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  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

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  • Java Collections.Rotate with an array doesn't work

    - by steve_72
    I have the following java code: import java.util.Arrays; import java.util.Collections; public class Test { public static void main(String[] args) { int[] test = {1,2,3,4,5}; Collections.rotate(Arrays.asList(test), -1); for(int i = 0; i < test.length; i++) { System.out.println(test[i]); } } } I want the array to be rotated, but the output I get is 1 2 3 4 5 Why is this? And is there an alternative solution?

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  • Sorting linked lists in Pascal

    - by user3712174
    I'm doing my final project for Informatics class and I can't get my sorting procedure to work. Have a look at my program, specifically the bolded part (some things are in Croatian. - if you need something translated, let me know): type pokazivac=^slog; slog=record prezime_ime:string[30]; redni_broj:string[2]; fakultet:string[50]; bodovi:integer; sljedeci:pokazivac; end; var pocetni, trenutni, prethodni:pokazivac; i:integer; procedure racunaj; var i,a,c:integer; b,d,e,f,g,h,j:real; begin write('Postotak bodova (u decimalnom zapisu) koje ucenik ostvaruje na temelju prosjeka ocjena - '); readln(e); e:=e*1000/4; write('Prosjek ocjena u prvom razredu : '); readln(f); f:=f/5*e; write('Prosjek ocjena u drugom razredu : '); readln(g); g:=g/5*e; write('Prosjek ocjena u trecem razredu : '); readln(h); h:=h/5*e; write('Prosjek ocjena u cetvrtom razredu : '); readln(j); j:=j/5*e; d:=f+g+h+j; write('Broj predmeta (ne racunajuci hrvatski jezik, strani jezik i matematiku) koju je ucenik/ca polagao na maturi - '); readln(a); write('Postotak rijesnosti ispita iz hrvatskog jezika te zatim maksimum bodova koje je ucenik/ca mogao ostvariti - '); readln(b); readln(c); d:=d+b*c; write('Postotak rijesnosti ispita iz stranog jezika te zatim maksimum bodova koje je ucenik/ca mogao ostvariti - '); readln(b); readln(c); d:=d+(b*c); write('Postotak rijesnosti ispita iz matematike te zatim maksimum bodova koje je ucenik/ca mogao ostvariti - '); readln(b); readln(c); d:=d+(b*c); for i:=1 to a do begin writeln('Postotak rijesnosti dodatnog predmeta te zatim maksimum bodova koje je ucenik/ca mogao ostvariti - '); readln(b); readln(c); d:=d+(b*c); end; d:=round(d); writeln('Vas broj bodova je: ', d:4:2); write('Za nastavak pritisnite ENTER..'); readln; end; procedure unos; begin new(trenutni); write('Redni broj ucenika - ');readln(trenutni^.redni_broj); write('Prezime i ime - ');readln(trenutni^.prezime_ime); write('Naziv fakultet - ');readln(trenutni^.fakultet); write('Bodovi - ');readln(trenutni^.bodovi); trenutni^.sljedeci:=pocetni; pocetni:=trenutni; end; procedure ispis; begin writeln(); writeln('Lista popisanih ucenika:'); writeln(); trenutni:=pocetni; while trenutni<>NIL do begin with trenutni^do begin writeln('IME: ',prezime_ime); writeln('FAKULTET: ',fakultet); writeln('BODOVI: ',bodovi); writeln(); end; trenutni:=trenutni^.sljedeci; end; writeln(); write('Za nastavak pritisnite ENTER..'); readln; end; procedure brisi; var s:string; begin trenutni:= pocetni; prethodni:=pocetni; write('Redni broj ucenika kojeg zelite izbrisati - '); readln(s); while trenutni<>NIL do begin if trenutni^.redni_broj=s then begin prethodni^.sljedeci:=trenutni^.sljedeci; dispose(trenutni); break; end; trenutni:=trenutni^.sljedeci; end; end; procedure izmjeni; var s:string; begin trenutni:=pocetni; write('Redni broj ucenika cije podatke zelite izmijeniti - '); readln(s); while trenutni<> NIL do begin if trenutni^.redni_broj=s then begin write(trenutni^.prezime_ime, ' - '); readln(trenutni^.prezime_ime); write(trenutni^.fakultet, ' - '); readln(trenutni^.fakultet); write(trenutni^.bodovi, ' - '); readln(trenutni^.bodovi); break; end; trenutni:=trenutni^.sljedeci; end; end; **procedure sortiraj; var t1,t2,t:pokazivac; begin t1:=pocetni; while t1 <> NIL do begin t2:=t1^.sljedeci; while t2<>NIL do if t2^.bodovi<t1^.bodovi then begin new(t); t^.redni_broj:=t1^.redni_broj; t^.prezime_ime:=t1^.prezime_ime; t^.fakultet:=t1^.fakultet; t^.bodovi:=t1^.bodovi; t1^.redni_broj:=t2^.redni_broj; t1^.prezime_ime:=t2^.prezime_ime; t1^.fakultet:=t2^.fakultet; t1^.bodovi:=t2^.bodovi; t2^.redni_broj:=t^.redni_broj; t2^.prezime_ime:=t^.prezime_ime; t2^.fakultet:=t^.fakultet; t2^.bodovi:=t^.bodovi; dispose(t); end; t2:=t2^.sljedeci; end; t1:=t1^.sljedeci; write('Za nastavak pritisnite ENTER..'); readln; end;** begin pocetni:=NIL; trenutni:=NIL; writeln('******************************************'); writeln('**********DOBRODOSLI U FAX-O-MAT**********'); writeln('******************************************'); repeat writeln('1 - Racunaj broj bodova'); writeln('2 - Dodaj ucenika'); writeln('3 - Brisi ucenika'); writeln('4 - Ispis liste'); writeln('5 - Izmjeni podatke'); writeln('6 - Sortiraj listu prema broju bodova'); writeln('0 - Kraj'); readln(i); case i of 1:racunaj; 2:unos; 3:brisi; 4:ispis; 5:izmjeni; 6:sortiraj; end; until i=0; end. Either it crashes with a fatal error, or when I press the number 6, nothing happens. The pointer keeps blinking and I can't enter any more numbers.

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  • can list be converted into string

    - by PARIJAT
    Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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  • Simple Ticker (jQuery)

    - by Nimbuz
    <ul> <li><a href="#">one</a></li> <li><a href="#">two</a></li> <li><a href="#">three</a></li> </ul> I'd like to show only one li at a time using slide effect, thats it. I'd like to avoid using plugins for something as simple as this. Thanks in advance for your help.

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  • Cadr of a list involving assoc function

    - by user3619045
    I have looked around on the net and cant find an answer to my query. I would really appreciate if someone could provide a good answer without down rating this post. In Lisp car, cdr are used on data mode like '(whatever here) which makes sense to me. Now, in the book Land of Lisp the author is explaining how to build a text engine and suddenly he uses the following description to make a function. (defun describe-location (location nodes) (cadr (assoc location nodes))) Can I ask why is he doing a cadr on a list and how come it provides a response and not an error? shouldn't it be a data mode i.e with a quote in front of the opening bracket '(whatever here)? and also why is he using assoc as in (assoc location nodes) and not (assoc 'garden *nodes*) Isn't the second correct way to use assoc ? I may be missing the big picture and as such would really appreciate someone explaining these key points please. Many thanks!

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  • putting values from database into a drop down list

    - by sushant
    hi. my tool is in asp. i am using this code for a query in sql dim req_id req_id=Request.Form("Req_id") if req_id<>"" then Set conn=server.CreateObject("adodb.connection") conn.Open session("Psrconnect") Set rs=CreateObject("Adodb.Recordset") rs.Open "select * from passwords where REQ_ID='"&req_id&"'", conn i want to put the results of this query into a drop down list. how do i do it? any help is very much appreciated.

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  • Noob Python Question: List Confusion

    - by potatocubed
    I'm trying to transfer the contents of one list to another, but it's not working and I don't know why not. My code looks like this: list1 = [1, 2, 3, 4, 5, 6] list2 = [] for item in list1: list2.append(item) list1.remove(item) But if I run it my output looks like this: >>> list1 [2, 4, 6] >>> list2 [1, 3, 5] My question is threefold, I guess: Why is this happening, how do I make it work, and am I overlooking an incredibly simple solution like a 'move' statement or something?

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  • Getting list of key values from app config with same name

    - by NoviceMe
    I have follwing in app.config file: <appSettings> <add key="Name" value="Office"/> ... <add key="Name" value="HotSpot"/> ... <add key="Name" value="Home"/> </appSettings> I tried ConfigurationManager.AppSettings["Name"] But it only gives me one Value? How can i get list of all values? I am using c# 3.5. Is there lambda expression or something i can use to get that?

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  • HTML5 tags for a search result list

    - by user509375
    i've a list of items from a query to database. Now i want to display them to user via HTML. My initial way is like this: <ol> <li> search element 1 </li> ... </ol> I'm wondering if there is a better semantic way with HTML5 like: <article> <section> search element 1 </section> ... </article Does anyone have a better semantic way?

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  • Data structure name: combination array/linked list

    - by me_and
    I have come up with a data structure that combines some of the advantages of linked lists with some of the advantages of fixed-size arrays. It seems very obvious to me, and so I'd expect someone to have thought of it and named it already. Does anyone know what this is called: Take a small fixed-size array. If the number of elements you want to put in your array is greater than the size of the array, add a new array and whatever pointers you like between the old and the new. Thus you have: Static array ————————————————————————— |1|2|3|4|5|6|7|8|9|a|b|c| ————————————————————————— Linked list ———— ———— ———— ———— ———— |1|*->|2|*->|3|*->|4|*->|5|*->NULL ———— ———— ———— ———— ———— My thing: ———————————— ———————————— |1|2|3|4|5|*->|6|7|8|9|a|*->NULL ———————————— ————————————

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  • Quickest and most efficient method to search top 3 numbers?

    - by Donal Rafferty
    I currently have an array of around 8 - 10 numbers that changes on a periodic basis. So around every 5 - 10 seconds the numbers get updated. I need to get the top 3 numbers in the array every 10 seconds. This is all done on a mobile device. At the minute I iterate through the array 3 times and each time I take out the three highest numbers and place them in three previously declared variables. My question is what should I look to do to increase speed and efficiency in this instance?

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  • Search a List inside another with IQueryable

    - by ovini poornima
    public static IQueryable<Institution> WithFunds(this IQueryable<Institution> query, IEnumerable<Fund> allowedFunds) { return query. } I want to get the query to return all Institutions having any of the Fund given in 'allowedFunds' list in Institution.Funds. Please help. My class hierarchy goes like this. public partial class Institution { public int Id { get; set; } public virtual ICollection<Fund> Funds { get; set; } } public partial class Fund { public int Id { get; set; } public virtual Institution Institution { get; set; } }

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  • Get all sets of list in prolog

    - by garm0nboz1a
    How can I generate all the possible sets of the elements of a list with current length? get_set(X, [1,2,3]). X = [1,1,1], X = [1,1,2], X = [1,1,3], X = [1,2,1], X = [1,2,2], X = [1,2,3], X = [1,3,1], X = [1,3,2], X = [1,3,3], ..... X = [3,3,2], X = [3,3,3]. UPD: there is good answer given by Sharky. But maybe it's not the best. Here is another: get_set(X,L) :- get_set(X,L,L). get_set([],_). get_set([X|Xs],[_|T],L) :- member(X,L), get_set(Xs,T,L).

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  • PHP - How do i display the first 20 li then have a link to display more (gallery)

    - by Matt Rogers
    I want to display about 20 li on a page with a link at the bottom that says something like 'display more'. This link will then clear the first 20 and display the next 20. How should i go about doing this. (I am creating a gallery) I was thinking about using PHP and MySQL. However for what I am doing I do not really need to store it in a database so is there an easier way of doing it only using html, php or javascript? thanks

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  • efficientcy effort: grep with a vectored pattern or match with a list of values

    - by Elad663
    I guess this is trivial, I apologize, I couldn't find how to do it. I am trying to abstain from a loop, so I am trying to vectorize the process: I need to do something like grep, but where the pattern is a vector. Another option is a match, where the value is not only the first location. For example data (which is not how the real data is, otherswise I would exploit it structure): COUNTRIES=c("Austria","Belgium","Denmark","France","Germany", "Ireland","Italy","Luxembourg","Netherlands", "Portugal","Sweden","Spain","Finland","United Kingdom") COUNTRIES_Target=rep(COUNTRIES,times=4066) COUNTRIES_Origin=rep(COUNTRIES,each=4066) Now, currently I got a loop that: var_pointer=list() for (i in 1:length(COUNTRIES_Origin)) { var_pointer[[i]]=which(COUNTRIES_Origin[i]==COUNTRS_Target) } The problem with match is that match(x=COUNTRIES_Origin,table=COUNTRIES_Target) returns a vector of the same length as COUNTRIES_Origin and the value is the first match, while I need all of them. The issue with grep is that grep(pattern=COUNTRIES_Origin,x=COUNTRIES_Target) is the given warning: Warning message: In grep(pattern = COUNTRIES_Origin, x = COUNTRIES_Target) : argument 'pattern' has length > 1 and only the first element will be used Any suggestions?

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  • Need to sync two lists with atrribute time, but times aren't equal

    - by virgula24
    I gonna try to describe my problem the best i can. I have two lists, one with audio frames and other with color frames (not relevant). Both of them have timestamps, they were captured at the same moment but at different instants. So, i have like this: index COLOR AUDIO 0 841 846 1 873 897 2 905 948 3 940 1000 the frames start at high numbers because they were captured and then trimmed to specific parts, but im shot, frame 0 is synced with only 5ms apart(timestamp in ms). On every case i have, the audio frames count is less than the color count. I need to make them have the same count. The stating frames may be coloraudio, color

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  • depth first search graph by using linked list

    - by programmerwannabe
    im using mac book and i cannot read the text file using this code. moreover, can you guys please add function(graph is connected?, and is this graph tree?) inputA.txt consist 1 2 1 6 1 5 2 3 2 6 3 4 3 6 4 5 4 6 5 6 #include <stdio.h> #include <memory.h> #include <stdlib.h> #define MAX 10 #define TRUE 1 #define FALSE 0 typedef struct Graph{ int vertex; struct Graph* link; } g_node; typedef struct graphType{ int x; int visited[MAX]; g_node* adjList_H[MAX]; } graphType; typedef struct stack{ int data; struct stack* link; } s_node; s_node* top; void push(int item){ s_node* n=(s_node*)malloc(sizeof(s_node)); n->data = item; n->link = top; top = n; } int pop(){ int item; s_node* n=top; if(top == NULL){ puts("\nstack is empty!\n"); return 0; } else { item = n-> data; top = n->link; free(n); return item; } } void createGraph(graphType* g){ int v; g->x = 1; for(v=1 ; v < MAX ; v++){ g -> visited[v] = FALSE; g -> adjList_H[v] = NULL; } } void insertVertex(graphType* g, int v){ if(((g->x)) > MAX){ puts("\n it has been overed the number of vertex\n"); return ; } g -> x++; } void insertEdge(graphType* g, int u, int v){ g_node* node; if(u >= g -> x || v >= g -> x){ puts("\n no vertex in the graph\n"); return ; } node = (g_node*)malloc(sizeof(g_node)); node -> vertex = v; node -> link = g -> adjList_H[u]; g-> adjList_H[u] = node; } void print_adjList(graphType* g){ int i; g_node *p; for(i=1 ; i<g -> x ; i++){ printf("\n\t\t vertex %d adjacency list ", i); p = g -> adjList_H[i]; while(p){ printf("-> %d", p-> vertex); p = p-> link; } } } void DFS_adjList(graphType* g, int v) { g_node* w; top = NULL; push(v); g->visited[v] = TRUE; printf(" %d", v); while(top != NULL){ w=g->adjList_H[v]; while(w){ if (!g->visited[w->vertex]){ push(w->vertex); g->visited[w->vertex] = TRUE; printf(" %d", w->vertex); v = w->vertex; w=g->adjList_H[v]; } else w= w->link; } v = pop(); } } int main (int argc, const char * argv[]) { FILE *fp; char mychar; char arr[][2]={0, }; int j, k; int i; graphType *G9; G9 = (graphType*)malloc(sizeof(graphType)); createGraph(G9); for(i=1; i<7 ; i++) insertVertex(G9, i); fp = fopen("inputD.txt", "r"); for(j = 0 ; j< 10 ; j++){ for(k = 0 ; k < 2 ; k++){ mychar = fgetc(fp); if(mychar = EOF){ j=10; break; } else if(mychar == ' ') continue; else if(mychar <= '9' || mychar >= '1'){ arr[j][k] = mychar; printf("%d%d", arr[i][k]); } } } insertEdge(G9, 1, 2); insertEdge(G9, 1, 6); insertEdge(G9, 1, 5); insertEdge(G9, 2, 3); insertEdge(G9, 2, 6); insertEdge(G9, 3, 4); insertEdge(G9, 3, 6); insertEdge(G9, 4, 5); insertEdge(G9, 4, 6); insertEdge(G9, 5, 6); insertEdge(G9, 6, 5); insertEdge(G9, 6, 4); insertEdge(G9, 5, 4); insertEdge(G9, 6, 3); insertEdge(G9, 4, 3); insertEdge(G9, 6, 2); insertEdge(G9, 3, 2); insertEdge(G9, 5, 1); insertEdge(G9, 6, 1); insertEdge(G9, 2, 1); printf("\n graph adjacency list "); print_adjList(G9); printf("\n \n//////////////////////////////////////////////\n\n depth fist search >> "); DFS_adjList(G9, 1); return 0; }

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  • Is there an intuitive way to reopen Empathy's contact list?

    - by aef
    Since a short while I'm using Ubuntu Oneiric Ocelot (11.10) with gnome-shell (Gnome 3) and I'm trying to get accustomed to the default Empathy Instant Messaging client. When I hit the close button of Empathy's contact list the window disappears as expected. When I now start Empathy over the Gnome Activities menu the contact list reappears. That's not as easy as clicking a system tray icon back in Psi on Gnome 2 but it works for now. But when I start a conversation first and have an open conversation window, then close the contact list, and try to regain access to it by using Gnome Activities, I only get the conversation window into focus and no contact list appears. I only seem to be able to get the contact list back if I close the conversation window (and thereby signal the conversations to be over) and then use Gnome Activities again to get my contact list back. That's horrible. Is this intended? Is there something I'm missing?

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  • The Definitive C++ Book Guide and List

    - by grepsedawk
    After more than a few questions about deciding on C++ books I thought we could make a better community wiki version. Providing QUALITY books and an approximate skill level. Maybe we can add a short blurb/description about each book that you have personally read / benefited from. Feel free to debate quality, headings, etc. Note: There is a similar post for C: The Definitive C Book Guide and List Reference Style - All Levels The C++ Programming Language - Bjarne Stroustrup C++ Standard Library Tutorial and Reference - Nicolai Josuttis Beginner Introductory: C++ Primer - Stanley Lippman / Josée Lajoie / Barbara E. Moo Accelerated C++ - Andrew Koenig / Barbara Moo Thinking in C++ - Bruce Eckel (2 volumes, 2nd is more about standard library, but still very good) Best practices: Effective C++ - Scott Meyers Effective STL - Scott Meyers Intermediate More Effective C++ - Scott Meyers Exceptional C++ - Herb Sutter More Exceptional C++ - Herb Sutter C++ Coding Standards: 101 Rules, Guidelines, and Best Practices - Herb Sutter / Andrei Alexandrescu C++ Templates The Complete Guide - David Vandevoorde / Nicolai M. Josuttis Large Scale C++ Software Design - John Lakos Above Intermediate Modern C++ Design - Andrei Alexandrescu C++ Template Metaprogramming - David Abrahams and Aleksey Gurtovoy Inside the C++ Object Model - Stanley Lippman Classics / Older Note: Some information contained within these books may not be up to date and no longer considered best practice. The Design and Evolution of C++ - Bjarne Stroustrup Ruminations on C++ Andrew Koenig / Barbara Moo Advanced C++ Programming Styles and Idioms - James Coplien

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  • Deleting file with SharePoint List web service fails

    - by Robert MacLean
    I am trying to delete a file from SharePoint using the list web service which is failing with the following error. Error Code: 0x81020030 Message: Invalid file name Detail: The file name you specified could not be used. It may be the name of an existing file or directory, or you may not have permission to access the file. The update XML I sent through is: <Batch OnError="Continue" PreCalc="TRUE" ListVersion="0" ViewName="{8FE4E2C8-939E-4462-ABA2-D633EED7F76E}"><Method ID="1" Cmd="Delete"><Field Name="ID">84</Field><Field Name="FileRef">http://win-4h0xp59sn75:40414/Shared%20Documents/del.txt</Field></Method></Batch> The SharePoint server error logs indicate: ERROR: Failed to OpenThreadToken, LastError=1008 The file you are attempting to save or retrieve has been blocked from this Web site by the server administrators. Things I have tried I've tried the changes in #1372971 which has no helped. I have also tried the changes recommended on the Microsoft Social site, which has also not helped. I have confirmed that the txt file extension is not blocked as indicated here. In addition I can remove the file via the website, it is just on the web service that this fails. The permissions are correct (or rather not in play) as I am running as a SharePoint administrator, which is the same account that uploaded it via the copy web service.

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  • IndexOutOfBoundsException when updating a contact in contact list - Blackberry

    - by Taha
    Software and Simulator version i am using Blackberry Smartphone simulator: 2.13.0.65 Blackberry software version 5.0.0_5.0.0.14 I am looking at modifying contacts. Below is the code snippet i am using. I am getting a IndexOutOfBounds Exception at line String wtel = blackBerryContact.getString(BlackBerryContact.TEL, supportedAttributes[i]); Can someone advise what is going wrong here. Following is the code snippet ..... // Load the addressbook and let the user choose from list of contact BlackBerryContactList contactList = (BlackBerryContactList) PIM.getInstance().openPIMList(PIM.CONTACT_LIST,PIM.READ_WRITE); PIMItem pimItem = contactList.choose(); BlackBerryContact blackBerryContact = (BlackBerryContact)pimItem; PIMList pimList = blackBerryContact.getPIMList(); // get the supported attributes for Contact.TEL int[] supportedAttributes = pimList.getSupportedAttributes(Contact.TEL); Dialog.alert("Supported Attributes "+supportedAttributes.length); // gives me 8 for (int i=0; i < supportedAttributes.length;i++){ if(blackBerryContact.ATTR_WORK == supportedAttributes[i]){ Dialog.alert("updating Work"); // This alert is shown Dialog.alert("is supported "+ pimList.isSupportedAttribute(BlackBerryContact.TEL, supportedAttributes[i])+" "+pimList.getAttributeLabel(supportedAttributes[i])); // shows true and work String wtel = blackBerryContact.getString(BlackBerryContact.TEL, supportedAttributes[i]); // I get a IndexOutOfBounds Exception here if(wtel != ""){ pimItem.removeValue(BlackBerryContact.TEL, supportedAttributes[i]); } pimItem.addString( Contact.TEL, BlackBerryContact.ATTR_WORK, number); // passing the number that has to be updated if(pimItem.isModified()) { pimItem.commit(); Dialog.alert("Updated Work Number"); } } } ..... I want to update all the supported attributes for Contact.TEL field http://www.blackberry.com/developers/docs/5.0.0api/net/rim/blackberry/api/pdap/BlackBerryContact.html Field Values Per Field Supported Attributes ----------------------------------------------------------------------------- Contact.TEL 8 Contact.ATTR_WORK, Contact.ATTR_HOME, Contact.ATTR_MOBILE, Contact.ATTR_PAGER, Contact.ATTR_FAX, Contact.ATTR_OTHER, Contact.ATTR_HOME2, Contact.ATTR_WORK2

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  • MVC Checkbox List

    - by David in Dakota
    I just wrote perhaps the ugliest bit of MVC code in existence. It is: <table> <tr> <% int i = 0; foreach(Thyla.Models.Tag tag in this.Model) { i += 1; %> <td> <span> <input type="checkbox" name="TagSelector" id='<%= tag.TagName%>' value='<%= tag.TagName%>' /> <label for="<%= tag.TagName%>" title="<%= tag.TagName%>"><%= tag.TagName%></label> </span> </td> <%if (i % 5 == 0){%> </tr><tr> <%} %> <%} %> <% if (i % 5 != 0){%></tr><%} %> </table> What is the canonical approach to making a checkbox list with a specified number of columns in ASP.NET MVC?

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  • trying to delete a song from a list UITableView sigbart error - addMusic Example

    - by Pavan
    hi im trying to implement a delete feature into the addmusic example this is the code ive added it doesnt work, i cant get my head around whats wrong. can someone please tell me whats wrong and what i need to do to make sure it works. - (void)tableView:(UITableView*)tableView willBeginEditingRowAtIndexPath:(NSIndexPath *)indexPath { } - (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath { // If row is deleted, remove it from the list. if (editingStyle == UITableViewCellEditingStyleDelete) { MainViewController *mainViewController = (MainViewController *) self.delegate; NSUInteger index = [indexPath row]; MPMediaItem *itemToDelete = [mainViewController.userMediaItemCollection mediaItemAtIndex:index]; if ([itemToDelete isEqual:mainViewController.musicPlayer.nowPlayingItem]) { [mainViewController.musicPlayer skipToNextItem]; } MPMediaItemCollection *newCollection = [mainViewController.userMediaItemCollection collectionByDeletingMediaItemAtIndex:index]; mainViewController.userMediaItemCollection = newCollection; NSUInteger indices[] = {0, index}; NSIndexPath *deletePath = [NSIndexPath indexPathWithIndexes:indices length:2]; [tableView deleteRowsAtIndexPaths:[NSArray arrayWithObject:deletePath] withRowAnimation:UITableViewRowAnimationFade]; I also get these warnings when i compile the program and run it: heres the image: http://www.freeimagehosting.net/uploads/6e42f166b9.png Any ideas and help appreciated.

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