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  • Django - how to make ImageField/FileField optional?

    - by ilya
    class Product(models.Model): ... image = models.ImageField(upload_to = generate_filename, blank = True) When I use ImageField (blank=True) and do not select image into admin form, exception occures. In django code you can see this: class FieldFile(File): .... def _require_file(self): if not self: raise ValueError("The '%s' attribute has no file associated with it." % self.field.name) def _get_file(self): self._require_file() ... Django trac has ticket #13327 about this problem, but seems it can't be fixed soon. How to make these field optional?

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  • Django: Data corrupted after loading? (possible programmer error)

    - by Rosarch
    I may be loading data the wrong way. excerpt of data.json: { "pk": "1", "model": "myapp.Course", "fields": { "name": "Introduction to Web Design", "requiredFor": [9], "offeringSchool": 1, "pre_reqs": [], "offeredIn": [1, 5, 9] } }, I run python manage.py loaddata -v2 data: Installed 36 object(s) from 1 fixture(s) Then, I go to check the above object using the Django shell: >>> info = Course.objects.filter(id=1) >>> info.get().pre_reqs.all() [<Course: Intermediate Web Programming>] # WRONG! There should be no pre-reqs >>> from django.core import serializers >>> serializers.serialize("json", info) '[{"pk": 1, "model": "Apollo.course", "fields": {"pre_reqs": [11], "offeredIn": [1, 5, 9], "offeringSchool": 1, "name": "Introduction to Web Design", "requiredFor": [9]}}]' The serialized output of the model is not the same as the input that was given to loaddata. The output has a non-empty pre_req list, whereas the input's pre_reqs field is empty. What am I doing wrong?

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  • Aggregation over a few models - Django

    - by RadiantHex
    Hi folks, I'm trying to compute the average of a field over various subsets of a queryset. Player.objects.order_by('-score').filter(sex='male').aggregate(Avg('level')) This works perfectly! But... if I try to compute it for the top 50 players it does not work. Player.objects.order_by('-score').filter(sex='male')[:50].aggregate(Avg('level')) This last one returns the exact same result as the query above it, which is wrong. What am I doing wrong? Help would be very much appreciated!

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  • Django: Summing values

    - by Anry
    I have a two Model - Project and Cost. class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() I must return the sum of costs for each project. view.py: from mypm.costs.models import Project, Cost from django.shortcuts import render_to_response from django.db.models import Avg, Sum def index(request): #... return render_to_response('index.html',... How?

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  • How to deal with multiple sub-type of one super-type in Django admin

    - by Henri
    What would be the best solution for adding/editing multiple sub-types. E.g a super-type class Contact with sub-type class Client and sub-type class Supplier. The way shown here works, but when you edit a Contact you get both inlines i.e. sub-type Client AND sub-type Supplier. So even if you only want to add a Client you also get the fields for Supplier of vice versa. If you add a third sub-type , you get three sub-type field groups, while you actually only want one sub-type group, in the mentioned example: Client. E.g.: class Contact(models.Model): contact_name = models.CharField(max_length=128) class Client(models.Model): contact = models.OneToOneField(Contact, primary_key=True) user_name = models.CharField(max_length=128) class Supplier(models.Model): contact.OneToOneField(Contact, primary_key=True) company_name = models.CharField(max_length=128) and in admin.py class ClientInline(admin.StackedInline): model = Client class SupplierInline(admin.StackedInline): model = Supplier class ContactAdmin(admin.ModelAdmin): inlines = (ClientInline, SupplierInline,) class ClientAdmin(admin.ModelAdmin): ... class SupplierAdmin(admin.ModelAdmin): ... Now when I want to add a Client, i.e. only a Client I edit Contact and I get the inlines for both Client and Supplier. And of course the same for Supplier. Is there a way to avoid this? When I want to add/edit a Client that I only see the Inline for Client and when I want to add/edit a Supplier that I only see the Inline for Supplier, when adding/editing a Contact? Or perhaps there is a different approach. Any help or suggestion will be greatly appreciated.

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Django models & Python class attributes

    - by Geo
    The tutorial on the django website shows this code for the models: from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() Now, each of those attribute, is a class attribute, right? So, the same attribute should be shared by all instances of the class. A bit later, they present this code: class Poll(models.Model): # ... def __unicode__(self): return self.question class Choice(models.Model): # ... def __unicode__(self): return self.choice How did they turn from class attributes into instance attributes? Did I get class attributes wrong?

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  • Django Form for date range

    - by gramware
    I am trying to come up with a form that lets the user select a date range to generate a web query in Django. I am having errors getting the date to filter with in my view, I am unable to strip the date. Here is my forms.py class ReportFiltersForm(forms.Form): start_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) end_date = forms.DateField(input_formats='%Y,%m,%d',widget=SelectDateWidget()) And my view if request.method == 'POST': form = ReportFiltersForm(request.POST) sdy = request.POST['start_date_year'] sdm = request.POST['start_date_month'] sdd = request.POST['start_date_day'] edy = request.POST['end_date_year'] edm = request.POST['end_date_month'] edd = request.POST['end_date_day'] start_date= datetime.date(sdy, sdm, sdd) end_date= datetime.date(edy, edm,edd) Traceback Traceback (most recent call last): File "/usr/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py", line 92, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/home/projects/acms/cms/views.py", line 470, in eventreports start_date= datetime.date(sdy, sdm, sdd) TypeError: an integer is required

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  • Detect the language & django locale-url

    - by mamcx
    I want to deploy a website in english & spanish and detect the user browser languaje & redirect to the correct locale site. My site is www.elmalabarista.com I install django-localeurl, but I discover that the languaje is not correctly detected. This are my middlewares: MIDDLEWARE_CLASSES = ( 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware', 'middleware.feedburner.FeedburnerMiddleware', 'lib.threadlocals.ThreadLocalsMiddleware', 'middleware.url.UrlMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'maintenancemode.middleware.MaintenanceModeMiddleware', 'middleware.redirect.RedirectMiddleware', 'openidconsumer.middleware.OpenIDMiddleware', 'django.middleware.doc.XViewMiddleware', 'middleware.ajax_errors.AjaxMiddleware', 'pingback.middleware.PingbackMiddleware', 'localeurl.middleware.LocaleURLMiddleware', 'multilingual.flatpages.middleware.FlatpageFallbackMiddleware', 'django.middleware.common.CommonMiddleware', ) But ALWAYS the site get to US despite the fact my OS & Browser setup is spanish. LANGUAGES = ( ('en', ugettext('English')), ('es', ugettext('Spanish')), ) DEFAULT_LANGUAGE = 1 Then, I hack the middleware of locale-url and do this: def process_request(self, request): locale, path = self.split_locale_from_request(request) if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path if not locale: locale = settings.LANGUAGE_CODE translation.activate(locale) request.LANGUAGE_CODE = translation.get_language() However, this detect fine the language but redirect the "en" urls to "es". So is impossible navigate in english. UPDATE: This is the final code (after the input from Carl Meyer) with a fix for the case of "/": def process_request(self, request): locale, path = self.split_locale_from_request(request) if (not locale) or (locale==''): if request.META.has_key('HTTP_ACCEPT_LANGUAGE'): locale = utils.supported_language(request.META['HTTP_ACCEPT_LANGUAGE'].split(',')[0]) else: locale = settings.LANGUAGE_CODE locale_path = utils.locale_path(path, locale) if locale_path != request.path_info: if request.META.get("QUERY_STRING", ""): locale_path = "%s?%s" % (locale_path, request.META['QUERY_STRING']) return HttpResponseRedirect(locale_path) request.path_info = path translation.activate(locale) request.LANGUAGE_CODE = translation.get_language()

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  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

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  • How do I filter values in a Django form using ModelForm?

    - by malandro95
    I am trying to use the ModelForm to add my data. It is working well, except that the ForeignKey dropdown list is showing all values and I only want it to display the values that a pertinent for the logged in user. Here is my model for ExcludedDate, the record I want to add: class ExcludedDate(models.Model): date = models.DateTimeField() reason = models.CharField(max_length=50) user = models.ForeignKey(User) category = models.ForeignKey(Category) recurring = models.ForeignKey(RecurringExclusion) def __unicode__(self): return self.reason Here is the model for the category, which is the table containing the relationship that I'd like to limit by user: class Category(models.Model): name = models.CharField(max_length=50) user = models.ForeignKey(User, unique=False) def __unicode__(self): return self.name And finally, the form code: class ExcludedDateForm(ModelForm): class Meta: model = models.ExcludedDate exclude = ('user', 'recurring',) How do I get the form to display only the subset of categories where category.user equals the logged in user?

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  • How can I disable a model field in a django form

    - by jammon
    I have a model like this: class MyModel(models.Model): REGULAR = 1 PREMIUM = 2 STATUS_CHOICES = ((REGULAR, "regular"), (PREMIUM, "premium")) name = models.CharField(max_length=30) status = models.IntegerField(choices = STATUS_CHOICES, default = REGULAR) class MyForm(forms.ModelForm): class Meta: model = models.MyModel In a view I initialize one field and try to make it non-editable: myform = MyForm(initial = {'status': requested_status}) myform.fields['status'].editable = False But the user can still change that field. What's the real way to accomplish what I'm after?

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  • Django: select_related and GenericRelation

    - by Parand
    Does select_related work for GenericRelation relations, or is there a reasonable alternative? At the moment Django's doing individual sql calls for each item in my queryset, and I'd like to avoid that using something like select_related. class Claim(models.Model): proof = generic.GenericRelation(Proof) class Proof(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') I'm selecting a bunch of Claims, and I'd like the related Proofs to be pulled in instead of queried individually.

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  • Django menu item sorting

    - by doktorno
    Hi i've got MenuItem model : MenuItem(models.Model) name=models.CharField(max_length=50) url = models.URLField() position = models.IntegerField() Class Meta: ordering =['position'] then i'm retriving it by MenuItem.objects.all() My question is how can i make any user friendly interface in admin panel to allow sorting MenuItems - for example list with + and - buttons to move MenuItem up and down ....

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  • Post and Comment with the same Model.

    - by xRobot
    I have created a simple project where everyone can create one or more Blog. I want to use this models for Post and for Comment: class Post_comment(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField(_('object ID')) content_object = generic.GenericForeignKey() # Hierarchy Field parent = models.ForeignKey('self', null=True, blank=True, default=None, related_name='children') # User Field user = models.ForeignKey(User) # Date Fields date_submitted = models.DateTimeField(_('date/time submitted'), default = datetime.now) date_modified = models.DateTimeField(_('date/time modified'), default = datetime.now) title = models.CharField(_('title'), max_length=60, blank=True, null=True) post_comment = models.TextField(_('post_comment')) markup = models.IntegerField(choices=MARKUP_CHOICES, default=DEFAULT_MARKUP, null=True, blank=True) if it is a comment the parent is not null. So in most case the text field will contain a little bit of text. Can I use this model for both Post and Comment ?

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  • How can I filter these Django records?

    - by mipadi
    I have a set of Django models as shown in the following diagram (the names of the reverse relationships are shown in the yellow bubbles): In each relationship, a Person may have 0 or more of the items. Additionally, the slug field is (unfortunately) not unique; multiple Person records may have the same slug fields. Essentially these records are duplicates. I want to obtain a list of all records that meet the following criteria: All duplicate records (that is, having the same slug) with at least one Entry OR at least one Audio OR at least one Episode OR at least one Article. So far, I have the following query: Person.objects.values('slug').annotate(num_records=Count('slug')).filter(num_records__gt=1) This groups all records by slug, then adds a num_records attribute that says how many records have that slug, but the additional filtering is not performed (and I don't even know if this would work right anyway, since, given a set of duplicate records, one may have, e.g., and Entry and the other may have an Article). In a nutshell, I want to find all duplicate records and collapse them, along with their associated models, into one record. What's the best way to do this with Django?

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  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

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  • IntegrityError with Booleand Fields and Postgresql

    - by xRobot
    I have this simple Blog model: class Blog(models.Model): title = models.CharField(_('title'), max_length=60, blank=True, null=True) body = models.TextField(_('body')) user = models.ForeignKey(User) is_public = models.BooleanField(_('is public'), default = True) When I insert a blog in admin interface, I get this error: IntegrityError at /admin/blogs/blog/add/ null value in column "is_public" violates not-null constraint Why ???

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  • Javascript error when integrating django-tinymce and django-filebrowser

    - by jwesonga
    I've set up django-filebrowser in my app without any bugs, I already had django-tinymce set up and it loads the editor in the admin forms. I now want to use django-filebrowser with django-tinymce, but I keep getting a weird javascript error when I click on "Image URL" in the Image popup: r is undefined the error is js/tiny_mce/tiny_mce.js My settings.py file has the following configuration: TINYMCE_JS_URL=MEDIA_URL + 'js/tiny_mce/tiny_mce.js' TINYMCE_DEFAULT_CONFIG = { 'mode': "textareas", 'theme': "advanced", 'language': "en", 'skin': "o2k7", 'dialog_type': "modal", 'object_resizing': True, 'cleanup_on_startup': True, 'forced_root_block': "p", 'remove_trailing_nbsp': True, 'theme_advanced_toolbar_location': "top", 'theme_advanced_toolbar_align': "left", 'theme_advanced_statusbar_location': "none", 'theme_advanced_buttons1': "formatselect,styleselect,bold,italic,underline,bullist,numlist,undo,redo,link,unlink,image,code,template,visualchars,fullscreen,pasteword,media,search,replace,charmap", 'theme_advanced_buttons2': "", 'theme_advanced_buttons3': "", 'theme_advanced_path': False, 'theme_advanced_blockformats': "p,h2,h3,h4,div,code,pre", 'width': '700', 'height': '300', 'plugins': "advimage,advlink,fullscreen,visualchars,paste,media,template,searchreplace", 'advimage_update_dimensions_onchange': True, 'file_browser_callback': "CustomFileBrowser", 'relative_urls': False, 'valid_elements' : "" + "-p," + "a[href|target=_blank|class]," + "-strong/-b," + "-em/-i," + "-u," + "-ol," + "-ul," + "-li," + "br," + "img[class|src|alt=|width|height]," + "-h2,-h3,-h4," + "-pre," + "-code," + "-div", 'extended_valid_elements': "" + "a[name|class|href|target|title|onclick]," + "img[class|src|border=0|alt|title|hspace|vspace|width|height|align|onmouseover|onmouseout|name]," + "br[clearfix]," + "-p[class<clearfix?summary?code]," + "h2[class<clearfix],h3[class<clearfix],h4[class<clearfix]," + "ul[class<clearfix],ol[class<clearfix]," + "div[class]," } TINYMCE_FILEBROWSER = False TINYMCE_COMPRESSOR = False i've tried switching back to older versions of tinyMCE Javascript but nothing seems to work. Would appreciate some help

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  • While trying to set up Django on Windows: AttributeError: 'Settings' object has no attribute 'DATABA

    - by user326370
    I'm following these instructions in order to set up Django on Windows. I have installed Python 2.6, PostgreSQL 8.4, Psycopg 2.0.14 for Python 2.6 and the latest version of Django from SVN. I'm now following these instructions to run a test project (copied from the page linked to above): C:\Documents and Settings\John>cd C:\ C:\>mkdir django C:\>cd django C:\django>django-admin.py startproject testproject C:\django>cd testproject C:\django\testproject>python manage.py runserver When I run the last line, this is the output: Validating models... Unhandled exception in thread started by <function inner_run at 0x01ECB930> Traceback (most recent call last): File "J:\Python26\lib\site-packages\django\core\management\commands\runserver.py", line 48, in inn er_run self.validate(display_num_errors=True) File "J:\Python26\lib\site-packages\django\core\management\base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "J:\Python26\lib\site-packages\django\core\management\validation.py", line 22, in get_validat ion_errors from django.db import models, connection File "J:\Python26\lib\site-packages\django\db\__init__.py", line 14, in <module> if not settings.DATABASES: File "J:\Python26\lib\site-packages\django\utils\functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'DATABASES' Did I forget to do something with the database? Any help will be appreciated. Thank you!

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  • forms problem in django 1.1

    - by alexarsh
    I have the following form: class ModuleItemForm2(forms.ModelForm): class Meta: model = Module_item fields = ('title', 'media', 'thumb', 'desc', 'default', 'player_option') The model is: class Module_item(models.Model): title = models.CharField(max_length=100) layout = models.CharField(max_length=5, choices=LAYOUTS_CHOICE) media = models.CharField(help_text='Media url', max_length=500, blank=True, null=True) conserv = models.ForeignKey(Conserv, help_text= 'Redirect to Conserv', blank=True, null=True) conserve_section = models.CharField(max_length=100, help_text= 'Section within the redirected Conserv', blank=True, null=True) parent = models.ForeignKey('self', help_text='Upper menu.', blank=True, null=True) module = models.ForeignKey(Module, blank=True, null=True) thumb = models.FileField(upload_to='sms/module_items/thumbs', blank=True, null=True) desc = models.CharField(max_length=500, blank=True, null=True) auto_play = models.IntegerField(help_text='Auto start play (miliseconds)', blank=True, null=True) order = models.IntegerField(help_text='Display order', blank=True, null=True) depth = models.IntegerField(help_text='The layout depth', blank=True, null=True) flow_replace = models.IntegerField(blank=True, null=True) default = models.IntegerField(help_text='The selected sub item (Note: Starting from 0)', blank=True, null=True) player_options = models.CharField(max_length=1000, null=True, blank=True) In my view I build form: module_item_form2 = ModuleItemForm2() print module_item_form2 And I get the following error on the print line: 'NoneType' object has no attribute 'label' It works fine with django 1.0.2. I see the error only in django 1.1. Do you have an idea what am I doing wrong? Regards, Arshavski Alexander.

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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