Search Results

Search found 3592 results on 144 pages for 'pointer'.

Page 138/144 | < Previous Page | 134 135 136 137 138 139 140 141 142 143 144  | Next Page >

• xmlpullparser(), whats wrong with my code?

  - by Avinazz

  I am expecting output to be an array list filled with all items as "thought" but instead, every time i add a value into arraylist, the previous value in list also gets update with new, hence resulting in duplicates. This behaviour goes on till end. Even though i have achieved the result by changing the approach, failure of my previous approach still bothers me. Any help or pointer will be really appreciated. Below is xml snippet: <Thoughts> <country> <name>India</name> <item> <itemId>1</itemId> <itemDetailImage>detail.png</itemDetailImage> <itemImage>image1.png</itemImage> <itemDesc>Item Description 1</itemDesc> <itemTitle>Item Title 1</itemTitle> </item> <item> <itemId>2</itemId> <itemDetailImage>detail2.png</itemDetailImage> <itemImage>image2.png</itemImage> <itemDesc>Item Description 2</itemDesc> <itemTitle>Item Title 2</itemTitle> </item> <item> <itemId>3</itemId> <itemDetailImage>detail3.png</itemDetailImage> <itemImage>image3.png</itemImage> <itemDesc>Item Description 3</itemDesc> <itemTitle>Item Title 3</itemTitle> </item> Below is a method for my trial and error: private void printAll() throws XmlPullParserException, IOException{ XmlPullParserFactory factory = XmlPullParserFactory.newInstance(); factory.setNamespaceAware(false); XmlPullParser parser = factory.newPullParser(); URL url = new URL("http://192.168.1.3/DefaultXML.xml"); URLConnection ucon = url.openConnection(); InputStream is = ucon.getInputStream(); parser.setInput(is, null); int eventType = parser.getEventType(); String name; while(eventType != parser.END_DOCUMENT){ if(eventType == parser.START_DOCUMENT){ Log.i(TAG,"Start document"); }else if (eventType == parser.START_TAG ) { name = parser.getName(); if(name.equalsIgnoreCase(NAME)){ this.cName = new Country(); this.cName.setName(parser.nextText()); }else if(name.equalsIgnoreCase(ITEM_DESC)){ this.thought.setItemDesc(parser.nextText()); }else if (name.equalsIgnoreCase(ITEM_ID)) { this.thought.setItemID(parser.nextText()); }else if (name.equalsIgnoreCase(ITEM_DETAIL_IMAGE)) { this.thought.setItemDetailImage(parser.nextText()); }else if (name.equalsIgnoreCase(ITEM_IMAGE)) { this.thought.setItemImage(parser.nextText()); }else if (name.equalsIgnoreCase(ITEM_TITLE)) { this.thought.setItemTitle(parser.nextText()); } }else if (eventType == parser.END_TAG) { name = parser.getName(); if(name.equalsIgnoreCase(ITEM)) { this.cName.setThought(this.thought); ctry.add(cName); this.thought = new Thought(); } } eventType = parser.next(); } //Log.i(TAG,"---" + ctry.toString()); }

  Read the article

• Where are the function address literals in c++?

  - by academicRobot

  First of all, maybe literals is not the right term for this concept, but its the closest I could think of (not literals in the sense of functions as first class citizens). <UPDATE> After some reading with help from answer by Chris Dodd, what I'm looking for is literal function addresses as template parameters. Chris' answer indicates how to do this for standard functions, but how can the addresses of member functions be used as template parameters? Since the standard prohibits non-static member function addresses as template parameters (c++03 14.3.2.3), I suspect the work around is quite complicated. Any ideas for a workaround? Below the original form of the question is left as is for context. </UPDATE> The idea is that when you make a conventional function call, it compiles to something like this: callq <immediate address> But if you make a function call using a function pointer, it compiles to something like this: mov <memory location>,%rax callq *%rax Which is all well and good. However, what if I'm writing a template library that requires a callback of some sort with a specified argument list and the user of the library is expected to know what function they want to call at compile time? Then I would like to write my template to accept a function literal as a template parameter. So, similar to template <int int_literal> struct my_template {...};` I'd like to write template <func_literal_t func_literal> struct my_template {...}; and have calls to func_literal within my_template compile to callq <immediate address>. Is there a facility in C++ for this, or a work around to achieve the same effect? If not, why not (e.g. some cataclysmic side effects)? How about C++0x or another language? Solutions that are not portable are fine. Solutions that include the use of member function pointers would be ideal. I'm not particularly interested in being told "You are a <socially unacceptable term for a person of low IQ>, just use function pointers/functors." This is a curiosity based question, and it seems that it might be useful in some (albeit limited) applications. It seems like this should be possible since function names are just placeholders for a (relative) memory address, so why not allow more liberal use (e.g. aliasing) of this placeholder. p.s. I use function pointers and functions objects all the the time and they are great. But this post got me thinking about the don't pay for what you don't use principle in relation to function calls, and it seems like forcing the use of function pointers or similar facility when the function is known at compile time is a violation of this principle, though a small one. Edit The intent of this question is not to implement delegates, rather to identify a pattern that will embed a conventional function call, (in immediate mode) directly into third party code, possibly a template.

  Read the article

• Getting Segmentation Fault in C++, but why?

  - by Carlos

  I am getting segmentation fault in this code but i cant figure out why. I know a segmentation fault happens when a pointer is NULL, or when it points to a random memory address. #include <iostream> #include <fstream> #include <cmath> using namespace std; //**************************** CLASS ******************************* class Database { struct data{ string city; float latitude, longitude; data *link; }*p; public: Database(); void display(); void add(string cityName, float lat, float lon); private: string cityName; float lat, lon; }; //************************** CLASS METHODS ************************** Database::Database() { p = NULL; } void Database::add(string cityName, float lat, float lon){ data *q, *t; if(p == NULL){ p = new data; p -> city = cityName; p -> latitude = lat; p -> longitude = lon; p -> link = NULL; } else{ q = p; while(q -> link != NULL){ q = q -> link; } t = new data; t -> city = cityName; t -> latitude = lat; t -> longitude = lon; q -> link = t; } } void Database::display() { data *q; cout<<endl; for( q = p ; q != NULL ; q = q->link ) cout << endl << q -> city; } //***************************** MAIN ******************************* //*** INITIALIZATION *** Database D; void loadDatabase(); //****** VARIABLES ***** //******* PROGRAM ****** int main() { loadDatabase(); D.display(); } void loadDatabase() { int i = 0; string cityName; float lat, lon; fstream city; city.open("city.txt", ios::in); fstream latitude; latitude.open("lat.txt", ios::in); fstream longitude; longitude.open("lon.txt", ios::in); while(!city.eof()){ //************************************ city >> cityName; //* * latitude >> lat; //Here is where i think is the problem longitude >> lon; //* * D.add(cityName, lat, lon); //************************************ } city.close(); latitude.close(); longitude.close(); } This is the error am actually getting in console

  Read the article

• GetAcceptExSockaddrs returns garbage! Does anyone know why?

  - by David

  Hello, I'm trying to write a quick/dirty echoserver in Delphi, but I notice that GetAcceptExSockaddrs seems to be writing to only the first 4 bytes of the structure I pass it. USES SysUtils; TYPE BOOL = LongBool; DWORD = Cardinal; LPDWORD = ^DWORD; short = SmallInt; ushort = Word; uint16 = Word; uint = Cardinal; ulong = Cardinal; SOCKET = uint; PVOID = Pointer; _HANDLE = DWORD; _in_addr = packed record s_addr : ulong; end; _sockaddr_in = packed record sin_family : short; sin_port : uint16; sin_addr : _in_addr; sin_zero : array[0..7] of Char; end; P_sockaddr_in = ^_sockaddr_in; _Overlapped = packed record Internal : Int64; Offset : Int64; hEvent : _HANDLE; end; LP_Overlapped = ^_Overlapped; IMPORTS function _AcceptEx (sListenSocket, sAcceptSocket : SOCKET; lpOutputBuffer : PVOID; dwReceiveDataLength, dwLocalAddressLength, dwRemoteAddressLength : DWORD; lpdwBytesReceived : LPDWORD; lpOverlapped : LP_OVERLAPPED) : BOOL; stdcall; external MSWinsock name 'AcceptEx'; procedure _GetAcceptExSockaddrs (lpOutputBuffer : PVOID; dwReceiveDataLength, dwLocalAddressLength, dwRemoteAddressLength : DWORD; LocalSockaddr : P_Sockaddr_in; LocalSockaddrLength : LPINT; RemoteSockaddr : P_Sockaddr_in; RemoteSockaddrLength : LPINT); stdcall; external MSWinsock name 'GetAcceptExSockaddrs'; CONST BufDataSize = 8192; BufAddrSize = SizeOf (_sockaddr_in) + 16; VAR ListenSock, AcceptSock : SOCKET; Addr, LocalAddr, RemoteAddr : _sockaddr_in; LocalAddrSize, RemoteAddrSize : INT; Buf : array[1..BufDataSize + BufAddrSize * 2] of Byte; BytesReceived : DWORD; Ov : _Overlapped; BEGIN //WSAStartup, create listen socket, bind to port 1066 on any interface, listen //Create event for overlapped (autoreset, initally not signalled) //Create accept socket if _AcceptEx (ListenSock, AcceptSock, @Buf, BufDataSize, BufAddrSize, BufAddrSize, @BytesReceived, @Ov) then WinCheck ('SetEvent', _SetEvent (Ov.hEvent)) else if GetLastError <> ERROR_IO_PENDING then WinCheck ('AcceptEx', GetLastError); {do WaitForMultipleObjects} _GetAcceptExSockaddrs (@Buf, BufDataSize, BufAddrSize, BufAddrSize, @LocalAddr, @LocalAddrSize, @RemoteAddr, @RemoteAddrSize); So if I run this, connect to it with Telnet (on same computer, connecting to localhost) and then type a key, WaitForMultipleObjects will unblock and GetAcceptExSockaddrs will run. But the result is garbage! RemoteAddr.sin_family = -13894 RemoteAddr.sin_port = 64 and the rest is zeroes. What gives? Thanks in advance!

  Read the article

• jQuery - animating 'left' position of absolutely positioned div when sliding panel is revealed

  - by trickymatt

  Hello, I have a hidden panel off the left side of the screen which slides into view on the click of a 'tab' positioned on the left side of the screen. I need the panel to slide over the top of the existing page content, and I need the tab to move with it. and so both are absolutely positioned in css. Everything works fine, apart from I need the tab (and thus the tab-container) to move left with the panel when it is revealed, so it appears to be stuck to the right-hand-side of the panel. Its relatively simple when using floats, but of course this affects the layout of the existing content, hence absolute positioning. I have tried animating the left position of the panel-container (see the documented jquery function), but I cant get it to work. My HTML <div><!--sample page content--> <p> Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et </p> </div> <div id="panel" class="height"> <!--the hidden panel --> <div class="content"> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore</p> </div> </div> <!--if javascript is disabled use this link--> <div id="tab-container" class="height"> <a href="#" onclick="return()"> <div id="tab"><!-- this will activate the panel. --></div> </a> </div> My jQuery $(document).ready(function(){ $("#panel, .content").hide(); //hides the panel and content from the user $('#tab').toggle(function(){ //adding a toggle function to the #tab $('#panel').stop().animate({width:"400px", opacity:0.8}, 100, //sliding the #panel to 400px // THIS NEXT FUNCTION DOES NOT WORK --> function() { $('#tab-container').animate({left:"400px"} //400px to match the panel width }); function() { $('.content').fadeIn('slow'); //slides the content into view. }); }, function(){ //when the #tab is next cliked $('.content').fadeOut('slow', function() { //fade out the content $('#panel').stop().animate({width:"0", opacity:0.1}, 500); //slide the #panel back to a width of 0 }); }); }); and this is the css #panel { position:absolute; left:0px; top:50px; background-color:#999999; height:500px; display:none;/*hide the panel if Javascript is not running*/ } #panel .content { width:290px; margin-left:30px; } #tab-container{ position:absolute; top:20px; width:50px; height:620px; background:#161616; } #tab { width:50px; height:150px; margin-top:100px; display:block; cursor:pointer; background:#DDD; } Many thanks

  Read the article

• CSS Horizontal sub menu - IE 6,7 both dont working, tried with whatever hover.

  - by SHAKTI

  I'm not expert about css menus. But I know basic system to make css menu. I used this system before and works, but this time it is not working. The site is http://www.uniethos.com. Please check this site This menu works with all other latest Browsers. But not with IE 6 & 7. I know IE6 don't support hover except anchor. So before I was using Whatever Hover. But this time it is not working and even with IE7. I don't know why its happening. May be there could be some problem with my css. Please check the css. If you don't have IE 6 or 7 installed you can run one from http://spoon.net/browsers/. Require to install one plugin. The CSS I'm using for the menu is .glossymenu{ background: #B4B3B3; height: 30px; width: 100%; padding: 0; margin: 0; display:inline-block; position:relative; } .glossymenu ul { list-style: none; padding: 0px; margin: 0; padding-left: 0px; } .glossymenu li ul { display:none; position:absolute; width: 80%; top:30px; left:0px; background-color:#5B0C10; border:0px; z-index: 99; } .glossymenu li li a { padding: 0px 10px 0px 10px; } .glossymenu li li a:hover { background : #871016; } .glossymenu li{ float:left; padding: 0; } .glossymenu li a{ float: left; display:block; position:relative; color:#FFF; text-decoration: none; font-family: sans-serif; font-size: 13px; font-weight: bold; padding:0 0 0 16px; /*Padding to accomodate left tab image. Do not change*/ height: 30px; line-height: 30px; text-align: center; cursor: pointer; } .glossymenu li a b{ float: left; display: block; padding: 0 24px 0 8px; /*Padding of menu items*/ } .glossymenu li.current a, .glossymenu li a:hover{ color: #FFF; background: #5B0C10; background-position: left; text-decoration: none; } .glossymenu li a:visited{ text-decoration: none; } .glossymenu ul li:hover ul { display: block; }

  Read the article

• z-index not working in IE8 with the sortable jQuery plugin

  - by Ojtwist

  I'm working with the jQuery Sortable plugin to drag and drop images from one box to another box. This works fine in ff,chrome and safari but it fails in IE8. It seems that when you start dragging that the image is send to the back. I've tried to solve this by adding the z-index option to the sortable plugin, i've tried appending it to a node higher in the hierarchy (body). It appears that setting a z-index on every other item in the page would fix this, haven't tried it yet and i'm not planning on doing this because this would mess up alot. So the user can drag an image from 1 gallery to the next gallery screenshot of how it should work: http://img69.imageshack.us/i/draganddrop.jpg/ Some html: <!--SECOND ARROCRDION ITEM --> <a class="flickr_accordeon_header" id="flickr_second_header" href="javascript:;">__MSG__SEARCH_FOR_PHOTOS__</a> <div> <p class ="flickr_text" > __MSG__SEARCH_FOR_PHOTOS__</p> <form method="GET" action="javascript:;"> <p> <input type="text" value="__MSG__SEARCH__" id="flickr_key_input" class="flickr_changeColorNormal" /> <button class="s3d-button flickr_search" id="flickr_seach_button"> <span class="s3d-button-inner" >__MSG__SEARCH__</span> </button> <img src="/devwidgets/flickr/images/ajax-loader-gray.gif" alt="__MSG__LOADING_IMAGE__" id="flickr_loading_img" /> <a href="javascript:;" id="flickr_refresh_key_button"><img src="/dev/_images/recent_activity_icon.png" alt="refresh" title='refresh' /></a> </p> </form> <div id="flickr_input_error">__MSG__INPUT_ERROR__</div> <div id="flickr_input_same_error">__MSG__INPUT_SAME_ERROR__</div> **<div id="flickr_key_gallery" ><ul class="flickr_key_ul"><li></li></ul></div>** <div id="flickr_key_pagging" ></div> </div> </div> <!--SLIDING SIDEBAR --> <div id="flickr_sidebar" class="jcarousel-skin-tango"> <div id="flickr_side_paging"></div> **<ul> <li><img src="/devwidgets/flickr/images/drop-image.png" alt="__MSG__DROP_HERE__" class="flick_drop_here"></li> </ul>** </div> The images get rendered into the ul, so basically it's just an ul with li's with images javascript for sortable: horizontal: { helper: "clone", // Instead of dragging the real image a copy will be dragged connectWith: ["#flickr_sidebar ul"], // To be able to drag and drop an image to another image gallery they need to be connected cursor: 'pointer', //change the cursor when dragging opacity: 0.50, //Change the opacity while dragging appendTo: 'body', //When dropped the images need to be appended to the image gallery where they are dropped containment: 'body', //Make sure the user can't drag the images outside the widget revert: true, // if the user releases the image ouside the dropbox it'll return to it's original position zIndex: 9999 } I've tried it with setting the dragged image to absolute and the container on relative... doesn't work Anyone know how to solve this in IE8 ?

  Read the article

• Problems with passing an anonymous temporary function-object to a templatized constructor.

  - by Akanksh

  I am trying to attach a function-object to be called on destruction of a templatized class. However, I can not seem to be able to pass the function-object as a temporary. The warning I get is (if the comment the line xi.data = 5;): warning C4930: 'X<T> xi2(writer (__cdecl *)(void))': prototyped function not called (was a variable definition intended?) with [ T=int ] and if I try to use the constructed object, I get a compilation error saying: error C2228: left of '.data' must have class/struct/union I apologize for the lengthy piece of code, but I think all the components need to be visible to assess the situation. template<typename T> struct Base { virtual void run( T& ){} virtual ~Base(){} }; template<typename T, typename D> struct Derived : public Base<T> { virtual void run( T& t ) { D d; d(t); } }; template<typename T> struct X { template<typename R> X(const R& r) { std::cout << "X(R)" << std::endl; ptr = new Derived<T,R>(); } X():ptr(0) { std::cout << "X()" << std::endl; } ~X() { if(ptr) { ptr->run(data); delete ptr; } else { std::cout << "no ptr" << std::endl; } } Base<T>* ptr; T data; }; struct writer { template<typename T> void operator()( const T& i ) { std::cout << "T : " << i << std::endl; } }; int main() { { writer w; X<int> xi2(w); //X<int> xi2(writer()); //This does not work! xi2.data = 15; } return 0; }; The reason I am trying this out is so that I can "somehow" attach function-objects types with the objects without keeping an instance of the function-object itself within the class. Thus when I create an object of class X, I do not have to keep an object of class writer within it, but only a pointer to Base<T> (I'm not sure if I need the <T> here, but for now its there). The problem is that I seem to have to create an object of writer and then pass it to the constructor of X rather than call it like X<int> xi(writer(); I might be missing something completely stupid and obvious here, any suggestions?

  Read the article

• Linked Lists in Java - Help with assignment

  - by doron2010

  I have been trying to solve this assignment all day, please help me. I'm completely lost. Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) public char charAt (int i) - returns the char in the place i in the string. Assume that the value of i is in the right range. public StringList concat (String str) - returns a string that consists of the string that it is operated on and in its end the string "str" is concatenated. public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. public int indexOf (int ch, int fromIndex) - returns the index in the string it is operated on of the first appeareance of the char "ch", as the search begins in the index "fromIndex". If the char "ch" doesn't appear in the string, returns -1. public boolean equals (String str) - returns true if the string that it is operated on is equal to the string str. Otherwise returns false. This method must be written in recursion, without using loops at all. public int compareTo (String str) - compares between the string that the method is operated on to the string "str" that is in the parameter. The method returns 0 if the strings are equal. If the string in the object is smaller lexicographic from the string "str" in the paramater, a negative number will be returned. And if the string in the object is bigger lexicographic from the string "str", a positive number will be returned. public StringList substring (int i) - returns the list of the substring that starts in the place i in the string on which it operates. Meaning, the sub-string from the place i until the end of the string. Assume the value of i is in the right range. public StringList substring (int i, int j) - returns the list of the substring that begins in the place i and ends in the place j (not included) in the string it operates on. Assume the values of i, j are in the right range. public int length() - will return the length of the string on which it operates. Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations.

  Read the article

• Accessing Layout Items from inside Widget AppWidgetProvider

  - by cam4mav

  I am starting to go insane trying to figure this out. It seems like it should be very easy, I'm starting to wonder if it's possible. What I am trying to do is create a home screen widget, that only contains an ImageButton. When it is pressed, the idea is to change some setting (like the wi-fi toggle) and then change the Buttons image. I have the ImageButton declared like this in my main.xml <ImageButton android:id="@+id/buttonOne" android:src="@drawable/button_normal_ringer" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center" /> my AppWidgetProvider class, named ButtonWidget * note that the RemoteViews class is a locally stored variable. this allowed me to get access to the RViews layout elements... or so I thought. @Override public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) { remoteViews = new RemoteViews(context.getPackageName(), R.layout.main); Intent active = new Intent(context, ButtonWidget.class); active.setAction(VIBRATE_UPDATE); active.putExtra("msg","TESTING"); PendingIntent actionPendingIntent = PendingIntent.getBroadcast(context, 0, active, 0); remoteViews.setOnClickPendingIntent(R.id.buttonOne, actionPendingIntent); appWidgetManager.updateAppWidget(appWidgetIds, remoteViews); } @Override public void onReceive(Context context, Intent intent) { // v1.5 fix that doesn't call onDelete Action final String action = intent.getAction(); Log.d("onReceive",action); if (AppWidgetManager.ACTION_APPWIDGET_DELETED.equals(action)) { final int appWidgetId = intent.getExtras().getInt( AppWidgetManager.EXTRA_APPWIDGET_ID, AppWidgetManager.INVALID_APPWIDGET_ID); if (appWidgetId != AppWidgetManager.INVALID_APPWIDGET_ID) { this.onDeleted(context, new int[] { appWidgetId }); } } else { // check, if our Action was called if (intent.getAction().equals(VIBRATE_UPDATE)) { String msg = "null"; try { msg = intent.getStringExtra("msg"); } catch (NullPointerException e) { Log.e("Error", "msg = null"); } Log.d("onReceive",msg); if(remoteViews != null){ Log.d("onReceive",""+remoteViews.getLayoutId()); remoteViews.setImageViewResource(R.id.buttonOne, R.drawable.button_pressed_ringer); Log.d("onReceive", "tried to switch"); } else{ Log.d("F!", "--naughty language used here!!!--"); } } super.onReceive(context, intent); } } so, I've been testing this and the onReceive method works great, I'm able to send notifications and all sorts of stuff (removed from code for ease of reading) the one thing I can't do is change any properties of the view elements. To try and fix this, I made RemoteViews a local and static private variable. Using log's I was able to see that When multiple instances of the app are on screen, they all refer to the one instance of RemoteViews. perfect for what I'm trying to do The trouble is in trying to change the image of the ImageButton. I can do this from within the onUpdate method using this. remoteViews.setImageViewResource(R.id.buttonOne, R.drawable.button_pressed_ringer); that doesn't do me any good though once the widget is created. For some reason, even though its inside the same class, being inside the onReceive method makes that line not work. That line used to throw a Null pointer as a matter of fact, until I changed the variable to static. now it passes the null test, refers to the same layoutId as it did at the start, reads the line, but it does nothing. Its like the code isn't even there, just keeps chugging along. SO...... Is there any way to modify layout elements from within a widget after the widget has been created!? I want to do this based on the environment, not with a configuration activity launch. I've been looking at various questions and this seems to be an issue that really hasn't been solved, such as link text and link text oh and for anyone who finds this and wants a good starting tutorial for widgets, this is easy to follow (though a bit old, it gets you comfortable with widgets) .pdf link text hopefully someone can help here. I kinda have the feeling that this is illegal and there is a different way to go about this. I would LOVE to be told another approach!!!! Thanks

  Read the article

• Sidebar with CSS3 transform

  - by Malcoda

  Goal I'm working on a collapsible sidebar using jQuery for animation. I would like to have vertical text on the sidebar that acts as a label and can swap on the animateOut/animateIn effect. Normally I would use an image of the text that I've simply swapped vertically, and switch it out on animation, but with CSS3 transforms I'd like to get it to work instead. Problem The problem I'm facing is that setting the height on my rotated container makes it expand horizontally (as it's rotated 90deg) so that doesn't work. I then tried to set the width (hoping it would expand vertically, acting as height), but that has an odd effect of causing the width of my parent container to expand as well. Fix? Anyone know why this happens and also what the fix/workaround could be without setting max-widths and overflow: hidden? I've got a fairly good understanding of both html elements behavior and css3, but this is stumping me. Live Example Here's a fiddle that demonstrates my problem: Fiddle The collapse-pane class is what I have rotated and contains the span I have my text inside. You'll notice it has a width set, that widens the border, but also affects the parent container. The code: CSS: .right-panel{ position:fixed; right:0; top:0; bottom:0; border:1px solid #ccc; background-color:#efefef; } .collapse-pane{ margin-top:50px; width:30px; border:1px solid #999; cursor:pointer; /* Safari */ -webkit-transform: rotate(-90deg); /* Firefox */ -moz-transform: rotate(-90deg); /* IE */ -ms-transform: rotate(-90deg); /* Opera */ -o-transform: rotate(-90deg); /* Internet Explorer */ filter: progid:DXImageTransform.Microsoft.BasicImage(rotation=3); } .collapse-pane span{ padding:5px; } HTML <div class="right-panel"> <div class="collapse-pane"> <span class="expand">Expand</span> </div> <div style="width:0;" class="panel-body"> <div style="display:none;" class="panel-body-inner"> adsfasdfasdf </div> </div> </div> JavaScript (Thought not really relevant) $(document).ready(function(){ var height = $(".right-panel").height(); $(".collapse-pane").css({marginTop: height/2 - 20}); $('.collapse-pane').click(function(){ if($(".collapse-pane span").html() == "Expand"){ $(".panel-body").animate({width:200}, 400); $(".panel-body-inner").fadeIn(500); $(".collapse-pane span").html("Collapse"); }else{ $(".panel-body").animate({width:00}, 400); $(".panel-body-inner").fadeOut(300); $(".collapse-pane span").html("Expand"); } }); }); I hope this was clear... Thanks for any help!

  Read the article

• Effective optimization strategies on modern C++ compilers

  - by user168715

  I'm working on scientific code that is very performance-critical. An initial version of the code has been written and tested, and now, with profiler in hand, it's time to start shaving cycles from the hot spots. It's well-known that some optimizations, e.g. loop unrolling, are handled these days much more effectively by the compiler than by a programmer meddling by hand. Which techniques are still worthwhile? Obviously, I'll run everything I try through a profiler, but if there's conventional wisdom as to what tends to work and what doesn't, it would save me significant time. I know that optimization is very compiler- and architecture- dependent. I'm using Intel's C++ compiler targeting the Core 2 Duo, but I'm also interested in what works well for gcc, or for "any modern compiler." Here are some concrete ideas I'm considering: Is there any benefit to replacing STL containers/algorithms with hand-rolled ones? In particular, my program includes a very large priority queue (currently a std::priority_queue) whose manipulation is taking a lot of total time. Is this something worth looking into, or is the STL implementation already likely the fastest possible? Along similar lines, for std::vectors whose needed sizes are unknown but have a reasonably small upper bound, is it profitable to replace them with statically-allocated arrays? I've found that dynamic memory allocation is often a severe bottleneck, and that eliminating it can lead to significant speedups. As a consequence I'm interesting in the performance tradeoffs of returning large temporary data structures by value vs. returning by pointer vs. passing the result in by reference. Is there a way to reliably determine whether or not the compiler will use RVO for a given method (assuming the caller doesn't need to modify the result, of course)? How cache-aware do compilers tend to be? For example, is it worth looking into reordering nested loops? Given the scientific nature of the program, floating-point numbers are used everywhere. A significant bottleneck in my code used to be conversions from floating point to integers: the compiler would emit code to save the current rounding mode, change it, perform the conversion, then restore the old rounding mode --- even though nothing in the program ever changed the rounding mode! Disabling this behavior significantly sped up my code. Are there any similar floating-point-related gotchas I should be aware of? One consequence of C++ being compiled and linked separately is that the compiler is unable to do what would seem to be very simple optimizations, such as move method calls like strlen() out of the termination conditions of loop. Are there any optimization like this one that I should look out for because they can't be done by the compiler and must be done by hand? On the flip side, are there any techniques I should avoid because they are likely to interfere with the compiler's ability to automatically optimize code? Lastly, to nip certain kinds of answers in the bud: I understand that optimization has a cost in terms of complexity, reliability, and maintainability. For this particular application, increased performance is worth these costs. I understand that the best optimizations are often to improve the high-level algorithms, and this has already been done.

  Read the article

• Split a Large File In C++

  - by wdow88

  Hey all, I'm trying to write a program that takes a large file (of any time) and splits it into many smaller "chunks". I think I have the basic idea down, but for some reason I cannot create a chunk size over 12,000 bites. I know there are a few solutions on google, etc. but I am more interested in learning what the origin of this limitation is then actually using the program to split files. //This file splits are larger into smaller files of a user inputted size. #include<iostream> #include<fstream> #include<string> #include<sstream> #include <direct.h> #include <stdlib.h> using namespace std; void GetCurrentPath(char* buffer) { _getcwd(buffer, _MAX_PATH); } int main() { // use the function to get the path char CurrentPath[_MAX_PATH]; GetCurrentPath(CurrentPath);//Get the current directory (used for displaying output) fstream bigFile; string filename; int partsize; cout << "Enter a file name: "; cin >> filename; //Recieve target file cout << "Enter the number of bites in each smaller file: "; cin >> partsize; //Recieve volume size bigFile.open(filename.c_str(),ios::in | ios::binary); bigFile.seekg(0, ios::end); // position get-ptr 0 bytes from end int size = bigFile.tellg(); // get-ptr position is now same as file size bigFile.seekg(0, ios::beg); // position get-ptr 0 bytes from beginning for (int i = 0; i <= (size / partsize); i++) { //Build File Name string partname = filename; //The original filename string charnum; //archive number stringstream out; //stringstream object out, used to build the archive name out << "." << i; charnum = out.str(); partname.append(charnum); //put the part name together //Write new file part fstream filePart; filePart.open(partname.c_str(),ios::out | ios::binary); //Open new file with the name built above //Check if near the end of file if (bigFile.tellg() < (size - (size%partsize))) { filePart.write(reinterpret_cast<char *>(&bigFile),partsize); //Write the selected amount to the file filePart.close(); //close file bigFile.seekg(partsize, ios::cur); //move pointer to next position to be written } //Changes the size of the last volume because it is the end of the file else { filePart.write(reinterpret_cast<char *>(&bigFile),(size%partsize)); //Write the selected amount to the file filePart.close(); //close file } cout << "File " << CurrentPath << partname << " produced" << endl; //display the progress of the split } bigFile.close(); cout << "Split Complete." << endl; return 0; } Any ideas? Thanks!

  Read the article

• Can anyone help me find why this C program work on VS2005 but not on DEV-C++

  - by user333771

  Hello to everybody..and greetings from Greece I have a C program for an exercise and it has a strange issue The program runs just fine on VS 2005 but it crashes on DEV-C++ and the problem that the problem is that the exercise is always evaluated against DEV-C++ The program is about inserting nodes to a BST and this is where the problem lies... Well i would really appreciate some help. enter code here #include <stdio.h> #include <stdlib.h> #include <malloc.h> typedef struct tree_node { int value; int weight; struct tree_node *left; struct tree_node *right; } TREE_NODE; /* The Following function creates a Binary Search Treed */ TREE_NODE *create_tree(int list[], int size); TREE_NODE *search_pos_to_insert(TREE_NODE *root, int value, int *left_or_right); /* this is the problematic function */ void inorder(TREE_NODE *root); /* Inorder Traversing */ TREE_NODE *temp; int main() { TREE_NODE *root; /* Pointer to the root of the BST */ int values[] = {10, 5, 3, 4, 1, 9, 6, 7, 8, 2}; /* Values for BST */ int size = 10, tree_weight; root = create_tree(values, 10); printf("\n"); inorder(root); /* Inorder BST*/ system("PAUSE"); } TREE_NODE *search_pos_to_insert(TREE_NODE *root, int value, int *left_or_right) { if(root !=NULL) { temp = root; if(value >root->value) { *left_or_right=1; *search_pos_to_insert(root->right, value, left_or_right); } else { *left_or_right=0; *search_pos_to_insert(root->left, value, left_or_right); } } else return temp;/* THIS IS THE PROBLEM (1) */ } TREE_NODE *create_tree(int list[], int size) { TREE_NODE *new_node_pntr, *insert_point, *root = NULL; int i, left_or_right; /* First Value of the Array is the root of the BST */ new_node_pntr = (TREE_NODE *) malloc(sizeof(TREE_NODE)); new_node_pntr->value = list[0]; /* ¸íèåóå ôçí ðñþôç ôéìÞ ôïõ ðßíáêá. */ new_node_pntr->weight = 0; new_node_pntr->left = NULL; new_node_pntr->right = NULL; root = new_node_pntr; /* Now the rest of the arrat. */ for (i = 1; i < size; i++) { insert_point = search_pos_to_insert(root, list[i], &left_or_right); /* THIS IS THE PROBLEM (2) */ /* insert_point just won't get the return from temp */ new_node_pntr = (TREE_NODE *) malloc(sizeof(TREE_NODE)); new_node_pntr->value = list[i]; new_node_pntr->weight = 0; new_node_pntr->left = NULL; new_node_pntr->right = NULL; if (left_or_right == 0) insert_point->left = new_node_pntr; else insert_point->right = new_node_pntr; } return(root); } void inorder(TREE_NODE *root) { if (root == NULL) return; inorder(root->left); printf("Value: %d, Weight: %d.\n", root->value, root->weight); inorder(root->right); }

  Read the article

• How to safely operate on parameters in threads, using C++ & Pthreads?

  - by ChrisCphDK

  Hi. I'm having some trouble with a program using pthreads, where occassional crashes occur, that could be related to how the threads operate on data So I have some basic questions about how to program using threads, and memory layout: Assume that a public class function performs some operations on some strings, and returns the result as a string. The prototype of the function could be like this: std::string SomeClass::somefunc(const std::string &strOne, const std::string &strTwo) { //Error checking of strings have been omitted std::string result = strOne.substr(0,5) + strTwo.substr(0,5); return result; } Is it correct to assume that strings, being dynamic, are stored on the heap, but that a reference to the string is allocated on the stack at runtime? Stack: [Some mem addr] pointer address to where the string is on the heap Heap: [Some mem addr] memory allocated for the initial string which may grow or shrink To make the function thread safe, the function is extended with the following mutex (which is declared as private in the "SomeClass") locking: std::string SomeClass::somefunc(const std::string &strOne, const std::string &strTwo) { pthread_mutex_lock(&someclasslock); //Error checking of strings have been omitted std::string result = strOne.substr(0,5) + strTwo.substr(0,5); pthread_mutex_unlock(&someclasslock); return result; } Is this a safe way of locking down the operations being done on the strings (all three), or could a thread be stopped by the scheduler in the following cases, which I'd assume would mess up the intended logic: a. Right after the function is called, and the parameters: strOne & strTwo have been set in the two reference pointers that the function has on the stack, the scheduler takes away processing time for the thread and lets a new thread in, which overwrites the reference pointers to the function, which then again gets stopped by the scheduler, letting the first thread back in? b. Can the same occur with the "result" string: the first string builds the result, unlocks the mutex, but before returning the scheduler lets in another thread which performs all of it's work, overwriting the result etc. Or are the reference parameters / result string being pushed onto the stack while another thread is doing performing it's task? Is the safe / correct way of doing this in threads, and "returning" a result, to pass a reference to a string that will be filled with the result instead: void SomeClass::somefunc(const std::string &strOne, const std::string &strTwo, std::string result) { pthread_mutex_lock(&someclasslock); //Error checking of strings have been omitted result = strOne.substr(0,5) + strTwo.substr(0,5); pthread_mutex_unlock(&someclasslock); } The intended logic is that several objects of the "SomeClass" class creates new threads and passes objects of themselves as parameters, and then calls the function: "someFunc": int SomeClass::startNewThread() { pthread_attr_t attr; pthread_t pThreadID; if(pthread_attr_init(&attr) != 0) return -1; if(pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_DETACHED) != 0) return -2; if(pthread_create(&pThreadID, &attr, proxyThreadFunc, this) != 0) return -3; if(pthread_attr_destroy(&attr) != 0) return -4; return 0; } void* proxyThreadFunc(void* someClassObjPtr) { return static_cast<SomeClass*> (someClassObjPtr)->somefunc("long string","long string"); } Sorry for the long description. But I hope the questions and intended purpose is clear, if not let me know and I'll elaborate. Best regards. Chris

  Read the article

• Placeholder is not shown in jquery sortable, drag & drop

  - by balakrishnan

  I can't show Place holder for the sortable items in a div. &lt;script type="text/javascript"&gt; $(function() { $("#userContent").sortable({ handle: '.close_button', connectWith: '#userContent', placeholder: 'placeholder', forcePlaceholderSize: true, tolerance: 'pointer', revert: true, }); }); </script> <style type="text/css"> .webtitle_paragraphs { width:98%; float:left; border:1px solid #0099CC; margin:5px; } .close_button { display:block; overflow:visible; visibility:visible; height:20px; background:#0099CC; width:100%; } .placeholder { background: #f0f0f0; border:1px dashed #ddd; visibility: visible !important; } .webtitle input { width:98%; font: bold 20px verdana; border:0px; } .paragraph_txt textarea { width:98%; height:auto; border:0px; } </style> </head> <body> <div id="userContent"> <div class="webtitle_paragraphs" id="div4463_text"> <div class="close_button" id="close_4463"><a onclick="removeDiv('div4463_text');"><img src="images/close_button.png" alt="close" width="15" height="15" border="0" align="right"/></a></div> <div class="webtitle_paragraph"> <div class="webtitle"> <input value="Title" name="webtitle4463" type="text" class="text _4463" /> </div> </div> </div> <div class="webtitle_paragraphs" id="div7192_image"> <div class="close_button" id="close_7192"><a onclick="removeDiv('div7192_image');"><img src="images/close_button.png" alt="close" width="15" height="15" border="0" align="right"/></a></div> <div class="webtitle_paragraph"> <div class="paragraph"><img src="https://localhost/web20/user_site_designs/images/noImage.jpeg" id="img7192" class="imageCntrl" onclick="uploadFile(7192)"/> <input type="hidden" name="imgName7192" id="imgName7192" value="" class="image _7192"/> </div> </div> </div> <div class="webtitle_paragraphs" id="div9683_paragraph"> <div class="close_button" id="close_9683"><a onclick="removeDiv('div9683_paragraph');"><img src="images/close_button.png" alt="close" width="15" height="15" border="0" align="right"/></a></div> <div class="webtitle_paragraph"> <div class="paragraph_txt"> <textarea class="paragraph _9683" name="myTextarea9683" id="myTextarea9683">Paragraphp</textarea> </div> </div> </div> </div> Thanks is advance.

  Read the article

• show hidden div tag from another page

  - by neueweblernen

  I'm trying to link to an all-inclusive FAQ page from various pages. The answers are contained in tags, nested within a line item of an unordered list housed by categories. The FAQ page has the following categories: Practical Nurse Exam Online Renewal Practice Hours etc. Under Practical Nurse Exam, there are sub categories, subjects, with questions below in tags that expand onClick. (e.g. Examination Day, Exam Results, etc.) Let's say I'm on a different page called Registration and there's a link to the FAQs for Exam Results. I'm able to link to the page and included the hashtag on the anchor or Exam Results, but it does not expand the subcategory. I've read this thread but it didn't work for me. Please help! The code is below: <script type="text/javascript"> function toggle(Info,pic) { var CState = document.getElementById(Info); CState.style.display = (CState.style.display != 'block') ? 'block' : 'none'; } window.onload = function() { var hash = window.location.hash; // would be "#div1" or something if(hash != "") { var id = hash.substr(1); // get rid of # document.getElementById(id).style.display = 'block'; } } </script> <style type="text/css"> .FAQ { cursor:hand; cursor:pointer; } .FAA { display:none; padding-left:20px; text-indent:-20px; } #FAQlist li { list-style-type: none; } #FAQlist ul { margin-left:0px; } headingOne{ font-family:Arial, Helvetica, sans-serif; color:#66BBFF; font-size:20px; font-weight:bold;} </style> Here's the body (part of it anyway) <headingOne class="FAQ" onClick="toggle('CPNRE', this)">PRACTICAL NURSE EXAM</headingOne> <div class="FAA" id="CPNRE"> <h3><a name="applying">Applying to write the CPNRE</a></h3> <ul id="FAQlist" style="width:450px;"> <li class="FAQ"> <p onclick="toggle('faq1',this)"> <strong>Q: How much does it cost to write the exam?</strong></p> <div class="FAA" id="faq1"> <b>A.</b> In 2013, the cost for the first exam writing is $600.00 which includes the interim license fee. See <a href="https://www.clpnbc.org/What-is-an-LPN/Becoming-an-LPN/Canadian-Practical-Nurse-Registration-Examination/Fees-and-Deadlines.aspx"> fee schedule</a>.</div> <hr /> </li> and here's the body of the other page that contains the link and the same script syntax as the all-inclusive FAQ page. This is just a test, that's not exactly what it will say: <a onclick="toggle('CPNRE', this)" href="file:///S|/Designs/Web stuff/FAQ all inclusive.html#applying"> click here</a>

  Read the article

• Java JNI leak in c++ process.

  - by user662056

  Hi all.. I am beginner in Java. My problem is: I am calling a Java class's method from c++. For this i am using JNI. Everythings works correct, but i have some memory LEAKS in the process of c++ program... So.. i did simple example.. 1) I create a java machine (jint res = JNI_CreateJavaVM(&jvm, (void**)&env, &vm_args);) 2) then i take a pointer on java class (jclass cls = env-FindClass("test_jni")); 3) after that i create a java class object object, by calling the constructor (testJavaObject = env-NewObject(cls, testConstruct);) AT THIS very moment in the process of c++ program is allocated 10 MB of memory 4) Next i delete the class , the object, and the Java Machine .. AT THIS very moment the 10 MB of memory are not free ................. So below i have a few lines of code c++ program void main() { { //Env JNIEnv *env; // java virtual machine JavaVM *jvm; JavaVMOption* options = new JavaVMOption[1]; //class paths options[0].optionString = "-Djava.class.path=C:/Sun/SDK/jdk/lib;D:/jms_test/java_jni_leak;"; // other options JavaVMInitArgs vm_args; vm_args.version = JNI_VERSION_1_6; vm_args.options = options; vm_args.nOptions = 1; vm_args.ignoreUnrecognized = false; // alloc part of memory (for test) before CreateJavaVM char* testMem0 = new char[1000]; for(int i = 0; i < 1000; ++i) testMem0[i] = 'a'; // create java VM jint res = JNI_CreateJavaVM(&jvm, (void**)&env, &vm_args); // alloc part of memory (for test) after CreateJavaVM char* testMem1 = new char[1000]; for(int i = 0; i < 1000; ++i) testMem1[i] = 'b'; //Creating java virtual machine jclass cls = env->FindClass("test_jni"); // Id of a class constructor jmethodID testConstruct = env->GetMethodID(cls, "<init>", "()V"); // The Java Object // Calling the constructor, is allocated 10 MB of memory in c++ process jobject testJavaObject = env->NewObject(cls, testConstruct); // function DeleteLocalRef, // In this very moment memory not free env->DeleteLocalRef(testJavaObject); env->DeleteLocalRef(cls); // 1!!!!!!!!!!!!! res = jvm->DestroyJavaVM(); delete[] testMem0; delete[] testMem1; // In this very moment memory not free. TO /// } int gg = 0; } java class (it just allocs some memory) import java.util.*; public class test_jni { ArrayList<String> testStringList; test_jni() { System.out.println("start constructor"); testStringList = new ArrayList<String>(); for(int i = 0; i < 1000000; ++i) { // ??????? ?????? testStringList.add("TEEEEEEEEEEEEEEEEST"); } } } process memory view, after crating javaVM and java object: testMem0 and testMem1 - test memory, that's allocated by c++. ************** testMem0 ************** JNI_CreateJavaVM ************** testMem1 ************** // create java object jobject testJavaObject = env->NewObject(cls, testConstruct); ************** process memory view, after destroy javaVM and delete ref on java object: testMem0 and testMem1 are deleted to; ************** JNI_CreateJavaVM ************** // create java object jobject testJavaObject = env->NewObject(cls, testConstruct); ************** So testMem0 and testMem1 is deleted, But JavaVM and Java object not.... Sow what i do wrong... and how i can free memory in the c++ process program.

  Read the article

• C++ linked list based tree structure. Sanely copy nodes between lists.

  - by krunk

  edit Clafification: The intention is not to remove the node from the original list. But to create an identical node (data and children wise) to the original and insert that into the new list. In other words, a "move" does not imply a "remove" from the original. endedit The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

  Read the article

• Weird behavior of fork() and execvp() in C

  - by ron

  After some remarks from my previous post , I made the following modifications : int main() { char errorStr[BUFF3]; while (1) { int i , errorFile; char *line = malloc(BUFFER); char *origLine = line; fgets(line, 128, stdin); // get a line from stdin // get complete diagnostics on the given string lineData info = runDiagnostics(line); char command[20]; sscanf(line, "%20s ", command); line = strchr(line, ' '); // here I remove the command from the line , the command is stored in "commmand" above printf("The Command is: %s\n", command); int currentCount = 0; // number of elements in the line int *argumentsCount = &currentCount; // pointer to that // get the elements separated char** arguments = separateLineGetElements(line,argumentsCount); printf("\nOutput after separating the given line from the user\n"); for (i = 0; i < *argumentsCount; i++) { printf("Argument %i is: %s\n", i, arguments[i]); } // here we call a method that would execute the commands pid_t pid ; if (-1 == (pid = fork())) { sprintf(errorStr,"fork: %s\n",strerror(errno)); write(errorFile,errorStr,strlen(errorStr + 1)); perror("fork"); exit(1); } else if (pid == 0) // fork was successful { printf("\nIn son process\n"); // if (execvp(arguments[0],arguments) < 0) // for the moment I ignore this line if (execvp(command,arguments) < 0) // execute the command { perror("execvp"); printf("ERROR: execvp failed\n"); exit(1); } } else // parent { int status = 0; pid = wait(&status); printf("Process %d returned with status %d.", pid, status); } // print each element of the line for (i = 0; i < *argumentsCount; i++) { printf("Argument %i is: %s\n", i, arguments[i]); } // free all the elements from the memory for (i = 0; i < *argumentsCount; i++) { free(arguments[i]); } free(arguments); free(origLine); } return 0; } When I enter in the Console : ls out.txt I get : The Command is: ls execvp: No such file or directory In son process ERROR: execvp failed Process 4047 returned with status 256.Argument 0 is: > Argument 1 is: out.txt So I guess that the son process is active , but from some reason the execvp fails . Why ? Regards REMARK : The ls command is just an example . I need to make this works with any given command . EDIT 1 : User input : ls > qq.out Program output : The Command is: ls Output after separating the given line from the user Argument 0 is: > Argument 1 is: qq.out In son process >: cannot access qq.out: No such file or directory Process 4885 returned with status 512.Argument 0 is: > Argument 1 is: qq.out

  Read the article

• about getadrrinfo() C++?

  - by Isavel

  I'm reading this book called beej's guide to network programming and there's a part in the book were it provide a sample code which illustrate the use of getaddrinfo(); the book state that the code below "will print the IP addresses for whatever host you specify on the command line" - beej's guide to network programming. now I'm curious and want to try it out and run the code, but I guess the code was develop in UNIX environment and I'm using visual studio 2012 windows 7 OS, and most of the headers was not supported so I did a bit of research and find out that I need to include the winsock.h and ws2_32.lib for windows, for it to get working, fortunately everything compiled no errors, but when I run it using the debugger and put in 'www.google.com' as command argument I was disappointed that it did not print any ipaddress, the output that I got from the console is "getaddrinfo: E" what does the letter E mean? Do I need to configure something out of the debugger? Interestingly I left the command argument blank and the output changed to "usage: showip hostname" Any help would be appreciated. #ifdef _WIN32 #endif #include <sys/types.h> #include <winsock2.h> #include <ws2tcpip.h> #include <iostream> using namespace std; #include <stdio.h> #include <string.h> #include <sys/types.h> #include <winsock.h> #pragma comment(lib, "ws2_32.lib") int main(int argc, char *argv[]) { struct addrinfo hints, *res, *p; int status; char ipstr[INET6_ADDRSTRLEN]; if (argc != 2) { fprintf(stderr,"usage: showip hostname\n"); system("PAUSE"); return 1; } memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; // AF_INET or AF_INET6 to force version hints.ai_socktype = SOCK_STREAM; if ((status = getaddrinfo(argv[1], NULL, &hints, &res)) != 0) { fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(status)); system("PAUSE"); return 2; } printf("IP addresses for %s:\n\n", argv[1]); for(p = res;p != NULL; p = p->ai_next) { void *addr; char *ipver; // get the pointer to the address itself, // different fields in IPv4 and IPv6: if (p->ai_family == AF_INET) { // IPv4 struct sockaddr_in *ipv4 = (struct sockaddr_in *)p->ai_addr; addr = &(ipv4->sin_addr); ipver = "IPv4"; } else { // IPv6 struct sockaddr_in6 *ipv6 = (struct sockaddr_in6 *)p->ai_addr; addr = &(ipv6->sin6_addr); ipver = "IPv6"; } // convert the IP to a string and print it: inet_ntop(p->ai_family, addr, ipstr, sizeof ipstr); printf(" %s: %s\n", ipver, ipstr); } freeaddrinfo(res); // free the linked list system("PAUSE"); return 0; }

  Read the article

• jQuery embedding youtube IE issue

  - by webmonkey237

  I have been working on a custom image slider featured here: JQuery $(function(){ $('.cont:gt(0)').hide(); $("#parent").on("mouseenter", ".extraContent div", function(){ var ind = $(this).index(); $("#parent").find(".cont").stop().fadeTo(600,0,function(){ $('#parent').find('.cont').eq(ind).stop().fadeTo(300,1); }); }); $('#parent .extraContent').on('click',function(){ window.location=$(this).find("a").attr("href"); return false; }); }); CSS ?#parent { width:400px; margin:auto} .mainContent { width:430px; height:300px; border:1px solid #000;padding:5px; } .extraContent {overflow:auto; width:450px;} .extraContent div{float:left; width:90px; height:90px; border:1px solid #00F; margin:5px; padding:5px } .extraContent div:hover { border:1px solid #0F0;cursor:pointer } .cont{ position:absolute; } HTML <div id="parent"> <div class="mainContent"> <div class="cont"> Content 1....</div> <div class="cont"> Content 2....</div> <div class="cont">Content 3...<br /><iframe width="267" height="200" src="http://www.youtube.com/embed/6tlQn7iePV4?rel=0" frameborder="0" allowfullscreen></iframe></div> <div class="cont"> Content 4....</div> </div> <div class="extraContent"> <div><p>1 Custom content here <br /> <a href="">Some link</a></p></div> <div><p>2 Custom content here <br /> <a href="">Some link</a></p></div> <div><p>3 Custom content here <br /> <a href="">Some link</a></p></div> <div><p>4 Custom content here <br /> <a href="">Some link</a></p></div> </div> </div>? My problem is if I embed YouTube video straight from the site using there iframe it transitions fine in Chrome but Firefox & IE just display the video straight away and each slide/div appears under the video, is this a known problem and doesn't anyone know a way I can get IE & FF to behave. p.s. because this is going to be in a content management system the only way the user can embed the video is using the default code from youtube. FIDDLE HERE

  Read the article

• How To Run XP Mode in VirtualBox on Windows 7 (sort of)

  - by Matthew Guay

  A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

  Read the article

• How To Run XP Mode in VirtualBox on Windows 7 (sort of)

  - by Matthew Guay

  A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

  Read the article

• The How-To Geek Holiday Gift Guide (Geeky Stuff We Like)

  - by The Geek

  Welcome to the very first How-To Geek Holiday Gift Guide, where we’ve put together a list of our absolute favorites to help you weed through all of the junk out there to pick the perfect gift for anybody. Though really, it’s just a list of the geeky stuff we want. We’ve got a whole range of items on the list, from cheaper gifts that most anybody can afford, to the really expensive stuff that we’re pretty sure nobody is giving us. Stocking Stuffers Here’s a couple of ideas for items that won’t break the bank. LED Keychain Micro-Light   Magcraft 1/8-Inch Rare Earth Cube Magnets Best little LED keychain light around. If they don’t need the penknife of the above item this is the perfect gift. I give them out by the handfuls and nobody ever says anything but good things about them. I’ve got ones that are years old and still running on the same battery.  Price: $8   Geeks cannot resist magnets. Jason bought this pack for his fridge because he was sick of big clunky magnets… these things are amazing. One tiny magnet, smaller than an Altoid mint, can practically hold a clipboard right to the fridge. Amazing. I spend more time playing with them on the counter than I do actually hanging stuff.  Price: $10 Lots of Geeky Mugs   Astronomy Powerful Green Laser Pointer There’s loads of fun, geeky mugs you can find on Amazon or anywhere else—and they are great choices for the geek who loves their coffee. You can get the Caffeine mug pictured here, or go with an Atari one, Canon Lens, or the Aperture mug based on Portal. Your choice. Price: $7   No, it’s not a light saber, but it’s nearly bright enough to be one—you can illuminate low flying clouds at night or just blind some aliens on your day off. All that for an extremely low price. Loads of fun. Price: $15       Geeky TV Shows and Books Sometimes you just want to relax and enjoy a some TV or a good book. Here’s a few choices. The IT Crowd Fourth Season   Doctor Who, Complete Fifth Series Ridiculous, funny show about nerds in the IT department, loved by almost all the geeks here at HTG. Justin even makes this required watching for new hires in his office so they’ll get his jokes. You can pre-order the fourth season, or pick up seasons one, two, or three for even cheaper. Price: $13   It doesn’t get any more nerdy than Eric’s pick, the fifth all-new series of Doctor Who, where the Daleks are hatching a new master plan from the heart of war-torn London. There’s also alien vampires, humanoid reptiles, and a lot more. Price: $52 Battlestar Galactica Complete Series   MAKE: Electronics: Learning Through Discovery Watch the epic fight to save the human race by finding the fabled planet Earth while being hunted by the robotic Cylons. You can grab the entire series on DVD or Blu-ray, or get the seasons individually. This isn’t your average sci-fi TV show. Price: $150 for Blu-ray.   Want to learn the fundamentals of electronics in a fun, hands-on way? The Make:Electronics book helps you build the circuits and learn how it all works—as if you had any more time between all that registry hacking and loading software on your new PC. Price: $21       Geeky Gadgets for the Gadget-Loving Geek Here’s a few of the items on our gadget list, though lets be honest: geeks are going to love almost any gadget, especially shiny new ones. Klipsch Image S4i Premium Noise-Isolating Headset with 3-Button Apple Control   GP2X Caanoo MAME/Console Emulator If you’re a real music geek looking for some serious quality in the headset for your iPhone or iPod, this is the pair that Alex recommends. They aren’t terribly cheap, but you can get the less expensive S3 earphones instead if you prefer. Price: $50-100   Eric says: “As an owner of an older version, I can say the GP2X is one of my favorite gadgets ever. Touted a “Retro Emulation Juggernaut,” GP2X runs Linux and may be the only open source software console available. Sounds too good to be true, but isn’t.” Price: $150 Roku XDS Streaming Player 1080p   Western Digital WD TV Live Plus HD Media Player If you do a lot of streaming over Netflix, Hulu Plus, Amazon’s Video on Demand, Pandora, and others, the Roku box is a great choice to get your content on your TV without paying a lot of money.  It’s also got Wireless-N built in, and it supports full 1080P HD. Price: $99   If you’ve got a home media collection sitting on a hard drive or a network server, the Western Digital box is probably the cheapest way to get that content on your TV, and it even supports Netflix streaming too. It’ll play loads of formats in full HD quality. Price: $99 Fujitsu ScanSnap S300 Color Mobile Scanner   Doxie, the amazing scanner for documents Trevor said: “This wonderful little scanner has become absolutely essential to me. My desk used to just be a gigantic pile of papers that I didn’t need at the moment, but couldn’t throw away ‘just in case.’ Now, every few weeks, I’ll run that paper pile through this and then happily shred the originals!” Price: $300   If you don’t scan quite as often and are looking for a budget scanner you can throw into your bag, or toss into a drawer in your desk, the Doxie scanner is a great alternative that I’ve been using for a while. It’s half the price, and while it’s not as full-featured as the Fujitsu, it might be a better choice for the very casual user. Price: $150       (Expensive) Gadgets Almost Anybody Will Love If you’re not sure that one of the more geeky presents is gonna work, here’s some gadgets that just about anybody is going to love, especially if they don’t have one already. Of course, some of these are a bit on the expensive side—but it’s a wish list, right? Amazon Kindle       The Kindle weighs less than a paperback book, the screen is amazing and easy on the eyes, and get ready for the kicker: the battery lasts at least a month. We aren’t kidding, either—it really lasts that long. If you don’t feel like spending money for books, you can use it to read PDFs, and if you want to get really geeky, you can hack it for custom screensavers. Price: $139 iPod Touch or iPad       You can’t go wrong with either of these presents—the iPod Touch can do almost everything the iPhone can do, including games, apps, and music, and it has the same Retina display as the iPhone, HD video recording, and a front-facing camera so you can use FaceTime. Price: $229+, depending on model. The iPad is a great tablet for playing games, browsing the web, or just using on your coffee table for guests. It’s well worth buying one—but if you’re buying for yourself, keep in mind that the iPad 2 is probably coming out in 3 months. Price: $500+ MacBook Air  The MacBook Air comes in 11” or 13” versions, and it’s an amazing little machine. It’s lightweight, the battery lasts nearly forever, and it resumes from sleep almost instantly. Since it uses an SSD drive instead of a hard drive, you’re barely going to notice any speed problems for general use. So if you’ve got a lot of money to blow, this is a killer gift. Price: $999 and up. Stuck with No Idea for a Present? Gift Cards! Yeah, you’re not going to win any “thoughtful present” awards with these, but you might just give somebody what they really want—the new Angry Birds HD for their iPad, Cut the Rope, or anything else they want. ITunes Gift Card   Amazon.com Gift Card Somebody in your circle getting a new iPod, iPhone, or iPad? You can get them an iTunes gift card, which they can use to buy music, games or apps. Yep, this way you can gift them a copy of Angry Birds if they don’t already have it. Or even Cut the Rope.   No clue what to get somebody on your list? Amazon gift cards let them buy pretty much anything they want, from organic weirdberries to big screen TVs. Yeah, it’s not as thoughtful as getting them a nice present, but look at the bright side: maybe they’ll get you an Amazon gift card and it’ll balance out. That’s the highlights from our lists—got anything else to add? Share your geeky gift ideas in the comments. Latest Features How-To Geek ETC The How-To Geek Holiday Gift Guide (Geeky Stuff We Like) LCD? LED? Plasma? The How-To Geek Guide to HDTV Technology The How-To Geek Guide to Learning Photoshop, Part 8: Filters Improve Digital Photography by Calibrating Your Monitor Our Favorite Tech: What We’re Thankful For at How-To Geek The How-To Geek Guide to Learning Photoshop, Part 7: Design and Typography Happy Snow Bears Theme for Chrome and Iron [Holiday] Download Full Command and Conquer: Tiberian Sun Game for Free Scorched Cometary Planet Wallpaper Quick Fix: Add the RSS Button Back to the Firefox Awesome Bar Dropbox Desktop Client 1.0.0 RC for Windows, Linux, and Mac Released Hang in There Scrat! – Ice Age Wallpaper

  Read the article

< Previous Page | 134 135 136 137 138 139 140 141 142 143 144  | Next Page >