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  • iPhone OS: Is there a way to set up KVO between two ManagedObject Entities?

    - by nickthedude
    I have 2 entities I want to link with KVO, one a single statTracker class that keeps track of different stats and the other an achievement class that contains information about achievements. Ideally what I want to be able to do is set up KVO by having an instance of the achievement class observe a value on the statTracker class and also set up a threshold value at which the achievement instance should be "triggered"(triggering in this case would mean showing a UIAlertView and changing a property on the achievement class.) I'd like to also set these relationships up on instantiation of the achievement class if possible so kind of like this: Achievement *achievement1 = (Achievement *)[NSEntityDescription insertNewObjectForEntityForName:@"Achievement" inManagedObjectContext:[[CoreDataSingleton sharedCoreDataSingleton] managedObjectContext]]; [achievement1 setAchievementName:@"2 time launcher"]; [achievement1 setAchievementDescription:@"So you've decided to come back for more eh? Here are some achievement points to get you going"]; [achievement1 setAchievementPoints:[NSNumber numberWithInt:300]; [achievement1 setObjectToObserve:@"statTrackerInstace" propertyToObserve:@"timesLaunched" valueOfPropertToSatisfyAchievement:2] Anyone out there know how I would set this up? Is there some way I could do this by way of relationships that I'm not seeing? Thanks, Nick

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  • How to distinguish between two different UDP clients on the same IP address?

    - by Ricket
    I'm writing a UDP server, which is a first for me; I've only done a bit of TCP communications. And I'm having trouble figuring out exactly how to distinguish which user is which, since UDP deals only with packets rather than connections and I therefore cannot tell exactly who I'm communicating with. Here is pseudocode of my current server loop: DatagramPacket p; socket.receive(p); // now p contains the user's IP and port, and the data int key = getKey(p); if(key == 0) { // connection request key = makeKey(p); clients.add(key, p.ip); send(p.ip, p.port, key); // give the user his key } else { // user has a key // verify key belongs to that IP address // lookup the user's session data based on the key // react to the packet in the context of the session } When designing this, I kept in mind these points: Multiple users may exist on the same IP address, due to the presence of routers, therefore users must have a separate identification key. Packets can be spoofed, so the key should be checked against its original IP address and ignored if a different IP tries to use the key. The outbound port on the client side might change among packets. Is that third assumption correct, or can I simply assume that one user = one IP+port combination? Is this commonly done, or should I continue to create a special key like I am currently doing? I'm not completely clear on how TCP negotiates a connection so if you think I should model it off of TCP then please link me to a good tutorial or something on TCP's SYN/SYNACK/ACK mess. Also note, I do have a provision to resend a key, if an IP sends a 0 and that IP already has a pending key; I omitted it to keep the snippet simple. I understand that UDP is not guaranteed to arrive, and I plan to add reliability to the main packet handling code later as well.

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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Invoke an Overloaded Constructor through this keyword (What's the Different between this two Sample code?)

    - by Alireza Dehqani
    using System; namespace ConsoleApplication1 { class Program { static void Main() { // Sample Sample ob = new Sample(); // line1 // Output for line1 /* * Sample(int i) * Sample() / // Sample2 Sample2 ob2 = new Sample2(); // line2 // Output for line2 / * Sample2() */ } } class Sample { // Fields private int a; // Constructors public Sample(int i) // Main Constructor { Console.WriteLine(" Sample(int i)"); a = i; } // Default Constructor public Sample() : this(0) { Console.WriteLine(" Sample()"); } } class Sample2 { // fields private int a; // Constructors public Sample2(int i) { Console.WriteLine("Sample2(int i)"); a = i; } public Sample2() { Console.WriteLine("Sample2()"); a = 0; } } }

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  • Why does the following Toggle function perform four different operations instead of two?

    - by marcamillion
    You can see the implementation here: http://jsfiddle.net/BMWZd/8/ What I am trying to do, when you click on 'John Brown', you see the first element at top turn black. When you click it again, the border of the dotted circle disappears, then when you click 'John Brown' again, you see something else, then finally once again it all disappears. What I am trying to achieve is when you click it once, everything turns black (like it does now), then you click it again, everything disappears and goes back to the original state. Important distinction, what I mean is...when one of the names in the box are not clicked. So if you clicked John Brown then moved to Jack Dorsey, the #1 at top should stay black. But if you were to click Jack Dorsey again, i.e. you 'unclicked' it, then it should disappear. Also, how do I tighten it up, so that it responds quicker. Now when you click it, it feels like there is a little bit of a lag between when it was clicked and when it responds. Edit1: If anyone is interested...the UI that this will be used in is for my webapp - http://www.compversions.com

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  • Efficient algorithm to find a maximum common subset of two sets?

    - by datasunny
    Each set contains bunch of checksums. For example: Set A: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f 07736dde2f8484a4a3af463e05f039e3 5b1e374ff2ba949ab49870ca24d3163a } Set B: { 6639e1da308fd7b04b7635a17450df7c 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } The maximum common subset of A and B is: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } A lot of this operations will be performed, so I'm looking for an efficient algorithm to do so. Thanks for your help.

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  • Is it possible to bind data asynchronously between two dropdownlists in a view?

    - by user252160
    I'd like to achieve the following effect using ASP.NET MVC and JQuery. I've got a drop down list displaying a list of Countries. I want to make it so that when I change the value of the country, a new drop down list appears below it, showing a list of companies whose country of origin is the particular selected company. The thing is that I do not want to rely too much on controller actions because I'm using it in a Template Helper which is a "headless" view. Can I bind it somehow?

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  • Cache inferno - how can Model.A be two different things at the same time?

    - by Martin
    I have this <%=Model.StartDate%> <%=Html.Hidden("StartDate", Model.StartDate)%> it outputs: 2010-05-11 11:00:00 +01:00 <input type="hidden" value="2010-03-17 11:00:00 +01:00" name="StartDate" id="StartDate"> What the... It's a paging mechanism so the hidden value was valid on the first page and I've been able to move forward to the next page. But since the values won't update properly it ends there. What do I need to do. Using firefox.

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  • how to specify in xml schema that either one of two fields must be present?

    - by matti
    i want to specify that either fieldname or freetext is always present in xml files that apply to xsd. is there a way to define it? <xs:complexType name="tSome"> <xs:sequence> <!-- either of 2 below have 2 be present. --> <xs:element name="fieldname" type="xs:string" minOccurs="0" /> <xs:element name="freetext" type="xs:string" minOccurs="0" /> <xs:element name="dbtablename" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> thanks & best regards: Matti

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  • Why doesn't a URL with two hyphens ( in one segment ) match a Route in my Route Table?

    - by Atomiton
    I'm trying to resolve this URL Route: Route articlesByCategory = new Route("articles/c{cid}-{category}", new Handler); However, it seems like the following url won't resolve to this route: // doesn't work www.site.com/articles/c24-this-is-the-category-title // This works www.site.com/articles/c24-category I assume it has to do with the dashes in the title, but can anyone tell me why this works this way? Is there a way to allow dashes in the title for a URL route like this?

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  • How do you search between two columns using a parameter and a case when statement? SQL Server

    - by Kip Birgen
    I would like to search between to columns in a s query or a table depending on the variable on a paramenter e.g Declare @SelectAll as interger Set @SelectAll = 1 Declare @Column as interger Select mt.Column1, mtColumn2 From MyTable as mt Where Case When @SelectAll = 1 Then mt.Column1 IN(@Column) and mt.Column2 (' Selecting all") When @SelectAll = 1 Then mt.Column2 IN(@Column) and mt.Column1 (' Selecting all") End The purpose of this query is to allow the user to search between the column they choose. Further more the use of parameter is for the purposes of writing reporting services reports.

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  • Why do I get two clicked or released signals when using a custom slot for a QPushButton ?

    - by Chris
    here's the main code at first I thought is was the message box but setting a label instead has the same effect. #include <time.h> #include "ui_mainwindow.h" #include <QMessageBox> class MainWindow : public QWidget, private Ui::MainWindow { Q_OBJECT public: MainWindow(QWidget *parent = 0); void makeSum(void); private: int r1; int r2; private slots: void on_pushButton_released(void); }; MainWindow::MainWindow(QWidget *parent) : QWidget(parent) { setupUi(this); } void MainWindow::on_pushButton_released(void) { bool ok; int a = lineEdit->text().toInt(&ok, 10); if (ok) { if (r1+r2==a) { QMessageBox::information( this, "Sums","Correct!" ); } else { QMessageBox::information( this, "Sums","Wrong!" ); } } else { QMessageBox::information( this, "Sums","You need to enter a number" ); } makeSum(); } void MainWindow::makeSum(void) { r1 = rand() % 10 + 1; r2 = rand() % 10 + 1; label->setText(QString::number(r1)); label_3->setText(QString::number(r2)); } int main(int argc, char *argv[]) { srand ( time(NULL) ); QApplication app(argc, argv); MainWindow mw; mw.makeSum(); mw.show(); return app.exec(); } #include "main.moc"

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  • Rails3. How do I display two different objects in a search?

    - by JZ
    I am using a simple search that displays search results: @adds = Add.search(params[:search]) In addition to the search results I'm trying to utilize a method, nearbys(), which displays objects that are close in proximity to the search result. The following method displays objects which are close to 2, but it does not display object 2. How do I display object 2 in conjunction with the nearby objects? @adds = Add.find(2).nearbys(10) While the above code functions, when I use search, @adds = Add.search(params[:search]).nearbys(10) a no method error is returned, undefined methodnearbys' for Array:0x30c3278` How can I search the model for an object AND use the nearbys() method AND display all results returned?

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  • What kind of storage with two-way replication for multi site C# application?

    - by twk
    Hi I have a web-based system written using asp.net backed by mssql. A synchronized replica of this system is to be run on mobile locations and must be available regardless of the state of the connection to the main system (few hours long interruptions happens). For now I am using a copy of the main web application and a copy of the mssql server with merge replication to the main system. This works unreliably, and setting the replication is a pain. The amount of data the system contains is not huge, so I can migrate to different storage type. For the new version of this system I would like to implement a new replication system. I am considering migration to db4o for storage with it's replication support. I am thinking about other possible solutions like couchdb which had native replication support. I would like to stay with C#. Could you recommend a way to go for such a distributed environment? PS. Master-Slave replication is not an option: any side must be allowed to add/update data.

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  • What is the difference between these two different lines of Objective-C, and why does one work and n

    - by jrtc27
    If I try and release tempSeedsArray after seedsArray = tempSeedsArray , I get an EXEC_BAD_ACCESS, and Instruments shows that tempSeedsArray has been released twice. Here is my viewWillAppear method: - (void)viewWillAppear:(BOOL)animated { NSString *arrayFilePath = [[NSBundle mainBundle] pathForResource:@"SeedsArray" ofType:@"plist"]; NSLog(@"HIT!"); NSMutableArray *tempSeedsArray = [[NSMutableArray alloc] initWithContentsOfFile:arrayFilePath]; seedsArray = tempSeedsArray; NSLog(@"%u", [seedsArray retainCount]); [seedsArray sortUsingSelector:@selector(localizedCaseInsensitiveCompare:)]; [super viewWillAppear:animated]; } seedsArray is an NSMutableArray set as a nonatomic and a retain property, and is synthesised. However, if I change seedsArray = tempSeedsArray to self.seedsArray = tempSeedsArray (or [self seedsArray] = tempSeedsArray etc.), I can release tempSeedsArray. Could someone please explain simply to me why this is, as I am very confused! Thanks

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  • How do I pass a string or data object between two view controllers?

    - by Jonathan
    In my last question i asked how to best send a string from one view controller to another, both which were on a navigation stack: http://stackoverflow.com/questions/2898860/pass-string-from-tableviewcontroller-to-viewcontroller-in-navigation-stack However I just realised I can either pass the path to the file in the app's document's folder as the first (the table view) has already accessed the data in the file should I pass viewcontroller the data to the pushed VC?

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  • Regex to extract a string between two delimeters WITHOUT also returning the delimeters?

    - by CSharp Noob
    Hello, I want to just extract the text between the brackets -- NOT the brackets, too! My code looks currently like this: var source = "Harley, J. Jesse Dead Game (2009) [Guard]" // Extract role with regex m = Regex.Match(source, @"[(.*)]"); var role = m.Groups[0].Value; // role is now "[Guard]" role = role.Substring(1, role.Length-2); // role is now "Guard" Can you help me to simplify this to just a single regex, instead of the regex, then the substring?

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