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  • How to add an self defined attribute to ldap user?

    - by Arnab Das
    Hi, I have created an attribute in LDAP using the following code. attrs.put("NUMERICOID", "1.3.6.1.4.1.42.2.27.4.2.3.1.1.9"); attrs.put("NAME", "myattribute"); attrs.put("DESC", "for JNDITutorial example only"); attrs.put("SYNTAX", "1.3.6.1.4.1.1466.115.121.1.15"); DirContext schema = context.getSchema(""); DirContext newAttr = schema.createSubcontext ("AttributeDefinition/myattribute1", attrs); The attribute is created successfully, Now I am trying to add this attribute to a user say "user1"(uid). Attributes attributeslist = context.getAttributes(ld.getUserDN(username)); attributeslist.put("myattribute1", ""); context.modifyAttributes(ld.getUserDN("test5"), DirContext.REPLACE_ATTRIBUTE, attributeslist); But it gives me object class violation error. Can anyone help me to solve this? I need to add an user defined attribut to the user using java code.

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  • Notifying JMS Message sender (Web App) after message processed by Listener

    - by blob
    I have a Web application (Flex 4 - Spring Blaze DS - Spring 3.0) which sends out an JMS event to a batch application (Standalone java) I am using JMS infrastrucure provided by Spring (spring JmsTemplate,SimpleMessageListenerContainer,MessageListenerAdapter) with TIBCO EMS. Is there any way by which we can notify a web user once message processing is completed by listener. One of the way to send a response event which will be listened by web application; but how to address following scenario: User1 click on submit - which in turn sends a JMS message Listener on receiving message processes the message (message processing may take 20-30 mins to complete). Listener application sends out another JMS event "Process_complete" As this is a web application; there are n users currently logged into the application. so how to identify a correct user / what if user is already logged off? Is there any way to handle this? Please post your views.

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  • Can a browser maintain multiple sessions with one server?

    - by Blaine
    Is there a way to maintain multiple sessions with one server within the browser? Here is what I am trying to accomplish: User1 has exclusive access to ContentA and User2 has exclusive access to ContentB. I want to be able to allow User3 to login multiple times, to allow access to ContentA and ContentB. I admit that this scenario seems almost silly but it stems from the fact that I can't change the way the server handles content permissions. Any ideas on how I could accomplish this without touching the server? In say Safari on the iPhone?

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  • Creating Two Cascading Foreign Keys Against Same Target Table/Col

    - by alram
    I have the following tables: user (userid int [pk], name varchar(50)) action (actionid int [pk], description nvarchar(50)) being referenced by another table that captures the relationship: <user1> <action>'s <user2>. I did this with the following table: userAction (userActionId int [pk], actionid int [fk: action.actionid], **userId1 int [fk ref's user.userid; on del/update cascade], userId2 int [fk ref's user.userid; on del/update cascade]**). However, when I try to save the userAction table i get an error because I have two cascading fk's against user.userid. Is there any way to remedy this or must I use a trigger?

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  • sql select with exact outcome

    - by Shiro
    Asking a simple question, just want everyone have fun to solve it. I got 2 tables. 1. Student 2. Course Student +----+--------+ | id | name | +----+--------+ | 1 | User1 | | 2 | User2 | +----+--------+ Course +----+------------+------------+ | id | student_id | course_name| +----+------------+------------+ | 1 | 1 | English | | 2 | 1 | Chinese | | 3 | 2 | English | | 4 | 2 | Japanese | +----+------------+------------+ I would like to get the result all student, who have taken English and Chinese, NOT English or Chinese. Expected result: +----+------------+------------+ | id | student_id | course_name| +----+------------+------------+ | 1 | 1 | English | | 2 | 1 | Chinese | +----+------------+------------+ What we normally do is select * from student join course on (student.id = course.student_id) WHERE course_name = 'English' OR course_name = 'Chinese' but in this result I can get User2 record which is not my expected result. I want the record only display the User take the course English+Chinese only.

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  • Why does the token returned by LogonUser() in Win x64 not belong to LOCAL group?

    - by edwinbs
    Hi, I have a piece of code that calls LogonUser() followed by CreateProcessAsUser(). In Win32, the resulting process belongs to a user (say, TESTDOMAIN\user1) who belongs to the LOCAL group. However, in x64, the process owner does not belong to LOCAL. The owner still belongs to all other groups (Authenticated Users, Everyone, etc.) Does anyone know if this is a documented behavior change? Or am I supposed to put some special flag in x64 when calling LogonUser()? Thanks.

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  • How to get count of another table in a left join

    - by Sinan
    I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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  • What is wrong with my Basic Authentication in FireFox?

    - by Pure.Krome
    Hi folks, i'm trying to goto the following url :- http://user1:pass1@localhost:1234/api/users?format=xml nothing to complex. Notice how i've got the username/password in the url? this, i believe, is for basic authentication. When i do that, the Request Headers are MISSING the 'Authorize' header. Er... that's not right :( I have anonymous authentication only setup on the site. I don't want to have anon off and basic turned on .. because not all of the site requires basic.. only a few action methods. So .. why is this not working? Is this something to do with the fact my code is not sending a 401 challenge or some crap? For What It's Worth, my site is ASP.NET MVC1 running on IIS7 (and the same thing happens when i run it on cassini).

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  • Please help clarify my regex pattern

    - by Dmitriy Sosunov
    I have the following string: <script>m('02:29:1467301/>Sender1*>some text message?<<02:29:13625N1/>Sender2*>Recipient2: another message??<>A<<02:29:1393100=>User1*|0User2*|%></B><<','');</script> N.B. messages are separated by << I need extract from message the following parts: 1. Time 2. Sender 3. Recipient 4. Text Recipient may being defined or not, this field is optional. I do this by the following pattern: (?<message>(?<time>\d{1,2}:\d{1,2}:[0-9a-z]+)/>(?<messageData>(?<sender>.+?)\*>(.+?)))<< But, I cannot extract recipient separately from the message text. (?<message>(?<time>\d{1,2}:\d{1,2}:[0-9a-z]+)/>(?<messageData>(?<sender>.+?)\*>(((?<recipient>.+?):){0,1}(?<messageText>.+?))))<< Please help correct my pattern.

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  • Problems using User model in django unit tests

    - by theycallmemorty
    I have the following django test case that is giving me errors: class MyTesting(unittest.TestCase): def setUp(self): self.u1 = User.objects.create(username='user1') self.up1 = UserProfile.objects.create(user=self.u1) def testA(self): ... def testB(self): ... When I run my tests, testA will pass sucessfully but before testB starts, I get the following error: IntegrityError: column username is not unique It's clear that it is trying to create self.u1 before each test case and finding that it already exists in the Database. How do I get it to properly clean up after each test case so that subsequent cases run correctly?

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • Please clarify a few points concerning Java Servlets

    - by EugeneP
    suppose, I use Tomcat as a web container. Is it true that once all the servlets found in a web-app/WEBAPPNAME are init(IALIZED) then every change of a Servlet's property will be seen to every session. So session 1 changes a property userName of a Servlet1 from "user1" to "user2" session 1 is closed. session 2 starts. It will see "user2" as the only value of Servlet1.userName property?? Any change of a Servlet's field will be seen to all subsequent sessions? Are servlets singletons, aren't they?

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  • Hibernate, select by id or unique column

    - by Nican
    I am using hibernate for Java, and I want to be able to select users by id or by name from the database. Nice thing about Hibernate is that it caches the result by id, but I seem to be unable to make it cache by name. static Session openSession = Factory.openSession(); public static User GetUser(int Id) { return (User) openSession.get(User.class, new Integer(Id)); } public static User GetUser( String Name ){ return (User) openSession.createCriteria( User.class ). add( Restrictions.eq("username", Name) ). uniqueResult(); } If I use GetUser(1) many times, hibernate will only show that it executed the first time. But every time I use GetUser("user1"), hibernate shows that it is executing a new query to database. What would be the best way to have the string identifier be cached also?

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  • PHP New Line will not work

    - by user364333
    Hi I am trying to create some code that first reads the existing contents of the file in and then adds the new line of code on a new line but the code i am using just adds it on the new text on to the already existing line instead of the new line... Here is the code i am using: <?php $id = $_GET['id']; $userfile = "user1.txt"; $fo = fopen($userfile, 'r') or die("can't open favourites file"); $currentdata = fread($fo, filesize($userfile)); fclose($fo); $fw = fopen($userfile, 'w') or die("can't open favourites file"); $currentprocessed = "$currentdata\n"; fwrite($fw, $currentprocessed); fwrite($fw, $id); fclose($fw); ?> I have tried a whole range of different ideas but nothing has worked, any help would be appreciated.

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  • mysql twitter/facebook like status feed

    - by barjonah
    Hi, I have two tables. One named status like this... user_id | status --------+----------- 1 | random status from user 1 2 | random status from user 2 3 | random message from user 3 4 | staus from user 4 1 | second status for user1 etc... and another named users_following like this... user_id | is_following --------+----------- 1 | 2 1 | 3 2 | 1 3 | 2 meaning that user 1 is following both users 2 and 3 etc... So, let's say I chose user 1. What is the best query (performance wise) to show the status updates of users that user 1 is following, in this case users 2 and 3 currently I have something like SELECT * from status WHERE user_id IN(SELECT is_following FROM users_following WHERE user_id='1') LIMIT 0,5 but I don't think this is good for performance if a user was following thousands+ of users

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  • jquery .load() function only gets called once

    - by user1288099
    the html <div class="stackwrapper" id="user1"></div> <div class="stackwrapper" id="user2"></div> <div class="userdrawings"></div> the javascript $('.stackwrapper').click(function(e){ var id=$(this).attr('id'); $('.userdrawings').load('loadSession.php?user='+id).fadeIn("slow"); }); Somehow it only works at once, only at the first click on stackwrapper, when I click on the second one, the function is not triggered again.

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  • Read video information(date created)?

    - by Lynx
    In window, i can get the date created of the video from properties(right click). I have a few idea on this but i dont know how to do it. 1. Get the video information directly from video(like in windows), 2. By extracting the video name to get the date created(The video's name is in date format, which is the time it created). And i also using taglib-sharp to get the video duration and resolution, but i cant find any sample code on how to get the video creation date. Note: video name in date format - example, 20121119_125550.avi Edit Found this code and so far its working string fileName = Server.MapPath("//video//20121119_125550.avi"); FileInfo fileInfo = new FileInfo(fileName); DateTime creationTime = fileInfo.CreationTime; Output: 2012/11/19 12:55:50 For the file's name, i will add another string in name. For example User1-20121119_125550.avi.avi, so it will get complicated after that.

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  • How to specify "PG-USERNAME" in pg_ident.conf so that it'll match any database user ?

    - by felace
    I need to restrict a specific unix user so that it can login with only a few select postgres usernames (with password prompt), but allowing every other user to use whatever pg username they want. Assuming restrUnixUser is the unix user name and restrUser is one of the postgres users it may use, and AllowedDB is the only database they should connect to : pg_hba.conf : local AllowedDB restrUser password local all restrUser reject local all all ident map=exceptrestrUser And pg_ident.conf : exceptrestrUser /^(?!restrUnixUser).*$ user1 exceptrestrUser /^(?!restrUnixUser).*$ user2 exceptrestrUser /^(?!restrUnixUser).*$ postgres does what I exactly want to do right now, however, I'll probably add a lot more users so I wonder if there is something like mapname unixuserpattern allpgusers that'll match with whatever username used to login by any unix user matching the pattern.

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  • get value from database based on array in codeigniter

    - by Developer
    I have an array $user = array([0]=>1 [1]=>2 [2]=>3) which contains id's of certain users. I need to get the countries of these users from database. foreach($userid as $user){ $this->db->select('country'); $this->db->where('user_id',$user); $this->db->from('company'); $usercountry = $this->db->get(); $count = $usercountry->row(); $country = $count->country; } Suppose user1 has country ES, user2 has IN, user3 has US, user4 has UK. then if array contains 1,2,3. Then i need to get the countries ES,IN,US.

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  • Apache Alias Isn't In Directory Listing

    - by Phunt
    I've got a site running on my home server that's just a front end for me to grab files remotely. There's no pages, just a directory listing (Options Indexes...). I wanted to add a link to a directory outside of the webroot so I made an alias. After a minute of dealing with permissions, I can now navigate to the directory by typing the URL into the browser, but the directory isn't listed in the root index. Is there a way to do this without creating a symlink in the root? Server: Ubuntu 11.04, Apache 2.2.19 Relevant vhost: <VirtualHost *:80> ServerName some.url.net DocumentRoot "/var/www/some.url.net" <Directory /var/www/some.url.net> Options Indexes FollowSymLinks AllowOverride None Order Allow,Deny Allow From All AuthType Basic AuthName "TPS Reports" AuthUserFile /usr/local/apache2/passwd/some.url.net Require user user1 user2 </Directory> Alias /some_alias "/media/usb_drive/extra files" <Directory "/media/usb_drive/extra files"> Options Indexes FollowSymLinks Order Allow,Deny Allow From All </Directory> </VirtualHost>

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  • VNC authentication failure

    - by cf16
    I try to connect to my vncserver running on CentOs from home computer, behind firewall. I have installed Win7 and Ubuntu both on this machine. I have an error: VNC conenction failed: vncserver too many security failures even when loging with right credentials (I reset passwd on CentOs) I get: authentication failure. I observe that I have to wait a whole day to be able to relogin at all. Is it something regarding that I try as root? I think important is also that I have to login to remote Centos through port 6050 - none else port works for me. Do I have to do something with other ports? I see that vncserver is listening on 5901, 5902 if another added - and I consider connection is established because from time to time (long time) the passwd prompt appears,... right? I have created additional user1, password for him to CentOS and to VNC, also user2. I do: service vncserver start and two servers starts, one :1, and second on :2. When I try to connect to vncserverIP:1 I get what described above, but when I try connect to vncserverIP:2 it says that the trial was unsuccessful. please help, what to do? additionally: how to disable this lockout for a testing purposes?

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  • How to configure multiple virtual hosts for multiple users on Linux/Apache2.2

    - by authentictech
    I want to set up a virtual hosting server on Linux/Apache2.2 that allows multiple users to set up multiple website domains as would be appropriate for commercial shared hosting. I have seen examples (from my then perspective as a shared hosting customer) that allow users to store their web files in their user home directory with directories to correspond to the virtual host domain, e.g.: /home/user1/www/example1.com /home/user2/www/example2.com instead of using /var/www Questions: How would you configure this in your Apache configuration files? (Don't worry about DNS) Is this the best way to manage multiple virtual hosts? Are there others? What safety or security issues do you think I should be aware of in doing this? Many thanks, folks. Edit: If you want to only answer question 1, please feel free, as that is the most urgent to me at this moment and I would consider that an answer to the question. I have done it for myself since posting, but I am not confident that it's the best solution and I would like to know how an experienced sysadmin would do it. Thanks.

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  • Proxy settings in Java mail API

    - by coder
    I've written a piece of java code where user1 sends email to user2. I'm behind a proxy and hence I'm getting a javax.mail.MessagingException. How do I solve this problem? Here is the code- import java.util.Properties; import javax.mail.Message; import javax.mail.MessagingException; import javax.mail.PasswordAuthentication; import javax.mail.Session; import javax.mail.Transport; import javax.mail.internet.InternetAddress; import javax.mail.internet.MimeMessage; public class Mail { public static void main(String[] args) { final String username = "[email protected]"; final String password = "abc"; Properties props = new Properties(); props = System.getProperties(); props.put("mail.smtp.auth", "true"); props.put("mail.smtp.starttls.enable", "true"); props.put("mail.smtp.host", "smtp.gmail.com"); props.put("mail.smtp.port", "587"); Session session = Session.getInstance(props, new javax.mail.Authenticator() { protected PasswordAuthentication getPasswordAuthentication() { return new PasswordAuthentication(username, password); } }); try { Message message = new MimeMessage(session); message.setFrom(new InternetAddress("[email protected]")); message.setRecipients(Message.RecipientType.TO, InternetAddress.parse("[email protected]")); message.setSubject("Testing Subject"); message.setText("Dear Mail Crawler," + "\n\n No spam to my email, please!"); Transport.send(message); System.out.println("Done"); } catch (MessagingException e) { throw new RuntimeException(e); } } }

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  • SharePoint web services not protected?

    - by Philipp Schmid
    Using WSS 3.0, we have noticed that while users can be restricted to access only certain sub-sites of a site collection through permission settings, the same doesn't seem to be true for web services, such as /_vti_bin/Lists.asmx! Here's our experimental setup: http://formal/test : 'test' site collection - site1 : first site in test site collection, user1 is member - site2 : second site in test site collection, user2 is member With this setup, using a web browser user2 can: - access http://formal/test/site2/Default.aspx - cannot access http://formal/test/site1/Default.aspx That's what is expected. To our surprise however, using the code below, user2 can retrieve the names of the lists in site1, something he should not have access to! Is that by (unfortunate) design, or is there a configuration setting we've missed that would prevent user2 from retrieving the names of lists in site1? Is this going to be different in SharePoint 2010? Here's the web service code used in the experiment: class Program { static readonly string _url ="http://formal/sites/research/site2/_vti_bin/Lists.asmx"; static readonly string _user = "user2"; static readonly string _password = "password"; static readonly string _domain = "DOMAIN"; static void Main(string[] args) { try { ListsSoapClient service = GetServiceClient(_url, _user, _password, _domain); var result = service.GetListCollection(); Console.WriteLine(result.Value); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } private static ListsSoapClient GetServiceClient(string url, string userName, string password, string domain) { BasicHttpBinding binding = new BasicHttpBinding(BasicHttpSecurityMode.TransportCredentialOnly); binding.Security.Transport.ClientCredentialType = HttpClientCredentialType.Ntlm; ListsSoapClient service = new ListsSoapClient(binding, new System.ServiceModel.EndpointAddress(url)); service.ClientCredentials.UserName.Password = password; service.ClientCredentials.UserName.UserName = (!string.IsNullOrEmpty(domain)) ? domain + "\\" + userName : userName; return service; } }

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  • Start & shutdown as tomcat as non-root user

    - by user53864
    How to start, shutdown and restart tomcat as non-root user. I have tomcat5.x installed on ubuntu machine(usr/share/tomcat). The tomcat directory has full permissions. When I shutdown(/usr/share/tomcat/bin/shudown.sh) or startup(/usr/share/tomcat/startup.sh) tomcat as normal user, it starts & shuts down normally as if it is executed as root user but I could not access webpage even after starting tomcat as non-root user. user1@station2:/usr/share/tomcat/webapps$ ../bin/shutdown.sh Using CATALINA_BASE: /usr/share/tomcat Using CATALINA_HOME: /usr/share/tomcat Using CATALINA_TMPDIR: /usr/share/tomcat/temp Using JRE_HOME: /usr 4 Oct, 2010 6:41:11 PM org.apache.catalina.startup.Catalina stopServer SEVERE: Catalina.stop: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:310) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:176) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:163) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:384) at java.net.Socket.connect(Socket.java:546) at java.net.Socket.connect(Socket.java:495) at java.net.Socket.<init>(Socket.java:392) at java.net.Socket.<init>(Socket.java:206) at org.apache.catalina.startup.Catalina.stopServer(Catalina.java:421) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.stopServer(Bootstrap.java:337) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:415)

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