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  • PHP OOP singleton doesn't return object

    - by Misiur
    Weird trouble. I've used singleton multiple times but this particular case just doesn't want to work. Dump says that instance is null. define('ROOT', "/"); define('INC', 'includes/'); define('CLS', 'classes/'); require_once(CLS.'Core/Core.class.php'); $core = Core::getInstance(); var_dump($core->instance); $core->settings(INC.'config.php'); $core->go(); Core class class Core { static $instance; public $db; public $created = false; private function __construct() { $this->created = true; } static function getInstance() { if(!self::$instance) { self::$instance = new Core(); } else { return self::$instance; } } public function settings($path = null) { ... } public function go() { ... } } Error code Fatal error: Call to a member function settings() on a non-object in path It's possibly some stupid typo, but I don't have any errors in my editor. Thanks for the fast responses as always.

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  • How to upgrade internal php version of Zend Studio / Eclipse

    - by Moak
    I was following this tutorial when typing up this code: public function search($term){ $filter = function($tag) use ($term){ if(stristr($tag,$term)) return true; return false; }; return array_filter($this->_tags,$filter); } I get following errors in Zend Studio 8 syntax error, unexpected '{' syntax error, unexpected 'function' syntax error, unexpected 'use' However the code works fine on my Xampp with php 5.3.1 - How can I find the version of PHP in Zend Studio, and how can I upgrade it?

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  • PHP Included files writing their own content from Importer values ...

    - by Adrian
    Hello, I have a index.php file that will include several external files: "content/templates/id1/template.php" "content/templates/id2/template.php" "content/templates/id3/template.php" etc. All these files are loaded dynamically into index.php (it reads all folders inside "templates" directory and then includes every "template.php" file). I want to make "template.php" to have the same code in all the "id1,id2,id3" folders, BUT to load values from index.php depending in which folder it stays.. How can I do that? Thank You!

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  • SQL wont work? It doesn't come up with errors either

    - by Stefan
    Hey there, I have php function which checks to see if variables are set and then adds them onto my sql query. However I am don't seem to be getting any results back!? $where_array = array(); if (array_key_exists("location", $_GET)) { $location = addslashes($_GET['location']); $where_array[] = "`mainID` = '".$location."'"; } if (array_key_exists("gender", $_GET)) { $gender = addslashes($_GET["gender"]); $where_array[] = "`gender` = '".$gender."'"; } if (array_key_exists("hair", $_GET)) { $hair = addslashes($_GET["hair"]); $where_array[] = "`hair` = '".$hair."'"; } if (array_key_exists("area", $_GET)) { $area = addslashes($_GET["area"]); $where_array[] = "`locationID` = '".$area."'"; } $where_expr = ''; if ($where_array) { $where_expr = "WHERE " . implode(" AND ", $where_array); } $sql = "SELECT `postID` FROM `posts` ". $where_expr; $dbi = new db(); $result = $dbi->query($sql); $r = mysql_fetch_row($result); I'm trying to call the data after in a list like so: $dbi = new db(); $offset = ($currentpage - 1) * $rowsperpage; // get the info from the db $sql .= " ORDER BY `time` DESC LIMIT $offset, $rowsperpage"; $result = $dbi->query($sql); // while there are rows to be fetched... while ($row = mysql_fetch_object($result)){ // echo data echo $row['text']; } // end while Anyone got any ideas why I am not retrieving any data? -Stefan

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  • php insert doesnot take place _ URGENT HELP PLEASE

    - by reggie
    my code is as follows <?php include("config.php"); $ip=$_SERVER['REMOTE_ADDR']; if($_POST['id']) { $id=$_POST['id']; $id = mysql_escape_String($id); $ip_sql=mysql_query("select ip_add from Voting_IP where mes_id_fk='$id' and ip_add='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0) { $sql = "update Messages set up=up+1 where mes_id='$id'"; mysql_query($sql); $sql_in = "insert into Voting_IP (mes_id_fk,ip_add) values ('$id','$ip')"; mysql_query($sql_in) or die(mysql_error()); echo "<script>alert('Thanks for the vote');</script>"; } else { echo "<script>alert('You have already voted');</script>"; } $result=mysql_query("select up from Messages where mes_id='$id'"); $row=mysql_fetch_array($result); $up_value=$row['up']; echo "<img src='button.png' width='110' height='90'>"; echo $up_value; } ?> My problem is that the insert process doesnot take place at all. the script tags echos an alert box. even the img tag is echoed to the web page. but the insert process doesnot take place. the config file is fine.. note: this code works on my local machine which has php 5.3 but it doesnot work on the server which has php 5.2.. any advice..???

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  • [PHP] strtr function OS-reltated problem

    - by Casidiablo
    Hello there! I have this funtion that converts all special chars to uppercase: function uc_latin1($str) { if(!defined("LATIN1_UC_CHARS")) define("LATIN1_UC_CHARS", "ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝ"); if(!defined("LATIN1_LC_CHARS")) define("LATIN1_LC_CHARS", "àáâãäåæçèéêëìíîïðñòóôõöøùúûüý"); $str = strtoupper ( strtr ( $str, LATIN1_LC_CHARS, LATIN1_UC_CHARS ) ); return $str; } This function works fine in my development PC (which runs Windows XP)... but, when I test it in the production server (running Redhat Linux) it does not uppercase the string. The string is ISO-8859-1 encoded. How can I make it work in Linux too? Thanks for reading.

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  • Adding an Array inside an array in a PHP function

    - by bateman_ap
    I have created a function in PHP that calls a webservice and parses through the result, assinging values to variables and returning them all as an Array. This all works perfectly, however I have come across a need to have an "array within my array" I am assigning values as below: $productName = $product->Name; $productID = $product->ID; $productArray = array( 'productName' => "$productName", 'productID' => "$productID" ); return $productArray; However I now have a piece of data that comes back with multiple results so I need to have a additional array to store these, I am getting the values from the returned XML using a foreach loop, however I want to be able to add them to the array with a name so I can reference them in the returned data, this is where I have a problem... $bestForLists = $product->BestFors; foreach( $bestForLists as $bestForList ) { $productBestFors = $bestForList->BestFor; foreach( $productBestFors as $productBestFor ) { $productBestForName = $productBestFor->Name; $productBestForID = $productBestFor->ID; } } I tried creating an array for these using the below code: $bestForArray[] = (array( "productBestForID" => "$productBestForID", "productBestForName" => "$productBestForName" )); And then at the end merging these together: $productArray= array_merge($productArray,$bestForArray); If I print out the returned value I get: Array ( [productName] => Test Product [productID] => 14128 [0] => Array ( [productBestForID] => 56647 [productBestForName] => Lighting ) [1] => Array ( [productBestForID] => 56648 [productBestForName] => Sound ) ) I would like to give the internal Array a name so I can reference it in my code, or is there a better way of doing this, at the moment I am using the following in my PHP page to get values: $productName = $functionReturnedValues['productName']; I would like to use the following to access the array I could then loop through: $bestForArray = $functionReturnedValues['bestForArray']; Hope someone can help

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  • pass php array to jquery with getJSON

    - by robertdd
    i want to pass a php aray to jQuery: $.getimagesarr = function() { $.getJSON('operations.php', {'operation':'getimglist'}, function(data){ var arr = new Array(); arr = data; return arr; }); } var data = $.getimagesarr(); if (data){ jQuery.each(data, function(i, val) { .... }); } it return undefined in php i have this: function getimglist(){ $results = $_SESSION['files']; echo json_encode($results); } it is possible?

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  • Using JQuery Ajax to call a php function

    - by Stevie Jenowski
    Hello! First and foremost thank you for checking out my problem, and for any help you may give! Okay, so like the title says I'm in need of calling a php function from my index page, which adds a new record in my database as a vote, using JQuery Ajax. This function will return one integer, which will then be printed inside the form button in which it was called from. Anyone have an idea on how I would accomplish this? Any guidance is appreciated!

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  • Parsing HTML: Call to a member function > children() on a non-object

    - by sm56d
    Hello all, I was just helped with this question but I can't get it to move to the next block of HTML. $html = file_get_html('http://music.banadir24.com/singer/aasha_abdoo/247.html'); $urls = $html->find('table[width=100%] table tr'); foreach($urls as $url){ $song_name = $url->children(2)->plaintext; $url = $url->children(6)->children(0)->href; } It returns the list of the names of the first album (Deesco) but it does not continue to the next album (The Best Of Aasha)? It just gives me this error: Notice: Trying to get property of non-object in C:\wamp\www\test3.php on line 26 Fatal error: Call to a member function children() on a non-object in C:\wamp\www\test3.php on line 28 Why is this and how can I get it to continue to the next table element? I appreciate any help on this! Please note: This is legal as the songs are not bound by copyright and they are available to download freely, its just I need to download a lot of them and I can't sit there clicking a button all day. Having said that, its taken me an hour to get this far.

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  • Calling overridden method from within overriding method in OO PHP

    - by paddymcc
    Working in a symfony model, I want to override a function and call the overridden function from within the overriding one, along the lines of class MyClass extends BaseMyClass { function setMyProperty($p) { parent::setMyProperty($p); //do some other stuff } } This is resulting in a segmentation fault. I don't want to alter the parent class - it's been generated by symfony, and may feasibly be overwritten in the future if the model is rebuilt. This seems like something that should be straightforward, but I'm struggling to find the solution. Thanks for any advice

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • matlab constant anonymous function returns only one value instead of an array

    - by Filo
    I've been searching the net for a couple of mornings and found nothing, hope you can help. I have an anonymous function like this f = @(x,y) [sin(2*pi*x).*cos(2*pi*y), cos(2*pi*x).*sin(2*pi*y)]; that needs to be evaluated on an array of points, something like x = 0:0.1:1; y = 0:0.1:1; w = f(x',y'); Now, in the above example everything works fine, the result w is a 11x2 matrix with in each row the correct value f(x(i), y(i)). The problem comes when I change my function to have constant values: f = @(x,y) [0, 1]; Now, even with array inputs like before, I only get out a 1x2 array like w = [0,1]; while of course I want to have the same structure as before, i.e. a 11x2 matrix. I have no idea why Matlab is doing this...

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  • How to send XML and other post parameters via cURL in PHP

    - by tomaszs
    Hello. I've used code below to send XML to my REST API. $xml_string_data contains proper XML, and it is passed well to mypi.php: //set POST variables $url = 'http://www.server.cu/mypi.php'; $fields = array( 'data'=>urlencode($xml_string_data) ); //url-ify the data for the POST $fields_string = ""; foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); echo $fields_string; //open connection $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch,CURLOPT_HTTPHEADER,array ( "Expect: " )); //execute post $result = @curl_exec($ch); But when I've added other field: $fields = array( 'method' => "methodGoPay", 'data'=>urlencode($xml_string_data) ); It stopped to work. On the mypi.php I don't recieve any more POST parameters at all! Could you you please tell me what to do to send XML and other post parameters in one cURL request? Please don't suggest using any libraries, I wan't to acomplish it in plain PHP.

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  • PHP - JSON Steam API query

    - by Hunter
    First time using "JSON" and I've just been working away at my dissertation and I'm integrating a few features from the steam API.. now I'm a little bit confused as to how to create arrays. function test_steamAPI() { $api = ('http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key='.get_Steam_api().'&steamids=76561197960435530'); $test = decode_url($api); var_dump($test['response']['players'][0]['personaname']['steamid']); } //Function to decode and return the data. function decode_url($url) { $decodeURL = $url; $data = file_get_contents($url); $data_output = json_decode($data, true); return $data_output; } So ea I've wrote a simple method to decode Json as I'll be doing a fair bit.. But just wondering the best way to print out arrays.. I can't for the life of me get it to print more than 1 element without it retunring an error e.g. Warning: Illegal string offset 'steamid' in /opt/lampp/htdocs/lan/lan-includes/scripts/class.steam.php on line 48 string(1) "R" So I can print one element, and if I add another it returns errors. EDIT -- Thanks for help, So this was my solution: function test_steamAPI() { $api = ('http://api.steampowered.com/ISteamUser/GetPlayerSummaries/v0002/?key='.get_Steam_api().'&steamids=76561197960435530,76561197960435530'); $data = decode_url($api); foreach($data ['response']['players'] as $player) { echo "Steam id:" . $player['steamid'] . "\n"; echo "Community visibility :" . $player['communityvisibilitystate'] . "\n"; echo "Player profile" . $player['profileurl'] ."\n"; } } //Function to decode and return the data. function decode_url($url) { $decodeURL = $url; $json = file_get_contents($decodeURL); $data_output = json_decode($json, true); return $data_output; } Worked this out by taking a look at the data.. and a couple json examples, this returns an array based on the Steam API URL (It works for multiple queries.... just FYI) and you can insert loops inside for items etc.. (if anyone searches for this).

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  • php request variables assigning $_GEt

    - by chris
    if you take a look at a previous question http://stackoverflow.com/questions/2690742/mod-rewrite-title-slugs-and-htaccess I am using the solution that Col. Shrapnel proposed- but when i assign values to $_GET in the actual file and not from a request the code doesnt work. It defaults away from the file as if the $_GET variables are not set The code I have come up with is- if(!empty($_GET['cat'])){ $_GET['target'] = "category"; if(isset($_GET['page'])){ $_GET['pageID'] = $_GET['page']; } $URL_query = "SELECT category_id FROM cats WHERE slug = '".$_GET['cat']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); $_GET['category_id'] = $URL_array['category_id']; }elseif($_GET['product']){ $_GET['target'] = "product"; $URL_query = "SELECT product_id FROM products WHERE slug = '".$_GET['product']."';"; $URL_result = mysql_query($URL_query); $URL_array = mysql_fetch_array($URL_result); print_r($URL_array); $_GET['product_id'] = $URL_array['product_id']; The original variable string that im trying to represent is /cart.php?Target=product&product_id=16142&category_id=249 And i'm trying to build the query string variables with code and including cart.php so i can use cleaner URL's So I have product/product-title-with-clean-url/ going to slug.php?product=slug Then the slug searches the db for a record with the matching slug and returns the product_id as in the code above.Then built the query string and include cart.php

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  • bitly php url wont work???

    - by mathiregister
    Hi guys, <?php include('bitly.php'); $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten('http://www.google.com'); ?> WORKING!!! $currenturl = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; include('bitly.php'); $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten($currenturl); WORKING!!! include('bitly.php'); $currenturl = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = "somehashtag" $shareurl = $currenturl . '#' . $url; $bitly = new bitly('myusername', 'myapikey'); print $bitly->shorten($shareurl); NOT WORKING!!! Any idea why? If i print out the $shareurl i can see that it's a completely normal url that i could paste onto the normal bit.ly website. I don't get it! Any ideas? Would be great if you could help me!

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  • Unserializing an API return object (PHP/Ebay API)

    - by DavidYell
    I have been working with the Ebay api for a project and have found it great. I have however found a problem now, more PHP related. When I read my items from Ebay, I store a bunch of details in the database. Currently, just for the sake of it really, I serialize the whole return object and store it in the database in a related table. The idea being, that when I display my information, I have all the details to hand should I need them. The problem arises in that the pricing information is always in a sub object. [ConvertedAdjustmentAmount] => __PHP_Incomplete_Class Object ( [__PHP_Incomplete_Class_Name] => eBayAmountType [_] => 0 [currencyID] => USD ) As you can see when I unserialize my object, my cunning plan falls foul of the Incomplete class problem. I have checked the following question, without success. http://stackoverflow.com/questions/965611/forcing-access-to-php-incomplete-class-object-properties The main issue lies, as far as I can see, in that the price class is stored in the Ebay api, so how do I recreate it? I have been reading this page, http://uk3.php.net/manual/en/function.unserialize.php and trying to figure out, unserialize_callback_func which I can't figure out either, so any help would be appreciated!

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  • HTML5 audio with PHP script does not work on iPad/Iphone

    - by saulob
    Ok, I'm trying to play an HTML audio code on iPad but does not work. I created one PHP script to send to the MP3 request to the HTML5 audio code mp3_file_player.php?n=mp3file.mp3 The player is here: http://www.avault.com/news/podcast-news/john-romero-podcast-episode-80/ You will see that works on every HTML5 supported browser even on my iPod Touch. But does not work on iPad/iPhone, even on Safari on Mac OSX (I tried on Safari/Windows, worked fine) This is my PHP code: header("X-Powered-By: "); header("Accept-Ranges: bytes"); header("Content-Length: ". (string)(filesize($episode_filename)) .""); header("Content-type: audio/mpeg"); readfile($episode_filename); exit(); Everything works fine, the MP3 has the same headers like reading the mp3 directly. HTTP Headers from direct file access: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:31 GMT Server Apache/2.2.9 Last-Modified Wed, 26 May 2010 13:39:19 GMT Etag "dac0039-41d91f8-4877f669cefc0" Accept-Ranges bytes Content-Length 50656162 Content-Range bytes 18390614-69046775/69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg HTTP Header from my PHP script: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:08 GMT Server Apache/2.2.9 Accept-Ranges bytes Content-Length 69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg The only thing different it's the Content-Range, I even tried to add it, but if I use it the player will not work on my Ipod Touch. So I removed. Thank you very much.

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  • mysql data being inserted twice via php

    - by Jascha
    I can't for the life of me figure out why this function is causing multiple entries into my database table... When I run the function I end up with two records stacked on top of each one second apart here is the function: function generate_signup_token(){ $connection = new DB_Connect(); // <--- my database connection class $ip = mysql_real_escape_string($_SERVER['REMOTE_ADDR']); $sign_up_token = uniqid(mt_rand(), true); $_SESSION['signup_token'] = $sign_up_token; $sign_up_token = mysql_real_escape_string($sign_up_token); $query = "INSERT INTO `token_manager` (`ip_address`, `signup_token`) VALUES ('$ip', '$sign_up_token')"; mysql_query($query); } generate_signup_token();

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  • Problem with checkboxes, sql select statements & php

    - by smokey20
    I am trying to display some rows from a database table based on choices submitted by the user. Here is my form code <form action="choice.php" method="POST" > <input type="checkbox" name="variable[]" value="Apple">Apple <input type="checkbox" name="variable[]" value="Banana">Banana <input type="checkbox" name="variable[]" value="Orange">Orange <input type="checkbox" name="variable[]" value="Melon">Melon <input type="checkbox" name="variable[]" value="Blackberry">Blackberry From what I understand I am placing the values of these into an array called variable. Two of my columns are called receipe name and ingredients(each field under ingredients can store a number of fruits). What I would like to do is, if a number of checkboxes are selected then the receipe name/s is displayed. Here is my php code. <?php // Make a MySQL Connection mysql_connect("localhost", "*****", "*****") or die(mysql_error()); mysql_select_db("****") or die(mysql_error()); $variable=$_POST['variable']; foreach ($variable as $variablename) { echo "$variablename is checked"; } $query = "SELECT receipename FROM fruit WHERE $variable like ingredients"; $row = mysql_fetch_assoc($result); foreach ($_POST['variabble'] as $ingredients) echo $row[$ingredients] . '<br/>'; ?> I am very new to php and just wish to display the data, I do not need to perform any actions on it. I have tried many select statements but I cannot get any results to display. My db connection is fine and it does print out what variables are checked. Many thanks in advance.

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  • Problem with thumbnails after newly added - PHP on-the-fly method

    - by Wayne
    Hey again... to those that may have read my previous question that got solved a couple minutes ago .< The on-the-fly php script works perfectly, but when I went to upload new images into a gallery which I made myself, the images are resized to 150 x 150 for what I wanted... however, when it comes to new images being added it is all black... As you can see the three black images that were uploaded to the folder and the directory added to the database. What is causing this? If I view the source, the code is fine... the while loop in the PHP generates an output like this: <div class="view-wrap" id="photo-10"> <div class="view-icon"> <div class="img-label"> <a href="#" id="10" class="delete"><img src="img/small-delete.png" /> Delete</a> </div> <a href="img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg"> <img src="image.php?dir=img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg" alt="" width="110" height="110" /> </a> </div> </div> An example of one block. If I view the source (in Firefox) and click on the image.php?dir=img/events/Paintballing/24251_1395408043148_1170626626_1204038_5382765_n.jpg by exmaple, I can see the thumbnail at it's 150 x 150 size but in the layout, it shows a black thumbnail... Does anyone know why this is happening?

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  • Creating an HTML file by combining multiple PHP files via the command line?

    - by FishOrDie
    Is it possible to combine multiple PHP files via the command line and create an HTML file? For example, this will save the rendered version of a single PHP file as HTML: php /path/to/my/file/filename.php > /path/to/my/file/test.html I need it to combine multiple files, but I can't seem to get it it to work. Ideally, it would be something like this: php /path/to/my/file/filename.php + /path/to/my/file/filename2.php + /path/to/my/file/filename3.php > /path/to/my/file/test.html Is this possible? If so, how?

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  • Image generated with PHP dosn't show

    - by lolalola
    Hi, whats wrong with my code. image dosn't show in test2.php file File: test2.php: <img src = "test.php" /> File: test.php session_start(); $md5_hash = md5(rand(0,999)); $security_code = substr($md5_hash, 15, 5); $_SESSION["security_code"] = $security_code; $width = 100; $height = 20; header("Content-type: image/png"); $image = ImageCreate($width, $height); $white = ImageColorAllocate($image, 255, 255, 255); $black = ImageColorAllocate($image, 0, 0, 0); $grey = ImageColorAllocate($image, 204, 204, 204); ImageFill($image, 0, 0, $black); //Add randomly generated string in white to the image ImageString($image, 3, 30, 3, $security_code, $white); //Throw in some lines to make it a little bit harder for any bots to break imageRectangle($image,0,0,$width-1,$height-1,$grey); imageline($image, 0, $height/2, $width, $height/2, $grey); imageline($image, $width/2, 0, $width/2, $height, $grey); imagepng($image); imagedestroy($image);

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