Search Results

Search found 8340 results on 334 pages for 'merge join'.

Page 14/334 | < Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >

• How to merge a "branch" that isn't really a branch (wasn't created by an svn copy)

  - by MatrixFrog

  I'm working on a team with lots of people who are pretty unfamiliar with the concepts of version control systems, and are just kind of doing whatever seems to work, by trial and error. Someone created a "branch" from the trunk that is not ancestrally related to the trunk. My guess is it went something like this: They created a folder in branches. They checked out all the code from the trunk to somewhere on their desktop. They added all that code to the newly created folder as though it was a bunch of brand new files. So the repository isn't aware that all that code is actually just a copy of the trunk. When I look at the history of that branch in TortoiseSVN, and uncheck the "Stop on copy/rename" box, there is no revision that has the trunk (or any other path) under the "Copy from path" column. Then they made lots of changes on their "branch". Meanwhile, others were making lots of changes on the trunk. We tried to do a merge and of course it doesn't work. Because, the trunk and the fake branch are not ancestrally related. I can see only two ways to resolve this: Go through the logs on the "branch", look at every change that was made, and manually apply each change to the trunk. Go through the logs on the trunk, look at every change that was made between revision 540 (when the "branch" was created) and HEAD, and manually apply each change to the "branch". This involves 7 revisions one way or 11 revisions the other way, so neither one is really that terrible. But is there any way to cause the repository to "realize" that the branch really IS ancestrally related even though it was created incorrectly, so that we can take advantage of the built-in merging functionality in Eclipse/TortoiseSVN? (You may be wondering: Why did your company hire these people and allow them to access the SVN repository without making sure they knew how to use it properly first?! We didn't -- this is a school assignment, which is a collaboration between two different classes -- the ones in the lower class were given a very quick hand-wavey "overview" of SVN which didn't really teach them anything. I've asked everyone in the group to please PLEASE read the svn book, and I'll make sure we (the slightly more experienced half of the team) keep a close eye on the repository to ensure this doesn't happen again.)

  Read the article

• Office 2007 Mail Merge: How do I view field names instead of data?

  - by One Monkey

  I've just received a document which forms the basis of a mail merge as an attachment and I need to view the field names like they display in 2003 with the double chevrons e.g. <<titles>><<initials>><<surname>> However even though I get a dialogue as I open the docx file saying that it is going to attempt to merge from a file (which I don't have) and I cancel that operation the document still displays merge data e.g. Mr A Test Instead of the field names. I have clicked on the fields which turn grey to demonstrate that they are fields but I can't find a way to make it display the field names not the data. I don't even know where it's getting the data from as I don't have the data source file for the document to use.

  Read the article

• How can I get command prompt to merge my files in name order?

  - by Anastasia

  I'm using the copy command in command prompt to merge all the files in a directory, for a number of directories. The problem is, I need to edit the first file in each directory before I merge. This means that when I put in the command "copy /b *.mp3 name.mp3", the joined file has part 2 at the start and part 1 at the end, presumably because it was created last. Is there a way of using the copy command so that the files merge in name order? Each folder has a different number of parts, anywhere from 2 to 1000 so I don't want to list each file with a "+" in between. Ideally, I'd like to find something to insert into the copy command I'm already using. Otherwise, is there a way of rearranging the files in a folder so that if you enter "DIR", part 1 shows up first even if it was edited last? I'm using Windows 7 by the way.

  Read the article

• Hibernate Criteria: Perform JOIN in Subquery/DetachedCriteria

  - by Gilean

  I'm running into an issue with adding JOIN's to a subquery using DetachedCriteria. The code looks roughly like this: Criteria criteria = createCacheableCriteria(ProductLine.class, "productLine"); criteria.add(Expression.eq("productLine.active", "Y")); DetachedCriteria subCriteria = DetachedCriteria.forClass(Models.class, "model"); subCriteria.setProjection(Projections.rowCount()); subCriteria.createAlias("model.language", "modelLang"); criteria.add(Expression.eq("modelLang.language_code", "EN")); subCriteria.add(Restrictions.eqProperty("model.productLine.id","productLine.id")); criteria.add(Subqueries.lt(0, subCriteria)); But the logged SQL does not contain the JOIN in the subquery, but does include the alias which is throwing an error SELECT * FROM PRODUCT_LINES this_ WHERE this_.ACTIVE=? AND ? < (SELECT COUNT(*) AS y0_ FROM MODELS this0__ WHERE modelLang3_.LANGUAGE ='EN' AND this0__.PRODUCT_LINE_ID =this_.ID ) How can I add the joins to the DetachedCriteria? Hibernate version: 3.2.6.ga Hibernate core: 3.3.2.GA Hibernate annotations: 3.4.0.GA Hibernate commons-annotations: 3.3.0.ga Hibernate entitymanager: 3.4.0.GA Hibernate validator: 3.1.0.GA

  Read the article

• solr JOIN query

  - by Sfairas

  I need to run a JOIN query on a solr index. I've got two xmls that I have indexed, person.xml and subject.xml. Person: <doc> <field name="id">P39126</field> <field name="family">Smith</field> <field name="given">John</field> <field name="subject">S1276</field> <field name="subject">S1312</field> </doc> Subject: <doc> <field name="id">S1276</field> <field name="topic">Abnormalities, Human</field> </doc> I need to only display information from the person doc but each query should match fields in both person and subject. In the case the query matches only the subject doc I need to display all docs from the person that have a matching id. Is this possible to do without running two seperate queries? Something like a JOIN query would do the job. Any help?

  Read the article

• Linq join with an inner collection

  - by bronze

  Hi, I am trying a LINQ to Object query on 2 collections Customer.Orders Branches.Pending.Orders (Collection within a collection) I want to output each branch which is yet to deliver any order of the customer. var match = from order in customer.Orders join branch in Branches on order equals branch.Pending.Orders select branch; This does not work, I get : The type of one of the expressions in the join clause is incorrect. Type inference failed in the call to 'GroupJoin'. From my search, I think this is because Order or collection of Orders does not implement equals. If this query worked, it will still be wrong, as it will return a branch if the customer's and pending orders match exactly. I want a result if any of the order matches. I am learning Linq, and looking for a approach to address such issues, rather than the solution itself. I would have done this in SQL like this; SELECT b.branch_name from Customers c, Branches b, Orders o WHERE c.customer_id = o.customer_id AND o.branch_id = b.branch_id AND c.customer_id = 'my customer' AND o.order_status = 'pending'

  Read the article

• using a JOIN in an UPDATE in SQL

  - by SDLFunTimes

  Hi, I'm having trouble formulating a legal statement to double the statuses of the suppliers (s) who have shipped (sp) more than 500 units. I've been trying: update s set s.status = s.status * 2 from s join sp on (sp.sno = s.sno) group by sno having sum(qty) > 500; however I'm getting this error from Mysql: ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from s join sp on (sp.sno = s.sno) group by sno having sum(qty) > 500' at line 1 Does anyone have any ideas about what is wrong with this query? Here's my schema: create table s ( sno char(5) not null, sname char(20) not null, status smallint, city char(15), primary key (sno) ); create table p ( pno char(6) not null, pname char(20) not null, color char(6), weight smallint, city char(15), primary key (pno) ); create table sp ( sno char(5) not null, pno char(6) not null, qty integer not null, primary key (sno, pno) );

  Read the article

• SQL statement to split a table based on a join

  - by williamjones

  I have a primary table for Articles that is linked by a join table Info to a table Tags that has only a small number of entries. I want to split the Articles table, by either deleting rows or creating a new table with only the entries I want, based on the absence of a link to a certain tag. There are a few million articles. How can I do this? Not all of the articles have any tag at all, and some have many tags. Example: table Articles primary_key id table Info foreign_key article_id foreign_key tag_id table Tags primary_key id It was easy for me to segregate the articles that do have the match right off the bat, so I thought maybe I could do that and then use a NOT IN statement but that is so slow running it's unclear if it's ever going to finish. I did that with these commands: INSERT INTO matched_articles SELECT * FROM articles a LEFT JOIN info i ON a.id = i.article_id WHERE i.tag_id = 5; INSERT INTO unmatched_articles SELECT * FROM articles a WHERE a.id NOT IN (SELECT m.id FROM matched_articles m); If it makes a difference, I'm on Postgres.

  Read the article

• Filtering on a left join in SQLalchemy

  - by Adam Ernst

  Using SQLalchemy I want to perform a left outer join and filter out rows that DO have a match in the joined table. I'm sending push notifications, so I have a Notification table. This means I also have a ExpiredDeviceId table to store device_ids that are no longer valid. (I don't want to just delete the affected notifications as the user might later re-install the app, at which point the notifications should resume according to Apple's docs.) CREATE TABLE Notification (device_id TEXT, time DATETIME); CREATE TABLE ExpiredDeviceId (device_id TEXT PRIMARY KEY, expiration_time DATETIME); Note: there may be multiple Notifications per device_id. There is no "Device" table for each device. So when doing SELECT FROM Notification I should filter accordingly. I can do it in SQL: SELECT * FROM Notification LEFT OUTER JOIN ExpiredDeviceId ON Notification.device_id = ExpiredDeviceId.device_id WHERE expiration_time == NULL But how can I do it in SQLalchemy? sess.query( Notification, ExpiredDeviceId ).outerjoin( (ExpiredDeviceId, Notification.device_id == ExpiredDeviceId.device_id) ).filter( ??? ) Alternately I could do this with a device_id NOT IN (SELECT device_id FROM ExpiredDeviceId) clause, but that seems way less efficient.

  Read the article

• JOIN (SELECT DISTINCT [..] substitute

  - by FRKT

  Hello, I'd like to find a substitute for using SELECT DISTINCT in a derived table. Let's say I have three tables: CREATE TABLE `trades` ( `tradeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `employeeID` int(11) unsigned NOT NULL, `corporationID` int(11) unsigned NOT NULL, `profit` int(11) NOT NULL, KEY `tradeID` (`tradeID`), KEY `employeeID` (`employeeID`), KEY `corporationID` (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `corporations` ( `corporationID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `employees` ( `employeeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`employeeID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 Let's say I'd like to find out how much profit a specific employee has generated. Simple: SELECT SUM(profit) FROM trades JOIN employees ON trades.employeeID = employees.employeeID AND employees.employeeID = 1; It gets trickier if I'd like to query how much revenue a specific corporation has, however. I cannot simply replicate the aforementioned query, because two or more employees from the same company might be involved in the same trade. This query should do the trick: SELECT SUM(profit) FROM trades JOIN (SELECT DISTINCT tradeID FROM trades WHERE trades.corporationID = 1) ... unfortunately, DISTINCT JOINs seem crazy ineffective. Is there any alternative I can use to determine how much revenue a corporation has, taking into account that a corporation might be listed several times with the same tradeID?

  Read the article

• Hibernate HQL m:n join problem

  - by smallufo

  I am very unfamiliar with SQL/HQL , and am currently stuck with this 'maybe' simple problem : I have two many-to-many Entities , with a relation table : Car , CarProblem , and Problem . One Car may have many Problems , One Problem may appear in many Cars, CarProblem is the association table with other properties . Now , I want to find Car(s) with specified Problem , how do I write such HQL ? All ids are Long type . I've tried a lot of join / inner-join combinations , but all in vain.. -- updated : Sorry , forget to mention : Car has many CarProblem Problem has many CarProblem Car and Problem are not directly connected in Java Object. -- update , java code below -- @Entity public class Car extends Model{ @OneToMany(mappedBy="car" , cascade=CascadeType.ALL) public Set<CarProblem> carProblems; } @Entity public class CarProblem extends Model{ @ManyToOne public Car car; @ManyToOne public Problem problem; ... other properties } @Entity public class Problem extends Model { other properties ... // not link to CarProblem , It seems not related to this problem // **This is a very stupid query , I want to get rid of it ...** public List<Car> findCars() { List<CarProblem> list = CarProblem.find("from CarProblem as cp where cp.problem.id = ? ", id).fetch(); Set<Car> result = new HashSet<Car>(); for(CarProblem cp : list) result.add(cp.car); return new ArrayList<Car>(result); } } The Model is from Play! framework , so these properties are all public .

  Read the article

• SQL Standard Regarding Left Outer Join and Where Conditions

  - by Ryan

  I am getting different results based on a filter condition in a query based on where I place the filter condition. My questions are: Is there a technical difference between these queries? Is there anything in the SQL standard that explains the different resultsets in the queries? Given the simplified scenario: --Table: Parent Columns: ID, Name, Description --Table: Child Columns: ID, ParentID, Name, Description --Query 1 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID) WHERE c.ID IS NULL OR c.Description = 'FilterCondition' --Query 2 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID AND c.Description = 'FilterCondition') I assumed the queries would return the same resultsets and I was surprised when they didn't. I am using MS SQL2005 and in the actual queries, query 1 returned ~700 rows and query 2 returned ~1100 rows and I couldn't detect a pattern on which rows were returned and which rows were excluded. There were still many rows in query 1 with child rows with data and NULL data. I prefer the style of query 2 (and I think it is more optimal), but I thought the queries would return the same results.

  Read the article

• Left Join only returning one row

  - by Adam

  I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

  Read the article

• What does this Eclipse icon mean in a Merge Results view?

  - by user68759

  I just did an svn merge from a branch to a trunk in my Eclipse IDE, and in the Merge Results view, there is this following icon: I am dying to know what it means. I have searched the entire Eclipse documentation and some relevant StackOverflow questions, but couldn't find anything. The CollabNet documentation about Merge Results View explains what a Merge Results View is, but doesn't mention anything about the meanings of its icons. Does anyone know? Thanks!

  Read the article

• SSIS Basics: Using the Merge Join Transformation

  SSIS is able to take sorted data from more than one OLE DB data source and merge them into one table which can then be sent to an OLE DB destination. This 'Merge Join' transformation works in a similar way to a SQL join by specifying a 'join key' relationship. this transformation can save a great deal of processing on the destination. Annette Allen, as usual, gives clear guidance on how to do it.

  Read the article

• SSIS Basics: Using the Merge Join Transformation

  SSIS is able to take sorted data from more than one OLE DB data source and merge them into one table which can then be sent to an OLE DB destination. This 'Merge Join' transformation works in a similar way to a SQL join by specifying a 'join key' relationship. this transformation can save a great deal of processing on the destination. Annette Allen, as usual, gives clear guidance on how to do it.

  Read the article

• Oracle - Update statement with inner join

  - by user169743

  I have a query which works fine in MySQL, I'm trying to get it working on oracle but get the following error SQL Error: ORA-00933: SQL command not properly ended 00933. 00000 - "SQL command not properly ended" The query is: UPDATE table1 INNER JOIN table2 ON table1.value = table2.DESC SET table1.value = table2.CODE WHERE table1.UPDATETYPE='blah'; I'd be extremely grateful for any help.

  Read the article

• SQL is this equvelent to a LEFT JoIn?

  - by Jim

  Is this equvelent to a LEFT JOIN? select distinct a.name, b.name from tableA a, (select name from tableB) as b It seems as though there is no link between the two tables. Is there an easier / more efficient way to write this?

  Read the article

• How to do a join that removes values?

  - by Georg

  Customers Holidays id | name customer_id | start | end ---+------ ------------+--------+------ 1 | Peter 1 | 5 | 10 2 | Simon 1 | 15 | 20 3 | Mary 2 | 5 | 20 How should my SQL query look that out of start=11,end=14 I get these customers: Peter Mary Is this even manageable with a simple SQL join, or do I need to use sub-queries?

  Read the article

• Self join to a table

  - by Mohit

  I have a table like Employee ================== name salary ================== a 10000 b 20000 c 5000 d 40000 i want to get all the employee whose salary is greater than A's salary. I don't want to use any nested or sub query. It has been asked in an interview and hint was to use self join. I really can't figure out how to achieve the same.

  Read the article

• Rails3: how to use relational algebra to replace SQL-constructions like NOT and OUTER JOIN

  - by petRUShka

  There are two models Post and Comment. I should get all posts, which have no comments with specific tag. How can I do this using new Rails 3 features such relational algebra (arel). SQL-solution should be something like this: SELECT `posts`.* FROM `posts` LEFT OUTER JOIN `comments` ON `posts`.`id` = `comments`.`post_id` WHERE NOT (`comments`.`tag` = 'my_tag')

  Read the article

• Mysql Left Join Null Result

  - by Ozzy

  I have this query SELECT articles.*, users.username AS `user` FROM `articles` LEFT JOIN `users` ON articles.user_id = users.id ORDER BY articles.timestamp Basically it returns the list of articles and the username that the article is associated to. Now if there is no entry in the users table for a particular user id, the users var is NULL. Is there anyway to make it that if its null it returns something like "User Not Found"? or would i have to do this using php?

  Read the article

• join query in mysql cursor

  - by parag

  As the title describes all we can declare cursor like this DECLARE cur1 CURSOR FOR SELECT id,data FROM test.t1; Can we use join query instead off simple query?

  Read the article

• PHP MySQL join table

  - by Jordan Pagaduan

  $sql = "SELECT logs.full_name, logout.status FROM logs, logout WHERE logs.employee_id = logout.employee_id"; tables -- logs logout I'm having error on this. I search join tables in google. And that's what I got. What is wrong with this code?

  Read the article

• Sql query to get the GrandFather name by doing a self join

  - by mahesh

  Hello all , Can any one please give me the query to get the child name and his grand fathers name For eg - if i have a table Relationships in the i have childid and fatherid columns so how will i get the grandfather, i can easily get the father name by using a join but for grandfather i need to do joins 2 times so can any one help me with this D.Mahesh

  Read the article

< Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >