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  • How could I parse this HTML file?

    - by Sergio Tapia
    <div id="main"> <style type="text/css"> </style> <script language="JavaScript"> </script> <p style="margin: 0pt 0pt 0.5em;"><b>Media from&nbsp;<a onclick="(new Image()).src='/rg/find-media-title/media_strip/images/b.gif?link=/title/tt0087538/';" href="/title/tt0087538/">The Karate Kid</a> (1984)</b></p> <style type="text/css"> </style> <table style="border-collapse: collapse;"> </table> </div> I need to somehow extract the href value of the (new Image()). How exactly would I accomplish this with HtmlAgilityPack? I'm new to it, and so far I haven't found a useful tutorial on how to effectively use it for parsing. Thanks for the help!

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  • AS2 attaching or duplicating the MC

    - by ortho
    var myXML:XML = new XML(); myXML.ignoreWhite=true; myXML.load("tekst.xml"); myXML.onLoad = function(success){ var yC:Number = 65; if (success){ var myTxt:Array = Array(0); var myNode = this.firstChild.childNodes; for (i=0; i } } var c:Number = 70 for(hiThere=1;hiThere<5;hiThere++){ kropka1.duplicateMovieClip("circleCopy"+hiThere, c); this["circleCopy"+hiThere]._y=c; c += 20; } So my problem is that I want to create it dynamicaly as text fields above, now it creates only 4 MovieClips and I would like to specify the Y value from xml file and number of loops (here 5), but it should be the same condition as loop above. Please help

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  • SL4: Root element is missing

    - by Number8
    Hello, I know this has been asked elsewhere, but none of the questions or answers helped. I open an xml file in my SL 4 app: StreamResouceInfo sri = Application.GetResourceStream(new System.Uri("z.xml", UriKind.Relative)); if (null != sri) { XDocument xDoc = XDocument.Load(sri.Stream); } "Root element is missing" exception. The xml: Hmm, can't seem to post the xml... It is well-formed and valid, with a single root node and all tags closed. Thanks for any hints...

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  • Dumping an ADODB recordset to XML, then back to a recordset, then saving to the db

    - by Mark Biek
    I've created an XML file using the .Save() method of an ADODB recordset in the following manner. dim res dim objXML: Set objXML = Server.CreateObject("MSXML2.DOMDocument") 'This returns an ADODB recordset set res = ExecuteReader("SELECT * from some_table) With res Call .Save(objXML, 1) Call .Close() End With Set res = nothing Let's assume that the XML generated above then gets saved to a file. I'm able to read the XML back into a recordset like this: dim res : set res = Server.CreateObject("ADODB.recordset") res.open server.mappath("/admin/tbl_some_table.xml") And I can loop over the records without any problem. However what I really want to do is save all of the data in res to a table in a completely different database. We can assume that some_table already exists in this other database and has the exact same structure as the table I originally queried to make the XML. I started by creating a new recordset and using AddNew to add all of the rows from res to the new recordset dim outRes : set outRes = Server.CreateObject("ADODB.recordset") dim outConn : set outConn = Server.CreateObject("ADODB.Connection") dim testConnStr : testConnStr = "DRIVER={SQL Server};SERVER=dev-windows\sql2000;UID=myuser;PWD=mypass;DATABASE=Testing" outConn.open testConnStr outRes.activeconnection = outConn outRes.cursortype = adOpenDynamic outRes.locktype = adLockOptimistic outRes.source = "product_accessories" outRes.open while not res.eof outRes.addnew for i=0 to res.fields.count-1 outRes(res.fields(i).name) = res(res.fields(i).name) next outRes.movefirst res.movenext wend outRes.updatebatch But this bombs the first time I try to assign the value from res to outRes. Microsoft OLE DB Provider for ODBC Drivers error '80040e21' Multiple-step OLE DB operation generated errors. Check each OLE DB status value, if available. No work was done. Can someone tell me what I'm doing wrong or suggest a better way for me to copy the data loaded from XML to a different database?

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  • Still confuse parse JSON in GWT

    - by graybow
    Please help meee. I create a project named 'tesdb3' in eclipse. I create the PHP side to access the database, and made the output as JSON.. I create the userdata.php in folder war. then I compile tesdb3 project. Folder tesdb3 and the userdata.php in war moved in local server(I use WAMP). I put the PHP in folder tesdb3. This is the result from my localhost/phpmyadmin/tesdb3/userdata.php [{"kode":"002","nama":"bambang gentolet"},{"kode":"012","nama":"Algiz"}] From that result I think the PHP side was working good.Then I create UserData.java as JSNI overlay like this: package com.tesdb3.client; import com.google.gwt.core.client.JavaScriptObject; class UserData extends JavaScriptObject{ protected UserData() {} public final native String getKode() /*-{ return this.kode; }-*/; public final native String getNama() /*-{ return this.nama; }-*/; public final String getFullData() { return getKode() + ":" + getNama(); } } Then Finally in the tesdb3.java: public class Tesdb3 implements EntryPoint { String url= "http://localhost/phpmyadmin/tesdb3/datauser.php"; private native JsArray<UserData> getuserdata(String json) /*-{ return eval(json); }-*/; public void LoadData() throws RequestException{ RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(url)); builder.sendRequest(null, new RequestCallback(){ @Override public void onError(Request request, Throwable exception) { Window.alert("error " + exception); } public void onResponseReceived(Request request, Response response) { Window.alert("betul" + response.getText()); //data(getuserdata(response.getText())); } }); } public void data(JsArray<UserData> data){ for (int i = 0; i < data.length(); i++) { String lkode =data.get(i).getKode(); String lname =data.get(i).getNama(); Label l = new Label(lkode+" "+lname); tb.setWidget(i, 0, l); } RootPanel.get().add(new HTML("my data")); RootPanel.get().add(tb); } public void onModuleLoad() { try { LoadData(); } catch (RequestException e) { } } } The result just showing string "my data". And the Window.alert(response.getText()) showing nothing. Whyy?

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  • svg data visualizations

    - by garymlewis
    I'd like to experiment with SVG as a way of displaying data-driven graphs, charts, etc. The data exists as xml, and I'll use XQuery to produce the xml. What options (eg, graphics libraries) should I consider for creating the SVG from the xml? Many thanks.

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  • Angularjs: addition of integers even after I parse the variable as integer

    - by Shiv Kumar
    I really have a weird problem in adding two numbers. Here is my code, in the first controller everything is working fine, but in the second controller instead of 0 if I add 10, the output is completely weird Here is html code <div ng-app=""> <div ng-controller="Controller1"> <br/>**** Controller-1 <br/>Add 0 : {{update1(0)}} <br/>Add 10 : {{update1(10)}} <br/>Add 50 : {{update1(50)}} <br/>Add -60 : {{update1(-60)}}</div> <div ng-controller="Controller2"> <br/>**** Controller-2 <br/>Add 10 : {{update2(10)}} <br/>Add 10 : {{update2(10)}} <br/>Add 50 : {{update2(50)}} <br/>Add -60 : {{update2(-60)}}</div> </div> Here is my javascript function Controller1($scope) { var x = 0; $scope.update1 = function (smValue) { x += parseInt(smValue); return x; } } function Controller2($scope) { var y = 0; $scope.update2 = function (smValue) { y += parseInt(smValue); return y; } } and here is the output **** Controller-1 Add 0 : 0 Add 10 : 10 Add 50 : 60 Add -60 : 0 **** Controller-2 Add 0 : 110 Add 10 : 120 Add 50 : 170 Add -60 : 110 here is the link to try: http://jsfiddle.net/6VqqN/ can anyone please explain me why it is behaving like that. Even if I add a 3or4 digit number, output is completely different then what I expected.

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  • Switching languages on a website with PHP

    - by jnkrois
    Hello everybody, I'm just looking for some advice. I'm creating a website that offers (at least) 2 languages. The way I'm setting it up is by using XML files for the language, PHP to retrieve the values in the XML nodes. Say you have any XML file, being loaded as follows: <?php $lang = "en"; $xmlFile = simplexml_load_file("$lang/main.xml"); ?> Once the file contents are available, I just output each node into an HTML tag like so: <li><?php echo $xmlFile->navigation->home; ?></li> which in turn is equal to : <li><a href="#">Home</a></li> as a nav bar link. Now, the way in which I'm switching languages is by changing the value of the "$lang" variable, through a "$_POST", like so: if(isset($_POST['es'])){ $lang = "es"; }elseif(isset($_POST['en'])){ $lang = "en"; } The value of the "$lang" variable is reset and the new file is loaded, loading as well all the new nodes from the new XML file, hence changing the language. I'm just wondering if there is another way to reset the "$lang" variable using something else, other than "$_POST" or "$_GET". I don't want to use query string either. I know I could use JavaScript or jQuery to achieve this, but I'd like to make the site not too dependable on JavaScript. I'd appreciate any ideas or advice. Thanks

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  • Force close message when preferences are called via menu button

    - by Dan T
    I see no problem in the code. Help? preferences.xml <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android"> <ListPreference android:title="Gender" android:summary="Are you male or female?" android:key="genderPref" android:defaultValue="male" android:entries="@array/genderArray" android:entryValues="@array/genderValues" /> <ListPreference android:title="Weight" android:summary="How much do you weigh?" android:key="weightPref" android:defaultValue="180" android:entries="@array/weightArray" android:entryValues="@array/weightValues" /> </PreferenceScreen> arrays.xml <?xml version="1.0" encoding="utf-8"?> <resources> <string-array name="genderArray"> <item>Male</item> <item>Female</item> </string-array> <string-array name="genderValues"> <item>male</item> <item>female</item> </string-array> <string-array name="weightArray"> <item>120</item> <item>150</item> <item>180</item> <item>210</item> <item>240</item> <item>270</item> </string-array> <string-array name="weightValues"> <item>120</item> <item>150</item> <item>180</item> <item>210</item> <item>240</item> <item>270</item> </string-array> </resources> Preferences.java: package com.dantoth.drinkingbuddy; import android.os.Bundle; import android.preference.PreferenceActivity; public class Preferences extends PreferenceActivity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.preferences); }; } butts.xml (idk why it's butts but I've gotten used to it now. really just sets up the menu button) <?xml version="1.0" encoding="utf-8"?> <menu xmlns:android="http://schemas.android.com/apk/res/android"> <item android:id="@+id/settings" android:title="Settings" android:icon="@drawable/ic_menu_settings" /> <item android:id="@+id/archive" android:title="Archive" android:icon="@drawable/ic_menu_archive" /> <item android:id="@+id/new_session" android:title="New Session" android:icon="@drawable/ic_menu_new" /> <item android:id="@+id/about" android:title="About" android:icon="@drawable/ic_menu_about" /> </menu> within DrinkingBuddy.java: @Override public boolean onOptionsItemSelected(MenuItem item) { switch (item.getItemId()) { case R.id.settings: startActivity(new Intent(this, Preferences.class)); return true; case R.id.archive: Toast.makeText(this, "Expect to see your old drinking sessions here.", Toast.LENGTH_LONG).show(); return true; //ETC. } return false; That's it. I can press the menu button on the phone and see the menu items I created, but when I click on the "Settings" (r.id.settings) it FC. Do I have to do anything to the manifest/other thing to get this to work??

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  • XmlSerialize a custom collection with an Attribute

    - by roomaroo
    I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

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  • How can i call an XSL template within a hyperlink in the XSL stylesheet

    - by AdRock
    I am making my own XSL stylesheet which will perform different views on the same XML document Because the XML document is so large, i would like some links at the top of the outputted page to call each template that will be used to display the data. At the moment I can create links that use anchors to a place in the document but it would be better if i just call each template as needed. How can i just call each template in a link? Would i have to use xlink? <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="folktask"> <html> <body> <a href="folk.xml#organisers">Show all the users</a> <a href="folk.xml#organisers">Show all the festival organisers</a> <xsl:call-template name="show_all_users" /> <xsl:call-template name="show_all_organisers" /> </body> </html> </xsl:template> </xsl:stylesheet>

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  • Is there a good Open Source, XSD based Web Editor?

    - by ashansky
    I'm looking for a good open source web editor that will take xsd (or some other standard XML) and from that generate web forms that will enable the end user to generate standard xml (without knowing anything about xml obliviously). I took a look at kupu, but there doesn't seem to be much documentation and the site appears to no longer exist. Is there anything out there that does this already. I could write something like this myself, but if there's something that out there that will save me some time that would be great. Thanks

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  • How to intercept, parse and compile?

    - by epitka
    This is a problem I've been struggling to solve for a while. I need a way to either replace code in the method with a parsed code from the template at compile time (PostSharp comes to mind) or to create a dynamic proxy (Linfu or Castle). So given a source code like this [Template] private string GetSomething() { var template = [%=Customer.Name%] } I need it to be compiled into this private string GetSomething() { MemoryStream mStream = new MemoryStream(); StreamWriter writer = new StreamWriter(mStream,System.Text.Encoding.UTF8); writer.Write(@"" ); writer.Write(Customer.Name); StreamReader sr = new StreamReader(mStream); writer.Flush(); mStream.Position = 0; return sr.ReadToEnd(); } It is not important what technology is used. I tried with PostSharp's ImplementMethodAspect but got nowhere (due to lack of experience with it). I also looked into Linfu framework. Can somebody suggest some other approach or way to do this, I would really appreciate. My whole project depends on this.

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  • Find/parse server-side <?abc?>-like tags in html document

    - by Iggyhopper
    I guess I need some regex help. I want to find all tags like <?abc?> so that I can replace it with whatever the results are for the code ran inside. I just need help regexing the tag/code string, not parsing the code inside :p. <b><?abc print 'test' ?></b> would result in <b>test</b> Edit: Not specifically but in general, matching (<?[chars] (code group) ?>)

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  • Scala parser combinators: how to parse "if(x)" if x can contain a ")"

    - by Germán
    I'm trying to get this to work: def emptyCond: Parser[Cond] = ("if" ~ "(") ~> regularStr <~ ")" ^^ { case s => Cond("",Nil,Nil) } where regularStr is defined to accept a number of things, including ")". Of course, I want this to be an acceptable input: if(foo()). But for any if(x) it is taking the ")" as part of the regularStr and so this parser never succeeds. What am I missing?

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  • How to parse json data from https client in android

    - by Madhan Shanmugam
    I try to fetch data from https client. Same code i used to fetch from http client. but its working fine. when i try to use Https client its not working. i am getting the following error. java.net.UnknownHostException: Host is unresolved: https client address:443 Error Log: 10-27 10:01:08.280: W/System.err(21826): java.net.UnknownHostException: Host is unresolved: https client address.com 443 10-27 10:01:08.290: W/System.err(21826): at java.net.Socket.connect(Socket.java:1037) 10-27 10:01:08.290: W/System.err(21826): at org.apache.http.conn.ssl.SSLSocketFactory.connectSocket(SSLSocketFactory.java:317) 10-27 10:01:08.310: W/System.err(21826): at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:129) 10-27 10:01:08.310: W/System.err(21826): at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 10-27 10:01:08.310: W/System.err(21826): at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 10-27 10:01:08.310: W/System.err(21826): at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:348) 10-27 10:01:08.310: W/System.err(21826): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 10-27 10:01:08.320: W/System.err(21826): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 10-27 10:01:08.320: W/System.err(21826): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 10-27 10:01:08.320: W/System.err(21826): at com.myfile.JSONParser.getJSONFromUrl(JSONParser.java:38) 10-27 10:01:08.320: W/System.err(21826): at com.myfile.myfile.processThread(myfile.java:159) 10-27 10:01:08.330: W/System.err(21826): at com.peripay.PERIPay$1$1.run(myfile.java:65) 10-27 10:01:08.330: E/Buffer Error(21826): Error converting result java.lang.NullPointerException 10-27 10:01:08.330: E/JSON Parser(21826): Error parsing data org.json.JSONException: A JSONObject text must begin with '{' at character 0 of

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  • How to parse a url string using mvc2 routes

    - by Lavinski
    If I have a url http://www.site.com/controllerA/actionB/idC how can i extract the RouteValueDictionary where the item with the key controller would have the value of controllerA. Note this isn't for testing so I don't want to use mocking and the solution here does not seem to be working.

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  • Populating fields, input types etc using JSON

    - by Franco
    I have a form that works as follows.. Server request builds XML of the data on server side and sends xml, XSL stylesheet then transforms the XML data into the plain html page distributing the data to the relevant/desired locations of the form on the page. Person can view page and edit the populated form, submit back to DB. I think JSON is more suitable for this from what I have read. The form itself is split into 3 areas, for me this is 3 maps/associative arrays etc each with a name related to the id of an input element etc. The problem for me comes with having the JSON sent to the page, what should I do with it next in order to achieve the same result as I currently get with XML and XSL. Thanks.

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  • How can I read/write data from a file?

    - by samy
    I'm writing a simple chrome extension. I need to create the ability to add sites URLs to a list, or read from the list. I use the list to open the sites in the new tabs. I'm looking for a way to have a data file I can write to, and read from. I was thinking on XML. I read there is a problem changing the content of files with Javascript. Is XML the right choice for this kinda thing? I should add that there is no web server, and the app will run locally, so maybe the problem websites are having are not same as this. Before I wrote this question, I tried one thing, and started to feel insecure because it didn't work. I made a XML file called Site.xml: <?xml version="1.0" encoding="utf-8" ?> <Sites> <site> <url> http://www.sulamacademy.com/AddMsgForum.asp?FType=273171&SBLang=0&WSUAccess=0&LocSBID=20375 </url> </site> <site> <url> http://www.wow.co.il </url> </site> <site> <url> http://www.Google.co.il </url> </site> I made this script to read the data from him, and put in on the html file. function LoadXML() { var ajaxObj = new XMLHttpRequest(); ajaxObj.open('GET', 'Sites.xml', false); ajaxObj.send(); var myXML = ajaxObj.responseXML; document.write('<table border="2">'); var prs = myXML.getElementsByTagName("site"); for (i = 0; i < prs.length; i++) { document.write("<tr><td>"); document.write(prs[i].getElementsByName("url")[0].childNode[0].nodeValue); document.write("</td></tr>"); } document.write("</table"); }

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  • Drupal Views Bonus Pack export issue

    - by evanmcd
    Hi, In trying to solve the problem of getting data from Drupal into XML, I found the Views Bonus Pack module, which with a little figuring out works great. Except... When setting the Style property in the Basic settings of Feed view to XML file no items show up unless I am authenticated. If I log in, I see all the entries. If I log out, I see only <xml> <node/> </xml> The Access setting is set to unrestricted in both the Defaults and the Feed view. Anybody have any ideas as to how to fix this? Thanks a lot.

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  • NSString writeToFile operation couldn't be completed

    - by Chonch
    Hey, I have an xml file in my application bundle. I want to copy it to the documents folder at installation and then, every time the app launches, get the newest version of this file from the Internet. I use this code: // Check if the file exists in the documents folder NSString *documentsPath = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0]; if (![[NSFileManager defaultManager] fileExistsAtPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"]]) // If not, copy it there (from the bundle) [[NSFileManager defaultManager] copyItemAtPath:[[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"OriginalFile.xml"] toPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] error:nil]; // Get the newest version of the file from the server NSURL *url=[[NSURL alloc] initWithString:@"http://www.sitename.com/webservice.asmx/webserviceName"]; NSString *results = [[NSString alloc] initWithContentsOfURL:url]; // Replace the current version with the newest one, only if it is valid if (results != nil) [results writeToFile:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] atomically:NO encoding:NSStringEncodingConversionAllowLossy error:nil]; The problem is that the writeToFile command always returns NO and the file's contents remain identical to the original file I included in my app bundle. I checked the value of results and it's correct. I also made sure that the app does perform the writeToString command, but still, it always returns NO. Can anybody tell me what I'm doing wrong? Thanks,

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  • Using XPath on String in Android (JAVA)

    - by Rav
    I am looking for some examples of using xpath in Android? Or if anyone can share their experiences. I have been struggeling to make tail or head of this problem :-( I have a string that contains a standard xml file. I believe I need to convert that into an xml document. I have found this code which I think will do the trick: public static Document stringToDom(String xmlSource) throws SAXException, ParserConfigurationException, IOException { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); return builder.parse(new InputSource(new StringReader(xmlSource))); } Next steps Assuming the code above is OK, I need to apply xpath to get values from cat: "/animal/mammal/feline/cat" I look at the dev doc here: http://developer.android.com/reference/javax/xml/xpath/XPath.html and also look online, but I am not sure where to start! I have tried to use the following code: XPathFactory xPathFactory = XPathFactory.newInstance(); // To get an instance of the XPathFactory object itself. XPath xPath = xPathFactory.newXPath(); // Create an instance of XPath from the factory class. String expression = "SomeXPathExpression"; XPathExpression xPathExpression = xPath.compile(expression); // Compile the expression to get a XPathExpression object. Object result = xPathExpression.evaluate(xmlDocument); // Evaluate the expression against the XML Document to get the result. But I get "Cannot be resolved". Eclipse doesn't seem to be able to fix this import. I tried manually entering: javax.xml.xpath.XPath But this did not work. Does anyone know any good source code that I can utilise, for Android platform? 1.5

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