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• Connection to mysql works through php but not through a form submission?

  - by Legend

  I have a download.php file that connects to a remote mysql database. If I run it using php download.php it works fine. But if I create another php file form.php and then submit the form to this download.php, it complains the following: Can't connect to MySQL server on '<IP_ADDRESS>' (13) Does anyone know why this might be happening? I can't see a reason why this works directly but fails to work upon form submission...

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• function file_exists not working in php

  - by Rakesh R Nair

  I have been trying to find if a file_exist in the directory. If not i want to use a different image. But as i am using the file_exists function it always returns false. The code i used is while($r=mysql_fetch_row($res)) { if(!file_exists('http://localhost/dropbox/lib/admin/'.$r[5])) { $file='http://localhost/dropbox/lib/admin/images/noimage.gif'; } else $file='http://localhost/dropbox/lib/admin/'.$r[5];} But the function always return false even if the file exits. I checked that by using <img src="<?php echo 'http://localhost/dropbox/lib/admin/'.$r[5]; ?>" /> This displayed the image correctly. Please Someone Help Me

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• Adding a method to a function object at runtime

  - by Carson Myers

  I read a question earlier asking if there was a times method in Python, that would allow a function to be called n times in a row. Everyone suggested for _ in range(n): foo() but I wanted to try and code a different solution using a function decorator. Here's what I have: def times(self, n, *args, **kwargs): for _ in range(n): self.__call__(*args, **kwargs) import new def repeatable(func): func.times = new.instancemethod(times, func, func.__class__) @repeatable def threeArgs(one, two, three): print one, two, three threeArgs.times(7, "one", two="rawr", three="foo") When I run the program, I get the following exception: Traceback (most recent call last): File "", line 244, in run_nodebug File "C:\py\repeatable.py", line 24, in threeArgs.times(7, "one", two="rawr", three="foo") AttributeError: 'NoneType' object has no attribute 'times' So I suppose the decorator didn't work? How can I fix this?

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• Write to PDF using PHP from android device

  - by Brent Mitchell

  I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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• get the list and input from one function and run them in different function

  - by rookie

  i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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• PHP classes, parse syntax errors when using 'var' to declare variables

  - by jon

  I am a C# guy trying to translate some of my OOP understanding over to php. I'm trying to make my first class object, and are hitting a few hitches. Here is the beginning of the class: <?php require("Database/UserDB.php"); class User { private var $uid; private var $username; private var $password; private var $realname; private var $email; private var $address; private var $phone; private var $projectArray; public function _construct($username) { $userArray = UserDB::GetUserArray($username); $uid = $userArray['uid']; $username = $userArray['username']; $realname = $userArray['realname']; $email = $userArray['email']; $phone = $userArray['phone']; $i = 1; $projectArray = UserDB::GetUserProjects($this->GetID()); while($projectArray[$i] != null) { $projectArray[$i] = new Project($projectArray[$i]); } UserDB.php is where I have all my static functions interacting with the Database for this User Class. I am getting errors using when I use var, and I'm getting confused. I know I don't HAVE to use var, or declare the variables at all, but I feel it is a better practice to do so. the error is "unexpected T_VAR, expecting T_VARIABLE" When I simply remove var from the declarations it works. Why is this?

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• Increasing understanding of validating a string with PHP string functions

  - by user1554264

  I've just started attempts to validate data in PHP and I'm trying to understand this concept better. I was expecting the string passed as an argument to the $data parameter for the test_input() function to be formatted by the following PHP functions. trim() to remove white space from the end of the string stripslashes() to return a string with backslashes stripped off htmlspecialchars() to convert special characters to HTML entities The issue is that the string that I am echoing at the end of the function is not being formatted in the way I desire at all. In fact it looks exactly the same when I run this code on my server - no white space removed, the backslash is not stripped and no special characters converted to HTML entities. My question is have I gone about this in the wrong approach? Should I be creating the variable called $santised_input on 3 separate lines with each of the functions trim(), stripslashes() and htmlspecialchars()? By my understanding surely I am overwriting the value of the $santised_input variable each time I recreate it on a new line of code. Therefore the trim() and stripslashes() string functions will never be executed. What I am trying to achieve is using the "$santised_input" variable to run all of these PHP string functions when the $data argument is passed to my test_input() function. In other words can these string functions be chained together so that I only need to create $santised_input once? <?php function test_input($data) { $santised_input = trim($data); $santised_input = stripslashes($data); $santised_input = htmlspecialchars($data); echo $santised_input; } test_input("%22%3E%3Cscript%3Ealert('hacked')%3C/script%3E\ "); //Does not output desired result "&quot;&gt;&lt;script&gt;alert('hacked')&lt;/script&gt;" ?>

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• Pointer to current function

  - by pythonic metaphor

  Is there any way to get a pointer to the current function, maybe through gcc extensions or some other trickery?

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• Upload to a PHP Server, using Ajax ( XMLHttp POST)

  - by Krishnanunni

  Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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• using a href (html)tag along with PHP

  - by dexter

  i have tried: <?php include("delete.php") ?> <?php .... .... .... if($result=mysql_query($sql)) { echo "<table><th>Id</th><th>Name</th><th>Description</th><th>Unit Price</th>"; while($row = mysql_fetch_array($result)) { echo "<tr><td>".$row['Id']."</td><td>".$row['Name']."</td><td>".$row['Description']."</td><td>".$row['UnitPrice']."</td> <td><a href='delproduct($row[Id])' onclick = 'return MsgOkCancel()'>Delete</a></td></tr>"; echo "<br/>"; } } ?> following javascript is in the same page: <script type="text/javascript" language="javascript"> function MsgOkCancel() { if (confirm("Are You Sure You Want to Delete?")) { return true } else {return false} } </script> where delproduct is a javascript function in delete.php written like: <script type="javascript"> function delproduct(Id) { alert('Id '+ Id); } <script> ** after ** clicking Delete a okcancel message-box appear asking conformation ** but ** after clicking 'ok' it should execute statements inside delproduct function but it doesn't it gives error like: Object Not Found :The requested URL was not found on this server. what would be the problem? pls help, thanks

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• Why is my php script freezing?

  - by William

  What is causing my php code to freeze? I know it's cause of the while loop, but I have $max_threads--; at the end so it shouldn't do that. <html> <head> <?php $db = mysql_connect("host","name","pass") or die("Can't connect to host"); mysql_select_db("dbname",$db) or die("Can't connect to DB"); $sql_result = mysql_query("SELECT MAX(Thread) FROM test_posts", $db); $rs = mysql_fetch_row($sql_result); $max_threads = $rs[0]; $board = $_GET['board']; ?> </head> <body> <?php While($max_threads >= 0) { $sql_result = mysql_query("SELECT MIN(ID) FROM test_posts WHERE Thread=".$max_threads."", $db); $rs = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT post FROM test_posts WHERE ID=".$rs[0]."", $db); $post = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT name FROM test_posts WHERE ID=".$rs[0]."", $db); $name = mysql_fetch_row($sql_result); $sql_result = mysql_query("SELECT trip FROM test_posts WHERE ID=".$rs[0]."", $db); $trip = mysql_fetch_row($sql_result); if(!empty($post)) echo'<div class="postbox"><h4>'.$name[0].'['.$trip[0].']</h4><hr />' . $post[0] . '<br /><hr />[<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread='.$max_threads.'">Reply</a>]</div>'; $max_threads--; } ?> </body> </html>

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• Redirecting Pages with PHP causing problems

  - by psp

  I have a page which has a link to a php page which takes data from $_GET and updates a database. After that it returns the user to the homepage with: header("Location: http://localhost/"); The thing is that this seems to "interrupt" the mysql part of the code. If I remove this redirect, everything in the database is updated, but when I put it back, nothing gets updated... This is the database update code, I am using a class of mine as a mysql wrapper: $conn->where('hash',$data1['hash']); $conn->update(TABLE_ITEMS,$newData1); $conn->where('hash',$data2['hash']); $conn->update(TABLE_ITEMS,$newData2); Notes: -There is no text or echo()'s on the page and no space before the <?php tag Order of Code: Data received from $_SESSION and $_GET Data processed and placed into arrays Data placed into mysql database header(); used to redirect page Code <?php require_once('config.php'); import(); if ( isset ( $_GET['g'] ) && isset ( $_SESSION['itemA'] ) && isset ( $_SESSION['itemB'] ) ) { $itemA = $_SESSION['gameA']; $itemB = $_SESSION['gameB']; $newData1 = processData($itemA); $newData2 = processData($itemB); $conn->update(TABLE_ITEMS,$newData1); $conn->update(TABLE_ITEMS,$newData2); header('Location: http://localhost/'); } else { header('Location: http://localhost/'); }

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• I want to store a php $_SESSION variable and retrieve it on another page.

  - by CDeanMartin

  <?php session_start(); // store session data $_SESSION['count']=0; ?> <html><head></head> <body> <?php include ("getElement.php"); echo getLinkButton("myscript.php", "myscript.php"); echo $_SESSION['count']++; ?> </body> </html> The code above works, but when I click the link to navigate to myscript.php: <?php echo $_SESSION['count']; ?> I get this error: Undefined variable: _SESSION in /home/ubuntu/public_html/myscript.php on line 2

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• Add a + sign to a +ve number in PHP

  - by user318466

  I need to design a function to return -ve numbers unchanged but should add a + sign at the start of the number if its alreay no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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• in_array() - help on what specifically would return true

  - by Kerri

  I am using in_array, and I'm trying to use it in a way where it will only return true if it's an exact match of one of the objects in the array, not just if it's "in" the array. e.g. 1. $sample_array = array('123', '234', '345'); 2. $sample_array = array('23', '34', '45'); in_array('23', $sample_array); In the above example, I would only want version 2 to return true, because it has the exact string, '23'. Version 1 returns true as well though, because the array contains instances of the string '23'. How would I get this to work so that only version 2 returns true? Am I even using the right function?

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• post values to external page explicitly PHP

  - by JPro

  Hi, I want to post values to a page through a hyperlink in another page. Is it possible to do that? Let's say I have a page results.php which has the starting line, <?php if(isset($_POST['posted_value'])) { echo "expected value"; // do something with the data } else { echo "no the value expected"; } If from another page say link.php I place a hyperlink like this: <a href="results.php?posted_value=1"> , will this be accepetd by the results page? If instead if I replace the above starting line with if(isset($_REQUEST['posted_value'])), will this work? I believe the above hyperlink evaluates to GET, but since the only visibility difference between GET and POST that is you can see parameters in the address bar with GET But, is there any other way to place a hyperlink which can post values to a page? or can we use jquery in the place of hyperlink to POST the values? Can anyone please suggest me something on this please? Thanks.

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• PHP & MySQL storing multiple values in a database.

  - by R.I.P.coalMINERS

  I'm basically a front end designer and new to PHP and MySQL but I want a user to be able to store multiple names and there meanings in a MySQL database table named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. All I want to know is how can I store multiple names and there meanings in a database and then display them back to the user for them to edit or delete using PHP MySQL? I created the MySQL table already. CREATE TABLE names ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, userID INT NOT NULL, name VARCHAR(255) NOT NULL, meaning VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); Here is the HTML. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /> <input type="hidden" name="submit" value="true" /></li> </ul> </form>

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• What is good about php/what is php good for?

  - by Roman A. Taycher

  I have often seen php bashed around the webs as a loosely typed(loose typing as in a lot of type coercion and/or easy(and perhaps common) to cast object all over not dynamic typing) language without a great compiler/interpreter/vm, with even the standard library using a number of different naming conventions. A lot of people complain about perl but many (including a lot of the complainers) also give it a lot of credit for its regexes and general flexibility and power. Other then legacy code , giant web frameworks that can do tons(drupal,ect.), and easy cheap hosting what is good about php (,also what criticism are unfair, and how is the language evolving to overcome its problems). Why would i want to learn it? why would I want to do an independent project in it? The main thing I have heard is that its php codes simplicity is sometimes easier then the over-engineered complexity you find in certain Java frameworks and applications. I'm not just trolling, i'm genuinly curious what makes php programmers use it. try to convince me to put it on my languages to dabble in and languages to learn more in depth lists.

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• Write transparent HTTP Proxy script in PHP

  - by Leo Izen

  Is there an easy forwarding/transparent php proxy script that I can host on my web server? These are my conditions: I'm using free web hosting, so I have pretty much no control over my machine. Otherwise I could use Perl's HTTP::Proxy module. This means no root password. It does run php though. I already have a server running on port 80. What I mean is I would like to put a php script as index.php on my server that will forward all requests. I don't want a script like PHProxy or Glype where I go to the site, then enter a URL. I want a server so I can enter proxy.example.com:80 in Firefox's or IE's or whatever's proxy settings and it will forward all requests to the server. Preferably (though not fatal if not possible) I would like for it to pass on the USER_AGENT environmental variable (That's the browser) instead of setting itself to be the USER_AGENT I can't start a new Daemon. My server won't allow it. Is there a script that will do this? If so, which?

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• Passing Javascript value to PHP Variable using ajax

  - by shels

  I am trying to use a Flash detection script to assess whether Flash Plugin is enabled in the user browser so that a different page loads. The Flash detection script is as follows, using jquery 1.8.2 and jquery.jqplugin 1.0.2 <script type="text/javascript" src="jquery-1.8.2.min.js"></script> <script type="text/javascript" src="jquery.jqplugin.1.0.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#withflash").hide(); $("#noflash").hide(); if ($.browser.flash == true) $("#withflash").show (); else $("#noflash").show (); }); </script> <div id="withflash">Flash Supported</div> <div id="noflash">Flash Not Supported</div> I get the display that "Flash Supported" if Flash Plugin is present.. I need to capture the value whether flash plugin value is true in a php variable $hasFlashSupport as below: <?php echo " $hasFlashSupport"; exit; ?> I am aware that PHP is server based and Javascript is client based.. Hence Ajax would be a nice option to capture the javascript variable to my php variable. I am totally ignorant about Ajax syntax and how to achieve it. Request the experts here to help me out with the code on how this can be achieved... Thanking all of you in advance..

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• PHP Fix Warning: Cannot modify header information - headers already sent...

  - by Storm Kiernan

  Warning: Cannot modify header information - headers already sent by (output started at /home/blocexco/public_html/homepage.php:73) in /home/blocexco/public_html/classes/mysql/mysql.security.php on line 99 This error is repeated a second time for mysql.security.php on line 100. homepage:73 <div class="login"> <?php require_once 'login.php'; ?> </div> mysql.security.php: 99-100 setcookie('username', "", time() - (60 * 60 * 24 * 365)); setcookie('password', "", time() - (60 * 60 * 24 * 365)); I know this isn't a "BOM" issue as I've read about. There is output before and after my calls to header() and setcookie() functions - this is necessary since the homepage includes a php file which then injects the right login or logout form. I've heard about using ob_start() at the beginning of content, but that's not a very specific instruction...I tried placing it at the beginning of homepage.php (just before the html tag) and that didn't fix anything. I'm new to PHP (a few days in, and new to web-app dev in general). To be honest, it blows my mind that I can't just change which page I am on, via php without bending over backwards...

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• PHP, since upgrading to 5.2.17 getting some warning ?

  - by Jules

  I can't reproduce this on my test server no idea why this is happening, other queries / functions work.. I'm getting this warning PHP Warning: mysql_connect() [<a href='function.mysql-connect'> function.mysql-connect</a>]: Can't connect to MySQL server on '--my isps server--' (10060) in D:\domains\mydomain.com\wwwroot\p hp\_stdfuncs.php on line 191 This function and others like it are having problems (but some are ok), this is my include file... function AddPageError($PageHandle, $Requested) { global $server; global $db; global $user; global $pass; global $sDebug; $con = mysql_connect($server,$user,$pass); I have an include file which sets those variables, as I say they work on other pages and functions.. No idea why ??

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• Reading function pointer syntax

  - by bobobobo

  Everytime I look at a C function pointer, my eyes glaze over. I can't read them. From here, here are 2 examples of function pointer TYPEDEFS: typedef int (*AddFunc)(int,int); typedef void (*FunctionFunc)(); Now I'm used to something like: typedef vector<int> VectorOfInts ; Which I read as typedef vector<int> /* as */ VectorOfInts ; But I can't read the above 2 typedefs. The bracketing and the asterisk placement, it's just not logical. Why is the * beside the word AddFunc..?

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• Misunderstanding function pointer - passing it as an argument

  - by Stef

  I want to pass a member function of class A to class B via a function pointer as argument. Please advise whether this road is leading somewhere and help me fill the pothole. #include <iostream> using namespace std; class A{ public: int dosomeA(int x){ cout<< "doing some A to "<<x <<endl; return(0); } }; class B{ public: B(int (*ptr)(int)){ptr(0);}; }; int main() { A a; int (*APtr)(int)=&A::dosomeA; B b(APtr); return 0; } This brilliant piece of code leaves me with the compiler error: cannot convert int (A::*)(int)' toint (*)(int)' in initialization Firstly I want it to compile. Secondly I don't want dosomeA to be STATIC.

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• Error while saving csv file generated by PHP

  - by user1667374

  I have created below script which is saving the csv file in the same path of this script but when I am saving it to different directory, it gives me error. Can somebody please help me on this? This is the error: Warning: fopen(/store/secure/mas/) [function.fopen]: failed to open stream: No such file or directory in /getdetails.php on line 15 Warning: fputs(): supplied argument is not a valid stream resource in /getdetails.php on line 36 Warning: fclose(): supplied argument is not a valid stream resource in /getdetails.php on line 39 This is the script: <?php $MYSQL_HOST="localhost"; $MYSQL_USERNAME="***"; $MYSQL_PASSWORD="***"; $MYSQL_DATABASE="shop"; $MYSQL_TABLE="ds_orders"; mysql_connect( "$MYSQL_HOST", "$MYSQL_USERNAME", "$MYSQL_PASSWORD" ) or die( mysql_error( ) ); mysql_select_db( "$MYSQL_DATABASE") or die( mysql_error( $conn ) ); $filename="Order_Details"; $directory = "/store/secure/mas/"; $csv_filename = $filename.".csv"; $fd = fopen ( "$directory" . $cvs_filename, "w"); $today="2009-03-17"; $disp_date="05122008"; $sql = "SELECT * FROM $MYSQL_TABLE where cDate='$today'"; $result=mysql_query($sql); $rows=mysql_num_rows($result); echo $rows; if(mysql_num_rows($result)>0){ $fileContent="Record ID,Discount Percent\n"; while($data=mysql_fetch_array($result)) { $fileContent.= "".$data['oID'].",".$data['discount']."\n"; } $fileContent=str_replace("\n\n","\n",$fileContent); fputs($fd, $fileContent); } fclose($fd); ?>

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