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  • MySQL - Find entries that refer to a specified index.

    - by Conor H
    Hi, So I have a booking system where I have a 'lesson_type' table with 'lesson_type_id' as PK. I have a constraint in place here so I can't delete a lesson_type if there are bookings made for that lesson_type. I would like to be able to determine if this lesson_type_id is being referred to by any entries in the bookings table (or any other table for that matter) so I can notify the user gracefully. i.e. not have a mysql error be thrown when they try and delete a record. What kind of query would I use for this? Thanks.

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  • How to retrieve Google Appengine Objects by id (Long value) ?

    - by David
    Hi, i have declared an entity the following way: public class MyEntity { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Long id; @Persistent private String text; //getters and setters } Now I want to retrieve the objects using the id. I tried to manage it from the Google Appengine Data Viewer with "SELECT * FROM MyEntity Where id = 382005" or via a query in a servlet. I get no results returned. But i know for sure that the object with the id exists (i made a jsp which queries all objects in the db and displays them in the db). So what is wrong in my query? Am I querying the wrong field? The Google Appengine Data Viewer names the field "ID/name" and it has the value "id=382005". Do I have to query with this names? I've tried but it didn't work out :(

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  • Specifying $(this).val() for two different elements (by class)

    - by Chaya Cooper
    What would be the correct syntax for specifying 2 elements by class to evaluate their values when they have different classes? This snippet adds and/or removes values from "increase_priority1" when the user has selected both a complaint and ranked the importance level of the issue, however when I added the 2nd element (".complaint select") to the If Statement it stopped working properly and only accepts input from the 2nd item (Waist) after the 1rst item (Shoulders) has been selected. I believe the problem is that it's unable to determine which ".complaint select" to use, but I haven't been able to figure out how to use (this) for the 2nd element, or another similar approach. The complete function includes apx. 20 similar pairs of If Statements to set & unset other elements, and a working example with 4 pairs is available at http://jsfiddle.net/chayacooper/vWLEn/168/ I'm trying to avoid using ID's because that becomes pretty cumbersome to do for 25 Select elements and each of their values (ID's were also problematic because it stopped working when I added a 2nd element to the If Statement for removing/unsetting a value) Javascript var $increase_priority1 = $(".increase_priority1"); // If value is "Shoulders", complaint was Shoulders too small (select name=Shoulders value=Too_small) and it was assigned a level 1 priority (select class="ranking shoulders" value=1). // var's for other issues and priority levels go here $(".ranking, .complaint select").change(function() { var name = $(this).data("name"); //get priority name if ($(".complaint select").val() === "Too_small" && $(this).val() == 1 && !$(this).data("increase_priority1")) { //rank is 1, and not yet added to priority list $("<option>", {text:name, val:name}).appendTo($increase_priority1); $(this).data("increase_priority1", true); //flag as a priority item } if ($(this).data("increase_priority1") && ($(this).val() != 1 || $(".complaint select").val() != "Too_small")) { //is in priority list, but now demoted $("option[value=" + name + "]", $increase_priority1).remove(); $(this).removeData("increase_priority1"); //no longer a priority item } // Similar If Statements to set & unset other elements go here }); HTML <div> <label>To Increase - 1rst Priority <select name="modify_increase_1rst[]" class="increase_priority1" multiple> </select></label> </div> <div> <span class="complaint"> <label>Shoulders</label> <select name=Shoulders> <option value="null">Select</option><option value="Too_small">Too Small</option><option value="Too_big">Too Big</option><option value="Too_expensive">Too expensive</option> </select> </span> <label>Ranking</label> <select name="importance_bother_shoulders" class="ranking shoulders" data-name="Shoulders"> <option value="Null">Select</option><option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option> <option value="5">5</option> </select> </div> <div> <span class="complaint"> <label>Waist</label> <select name=Waist> <option value="null">Select</option><option value="Too_small">Too Small</option><option value="Too_big">Too Big</option><option value="Too_expensive">Too expensive</option> </select> </span> <label>Ranking</label> <select name="importance_bother_waist" class="ranking waist" data-name="Waist"> <option value="Null">Select</option><option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option> <option value="5">5</option> </select> </div>

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  • Saving a grails object with a composite id

    - by Jared
    The answer to this may be obvious but how do you save an object, in grails, that has a composite id. I have an object that has a composite id including a long and a date and I am trying to save an instance of the object from the update method of another classes controller, and using (object).save() isn't working. Any tips or suggestions?

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  • Content Assist problem in eclipse 3.5

    - by user361996
    I've got a Content Assist problem in eclipse 3.5, which is eclipse-java-galileo-win32.zip. When I press Alt+/(I've changed Ctrl+Space to this) in Java Editor, no assistant tips are shown up. I've solved this problem and I'd like to share my experience. 1 Eclipse--Preferences--General--Keys; 2 Search 'Content Assist'; 3 You'll find that in 'When' Field, the default value is 'in dialogs and window', change it to 'Editing Java Source', then press 'OK' to save; I can not post a image, but here is a link: http://www.freeimagehosting.net/image.php?e0987ea847.png That's All.

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  • How to update a mesh position base on a pressed key?

    - by steven166
    I have a mesh loaded from a file, like a tiger mesh. At the first time it locates at A position, then if I press a left key, it will moves to B position but the problem is if I press a left key one more time, it will move from B position to C position. It means that the amount I want to move the mesh will base on the current position instead of the first time rendering position. I can do it if I have a array vertices then I just update the vertex buffer, but a mesh loaded from a file does not have an array vertices, so how to do it? Anybody help me, please?

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  • LINQ2SQL: How to let a column accept null values as zero (0) in Self-Relation table

    - by Remon
    As described in the img, I got a parent-Children relation and since the ParentID not accepting null values (and I can't change to nullabel due to some restriction in the UI I have), how can I remove an existence relation between ReportDataSources in order to change the parent for them (here i want to set the parentId for one of them = 0) how could i do that since i cant change the ParentID directly and setting Parent = null is not valid public void SetReportDataSourceAsMaster(ReportDataSource reportDataSource) { //Some logic - not necessarily for this scenario //Reset Master this.ReportDataSources.ToList().ForEach(rds => rds.IsMaster = false); //Set Master reportDataSource.IsMaster = true; //Set Parent ID for the rest of the Reports data sources this.ReportDataSources.Where(rds => rds.ID != reportDataSource.ID).ToList().ForEach(rds => { //Change Parent ID rds.Parent = reportDataSource; //Remove filttering data rds.FilteringDataMembers.Clear(); //Remove Grouping Data rds.GroupingDataMembers.Clear(); }); //Delete parent HERE THE EXCEPTION THROWN AFTER CALLING SUBMITCHANGES() reportDataSource.Parent = null; //Other logic } Exception thrown after calling submitChanges An attempt was made to remove a relationship between a ReportDataSource and a ReportDataSource. However, one of the relationship's foreign keys (ReportDataSource.ParentID) cannot be set to null.

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  • how to store data with many categories and many properties efficiently?

    - by Mickey Shine
    We have a large number of data in many categories with many properties, e.g. category 1: Book properties: BookID, BookName, BookType, BookAuthor, BookPrice category 2: Fruit properties: FruitID, FruitName, FruitShape, FruitColor, FruitPrice We have many categories like book and fruit. Obviously we can create many tables for them (MySQL e.g.), and each category a table. But this will have to create too many tables and we have to write many "adapters" to unify manipulating data. The difficulties are: 1) Every category has different properties and this results in a different data structure. 2) The properties of every categoriy may have to be changed at anytime. 3) Hard to manipulate data if each category a table (too many tables) How do you store such kind of data?

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  • Should I try to write simple key-value storage by myself?

    - by shabunc
    I need a key-value storage in a simplest form we can think of. Keys should be some fixed-length strings, values should be some texts. This key-value storage should have an HTTP-backed API. That's basically it. As you can see, there is no big difference between such storage and some web application with some upload functionality. The thing is - it'll take few hours (including tests and coffee drinking) to write something like this. "Something like this" will be fully under my control and can be tuned on demand. Should I, in this specific case, not try to reinvent bicycles? Is it better to use some of existing NoSQL solutions. If yes, which one exactly? If, say, I'd needed something SQL-like, I won't ask and won't try to write something by myself. But with NoSQL I just don't know what is adequate and what is not.

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  • array_key_exists is not working

    - by Arun
    array_key_exists is not working for large multidimensional array. For ex $arr=array( '1'=>10, '2'=>array('21'=>21, '22'=>22, '23'=>array('test'=>100, '231'=>231), ), '3'=>30, '4'=>40 ); array_key_exists('test',$arr) returns 'false' but it works with some simple arrays.

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  • Rename INDEX Column

    - by Lee
    Hey All I have a database with around 40 tables and need to rename every index column. IE USER a table has a bunch of fields like user_id | user_username | user_password | etc... I want to rename the ID columns just to id ie id | user_username | user_password | etc... But I keep getting mysql errors on the alter table command ie. ALTER TABLE database RENAME COLUMN user_id to id; Plus many different variations. Whats the best way to do this ? Hope you can advise

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  • How to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x

    - by TheStruggler
    I'm stuck on how to formulate this problem properly and the following is: What if we had the following values: {('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3) The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values. So we remove the alphabet with the fewest first place picks. Which in this case is C. I want to return a dictionary where {'A':5, 'B':4, 'C':2, 'D':3} without importing anything. This is my work: def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -> dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary This returns duplicate of keys which I cannot get rid of. Thanks.

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  • Entity framework Update fails when object is linked to a missing child

    - by McKay
    I’m having trouble updating an objects child when the object has a reference to a nonexising child record. eg. Tables Car and CarColor have a relationship. Car.CarColorId CarColor.CarColorId If I load the car with its color record like so this var result = from x in database.Car.Include("CarColor") where x.CarId = 5 select x; I'll get back the Car object and it’s Color object. Now suppose that some time ago a CarColor had been deleted but the Car record in question still contains the CarColorId value. So when I run the query the Color object is null because the CarColor record didn’t exist. My problem here is that when I attach another Color object that does exist I get a Store update, insert error when saving. Car.Color = newColor Database.SaveChanges(); It’s like the context is trying to delete the nonexisting color. How can I get around this?

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  • Importing data and keeping ids and relationships

    - by Justin Hamade
    I am working on cleaning up a mess that another programmer started. The created 2 identical databases for different locations but that obviously caused major issues. They are using cakePHP and there are quite a few relationships. I am pretty sure I will have to write a script to import that data from on DB to the other and keep all the relationships but was wondering if there is an easier way to do it.

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  • Database PK-FK design for future-effective-date entries?

    - by Scott Balmos
    Ultimately I'm going to convert this into a Hibernate/JPA design. But I wanted to start out from purely a database perspective. We have various tables containing data that is future-effective-dated. Take an employee table with the following pseudo-definition: employee id INT AUTO_INCREMENT ... data fields ... effectiveFrom DATE effectiveTo DATE employee_reviews id INT AUTO_INCREMENT employee_id INT FK employee.id Very simplistic. But let's say Employee A has id = 1, effectiveFrom = 1/1/2011, effectiveTo = 1/1/2099. That employee is going to be changing jobs in the future, which would in theory create a new row, id = 2 with effectiveFrom = 7/1/2011, effectiveTo = 1/1/2099, and id = 1's effectiveTo updated to 6/30/2011. But now, my program would have to go through any table that has a FK relationship to employee every night, and update those FK to reference the newly-effective employee entry. I have seen various postings in both pure SQL and Hibernate forums that I should have a separate employee_versions table, which is where I would have all effective-dated data stored, resulting in the updated pseudo-definition below: employee id INT AUTO_INCREMENT employee_versions id INT AUTO_INCREMENT employee_id INT FK employee.id ... data fields ... effectiveFrom DATE effectiveTo DATE employee_reviews id INT AUTO_INCREMENT employee_id INT FK employee.id Then to get any actual data, one would have to actually select from employee_versions with the proper employee_id and date range. This feels rather unnatural to have this secondary "versions" table for each versioned entity. Anyone have any opinions, suggestions from your own prior work, etc? Like I said, I'm taking this purely from a general SQL design standpoint first before layering in Hibernate on top. Thanks!

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  • MYSQL to UPDATE table if row with 2 specific columns exist or INSERT new row if it does not exist

    - by user2509541
    I have a MYSQL table that looks as follows: id id_jugador id_partido team1 team2 1 2 1 5 2 2 2 2 1 1 3 1 2 0 0 I need to create a query to either INSERT new rows in the table or UPDATE the table. The condition is based on id_jugador and id_partido, meaning that if I wanted to insert id_jugador = 2 and id_partido = 1, then it should just UPDATE the existing row with the new team1 and team2 values I am sending. And dont duplicate the row. However, if I have an entry id_jugador=2 and id_partido=3, since this combination does not exist yet, it should add the new row. I read about the REPLACE INTO but it seems to be unable to check combination of UNIQUE KEYS.

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  • Solution for this SQL query?

    - by homeWorkBoy
    Suppose you have these tables: Table Name: Salesman Fields: S_ID(Primary Key), Name Table Name: Region_1 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_2 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_3 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Table Name: Region_4 Fields: Reg_ID(Primary Key), S_ID(Foreign Key), sales Query 1: Find out total of sales of each salesman in all the regions. Query 2: Find out total of sales of a particual salesman in all the regions. (if the first one is solved I think this will be easy. :-) )

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  • Retrieving an RSA key from a running instance of Apache?

    - by Nathan Osman
    I created an RSA keypair for an SSL certificate and stored the private key in /etc/ssl/private/server.key. Unfortunately this was the only copy of the private key that I had. Then I accidentally overwrote the file on disk (yes, I know). Apache is still running and still serving SSL requests, leading me to believe that there may be hope in recovering the private key. (Perhaps there is a symbolic link somewhere in /proc or something?) This server is running Ubuntu 12.04 LTS.

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