Search Results

Search found 6723 results on 269 pages for 'django models'.

Page 14/269 | < Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >

  • Django: customizing the message after a successful form save

    - by chiurox
    Hello, whenever I save a model in my Admin interface, it displays the usual "successfully saved message." However, I want to know if it's possible to customize this message because I have a situation where I want to warn the user about what he just saved and the implications of these actions. class PlanInlineFormset(forms.models.BaseInlineFormset): def clean(self): ### How can I detect the changes? ### (self.changed_data doesn't work because it's an inline) ### and display what he/she just changed at the top AFTER the successful save? class PlanInline(admin.TabularInline): model = Plan formset = PlanInlineFormset

    Read the article

  • Left Join with a OneToOne field in Django

    - by jamida
    I have 2 tables, simpleDB_all and simpleDB_some. The "all" table has an entry for every item I want, while the "some" table has entries only for some items that need additional information. The Django models for these are: class all(models.Model): name = models.CharField(max_length=40) important_info = models.CharField(max_length=40) class some(models.Model): all_key = models.OneToOneField(all) extra_info = models.CharField(max_length=40) I'd like to create a view that shows every item in "all" with the extra info if it exists in "some". Since I'm using a 1-1 field I can do this with almost complete success: allitems = all.objects.all() for item in allitems: print item.name, item.important_info, item.some.extra_info but when I get to the item that doesn't have a corresponding entry in the "some" table I get a DoesNotExist exception. Ideally I'd be doing this loop inside a template, so it's impossible to wrap it around a "try" clause. Any thoughts? I can get the desired effect directly in SQL using a query like this: SELECT all.name, all.important_info, some.extra_info FROM all LEFT JOIN some ON all.id = some.all_key_id; But I'd rather not use raw SQL.

    Read the article

  • extending django usermodel

    - by imran-glt
    Hi i am trying to create a signup form for my django app. for this i have extended the user model. This is my Forms.py from contact.models import register from django import forms from django.contrib import auth class registerForm(forms.ModelForm): class Meta: model=register fields = ('latitude', 'longitude', 'status') class Meta: model = auth.models.User # this gives me the User fields fields = ('username', 'first_name', 'last_name', 'email') and this is my model.py from django.db import models from django.contrib.auth.models import User STATUS_CHOICES = ( ('Online', 'Online.'), ('Busy', 'Busy.'), ('AppearOffline', 'AppearOffline.'),) class register(models.Model): user = models.ForeignKey('auth.User', unique = True) latitude = models.DecimalField(max_digits=8, decimal_places=6) longitude = models.DecimalField(max_digits=8, decimal_places=6) status = models.CharField(max_length=8,choices=STATUS_CHOICES, blank= True, null=True) i dont know where i am making a mistake. the users passwords are not accepted at the login and the latitude and logitude are not saved against the created user user. i am fiarly new to django and dont know what to do any body have any solution .?

    Read the article

  • django admin gives warning "Field 'X' doesn't have a default value"

    - by noam
    I have created two models out of an existing legacy DB , one for articles and one for tags that one can associate with articles: class Article(models.Model): article_id = models.AutoField(primary_key=True) text = models.CharField(max_length=400) class Meta: db_table = u'articles' class Tag(models.Model): tag_id = models.AutoField(primary_key=True) tag = models.CharField(max_length=20) article=models.ForeignKey(Article) class Meta: db_table = u'article_tags' I want to enable adding tags for an article from the admin interface, so my admin.py file looks like this: from models import Article,Tag from django.contrib import admin class TagInline(admin.StackedInline): model = Tag class ArticleAdmin(admin.ModelAdmin): inlines = [TagInline] admin.site.register(Article,ArticleAdmin) The interface looks fine, but when I try to save, I get: Warning at /admin/webserver/article/382/ Field 'tag_id' doesn't have a default value

    Read the article

  • Django: Geocoding an address on form submission?

    - by User
    Trying to wrap my head around django forms and the django way of doing things. I want to create a basic web form that allows a user to input an address and have that address geocoded and saved to a database. I created a Location model: class Location(models.Model): address = models.CharField(max_length=200) city = models.CharField(max_length=100) state = models.CharField(max_length=100, null=True) postal_code = models.CharField(max_length=100, null=True) country = models.CharField(max_length=100) latitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) longitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) And defined a form: class LocationForm(forms.ModelForm): class Meta: model = models.Location exclude = ('latitude','longitude') In my view I'm using form.save() to save the form. This works and saves an address to the database. I created a module to geocode an address. I'm not sure what the django way of doing things is, but I guess in my view, before I save the form, I need to geocode the address and set the lat and long. How do I set the latitude and longitude before saving?

    Read the article

  • Model in sub-directory via app_label?

    - by prometheus
    In order to place my models in sub-folders I tried to use the app_label Meta field as described here. My directory structure looks like this: project apps foo models _init_.py bar_model.py In bar_model.py I define my Model like this: from django.db import models class SomeModel(models.Model): field = models.TextField() class Meta: app_label = "foo" I can successfully import the model like so: from apps.foo.models.bar_model import SomeModel However, running: ./manage.py syncdb does not create the table for the model. In verbose mode I do see, however, that the app "foo" is properly recognized (it's in INSTALLED_APPS in settings.py). Moving the model to models.py under foo does work. Is there some specific convention not documented with app_label or with the whole mechanism that prevents this model structure from being recognized by syncdb?

    Read the article

  • How can I display multiple django modelformset forms in a grouped fieldsets?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results (after form validation) base_models = base_formset.save(commit=False) like_models = like_formset.save(commit=False) for base_model, likes_model in map(None, base_models, likes_models): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements. EDIT: Updated the problem statement to be more clear about what exactly I'm processing (I'm processing models not forms in the for loop)

    Read the article

  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

    Read the article

  • Putting a django login form on every page

    - by asciitaxi
    I'd like the login form (AuthenticationForm from django.contrib.auth) to appear on every page in my site if the user is not logged in. When the user logs in, they will be redirected to the same page. If there is an error, the error will be shown on the same page with the form. I suppose you'd need a context processor to provide the form to every template. But, then you'd also need every view to handle the posted form? Does this mean you need to create some middleware? I'm a bit lost. Is there an accepted way of doing this?

    Read the article

  • Django templates onchange data

    - by Hulk
    In the following code, i have a drop down box and a multi select box. My question is that using javascript and django .how will i changes the designation with changes in names from drop down box. <tr><td> name:</td><td><select id="name" name="name">{% for name in names %} <option value="{{name.id}}" {% for selected_id in names %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.name}}</option>{% endfor %} </select> </td></tr> {% for desg in designation %} <tr><td><p>Topics:</td><td> <select id="desg" name="desg" multiple="multiple"> <option value="{{desg.id}}" >{{desg.desg}}</option> </select></p></td></tr> {% endfor %} Thanks..

    Read the article

  • Get the currently saved object in a view in Django

    - by mridang
    Hi, I has a Django view which is accessed through an AJAX call. It's a pretty simple one — all it does is simply pass the request to a form object and save the data. Here's a snippet from my view: form = AddSiteForm(request.user, request.POST) if form.is_valid(): obj = form.save(commit=False) obj.user = request.user obj.save() data['status'] = 'success' data['html'] = render_to_string('site.html', locals(), context_instance=RequestContext(request)) return HttpResponse(simplejson.dumps(data), mimetype='application/json') How do I get the currently saved object (including the internally generated id column) and pass it to the template? Any help guys? Mridang

    Read the article

  • How to test custom template tags in Django?

    - by Mark Lavin
    I'm adding a set of template tags to a Django application and I'm not sure how to test them. I've used them in my templates and they seem to be working but I was looking for something more formal. The main logic is done in the models/model managers and has been tested. The tags simply retrieve data and store it in a context variable such as {% views_for_object widget as views %} """ Retrieves the number of views and stores them in a context variable. """ # or {% most_viewed_for_model main.model_name as viewed_models %} """ Retrieves the ViewTrackers for the most viewed instances of the given model. """ So my question is do you typically test your template tags and if you do how do you do it?

    Read the article

  • Django snippet with logic

    - by etam
    Hi, is there a way to create a Django snippet that has logic? I think about something like contact template tag: {% contact_form %} with template: <form action="send_contact_form" method="POST">...</form> with logic: def send_contact_form(): ... I want to be able to use it anywhere in my projects. It should work only by specifying 1 template tag... Do you know what I mean? Is it possible? Thanks in advance, Etam.

    Read the article

  • Django-allauth redirected to connections

    - by camara90100
    I'm using django-allauth to signup users with Facebook, and I'm setting the ACCOUNT_EMAIL_REQUIRED to True so when a user doesn't have email saved on his account I get redirected to the allauth/templates/socialaccount/Signup.html and when I use a test user to enter a valid email, I get redirect to "connections.html" which then asks me to choose one of the social accounts and remove it. and the form action method is set to 'connections url' so it becomes an infinite loop. anyone knows what's wrong? here's my settings SOCIALACCOUNT_PROVIDERS = \ { 'facebook': { 'SCOPE': ['email', 'publish_stream'], # 'AUTH_PARAMS': { 'auth_type': 'reauthenticate' }, 'METHOD': 'js_sdk' , 'LOCALE_FUNC': lambda request: 'en_US'}} ACCOUNT_EMAIL_REQUIRED =True ACCOUNT_ADAPTER = 'profiles.adapter.MyAccountAdapter' SOCIALACCOUNT_ADAPTER ='profiles.adapter.MySocialAccountAdapter'

    Read the article

  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

    Read the article

  • Django - Problem with models/manager to organise a query...

    - by user296644
    Hi, I have an application to count the number of access to an object for each website in a same database. class SimpleHit(models.Model): """ Hit is the hit counter of a given object """ content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') site = models.ForeignKey(Site) hits_total = models.PositiveIntegerField(default=0, blank=True) [...] class SimpleHitManager(models.Manager): def get_query_set(self): print self.model._meta.fields qset = super(SimpleHitManager, self).get_query_set() qset = qset.filter(hits__site=settings.SITE_ID) return qset class SimpleHitBase(models.Model): hits = generic.GenericRelation(SimpleHit) objects = SimpleHitManager() _hits = None def _db_get_hits(self, only=None): if self._hits == None: try: self._hits = self.hits.get(site=settings.SITE_ID) except SimpleHit.DoesNotExist: self._hits = SimpleHit() return self._hits @property def hits_total(self): return self._db_get_hits().hits_total [...] class Meta: abstract = True And I have a model like: class Model(SimpleHitBase): name = models.CharField(max_length=255) url = models.CharField(max_length=255) rss = models.CharField(max_length=255) creation = AutoNowAddDateTimeField() update = AutoNowDateTimeField() So, my problem is this one: when I call Model.objects.all(), I would like to have one request for the SQL (not two). In this case: one for Model in order to have information and one for the hits in order to have the counter (hits_total). This is because I cannot call directly hits.hits_total (due to SITE_ID?). I have tried select_related, but it seems to do not work... Question: - How can I add column automatically like (SELECT hits.hits_total, model.* FROM [...]) to the queryset? - Or use a functional select_related with my models? I want this model could be plugable on all other existing model. Thank you, Best regards.

    Read the article

  • Subclassed django models with integrated querysets

    - by outofculture
    Like in this question, except I want to be able to have querysets that return a mixed body of objects: >>> Product.objects.all() [<SimpleProduct: ...>, <OtherProduct: ...>, <BlueProduct: ...>, ...] I figured out that I can't just set Product.Meta.abstract to true or otherwise just OR together querysets of differing objects. Fine, but these are all subclasses of a common class, so if I leave their superclass as non-abstract I should be happy, so long as I can get its manager to return objects of the proper class. The query code in django does its thing, and just makes calls to Product(). Sounds easy enough, except it blows up when I override Product.__new__, I'm guessing because of the __metaclass__ in Model... Here's non-django code that behaves pretty much how I want it: class Top(object): _counter = 0 def __init__(self, arg): Top._counter += 1 print "Top#__init__(%s) called %d times" % (arg, Top._counter) class A(Top): def __new__(cls, *args, **kwargs): if cls is A and len(args) > 0: if args[0] is B.fav: return B(*args, **kwargs) elif args[0] is C.fav: return C(*args, **kwargs) else: print "PRETENDING TO BE ABSTRACT" return None # or raise? else: return super(A).__new__(cls, *args, **kwargs) class B(A): fav = 1 class C(A): fav = 2 A(0) # => None A(1) # => <B object> A(2) # => <C object> But that fails if I inherit from django.db.models.Model instead of object: File "/home/martin/beehive/apps/hello_world/models.py", line 50, in <module> A(0) TypeError: unbound method __new__() must be called with A instance as first argument (got ModelBase instance instead) Which is a notably crappy backtrace; I can't step into the frame of my __new__ code in the debugger, either. I have variously tried super(A, cls), Top, super(A, A), and all of the above in combination with passing cls in as the first argument to __new__, all to no avail. Why is this kicking me so hard? Do I have to figure out django's metaclasses to be able to fix this or is there a better way to accomplish my ends?

    Read the article

  • django: Display image in admin interface

    - by Oleg Tarasenko
    Hi, I've defined a model which contains a link an image. Is there a way to display the image in the model items list. (e.g. if I defined an article this way: class Article(models.Model): url = models.CharField(max_length = 200, unique = True, help_text="/lessons/") title = models.CharField(max_length = 500) img = models.CharField(max_length = 100) # Contains path to image def __unicode__(self): return u"%s" %title ) Is there a way to display image together with title?

    Read the article

  • Crossed import in django

    - by Kuhtraphalji
    On example, i have 2 apps: alpha and beta in alpha/models.py import of model from beta.models and in beta/models.py import of model from alpha.models manage.py validate says that ImportError: cannot import name ModelName how to solve this problem?

    Read the article

  • Images missing after moving Django to new server

    - by miszczu
    I'm moving Django project to new server. I'm newbie in Django, and I don't know where should be upload folder. There are all images which should be displayed on website. In config file I haven't seen upload folder I could specify, so I'm guessing it always should be the same location for django projects or I just can't find it. Locations are saved in database. When I've put uploaded files into media folder, so url was like domain.co.uk/media/upload/media/images/year/month/day/image_name.ext and the same is on the old website, images on website ware still missing. All images are visible if I put url by hand, but django doesn't seems to see files. Also I check django log file: 2012-05-30 09:13:33,393 ERROR render: Thumbnail tag failed: [in /usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/templatetags/thumbnail.py (line 49)] Traceback (most recent call last): File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/templatetags/thumbnail.py", line 45, in render return self._render(context) File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/templatetags/thumbnail.py", line 97, in _render file_, geometry, **options File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/base.py", line 50, in get_thumbnail cached = default.kvstore.get(thumbnail) File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/kvstores/base.py", line 25, in get return self._get(image_file.key) File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/kvstores/base.py", line 123, in _get value = self._get_raw(add_prefix(key, identity)) File "/usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/kvstores/cached_db_kvstore.py", line 26, in _get_raw value = KVStoreModel.objects.get(key=key).value File "/usr/lib/python2.6/site-packages/django/db/models/manager.py", line 132, in get return self.get_query_set().get(*args, **kwargs) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 344, in get num = len(clone) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 82, in __len__ self._result_cache = list(self.iterator()) File "/usr/lib/python2.6/site-packages/django/db/models/query.py", line 273, in iterator for row in compiler.results_iter(): File "/usr/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 680, in results_iter for rows in self.execute_sql(MULTI): File "/usr/lib/python2.6/site-packages/django/db/models/sql/compiler.py", line 735, in execute_sql cursor.execute(sql, params) File "/usr/lib/python2.6/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/usr/lib/python2.6/site-packages/django/db/backends/mysql/base.py", line 86, in execute return self.cursor.execute(query, args) File "/usr/lib64/python2.6/site-packages/MySQLdb/cursors.py", line 174, in execute self.errorhandler(self, exc, value) File "/usr/lib64/python2.6/site-packages/MySQLdb/connections.py", line 36, in defaulterrorhandler raise errorclass, errorvalue DatabaseError: (1146, "Table 'thumbnail_kvstore' doesn't exist") 2012-05-30 09:13:33,396 DEBUG execute: (0.000) SELECT `freetext_freetext`.`id`, `freetext_freetext`.`key`, `freetext_freetext`.`content`, `freetext_freetext`.`active` FROM `freetext_freetext` WHERE (`freetext_freetext`.`active` = True AND `freetext_freetext`.`key` = office-closed-message ); args=(True, u'office-closed-message') [in /usr/lib/python2.6/site-packages/django/db/backends/util.py (line 44)] 2012-05-30 09:13:33,399 DEBUG execute: (0.000) SELECT `menus_menu`.`id`, `menus_menu`.`name`, `menus_menu`.`slug`, `menus_menu`.`base_url`, `menus_menu`.`description`, `menus_menu`.`enabled` FROM `menus_menu` WHERE (`menus_menu`.`enabled` = True AND `menus_menu`.`slug` = about ); args=(True, u'about') [in /usr/lib/python2.6/site-packages/django/db/backends/util.py (line 44)] 2012-05-30 09:13:33,401 DEBUG execute: (0.000) SELECT `menus_menuitem`.`id`, `menus_menuitem`.`menu_id`, `menus_menuitem`.`title`, `menus_menuitem`.`url`, `menus_menuitem`.`order` FROM `menus_menuitem` INNER JOIN `menus_menu` ON (`menus_menuitem`.`menu_id` = `menus_menu`.`id`) WHERE `menus_menu`.`slug` = about ORDER BY `menus_menuitem`.`order` ASC; args=(u'about',) [in /usr/lib/python2.6/site-packages/django/db/backends/util.py (line 44)] 2012-05-30 09:13:33,404 DEBUG execute: (0.000) SELECT `freetext_freetext`.`id`, `freetext_freetext`.`key`, `freetext_freetext`.`content`, `freetext_freetext`.`active` FROM `freetext_freetext` WHERE (`freetext_freetext`.`active` = True AND `freetext_freetext`.`key` = contactdetails-footer ); args=(True, u'contactdetails-footer') [in /usr/lib/python2.6/site-packages/django/db/backends/util.py (line 44)] I checked database and there is no table calls thumbnail_kvstore, but I have database backup, and in backup files this table doesn't exist. All uploaded files I get are in media/uploads/media/. Also I'm getting errors on some pages: Syntax error. Expected: ``thumbnail source geometry [key1=val1 key2=val2...] as var`` /usr/lib/python2.6/site-packages/sorl_thumbnail-11.12-py2.6.egg/sorl/thumbnail/templatetags/thumbnail.py in __init__, line 72 In template /var/www/vhosts/domain.co.uk/sites/apps/shop/products/templates/products/product_detail.html, error at line 34 {% thumbnail image.file "800x700" detail as zoom %} Maybe some modules I install are not in the right version. Dont know how to fix it. Im using, CentOS 6, mod_wsgi, apache, python 2.6. Update 1.0: On the old server was Django 1.3, on the new one is Django 1.3.1 Update 1.1: I this i know where is the problem. I tried python manage.py syncdb and this is output: Syncing... Creating tables ... The following content types are stale and need to be deleted: orders | ordercontact Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'. Type 'yes' to continue, or 'no' to cancel: no Installing custom SQL ... Installing indexes ... No fixtures found. Synced: > django.contrib.auth > django.contrib.contenttypes > django.contrib.sessions > django.contrib.sites > django.contrib.messages > django.contrib.admin > django.contrib.admindocs > django.contrib.markup > django.contrib.sitemaps > django.contrib.redirects > django_filters > freetext > sorl.thumbnail > django_extensions > south > currencies > pagination > tagging > honeypot > core > faq > logentry > menus > news > shop > shop.cart > shop.orders Not synced (use migrations): - dbtemplates - contactform - links - media - pages - popularity - testimonials - shop.brands - shop.collections - shop.discount - shop.pricing - shop.product_types - shop.products - shop.shipping - shop.tax (use ./manage.py migrate to migrate these) Next I run python manage.py migrate, and thats what i get: Running migrations for dbtemplates: - Migrating forwards to 0002_auto__del_unique_template_name. > dbtemplates:0001_initial ! Error found during real run of migration! Aborting. ! Since you have a database that does not support running ! schema-altering statements in transactions, we have had ! to leave it in an interim state between migrations. ! You *might* be able to recover with: = DROP TABLE `django_template` CASCADE; [] = DROP TABLE `django_template_sites` CASCADE; [] ! The South developers regret this has happened, and would ! like to gently persuade you to consider a slightly ! easier-to-deal-with DBMS. ! NOTE: The error which caused the migration to fail is further up. Traceback (most recent call last): File "manage.py", line 13, in <module> execute_manager(settings) File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 81, in run_migration migration_function() File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/usr/lib/python2.6/site-packages/django_dbtemplates-1.3-py2.6.egg/dbtemplates/migrations/0001_initial.py", line 18, in forwards ('last_changed', self.gf('django.db.models.fields.DateTimeField')(default=datetime.datetime.now)), File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/usr/lib/python2.6/site-packages/South-0.7.3-py2.6.egg/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/usr/lib/python2.6/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/usr/lib/python2.6/site-packages/django/db/backends/mysql/base.py", line 86, in execute return self.cursor.execute(query, args) File "/usr/lib64/python2.6/site-packages/MySQLdb/cursors.py", line 174, in execute self.errorhandler(self, exc, value) File "/usr/lib64/python2.6/site-packages/MySQLdb/connections.py", line 36, in defaulterrorhandler raise errorclass, errorvalue _mysql_exceptions.OperationalError: (1050, "Table 'django_template' already exists") Also i run python manage.py migrate --list, and uotput is: dbtemplates (*) 0001_initial (*) 0002_auto__del_unique_template_name contactform (*) 0001_initial (*) 0002_auto__add_callback (*) 0003_auto__add_field_callback_notes (*) 0004_auto__add_field_callback_is_closed__add_field_callback_closed (*) 0005_auto__add_field_callback_url (*) 0006_auto__add_contact (*) 0007_auto__add_field_contact_category (*) 0008_auto__add_field_contact_url links (*) 0001_initial (*) 0002_auto__add_field_category_enabled__add_field_category_order media (*) 0001_initial (*) 0002_auto__del_field_image_external_url__add_field_image_link_url__del_fiel (*) 0003_add_model_FileAttachment (*) 0004_auto__chg_field_file_slug__chg_field_image_slug (*) 0005_auto__chg_field_image_file (*) 0006_auto__chg_field_file_file pages (*) 0001_initial (*) 0002_auto__chg_field_page_meta_description__chg_field_page_meta_title__chg_ (*) 0003_auto__add_field_page_show_in_sitemap (*) 0004_auto__add_field_page_changefreq__add_field_page_priority popularity (*) 0001_initial testimonials (*) 0001_initial (*) 0002_auto__add_field_testimonial_is_featured brands (*) 0001_initial (*) 0002_auto__add_field_brand_template (*) 0003_auto__chg_field_brand_meta_description__chg_field_brand_meta_title__ch (*) 0004_auto__add_field_brand_url (*) 0005_auto__del_field_brand_image__add_field_brand_logo collections (*) 0001_initial (*) 0002_auto__add_field_collection_discount (*) 0003_auto__chg_field_collection_meta_description__chg_field_collection_meta (*) 0004_auto__add_field_collection_is_featured (*) 0005_auto__add_field_collection_order discount (*) 0001_initial (*) 0002_added_field_discount_description (*) 0003_auto__add_field_discountvoucher_automatic (*) 0004_auto__add_field_discountvoucher_collection (*) 0005_auto__del_field_discountvoucher_collection (*) 0006_auto__chg_field_discountvoucher_expiry_date pricing (*) 0001_initial (*) 0002_auto__add_pricingrule product_types (*) 0001_initial (*) 0002_auto__add_field_producttype_meta_title__add_field_producttype_meta_des (*) 0003_auto__add_field_producttype_summary__add_field_producttype_description products (*) 0001_initial (*) 0002_auto__del_field_product_is_featured (*) 0003_auto__chg_field_product_meta_keywords__chg_field_product_meta_descript (*) 0004_auto shipping (*) 0001_initial (*) 0002_auto__add_field_shippingmethod_includes_tax__add_field_shippingmethod_ (*) 0003_auto__add_field_shippingmethod_order (*) 0004_auto__del_field_shippingmethod_tax_rate__del_field_shippingmethod_incl (*) 0005_auto__del_field_shippingrule_enabled tax (*) 0001_initial (*) 0002_auto__add_field_taxrate_internal_name (*) 0003_initial_internal_names (*) 0004_auto__add_unique_taxrate_internal_name (*) 0005_force_unique_taxrate_name (*) 0006_auto__add_unique_taxrate_name After that some images source were something like this: src="cache/1e/bd/1ebd719910aa843238028edd5fe49e71.jpg" Is any1 could help me with syncdb pledase?

    Read the article

  • Django many to many annotations and filters

    - by dl8
    So I have two models, Person and Film where they're in a many to many relationship. My goal is to grab a film, and output the persons that have also appeared in at least 10 films. For example I can get the count individually by: >>> Person.objects.get(short__istartswith = "Matt Damon").film_set.count() 71 However, if I try to filter all the actors of a particular film out: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film')).filter(film_count__gte=10) [] it returns an empty set since if I manually look at everyone's film_count it's 1, even though an actor such as Matt Damon (as seen above) has been in 71 films in my db. As you can see with this query, the annotation doesn't work: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_count 1 >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_set.count() 7 and I can't seem to figure out a way to filter it by the film_set.count()

    Read the article

  • How to save link with tag e parameters in TextField

    - by xRobot
    I have this simple Post model: class Post(models.Model): title = models.CharField(_('title'), max_length=60, blank=True, null=True) body = models.TextField(_('body')) blog = models.ForeignKey(Blog, related_name="posts") user = models.ForeignKey(User) I want that when I insert in the form the links, the these links are saved in the body from this form: http://www.example.com or www.example.com to this form ( with tag and rel="nofollow" parameter ): <a href="http://www.example.com" rel="nofollow">www.example.com</a> How can I do this ? Thanks ^_^

    Read the article

  • How to save links with tags and parameters in TextField

    - by xRobot
    I have this simple Post model: class Post(models.Model): title = models.CharField(_('title'), max_length=60, blank=True, null=True) body = models.TextField(_('body')) blog = models.ForeignKey(Blog, related_name="posts") user = models.ForeignKey(User) I want that when I insert in the form the links, then these links are saved in the body from this form: http://www.example.com or www.example.com to this form ( with tag and rel="nofollow" parameter ): <a href="http://www.example.com" rel="nofollow">www.example.com</a> How can I do this ? Thanks ^_^

    Read the article

  • Are Django template tags cached?

    - by thebossman
    I have gone through the (painful) process of writing a custom template tag for use in Django. It is registered as an inclusion_tag so that it renders a template. However, this tag breaks as soon as I try to change something. I've tried changing the number of parameters and correspondingly changing the parameters when it's called. It's clear the new tag code isn't being loaded, because an error is thrown stating that there is a mismatch in the number of parameters, and it's evident that it's attempting to call the old function. The same problem occurs if I try to change the name of the template being rendered and correspondingly change the name of the template on disk. It continues to try to call the old template. I've tried clearing old .pyc files with no luck. Overall, the system is acting as though it's caching the template tags, likely due to the register command. I have dug through endless threads trying to find out if this is so, but all could find it James Bennett stating here that register doesn't do anything. Please help!

    Read the article

  • Django DRY Feeds

    - by Mandx
    I'm using the Django Feeds Framework and it's really nice, very intuitive and easy to use. But, I think there is a problem when creating links to feeds in HTML. For example: <link rel="alternate" type="application/rss+xml" title="{{ feed_title }}" href="{{ url_of_feed }}" /> Link's HREF attribute can be easily found out, just use reverse() But, what about the TITLE attribute? Where the template engine should look for this? Even more, what if the feed is build up dinamically and the title depends on parameters (like this)? I can't come up with a solution that "seems" DRY to me... All that I can come up with is using context processors o template tags, but it gets messy when the context procesor/template tag has to find parameters to construct the Feed class, and writing this I realize I don't even know how to create a Feed instance myself within the view. If I put all this logic in the view, it would not be just one view. Also, the value for TITLE would be in the view AND in the feed.

    Read the article

< Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >