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  • Adaptive Case Management Modeling with CMMN by Jessica Ray

    - by JuergenKress
    A new version of Oracle BPM Suite 11.1.1.7 with Adaptive Case Management (ACM) is now available, so what will that mean for requirements gathering? BPM project requirements can be documented using Business Process Model and Notation (BPMN 2.0). For ACM, there is a new notation in the works. It is called Case Management Model and Notation (CMMN). For now, this notation isn’t included as a modeling tool in the new version of Oracle BPM Suite 11.1.1.7 with ACM, but it is possible that a modeling tool could be included in a future release. What is CMMN? CMMN is a standard intended to capture the common elements that Case Management Products use, the same way that BPMN is a standard for BPM products (such as Oracle BPM). CMMN is created by the Object Management Group (OMG) and is still in the beta version. In April 2014, OMG released the second beta version the CMMN 1.0, and the most recent version is available here. CMMN captures some of the elements that are commonly used when talking about ACM such as Cases, Milestones, and Tasks. It also introduces some elements that you may not automatically hear when talking about ACM such as Stages, Events, and Decorators. Here is a quick summary at a few (but not all) of the elements of CMMN taken from the CMMN spec. A Few CMMN Elements Read the complete article here SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Facebook Wiki Technorati Tags: Jessica Ray,Avio,Adaptive Case Management,ACM,CMMN,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • C# setting case constant expressions, do they have to follow a specific order?

    - by Umeed
    Say I'm making a simple program, and the user is in the menu. And the menu options are 1 3 5 7 (i wouldn't actually do that but lets just go with it). and I want to make my switch statement using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace DecisionMaking2 { class Program { static void Main(string[] args) { Console.WriteLine("Please choose an option: "); string SelectedOpt = Console.ReadLine(); double Selection = Convert.ToDouble(SelectedOpt); double MenuOption = (Selection); switch (MenuOption) { case 1: Console.WriteLine("Selected option #1"); break; case 2: Console.WriteLine("Selected option #3"); break; case 3: Console.WriteLine("Selected option #5"); break; case 4: Console.WriteLine("Selected option #7"); break; default: Console.WriteLine("Please choose from the options List!"); break; } } } } would that work? or would I have to name each case constant expression the option number I am using? I went to the microsoft website and I didn't quite pick up on anything i was looking for. . Also while I have your attention, how would I make it so the user chooses from either option and because I don't know which option the user will select " double MenuOption = " could be anything, whatever the user inputs right? so would what I have even work? I am doing this all by hand, and don't get much lab time to work on this as I have tons of other courses to work on and then a boring job to go to, and my PC at home has a restarting issue lol. soo any and all help is greatly appreciated. p.s the computer I'm on right now posting this, doesn't have any compilers, coding programs, and it's not mine just to get that out of the way. Thanks again!

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  • Adaptive Case Management OTN WebCast with Danilo Schmiedel

    - by JuergenKress
    Oracle ACE Director Danilo Schmiedel, SOA/BPM solution architect with Opitz Consulting in Germany, talks about Adaptive Case Management, Predictive Analytics, and Process Mining. Watch the video here. To download the Adaptive Case Management post mentioned in this interview, please visit the blog post. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Facebook Wiki Technorati Tags: ACM,Adaptive Case Management,Danilo Schmiedel,Opitz,OTN,SOA Community,Oracle SOA,Oracle BPM,Community,OPN,Jürgen Kress

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  • Oracle Database Machine: customer case at OOW2010

    - by rene.kundersma
    I proudly announce that on Openworld 2010, together with TUI I will be co-presenting the customer case on their Database Machine implementation. Our session number is S314935. The sesison will be about the business case, the choices made for the setup, how we did the migration to v1, the migration to v2. Also how we implemented backup/restore and disaster recovery solutions. It will be a very interesting case for everyone interested in customer implementations of the DBM ! Hope to see you there Rene Kundersma Technical Architect Oracle Technology Services

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  • When is a Use Case layer needed?

    - by Meta-Knight
    In his blog post The Clean Architecture Uncle Bob suggests a 4-layer architecture. I understand the separation between business rules, interfaces and infrastructure, but I wonder if/when it's necessary to have separate layers for domain objects and use cases. What added value will it bring, compared to just having the uses cases as "domain services" in the domain layer? The only useful info I've found on the web about a use case layer is an article by Martin Fowler, who seems to contradict Uncle Bob about its necessity: At some point I may run into the problems, and then I'll make a Use Case Controller - but only then. And even when I do that I rarely consider the Use Case Controllers to occupy a separate layer in the system architecture. Edit: I stumbled upon a video of Uncle Bob's Architecture: The Lost Years keynote, in which he explains this architecture in depth. Very informative.

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  • Can I use this power supply + case combination without causing problems?

    - by evan
    I am putting together a computer with a Antec P180 case and a Thermaltake TR2 RX 650 W power supply. The problem is that the Antec P180 case has a separate compartment for the power supply. With an opening for the on/off switch + ac connector to one side, a wall with a small hole for cables to route through on top, a wall on the bottom, and on the other side a fan which pushes air from the hard drive compartment to the power supply compartment. I think the design of the case assumes the power supplies fan is on the side next to the on/off switch, but the fan on the power supply I have is on top, which makes me worry about overheating the power supply. There is about half an inch between the top of the power supply and the wall and the other fan should keep air flowing to push out the air that the power supply pushes upwards. Do you think this setup should work, or should I go get another power supply? Thanks!! PS: This computer will be running an Ubuntu server, so it will always be on, but the rest of the components shouldn't be generating as much heat as they would on say a gaming machine.

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  • Generate a merge statement from table structure

    - by Nigel Rivett
    This code generates a merge statement joining on he natural key and checking all other columns to see if they have changed. The full version deals with type 2 processing and an audit trail but this version is useful. Just the insert or update part is handy too. Change the table at the top (spt_values in master in the version) and the join columns for the merge in @nk. The output generated is at the top and the code to run to generate it below. Output merge spt_values a using spt_values b on a.name = b.name and a.number = b.number and a.type = b.type when matched and (1=0 or (a.low b.low) or (a.low is null and b.low is not null) or (a.low is not null and b.low is null) or (a.high b.high) or (a.high is null and b.high is not null) or (a.high is not null and b.high is null) or (a.status b.status) or (a.status is null and b.status is not null) or (a.status is not null and b.status is null) ) then update set low = b.low , high = b.high , status = b.status when not matched by target then insert ( name , number , type , low , high , status ) values ( b.name , b.number , b.type , b.low , b.high , b.status ); Generator set nocount on declare @t varchar(128) = 'spt_values' declare @i int = 0 -- this is the natural key on the table used for the merge statement join declare @nk table (ColName varchar(128)) insert @nk select 'Number' insert @nk select 'Name' insert @nk select 'Type' declare @cols table (seq int, nkseq int, type int, colname varchar(128)) ;with cte as ( select ordinal_position, type = case when columnproperty(object_id(@t), COLUMN_NAME,'IsIdentity') = 1 then 3 when nk.ColName is not null then 1 else 0 end, COLUMN_NAME from information_schema.columns c left join @nk nk on c.column_name = nk.ColName where table_name = @t ) insert @cols (seq, nkseq, type, colname) select ordinal_position, row_number() over (partition by type order by ordinal_position) , type, COLUMN_NAME from cte declare @result table (i int, j int, k int, data varchar(500)) select @i = @i + 1 insert @result (i, data) select @i, 'merge ' + @t + ' a' select @i = @i + 1 insert @result (i, data) select @i, ' using cte b' select @i = @i + 1 insert @result (i, j, data) select @i, nkseq, ' ' + case when nkseq = 1 then 'on' else 'and' end + ' a.' + ColName + ' = b.' + ColName from @cols where type = 1 select @i = @i + 1 insert @result (i, data) select @i, ' when matched and (1=0' select @i = @i + 1 insert @result (i, j, k, data) select @i, seq, 1, ' or (a.' + ColName + ' b.' + ColName + ')' + ' or (a.' + ColName + ' is null and b.' + ColName + ' is not null)' + ' or (a.' + ColName + ' is not null and b.' + ColName + ' is null)' from @cols where type 1 select @i = @i + 1 insert @result (i, data) select @i, ' )' select @i = @i + 1 insert @result (i, data) select @i, ' then update set' select @i = @i + 1 insert @result (i, j, data) select @i, nkseq, ' ' + case when nkseq = 1 then ' ' else ', ' end + colname + ' = b.' + colname from @cols where type = 0 select @i = @i + 1 insert @result (i, data) select @i, ' when not matched by target then insert' select @i = @i + 1 insert @result (i, data) select @i, ' (' select @i = @i + 1 insert @result (i, j, data) select @i, seq, ' ' + case when seq = 1 then ' ' else ', ' end + colname from @cols where type 3 select @i = @i + 1 insert @result (i, data) select @i, ' )' select @i = @i + 1 insert @result (i, data) select @i, ' values' select @i = @i + 1 insert @result (i, data) select @i, ' (' select @i = @i + 1 insert @result (i, j, data) select @i, seq, ' ' + case when seq = 1 then ' ' else ', ' end + 'b.' + colname from @cols where type 3 select @i = @i + 1 insert @result (i, data) select @i, ' );' select data from @result order by i,j,k,data

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  • Bind Variable and SQL error during statement preparation

    - by Abhishek Dwivedi
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}  I was getting the following exception at run-time. JBO-27122: SQL error during statement preparation. Statement: SELECT AxEO.A_ID, AxEO.B_ID, AxEO.C_ID, ByEO.A_ID, ByEO.B_ID, ByEO.C_ID, Cz.A_ID, Cz.B_ID, Cz.C_ID FROM ABC_x AxEO, ABC_y ByEO, ABC_z CzEO WHERE AxEO.A_ID = ByEO.A_ID AND  CzEO.A_ID = :Bind_PId I copied and pasted the query on SQL worksheet, replaced :Bind_PId with a valid id, and executed the query. The query worked alright, implying the query was alright. I tried to connect to different DBs but the issue persisted, meaning it was not a DB issue either. Finally, the root cause was found to be in the concerned VO; one of the bind variables (say Bind_TId) was marked "Required". De-selecting the Required check-box resolved the issue. In retrospect, the issue looks to be rather straight-forward. However, the error message is not very helpful, if not misleading. Besides, it's counter-intuitive to think that a bind variable which is not being used in a query can cause error while statement preparation. The other bind variable - Bind_TId - was being used in other view criteria, not the view criteria involved in the given query. Still, it was required.

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  • Execute TSQL statement with ExecuteStoreQuery in entity framework 4.0

    - by Jalpesh P. Vadgama
    I was playing with entity framework in recent days and I was searching something that how we can execute TSQL statement in entity framework. And I have found one great way to do that with entity framework ‘ExecuteStoreQuery’ method. It’s executes a TSQL statement against data source given enity framework context and returns strongly typed result. You can find more information about ExcuteStoreQuery from following link. http://msdn.microsoft.com/en-us/library/dd487208.aspx So let’s examine how it works. So Let’s first create a table against which we are going to execute TSQL statement. So I have added a SQL Express database as following. Now once we are done with adding a database let’s add a table called Client like following. Here you can see above Client table is very simple. There are only two fields ClientId and ClientName where ClientId is primary key and ClientName is field where we are going to store client name. Now it’s time to add some data to the table. So I have added some test data like following. Now it’s time to add entity framework model class. So right click project->Add new item and select ADO.NET entity model as following. After clicking on add button a wizard will start it will ask whether we need to create model classes from database or not but we already have our client table ready so I have selected generate from database as following. Once you process further in wizard it will be presented a screen where we can select the our table like following. Now once you click finish it will create model classes with for us. Now we need a gridview control where we need to display those data. So in Default.aspx page I have added a grid control like following. <%@ Page Title="Home Page" Language="C#" MasterPageFile="~/Site.master" AutoEventWireup="true" CodeBehind="Default.aspx.cs" Inherits="EntityFramework._Default" %> <asp:Content ID="HeaderContent" runat="server" ContentPlaceHolderID="HeadContent"> </asp:Content> <asp:Content ID="BodyContent" runat="server" ContentPlaceHolderID="MainContent"> <h2> Welcome to ASP.NET! </h2> <p> To learn more about ASP.NET visit <a href="http://www.asp.net" title="ASP.NET Website">www.asp.net</a>. </p> <p> You can also find <a href="http://go.microsoft.com/fwlink/?LinkID=152368&amp;clcid=0x409" title="MSDN ASP.NET Docs">documentation on ASP.NET at MSDN</a>. <asp:GridView ID="grdClient" runat="server"> </asp:GridView> </p> </asp:Content> Now once we are done with adding Gridview its time to write code for server side. So I have written following code in Page_load event of default.aspx page. protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { using (var context = new EntityFramework.TestEntities()) { ObjectResult<Client> result = context.ExecuteStoreQuery<Client>("Select * from Client"); grdClient.DataSource = result; grdClient.DataBind(); } } } Here in the above code you can see that I have written create a object of our entity model and then with the help of the ExecuteStoreQuery method I have execute a simple select TSQL statement which will return a object result. I have bind that object result with gridview to display data. So now we are done with coding.So let’s run application in browser. Following is output as expected. That’s it. Hope you like it. Stay tuned for more..Till then happy programming.

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  • Add "not" to if statement in shell script

    - by John Crawford
    I have the following script that should exist if the user does not exist. #check if user currently exists on system if id $User > /dev/null 2>&1 then #user exists no need to exit program echo "blah blah, what a waste of space" else echo "This user does NOT exists. Please create that user before using this script.\n" exit fi My problem is that I would ideally like to place a "not" if that first if statement so that I can trim down my if, else statement. Ideally I would like something like this: if !(id $User > /dev/null 2>&1) then echo "This user does NOT exists. Please create that user before using this script.\n" exit fi

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  • Neues Statement Of Direction veröffentlicht

    - by carstenczarski
    Das APEX Entwicklerteam hat ein neues Statement Of Direction (SOD) für die Version 5.0 veröffentlicht. Wie immer wird es die Verbesserung und Erweiterung vorhandener und die Einführung neuer Funktionen geben. Wie immer, ist das Statement Of Direction dazu gedacht, die Pläne und Ziele des APEX-Entwicklerteams mit der Community zu teilen. Insofern ist für APEX 5.0 unter anderem geplant ... ... modale Dialoge deklarativ bereitzustellen ... den Drag and Drop Layout Editor zurückzubringen ... HTML5 noch besser zu unterstützen ... mehr Varianten und Möglichkeiten für PDF-Ausgabe bereitzustellen ... spezielle User Interfaces für Tablets einzuführen ... Master / Detail / Detail Formulare zu ermöglichen ... mehrerer Interaktive Berichte auf einer Seite zu erlauben ... und vieles weitere mehr. Die APEX-Erfolgsgeschichte geht also weiter.

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  • How can I make an SQL statement that finds unassociated records?

    - by William Calleja
    I have two tables as follows: tblCountry (countryID, countryCode) tblProjectCountry(ProjectID, countryID) The tblCountry table is a list of all countries with their codes and the tblProjectCountry table associates certain countries with certain projects. I need an SQL statement that gives me a list of the countries with their country code that do NOT have an associated record in the tblProjectCountry table. so far I got to here: SELECT tblCountry.countryID, tblCountry.countryCode FROM tblProjectCountry INNER JOIN tblCountry ON tblProjectCountry.countryID = tblCountry.countryID WHERE (SELECT COUNT(ProjectID) FROM tblProjectCountry WHERE (ProjectID = 1) AND (countryID = tblCountry.countryID)) = 0 The above statement parses as correct but doesn't give the exact result I'm looking for. Can anyone help?

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  • SELECT..CASE - Refactor T-SQL

    - by Nev_Rahd
    Hello Can I refactor the below SQL CASE statements into single for each case ? SELECT CASE RDV.DOMAIN_CODE WHEN 'L' THEN CN.FAMILY_NAME ELSE NULL END AS [LEGAL_FAMILY_NAME], CASE RDV.DOMAIN_CODE WHEN 'L' THEN CN.GIVEN_NAME ELSE NULL END AS [LEGAL_GIVEN_NAME], CASE RDV.DOMAIN_CODE WHEN 'L' THEN CN.MIDDLE_NAMES ELSE NULL END AS [LEGAL_MIDDLE_NAMES], CASE RDV.DOMAIN_CODE WHEN 'L' THEN CN.NAME_TITLE ELSE NULL END AS [LEGAL_NAME_TITLE], CASE RDV.DOMAIN_CODE WHEN 'P' THEN CN.FAMILY_NAME ELSE NULL END AS [PREFERRED_FAMILY_NAME], CASE RDV.DOMAIN_CODE WHEN 'P' THEN CN.GIVEN_NAME ELSE NULL END AS [PREFERRED_GIVEN_NAME], CASE RDV.DOMAIN_CODE WHEN 'P' THEN CN.MIDDLE_NAMES ELSE NULL END AS [PREFERRED_MIDDLE_NAMES], CASE RDV.DOMAIN_CODE WHEN 'P' THEN CN.NAME_TITLE ELSE NULL END AS [PREFERRED_NAME_TITLE] FROM dbo.CLIENT_NAME CN JOIN dbo.REFERENCE_DOMAIN_VALUE RDV ON CN.NAME_TYPE_CODE = RDV.DOMAIN_CODE AND RDV.REFERENCE_DOMAIN_ID = '7966'

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  • In an If-Else Statement for a method return, should an Else be explicitly stated if it can instead b

    - by ccomet
    I have a method that checks certain things and returns a Boolean based on those checks. It involves a single branching If section that checks about 5 conditions in sequence. If any of those conditions return true, then the method will return true;. If none of the conditions return true, then the method will return false;. Since the code after the If section will only run if none of the conditions are true, then that code is logically identical to including an actual Else statement. So is it a better idea to actually write in the Else statement for this kind of situation?

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  • Checking if the email had been already taken in the following if statement (Rails)?

    - by alexchenco
    I have the following action: users.rb: def omniauth_create auth = request.env["omniauth.auth"] user = User.from_omniauth(env["omniauth.auth"]) unless user.email.blank? if user.id.nil? # Save the user since he hasn't been created yet user.save! end sign_in user redirect_back_or user else # Send user to a form to fill his email #session[:omniauth] = request.env['omniauth.auth'].except('extra') redirect_to(enter_email_path(oprovider: user.provider, ouid: user.uid, oname: user.name, opassword: user.password, opassword_confirmation: user.password)) end end It does the following: If the user's email is not blank, sign him in, and redirect him to his profile (and save him if his id is nil. In other words, if he hasn't been created yet). If the user's email is blank, send him to enter_email_path (where the user can enter his email). Now I want to add another if statement that flashes an error if the email had been already taken, and redirects the user to the root_path I'm not very sure how to do this, Any suggestions? (and where to put that if statement?)

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  • SQL SERVER – Solution of Puzzle – Swap Value of Column Without Case Statement

    - by pinaldave
    Earlier this week I asked a question where I asked how to Swap Values of the column without using CASE Statement. Read here: SQL SERVER – A Puzzle – Swap Value of Column Without Case Statement. I have proposed 3 different solutions in the blog posts itself. I had requested the help of the community to come up with alternate solutions and honestly I am stunned and amazed by the qualified entries. I will be not able to cover every single solution which is posted as a comment, however, I would like to for sure cover few interesting entries. However, I am selecting 5 solutions which are different (not necessary they are most optimal or best – just different and interesting). Just for clarity I am involving the original problem statement here. USE tempdb GO CREATE TABLE SimpleTable (ID INT, Gender VARCHAR(10)) GO INSERT INTO SimpleTable (ID, Gender) SELECT 1, 'female' UNION ALL SELECT 2, 'male' UNION ALL SELECT 3, 'male' GO SELECT * FROM SimpleTable GO -- Insert Your Solutions here -- Swap value of Column Gender SELECT * FROM SimpleTable GO DROP TABLE SimpleTable GO Here are the five most interesting and different solutions I have received. Solution by Roji P Thomas UPDATE S SET S.Gender = D.Gender FROM SimpleTable S INNER JOIN SimpleTable D ON S.Gender != D.Gender I really loved the solutions as it is very simple and drives the point home – elegant and will work pretty much for any values (not necessarily restricted by the option in original question ‘male’ or ‘female’). Solution by Aneel CREATE TABLE #temp(id INT, datacolumn CHAR(4)) INSERT INTO #temp VALUES(1,'gent'),(2,'lady'),(3,'lady') DECLARE @value1 CHAR(4), @value2 CHAR(4) SET @value1 = 'lady' SET @value2 = 'gent' UPDATE #temp SET datacolumn = REPLACE(@value1 + @value2,datacolumn,'') Aneel has very interesting solution where he combined both the values and replace the original value. I personally liked this creativity of the solution. Solution by SIJIN KUMAR V P UPDATE SimpleTable SET Gender = RIGHT(('fe'+Gender), DIFFERENCE((Gender),SOUNDEX(Gender))*2) Sijin has amazed me with Difference and Soundex function. I have never visualized that above two functions can resolve the problem. Hats off to you Sijin. Solution by Nikhildas UPDATE St SET St.Gender = t.Gender FROM SimpleTable St CROSS Apply (SELECT DISTINCT gender FROM SimpleTable WHERE St.Gender != Gender) t I was expecting that someone will come up with this solution where they use CROSS APPLY. This is indeed very neat and for sure interesting exercise. If you do not know how CROSS APPLY works this is the time to learn. Solution by mistermagooo UPDATE SimpleTable SET Gender=X.NewGender FROM (VALUES('male','female'),('female','male')) AS X(OldGender,NewGender) WHERE SimpleTable.Gender=X.OldGender As per author this is a slow solution but I love how syntaxes are placed and used here. I love how he used syntax here. I will say this is the most beautifully written solution (not necessarily it is best). Bonus: Solution by Madhivanan Somehow I was confident Madhi – SQL Server MVP will come up with something which I will be compelled to read. He has written a complete blog post on this subject and I encourage all of you to go ahead and read it. Now personally I wanted to list every single comment here. There are some so good that I am just amazed with the creativity. I will write a part of this blog post in future. However, here is the challenge for you. Challenge: Go over 50+ various solutions listed to the simple problem here. Here are my two asks for you. 1) Pick your best solution and list here in the comment. This exercise will for sure teach us one or two things. 2) Write your own solution which is yet not covered already listed 50 solutions. I am confident that there is no end to creativity. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Function, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • C Number to Text problem with ones and tens..

    - by Joegabb
    #include<stdio.h> #include<conio.h> main() { int ones,tens,ventoteen, myloop = 0; long num2,cents2,centeens,cents1,thousands,hundreds; double num; do{ printf("Enter a number: "); scanf("%lf",&num); if(num<=10000 || num>=0) { if (num==0) { printf("\t\tZero"); } num=(num*100); num2= (long)num; thousands=num2/100000; num2=num2%100000; hundreds=num2/10000; num2=num2%10000; if ((num2>=1100) || (num2<=1900)) { tens=0; ones=0; ventoteen=num2%1000; } else { tens=num2/1000; num2=num2%1000; ones=num2/100; num2=num2%100; } if((num2>=11) && (num2<=19)) { cents1=0; cents2=0; centeens=num2%10; } else { cents1=num2/10; num2=num2%10; cents2=num2/1; } if (thousands == 1) printf("One thousand "); else if (thousands == 2) printf("Two thousand "); else if (thousands == 3) printf("Three Thousand "); else if (thousands == 4) printf("Four thousand "); else if (thousands == 5) printf("Five Thousand "); else if (thousands == 6) printf("Six thousand "); else if (thousands == 7) printf("Seven Thousand "); else if (thousands == 8) printf("Eight thousand "); else if (thousands == 9) printf("Nine Thousand "); else {} if (hundreds == 1) printf("one hundred "); else if (hundreds == 2) printf("two hundred "); else if (hundreds == 3) printf("three hundred "); else if (hundreds == 4) printf("four hundred "); else if (hundreds == 5) printf("five hundred "); else if (hundreds == 6) printf("six hundred "); else if (hundreds == 7) printf("seven hundred "); else if (hundreds == 8) printf("eight hundred "); else if (hundreds == 9) printf("nine hundred "); else {} switch(ventoteen) { case 1: printf("eleven ");break; case 2: printf("twelve ");break; case 3: printf("thirteen ");break; case 4: printf("fourteen ");break; case 5: printf("fifteen ");break; case 6: printf("sixteen ");break; case 7: printf("seventeen ");break; case 8: printf("eighteen ");break; case 9: printf("nineteen ");break; } switch(tens) { case 1: printf("ten ");break; case 2: printf("twenty ");break; case 3: printf("thirty ");break; case 4: printf("forty ");break; case 5: printf("fifty ");break; case 6: printf("sixty ");break; case 7: printf("seventy ");break; case 8: printf("eighty ");break; case 9: printf("ninety ");break; } switch(ones) { case 1: printf("one ");break; case 2: printf("two ");break; case 3: printf("three ");break; case 4: printf("four ");break; case 5: printf("five ");break; case 6: printf("six ");break; case 7: printf("seven ");break; case 8: printf("eight ");break; case 9: printf("nine ");break; } switch(cents1) { case 1: printf("and ten centavos ");break; case 2: printf("and twenty centavos ");break; case 3: printf("and thirty centavos ");break; case 4: printf("and fourty centavos ");break; case 5: printf("and fifty centavos ");break; case 6: printf("and sixty centavos ");break; case 7: printf("and seventy centavos ");break; case 8: printf("and eighty centavos ");break; case 9: printf("and ninety centavos ");break; } switch(centeens) { case 1: printf("and eleven centavos ");break; case 2: printf("and twelve centavos ");break; case 3: printf("and thirteen centavos ");break; case 4: printf("and fourteen centavos ");break; case 5: printf("and fifteen centavos ");break; case 6: printf("and sixteen centavos ");break; case 7: printf("and seventeen centavos ");break; case 8: printf("and eighteen centavos ");break; case 9: printf("and nineteen centavos ");break; } switch(cents2) { case 1: printf("and one centavos ");break; case 2: printf("and two centavos ");break; case 3: printf("and three centavos ");break; case 4: printf("and four centavos ");break; case 5: printf("and five centavos ");break; case 6: printf("and six centavos ");break; case 7: printf("and seven centavos ");break; case 8: printf("and eight centavos ");break; case 9: printf("and nine centavos ");break; } } getch(); }while(myloop == 0); return 0; } my code is working fine but the problem is when i input 1 - 90 nothing appears but when i input 100 the output would be fine and that is "One Hundred" and so as 1000 the output would be "One Thousand". thanks for the help..

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  • lower-case 'c' key not working in bash

    - by gavin
    This is a bit of a strange one. I'm running Ubuntu 12.04. It's been working well but today, I ran into a hell of strange phenomenon. I can no longer type a lower-case 'c' in bash. At first I thought it was a misconfiguration for the gnome terminal but I tried both a stock xterm and directly at the console (ctrl+alt+F1) and the issue was the same. I can type an upper-case C without any difficulty and I can type lower-case 'c' in any other terminal based program (vim, bash, less, etc.). The lower 'c' also works if I jump into plain old sh. I looked at all the configuration files I know of and haven't found anything incriminating in there. I suspect it's not going to be that simple anyway because if I run bash with the '--norc' option from within sh, the problem remains. I don't know what else to check. In fact, if I wanted to cause this problem on a given machine, I have no idea how it could be done. Total mystery.

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  • Switch vs Polymorphism when dealing with model and view

    - by Raphael Oliveira
    I can't figure out a better solution to my problem. I have a view controller that presents a list of elements. Those elements are models that can be an instance of B, C, D, etc and inherit from A. So in that view controller, each item should go to a different screen of the application and pass some data when the user select one of them. The two alternatives that comes to my mind are (please ignore the syntax, it is not a specific language) 1) switch (I know that sucks) //inside the view controller void onClickItem(int index) { A a = items.get(index); switch(a.type) { case b: B b = (B)a; go to screen X; x.v1 = b.v1; // fill X with b data x.v2 = b.v2; case c: go to screen Y; etc... } } 2) polymorphism //inside the view controller void onClickItem(int index) { A a = items.get(index); Screen s = new (a.getDestinationScreen()); //ignore the syntax s.v1 = a.v1; // fill s with information about A s.v2 = a.v2; show(s); } //inside B Class getDestinationScreen(void) { return Class(X); } //inside C Class getDestinationScreen(void) { return Class(Y); } My problem with solution 2 is that since B, C, D, etc are models, they shouldn't know about view related stuff. Or should they in that case?

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  • Is there any alternative way of writing this switch statement(C#3.0)

    - by Newbie
    Can it be done in a better way public static EnumFactorType GetFactorEnum(string str) { Standardization e = new Standardization(); switch (str.ToLower()) { case "beta": e.FactorType = EnumFactorType.BETA; break; case "bkp": e.FactorType = EnumFactorType.BOOK_TO_PRICE; break; case "yld": e.FactorType = EnumFactorType.DIVIDEND_YIELD; break; case "growth": e.FactorType = EnumFactorType.GROWTH; break; case "mean": e.FactorType = EnumFactorType.MARKET_CAP; break; case "momentum": e.FactorType = EnumFactorType.MOMENTUM; break; case "size": e.FactorType = EnumFactorType.SIZE; break; case "stat_fact1": e.FactorType = EnumFactorType.STAT_FACT_1; break; case "stat_fact2": e.FactorType = EnumFactorType.STAT_FACT_2; break; case "value": e.FactorType = EnumFactorType.VALUE; break; } return e.FactorType; } If I create a Static class(say Constatant) and declare variable like public static string BETA= "beta"; and then if I try to put that in the Case expression like Case Constants.BETA : e.FactorType = EnumFactorType.BETA; break; then the compiler will report error.(quite expected) So is there any other way?(I canot change the switch statement) Using C#3.0 Thanks

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  • Just a small help about switch's use

    - by Laurent Fournier
    If an answer on this already exist, my apologies i've not found on this question... is this statement correct if i want presice actions on integers from -2 to 0, and for those between 1 and 6 apply the same methods with only my integer who'll change ? Like this: public void setCaseGUI(Point pt, int i, boolean b){ plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setSelected(b); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setIcon(null); switch(i) { case -2: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case -1: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case 0: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(""); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; case 1: case 2: case 3: case 4: case 5: case 6: case 7: case 8: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i)); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; default: System.out.println("Erreur de changement d'état/case !"); } } Please don't be too harsh on me i've started to learn dev only a few month ago

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  • What characters are NOT escaped with a mysqli prepared statement?

    - by barfoon
    Hey everyone, I'm trying to harden some of my PHP code and use mysqli prepared statements to better validate user input and prevent injection attacks. I switched away from mysqli_real_escape_string as it does not escape % and _. However, when I create my query as a mysqli prepared statement, the same flaw is still present. The query pulls a users salt value based on their username. I'd do something similar for passwords and other lookups. Code: $db = new sitedatalayer(); if ($stmt = $db->_conn->prepare("SELECT `salt` FROM admins WHERE `username` LIKE ? LIMIT 1")) { $stmt->bind_param('s', $username); $stmt->execute(); $stmt->bind_result($salt); while ($stmt->fetch()) { printf("%s\n", $salt); } $stmt->close(); } else return false; Am I composing the statement correctly? If I am what other characters need to be examined? What other flaws are there? What is best practice for doing these types of selects? Thanks,

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  • Implementing a switch statement based on user input

    - by Dave Voyles
    I'm trying to delay the time it takes for the main menu screen to pop up after a user has won / lost a match. As it stands, the game immediately displays a message stating "you won / lost" and waits for 6 seconds before loading the menu screen. I would also like players to have the ability to press a key to advance to the menu screen immediately but thus far my switch statement doesn't seem to do the trick. I've included the switch statement, along with my (theoretical) inputs. What could I be doing wrong here? if (gamestate == GameStates.End) switch (input.IsMenuDown(ControllingPlayer)) { case true: ScreenManager.AddScreen(new MainMenuScreen(), null); // Draws the MainMenuScreen break; case false: if (screenLoadDelay > 0) { screenLoadDelay -= gameTime.ElapsedGameTime.TotalSeconds; } ScreenManager.AddScreen(new MainMenuScreen(), null); // Draws the MainMenuScreen break; } /// <summary> /// Checks for a "menu down" input action. /// The controllingPlayer parameter specifies which player to read /// input for. If this is null, it will accept input from any player. /// </summary> public bool IsMenuDown(PlayerIndex? controllingPlayer) { PlayerIndex playerIndex; return IsNewKeyPress(Keys.Down, controllingPlayer, out playerIndex) || IsNewButtonPress(Buttons.DPadDown, controllingPlayer, out playerIndex) || IsNewButtonPress(Buttons.LeftThumbstickDown, controllingPlayer, out playerIndex); }

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