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  • How to switch position of two items in a Python list?

    - by mikl
    I haven’t been able to find a good solution for this problem on the net (probably because switch, position, list and Python are all such overloaded words). It’s rather simple – I have this list: ['title', 'email', 'password2', 'password1', 'first_name', 'last_name', 'next', 'newsletter'] I’d like to switch position of 'password2' and 'password1' – not knowing their exact position, only that they’re right next to one another and password2 is first. I’ve accomplished this with some rather long-winded list-subscripting, but I wondered if someone could come up with something a bit more elegant?

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  • Why is two-way binding in silverlight not working?

    - by Edward Tanguay
    According to how Silverlight TwoWay binding works, when I change the data in the FirstName field, it should change the value in CheckFirstName field. Why is this not the case? ANSWER: Thank you Jeff, that was it, for others: here is the full solution with downloadable code. XAML: <StackPanel> <Grid x:Name="GridCustomerDetails"> <Grid.RowDefinitions> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> <RowDefinition Height="*"/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="Auto"/> <ColumnDefinition Width="300"/> </Grid.ColumnDefinitions> <TextBlock VerticalAlignment="Center" Margin="10" Grid.Row="0" Grid.Column="0">First Name:</TextBlock> <TextBox Margin="10" Grid.Row="0" Grid.Column="1" Text="{Binding FirstName, Mode=TwoWay}"/> <TextBlock VerticalAlignment="Center" Margin="10" Grid.Row="1" Grid.Column="0">Last Name:</TextBlock> <TextBox Margin="10" Grid.Row="1" Grid.Column="1" Text="{Binding LastName}"/> <TextBlock VerticalAlignment="Center" Margin="10" Grid.Row="2" Grid.Column="0">Address:</TextBlock> <TextBox Margin="10" Grid.Row="2" Grid.Column="1" Text="{Binding Address}"/> </Grid> <Border Background="Tan" Margin="10"> <TextBlock x:Name="CheckFirstName"/> </Border> </StackPanel> Code behind: public Page() { InitializeComponent(); Customer customer = new Customer(); customer.FirstName = "Jim"; customer.LastName = "Taylor"; customer.Address = "72384 South Northern Blvd."; GridCustomerDetails.DataContext = customer; Customer customerOutput = (Customer)GridCustomerDetails.DataContext; CheckFirstName.Text = customer.FirstName; }

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  • Packaging one or two plugins as a standalone RCP application?

    - by Martin Cowie
    I have a handful of Eclipse plugins that I maintain. They are proving useful enough that non Eclipse users have asked for them without the overhead of a full eclipse install. I am certain this is possible, but uncertain how to make this possible. My attempts at creating a standalone RCP app and then including my plugins as dependencies have given me mixed results. More specifically, my perspective tries to instantiate a view from a plugin and fails (silently)... public void createInitialLayout(IPageLayout layout) { layout.addStandaloneView( "myPlugin.ID", false, IPageLayout.LEFT, 0.25f, editorArea); } ... but as the same plugin implements a search extension, it does show up in the standard Eclipse search dialog. Are there any resources that hardened Eclipse tars can point me to, that will help overcome this hurdle? M.

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  • How can I concatenate corresponding lines in two files in Perl?

    - by Nano HE
    file1.txt hello tom well file2.txt world jerry done How to merge file1.txt with file2.txt; then create a new file - file3.txt hello world tom jerry well done thank you for reading and reply. Attached the completed code. #!/usr/bin/perl use strict; use warnings; open(F1,"<","1.txt") or die "Cannot open file1:$!\n"; open(F2,"<","2.txt") or die "Cannot open file2:$!\n"; open (MYFILE, '>>3.txt'); while(<F1>){ chomp; chomp(my $f2=<F2>); print MYFILE $_ . $f2 ."\n"; }

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  • Can a CLSID be different for the same program installed on two different machines?

    - by uberjumper
    I am using comtypes to generate wrappers for a certain com library. I am having certain issues with a few things, that are not being generated properly. I can get around this by doing the missing work, manually. However can i depend on the fact that CLSID's will not change? Lets say: I install a program with the com library Foo 1.0, now i install the exact same version of that program on another PC, will the CLSID's of the interfaces change? This might be a terribly dumb question.

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  • How to distinguish between two different UDP clients on the same IP address?

    - by Ricket
    I'm writing a UDP server, which is a first for me; I've only done a bit of TCP communications. And I'm having trouble figuring out exactly how to distinguish which user is which, since UDP deals only with packets rather than connections and I therefore cannot tell exactly who I'm communicating with. Here is pseudocode of my current server loop: DatagramPacket p; socket.receive(p); // now p contains the user's IP and port, and the data int key = getKey(p); if(key == 0) { // connection request key = makeKey(p); clients.add(key, p.ip); send(p.ip, p.port, key); // give the user his key } else { // user has a key // verify key belongs to that IP address // lookup the user's session data based on the key // react to the packet in the context of the session } When designing this, I kept in mind these points: Multiple users may exist on the same IP address, due to the presence of routers, therefore users must have a separate identification key. Packets can be spoofed, so the key should be checked against its original IP address and ignored if a different IP tries to use the key. The outbound port on the client side might change among packets. Is that third assumption correct, or can I simply assume that one user = one IP+port combination? Is this commonly done, or should I continue to create a special key like I am currently doing? I'm not completely clear on how TCP negotiates a connection so if you think I should model it off of TCP then please link me to a good tutorial or something on TCP's SYN/SYNACK/ACK mess. Also note, I do have a provision to resend a key, if an IP sends a 0 and that IP already has a pending key; I omitted it to keep the snippet simple. I understand that UDP is not guaranteed to arrive, and I plan to add reliability to the main packet handling code later as well.

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  • iPhone OS: Is there a way to set up KVO between two ManagedObject Entities?

    - by nickthedude
    I have 2 entities I want to link with KVO, one a single statTracker class that keeps track of different stats and the other an achievement class that contains information about achievements. Ideally what I want to be able to do is set up KVO by having an instance of the achievement class observe a value on the statTracker class and also set up a threshold value at which the achievement instance should be "triggered"(triggering in this case would mean showing a UIAlertView and changing a property on the achievement class.) I'd like to also set these relationships up on instantiation of the achievement class if possible so kind of like this: Achievement *achievement1 = (Achievement *)[NSEntityDescription insertNewObjectForEntityForName:@"Achievement" inManagedObjectContext:[[CoreDataSingleton sharedCoreDataSingleton] managedObjectContext]]; [achievement1 setAchievementName:@"2 time launcher"]; [achievement1 setAchievementDescription:@"So you've decided to come back for more eh? Here are some achievement points to get you going"]; [achievement1 setAchievementPoints:[NSNumber numberWithInt:300]; [achievement1 setObjectToObserve:@"statTrackerInstace" propertyToObserve:@"timesLaunched" valueOfPropertToSatisfyAchievement:2] Anyone out there know how I would set this up? Is there some way I could do this by way of relationships that I'm not seeing? Thanks, Nick

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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Invoke an Overloaded Constructor through this keyword (What's the Different between this two Sample code?)

    - by Alireza Dehqani
    using System; namespace ConsoleApplication1 { class Program { static void Main() { // Sample Sample ob = new Sample(); // line1 // Output for line1 /* * Sample(int i) * Sample() / // Sample2 Sample2 ob2 = new Sample2(); // line2 // Output for line2 / * Sample2() */ } } class Sample { // Fields private int a; // Constructors public Sample(int i) // Main Constructor { Console.WriteLine(" Sample(int i)"); a = i; } // Default Constructor public Sample() : this(0) { Console.WriteLine(" Sample()"); } } class Sample2 { // fields private int a; // Constructors public Sample2(int i) { Console.WriteLine("Sample2(int i)"); a = i; } public Sample2() { Console.WriteLine("Sample2()"); a = 0; } } }

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  • Is it possible to bind data asynchronously between two dropdownlists in a view?

    - by user252160
    I'd like to achieve the following effect using ASP.NET MVC and JQuery. I've got a drop down list displaying a list of Countries. I want to make it so that when I change the value of the country, a new drop down list appears below it, showing a list of companies whose country of origin is the particular selected company. The thing is that I do not want to rely too much on controller actions because I'm using it in a Template Helper which is a "headless" view. Can I bind it somehow?

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  • Efficient algorithm to find a maximum common subset of two sets?

    - by datasunny
    Each set contains bunch of checksums. For example: Set A: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f 07736dde2f8484a4a3af463e05f039e3 5b1e374ff2ba949ab49870ca24d3163a } Set B: { 6639e1da308fd7b04b7635a17450df7c 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } The maximum common subset of A and B is: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } A lot of this operations will be performed, so I'm looking for an efficient algorithm to do so. Thanks for your help.

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  • Why does the following Toggle function perform four different operations instead of two?

    - by marcamillion
    You can see the implementation here: http://jsfiddle.net/BMWZd/8/ What I am trying to do, when you click on 'John Brown', you see the first element at top turn black. When you click it again, the border of the dotted circle disappears, then when you click 'John Brown' again, you see something else, then finally once again it all disappears. What I am trying to achieve is when you click it once, everything turns black (like it does now), then you click it again, everything disappears and goes back to the original state. Important distinction, what I mean is...when one of the names in the box are not clicked. So if you clicked John Brown then moved to Jack Dorsey, the #1 at top should stay black. But if you were to click Jack Dorsey again, i.e. you 'unclicked' it, then it should disappear. Also, how do I tighten it up, so that it responds quicker. Now when you click it, it feels like there is a little bit of a lag between when it was clicked and when it responds. Edit1: If anyone is interested...the UI that this will be used in is for my webapp - http://www.compversions.com

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  • how to specify in xml schema that either one of two fields must be present?

    - by matti
    i want to specify that either fieldname or freetext is always present in xml files that apply to xsd. is there a way to define it? <xs:complexType name="tSome"> <xs:sequence> <!-- either of 2 below have 2 be present. --> <xs:element name="fieldname" type="xs:string" minOccurs="0" /> <xs:element name="freetext" type="xs:string" minOccurs="0" /> <xs:element name="dbtablename" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> thanks & best regards: Matti

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  • Cache inferno - how can Model.A be two different things at the same time?

    - by Martin
    I have this <%=Model.StartDate%> <%=Html.Hidden("StartDate", Model.StartDate)%> it outputs: 2010-05-11 11:00:00 +01:00 <input type="hidden" value="2010-03-17 11:00:00 +01:00" name="StartDate" id="StartDate"> What the... It's a paging mechanism so the hidden value was valid on the first page and I've been able to move forward to the next page. But since the values won't update properly it ends there. What do I need to do. Using firefox.

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  • Why doesn't a URL with two hyphens ( in one segment ) match a Route in my Route Table?

    - by Atomiton
    I'm trying to resolve this URL Route: Route articlesByCategory = new Route("articles/c{cid}-{category}", new Handler); However, it seems like the following url won't resolve to this route: // doesn't work www.site.com/articles/c24-this-is-the-category-title // This works www.site.com/articles/c24-category I assume it has to do with the dashes in the title, but can anyone tell me why this works this way? Is there a way to allow dashes in the title for a URL route like this?

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  • How do you search between two columns using a parameter and a case when statement? SQL Server

    - by Kip Birgen
    I would like to search between to columns in a s query or a table depending on the variable on a paramenter e.g Declare @SelectAll as interger Set @SelectAll = 1 Declare @Column as interger Select mt.Column1, mtColumn2 From MyTable as mt Where Case When @SelectAll = 1 Then mt.Column1 IN(@Column) and mt.Column2 (' Selecting all") When @SelectAll = 1 Then mt.Column2 IN(@Column) and mt.Column1 (' Selecting all") End The purpose of this query is to allow the user to search between the column they choose. Further more the use of parameter is for the purposes of writing reporting services reports.

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  • Why do I get two clicked or released signals when using a custom slot for a QPushButton ?

    - by Chris
    here's the main code at first I thought is was the message box but setting a label instead has the same effect. #include <time.h> #include "ui_mainwindow.h" #include <QMessageBox> class MainWindow : public QWidget, private Ui::MainWindow { Q_OBJECT public: MainWindow(QWidget *parent = 0); void makeSum(void); private: int r1; int r2; private slots: void on_pushButton_released(void); }; MainWindow::MainWindow(QWidget *parent) : QWidget(parent) { setupUi(this); } void MainWindow::on_pushButton_released(void) { bool ok; int a = lineEdit->text().toInt(&ok, 10); if (ok) { if (r1+r2==a) { QMessageBox::information( this, "Sums","Correct!" ); } else { QMessageBox::information( this, "Sums","Wrong!" ); } } else { QMessageBox::information( this, "Sums","You need to enter a number" ); } makeSum(); } void MainWindow::makeSum(void) { r1 = rand() % 10 + 1; r2 = rand() % 10 + 1; label->setText(QString::number(r1)); label_3->setText(QString::number(r2)); } int main(int argc, char *argv[]) { srand ( time(NULL) ); QApplication app(argc, argv); MainWindow mw; mw.makeSum(); mw.show(); return app.exec(); } #include "main.moc"

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