Search Results

Search found 16738 results on 670 pages for 'lwuit button'.

Page 144/670 | < Previous Page | 140 141 142 143 144 145 146 147 148 149 150 151  | Next Page >

  • wpf: How to keep an image stay in its original size?

    - by Martin Luo
    hi, guys! i have a problem about the image display in wpf. here's my code <Button HorizontalAlignment="Left" Grid.Column="1" Grid.Row="5" Margin="0,5"> <Button.Content> <StackPanel Orientation="Horizontal" Margin="10,0"> <Image Source="/images/user_add.png" Stretch="None" HorizontalAlignment="Center" VerticalAlignment="Center" Width="24" Height="24" /> <TextBlock Text="??" /> </StackPanel> </Button.Content> </Button> i hava the image with original size 32*32, but when i ran the above code, the image will stretch to fill all the space, beyond its original size, and i also set the "Stretch" property to "None", but it seems that it doesn't work. so, how can i fix this problem? thank u~~~!

    Read the article

  • Jquery Click in li

    - by cKendrick
    I have my html set up like this: <li> Header <button>Edit</button> </li> And I was wondering if there is a way so that you can click on the li and have one action happen and click on the button and have another action happen. Right now if I have a jquery click element on the li it gets fired when you hit the button to. Is there a way to make this separate without changing the html structure?

    Read the article

  • How can i use appendTo and insertBefore properly

    - by Opoe
    hi all! With the append button i add elements to the same class. I want the append button and delete button beneath the appended elements, but when i use insertBefore, the Toggle function only toggles the buttons visibility. You can check out what i mean here; click add a box and start appending http://www.jsfiddle.net/myd3k/ replace appendTo with inserBefore and toggle the visibility. Thanks in advance

    Read the article

  • z-index not working in IE

    - by praveenjayapal
    Hi friends, I have a button, while clicking the button i just produce a div containing some checkbox. If the user select the required checkbox, it will produce a iframe according to the value of the checkbox and the div will disappear. Its placed immediately below the button. Up to this its working fine. If the user again click the button, the droping div is comes behind the frame. Please help me to make it visible above the frame. I have used z-index, its working in firefox - but i cant made it in IE.. Please help me regarding this. Thankspraveen j

    Read the article

  • How to get the url of the page which is currently loading i the iframe

    - by Gayathri
    Hi, I have an requirement that, in my application on clicking an button i have to laod one more application with the same template which i was using for my application. So, on clicking the button in my application i have used one intermediate page in that using iframe i passed that URL of an external application. Its working fine. But the problem is in the external applicatio which is not in my control on clicking an button it is moving to next page. In that page i want to hide an button. I did that also using div tag color as white and set the positions. But the problem is in all the pages in the same position that is affecting. So i want to get the url of the page which is loading in the iframe on the second or third click of an external application, so that i can using some conditions i can hide the control. So please any one help me to get the solution for this problem

    Read the article

  • problem loading resource from class library

    - by mishal153
    I have a class library (mylibrary) which has a resource called "close.png". I used redGate reflector to confirm that the resource is actually present in the dll. Now i use mylibrary.dll in a project where i attempt to extract this "close.png" resource like this : BitmapImage crossImage = new BitmapImage(); crossImage.BeginInit(); crossImage.UriSource = new Uri(@"/mylibrary;component/Resources/close.png", UriKind.RelativeOrAbsolute); crossImage.EndInit(); This BitmapImage crossImage is then used like : Button closeButton = new Button() { Content = new System.Windows.Controls.Image() { Source = crossImage }, MaxWidth = 20, MaxHeight = 20 }; On doing this i get no exceptions being thrown but the button shows no image. Also, i do see some exception info if i investigate the button's 'content' in the debugger.

    Read the article

  • how to close layer that showed in other layer in cocos2d-iphone

    - by yegomo
    I have one layer called alayer, and there is a button called abutton, when click the button, another layer called blayer will show in alayer, not replaceScene, please look at the following code, alayer.m -(void)abuttonclicked:(id)sender { blayer *blayer = [blayer node]; blayer.position = ccp(1,1); [self addChild:blayer]; } blayer.m has a button called bbutton and string value called bstring, I want to click the b button, it will close blayer (remove blayer from alayer), and pass the string value bstring to alayer, please look at following code, -(void)bbuttonclicked:(id)sender { // how can do here to close its self(remove its self from alayer), and pass the bstring to alayer? } thanks. ps. I can use NSUserDefault to pass the string value, but I think it's a bad way to do this, is there another way to pass value?

    Read the article

  • Sending tweets using Android

    - by Saranya.R
    I want to send a tweet from Android.I have executed the following code.But I am not bale to send any tweets.Avtually the button I created is not working.Can anybody tel me wats the prob? This is my code.. package samplecode.sampleapp.sampletwidgitpublicintent; import android.app.Activity; import android.content.ActivityNotFoundException; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.os.Bundle; public class TwidgitPublicIntent extends Activity implements OnClickListener { private static final int TWIDGIT_REQUEST_CODE = 2564; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ((Button)findViewById(R.id.tweet_button)).setOnClickListener(this); ((Button)findViewById(R.id.mention_button)).setOnClickListener(this); ((Button)findViewById(R.id.retweet_button)).setOnClickListener(this); ((Button)findViewById(R.id.message_button)).setOnClickListener(this); } public void onClick(View v) { switch(v.getId()) { case R.id.tweet_button: // Standard tweet Intent tIntent = new Intent("com.disretrospect.twidgit.TWEET"); tIntent.putExtra("com.disretrospect.twidgit.extras.MESSAGE", "_message_in_here_"); try { this.startActivityForResult(tIntent, TWIDGIT_REQUEST_CODE); } catch (ActivityNotFoundException e) { // If Twidgit is not installed } break; case R.id.mention_button: // Mention Intent mIntent = new Intent("com.disretrospect.twidgit.MENTION"); mIntent.putExtra("com.disretrospect.twidgit.extras.TO", "_username_to_xmention_"); mIntent.putExtra("com.disretrospect.twidgit.extras.MESSAGE", "_message_in_here_"); try { this.startActivityForResult(mIntent, TWIDGIT_REQUEST_CODE); } catch (ActivityNotFoundException e) { // If Twidgit is not installed } break; case R.id.retweet_button: // Retweet a tweet Intent rtIntent = new Intent("com.disretrospect.twidgit.RETWEET"); rtIntent.putExtra("com.disretrospect.twidgit.extras.MESSAGE", "_message_in_here_"); rtIntent.putExtra("com.disretrospect.twidgit.extras.VIA", "_original_author_of_tweet_name_"); try { this.startActivityForResult(rtIntent, TWIDGIT_REQUEST_CODE); } catch (ActivityNotFoundException e) { // If Twidgit is not installed } break; case R.id.message_button: // Send DM Intent dmIntent = new Intent("com.disretrospect.twidgit.DIRECT_MESSAGE"); dmIntent.putExtra("com.disretrospect.twidgit.extras.TO", "_username_to_send_dm_to_"); dmIntent.putExtra("com.disretrospect.twidgit.extras.MESSAGE", "_message_in_here_"); try { this.startActivityForResult(dmIntent, TWIDGIT_REQUEST_CODE); } catch (ActivityNotFoundException e) { // If Twidgit is not installed } break; } } @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); // Check result code if(resultCode == Activity.RESULT_OK) { // Check requestCode switch(requestCode) { case TWIDGIT_REQUEST_CODE: // Handle successful return break; } } else if(resultCode == Activity.RESULT_CANCELED){ // Handle canceled activity } } }

    Read the article

  • document.forms.gallery_form.submit is not a function

    - by Keene Maverick
    I swear, I have this exact thing working on another page. I'm such a javascript noob it's embarrassing... function delete_gallery() { var gallery = document.getElementById('gallery_id').value; var form = document.getElementById('gallery_form'); form.setAttribute('action', 'index.php?action=delete&section=galleries&id='+gallery); document.forms['gallery_form'].submit(); } Inspecting the element shows that it's updating the action correctly : <form method="post" action="index.php?action=delete&amp;section=galleries&amp;id=12" name="gallery_form" id="gallery_form"><input type="hidden" value="12" id="gallery_id" name="gallery_id"><p>Name: <input type="text" name="name" value="Woo"></p><p>Description:<br><textarea name="description">Dee</textarea><input type="hidden" value="2" name="artist"></p><p><input type="submit" value="Submit" name="submit"> </p></form> Here's the button I use to call the function, it's in a table below the form: <button onclick="delete_gallery()" type="button">Delete Gallery</button>

    Read the article

  • How do you return draggable content to their original positions in iPhone dev?

    - by Matt Thomas
    I am wanting to create a button in my iPhone app that when touched will return other draggable elements to their original position. I have looked at the Apple "MoveMe' example, but that returns the button to the center of the screen. I want to be able to position draggable objects around the screen, drag the objects within the app, and then return them to their original starting positions by pressing a designated button. Any help appreciated!

    Read the article

  • listener not being called

    - by deb
    I have a table with a button. When the button is clicked I call Modalbox.show (http://okonet.ru/projects/modalbox/) that displays a little form with another button. When the user clicks this second button, a listener is attached to an iframe in the form and the form is submitted to the server. The server does something then it should return back to the form and execute the listener function. This works fine on IE but not in Firefox (on Firefox it never comes back). Here it is the javascript function that is called when the user presses the second button (in the Modalbox) function attachFile() { //window.frames['upload_iframe'].name='upload_iframe'; iframe = document.getElementById('upload_iframe'); if (iframe.addEventListener)//FF iframe.addEventListener("load", iframeEventHandler, false); if (iframe.attachEvent)//IE iframe.attachEvent("onload", iframeEventHandler); // Set properties of form... form = document.getElementById('attchForm'); form.setAttribute("target","upload_iframe"); form.setAttribute("method","post"); form.setAttribute("enctype","multipart/form-data"); form.setAttribute("encoding","multipart/form-data"); // Submit the form... form.submit(); } I checked that it is adding the listener but somehow does not return to it. Any hints? Thanks deb

    Read the article

  • jQuery: preventdefault does not work

    - by Kent Miller
    I somehow cannot achieve that the a-tag looses its default action when clicking it: <a href="#" class="button dismiss">dismiss</a> $(document).ready(function() { $('.dismiss').click(function(e) { e.preventDefault(); $('#output').empty(); $('#MyUploadForm .button').show(); }); }); When I click the button, the browser window scrolls to the top. What is wrong here?

    Read the article

  • Facebook connect problem

    - by Stefano
    I'm trying to add facebook connect button to my ZF web site. After i click on FB connect button the popup with email and password fields opens. But when i send email and password to login with facebook the popub don't close and reload the same page where the facebook connect button was. Any idea? Sorry for my english ..

    Read the article

  • Javascript auto calculating with (+) and (-)

    - by Josh
    I need some help finding the error in my javascript calculation. I need to calculate the sum of my input boxes automatically and have my user be able to edit the calculation using + or - buttons. The code I have already does the calculation automatically if you manually enter the numbers, but pressing the + or - does not change the calculation. Here is the code: <html> <head> <script language="javascript"> function Calc(className){ var elements = document.getElementsByClassName(className); var total = 0; for(var i = 0; i < elements.length; ++i){ total += parseInt(elements[i].value); } document.form0.total.value = total; } function addone(field) { field.value = Number(field.value) + 1; } function subtractone(field) { field.value = Number(field.value) - 1; } </script> </head> <body> <form name="form0" id="form0"> 1: <input type="text" name="box1" id="box1" class="add" value="0" onKeyUp="Calc('add')" onChange="updatesum()" onClick="this.focus();this.select();" /> <input type="button" value=" + " onclick="addone(box1);"> <input type="button" value=" - " onclick="subtractone(box1);"> <br /> 2: <input type="text" name="box2" id="box2" class="add" value="0" onKeyUp="Calc('add')" onClick="this.focus();this.select();" /> <input type="button" value=" + " onclick="addone(box2);"> <input type="button" value=" - " onclick="subtractone(box2);"> <br /> 3: <input type="text" name="box3" id="box3" class="add" value="0" onKeyUp="Calc('add')" onClick="this.focus();this.select();" /> <input type="button" value=" + " onclick="addone(box3);"> <input type="button" value=" - " onclick="subtractone(box3);"> <br /> <br /> Total: <input readonly style="border:0px; font-size:14; color:red;" id="total" name="total"> </form> </body></html> Im sure the issue must be small, I just cant put my finger on it.

    Read the article

  • How to dislpay Kannada (Indic) Fonts in a Java application

    - by AJ
    I am trying to dislplay a kannda character in a Java app. String fonts[] = ge.getAvailableFontFamilyNames(); This shows that there is a font family by name "BRH Kannada" Font f = new Font("BRH Kannada", Font.PLAIN, 20); and then I do button.setFont(f); now when i set the button text, i have to ideally get the text on button to use the BRH kannada font. However, what and how should i give the string as? Rgds, AJ

    Read the article

  • How to inflate a view in a determined position?

    - by Tivie
    I have an activity with an "Add" and a "Delete" button. The "Add Button" inflates a view, the "Delete Button" removes a selected View. When I inflate a view with the "Add Button", it is automatically drawn below any previously infalted view. I would like to give the user the possibility to move each inflated view up and down, so he could change the order they are show in screen (in a drag'n'drop kind of effect) +---------------------+ +---------------------+ | +-----------------+ | | +-----------------+ | | | View 1 | | | | View 2 | | | +-----------------+ | | +-----------------+ | | | --> | | | +-----------------+ | | +-----------------+ | | | View 2 | | | | View 1 | | | +-----------------+ | | +-----------------+ | +---------------------+ +---------------------+ Is it possible to specify the "position" in which each view is inflated? (for instance, below or above the currently selected view?) If not, what is the best way to accomplish the desired effect? (feel free to ask for any piece of code, if you think it might help)

    Read the article

  • Open new UserControl in the mainWindows

    - by user287964
    Hi I have this snippet public partial class Window1 : Window { public Window1() { InitializeComponent(); } private void ToggleButton_Checked(object sender, RoutedEventArgs e) { switch ((sender as Button).Content.ToString()) { case "UserControl 1": AddItemToContainer(new UserControl1()); break; case "UserControl 2": AddItemToContainer(new UserControl2()); break; case "UserControl 3": AddItemToContainer(new UserControl3()); break; default: break; } } void AddItemToContainer(UIElement _myElement) { Grid.SetColumn(_myElement, 1); HostContainer.Children.Add(_myElement); } } } } With this I can open a new userControl in myMainwindow Let’s say something like adding child to myMainWinodw,Now I’m trying to click on a button from my userControl so I open another userControl that take the place of the first one I explain: I have the mainWindows it has 3 button first one to open the first UserControl the second one to open the second userControl and the third to open the last UserControl,imagine that I opened the first UserControl let’s call it UC1, In the UC1 I have a button to open the second userControl (let’s call it UC2) I like that when I clik the button from the UC1 the UC2 is opened and take the place of the UC1 (of course the UC2 is still a child of myMainWinodw) I have alredy try to call the AddItemToContainer methode from other methode but nothing is happened Any suggestion please

    Read the article

  • Activate WPF command based on TextBox value

    - by zendar
    This is MVVM application. I have form and related view model class. There is TextBox, Button and ListBox on form. Button is bound to DelegateCommand that has CanExecute function. Idea is that user enters some data in text box, presses button and data is appended to list box. I would like to enable command (and button) when user enters correct data in TextBox. Things look like this now: CanExecute() contains code that checks if data in property bound to text box is correct. Text box is bound to property in view model UpdateSourceTrigger is set to PropertyChanged and property in view model is updated after each key user presses. Problem is that CanExecute() does not fire when user enters data in text box. It doesn't fire even when text box lose focus. How could I make this work?

    Read the article

  • Can't add email signature in Android

    - by user1680411
    I'm trying to compose and send an email which will include a signature at the bottom of my email content in android. I'm able to send an email but I'm not getting the way that allows me to add my own signature. Do you have any suggestion? here's my code: public void addListener() { final Button button = (Button) findViewById(R.id.button1); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { findViewById = (TextView) findViewById(R.id.t1); Intent i = new Intent(Intent.ACTION_SEND); i.setType("text/plain"); i.putExtra(Intent.EXTRA_EMAIL, new String[] { "[email protected]"}); /*i.putExtra(Intent.EXTRA_CC, new String[] { "[email protected]" });*/ i.putExtra(Intent.EXTRA_SUBJECT, "Android Test"); i.putExtra(Intent.EXTRA_TEXT, "Body"); //i.putExtra(Intent.EXTRA_TEXT, "signature"); try { startActivity(Intent.createChooser(i, "Choose mail app...")); } catch (android.content.ActivityNotFoundException ex) { } } }); }

    Read the article

  • Reset after using a link with parameters

    - by CarolinaJay65
    I am using the window.location.search parameters (www.mysite.com?page=1) to direct the user to a specific page within the site. However, since those parameters are still in window.location (the browser) reset button continues to re-direct to the same page. I would like the reset button to re-direct to www.mysite.com How do I clear the .search parameters so the (browser) reset button re-directs where I want? Is it done after the page is loaded? or after the (browser) reset button has been clicked?

    Read the article

  • PHP - How to retrieve session in php

    - by Klaus Jasper
    I created a table that contains id - names - jobs and page that shows the names only and beside each name there is button Job and session that contains the id. this is my code $query = mysql_query("SELECT * FROM table"); while($fetch = mysql_fetch_array("$query")){ $name = $fetch['names']; $id = $fetch['id']; echo '</br>'; echo $name; $_SESSION['name'] = $id; echo "<button>Job</button>"; } I want when the user click on button Job redirect to a page that contains the job of that session. so how can I do it?

    Read the article

  • left click + hold = add checkbox

    - by Reigel
    html <button>a</button> <div class="headerer"> <p>visit <a href="http://reigel-codes.co.cc">reigel-codes.co.cc</a></p> </div> problem how can I add anchors checkbox after <button by pressing and hold left click ?.. then stop adding when left click is release... I have tried so far, $(document).ready(function(){ $('button').mousedown(function(){ $(this).after('<input type="checkbox">') }); })

    Read the article

  • How to change a sub layout dynamically

    - by user1762121
    I am newbie in android, but I want to change the contents of a layout, that is inside another layout, due to clicks on buttons. ----------------------------- | Button | Button | Button | ----------------------------- | | | Layout that changes | | dynamically | | | | | ------------------------------ Thanks

    Read the article

  • How to overwrite a convenience constructor the proper way?

    - by mystify
    For example I want to overwrite from UIButton: + (id)buttonWithType:(UIButtonType)buttonType So I would do: + (id)buttonWithType:(UIButtonType)buttonType { UIButton *button = [UIButton buttonWithType:buttonType]; if (button != nil) { // do own config stuff ... } return button; } is that the right way? Or did I miss something? (yeah, I have been overwriting thousands of instance methods, but never class methods ;) )

    Read the article

< Previous Page | 140 141 142 143 144 145 146 147 148 149 150 151  | Next Page >