Search Results

Search found 33214 results on 1329 pages for 'php guy'.

Page 141/1329 | < Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >

  • Switching languajes on a website with PHP

    - by jnkrois
    Hello everybody, I'm just looking for some advice. I'm creating a website that offers (at least) 2 languages. The way I'm setting it up is by using XML files for the language, PHP to retrieve the values in the XML nodes. Say you have any XML file, being loaded as follows: <?php $lang = "en"; $xmlFile = simplexml_load_file("$lang/main.xml"); ?> Once the file contents are available, I just output each node into an HTML tag like so: <li><?php echo $xmlFile->navigation->home; ?></li> which in turn is equal to : <li><a href="#">Home</a></li> as a nav bar link. Now, the way in which I'm switching languages is by changing the value of the "$lang" variable, through a "$_POST", like so: if(isset($_POST['es'])){ $lang = "es"; }elseif(isset($_POST['en'])){ $lang = "en"; } The value of the "$lang" variable is reset and the new file is loaded, loading as well all the new nodes from the new XML file, hence changing the language. I'm just wondering if there is another way to reset the "$lang" variable using something else, other than "$_POST" or "$_GET". I don't want to use query string either. I know I could use JavaScript or jQuery to achieve this, but I'd like to make the site not too dependable on JavaScript. I'd appreciate any ideas or advice. Thanks

    Read the article

  • How to solve this simple PHP forloop issue?

    - by Londonbroil Wellington
    Here is the content of my flat file database: Jacob | Little | 22 | Male | Web Developer * Adam | Johnson | 45 | Male | President * Here is my php code: <?php $fopen = fopen('db.txt', 'r'); if (!$fopen) { echo 'File not found'; } $fread = fread($fopen, filesize('db.txt')); $records = explode('|', $fread); ?> <table border="1" width="100%"> <tr> <thead> <th>First Name</th> <th>Last Name</th> <th>Age</th> <th>Sex</th> <th>Occupation</th> </thead> </tr> <?php $rows = explode('*', $fread); for($i = 0; $i < count($rows) - 1; $i++) { echo '<tr>'; echo '<td>'.$records[0].'</td>'; echo '<td>'.$records[1].'</td>'; echo '<td>'.$records[2].'</td>'; echo '<td>'.$records[3].'</td>'; echo '<td>'.$records[4].'</td>'; echo '</tr>'; } fclose($fopen); ?> </table> Problem is I am getting the output of the first record repeated twice instead of 2 records one for Jacob and one for Adam. How to fix this?

    Read the article

  • Using PDO with MVC

    - by mister martin
    I asked this question at stackoverflow and received no response (closed as duplicate with no answer). I'm experimenting with OOP and I have the following basic MVC layout: class Model { // do database stuff } class View { public function load($filename, $data = array()) { if(!empty($data)) { extract($data); } require_once('views/header.php'); require_once("views/$filename"); require_once('views/footer.php'); } } class Controller { public $model; public $view; function __construct() { $this->model = new Model(); $this->view = new View(); // determine what page we're on $page = isset($_GET['view']) ? $_GET['view'] : 'home'; $this->display($page); } public function display($page) { switch($page) { case 'home': $this->view->load('home.php'); break; } } } These classes are brought together in my setup file: // start session session_start(); require_once('Model.php'); require_once('View.php'); require_once('Controller.php'); new Controller(); Now where do I place my database connection code and how do I pass the connection onto the model? try { $db = new PDO('mysql:host='.DB_HOST.';dbname='.DB_DATABASE.'', DB_USERNAME, DB_PASSWORD); $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); } catch(PDOException $err) { die($err->getMessage()); } I've read about Dependency Injection, factories and miscellaneous other design patterns talking about keeping SQL out of the model, but it's all over my head using abstract examples. Can someone please just show me a straight-forward practical example?

    Read the article

  • "No database selected" even when db clearly selected

    - by Someone
    One of my webpages gets a recurring error: "No database selected", even though the DB is selected. Right about now it's a 50-50 chance whether the page will load just fine, or whether I receive this error. After one or two reloads, the page works again. I am including the exact same connection file on my other pages, and I don't have this problem. What could be the cause of this? I'm using ensim pro for webhosting. TIA.

    Read the article

  • PHP MySQL Weird Update Problem

    - by Tim
    I have a heap based table in MySQL that I am trying to update via PHP, but for some reason, the updates do not seem to be taking place. Here is my test code: <?php $freepoints[] = 1; $freepoints[] = 2; $freepoints[] = 3; foreach ($freepoints as $entrypoint) { $query = "update gates set lane='{$entrypoint}' where traffic > 50 limit 50"; echo "$query\n"; mysql_query($query); echo mysql_affected_rows()."\n"; } ?> This outputs the following: update gates set lane='1' where traffic > 50 limit 50 50 update gates set lane='2' where traffic > 50 limit 50 50 update gates set lane='3' where traffic > 50 limit 50 50 In the database to start with lanes 1/2/3 had 0 records and lanes 4/5/6 had 100 records. From this I am expecting all 6 lanes to now have 50 records each. However when I look lanes 4/5/6 still have 100 records and 1/2/3 still have 0 records. When I copy the query "update gates set lane='1' where traffic 50 limit 50" into phpMyAdmin it works absolutely fine, so any ideas why it isn't working in my PHP script when mysql_affected_rows is saying it has updated 50 records?

    Read the article

  • Loading a helper elsewhere than the autoload.php?

    - by drpcken
    I inherited a project and I'm cleaning up a bit and trying to finish it. I noticed that they used (or wrote) a breadcrumb helper. It is in my helpers folder and is named breadcrumb_helper.php It has a single function to build a breadcrumb menu with links and pass it to the view breadcrumbs.php. Here's the code: function show_breadcrumbs() { $ci =& get_instance(); $ci->load->helper('inflector'); $data = ''; //build breadcrumb and store in $data $this->load->view("breadcrumbs", $data) } I was trying to figure out how this helper worked and I checked the autoload.php but there is no reference to the helper in there. In face here is my autoload: $autoload['helper'] = array('url','asset','combine','navigation','form','portfolio','cookie','default'); This show_breadcrumbs() function is used quite a bit in some of my pages so I'm confused as to how its loading if it isn't in the autoloader. It is called like this in a few of my pages: <?=show_breadcrumbs()?> What am I missing? Why isn't this in my autoload? I even did a global search and couldn't find anywhere the helper is being loaded.

    Read the article

  • javascript, php, cookies

    - by kennedy
    When i declare mac = 123, my internet explorer and firefox will keep refresh non-stop. And if i declare mac = getMacAddress it returns a value 1... I'm able to do a document.write(getMacAddress()) and it would able to display the mac address nicely. 1) Why my explorer will keep refreshing non-stop when i code it manually with "123" 2) why is the document.write able to display out, and when i store it to the cookie, somehow it didnt mange to capture into the cookie and it return a value of "1". Anyone help? create_users.php <script language="JavaScript"> function getMacAddress(){ document.macaddressapplet.setSep( "-" ); return (document.macaddressapplet.getMacAddress()); } function setCookie(c_name,value) { document.cookie = c_name + "=" +escape(value); } //error checking //var mac = getMacAddress(); var mac = "123"; setCookie('cookie_name',mac); window.location = "checkAvailability.php"; </script> checkAvailability.php $javascript_cookie_value = isset($_COOKIE["cookie_name"]) ? $_COOKIE["cookie_name"] : 1; mysql_query("INSERT INTO test (mac) VALUES ('$javascript_cookie_value')");

    Read the article

  • Call Python From PHP And Get Return Code

    - by seaboy
    Hello everyone, I am calling a python script from PHP. The python program has to return some value according to the arguments passed to it. Here is a sample python program, which will give you a basic idea of what i am doing currently: #!/usr/bin/python import sys #get the arguments passed argList = sys.argv #Not enough arguments. Exit with a value of 1. if len(argList) < 3: #Return with a value of 1. sys.exit(1) arg1 = argList[1] arg2 = argList[2] #Check arguments. Exit with the appropriate value. if len(arg1) > 255: #Exit with a value of 4. sys.exit(4) if len(arg2) < 2: #Exit with a value of 8. sys.exit(8) #Do further coding using the arguments------ #If program works successfully, exit with a value of 0 As you can see from the above code, my basic aim is for the python program to return some values (0,1,4,8 etc) depending on the arguments. And then the calling PHP program to access these returned values and do the appropriate operation. Currently i have used "sys.exit(n)", for that purpose. Am i right in using sys.exit, or do I need to use something else? And also what method exists in PHP so that I can access the return code from python? Sorry for the long question, but hopefully it will help in you understanding my dilemma Thanks a ton

    Read the article

  • PHP Installer Script

    - by totallymike
    I'm looking to create a fully functional installer for a slightly complicated web application using PHP. Basically, you go to URL/setup.php and you are asked a series of questions, and during the process a database is set up and a config file is populated according to the answers given. A good example of this is how Wordpress handles its install procedure, as well as any number of PHP applications. My question to you, oh great internet, is this: This technique is so prevalent that surely not everyone is re-inventing the wheel, is there a place I can go to find a basic walkthrough (not code, just a description) of the technique. Either that or a good book which outlines if not this specific technique, then the fundamentals relevant to this? I can bang out something ugly and probably make it work myself, but if there's a best known method I'd like to find it. Far more important than having a working function is to have a description of what's going on from step to step. I'd like to have the installer, but I really want to learn how it's done. Thanks, Mike

    Read the article

  • Breaking up a large PHP object used to abstract the database. Best practices?

    - by John Kershaw
    Two years ago it was thought a single object with functions such as $database->get_user_from_id($ID) would be a good idea. The functions return objects (not arrays), and the front-end code never worries about the database. This was great, until we started growing the database. There's now 30+ tables, and around 150 functions in the database object. It's getting impractical and unmanageable and I'm going to be breaking it up. What is a good solution to this problem? The project is large, so there's a limit to the extent I can change things. My current plan is to extend the current object for each table, then have the database object contain these. So, the above example would turn into (assume "user" is a table) $database->user->get_user_from_id($ID). Instead of one large file, we would have a file for every table.

    Read the article

  • looping through variable post vars and adding them to the database

    - by Neil Hickman
    I have been given the task of devising a custom forms manager that has a mysql backend. The problem I have now encountered after setting up all the front end, is how to process a form that is dynamic. For E.G Form one could contain 6 fields all with different name attributes in the input tag. Form two could contain 20 fields all with different name attributes in the input tag. How would i process the forms without using up oodles of resource.

    Read the article

  • Generating an array of functions?

    - by Wordpressor
    I have a few PHP files filled with multiple functions. Let's call them functions1.php, functions2.php, functions3.php: function function_something( $atts ) { extract( something_atts( array( 'foo' => 'bar', 'bar' => 'foo, ), $atts ) ); return 'something'; } I'm loading these files within all_functions.php like this: require_once('functions1.php'); require_once('functions2.php'); require_once('functions3.php'); I'm wondering if it's possible to create an array of all these functions and their attributes? I'm thinking about something like: function my_functions() { require_once('functions1.php'); require_once('functions2.php'); require_once('functions3.php'); } And then some foreach loop, but I'm not sure how should it look like after all. I know this probably looks tricky, but I'm just curious if I'm able to list all my WordPress shortcodes without PHP's Reflection API :)

    Read the article

  • Filter sub-categories like in layered navigation

    - by russjman
    I created a new template file catalog/category/list.phtml. This is to display all sub categories of the current category. I have layered navigation which is displaying sub-categories as one of the filters, but I want this new template to work with these filters as well. Right now when i click the subcategory filter, it filters all products on the page, but still displays all categories of the parent category. $_filters is how i am trying to access these filters, but i get nothing. Is there something i am not initializing correctly to have access to these filters from the layered navigation. <?php $_helper = $this->helper('catalog/output'); $_filters = $this->getActiveFilters(); echo $_filters; if (!Mage::registry('current_category')) return ?> <?php $_categories=$this->getCurrentChildCategories() ?> <?php $_count = is_array($_categories)?count($_categories):$_categories->count(); ?> <?php if($_count): ?> <?php foreach ($_categories as $_category): ?> <?php if($_category->getIsActive()): ?> <?php $cur_category=Mage::getModel('catalog/category')->load($_category->getId()); $layer = Mage::getSingleton('catalog/layer'); $layer->setCurrentCategory($cur_category); $_imgHtml = ''; if ($_imgUrl = $this->getCurrentCategory()->getImageUrl()) { $_imgHtml = '<img src="'.$_imgUrl.'" alt="'.$this->htmlEscape($_category->getName()).'" title="'.$this->htmlEscape($_category->getName()).'" class="category-image" />'; $_imgHtml = $_helper->categoryAttribute($_category, $_imgHtml, 'image'); } echo $_category->getImageUrl(); ?> <div class="category-image-box"> <div class="category-description clearfix" > <div class="category-description-textbox" > <h2><span><?php echo $this->htmlEscape($_category->getName()) ?></span></h2> <p><?php echo $this->getCurrentCategory()->getDescription() ?></p> </div> <a href="<?php echo $this->getCategoryUrl($_category) ?>" class="collection-link<?php if ($this->isCategoryActive($_category)): ?> active<?php endif ?>" >See Entire Collection</a> <a href="<?php echo $this->getCategoryUrl($_category) ?>"><?php if($_imgUrl): ?><?php echo $_imgHtml ?><?php else: ?><img src="/store/skin/frontend/default/patio_theme/images/category-photo.jpg" class="category-image" alt="collection" /><?php endif; ?></a> </div> <?php echo '<pre>'.print_r($_category->getData()).'</pre>';?> </div> <?php endif; ?> <?php endforeach ?> <?php endif; ?>

    Read the article

  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

    Read the article

  • Using javascript and php together

    - by EmmyS
    I have a PHP form that needs some very simple validation on submit. I'd rather do the validation client-side, as there's quite a bit of server-side validation that happens to deal with writing form values to a database. So I just want to call a javascript function onsubmit to compare values in two password fields. This is what I've got: function validate(form){ var password = form.password.value; var password2 = form.password2.value; alert("password:"+password+" password2:" + password2); if (password != password2) { alert("not equal"); document.getElementByID("passwordError").style.display="inline"; return false; } alert("equal"); return true; } The idea being that a default-hidden div containing an error message would be displayed if the two passwords don't match. The alerts are just to display the values of password and password2, and then again to indicate whether they match or not (will not be used in production code). I'm using an input type=submit button, and calling the function in the form tag: <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" onsubmit="return validate(this);"> Everything is alerting as expected when entering non-matching values. I would have hoped (and assumed, based on past use) that if the function returned false, the actual submit would not occur. And yet, it is. I'm testing by entering non-matching values in the password fields, and the alerts clearly show me the values and the not equal result, but the actual form action is still occurring and it's trying to write to my database. I'm pretty new at PHP; is there something about it that will not let me combine with javascript this way? Would it be better to use an input type=button and include submit() in the function itself if it returns true?

    Read the article

  • Special characters stripped by mySQL/PHP JSON

    - by Will Gill
    Hi, I have a simple PHP script to extract data from a mySQL database and encode it as JSON. The problem is that special characters (for example German ä or ß characters) are stripped from the JSON response. Everything after the first special character for any single field is just stripped. The fields are set to utf8_bin, and in phpMyAdmin the characters display correctly. The PHP script looks like this: <?php header("Content-type: application/json; charset=utf-8"); $con = mysql_connect('database', 'username', 'password'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("sql01_5789willgil", $con); $sql="SELECT * FROM weightevent"; $result = mysql_query($sql); $row = mysql_fetch_array($result); $events = array(); while($row = mysql_fetch_array($result)) { $eventid = $row['eventid']; $userid = $row['userid']; $weight = $row['weight']; $sins = $row['sins']; $gooddeeds = $row['gooddeeds']; $date = $row['date']; $event = array("eventid"=>$eventid, "userid"=>$userid, "weight"=>$weight, "sins"=>$sins, "gooddeeds"=>$gooddeeds, "date"=>$date); array_push($events, $event); } $myJSON = json_encode($events); echo $myJSON; mysql_close($con); ?> Sample output: [{"eventid":"2","userid":"1","weight":"70.1","sins":"Weihnachtspl","gooddeeds":"situps! lots and lots of situps!","date":"2011-01-02"},{"eventid":"3","userid":"2","weight":"69.9","sins":"A second helping of pasta...","gooddeeds":"I ate lots of salad","date":"2011-01-01"}] -- in the first record the value for field 'sins' should be "Weihnachtsplätzchen". thanks very much!

    Read the article

  • Flex : providing data with a PHP Class

    - by Tristan
    Hello, i'm a very new user to flex (never use flex, nor flashbuilder, nor action script before), but i want to learn this langage because of the beautiful RIA and chart it can do. I watched the video on adobe : 1 hour to build your first program but i'm stuck : On the video it says that we have to provide a PHP class for accessing data and i used the example that flash builder gave (with zend framework and mysqli). I never used those ones and it makes a lot to learn if i count zen + mysqli. My question is : can i use a PHP class like this one ? What does flash builder except in return ? i hear that was automatic. example it may be wrong, i'm not very familiar with classes when acessing to database : <?php class DBConnection { protected $server = "localhost"; protected $username = "root"; protected $password = "root"; protected $dbname = "something"; protected $connection; function __construct() { $this->connection = mysql_connect($this->server, $this->username, $this->password); mysql_select_db($this->dbname,$this->connection); mysql_query("SET NAMES 'utf8'", $this->connection); } function query($query) { $result = mysql_query($query, $this->connection); if (!$result) { echo 'request error ' . mysql_error($this->connection); exit; } return $result; } function getAll() { $req = "select * from servers"; $result = query($req) return $result } function num_rows() { return mysql_num_rows($result); } function end() { mysql_close($this->connection); } } ?> Thank you,

    Read the article

  • PHP - upload.class image and $_FILES

    - by Ockonal
    Hello, I'm using class.upload.php to upload pictures onto the server. Here is my form: <form action="<?="http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];?>" method="post" enctype="multipart/form-data"> <table style="width: 100%; padding-top: 20px;"> <tr> <td>Image file:</td> <td><input type="file" name="image_file" /></td> </tr> <tr> <td>&nbsp;</td> <td align="right"><input type="submit" name="add_new" value="Add image" /><td></td> </tr> </table> </form> In php code I do: if( array_key_exists('add_new', $_POST) ) { echo 'add new is in array'; echo '<pre>'; print_r($_POST); print_r($_FILES); echo '</pre>'; $handle = new Upload($_FILES['image_file']); ... } Here is an output of print_r: Array ( [image_file] => somefile.png [add_new] => Add image ) Array ( ) As you can see second array is empty ($_FILES), so image doesn't upload. Why? operating system : Linux PHP version : 5.2.12 GD version : 2.0.34 supported image types : png jpg gif bmp open_basedir : /home/httpd/vhosts/kz-gbi.ru/httpdocs:/tmp

    Read the article

  • Codeigniter php activerecord orm limit and offset

    - by user2167174
    I am a bit stuck with this problem I have in phpactiverecord. What I am trying to do is a pagination so I need to limit and offset the query results. I am accessing all of the user posts like so: $user-post; How can I query this to limit and offset the results? Thanx in advance. Code: public function office() { if (!$this->session->userdata('username')) { redirect(base_url()); } $data = array(); $data['posts'] = []; $user = User::find('first', array('id' => $this->session->userdata('id'))); if ($user != null) { if ($user->post != null) { foreach ($user->post as $post) { $posts = array($post->name, $post->description, $post->date,'<a href="'.base_url().'Posts/edit/'.$post->id.'">Edit</a> <br /><a href="'.base_url().'Posts/delete/'.$post->id.'">Delete</a>'); array_push($data['posts'], $posts); } $this->table->set_heading('Name', 'Description', 'Date', '<a href="'.base_url().'Posts/create">+Add</a>'); $tmpl = array('table_open' => '<table class="table table-stripped table-bordered user-posts">'); $this->table->set_template($tmpl); $data['table'] = $this->table->generate($data['posts']); } $this->load->view('template/header.php'); $this->load->view('Users/office.php', $data); $this->load->view('template/footer.php'); } else { redirect(base_url()); } }

    Read the article

  • Lack of security in many PHP applications?

    - by John
    Over the past year of freelancing, I inherited two web projects, both of them built in PHP, both of them with sensitive information like credit card info, bank info, etc... In one application, when I typed http://thecompany.com/admin/, and without being asked for a username and password, I saw every user's sensitive information, including credit card numbers, bank account numbers etc... In another application, I was able to bypass the login screen by simply typing http://the2ndcompany.com/customer.php?user_id=777, and again, without any prompts for username and password, i was able to see user 777's credit card info. I cycled through a few more user_ids (any integer) and saw each person's credit card info. Is something wrong here? Or is this the quality of work that the "average" programmer produces? Because if this is what the average programmer produces, does that means I'm an...gasp...elite programmer?? No..that can't be right....something doesn't make sense. So my question is, is it just coincidence that I inherited two applications both of which are dangerously lacking in security? Or are there are a lot of bad PHP programmers out there?

    Read the article

  • translate a PHP $string using google translator API

    - by Toni Michel Caubet
    hey there! been google'ing for a while how is the best way to translate with google translator in PHP, found very different ways converting URLS, or using Js but i want to do it only with php (or with a very simple solution JS/JQUery) example: //hopefully with $from_lan and $to_lan being like 'en','de', .. or similar function translate($from_lan, $to_lan, $text){ // do return $translated_text; } can you give me a clue? or maybe you already have this function.. my intention it's to use it only for the languages i have not already defined (or keys i haven't defined), that's why i wan it so simple, will be only temporal.. EDIT thanks for your replies we are now trying this soulutions: function auto_translate($from_lan, $to_lan, $text){ // do $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); $translated_text = $json->responseData->translatedText; return $translated_text; } (there was a extra 'g' on variables for lang... anyway) it returns: works now :) i don't really understand much the function, so any idea why is not acepting the object? (now i do) OR: unction auto_translate($from_lan, $to_lan, $text){ // do // $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); // $translated_text = $json['responseData']['translatedText']; error_reporting(1); require_once('GTranslate.php'); try{ $gt = new Gtranslate(); $translated_text = $gt-english_to_german($text); } catch (GTranslateException $ge) { $translated_text= $ge->getMessage(); } return $translated_text; } And this one looks great but it doesn't even gives me an error, the page won't load (error_report(1) :S) thanks in advance!

    Read the article

  • imageconvolution leaves black dot in the upper left corner

    - by Peter O.
    I'm trying to sharp resized images using this code: imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); When the transparent PNG image is sharpened, using code above, it appears with a black dot in the upper left corner (I have tried different convolution kernels, but the result is the same). After resizing the image looked OK. 1st image is the original one 2nd image is the sharpened one EDIT: What am I going wrong? I'm using the color retrieved from pixel. $color = imagecolorat($imageResource, 0, 0); imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); imagesetpixel($imageResource, 0, 0, $color); Is imagecolorat the right function? Or is the position correct? EDIT2: I have changed coordinates, but still no luck. I've check the transparency given by imagecolorat (according to this post). This is the dump: array(4) { red => 0 green => 0 blue => 0 alpha => 127 } Alpha 127 = 100% transparent. Those zeroes might cause the problem...

    Read the article

  • Who to select value from DropDown list in PHP???Problem

    - by sandy
    Hello .. I want to know the error in this code The following code retrieves the names of the members of the database query in the dropdownlist But how do I know who you selected.... I want to send messages only to the members that selected form dropdown list <?php include ("connect.php"); $name = $_POST['sector_list']; echo $name ; ?> <form method="POST" action="" > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('select * from members ') or die (mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option size ="40" value=" '. $row['MemberID'] . '" name="' . $row['MemberName']. '">' . $row['MemberName']. '</option>'; } ?> </select> </form> I hope somebody can help me

    Read the article

  • Call phpexcel from joomla

    - by Oscar Calderon
    i have a problem about phpexcel and joomla. I'm developing some filter form to load excel reports, so i used phpexcel library to do this. Right now i have only a report, it works fine, but after that i upload inside joomla using PHP pages component that allows me to put php files inside joomla and call it. When i put them, i change a little bit the form that calls the php that generates the excel report, i call the php using a link like this: h**p://www.whiblix.com/index.php?option=com_php&Itemid=24 That is, calling it from Joomla, not directly the php. If i wanna call the php directly i could use this path: h**p://www.whiblix.com/components/com_php/files/repImportaciones.php What's the problem? The problem is, when i call the php that generates the excel through joomla, the excel that is downloaded is corrupt and only shows symbols in one cell when i open it. But if i call the php directly the report is generated fine. I could call the php directly, the problem is that if i call it directly i can't use this line of code: defined( '_JEXEC' ) or die( 'Restricted access' ); That is used to deny the direct access to php from call it directly, because it doesn' work because the security. Where's the problem? This is the code of php that generates the report (ommiting the code where generates the rows and cells): <?php //defined( '_JEXEC' ) or die( 'Restricted access' ); /** Error reporting */ error_reporting(E_ALL); date_default_timezone_set('Europe/London'); require_once 'Classes/PHPExcel.php'; // Create new PHPExcel object $objPHPExcel = new PHPExcel(); // Set properties $objPHPExcel->getProperties()->setCreator("Maarten Balliauw") ->setLastModifiedBy("Maarten Balliauw") ->setTitle("Office 2007 XLSX Test Document") ->setSubject("Office 2007 XLSX Test Document") ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.") ->setKeywords("office 2007 openxml php") ->setCategory("Test result file"); // Rename sheet $objPHPExcel->getActiveSheet()->setTitle('Reporte de Importaciones'); // Set active sheet index to the first sheet, so Excel opens this as the first sheet $objPHPExcel->setActiveSheetIndex(0); // Redirect output to a client’s web browser (Excel5) header('Content-Type: application/vnd.ms-excel'); header('Content-Disposition: attachment;filename="repPrueba.xls"'); header('Cache-Control: max-age=0'); $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel5'); $objWriter->save('php://output'); exit;

    Read the article

< Previous Page | 137 138 139 140 141 142 143 144 145 146 147 148  | Next Page >