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• Start & shutdown as tomcat as non-root user

  - by user53864

  How to start, shutdown and restart tomcat as non-root user. I have tomcat5.x installed on ubuntu machine(usr/share/tomcat). The tomcat directory has full permissions. When I shutdown(/usr/share/tomcat/bin/shudown.sh) or startup(/usr/share/tomcat/startup.sh) tomcat as normal user, it starts & shuts down normally as if it is executed as root user but I could not access webpage even after starting tomcat as non-root user. user1@station2:/usr/share/tomcat/webapps$ ../bin/shutdown.sh Using CATALINA_BASE: /usr/share/tomcat Using CATALINA_HOME: /usr/share/tomcat Using CATALINA_TMPDIR: /usr/share/tomcat/temp Using JRE_HOME: /usr 4 Oct, 2010 6:41:11 PM org.apache.catalina.startup.Catalina stopServer SEVERE: Catalina.stop: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:310) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:176) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:163) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:384) at java.net.Socket.connect(Socket.java:546) at java.net.Socket.connect(Socket.java:495) at java.net.Socket.<init>(Socket.java:392) at java.net.Socket.<init>(Socket.java:206) at org.apache.catalina.startup.Catalina.stopServer(Catalina.java:421) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.stopServer(Bootstrap.java:337) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:415)

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• running a command as root with /bin/su and without gives different results

  - by n00bInCpp

  Some background: I have a machine with SLES 11 installed. I am running a bash script that one of its lines is /bin/su $USER -c SOME_CMD. Unfortunately, the SOME_CMD that comes after the -c keeps failing, no matter if USER=root or any different user. However, if /bin/su $USER -c part is omitted then everything runs smoothly. Moreover, I have run the script on RHEL5 and it worked fine. Anyway, my question is why does it happen? If it is a permissions problems then why when I run this as root with /bin/su and without I get different results? P.S. apologize if somebody else has asked it before, I have done many googling and got nothing that satisfies. Thanks in advance, n00bInCpp EDIT Okay, I figured it out, I hope so. Instead of running /bin/su I used /user/bin/sudo -u $MY_USER_1 MY_ENV_VAR="/home/user1" SOME_CMD. I don't understand why I have to use sudo, though. I am used to run a command as a different user using su and not worrying about permissions problems, but I guess it doesn't work like that on SLES 11/SuSE. Anyhow, thanks to everyone who wanted to or helped me.

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• Must have local user to authenticate Samba to AD?

  - by Phil

  I've got a CentOS 5.3 server with Samba running. I've joined this server to my domain in the hopes of allowing AD users some access to my Samba shares. I've found that this works, but only as long as the AD username that I'm trying to authenticate with is also a local user on the server. In other words, if I'm trying to access a share, and try to authenticate with the AD username "joe", I get errors unless I create a user named 'joe' on the server. I don't have to create a matching password or anything....the local user's password is always blank, so I do know that the authentication is actually happening against the AD. Here's my smb.conf file: [global] workgroup = <mydomain> server string = <snip> netbios name = HOME security = ADS realm = <mydomain.com> password server = <snip> auth methods = winbind log level = 1 log file = /var/log/samba/%m.log [amore] path = /var/www/amore browseable = yes writable = yes valid users = DOMAIN\user1 DOMAIN\user2 DOMAIN\user3 DOMAIN\user4 I would assume that my kerberos settings are fine, as I've joined the domain and can use wbinfo to see users and groups. However, I can provide that info if necessary. Anyone have any ideas?

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• postfix email gateway

  - by k-h

  I am setting up a postfix email gateway. It will not hold any mail but will accept email for my domain and forward it to another internal mailserver and relay mail out from the internal server. One of the main problems is that I am working on a live running system and this will be an upgrade so I am using a test domain which I will change at some point to the real domain. I tried various methods but found the simplest way (that worked) was to use a script to create an aliases file (from ldap entries). There are various problems with this method. The main one being that the entries can't be of the simple form [email protected] because the gateway doesn't know where to send them. They have to be of the form: [email protected]. What I would like doesn't seem hard but I can't get my head around the postfix documentation. There seem to be various ways but none of them seem to work. Most of the examples I have found on the web assume the mail is going to end up on the server. I want a list of users somewhere, preferably of the form: user1, user2, etc rather than [email protected] (I can easily generate this list) and I would like postfix to forward all email to example.com to a particular server: ie realmailserver.example.com. Can anyone suggest clues as to how I might do this?

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• org.hibernate.MappingException: Unknown entity:

  - by tsegay

  I tried to see all the questions on this topic but none of them helped me. And I really want to understand what is going on with my code. I have a standalone application which uses spring and Hibernate as JPA and I am trying to run the test using a single main Class My main class package edu.acct.tsegay.common; import edu.acct.tsegay.model.User; import edu.acct.tsegay.business.IUserBusinessObject; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class App { public static void main(String[] args) { try { ApplicationContext context = new ClassPathXmlApplicationContext( "Spring3AndHibernate-servlet.xml"); IUserBusinessObject userBusinessObject = (IUserBusinessObject) context .getBean("userBusiness"); User user = (User) context.getBean("user1"); user.setPassword("pass"); user.setUsername("tsegay"); System.out.println(user.getPassword()); userBusinessObject.delete(user); User user2 = new User(); user2.setUsername("habest"); user2.setPassword("pass1"); System.out.println(user2.getPassword()); /* * userBusinessObject.save(user2); * * User user3 = userBusinessObject.searchUserbyId("tsegay"); * System.out.println("Search Result: " + user3.getUsername()); */ System.out.println("Success"); } catch (Exception e) { e.printStackTrace(); } } } my application context is: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- data source --> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost:3306/test" /> <property name="username" value="test" /> <property name="password" value="password" /> </bean> <!-- session factory --> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource" /> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <!-- exposed person business object --> <bean id="userBusiness" class="edu.acct.tsegay.business.UserBusinessObject"> <property name="userDao" ref="userDao" /> </bean> <bean id="user1" class="edu.acct.tsegay.model.User"> <property name="username" value="tse" /> <property name="password" value="pass" /> </bean> <!-- Data Access Object --> <bean id="userDao" class="edu.acct.tsegay.dao.UserDao"> <property name="sessionFactory" ref="sessionFactory" /> </bean> </beans> My User Model is: package edu.acct.tsegay.model; import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.Version; import org.hibernate.annotations.NaturalId; @Entity public class User implements Serializable { /** * */ private static final long serialVersionUID = 1L; private String username; private String password; private Integer VERSION; @Version public Integer getVERSION() { return VERSION; } public void setVERSION(Integer vERSION) { VERSION = vERSION; } @NaturalId public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } } My DAO is: package edu.acct.tsegay.dao; import edu.acct.tsegay.model.User; import org.hibernate.SessionFactory; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.orm.hibernate3.HibernateTemplate; import org.springframework.stereotype.Repository; @Repository public class UserDao implements IUserDao { private SessionFactory sessionFactory; private HibernateTemplate hibernateTemplate; public SessionFactory getSessionFactory() { return sessionFactory; } @Autowired public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory = sessionFactory; this.hibernateTemplate = new HibernateTemplate(sessionFactory); } public void save(User user) { // TODO Auto-generated method stub // getHibernateTemplate().save(user); this.hibernateTemplate.save(user); } public void delete(User user) { // TODO Auto-generated method stub this.hibernateTemplate.delete(user); } public User searchUserbyId(String username) { // TODO Auto-generated method stub return this.hibernateTemplate.get(User.class, username); } } And this my stacktrace error when i run the program: pass org.springframework.orm.hibernate3.HibernateSystemException: Unknown entity: edu.acct.tsegay.model.User; nested exception is org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:679) at org.springframework.orm.hibernate3.HibernateAccessor.convertHibernateAccessException(HibernateAccessor.java:412) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:411) at org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:837) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:833) at edu.acct.tsegay.dao.UserDao.delete(UserDao.java:34) at edu.acct.tsegay.business.UserBusinessObject.delete(UserBusinessObject.java:30) at edu.acct.tsegay.common.App.main(App.java:23) Caused by: org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:580) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1365) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:100) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:74) at org.hibernate.impl.SessionImpl.fireDelete(SessionImpl.java:793) at org.hibernate.impl.SessionImpl.delete(SessionImpl.java:771) at org.springframework.orm.hibernate3.HibernateTemplate$25.doInHibernate(HibernateTemplate.java:843) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:406) ... 6 more Please let me know if you need any more of my configuration. Any help is much appreciated..

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• Error with perl script using module Mail::Sendmail

  - by Octopus

  I am using below code to connect to SMTP server where authentication is required for connection. While executing script I am getting an error message saying "Error sending mail: Connection error from mail.utiba.com on port 465 ()". However the connection to the mail server is working fine, I can connect to the mail server using other mail clients. Please suggest what I am doing wrong here. Is there any sendmail settings required? #!/usr/bin/perl use strict; use warnings; use Mail::Sendmail; print "Testing Mail::Sendmail version $Mail::Sendmail::VERSION\n"; print "Default server: $Mail::Sendmail::mailcfg{smtp}->[0]\n"; print "Default sender: $Mail::Sendmail::mailcfg{from}\n"; my %mail = ( From=> 'username', Bcc => '[email protected]', Cc=> '[email protected]', Subject => 'Test message', 'X-Mailer' => "Mail::Sendmail version $Mail::Sendmail::VERSION", ); $mail{Smtp} = 'mail.server.com:port'; $mail{auth} = {user=>'username', password=>"password", required=>1 }; $mail{'X-custom'} = 'My custom additionnal header'; $mail{'mESSaGE : '} = "The message key looks terrible, but works."; $mail{Date} = Mail::Sendmail::time_to_date( time() - 86400 ); if (sendmail %mail) { print "Mail sent OK.\n" } else { print "Error sending mail: $Mail::Sendmail::error \n" } print "\n\$Mail::Sendmail::log says:\n", $Mail::Sendmail::log;

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• How to use perl for SMTP connection with user and SSL Auth and send emails with attachment

  - by Octopus

  I am using a SMTP mail server which require user + ssl authentication for connection. I am looking for the perl modules to connect to the mail server and send emails but doesn't found anything helpful. Any suggestion for perl module or any perl code would be really appreciated. EDIT I have tried to use Mail::Sendmail and Net::SMTP::SSL to connect to the sendmail server and send mail. Below is the sample code but getting the error user unknown. Error: mail: Net::SMTP::SSL=GLOB(0x9599850) not found RCPT TO: error (550 5.1.1 <[email protected]>... User unknown). Code: #!/usr/bin/perl use strict; use warnings; use Mail::Sendmail; use Net::SMTP::SSL; my %mail = ( #To=> 'No to field this time, only Bcc and Cc', From=> '[email protected]', Cc=> '[email protected]', # Cc will appear in the header. (Bcc will not) Subject => 'Test message', 'X-Mailer' => "Mail::Sendmail version $Mail::Sendmail::VERSION", ); $mail{Smtp} = Net::SMTP::SSL->new("mail.server.com", Port=> 465); $mail{auth} = {user=>'username', password=>"password", required=>1 }; $mail{'X-custom'} = 'My custom additionnal header'; $mail{Message} = "The message key looks terrible, but works."; # cheat on the date: $mail{Date} = Mail::Sendmail::time_to_date( time() - 86400 ); if (sendmail %mail) { print "Mail sent OK.\n" } else { print "Error sending mail: $Mail::Sendmail::error \n" } print "\n\$Mail::Sendmail::log says:\n", $Mail::Sendmail::log;

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• storing user info/pass in web.config authentication

  - by Tomaszewski

  Hello, I am trying to write a simple internal app with some simple authentication. I'm also trying to make this quick and learn about the forms authentication via web.config. So i have my authentication working if I hard code my 'user name' and 'password' into C# code and do a simple conditional. However, I'm having a tough time storing the a user/pass to be checked against in the web.config file. The MSDN manual says to put this into the web.config: <authentication mode="Forms"> <forms loginUrl="login.aspx"> <credentials passwordFormat="SHA1"> <user name="user1" password="27CE4CA7FBF00685AF2F617E3F5BBCAFF7B7403C" /> <user name="user2" password="D108F80936F78DFDD333141EBC985B0233A30C7A" /> <user name="user3" password="7BDB09781A3F23885CD43177C0508B375CB1B7E9"/> </credentials> </forms> </authentication> However, the minute I add 'credentials' into the 'authentication' section, I get this error: Server Error in '/' Application. Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: Unrecognized element 'credentials'. Source Error: Line 44: <authentication mode="Forms"> Line 45: <forms loginUrl="login.aspx" /> Line 46: <credentials> Line 47: Line 48: </credentials> Source File: C:\inetpub\wwwroot\asp\projects\passwordCatalog\passwordCatalog\web.config Line: 46 So my question is, how and where would I add the following in the web.config file? <credentials passwordFormat="SHA1"> <user name="johndoe" password="mypass123" /> </credentials>

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• How to make NAnt send an email using a real account

  - by Turro

  First of all, I have already seen this post: nant mail issues but the only answer is not satisfactory (i.e.: doesn't work for me). I am using NAnt to get latest version of source, upgrade version of the libraries and application, build the application, build the setups... all the usual things, I bet. I would like NAnt to send an email to some people confirming the conclusion of the build process; I've already checked the official (pretty ugly, IMHO) documentation for the task, but the example, once copied and customized, doesn't work. This are the NAnt target and task I'm using: <target name="sendMail" > <mail from="[email protected]" tolist="[email protected];[email protected]" subject="Subject of email" mailhost="smtp.gmail.com" message="Your new release is ready!"> </mail> </target> The error message I get is: 530 5.7.0 Must issue a STARTTLS command first. It looks like that the task was designed for use by an account whose provider doesn't need authentication; but what can I do if I must use an external smtp server which requires authentication (telling my boss I need an smtp server in house is not an option)? Can anybody help/teach me? Thanks in advance...

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• Collaborative filtering in MySQL ?

  - by user281434

  Hi I'm trying to develop a site that recommends items(fx. books) to users based on their preferences. So far, I've read O'Reilly's "Collective Intelligence" and numerous other online articles. They all, however, seem to deal with single instances of recommendation, for example if you like book A then you might like book B. What I'm trying to do is to create a set of 'preference-nodes' for each user on my site. Let's say a user likes book A,B and C. Then, when they add book D, I don't want the system to recommend other books based solely other users experience with book D. I wan't the system to look up similar 'preference-nodes' and recommend books based on that. Here's an example of 4 nodes: User1: 'book A'->'book B'->'book C' User2: 'book A'->'book B'->'book C'->'book D' user3: 'book X'->'book Y'->'book C'->'book Z' user4: 'book W'->'book Q'->'book C'->'book Z' So a recommendation system, as described in the material I've read, would recommend book Z to User 1, because there are two people who recommends Z in conjuction with liking C (ie. Z weighs more than D), even though a user with a similar 'preference-node', User2, would be more qualified to recommend book D because he has a more similar interest-pattern. So does any of you have any experience with this sort of thing? Is there some things I should try to read or does there exist any open source systems for this? Thanks for your time! Small edit: I think last.fm's algorithm is doing exactly what I my system to do. Using the preference-trees of people to recommmend music more personally to people. Instead of just saying "you might like B because you liked A"

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• What is wrong with my Basic Authentication in my Browser?

  - by Pure.Krome

  Hi folks, i'm trying to goto the following url :- http://user1:pass1@localhost:1234/api/users?format=xml nothing to complex. Notice how i've got the username/password in the url? this, i believe, is for basic authentication. When I do that, the Request Headers are MISSING the 'Authorize' header. Er... that's not right :( I have anonymous authentication only setup on the site. I don't want to have anon off and basic turned on .. because not all of the site requires basic.. only a few action methods. So .. why is this not working? Is this something to do with the fact my code is not sending a 401 challenge or some crap? For What It's Worth, my site is ASP.NET MVC1 running on IIS7 (and the same thing happens when i run it on cassini). Update: If this is an illegal way of calling a resource using basic auth (ala security flaw) .. then is this possible to do, for an ASP.NET MVC website .. per action method (and not the entire site, per say)?

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• org.hibernate.NonUniqueObjectException Within GWT application using hibernate through gilead

  - by molleman

  Hello Guys, i am working on a project for college that uses GWT,Hibernate and Gilead. Basically for the moment users should be able to add friends and remove them. also a user can see if his or her friends are online or not. my trouble is that when i add a friend that is already related to another friend i get this error org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: [com.example.client.YFUser#4] i have a service class public class TestServiceImpl extends PersistentRemoteService implements TestService { this is my service class for my gwt application. my toruble is here with my implmentation class of my serivce in this method that is called when a user presses add friend button on the client-side public void addYFUserFriend(String userName){ //this retrieves the current user YFUser user = (YFUser)getSession().getAttribute(SESSION_USER); Session session = com.example.server.HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); YFUser friend = (YFUser) session.createQuery("select u FROM YFUser u where u.username = :username").setParameter("username", userName).uniqueResult(); System.out.println("user " + friend.getUsername() + " Found"); user.getFriends().add(friend); friend.getBefriended().add(user); session.update(user); session.update(friend); session.getTransaction().commit(); } a scenerio : user1 adds user2 as a friend. this works fine. then user3 adds user2 and the exeception is thrown. any ideas why and where my logic is going wrong Ok so i have changed my code, and i have removed all the getCurrentASession() calls and replaced with openSession() call which are closed at the appropiate point, now the error i am getting is com.google.gwt.user.server.rpc.UnexpectedException: Service method 'public abstract void com.example.client.TestService.addYFUserFriend(java.lang.String)' threw an unexpected exception: org.hibernate.NonUniqueResultException: query did not return a unique result: 3

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• Establishing persistent connection to a database in Java

  - by gmile

  I've ran through several examples over the web, and found that every single time I need something from the DB, I should write the following code: try { // Step 1: Load the JDBC driver. Class.forName("mysql_driver_name"); // Step 2: Establish the connection to the database. String url = "jdbc:string_to_mysql_server"; Connection conn = DriverManager.getConnection(url,"user1","password"); // fetch from the DB ... } catch (Exception e) { System.err.println("Got an exception! "); System.err.println(e.getMessage()); } It's very annoying to put up this code every time I want something from the DB, so the question is - is there a way to only once connect entirely all my app to the DB somehow at the very start point, avoiding copy-pasting mentioned code, and then be able to do everything I want with DB? I've quickly looked through NetBeans's Project menu, but didn't find any clue on how to configurate a persistent connection to a selected DB. If it's important, i'm writing a purely desktop app, i.e. using Java EE. Also, it's worth mentioning that I'm a kinda beginner in Java.

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• FTPing a file to Mainframe using Java, Apache Common Net

  - by SKR

  I'm am trying to upload a file into mainframe server using FTP. My code is below FTPClient client = new FTPClient(); InputStream in = null; FileInputStream fis = null; try{ client.connect("10.10.23.23"); client.login("user1", "pass123"); client.setFileType(FTPClient.BINARY_FILE_TYPE); int reply ; reply = client.getReplyCode(); System.out.println("Reply Code:"+reply); if(FTPReply.isPositiveCompletion(reply)){ System.out.println("Positive reply"); String filename ="D:\\FILE.txt"; in = new FileInputStream(filename); client.storeFile("FILE.TXT", in); client.logout(); fis.close(); }else{ System.out.println("Negative reply"); } }catch(final Throwable t){ t.printStackTrace(); } The code gets struck in client.storeFile("FILE.TXT", in); I am unable to debug. Please suggest ways / solutions.

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• Best practice to test a web application, regarding domain name and integration with external service

  - by ycseattle

  I have run into these problems several times and was never able to find a comfortable solution. Let's say my website has the domain name MyDomain.com. When I run the tests on the test machine (a continuous integration server), I will modify the HOSTS file on this machine so the MyDomain.com is mapped to this local machine instead of the real production server. This doesn't work very well for many situations. For example, my application will create subdomain names user1.MyDomain.com dynamically but this is difficult to keep the testing flexible. Another problem is my web application will interact with Amazon S3, and sometimes other service like Amazon Simple Message Queue. I am only comfortable to include these interaction in my tests but I am never happy with my solution for mixing testing and production on Amazon services. Could somebody offer some tips on these issues? I would like to make my testing framework clean and flexible. I am sure this is a common question for all web applications and there must be a mature way to deal with these. Thanks!

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• Codeigniter achor producing dodgy link in email inbox.. what could the problem be?

  - by Psychonetics

  My application is emailing out fine but the email I receive displays incorrectly. Rather than have text and a simple "click here to activate" link it doesn't. it shows this instead: Hi user1, please click the following link to activate your account <a href="http://mysite.com/activation/fzyZuyxVAzZS2koVg5UFjfVjlcLNcrzp">ssss</a> Here is the code from my model that sends email to user when they request activation email. $this->load->library('email'); $this->email->from('[email protected]', 'my site'); $this->email->to($result[0]->email); $this->email->subject('my site - Activate your account'); $this->email->message('Hi ' . $result[0]->first_name . ', please click the following link to activate your account ' . anchor('http://mysite.com/activation/' . $new_activation_code, 'click here to activate')); $this->email->send(); Also the mail always ends up in my spam folder.

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• How to filter txt file by string with using batch

  - by Antediluvian

  Hello guys I know this kind of problem will be very easy for you but I am total beginner in batch mode. The question is how bat file code should look like to generate a new txt file from specific one . for example . I have report txt Displaying status for license file: 7788@Server01 License Server: server01 License In Use Free ------- ------ ---- Design* 1 6 (user1@host1) 127 server01 7788 4402 Assembly* 0 4 Pro 0 15 AdvSE 2 3 (user2@host2) AdvSE server01 7788 2706 (user3@host3) AdvSE server01 7788 1503 SingleSite_License 1 3 (user4@host4) SingleSite_License server01 7788 2003 Intra_CLIENT_License 1 4 (user2@host2) Intra_CLIENT_License server01 7788 2003 CAD 1 32 ^(user2@host2) CAD server01 7788 501 * = License Extensions - Available only on startup. ^ = Borrowed License. Press any key to continue . . . What I want to have in new file from this one are only lines : SingleSite_License 3 Intra_CLIENT_License 9 but both SingleSite_License and Intra_Client_License should be taken from 1st found string -other are not necessary. report txt can be different and licenses can be showed in different order . if it not possible - other solution can be just only Free value will be written in new txt file - f.e 3 and 9 . so the last string in line which contains specific words thank you for any tips

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• What is the simplest way to map a folder on the file system to a url in Tomcat?

  - by Simon

  Here's my problem... I have a small prototype app (happens to be in Grails hosted on AWS) and I want to add the ability of the user to upload a few (max 10) images. I want to persist these images on disk on the server machine, in a folder location which is outside my WAR. I realise that there is probably a super-scalable solution involving more web servers and optimised static asset serving, but for the approximately 100 users I am likely to get, it's really not worth the effort and cost. So, what is the simplest way I can have a virtual folder from my url map to a physical folder on disk? I sort of want... http://myapp.com/static to map to a folder which I can configure e.g. /var/www/static so I can then have in my code... <img src="/static/user1/picture.jpg"/> I don't particularly mind whether the resulting physical folders are directly browsable. Security will eventually be an issue, but it isn't at the start. So, what are my options? I have looked at virtual hosts on the apache site, but it feels more complicated than I need. I don't want to use the Grails static rendering plugins.

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• Play! 1.2.5 with mongodb | Model Validation not happening

  - by TGV

  I have a simple User model whose fields are annotated with play validation annotations and morphia annotations like below. import play.data.validation.*; import play.modules.morphia.Model; import com.google.code.morphia.annotations.*; @Entity public class User extends Model{ @Id @Indexed(name="USERID", unique=true) public ObjectId userId; @Required public String userName; @Email @Indexed(name="USEREMAIL", unique=true) @Required public String userEmail; } Now I have a service which has a CreateNewUser method responsible for persisting the data. I have used Morphia plugin for the dao support. But the problem is that User Document gets persisted in mongo-db even if userName or userEmail is NULL. Also @Email validation does not happen // Below code is in app/controllers/Application.java User a = new User(); a.userName = "user1"; // calling bean to create user, userService is in app/service/UserService userService.createNewUser(a); It does not work even after adding @valid and validation.hasErrors() check.Below code is in app/service/UserService public void createNewUser(@Valid User user) { if (Validation.hasErrors()) { System.out.println("has errors"); } else { // TODO Auto-generated method stub userDao.save(user); } }

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• PHP: Adding text to a file

  - by Kevin Duke

  I'm trying to set up authentication on my server, however, I know little about Php. I have a php file filled with users and passwords: function getPassword( $user ) { // the user/password database. For very small groups // of users, you may just get away with expanding this // array. $passwords= array ( 'user1' => 'password1', 'user2' => 'password2', 'user3' => 'password3', 'user4' => 'password4' ); $password = $passwords[ $user ]; if ( NULL == $password ) return NULL; Without manually editing the array of passwords, I want a php file to read in user inputs for usernames and passwords and append it to the array. I have a vague idea of how this could work by looking up documentation: <?php function fwrite_stream($fp, $string) { $fp = fopen('shit.php', 'w'); for ($written = 0; $written < strlen($string); $written += $fwrite) { $fwrite = fwrite($fp, substr($string, $written)); if ($fwrite === false) { return $written; } } return $written; fclose($fp); } ?> How do I tell this to write to the array?

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• mailing system DB structure, need help

  - by Anna

  i have a system there user(sender) can write a note to friends(receivers), number of receivers=0. Text of the message is saved in DB and visible to sender and all receivers then they login to system. Sender can add more receivers at any time. More over any of receivers can edit the message and even remove it from DB. For this system i created 3 tables, shortly: users(userID, username, password) messages(messageID, text) list(id, senderID, receiverID, messageID) in table "list" each row corresponds to pair sender-receiver, like sender_x_ID -- receiver_1_ID -- message_1_ID sender_x_ID -- receiver_2_ID -- message_1_ID sender_x_ID -- receiver_3_ID -- message_1_ID Now the problem is: 1. if user deletes the message from table "messages" how to automatically delete all rows from table "list" which correspond to deleted message. Do i have to include some foreign keys? More important: 2. if sender has let say 3 receivers for his message1 (username1, username2 and username3) and at certain moment decides to add username4 and username5 and at the same time exclude username1 from the list of receivers. PHP code will get the new list of receivers (username2, username3, username4, username5) That means insert to table "list" sender_x_ID -- receiver_4_ID -- message_1_ID sender_x_ID -- receiver_5_ID -- message_1_ID and also delete from table "list" the row corresponding to user1 (which is not in the list or receivers any more) sender_x_ID -- receiver_1_ID -- message_1_ID which sql query to send from PHP to make it in an easy and intelligent way? Please help! Examples of sql queries would be perfect!

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• Forms authentication: how do you store username password in web.config?

  - by Nick G

  I'm used to using Forms Authentication with a database, but I'm writing a little internal utility and the app doesn't have a database so I want to store the username and password in web.config. However for some reason, forms authentication is still trying to access SQL Server and I can't see how to stop it doing this and pick up the credentials from web.config. What am I doing wrong? I just get the error "Failed to generate a user instance of SQL Server due to a failure in impersonating the client. The connection will be closed." Here are the relevant sections of my web.config: <configuration> <system.web> <authentication mode="Forms"> <forms loginUrl="~/Login.aspx" timeout="60" name=".LoginCookie" path="/" > <credentials passwordFormat="Clear"> <user name="user1" password="[pass]" /> <user name="user2" password="[pass]" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration>

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• Store multiple values in a session variable

  - by user458790

  Hi, Before I ask my doubt, please consider this scenario that a user on my website have a profileID. With this profileID are associated some pluginID's. For eg: User1 might have 2, 3 and 5 plugins associated with its profile. When the user logs in, I store the profileID of the user in a session variable cod. At a certain page, the user tries to edit the plugins associated with his profile. So, on that page, I have retrieve those pluginID's from the DB. I have applied this code but this fetches only the maximum pluginID from the DB and not all the pluginID's. SqlCommand cmd1 = new SqlCommand("select plugin_id from profiles_plugins where id=(select id from profiles_plugins where profile_id=" + Convert.ToInt32(Session["cod"]) + ")", con); SqlDataReader dr1 = cmd1.ExecuteReader(); if (dr1.HasRows) { while (dr1.Read()) { Session["edp1"] = Convert.ToInt32(dr1[0]); } } dr1.Close(); cmd1.Dispose(); I was trying to figure out how can I store multiple pluginID's in this session variable? Thanks

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• Do you catch expected exceptions in the controller or business service of your asp.net mvc application

  - by Pascal

  I am developing an asp.net mvc application where user1 could delete data records which were just loaded before by user2. User2 either changes this non-existent data record (Update) or is doing an insert with this data in another table that a foreign-key constraint is violated. Where do you catch such expected exceptions? In the Controller of your asp.net mvc application or in the business service? Just a sidenote: I only catch the SqlException here if its a ForeignKey constraint exception to tell the user that another user has deleted a certain parent record and therefore he can not create the testplan. But this code is not fully implemented yet! Controller:   public JsonResult CreateTestplan(Testplan testplan)   {    bool success = false;    string error = string.Empty;    try   {    success = testplanService.CreateTestplan(testplan);    }   catch (SqlException ex)    {    error = ex.Message;    }    return Json(new { success = success, error = error }, JsonRequestBehavior.AllowGet);   } OR Business service: public Result CreateTestplan(Testplan testplan) { Result result = new Result(); try { using (var con = new SqlConnection(_connectionString)) using (var trans = new TransactionScope()) { con.Open(); _testplanDataProvider.AddTestplan(testplan); _testplanDataProvider.CreateTeststepsForTestplan(testplan.Id, testplan.TemplateId); trans.Complete(); result.Success = true; } } catch (SqlException e) { result.Error = e.Message; } return result; } then in the Controller: public JsonResult CreateTestplan(Testplan testplan)   {    Result result = testplanService.CreateTestplan(testplan);       return Json(new { success = result.success, error = result.error }, JsonRequestBehavior.AllowGet);   }

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• problem in variables in jquery

  - by Alvin

  Hi, I don't understand why I'm not getting the message as "username already exits" if type the username which is already in database. If the username in a server, then it is returning the value as "1" otherwise empty, and despite of successfully getting the value from the server based on username is present or not, and assigning the value to variable "x", I'm unable to get message when I pass already exist username. May I know? $(document).ready(pageInit); function pageInit() { $('#1').bind('blur',go); } function go() { var value = $('#1').val(); var x = 0; $.post('just.do',{username:value},function(data){ x = data; } ); if(x) { $('#para').show(); $('#para').html("Username already exits"); return false; } else { $('#para').hide(); return true; } }; EDIT: This is what I'm doing in post request in servlets: String user1 = request.getParameter("username"); if(user != null) { String query = "Select * from users where user_name="+"\""+user+"\""; b = db.doExecuteQuery(stmt,query); if(b) { out.write("1"); } }

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