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• Connect two database from 2 different host

  - by Maggie

  Hi, currently I have two websites: 1. A website connected to mySQL database in host A. 2. A website connected to Ms. Access database in Host B. Is there anyway if I update the database in Host B, the database in Host A can be updated automatically? Thank you. Really appreciate your help.

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• Project Euler 18: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 18.  As always, any feedback is welcome. # Euler 18 # http://projecteuler.net/index.php?section=problems&id=18 # By starting at the top of the triangle below and moving # to adjacent numbers on the row below, the maximum total # from top to bottom is 23. # # 3 # 7 4 # 2 4 6 # 8 5 9 3 # # That is, 3 + 7 + 4 + 9 = 23. # Find the maximum total from top to bottom of the triangle below: # 75 # 95 64 # 17 47 82 # 18 35 87 10 # 20 04 82 47 65 # 19 01 23 75 03 34 # 88 02 77 73 07 63 67 # 99 65 04 28 06 16 70 92 # 41 41 26 56 83 40 80 70 33 # 41 48 72 33 47 32 37 16 94 29 # 53 71 44 65 25 43 91 52 97 51 14 # 70 11 33 28 77 73 17 78 39 68 17 57 # 91 71 52 38 17 14 91 43 58 50 27 29 48 # 63 66 04 68 89 53 67 30 73 16 69 87 40 31 # 04 62 98 27 23 09 70 98 73 93 38 53 60 04 23 # NOTE: As there are only 16384 routes, it is possible to solve # this problem by trying every route. However, Problem 67, is the # same challenge with a triangle containing one-hundred rows; it # cannot be solved by brute force, and requires a clever method! ;o) import time start = time.time() triangle = [ [75], [95, 64], [17, 47, 82], [18, 35, 87, 10], [20, 04, 82, 47, 65], [19, 01, 23, 75, 03, 34], [88, 02, 77, 73, 07, 63, 67], [99, 65, 04, 28, 06, 16, 70, 92], [41, 41, 26, 56, 83, 40, 80, 70, 33], [41, 48, 72, 33, 47, 32, 37, 16, 94, 29], [53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14], [70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57], [91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48], [63, 66, 04, 68, 89, 53, 67, 30, 73, 16, 69, 87, 40, 31], [04, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 04, 23]] # Loop through each row of the triangle starting at the base. for a in range(len(triangle) - 1, -1, -1): for b in range(0, a): # Get the maximum value for adjacent cells in current row. # Update the cell which would be one step prior in the path # with the new total. For example, compare the first two # elements in row 15. Add the max of 04 and 62 to the first # position of row 14.This provides the max total from row 14 # to 15 starting at the first position. Continue to work up # the triangle until the maximum total emerges at the # triangle's apex. triangle [a-1][b] += max(triangle [a][b], triangle [a][b+1]) print triangle [0][0] print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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• Project Euler 11: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 11.  As always, any feedback is welcome. # Euler 11 # http://projecteuler.net/index.php?section=problems&id=11 # What is the greatest product # of four adjacent numbers in any direction (up, down, left, # right, or diagonally) in the 20 x 20 grid? import time start = time.time() grid = [\ [8,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,8],\ [49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00],\ [81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65],\ [52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91],\ [22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80],\ [24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50],\ [32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70],\ [67,26,20,68,02,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21],\ [24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72],\ [21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95],\ [78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,9,53,56,92],\ [16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57],\ [86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58],\ [19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40],\ [04,52,8,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66],\ [88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69],\ [04,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36],\ [20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16],\ [20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54],\ [01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48]] # left and right max, product = 0, 0 for x in range(0,17): for y in xrange(0,20): product = grid[y][x] * grid[y][x+1] * \ grid[y][x+2] * grid[y][x+3] if product > max : max = product # up and down for x in range(0,20): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x] * \ grid[y+2][x] * grid[y+3][x] if product > max : max = product # diagonal right for x in range(0,17): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x+1] * \ grid[y+2][x+2] * grid[y+3][x+3] if product > max: max = product # diagonal left for x in range(0,17): for y in xrange(0,17): product = grid[y][x+3] * grid[y+1][x+2] * \ grid[y+2][x+1] * grid[y+3][x] if product > max : max = product print max print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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• What are good NoSQL and non-relational database solutions for audit/logging database

  - by Juha Syrjälä

  What would be suitable database for following? I am especially interested about your experiences with non-relational NoSQL systems. Are they any good for this kind of usage, which system you have used and would recommend, or should I go with normal relational database (DB2)? I need to gather audit trail/logging type information from bunch of sources to a centralized server where I could generate reports efficiently and examine what is happening in the system. Typically a audit/logging event would consist always of some mandatory fields, for example globally unique id (some how generated by program that generated this event) timestamp event type (i.e. user logged in, error happened etc) some information about source (server1, server2) Additionally the event could contain 0-N key-value pairs, where value might be up to few kilobytes of text. It must run on Linux server It should work with high amount of data (100GB for example) it should support some kind of efficient full text search It should allow concurrent reading and writing It should be flexible to add new event types and add/remove key-value pairs to new events. Flexible=no changes should be required to database schema, application generating the events can just add new event types/new fields as needed. it should be efficient to make queries against database. For reporting and exploring what happened. For example: How many events with type=X occurred in some time period. Get all events where field A has value Y. Get all events with type X and field A has value 1 and field B is not 2 and event occurred in last 24h

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• Project structure: where to put business logic

  - by Mister Smith

  First of all, I'm not asking where does business logic belong. This has been asked before and most answers I've read agree in that it belongs in the model: Where to put business logic in MVC design? How much business logic should be allowed to exist in the controller layer? How accurate is "Business logic should be in a service, not in a model"? Why put the business logic in the model? What happens when I have multiple types of storage? However people disagree in the way this logic should be distributed across classes. There seem to exist three major currents of thought: Fat model with business logic inside entity classes. Anemic model and business logic in "Service" classes. It depends. I find all of them problematic. The first option is what most Fowlerites stick to. The problem with a fat model is that sometimes a business logic funtion is not only related to a class, and instead uses a bunch of other classes. If, for example, we are developing a web store, there should be a function that calcs an order's total. We could think of putting this function inside the Order class, but what actually happens is that the logic needs to use different classes, not only data contained in the Order class, but also in the User class, the Session class, and maybe the Tax class, Country class, or Giftcard, Payment, etc. Some of these classes could be composed inside the Order class, but some others not. Sorry if the example is not very good, but I hope you understand what I mean. Putting such a function inside the Order class would break the single responsibility principle, adding unnecesary dependences. The business logic would be scattered across entity classes, making it hard to find. The second option is the one I usually follow, but after many projects I'm still in doubt about how to name the class or classes holding the business logic. In my company we usually develop apps with offline capabilities. The user is able to perform entire transactions offline, so all validation and business rules should be implemented in the client, and then there's usually a background thread that syncs with the server. So we usually have the following classes/packages in every project: Data model (DTOs) Data Access Layer (Persistence) Web Services layer (Usually one class per WS, and one method per WS method). Now for the business logic, what is the standard approach? A single class holding all the logic? Multiple classes? (if so, what criteria is used to distribute the logic across them?). And how should we name them? FooManager? FooService? (I know the last one is common, but in our case it is bad naming because the WS layer usually has classes named FooWebService). The third option is probably the right one, but it is also devoid of any useful info. To sum up: I don't like the first approach, but I accept that I might have been unable to fully understand the Zen of it. So if you advocate for fat models as the only and universal solution you are welcome to post links explaining how to do it the right way. I'd like to know what is the standard design and naming conventions for the second approach in OO languages. Class names and package structure, in particular. It would also be helpful too if you could include links to Open Source projects showing how it is done. Thanks in advance.

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• Project Euler 17: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 17.  As always, any feedback is welcome. # Euler 17 # http://projecteuler.net/index.php?section=problems&id=17 # If the numbers 1 to 5 are written out in words: # one, two, three, four, five, then there are # 3 + 3 + 5 + 4 + 4 = 19 letters used in total. # If all the numbers from 1 to 1000 (one thousand) # inclusive were written out in words, how many letters # would be used? # # NOTE: Do not count spaces or hyphens. For example, 342 # (three hundred and forty-two) contains 23 letters and # 115 (one hundred and fifteen) contains 20 letters. The # use of "and" when writing out numbers is in compliance # with British usage. import time start = time.time() def to_word(n): h = { 1 : "one", 2 : "two", 3 : "three", 4 : "four", 5 : "five", 6 : "six", 7 : "seven", 8 : "eight", 9 : "nine", 10 : "ten", 11 : "eleven", 12 : "twelve", 13 : "thirteen", 14 : "fourteen", 15 : "fifteen", 16 : "sixteen", 17 : "seventeen", 18 : "eighteen", 19 : "nineteen", 20 : "twenty", 30 : "thirty", 40 : "forty", 50 : "fifty", 60 : "sixty", 70 : "seventy", 80 : "eighty", 90 : "ninety", 100 : "hundred", 1000 : "thousand" } word = "" # Reverse the numbers so position (ones, tens, # hundreds,...) can be easily determined a = [int(x) for x in str(n)[::-1]] # Thousands position if (len(a) == 4 and a[3] != 0): # This can only be one thousand based # on the problem/method constraints word = h[a[3]] + " thousand " # Hundreds position if (len(a) >= 3 and a[2] != 0): word += h[a[2]] + " hundred" # Add "and" string if the tens or ones # position is occupied with a non-zero value. # Note: routine is broken up this way for [my] clarity. if (len(a) >= 2 and a[1] != 0): # catch 10 - 99 word += " and" elif len(a) >= 1 and a[0] != 0: # catch 1 - 9 word += " and" # Tens and ones position tens_position_value = 99 if (len(a) >= 2 and a[1] != 0): # Calculate the tens position value per the # first and second element in array # e.g. (8 * 10) + 1 = 81 tens_position_value = int(a[1]) * 10 + a[0] if tens_position_value <= 20: # If the tens position value is 20 or less # there's an entry in the hash. Use it and there's # no need to consider the ones position word += " " + h[tens_position_value] else: # Determine the tens position word by # dividing by 10 first. E.g. 8 * 10 = h[80] # We will pick up the ones position word later in # the next part of the routine word += " " + h[(a[1] * 10)] if (len(a) >= 1 and a[0] != 0 and tens_position_value > 20): # Deal with ones position where tens position is # greater than 20 or we have a single digit number word += " " + h[a[0]] # Trim the empty spaces off both ends of the string return word.replace(" ","") def to_word_length(n): return len(to_word(n)) print sum([to_word_length(i) for i in xrange(1,1001)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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• mysql, sqlite database source code

  - by Yang

  hi guys, i know implementing database is a huge topic, but i want to have a basic understanding of how database systems works (e.g. memory management, binary tree, transaction, sql parsing, multi-threading, partitions, etc) by investigating the source code of the database, since there are a few already proven very robust open source databases like mysql, sqlite and so on. however, the code are very complicated and i have no clue where to start. also i find that the old school database textbooks are only explaining the theory, not the implementation details. Can anyone suggest how should i get started and is there any books that emphasis on the technology and techniques of building dbms used in modern database industry? Thank in advance!

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• Oracle vocabulary, what is the mysql/SQL Server equivalent of a database

  - by jeph perro

  Hi, I need some help with vocabulary, I don't use Oracle that often but I am familiar with MySQL and SQL Server. I have an application I need to upgrade and migrate, and part of the procedure to do that involves exporting to an XML file, allowing the installer to create new database tables, then import to the new database tables from the XML file. In Oracle, my database connection specifies a username, password, and an SID. Let's call the SID, "COMPANY-APPS". This SID contains tables belonging to several applications, each of which connects with a different user ( "WIKIUSER", "BUGUSER", "TIMETRACKERUSER" ). My question is: Can I re-use the same user to create the new tables ( with the same names ). In MySQL or SQL Server, I would create a new database and grant my user privileges to create tables in it. OR, do I need to create a new database user for my upgraded tables?

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• How to create SSIS package to update from one database to another database within same server

  - by Pavan Kumar

  My query is related to the answers i got for questions i had posted earlier in the same forum. I have a copy of a client database which is attached to SQL Server where the Central Database exists. The copy already contains the updated data. I just want to update from that copy to Central Database both holding same schema and are present in the same server using C# .NET. One of the solution i got was to create SSIS package and run it from the UI. I want to know as how i can create SSIS Package to achieve this. I am new to SSIS. I am using SQL Server 2005 Standard Edition and Visual Studio 2008 SP1 installed. I learnt that BIDS 2005 is used to create packages which comes by default with SQL Server 2005. Can someone please give me a example as i am new to this.

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• SQL Server: avoiding hard coding of database name in cross-database views

  - by codeulike

  So, lets say you have two SQL Server Databases on the same server that reference each others tables in their Views, Functions and Stored Procedures. You know, things like this: use database_foo create view spaghetti as select f.col1, c.col2 from fusilli f inner join database_bar.dbo.conchigli c on f.id = c.id (I know that cross-database views are not very good practice, but lets just say you're stuck with it) Are there any good techniques to avoid 'hard coding' the database names? (So that should you need to occasionally re-point to a different database - for testing perhaps - you don't need to edit loads of views, fns, sps) I'm interested in SQL 2005 or SQL 2008 solutions. Cheers.

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• Oracle vocabulary, what is the mysql/mssql equivalent of a database

  - by jeph perro

  Hi, I need some help with vocabulary, I don't use Oracle that often but I am familiar with MySQL and MSSQL. I have an application I need to upgrade and migrate, and part of the procedure to do that involves exporting to an XML, create new database tables, then populate the new database tables from the XML export. In Oracle, my database connection specifies a username, password, and an SID. This SID contains tables belonging to several applications. My question is: Can I re-use the same user to create the new tables ( with the same names ). In MySQL or MSSQL, I would create a new database and grant my user privileges to create tables in it. OR, do I need to create a new database user for my upgraded tables?

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• in-memory database in Python

  - by Claudiu

  I'm doing some queries in Python on a large database to get some stats out of the database. I want these stats to be in-memory so other programs can use them without going to a database. I was thinking of how to structure them, and after trying to set up some complicated nested dictionaries, I realized that a good representation would be an SQL table. I don't want to store the data back into the persistent database, though. Are there any in-memory implementations of an SQL database that supports querying the data with SQL syntax?

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• Project euler problem 3 in haskell

  - by shk

  I'm new in Haskell and try to solve 3 problem from http://projecteuler.net/. The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? My solution: import Data.List getD :: Int -> Int getD x = -- find deviders let deriveList = filter (\y -> (x `mod` y) == 0) [1 .. x] filteredList = filter isSimpleNumber deriveList in maximum filteredList -- Check is nmber simple isSimpleNumber :: Int -> Bool isSimpleNumber x = let deriveList = map (\y -> (x `mod` y)) [1 .. x] filterLength = length ( filter (\z -> z == 0) deriveList) in case filterLength of 2 -> True _ -> False I try to run for example: getD 13195 > 29 But when i try: getD 600851475143 I get error Exception: Prelude.maximum: empty list Why? Thank you @Barry Brown, I think i must use: getD :: Integer -> Integer But i get error: Couldn't match expected type `Int' with actual type `Integer' Expected type: [Int] Actual type: [Integer] In the second argument of `filter', namely `deriveList' In the expression: filter isSimpleNumber deriveList Thank you.

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• Drop database on DB2 9.5 - SQL1035N The database is currently in use

  - by Tommy

  I've never got this working the first time, but now I can't seem to do i at all. There is a connection pool somewhere using the database, so trying to drop the database when an application is using the database should give this error. The problem is there are no connection to the database when I issue these commands: db2 connect to mydatabase db2 quiesce database immediate force connections db2 connect reset db2 drop database mydatabase This allways give: SQL1035N The database is currently in use. SQLSTATE=57019 running this command shows no connections/applications DB2 list applications I can even deactivate the database, but still can't drop it. db2 => deactivate database mydatabase DB20000I The DEACTIVATE DATABASE command completed successfully. db2 => drop database mydatabase SQL1035N The database is currently in use. SQLSTATE=57019 db2 => Anyone got any clues? I'm running the cmd-windows as the local administrator (windows 2008) and this is also the admin for DB2. The connectionpool-user cannot connect during quiesce-state.

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• Drop database on DB2 9.5 - SQL1035N The database is currently in use

  - by Tommy

  I've never got this working the first time, but now I can't seem to do i at all. There is a connection pool somewhere using the database, so trying to drop the database when an application is using the database should give this error. The problem is there are no connection to the database when I issue these commands: db2 connect to mydatabase db2 quiesce database immediate force connections db2 connect reset db2 drop database mydatabase This allways give: SQL1035N The database is currently in use. SQLSTATE=57019 running this command shows no connections/applications DB2 list applications I can even deactivate the database, but still can't drop it. db2 => deactivate database mydatabase DB20000I The DEACTIVATE DATABASE command completed successfully. db2 => drop database mydatabase SQL1035N The database is currently in use. SQLSTATE=57019 db2 => Anyone got any clues? I'm running the cmd-windows as the local administrator (windows 2008) and this is also the admin for DB2. The connectionpool-user cannot connect during quiesce-state.

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• Managing Database Clusters - A Whole Lot Simpler

  - by mat.keep(at)oracle.com

  Clustered computing brings with it many benefits: high performance, high availability, scalable infrastructure, etc.  But it also brings with it more complexity.Why ?  Well, by its very nature, there are more "moving parts" to monitor and manage (from physical, virtual and logical hosts) to fault detection and failover software to redundant networking components - the list goes on.  And a cluster that isn't effectively provisioned and managed will cause more downtime than the standalone systems it is designed to improve upon.  Not so great....When it comes to the database industry, analysts already estimate that 50% of a typical database's Total Cost of Ownership is attributable to staffing and downtime costs.  These costs will only increase if a database cluster is to hard to properly administer.Over the past 9 months, monitoring and management has been a major focus in the development of the MySQL Cluster database, and on Tuesday 12th January, the product team will be presenting the output of that development in a new webinar.Even if you can't make the date, it is still worth registering so you will receive automatic notification when the on-demand replay is availableIn the webinar, the team will cover:    * NDBINFO: released with MySQL Cluster 7.1, NDBINFO presents real-time status and usage statistics, providing developers and DBAs with a simple means of pro-actively monitoring and optimizing database performance and availability.    * MySQL Cluster Manager (MCM): available as part of the commercial MySQL Cluster Carrier Grade Edition, MCM simplifies the creation and management of MySQL Cluster by automating common management tasks, delivering higher administration productivity and enhancing cluster agility. Tasks that used to take 46 commands can be reduced to just one!    * MySQL Cluster Advisors & Graphs: part of the MySQL Enterprise Monitor and available in the commercial MySQL Cluster Carrier Grade Edition, the Enterprise Advisor includes automated best practice rules that alert on key performance and availability metrics from MySQL Cluster data nodes.You'll also learn how you can get started evaluating and using all of these tools to simplify MySQL Cluster management.This session will last round an hour and will include interactive Q&A throughout. You can learn more about MySQL Cluster Manager from this whitepaper and on-line demonstration.  You can also download the packages from eDelivery (just select "MySQL Database" as the product pack, select your platform, click "Go" and then scroll down to get the software).While managing clusters will never be easy, the webinar will show hou how it just got a whole lot simpler !

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• Steps to Mitigate Database Security Worst Practices

  - by Troy Kitch

  The recent Top 6 Database Security Worst Practices webcast revealed the Top 6, and a bonus 7th , database security worst practices: Privileged user "all access pass" Allow application bypass Minimal and inconsistent monitoring/auditing Not securing application data from OS-level user No SQL injection defense Sensitive data in non-production environments Not securing complete database environment These practices are uncovered in the 2010 IOUG Data Security Survey. As part of the webcast we looked at each one of these practices and how you can mitigate them with the Oracle Defense-in-Depth approach to database security. There's a lot of additional information to glean from the webcast, so I encourage you to check it out here and see how your organization measures up.

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• Oracle Announces Oracle Exadata X3 Database In-Memory Machine

  - by jgelhaus

  Fourth Generation Exadata X3 Systems are Ideal for High-End OLTP, Large Data Warehouses, and Database Clouds; Eighth-Rack Configuration Offers New Low-Cost Entry Point ORACLE OPENWORLD, SAN FRANCISCO – October 1, 2012 News Facts During his opening keynote address at Oracle OpenWorld, Oracle CEO, Larry Ellison announced the Oracle Exadata X3 Database In-Memory Machine - the latest generation of its Oracle Exadata Database Machines. The Oracle Exadata X3 Database In-Memory Machine is a key component of the Oracle Cloud. Oracle Exadata X3-2 Database In-Memory Machine and Oracle Exadata X3-8 Database In-Memory Machine can store up to hundreds of Terabytes of compressed user data in Flash and RAM memory, virtually eliminating the performance overhead of reads and writes to slow disk drives, making Exadata X3 systems the ideal database platforms for the varied and unpredictable workloads of cloud computing. In order to realize the highest performance at the lowest cost, the Oracle Exadata X3 Database In-Memory Machine implements a mass memory hierarchy that automatically moves all active data into Flash and RAM memory, while keeping less active data on low-cost disks. With a new Eighth-Rack configuration, the Oracle Exadata X3-2 Database In-Memory Machine delivers a cost-effective entry point for smaller workloads, testing, development and disaster recovery systems, and is a fully redundant system that can be used with mission critical applications. Next-Generation Technologies Deliver Dramatic Performance Improvements Oracle Exadata X3 Database In-Memory Machines use a combination of scale-out servers and storage, InfiniBand networking, smart storage, PCI Flash, smart memory caching, and Hybrid Columnar Compression to deliver extreme performance and availability for all Oracle Database Workloads. Oracle Exadata X3 Database In-Memory Machine systems leverage next-generation technologies to deliver significant performance enhancements, including: Four times the Flash memory capacity of the previous generation; with up to 40 percent faster response times and 100 GB/second data scan rates. Combined with Exadata’s unique Hybrid Columnar Compression capabilities, hundreds of Terabytes of user data can now be managed entirely within Flash; 20 times more capacity for database writes through updated Exadata Smart Flash Cache software. The new Exadata Smart Flash Cache software also runs on previous generation Exadata systems, increasing their capacity for writes tenfold; 33 percent more database CPU cores in the Oracle Exadata X3-2 Database In-Memory Machine, using the latest 8-core Intel® Xeon E5-2600 series of processors; Expanded 10Gb Ethernet connectivity to the data center in the Oracle Exadata X3-2 provides 40 10Gb network ports per rack for connecting users and moving data; Up to 30 percent reduction in power and cooling. Configured for Your Business, Available Today Oracle Exadata X3-2 Database In-Memory Machine systems are available in a Full-Rack, Half-Rack, Quarter-Rack, and the new low-cost Eighth-Rack configuration to satisfy the widest range of applications. Oracle Exadata X3-8 Database In-Memory Machine systems are available in a Full-Rack configuration, and both X3 systems enable multi-rack configurations for virtually unlimited scalability. Oracle Exadata X3-2 and X3-8 Database In-Memory Machines are fully compatible with prior Exadata generations and existing systems can also be upgraded with Oracle Exadata X3-2 servers. Oracle Exadata X3 Database In-Memory Machine systems can be used immediately with any application certified with Oracle Database 11g R2 and Oracle Real Application Clusters, including SAP, Oracle Fusion Applications, Oracle’s PeopleSoft, Oracle’s Siebel CRM, the Oracle E-Business Suite, and thousands of other applications. Supporting Quotes “Forward-looking enterprises are moving towards Cloud Computing architectures,” said Andrew Mendelsohn, senior vice president, Oracle Database Server Technologies. “Oracle Exadata’s unique ability to run any database application on a fully scale-out architecture using a combination of massive memory for extreme performance and low-cost disk for high capacity delivers the ideal solution for Cloud-based database deployments today.” Supporting Resources Oracle Press Release Oracle Exadata Database Machine Oracle Exadata X3-2 Database In-Memory Machine Oracle Exadata X3-8 Database In-Memory Machine Oracle Database 11g Follow Oracle Database via Blog, Facebook and Twitter Oracle OpenWorld 2012 Oracle OpenWorld 2012 Keynotes Like Oracle OpenWorld on Facebook Follow Oracle OpenWorld on Twitter Oracle OpenWorld Blog Oracle OpenWorld on LinkedIn Mark Hurd's keynote with Andy Mendelsohn and Juan Loaiza - - watch for the replay to be available soon at http://www.youtube.com/user/Oracle or http://www.oracle.com/openworld/live/on-demand/index.html

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• Offloading (Some) EBS 12 Reporting to Active Data Guard Instances

  - by Steven Chan

  For most Oracle Database users, Oracle Active Data Guard allows users to:Create a physical standby database for business continuity and disaster recoveryOffload reporting from the production database to the read-only physical standby databaseE-Business Suite customers have been able to use Active Data Guard to create physical standby databases for their EBS environments since the feature was introduced with the 11g Database.  EBS sysadmins can use the generic Active Data Guard documentation to take advantage of the Active Data Guard standby database capabilities.  I am pleased to announce that it is now possible to offload a subset of some ReportWriter-based reports -- but not all -- from a production EBS environment to an Active Data Guard physical standby database.  But before I go into the details of this newly-certified configuration, it's necessary to understand some details about what happens whenever someone attempts to access the E-Business Suite.

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• Faq and Best tips Regarding Learning Database ?

  - by AdityaGameProgrammer

  For a programmer with no prior exposure to databases What would be a good database to learn Oracle vs SQLserver vs MySQLvs PostgreSQL? I have come across lot of discussion MySQL and PostgreSQL and frankly I am confused on which to start with. Are these very different, in the sense if one had to switch, would the exposure to one be counter-productive to learning the other? Is working with databases heavily platform dependent? What exactly do people mean by Data base programming vs. administration? Do people chose databases based on the programming language used for the application developed? In general, Working with databases is it implicit that we work with some server? Does the choice of databases differ when it comes to game development? If so what factors does it differ by? What are the Best Tips that you have found to be useful when learning databases Edit: Some FAQ i had and found the same on SO What should every developer know about databases? Which database if learning from scratch in 2010? For a beginner, is there much difference between MySQL and PostgreSQL What RDBMS should I learn/use? (MySql/SQL Server/Oracle etc.) To what extent should a developer learn database? How are database programmers different from other programmers? what kind of database are used in games?

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• Protecting offline IRM rights and the error "Unable to Connect to Offline database"

  - by Simon Thorpe

  One of the most common problems I get asked about Oracle IRM is in relation to the error message "Unable to Connect to Offline database". This error message is a result of how Oracle IRM is protecting the cached rights on the local machine and if that cache has become invalid in anyway, this error is thrown. Offline rights and security First we need to understand how Oracle IRM handles offline use. The way it is implemented is one of the main reasons why Oracle IRM is the leading document security solution and demonstrates our methodology to ensure that solutions address both security and usability and puts the balance of these two in your control. Each classification has a set of predefined roles that the manager of the classification can assign to users. Each role has an offline period which determines the amount of time a user can access content without having to communicate with the IRM server. By default for the context model, which is the classification system that ships out of the box with Oracle IRM, the offline period for each role is 3 days. This is easily changed however and can be as low as under an hour to as long as years. It is also possible to switch off the ability to access content offline which can be useful when content is very sensitive and requires a tight leash. So when a user is online, transparently in the background, the Oracle IRM Desktop communicates with the server and updates the users rights and offline periods. This transparent synchronization period is determined by the server and communicated to all IRM Desktops and allows for users rights to be kept up to date without their intervention. This allows us to support some very important scenarios which are key to a successful IRM solution. A user doesn't have to make any decision when going offline, they simply unplug their laptop and they already have their offline periods synchronized to the maximum values. Any solution that requires a user to make a decision at the point of going offline isn't going to work because people forget to do this and will therefore be unable to legitimately access their content offline. If your rights change to REMOVE your access to content, this also happens in the background. This is very useful when someone has an offline duration of a week and they happen to make a connection to the internet 3 days into that offline period, the Oracle IRM Desktop detects this online state and automatically updates all rights for the user. This means the business risk is reduced when setting long offline periods, because of the daily transparent sync, you can reflect changes as soon as the user is online. Of course, if they choose not to come online at all during that week offline period, you cannot effect change, but you take that risk in giving the 7 day offline period in the first place. If you are added to a NEW classification during the day, this will automatically be synchronized without the user even having to open a piece of content secured against that classification. This is very important, consider the scenario where a senior executive downloads all their email but doesn't open any of it. Disconnects the laptop and then gets on a plane. During the flight they attempt to open a document attached to a downloaded email which has been secured against an IRM classification the user was not even aware they had access to. Because their new role in this classification was automatically synchronized their experience is a good one and the document opens. More information on how the Oracle IRM classification model works can be found in this article by Martin Abrahams. So what about problems accessing the offline rights database? So onto the core issue... when these rights are cached to your machine they are stored in an encrypted database. The encryption of this offline database is keyed to the instance of the installation of the IRM Desktop and the Windows user account. Why? Well what you do not want to happen is for someone to get their rights for content and then copy these files across hundreds of other machines, therefore getting access to sensitive content across many environments. The IRM server has a setting which controls how many times you can cache these rights on unique machines. This is because people typically access IRM content on more than one computer. Their work desktop, a laptop and often a home computer. So Oracle IRM allows for the usability of caching rights on more than one computer whilst retaining strong security over this cache. So what happens if these files are corrupted in someway? That's when you will see the error, Unable to Connect to Offline database. The most common instance of seeing this is when you are using virtual machines and copy them from one computer to the next. The virtual machine software, VMWare Workstation for example, makes changes to the unique information of that virtual machine and as such invalidates the offline database. How do you solve the problem? Resolution is however simple. You just delete all of the offline database files on the machine and they will be recreated with working encryption when the Oracle IRM Desktop next starts. However this does mean that the IRM server will think you have your rights cached to more than one computer and you will need to rerequest your rights, even though you are only going to be accessing them on one. Because it still thinks the old cache is valid. So be aware, it is good practice to increase the server limit from the default of 1 to say 3 or 4. This is done using the Enterprise Manager instance of IRM. So to delete these offline files I have a simple .bat file you can use; Download DeleteOfflineDBs.bat Note that this uses pskillto stop the irmBackground.exe from running. This is part of the IRM Desktop and holds open a lock to the offline database. Either kill this from task manager or use pskillas part of the script.

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• Letöltheto az Oracle Database Firewall 5.0

  - by Lajos Sárecz

  2010 május 20-án jelentettük be, hogy megvettük az adatbázis tuzfal megoldást fejleszto Secerno céget. Azóta viszonylag keveset lehetett hallani errol a termékrol, idehaza egyedül az oszi ITBN konferencián tartott róla eloadást Stuart Sharp szuk fél órában. Ráadásul a felvásárlás óta a terméket sem lehetett megvásárolni, hiszen a merge után folyó fejlesztések még nem voltak készen. Január 11. óta azonban letötlheto az Oracle Database Firewall 5.0 telepítoje az Oracle edelivery oldaláról az Oracle Database Product Pack-en belül Linux x86 platformra. A Database Firewall az adatbázis védelem elso vonalának tekintheto. Valós idoben monitorozza az adatbázis aktivitását a hálózaton. SQL nyelvi elemzojével rendkívül pontosan képes detektálni a külso és belso támadásokat, a jogosultatlanul, támadó szándékkal végrehajtott tranzakciókat. Az SQL nyelvi elemzojének kifinomultsága lehetové teszi a szurés közel 100%-os pontosságát és megbízhatóságát, ami azért rendkívül fontos, mert nem elég minden támadó tranzakciót kiszurni, de fontos hogy a normál üzletmenetnek megfelelo tranzakciók közül egyet se szurjön, hiszen az is komoly üzleti károkat okozhat. Az adatbázis tuzfalról több részletet tudhat meg mindenki, aki regisztrál és ellátogat a január 27-i Oracle Security Summit rendezvényünkre, ahol a tervek szerint ismét Stuart Sharp tart majd eloadást, viszont ezúttal 1 órában sokkal több részletet tud megosztani a magyar ügyfelekkel és partnerekkel. A Database Firewall eloadást megelozoen egyébként én tartok egy kb. félórás áttekintést az Oracle Database biztonsági megoldásairól.

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• MAA a Database Machine-nel, maximális rendelkezésre állás

  - by Fekete Zoltán

  Néhány napja jelent meg egy, a maximális rendelkezésre állást boncolgató Oracle fehérpapír :): Oracle Data Guard: Disaster Recovery for Sun Oracle Database Machine. Ez a dokumentum az Exadata környezetben az Oracle Data Guard használatát elemzi. Az utolsó oldalakon néhány rendkívül hasznos linket is találunk. Mire is használható a Data Guard? - katasztrófa helyzet kezelése - adatbázis gördülo upgrade - egy megoldás az Exadata környezetre migrálásra - a standby adatbázis kihasználása A Sun Oracle Database Machine háromféle konfigurációban kapható: Full Rack, Half Rack és Quarter Rack, azaz teljes, fél és negyed szekrény kiépítésben. Felfelé upgrade-elheto és akár sok Full Rack összekapcsolva is egyetlen gépként tud muködni. A határ tehát a csillagos ég! :) Hiszen a nap a legfontosabb csillagunk. A Database Machine már önmagában is magas rendelkezésreállást biztosít, hiszen minden - a muködés szempontjából fontos - minden komponense legalább duplikált! Természetesen ez az adatokra is vonatkozik. A Database Machine ideális gyors környezet mind OLTP, mind DW futtatására, mind adatbázis konszolidációra. A tranzakciós (OLTP) rendszereknél régóta fontos követelmény, hogy az elsodleges site mögött legyen egy katasztrófa site, mely át tudja venni az adatbázis-kezelés feladatát, ha árvíz, tuz, vagy más szomorú katasztrófa történne az elsodleges site-on. Manapság már az adattárházak (DW) üzemeltetésében is fontos szerepet kap az MAA architektúra, azaz a Maximum Availability Architecture. Innen letöltheto a pdf: Oracle Data Guard: Disaster Recovery for Sun Oracle Database Machine.

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• Passing data from one database to another database table (Access) (C#)

  - by SAMIR BHOGAYTA

  string conString = "Provider=Microsoft.Jet.OLEDB.4.0 ;Data Source=Backup.mdb;Jet OLEDB:Database Password=12345"; OleDbConnection dbconn = new OleDbConnection(); OleDbDataAdapter dAdapter = new OleDbDataAdapter(); OleDbCommand dbcommand = new OleDbCommand(); try { if (dbconn.State == ConnectionState.Closed) dbconn.Open(); string selQuery = "INSERT INTO [Master] SELECT * FROM [MS Access;DATABASE="+ "\\Data.mdb" + ";].[Master]"; dbcommand.CommandText = selQuery; dbcommand.CommandType = CommandType.Text; dbcommand.Connection = dbconn; int result = dbcommand.ExecuteNonQuery(); } catch(Exception ex) {}

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• Minimal set of critical database operations

  - by Juan Carlos Coto

  In designing the data layer code for an application, I'm trying to determine if there is a minimal set of database operations (both single and combined) that are essential for proper application function (i.e. the database is left in an expected state after every data access call). Is there a way to determine the minimal set of database operations (functions, transactions, etc.) that are critical for an application to function correctly? How do I find it? Thanks very much!

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