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  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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  • How can I match everything in a string until the second occurrence of a delimiter with a regular expression?

    - by Steve
    I am trying to refine a preg_match_all by finding the second occurrence of a period then a space: <?php $str = "East Winds 20 knots. Gusts to 25 knots. Waters a moderate chop. Slight chance of showers."; preg_match_all ('/(^)((.|\n)+?)(\.\s{2})/',$str, $matches); $dataarray=$matches[2]; foreach ($dataarray as $value) { echo $value; } ?> But it does not work: the {2} occurrence is incorrect. I have to use preg_match_all because I am scraping dynamic HTML. I want to capture this from the string: East Winds 20 knots. Gusts to 25 knots.

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  • How to match a variable list of items separated by commas

    - by user261915
    I want to turn something like this CS 240, CS 246, ECE 222, ... (more or less); Software Engineering students only into ('CS 240', 'CS 246', 'ECE 222', 'ECE 220') in Python, code that matches a single course looks like >>> re.search('([A-Z]{2,5} \d{3})', 'SE 112').groups() ('SE 112',) I prefer a regular expression only method because I have a bunch of other alternate reg exps using '|' to combine them. However, a method with split is acceptable.

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  • Censoring selected words (replacing them with ****) using a single replaceAll?

    - by aioobe
    I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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  • Regular Expression to capture the first <p> of HTML

    - by Program.X
    I have the following regular expression: (?:<(?<tag>\w*)>(?<text>.*)</\k<tag>>) I want it t grab the text within the first HTML element. eg. <p>This should capture</p>This shouldn't Works, but ... <p>This should capture</p><p>This shouldn't</p> Doesn't work. As you'd expect, it returns: This should capture</p><p>This shouldn't I'm racking my brains here. How can I just have it select the FIRST inner text? (I'm trying to be tag-agnostic, so <strong>This should match</strong> is equally appropriate, etc.)

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  • JavaScript: add or subtract from number in string

    - by yoavf
    I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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  • Regular expression - starting and ending with a letter, accepting only letters, numbers and _

    - by jreid9001
    I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

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  • preg_replace replacing with array

    - by Scott
    What I want to do is replace the "[replace]" in input string with the corresponding vaule in the replace array. The total number of values will change but there will always be the same number in the replace array as in input string. I have tried doing this with preg_replace and preg_replace_callback but I can't get the pattern right for [replace], I also tried using vsprintf but the % in <table width="100%"> was messing it up. All help is greatly appreciated! Replace Array: $array = array('value 1','value 2','value 3'); Input String $string = ' <table width="100%"> <tr> <td>Name:</td> <td>[replace]</td> </tr> <tr> <td>Date:</td> <td>[replace]</td> </tr> <tr> <td>Info:</td> <td>[replace]</td> </tr> </table> '; Desired Result <table width="100%"> <tr> <td>Name:</td> <td>value 1</td> </tr> <tr> <td>Date:</td> <td>value 2</td> </tr> <tr> <td>Info:</td> <td>value 3</td> </tr> </table>

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  • extract word with regular expression

    - by farka
    I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

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  • Finding a integer number after a beginning t=

    - by user2966696
    I have a string like this: 33 00 4b 46 ff ff 03 10 30 t=25562 I am only interested in the five digits at the very end after the t= How can I get this numbers with a regular expression out of it? I tried grep t=..... but I also got all characters including the t= in the beginning, which I would like to drop? After finding that five digit number, I would like to divide this by 1000. So in the above mentioned case the number 25.562. Is this possible with grep and regular expressions? Thanks for your help.

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  • How can I improve this regular expression?

    - by Michael Haren
    I want a regular expression to match valid input into a Tags input field with the following properties: 1-5 tags Each tag is 1-30 characters long Valid tag characters are [a-zA-Z0-9-] input and tags can be separated by any amount of whitespace Here's what I have so far--it seems to work but I'm interested how it could be simplified or if it has any major flaws: \s*[a-zA-Z0-9-]{1,30}(\s+[a-zA-Z0-9-]{1,30}){0,4}\s* // that is: \s* // match all beginning whitespace [a-zA-Z0-9-]{1,30} // match the first tag (\s+[a-zA-Z0-9-]{1,30}){0,4} // match all subsequent tags \s* // match all ending whitespace Preprocessing the input to make the whitespace issue easier isn't an option (e.g. trimming or adding a space). If it matters, this will be used in javascript. Any suggestions would be appreciated, thanks!

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  • Finding C#-style unescaped strings using regular expressions

    - by possan
    I'm trying to write a regular expression that finds C#-style unescaped strings, such as string x = @"hello world"; The problem I'm having is how to write a rule that handles double quotes within the string correctly, like in this example string x = @"before quote ""junk"" after quote"; This should be an easy one, right?

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  • Regular Expression repetition of class

    - by codersarepeople
    I am trying to figure out a regular expression for the following: <tr class="A">.*</tr><tr class="(B|C)">.*</tr> Now The second tr class will repeat an unknown number of times, with something unknown in between repetitions, but simply putting it in parentheses and added a plus doesn't work. Here's the PHP code that didn't work: $pattern = '/<tr\ class=\"A\">.*(<tr\ class=\"(B|C)\">.*<\/tr>.*)+/'; preg_match_all($pattern,$playerHtml,$scores); But it only returns the first Here's an example of something that should match: <tr class="A">blah</tr>blah <tr class="B">blah</tr>blah <tr class="B">blah</tr>blah <tr class="C">blah</tr> This only matches blahblahblah

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  • not autolinking all-numeric twitter hashtags in perl?

    - by all_numeric_no_hash
    I'm producing HTML from twitter search results. Happily using the Net::Twitter module :-) One of the rules in Twitter is that all-numeric hashtags are not links. This allows to unambiguously tweet things like "ur not my #1 anymore", as in here: http://twitter.com/natarias2007/status/11246320622 The solution I came up with looks like: $tweet =~ s{#([0-9]*[A-Za-z_]+[0-9]*)}{<a href="http://twitter.com/search?q=%23$1">#$1</a>}g; It seems to work (let's hope), but I'm still curious... how would you do it?

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  • Extracting numbers from a url using javascript?

    - by stormist
    var exampleURL = '/example/url/345234/test/'; var numbersOnly = [?] The /url/ and /test portions of the path will always be the same. Note that I need the numbers between /url/ and /test. In the example URL above, the placeholder word example might be numbers too from time to time but in that case it shouldn't be matched. Only the numbers between /url/ and /test. Thanks!

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  • How to modify complex argument strings in Perl

    - by mmccoo
    I have a cmdline that I'm trying to modify to remove some of the arguments. What makes this complex is that I can have nested arguments. Say that I have this: $cmdline = "-a -xyz -a- -b -xyz -b- -a -xyz -a-" I have three different -xyz flags that are to be interpreted in two different contexts. One is the -a context and the other is the -b context. I want to remove the "a" -xyz's but leave the ones in the "b" -xyz. How can I most effectively do this in Perl?

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  • Normalizing Strings using Regexes

    - by RasputinJones
    How do I match this string "1 & 2" from this string "Foo Bar 1 & 2"? How do I match this string "1, 2 & 3" from this string "Foo Baz 1, 2 & 3"? Trying to split out "Foo Bar" from the string using regexes while using the presence of "1 & 2" or "1, 2 & 3" as conditionals to normalize these strings into "Foo Bar 1" and "Foo Bar 2" or "Foo Baz 1", "Foo Baz 2" and "Foo Baz 3" respectively.

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  • Regular Expression Fails

    - by Meander365
    Anyone help? When I run this I get " invalid quantifier ?<=href= " var aHrefMatch = new RegExp("(?<=href\=")[^]+?(?=")"); var matchedLink = mystring.match(aHrefMatch); But I know the regular expression is valid. Any ideas?

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  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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  • Regular Expression

    - by Blanca
    Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

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