a generic Repository RepositoryBase<T>.   public class CategoryRepository: RepositoryBase<Category>, ICategoryRepository     {     public CategoryRepository(IDatabaseFactory databaseFactory)         : base(databaseFactory)         {         }                } public interface ICategoryRepository : IRepository<Category> { } If we need additional methods than generic repository for the Category, we can define in the CategoryRepository. Dependency Injection using Unity 2.0 If you are new to Inversion of Control/ Dependency Injection or Unity, please have a look on my articles at http://weblogs.asp.net/shijuvarghese/archive/tags/IoC/default.aspx. I want to create a custom lifetime manager for Unity to store container in the current HttpContext.   public class HttpContextLifetimeManager<T> : LifetimeManager, IDisposable {     public override object GetValue()     {         return HttpContext.Current.Items[typeof(T).AssemblyQualifiedName];     }     public override void RemoveValue()     {         HttpContext.Current.Items.Remove(typeof(T).AssemblyQualifiedName);     }     public override void SetValue(object newValue)     {         HttpContext.Current.Items[typeof(T).AssemblyQualifiedName] = newValue;     }     public void Dispose()     {         RemoveValue();     } }   Let’s create controller factory for Unity in the ASP.NET MVC 3 application. public class UnityControllerFactory : DefaultControllerFactory { IUnityContainer container; public UnityControllerFactory(IUnityContainer container) {     this.container = container; } protected override IController GetControllerInstance(RequestContext reqContext, Type controllerType) {     IController controller;     if (controllerType == null)         throw new HttpException(                 404, String.Format(                     "The controller for path '{0}' could not be found" +     "or it does not implement IController.",                 reqContext.HttpContext.Request.Path));       if (!typeof(IController).IsAssignableFrom(controllerType))         throw new ArgumentException(                 string.Format(                     "Type requested is not a controller: {0}",                     controllerType.Name),                     "controllerType");     try     {         controller= container.Resolve(controllerType) as IController;     }     catch (Exception ex)     {         throw new InvalidOperationException(String.Format(                                 "Error resolving controller {0}",                                 controllerType.Name), ex);     }     return controller; }   }   Configure contract and concrete types in Unity Let’s configure our contract and concrete types in Unity for resolving our dependencies.   private void ConfigureUnity() {     //Create UnityContainer               IUnityContainer container = new UnityContainer()                 .RegisterType<IDatabaseFactory, DatabaseFactory>(new HttpContextLifetimeManager<IDatabaseFactory>())     .RegisterType<IUnitOfWork, UnitOfWork>(new HttpContextLifetimeManager<IUnitOfWork>())     .RegisterType<ICategoryRepository, CategoryRepository>(new HttpContextLifetimeManager<ICategoryRepository>());                 //Set container for Controller Factory                ControllerBuilder.Current.SetControllerFactory(             new UnityControllerFactory(container)); }   In the above ConfigureUnity method, we are registering our types onto Unity container with custom lifetime manager HttpContextLifetimeManager. Let’s call ConfigureUnity method in the Global.asax.cs for set controller factory for Unity and configuring the types with Unity.   protected void Application_Start() {     AreaRegistration.RegisterAllAreas();     RegisterGlobalFilters(GlobalFilters.Filters);     RegisterRoutes(RouteTable.Routes);     ConfigureUnity(); }   Developing web application using ASP.NET MVC 3 We have created our domain model for our web application and also have created repositories and configured dependencies with Unity container. Now we have to create controller classes and views for doing CRUD operations against the Category entity. Let’s create controller class for Category Category Controller   public class CategoryController : Controller {     private readonly ICategoryRepository categoryRepository;     private readonly IUnitOfWork unitOfWork;           public CategoryController(ICategoryRepository categoryRepository, IUnitOfWork unitOfWork)     {         this.categoryRepository = categoryRepository;         this.unitOfWork = unitOfWork;     }       public ActionResult Index()     {         var categories = categoryRepository.All();         return View(categories);     }     [HttpGet]     public ActionResult Edit(int id)     {         var category = categoryRepository.GetById(id);         return View(category);     }       [HttpPost]     public ActionResult Edit(int id, FormCollection collection)     {         var category = categoryRepository.GetById(id);         if (TryUpdateModel(category))         {             unitOfWork.Commit();             return RedirectToAction("Index");         }         else return View(category);                 }       [HttpGet]     public ActionResult Create()     {         var category = new Category();         return View(category);     }           [HttpPost]     public ActionResult Create(Category category)     {         if (!ModelState.IsValid)         {             return View("Create", category);         }                     categoryRepository.Add(category);         unitOfWork.Commit();         return RedirectToAction("Index");     }       [HttpPost]     public ActionResult Delete(int  id)     {         var category = categoryRepository.GetById(id);         categoryRepository.Delete(category);         unitOfWork.Commit();         var categories = categoryRepository.All();         return PartialView("CategoryList", categories);       }        }   Creating Views in Razor Now we are going to create views in Razor for our ASP.NET MVC 3 application.  Let’s create a partial view CategoryList.cshtml for listing category information and providing link for Edit and Delete operations. CategoryList.cshtml @using MyFinance.Helpers; @using MyFinance.Domain; @model IEnumerable<Category>      <table>         <tr>         <th>Actions</th>         <th>Name</th>          <th>Description</th>         </tr>     @foreach (var item in Model) {             <tr>             <td>                 @Html.ActionLink("Edit", "Edit",new { id = item.CategoryId })                 @Ajax.ActionLink("Delete", "Delete", new { id = item.CategoryId }, new AjaxOptions { Confirm = "Delete Expense?", HttpMethod = "Post", UpdateTargetId = "divCategoryList" })                           </td>             <td>                 @item.Name             </td>             <td>                 @item.Description             </td>         </tr>          }       </table>     <p>         @Html.ActionLink("Create New", "Create")     </p> The delete link is providing Ajax functionality using the Ajax.ActionLink. This will call an Ajax request for Delete action method in the CategoryCotroller class. In the Delete action method, it will return Partial View CategoryList after deleting the record. We are using CategoryList view for the Ajax functionality and also for Index view using for displaying list of category information. Let’s create Index view using partial view CategoryList  Index.chtml @model IEnumerable<MyFinance.Domain.Category> @{     ViewBag.Title = "Index"; }    <h2>Category List</h2>    <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>    <div id="divCategoryList">               @Html.Partial("CategoryList", Model) </div>   We can call the partial views using Html.Partial helper method. Now we are going to create View pages for insert and update functionality for the Category. Both view pages are sharing common user interface for entering the category information. So I want to create an EditorTemplate for the Category information. We have to create the EditorTemplate with the same name of entity object so that we can refer it on view pages using @Html.EditorFor(model => model) . So let’s create template with name Category. Let’s create view page for insert Category information   @model MyFinance.Domain.Category   @{     ViewBag.Title = "Save"; }   <h2>Create</h2>   <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script>   @using (Html.BeginForm()) {     @Html.ValidationSummary(true)     <fieldset>         <legend>Category</legend>                @Html.EditorFor(model => model)               <p>             <input type="submit" value="Create" />         </p>     </fieldset> }   <div>     @Html.ActionLink("Back to List", "Index") </div> ViewStart file In Razor views, we can add a file named _viewstart.cshtml in the views directory  and this will be shared among the all views with in the Views directory. The below code in the _viewstart.cshtml, sets the Layout page for every Views in the Views folder.      @{     Layout = "~/Views/Shared/_Layout.cshtml"; }   Source Code You can download the source code from http://efmvc.codeplex.com/ . The source will be refactored on over time.   Summary In this post, we have created a simple web application using ASP.NET MVC 3 and EF Code First. We have discussed on technologies and practices such as ASP.NET MVC 3, Razor, EF Code First, Unity 2, generic Repository and Unit of Work. In my later posts, I will modify the application and will be discussed on more things. Stay tuned to my blog  for more posts on step by step application building.

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  • Core data migration failing with "Can't find model for source store" but managedObjectModel for source is present

    - by Ira Cooke
    I have a cocoa application using core-data, which is now at the 4th version of its managed object model. My managed object model contains abstract entities but so far I have managed to get migration working by creating appropriate mapping models and creating my persistent store using addPersistentStoreWithType:configuration:options:error and with the NSMigratePersistentStoresAutomaticallyOption set to YES. NSDictionary *optionsDictionary = [NSDictionary dictionaryWithObject:[NSNumber numberWithBool:YES] forKey:NSMigratePersistentStoresAutomaticallyOption]; NSURL *url = [NSURL fileURLWithPath: [applicationSupportFolder stringByAppendingPathComponent: @"MyApp.xml"]]; NSError *error=nil; [theCoordinator addPersistentStoreWithType:NSXMLStoreType configuration:nil URL:url options:optionsDictionary error:&error] This works fine when I migrate from model version 3 to 4, which is a migration that involves adding attributes to several entities. Now when I try to add a new model version (version 5), the call to addPersistentStoreWithType returns nil and the error remains empty. The migration from 4 to 5 involves adding a single attribute. I am struggling to debug the problem and have checked all the following; The source database is in fact at version 4 and the persistentStoreCoordinator's managed object model is at version 5. The 4-5 mapping model as well as managed object models for versions 4 and 5 are present in the resources folder of my built application. I've tried various model upgrade paths. Strangely I find that upgrading from an early version 3 - 5 works .. but upgrading from 4 - 5 fails. I've tried adding a custom entity migration policy for migration of the entity whose attributes are changing ... in this case I overrode the method beginEntityMapping:manager:error: . Interestingly this method does get called when migration works (ie when I migrate from 3 to 4, or from 3 to 5 ), but it does not get called in the case that fails ( 4 to 5 ). I'm pretty much at a loss as to where to proceed. Any ideas to help debug this problem would be much appreciated.

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  • ASP.NET MVC: How do I validate a model wrapped in a ViewModel?

    - by Deniz Dogan
    For the login page of my website I would like to list the latest news for my site and also display a few fields to let the user log in. So I figured I should make a login view model - I call this LoginVM. LoginVM contains a Login model for the login fields and a List<NewsItem> for the news listing. This is the Login model: public class Login { [Required(ErrorMessage="Enter a username.")] [DisplayName("Username")] public string Username { get; set; } [Required(ErrorMessage="Enter a password.")] [DataType(DataType.Password)] [DisplayName("Password")] public string Password { get; set; } } This is the LoginVM view model: public class LoginVM { public Login login { get; set; } public List<NewsItem> newsItems { get; set; } } This is where I get stuck. In my login controller, I get passed a LoginVM. [HttpPost] public ActionResult Login(LoginVM model, FormCollection form) { if (ModelState.IsValid) { // What? In the code I'm checking whether ModelState is valid and this would work fine if the view model was actually the Login model, but now it's LoginVM which has no validation attributes at all. How do I make LoginVM "traverse" through its members to validate them all? Am I doing something fundamentally wrong using ModelState in this manner?

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  • Which view will be resolved, code from spring's docs

    - by Blankman
    So when you go to /appointments the get() action is called, so then would the view be get.jsp (assuming you are using .jsp, and assuming you are mapping action names to views)? And what about the getnewform? It seems to be returning an object? Is that basically passed into the view? @Controller @RequestMapping("/appointments") public class AppointmentsController { private final AppointmentBook appointmentBook; @Autowired public AppointmentsController(AppointmentBook appointmentBook) { this.appointmentBook = appointmentBook; } @RequestMapping(method = RequestMethod.GET) public Map<String, Appointment> get() { return appointmentBook.getAppointmentsForToday(); } @RequestMapping(value="/{day}", method = RequestMethod.GET) public Map<String, Appointment> getForDay(@PathVariable @DateTimeFormat(iso=ISO.DATE) Date day, Model model) { return appointmentBook.getAppointmentsForDay(day); } @RequestMapping(value="/new", method = RequestMethod.GET) public AppointmentForm getNewForm() { return new AppointmentForm(); } @RequestMapping(method = RequestMethod.POST) public String add(@Valid AppointmentForm appointment, BindingResult result) { if (result.hasErrors()) { return "appointments/new"; } appointmentBook.addAppointment(appointment); return "redirect:/appointments"; } } In the example, the @RequestMapping is used in a number of places. The first usage is on the type (class) level, which indicates that all handling methods on this controller are relative to the /appointments path. The get() method has a further @RequestMapping refinement: it only accepts GET requests, meaning that an HTTP GET for /appointments invokes this method. The post() has a similar refinement, and the getNewForm() combines the definition of HTTP method and path into one, so that GET requests for appointments/new are handled by that method.

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  • WPF View/ViewModels using Generics- how?

    - by Investor5555
    New to WPF, so please bear with me... Suppose I have 2 tables in SQL Thing OtherThing Both have the exact same fields: ID (int) Name (string) Description (string) IsActive (bit/bool) DateModified (DateTime) So, I want to create one Model (not two) and do something like this: BaseModel<T>() { public int ID {get;set;} ... } etc. (of course, using the INotifyPropertyChanged, just trying to keep the code simple). I want to be able to create a BaseView and BaseViewModel that would work with whatever model conforms to the Thing/OtherThing. I am really at a loss as to what to do here to make this generic, so I don't have to have a ThingView/ThingViewModel and a OtherThingView/OtherThingViewModel... It seems that this should be simple, but I cannot seem to figure it out. Does anyone have a code example where they could interchange various items from a dropdown list using one view, one ViewModel, and one base datamodel (and switching out the type from a dropdown)? For example, a combobox has 3 identical table structures for Thing OtherThing SomeThing and on selection changed, I want to pull the data from whatever table was selected, to be able to do standard CRUD operations on any of these 3 tables, without having to create concrete classes for each view/viewmodel.

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  • Android refresh StateListDrawable problem

    - by Max
    Hi all, I have a strange problem with StateListDrawable or maybe (probably) I'm missing something. I created a test application for it and the same problem occurs. So, this is my StateListDrawable resourse in file test_selection.xml <?xml version="1.0" encoding="utf-8"?> <selector xmlns:android="http://schemas.android.com/apk/res/android"> <item android:state_selected="true"> <shape android:shape="rectangle" android:background="#ff0000"> <corners android:radius="10dp" /> <gradient android:startColor="#ff5555" android:endColor="#ff5555" android:angle="0" /> </shape> </item> <item android:state_selected="false"> <shape android:shape="rectangle" android:background="#eeeeee"> <corners android:radius="10dp" /> <gradient android:startColor="#eeeeee" android:endColor="#eeeeee" android:angle="0" /> </shape> </item> </selector> It's a very simple selector that draw a red color for selected state and a white rect for the unselected one. My main.xml template is very simple. I simply use a TextView that uses the selection as background. <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" android:textSize="30dp" android:id="@+id/test_view_example" android:background="@drawable/test_selection"/> <Button android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/refresh" android:onClick="updateView" android:text="refresh"></Button> </LinearLayout> My Activity code is also very simple. public class TestDrawableStateActivity extends Activity { private final static int[] SELECTED_STATE = { android.R.attr.state_selected }; private final static int[] UNSELECTED_STATE = {}; private TextView textView; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); textView = (TextView) findViewById(R.id.test_view_example); } @Override protected void onResume() { super.onResume(); // Carichiamo la Drawable if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); } } public void updateView(View view) { if(textView.getBackground().setState(SELECTED_STATE)){ textView.invalidate(); }; } } When Activity starts I try to set the state of my Drawable (the StateListDrawable) with the value SELECTED. It seems all very simple.... but the problem is that the state is not shown. If, later, I click a button and execute the method updateView() the state changes. Where is my problem? Where am I wrong? Thankx a lot Max

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  • Handling form from different view and passing form validation through session in django

    - by Mo J. Mughrabi
    I have a requirement here to build a comment-like app in my django project, the app has a view to receive a submitted form process it and return the errors to where ever it came from. I finally managed to get it to work, but I have doubt for the way am using it might be wrong since am passing the entire validated form in the session. below is the code comment/templatetags/comment.py @register.inclusion_tag('comment/form.html', takes_context=True) def comment_form(context, model, object_id, next): """ comment_form() is responsible for rendering the comment form """ # clear sessions from variable incase it was found content_type = ContentType.objects.get_for_model(model) try: request = context['request'] if request.session.get('comment_form', False): form = CommentForm(request.session['comment_form']) form.fields['content_type'].initial = 15 form.fields['object_id'].initial = 2 form.fields['next'].initial = next else: form = CommentForm(initial={ 'content_type' : content_type.id, 'object_id' : object_id, 'next' : next }) except Exception as e: logging.error(str(e)) form = None return { 'form' : form } comment/view.py def save_comment(request): """ save_comment: """ if request.method == 'POST': # clear sessions from variable incase it was found if request.session.get('comment_form', False): del request.session['comment_form'] form = CommentForm(request.POST) if form.is_valid(): obj = form.save(commit=False) if request.user.is_authenticated(): obj.created_by = request.user obj.save() messages.info(request, _('Your comment has been posted.')) return redirect(form.data.get('next')) else: request.session['comment_form'] = request.POST return redirect(form.data.get('next')) else: raise Http404 the usage is by loading the template tag and firing {% comment_form article article.id article.get_absolute_url %} my doubt is if am doing the correct approach or not by passing the validated form to the session. Would that be a problem? security risk? performance issues? Please advise Update In response to Pol question. The reason why I went with this approach is because comment form is handled in a separate app. In my scenario, I render objects such as article and all I do is invoke the templatetag to render the form. What would be an alternative approach for my case? You also shared with me the django comment app, which am aware of but the client am working with requires a lot of complex work to be done in the comment app thats why am working on a new one.

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  • CodeIgniter: problem using foreach in view

    - by krike
    I have a model and controller who gets some data from my database and returns the following array Array ( [2010] => Array ( [year] => 2010 [months] => Array ( [0] => stdClass Object ( [sales] => 2 [month] => Apr ) [1] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) [2011] => Array ( [year] => 2011 [months] => Array ( [0] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) ) It shows exactly what it should show but the key's have different names so I have no idea on how to loop through the years using foreach in my view. Arrays is something I'm not that good at yet :( this is the controller if you need to know: function analytics() { $this->load->model('admin_model'); $analytics = $this->admin_model->Analytics(); foreach ($analytics as $a): $data[$a->year]['year'] = $a->year; $data[$a->year]['months'] = $this->admin_model->AnalyticsMonth($a->year); endforeach; echo"<pre style='text-align:left;'>"; print_r($data); echo"</pre>"; $data['main_content'] = 'analytics'; $this->load->view('template_admin', $data); }//end of function categories()

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  • Invalid table view update with insertRowsAtIndexPaths:

    - by Crystal
    I'm having trouble with insertRowsAtIndexPaths:. I'm not quite sure how it works. I watched the WWDC 2010 video on it, but I'm still getting an error. I thought I was supposed to update the model, then wrap the insertRowsAtIndexPaths: in the tableView beginUpdates and endUpdates calls. What I have is this: self.customTableArray = (NSMutableArray *)sortedArray; [_customTableView beginUpdates]; [tempUnsortedArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) { [sortedArray enumerateObjectsUsingBlock:^(id sortedObj, NSUInteger sortedIdx, BOOL *sortedStop) { if ([obj isEqualToString:sortedObj]) { NSIndexPath *newRow = [NSIndexPath indexPathForRow:sortedIdx inSection:0]; [_customTableView insertRowsAtIndexPaths:[NSArray arrayWithObject:newRow] withRowAnimation:UITableViewRowAnimationAutomatic]; *sortedStop = YES; } }]; }]; [_customTableView endUpdates]; customTableArray is my model array. sortedArray is just the sorted version of that array. When I run this code when I hit my plus button to add a new row, I get this error: Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Invalid update: invalid number of rows in section 0. The number of rows contained in an existing section after the update (2) must be equal to the number of rows contained in that section before the update (1), plus or minus the number of rows inserted or deleted from that section (2 inserted, 0 deleted) and plus or minus the number of rows moved into or out of that section (0 moved in, 0 moved out).' I'm not sure what I'm doing wrong. Thoughts? Thanks.

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  • What kind of data belongs in a view model?

    - by Byron Sommardahl
    The name "view model" suggests that it models the data for the view. That much is obvious. What else can or should go in the view model? As an example, a view might display a list of items in a shopping cart, fields for customer's credit card info, and fields for customer's billing information. The view model might contain properties for all that OR it might only contain properties for the shopping cart items.

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  • Looking into ASP.Net MVC 4.0 Mobile Development - part 1

    - by nikolaosk
    In this post I will be looking how ASP.Net MVC 4.0 helps us to create web solutions that target mobile devices.We all experience the magic that is the World Wide Web through mobile devices. Millions of people around the world, use tablets and smartphones to view the contents of websites,e-shops and portals.ASP.Net MVC 4.0 includes a new mobile project template and the ability to render a different set of views for different types of devices.There is a new feature that is called browser overriding which allows us to control exactly what a user is going to see from your web application regardless of what type of device he is using.In order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 2012 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine.It will work fine in Windows 7 as well so do not worry if you do not have the latest Microsoft operating system.1) Launch VS 2012 and create a new Web Forms application by going to File - >New Project - > ASP.Net MVC 4 Web Application and then click OKHave a look at the picture below  2) From the available templates select Mobile Application and then click OK.Have a look at the picture below 3) When I run the application I get the mobile view of the page. I would like to show you what a typical ASP.Net MVC 4.0 application looks like. So I will create a new simple ASP.Net MVC 4.0 Web Application. When I run the application I get the normal page view.Have a look at the picture below.On the left is the mobile view and on the right the normal view. As you can see we have more or less the same content in our mobile application (log in,register) compared with the normal ASP.Net MVC 4.0 application but it is optimised for mobile devices. 4) Let me explain how and when the mobile view is selected and finally rendered.There is a feature in MVC 4.0 that is called Display Modes and with this feature the runtime will select a view.If we have 2 views e.g contact.mobile.cshtml and contact.cshtml in our application the Controller at some point will instruct the runtime to select and render a view named contact.The runtime will look at the browser making the request and will determine if it is a mobile browser or a desktop browser. So if there is a request from my IPhone Safari browser for a particular site, if there is a mobile view the MVC 4.0 will select it and render it. If there is not a mobile view, the normal view will be rendered.5) In the  ASP.Net MVC 4.0 (Internet application) I created earlier (not the first project which was a mobile one) I can run it once more and see how it looks on the browser. If I want to view it with a mobile browser I must download one emulator like Opera Mobile.You can download Opera Mobile hereWhen I run the application I get the same view in both the desktop and the mobile browser. That was to be expected. Have a look at the picture below 6) Then I create another version of the _Layout.mobile.cshtml view in the Shared folder.I simply copy and paste the _Layout.cshtml  into the same folder and then rename it to _Layout.mobile.cshtml and then just alter the contents of the _Layout.mobile.cshtml.When I run again the application I get a different view on the desktop browser and a different one on the Opera mobile browser.Have a look at the picture below ?he Controller will instruct the ASP.Net runtime to select and render a view named _Layout.mobile.cshtml when the request will come from a mobile browser.?he runtime knows that a browser is a mobile one through the ASP.Net browser capability provider. Hope it helps!!!

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  • What causes a WPF ListCollectionView that uses custom sorting to re-sort its items?

    - by Drew Noakes
    Consider this code (type names genericised for the purposes of example): // Bound to ListBox.ItemsSource _items = new ObservableCollection<Item>(); // ...Items are added here ... // Specify custom IComparer for this collection view _itemsView = CollectionViewSource.GetDefaultView(_items) ((ListCollectionView)_itemsView).CustomSort = new ItemComparer(); When I set CustomSort, the collection is sorted as I expect. However I require the data to re-sort itself at runtime in response to the changing of the properties on Item. The Item class derives from INotifyPropertyChanged and I know that the property fires correctly as my data template updates the values on screen, only the sorting logic is not being called. I have also tried raising INotifyPropertyChanged.PropertyChanged passing an empty string, to see if a generic notification would cause the sorting to be initiated. No bananas. EDIT In response to Kent's suggestion I thought I'd point out that sorting the items using this has the same result, namely that the collection sorts once but does not re-sort as the data changes: _itemsView.SortDescriptions.Add( new SortDescription("PropertyName", ListSortDirection.Ascending));

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  • web2py server-side comments

    - by MikeWyatt
    In a web2py view, how do I comment out server-side code? In ASP.NET, I can surround any HTML or code tags with <%-- and --% and that block will not be compiled or sent to the client. Velocity does the same thing with #* and *#. Is there an equivalent in web2py? ASP.NET <div> <p><%=foo.bar%></p> <%-- don't print twice! <p><%=foo.bar%></p> --%> </div> web2py <div> <p><%=foo.bar%></p> ??? don't print twice! <p><%=foo.bar%></p> ??? </div>

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  • Zend Framework: how to remove rendered views in the controller?

    - by takpar
    i want to render one of these sets of views: head body-$id1 foot OR head body-$id2 foot which set exsists. i do it like this: try { $this->render("head"); $this->render("body-$id1"); $this->render("foot"); } catch (Exception $e) { $this->render("head"); $this->render("body-$id2"); $this->render("foot"); } but it causes the head view be rendered twice if body-$id1 does not exists. do you have a better solution? in another saying, may i check the existance of body-$id1 before rendering it?

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  • producing a typewriter-like effect

    - by Tony Ennis
    Android newb here. Please use small words :-) I'd like to simulate typewriter output on my Android. The output being displayed is generated by a game and is somewhat freeform. The effect I want to see individual characters appear at a rate of about 6 characters a second. When a 'carriage return' is seen, I'd like to insert a delay then resume typing on the left. What are some suggestions on views? Would the view of choice for this be a TextView? Even that seems like overkill for this read-only coarsely scrolling output. I saw something on this thread about an AsyncTask. That looks useful. Perhaps my game will write to some manner of buffer, and a subclass of AsyncTask will pull characters out every .15 seconds or so, add them to the TextView, then invalidate() the TextView? Sound like a plan?

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  • Client Id for Property (ASP.Net MVC)

    - by Felipe
    Hi guys... I'm begginer in asp.net mvc, and i have a doubs: I'm trying to do a label for a TextBox in my View and I'd like to know, how can I take a Id that will be render in client to generete scripts... for example: <label for="<%=x.Name.?ClientId?%>"> Name: </label> <%=Html.TextBoxFor(x=>x.Name) %> What need I put in "?ClientId?" to make sure that correct Id will be render to the corresponding control ? Thanks Cheers

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