Search Results

Search found 11358 results on 455 pages for 'utf 16'.

Page 138/455 | < Previous Page | 134 135 136 137 138 139 140 141 142 143 144 145  | Next Page >

  • sql to xml using linq - nested collections

    - by nelsonwebs
    I have a table of data that looks something like this. name, hour, price1, price2, price3, price4, price5 fred, 3, 12.5, 13.5, 14, 15, 16 dave, 6, 8, 12, 18, 20.2, 25 fred, 6, 10, 11, 14, 15, 19.7 This table needs to be output to an xml file that looks like this. <timeCost> <person name="fred"> <time hour="5"> <cost price="12.5" /> <cost price="13.5" /> <cost price="14" /> <cost price="15" /> <cost price="16" /> </time> <time hour="6"> <cost price="10" /> <cost price="11" /> <cost price="14" /> <cost price="15" /> <cost price="19.7" /> </time> </person> <person name="dave"> <time hour="6"> <cost price="8" /> <cost price="12" /> <cost price="18" /> <cost price="20.2" /> <cost price="25" /> </time> </person> </timeCost> I have a linq query to get the data from SQL something like this. // initialize data context var people = from p in dc.people orderby p.name, p.hour select p; However, I'm having trouble writing the xml out using linq (csharp). Specifically, the problem is I don't know how to deal with having multiple time nodes under each name node (nested loops/collections). How can this be done? This is a sql 08 ent db if it matters to anyone.

    Read the article

  • Asp.Net Export to Excel - Japanese Characters

    - by Kalyan
    I am currently using Visual Studio 2008 for my ASP .NET application. I am trying to Export some reports with Japanese Characters to Excel via the Response object. When I try to Export, all the Japanese characters looks garbled. It works fine with Chinese Characters. Here is what I tried: I tried Installed Japanese Language Pack / Encoding to UTF-8 / UTF-7 / Shift-JIS / Globalization (Web.Config) .. but no luck. Any Ideas how this can be fixed ? Thanks !! string attachment = "attachment; filename=PerksPlusReport.xls"; //Response.Clear(); Response.ClearContent(); Response.ClearHeaders(); Response.AddHeader("content-disposition", attachment); //Response.Charset = "UTF-8"; //Response.Charset = "UTF-7"; //Response.Charset = "Shift_JIS"; Response.ContentType = "application/vnd.ms-excel"; StringWriter sw = new StringWriter(); HtmlTextWriter htw = new HtmlTextWriter(sw); // Create a form to contain the grid HtmlForm frm = new HtmlForm(); ReportGridView.Parent.Controls.Add(frm); frm.Attributes["runat"] = "server"; GridView GridView2 = new GridView(); ReportView reportDetails = GetReportDetails(); GridView2.DataSource = GetReportResults(this.ReportId.Value, reportDetails.Sql); GridView2.DataBind(); PrepareGridViewForExport(GridView2); frm.Controls.Add(GridView2); frm.RenderControl(htw); string fileContents = sw.ToString(); int startSpot = fileContents.IndexOf("<table"); fileContents = fileContents.Substring(startSpot); int endSpot = fileContents.IndexOf("</table>"); fileContents = fileContents.Substring(0, endSpot + 8); try { // Replace all &lt; and &gt; with < and > fileContents = fileContents.Replace("&lt;", "<"); fileContents = fileContents.Replace("&gt;", ">"); fileContents = fileContents.Replace("€", "&euro;"); string RegularExpression = @"<a[^>]*>([^<]*)</a>"; Regex regex = new Regex(RegularExpression); //If match found .. uses the delegate function to replace the whole content with the filtered values if (regex.IsMatch(fileContents)) { regex.Replace(fileContents, delegate (Match m){return fileContents.Replace(m.Captures[0].Value, m.Groups[1].Value);}); } } catch (Exception ex2) { Response.Write(ex2.ToString()); } Response.Write(fileContents); Response.End();

    Read the article

  • linux build iso error

    - by Neil
    i played with linux customization and when i want to build the iso back i get this error: $ mkisofs -r -o rhel.iso -b isolinux/isolinux.bin -c isolinux/boot.cat ./ INFO: UTF-8 character encoding detected by locale settings. Assuming UTF-8 encoded filenames on source filesystem, use -input-charset to override. Unknown file type (unallocated) ./.. - ignoring and continuing. Using RELEA000.HTM;1 for /RELEASE-NOTES-pt_BR.html (RELEASE-NOTES-U1-pt_BR.html) Size of boot image is 20 sectors -> mkisofs: Error - boot image './isolinux/isolinux.bin' has not an allowable size. i didnt change the isolinux.bin why i ahve this error?

    Read the article

  • Return a number between 0 and 4

    - by munchine
    How do I return a number between 0 and 4, depending the input number? For example if I pass it number 23 it will return 3. The number set should look like 0 5 10 15 20 .. 1 6 11 16 21 .. 2 7 12 17 22 .. 3 8 13 18 23 .. 4 9 14 19 24 What's the math for this?

    Read the article

  • SQL for Opening Hours

    - by mouthpiec
    Hi, In my shops database I need to have the opening hours. Do you have an idea how i can implement this in my dB? The opening hours are from Monday to Sunday, each day can have 2 opening windows (ex 09:00-12:00, 16:00-19:00)

    Read the article

  • Tournament bracket

    - by Luke
    Not sure of the best way to go about this? I want to create a tournament bracket of 2,4,8,16,32, etc teams. The winner of the first two will play winner of the next 2 etc. All the way until there is a winner. Like this Can anyone help me?

    Read the article

  • WatiN, VBScript

    - by little_devil
    I am using WatiN for my web tests. In one of my web pages, I have a VBScript function which opens a dialogbox. I am unable to access it using WatiN. I tried using WatiNTestRecorder; it was unsuccessful. I tried this also: http://blogs.dovetailsoftware.com/blogs/kmiller/archive/2008/07/16/scenario-testing-with-watin.aspx, unsuccessful again.

    Read the article

  • c program output

    - by sandy101
    HELLO , I am trying some program and confused with the output of the program #include #define a(x) (x*x) int main() { int i=3,j; j=a(i+1); printf("%d",j); return 0 ; } i want to know why the program is not giving the output 16(as instead to that i an getting the output 7 for the above program )

    Read the article

  • quartz cron expression help (daily trigger)

    - by djmlog103
    Hi, i want to run a cron trigger every 5th day starting from the 16th of every month. so it should execute on every: 16th, 21st, 26th, 31st, 5th, 10th, 15th, 20th and so on i tried "0 0 1 16/5 * ?" but this gets execute on 16th, 21st, 26th, 31st, 16th, 21st.... It skips anything between 1st and 15th. Please help. thanks

    Read the article

  • What's wrong with my custom .desktop xsession?

    - by Noam Gagliardi
    I want to create a custom Xmonad session that loads an .xsession script in my home folder. This is the original file I copied. This one works: [Desktop Entry] Encoding=UTF-8 Name=XMonad Comment=Lightweight tiling window manager Exec=xmonad Icon=xmonad.png Type=XSession This is my modified file, xmonad-custom.desktop. When I logout, then login choosing this "xmonad-custom", the screen just flashes and sends me back to the ubuntu login screen (as if it briefly logs in and out of the session): [Desktop Entry] Encoding=UTF-8 Name=XMonad Custom Comment=Lightweight tiling window manager Exec=/home/{username}/.xsession Icon=xmonad.png Type=XSession X-Ubuntu-Gettext-Domain=gdm I also tried without the last line. This is my ~/.xsession file, in case there's an error with this script: #!/bin/env bash xrdb -merge .Xresources trayer --edge top --align right --SetDockType true --SetPartialStrut \ true --expand true --width 15 --height 12 --transparent true --tint 0x000000 & dropbox start & exec xmonad

    Read the article

  • PHP Kohana CentOS 5

    - by Undefined
    Trying to deploy a Kohana based project in CentOS 5. Installed PHP 5.3.1 but still getting the following error. Warning: preg_match() [function.preg-match]: Compilation failed: this version of PCRE is not compiled with PCRE_UTF8 support at offset 0 in /usr/local/apache2/htdocs/icarus/system/core/utf8.php on line 30 Fatal error: PCRE has not been compiled with UTF-8 support. See PCRE Pattern Modifiers for more information. This application cannot be run without UTF-8 support. in /usr/local/apache2/htdocs/icarus/system/core/utf8.php on line 38 Trying since last 2 days, i upgraded my PHP from 5.1 to 5.3 but still getting the same error.The problem as per me is that the PCRE module of PHP in phpinfo() says is of sep 2004. Below is the actual line PCRE Library Version 5.0 13-Sep-2004 Can anyone tell me how to upgrade it or wats the solution to the problem. Thanks.

    Read the article

  • AES decryption in Java - IvParameterSpec to big

    - by user1277269
    Im going to decrypt a plaintext with two keys. As you see in the picture were have one encrypted file wich contains KEY1(128 bytes),KEYIV(128 bytes),key2(128bytes) wich is not used in this case then we have the ciphertext. The error I get here is "Exception in thread "main" java.security.InvalidAlgorithmParameterException: Wrong IV length: must be 16 bytes long. but it is 64 bytes." Picture: http://i264.photobucket.com/albums/ii200/XeniuM05/bg_zps0a523659.png public class AES { public static void main(String[] args) throws Exception { byte[] encKey1 = new byte[128]; byte[] EncIV = new byte[256]; byte[] UnEncIV = new byte[128]; byte[] unCrypKey = new byte[128]; byte[] unCrypText = new byte[1424]; File f = new File("C://ftp//ciphertext.enc"); FileInputStream fis = new FileInputStream(F); byte[] EncText = new byte[(int) f.length()]; fis.read(encKey1); fis.read(EncIV); fis.read(EncText); EncIV = Arrays.copyOfRange(EncIV, 128, 256); EncText = Arrays.copyOfRange(EncText, 384, EncText.length); System.out.println(EncText.length); KeyStore ks = KeyStore.getInstance(KeyStore.getDefaultType()); char[] password = "lab1StorePass".toCharArray(); java.io.FileInputStream fos = new java.io.FileInputStream( "C://ftp//lab1Store"); ks.load(fos, password); char[] passwordkey1 = "lab1KeyPass".toCharArray(); PrivateKey Lab1EncKey = (PrivateKey) ks.getKey("lab1EncKeys", passwordkey1); Cipher rsaDec = Cipher.getInstance("RSA"); // set cipher to RSA decryption rsaDec.init(Cipher.DECRYPT_MODE, Lab1EncKey); // initalize cipher ti lab1key unCrypKey = rsaDec.doFinal(encKey1); // Decryps first key UnEncIV = rsaDec.doFinal(EncIV); //decryps encive byte array to undecrypted bytearray---- OBS! Error this is 64 BYTES big, we want 16? System.out.println("lab1key "+ unCrypKey +" IV " + UnEncIV); //-------CIPHERTEXT decryption--------- Cipher AESDec = Cipher.getInstance("AES/CBC/PKCS5Padding"); //---------convert decrypted bytearrays to acctual keys SecretKeySpec unCrypKey1 = new SecretKeySpec(unCrypKey, "AES"); IvParameterSpec ivSpec = new IvParameterSpec(UnEncIV); AESDec.init(Cipher.DECRYPT_MODE, unCrypKey1, ivSpec ); unCrypText = AESDec.doFinal(EncText); // Convert decrypted cipher bytearray to string String deCryptedString = new String(unCrypKey); System.out.println(deCryptedString); }

    Read the article

  • chef-solo example

    - by intern
    We are learning chef-solo and need a good example for better understanding.. Have searched a lot on net but the ideas are very confusing. can anyone suggest some examples.. and also how to run them.. We have installed chef-0.8.16 gem but couldnt figure out how to work with it.. We are using windows platform..Its urgent..

    Read the article

  • Plus signs appearing in Google searches

    - by emddudley
    Ever since Google implemented their new look at the beginning of May, I have been having trouble with their search engine changing all of the spaces in my query to plus signs. This behavior occurs when I use the search box in both Firefox and Internet Explorer. For example, if I search for google search plus signs I am taken to the following URL, where google+search+plus+signs is in the search box. http://www.google.com/search?q=google+search+plus+signs&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a However if I perform the search from google.com, I get taken to a different URL with google search plus signs as I'd expect: http://www.google.com/#hl=en&source=hp&q=google+search+plus+signs&aq=f&aqi=g1&aql=&oq=&gs_rfai=&fp=d2a3ca21987adb1 Do I need to update my browsers or something?

    Read the article

  • How do I insert data from a Python dictionary to MySQL?

    - by NJTechie
    I manipulated some data from MySQL and the resulting dictionary "data" (print data) displays something like this : {'1': ['1', 'K', abc, 'xyz', None, None, datetime.date(2009, 6, 18)], '2': ['2', 'K', efg, 'xyz', None, None, None, None], '3': ['3', 'K', ijk, 'xyz', None, None, None, datetime.date(2010, 2, 5, 16, 31, 2)]} How do I create a table and insert these values in a MySQL table? In other words, how do I dump them to MySQL or CSV? Not sure how to deal with datetime.date and None values. Any help is appreciated.

    Read the article

  • Am I compiling with x64 JDK?

    - by Mike
    Hi, Do I have the 64 bit of JDK installed on my machine? My java -version says: C:\Documents and Settings\Administratorjava -version java version "1.6.0_20" Java(TM) SE Runtime Environment (build 1.6.0_20-b02) Java HotSpot(TM) 64-Bit Server VM (build 16.3-b01, mixed mode) Should I expect a performance improvement in using a 64 bit compiler versus a 32 bit one? Thanks, Mike

    Read the article

  • Performance Optimization for Matrix Rotation

    - by Summer_More_More_Tea
    Hello everyone: I'm now trapped by a performance optimization lab in the book "Computer System from a Programmer's Perspective" described as following: In a N*N matrix M, where N is multiple of 32, the rotate operation can be represented as: Transpose: interchange elements M(i,j) and M(j,i) Exchange rows: Row i is exchanged with row N-1-i A example for matrix rotation(N is 3 instead of 32 for simplicity): ------- ------- |1|2|3| |3|6|9| ------- ------- |4|5|6| after rotate is |2|5|8| ------- ------- |7|8|9| |1|4|7| ------- ------- A naive implementation is: #define RIDX(i,j,n) ((i)*(n)+(j)) void naive_rotate(int dim, pixel *src, pixel *dst) { int i, j; for (i = 0; i < dim; i++) for (j = 0; j < dim; j++) dst[RIDX(dim-1-j, i, dim)] = src[RIDX(i, j, dim)]; } I come up with an idea by inner-loop-unroll. The result is: Code Version Speed Up original 1x unrolled by 2 1.33x unrolled by 4 1.33x unrolled by 8 1.55x unrolled by 16 1.67x unrolled by 32 1.61x I also get a code snippet from pastebin.com that seems can solve this problem: void rotate(int dim, pixel *src, pixel *dst) { int stride = 32; int count = dim >> 5; src += dim - 1; int a1 = count; do { int a2 = dim; do { int a3 = stride; do { *dst++ = *src; src += dim; } while(--a3); src -= dim * stride + 1; dst += dim - stride; } while(--a2); src += dim * (stride + 1); dst -= dim * dim - stride; } while(--a1); } After carefully read the code, I think main idea of this solution is treat 32 rows as a data zone, and perform the rotating operation respectively. Speed up of this version is 1.85x, overwhelming all the loop-unroll version. Here are the questions: In the inner-loop-unroll version, why does increment slow down if the unrolling factor increase, especially change the unrolling factor from 8 to 16, which does not effect the same when switch from 4 to 8? Does the result have some relationship with depth of the CPU pipeline? If the answer is yes, could the degrade of increment reflect pipeline length? What is the probable reason for the optimization of data-zone version? It seems that there is no too much essential difference from the original naive version. EDIT: My test environment is Intel Centrino Duo processor and the verion of gcc is 4.4 Any advice will be highly appreciated! Kind regards!

    Read the article

  • how to store data in ram in verilog

    - by anum
    i am having a bit stream of 128 bits @ each posedge of clk,i.e.total 10 bit streams each of length 128 bits. i want to divide the 128 bit stream into 8, 8 bits n hve to store them in a ram / memory of width 8 bits. i did it by assigning 8, 8 bits to wires of size 8 bit.in this way there are 16 wires. and i am using dual port ram...wen i cal module of memory in stimulus.i don know how to give input....as i am hving 16 different wires naming from k1 to k16. **codeeee** // this is stimulus file module final_stim; reg [7:0] in,in_data; reg clk,rst_n,rd,wr,rd_data,wr_data; wire [7:0] out,out_wr, ouut; wire[7:0] d; integer i; //wire[7:0] xor_out; reg kld,f; reg [127:0]key; wire [127:0] key_expand; wire [7:0]out_data; reg [7:0] k; //wire [7:0] k1,k2,k3,k4,k5,k6,k7,k8,k9,k10,k11,k12,k13,k14,k15,k16; wire [7:0] out_data1; **//key_expand is da output which is giving 10 streams of size 128 bits.** assign k1=key_expand[127:120]; assign k2=key_expand[119:112]; assign k3=key_expand[111:104]; assign k4=key_expand[103:96]; assign k5=key_expand[95:88]; assign k6=key_expand[87:80]; assign k7=key_expand[79:72]; assign k8=key_expand[71:64]; assign k9=key_expand[63:56]; assign k10=key_expand[55:48]; assign k11=key_expand[47:40]; assign k12=key_expand[39:32]; assign k13=key_expand[31:24]; assign k14=key_expand[23:16]; assign k15=key_expand[15:8]; assign k16=key_expand[7:0]; **// then the module of memory is instanciated. //here k1 is sent as input.but i don know how to save the other values of k. //i tried to use for loop but it dint help** memory m1(clk,rst_n,rd, wr,k1,out_data1); aes_sbox b(out,d); initial begin clk=1'b1; rst_n=1'b0; #20 rst_n = 1; //rd=1'b1; wr_data=1'b1; in=8'hd4; #20 //rst_n=1'b1; in=8'h27; rd_data=1'b0; wr_data=1'b1; #20 in=8'h11; rd_data=1'b0; wr_data=1'b1; #20 in=8'hae; rd_data=1'b0; wr_data=1'b1; #20 in=8'he0; rd_data=1'b0; wr_data=1'b1; #20 in=8'hbf; rd_data=1'b0; wr_data=1'b1; #20 in=8'h98; rd_data=1'b0; wr_data=1'b1; #20 in=8'hf1; rd_data=1'b0; wr_data=1'b1; #20 in=8'hb8; rd_data=1'b0; wr_data=1'b1; #20 in=8'hb4; rd_data=1'b0; wr_data=1'b1; #20 in=8'h5d; rd_data=1'b0; wr_data=1'b1; #20 in=8'he5; rd_data=1'b0; wr_data=1'b1; #20 in=8'h1e; rd_data=1'b0; wr_data=1'b1; #20 in=8'h41; rd_data=1'b0; wr_data=1'b1; #20 in=8'h52; rd_data=1'b0; wr_data=1'b1; #20 in=8'h30; rd_data=1'b0; wr_data=1'b1; #20 wr_data=1'b0; #380 rd_data=1'b1; #320 rd_data = 1'b0; /////////////// #10 kld = 1'b1; key=128'h 2b7e151628aed2a6abf7158809cf4f3c; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b0; #10 wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 kld = 1'b0; key = 128'h 2b7e151628aed2a6abf7158809cf4f3c; wr = 1'b1; rd = 1'b1; #20 wr = 1'b0; #20 rd = 1'b1; #4880 f=1'b1; ///////////////////////////////////////////////// // out_data[i] end /*always@(*) begin while(i) mem[i]^mem1[i] ; i<=16; break; end*/ always #10 clk=~clk; always@(posedge clk) begin //$monitor($time," out_wr=%h,out_rd=%h\n ",out_wr,out); #10000 $stop; end endmodule

    Read the article

  • Floating point mantissa bias

    - by user69514
    Does anybody know how to go out solving this problem? * a = 1.0 × 2^9 * b = -1.0 × 2^9 * c = 1.0 × 2^1 Using the floating-point (the representation uses a 14-bit format, 5 bits for the exponent with a bias of 16, a normalized mantissa of 8 bits, and a single sign bit for the number), perform the following two calculations, paying close attention to the order of operations. * b + (a + c) = ? * (b + a) + c = ?

    Read the article

  • Issue with XSL Criteria

    - by Rachel
    I am using the below piece of XSL to select the id of the text nodes whose content has a given index. This index value in input will be relative to a spcified node whose id value is known. The criteria to select the text node is, The text node content should contain a index say 'i' relative to node say 'n' whose id value i know. 'i' and 'id of n' is got as index and nodeName from the input param as seen in the xsl. Node 'd1e5' has the text content whose index ranges from 1 to 33. When i give an index value greater than 33 i want the below criteria to fail but it does not, [sum((preceding::text(), .)[normalize-space()][. >> //*[@id=$nodeName]]/string-length(.)) ge $index] Input xml: <?xml version="1.0" encoding="UTF-8"?> <html xmlns="http://www.w3.org/1999/xhtml" id="d1e1"> <head id="d1e3"> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title id="d1e5">Every document must have a title</title> </head> <body id="d1e9"> <h1 id="d1e11" align="center">Very Important Heading</h1> <p id="d1e13">Since this is just a sample, I won't put much text here.</p> </body> </html> XSL code used: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsd="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xsd" version="2.0"> <xsl:param name="insert-file" as="node()+"> <insert-data><data index="1" nodeName="d1e5"></data><data index="34" nodeName="d1e5"></data></insert-data> </xsl:param> <xsl:param name="nodeName" as="xsd:string" /> <xsl:variable name="main-root" as="document-node()" select="/"/> <xsl:variable name="insert-data" as="element(data)*"> <xsl:for-each select="$insert-file/insert-data/data"> <xsl:sort select="xsd:integer(@index)"/> <xsl:variable name="index" select="xsd:integer(@index)" /> <xsl:variable name="nodeName" select="@nodeName" /> <data text-id="{generate-id($main-root/descendant::text()[sum((preceding::text(), .)[normalize-space()][. >> //*[@id=$nodeName]]/string-length(.)) ge $index][1])}"> </data> </xsl:for-each> </xsl:variable> <xsl:template match="/"> <Output> <xsl:copy-of select="$insert-data" /> </Output> </xsl:template> </xsl:stylesheet> Actual output: <?xml version="1.0" encoding="UTF-8"?> <Output> <data text-id="d1t8"/> <data text-id="d1t14"/> </Output> Expected output: <?xml version="1.0" encoding="UTF-8"?> <Output> <data text-id="d1t8"/> </Output> This solution works fine if index lies between 1 and 33. Any index value greater that 33 causes incorrect text nodes to get selected. I could not understand why the text node 'd1t14' is getting selected. Please share your thoughts.

    Read the article

< Previous Page | 134 135 136 137 138 139 140 141 142 143 144 145  | Next Page >