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  • What is the best way to handle the Connections to MySql from c#

    - by srk
    I am working on a c# application which connects to MySql server. There are about 20 functions which will connect to database. This application will be deployed in 200 over machines. I am using the below code to connect to my database which is identical for all the functions. The problem is, i can some connections were not closed and still alive when deployed in 200 over machines. Connection String : <add key="Con_Admin" value="server=test-dbserver; database=test_admindb; uid=admin; password=1Password; Use Procedure Bodies=false;" /> Declaration of the connection string Globally in application [Global.cs] : public static MySqlConnection myConn_Instructor = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); Function to query database : public static DataSet CheckLogin_Instructor(string UserName, string Password) { DataSet dsValue = new DataSet(); //MySqlConnection myConn = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); try { string Query = "SELECT accounts.str_nric AS Nric, accounts.str_password AS `Password`," + " FROM accounts " + " WHERE accounts.str_nric = '" + UserName + "' AND accounts.str_password = '" + Password + "\'"; MySqlCommand cmd = new MySqlCommand(Query, Global.myConn_Instructor); MySqlDataAdapter da = new MySqlDataAdapter(); if (Global.myConn_Instructor.State == ConnectionState.Closed) { Global.myConn_Instructor.Open(); } cmd.ExecuteScalar(); da.SelectCommand = cmd; da.Fill(dsValue); Global.myConn_Instructor.Close(); } catch (Exception ex) { Global.myConn_Instructor.Close(); ExceptionHandler.writeToLogFile(System.Environment.NewLine + "Target : " + ex.TargetSite.ToString() + System.Environment.NewLine + "Message : " + ex.Message.ToString() + System.Environment.NewLine + "Stack : " + ex.StackTrace.ToString()); } return dsValue; }

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  • Can't diagnose my MySQL root user problem

    - by George Crawford
    Hi all, I have a problem with the MySQL root user in My MySQL setup, and I just can't for the life of me work out how to fix it. It seems that I have somehow messed up the root user, and my access to databases is now very erratic. For reference, I'm using MAMP on OS X to provide the MySQL server. I'm not sure how much that matters though - I'd guess that whatever I've done will require a command-line fix to solve it. I can start MySQL using MAMP as usual, and access databases using the 'standard' users I have created for my PHP apps. However, the root user, which I use in my MySQL GUI client, and also in phpMyAdmin, can only access the "information_schema" database, as well as two I have created manually, and presumably (and mistakenly) left permissions wide open for. My 15 or so other databases cannot be accessed my the root user. When I load up phpMyAdmin, the home screen says: "Create new database: No Privileges". I certainly did at some stage change my root user's password using the MAMP dialog. But I don't remember if I did anything else which might have caused this problem. I've tried changing the password again, and there seems to be no change in the issue. I've also tried resetting root password using the command line, including starting mysql manually with --skip-grant-tables then flushing privs, but again, nothing seems to fix the issue. I've come to the end of my ideas, and would very much appreciate some step-by-step advice and diagnosis from one of the experts here! Many thanks for your help.

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  • Insert Stored Procedure does not Create Database Record

    - by SidC
    Hello All, I have the following stored procedure: ALTER PROCEDURE Pro_members_Insert @id int outPut, @LoginName nvarchar(50), @Password nvarchar(15), @FirstName nvarchar(100), @LastName nvarchar(100), @signupDate smalldatetime, @Company nvarchar(100), @Phone nvarchar(50), @Email nvarchar(150), @Address nvarchar(255), @PostalCode nvarchar(10), @State_Province nvarchar(100), @City nvarchar(50), @countryCode nvarchar(4), @active bit, @activationCode nvarchar(50) AS declare @usName as varchar(50) set @usName='' select @usName=isnull(LoginName,'') from members where LoginName=@LoginName if @usName <> '' begin set @ID=-3 RAISERROR('User Already exist.', 16, 1) return end set @usName='' select @usName=isnull(email,'') from members where Email=@Email if @usName <> '' begin set @ID=-4 RAISERROR('Email Already exist.', 16, 1) return end declare @MemID as int select @memID=isnull(max(ID),0)+1 from members INSERT INTO members ( id, LoginName, Password, FirstName, LastName, signupDate, Company, Phone, Email, Address, PostalCode, State_Province, City, countryCode, active,activationCode) VALUES ( @Memid, @LoginName, @Password, @FirstName, @LastName, @signupDate, @Company, @Phone, @Email, @Address, @PostalCode, @State_Province, @City, @countryCode, @active,@activationCode) if @@error <> 0 set @ID=-1 else set @id=@memID Note that I've "inherited" this sproc and the database. I am trying to insert a new record from my signup.aspx page. My SQLDataSource is as follows: <asp:SqlDataSource runat="server" ID="dsAddMember" ConnectionString="rmsdbuser" InsertCommandType="StoredProcedure" InsertCommand="Pro_members_Insert" ProviderName="System.Data.SqlClient"> The click handler for btnSave is as follows: Protected Sub btnSave_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btnSave.Click Try dsAddMember.DataBind() Catch ex As Exception End Try End Sub When I run this page, signup.aspx, provide required fields and click submit, the page simply reloads and the database table does not reflect the newly-inserted record. Questions: 1. How do I catch the error messages that might be returned from the sproc? 2. Please advise how to change signup.aspx so that the insert occurs. Thanks, Sid

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  • Integrate OpenId into an existing site

    - by Andrea
    I have a working web application which already has a login and registration system. I'm looking for some advice on how to do it. Until now, users have a username, an email, a password and some optional fields. The registrartion is the usual process with email confirmation. Now I'd like to allow users to use OpenId. So I have added an openid field to the table. There are two different login forms, and users which are already registered can add their openid info and use either login form. The problem is with new users who come on the site for the first time and try to login with OpenId. I create a new user for them, and I don't need a password, but still I need at least a username, which is used on the site (I'm not sure if the email is needed). So my problems are: 1) How do I manage validation? Some fields are required for some users, (e.g. a password) but not for some others. I mean, I can do this, but it immediately gets messy. 2) Should I ask for a username and email on the first OpenId login? On the one hand I'd say yes, but I fear this vanishes the advantages of using OpenId, that is, not having to provide details. 3) I could get the details via SReg or AttributeExchange, but most providers have a bad support for those. For instance my Gmail OpenId account does not tell the email (!). Is there some place to learn more about the current support for these extensions?

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  • Providing custom database functionality to custom asp.net membership provider

    - by IrfanRaza
    Hello friends, I am creating custom membership provider for my asp.net application. I have also created a separate class "DBConnect" that provides database functionality such as Executing SQL statement, Executing SPs, Executing SPs or Query and returning SqlDataReader and so on... I have created instance of DBConnect class within Session_Start of Global.asax and stored to a session. Later using a static class I am providing the database functionality throughout the application using the same single session. In short I am providing a single point for all database operations from any asp.net page. I know that i can write my own code to connect/disconnect database and execute SPs within from the methods i need to override. Please look at the code below - public class SGI_MembershipProvider : MembershipProvider { ...... public override bool ChangePassword(string username, string oldPassword, string newPassword) { if (!ValidateUser(username, oldPassword)) return false; ValidatePasswordEventArgs args = new ValidatePasswordEventArgs(username, newPassword, true); OnValidatingPassword(args); if (args.Cancel) { if (args.FailureInformation != null) { throw args.FailureInformation; } else { throw new Exception("Change password canceled due to new password validation failure."); } } ..... //Database connectivity and code execution to change password. } .... } MY PROBLEM - Now what i need is to execute the database part within all these overriden methods from the same database point as described on the top. That is i have to pass the instance of DBConnect existing in the session to this class, so that i can access the methods. Could anyone provide solution on this. There might be some better techniques i am not aware of that. The approach i am using might be wrong. Your suggessions are always welcome. Thanks for sharing your valuable time.

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  • How to link different Servlet together?

    - by Harry Pham
    First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

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  • INSERT data from Textbox to Postgres SQL

    - by user1479013
    I just learn how to connect C# and PostgresSQL. I want to INSERT data from tb1(Textbox) and tb2 to database. But I don't know how to code My previous code is SELECT from database. this is my code private void button1_Click(object sender, EventArgs e) { bool blnfound = false; NpgsqlConnection conn = new NpgsqlConnection("Server=127.0.0.1;Port=5432;User Id=postgres;Password=admin123;Database=Login"); conn.Open(); NpgsqlCommand cmd = new NpgsqlCommand("SELECT * FROM login WHERE name='" + tb1.Text + "' and password = '" + tb2.Text + "'",conn); NpgsqlDataReader dr = cmd.ExecuteReader(); if (dr.Read()) { blnfound = true; Form2 f5 = new Form2(); f5.Show(); this.Hide(); } if (blnfound == false) { MessageBox.Show("Name or password is incorrect", "Message Box", MessageBoxButtons.OK, MessageBoxIcon.Exclamation, MessageBoxDefaultButton.Button1); dr.Close(); conn.Close(); } } So please help me the code.

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  • Inserting default "admin" user into database during Rails App startup

    - by gbc
    I'm building my first real rails application for a little in-house task. Most of the application tasks require authentication/authorization. The first time the app starts up (or starts with a wiped db), I'd like the process to be: User logs into the admin panel using "admin" & "admin" for authentication info. User navigates to admin credentials editing page and changes name and password to something safer so that "admin" & "admin" is no longer a valid login. To achieve this result, I'd like to stuff a default username & password combination into the database on if the application starts up and detects that there are no user credentials in the 'users' table. For example: if User.count == 0 User.create(:name => "admin", :password => "admin") end However, I'm unsure where to place that code. I tried adding an initializer script in the config/initializers, but the error I received appeared to indicate that the model classes weren't yet loaded into the application. So I'm curious to know at what point I can hook into the application startup cycle and insert data into the database through ActiveRecord before requests are dispatched.

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  • starting rails in test environment

    - by Brian D.
    I'm trying to load up rails in the test environment using a ruby script. I've tried googling a bit and found this recommendation: require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' This seems to load up my environment alright, but my development database is still being used. Am I doing something wrong? Here is my database.yml file... however I don't think it is the issue development: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_development pool: 5 username: root password: dev host: localhost # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_test pool: 5 username: root password: dev host: localhost production: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_production pool: 5 username: root password: dev host: localhost I can't use ruby script/server -e test because I'm trying to run ruby code after I load rails. More specifically what I'm trying to do is: run a .sql database script, load up rails and then run automated tests. Everything seems to be working fine, but for whatever reason rails seems to be loading in the development environment instead of the test environment. Here is a shortened version of the code I am trying to run: system "execute mysql script here" require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' describe Blog do it "should be initialized successfully" do blog = Blog.new end end I don't need to start a server, I just need to load my rails code base (models, controllers, etc..) so I can run tests against my code. Thanks for any help.

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  • Send file FTP over SSL with custom port number

    - by JM4
    I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

    - by Mumin Ali
    Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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  • Twitter Favorites and more than 20

    - by danit
    Im using curl to fetch my Twitter favorites: <?php $username = "bob"; $password = "password"; $twitterHost = "http://twitter.com/favorites.xml"; $curl; $curl = curl_init(); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, 2); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl, CURLOPT_USERPWD, "$username:$password"); curl_setopt($curl, CURLOPT_HTTP_VERSION, CURL_HTTP_VERSION_1_1); curl_setopt($curl, CURLOPT_URL, $twitterHost); $result = curl_exec($curl); curl_close($curl); header('Content-Type: application/xml; charset=ISO-8859-1'); print $result; ?> However this only fetches the last 20 favorites, not all of them. If i amend this line: $twitterHost = "http://twitter.com/favorites.xml"; And change it to: $twitterHost = "http://twitter.com/favorites.xml?page=2"; I can get the next set of 20 favorites. There doesnt appear to be anyway, using the Twitter API, to find out how many pages of favorites there are. As such can anyone suggest the best way to get all favorites? Or if this is not possible, get all the Tweets for a date range?

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  • URL-Encoded post parameters don't Bind to model

    - by Steven Klein
    I have the following Model namespace ClientAPI.Models { public class Internal { public class ReportRequest { public DateTime StartTime; public DateTime EndTime; public string FileName; public string UserName; public string Password; } } } with the following method: [HttpPost] public HttpResponseMessage GetQuickbooksOFXService(Internal.ReportRequest Request){ return GetQuickbooksOFXService(Request.UserName, Request.Password, Request.StartTime, Request.EndTime, Request.FileName); } My webform looks like this: <form method="POST" action="http://localhost:56772/Internal/GetQuickbooksOFXService" target="_blank"> <input type="text" name="StartTime" value="2013-04-03T00:00:00"> <input type="text" name="EndTime" value="2013-05-04T00:00:00"> <input type="text" name="FileName" value="Export_2013-04-03_to_2013-05-03.qbo"> <input type="text" name="UserName" value="UserName"> <input type="text" name="Password" value="*****"> <input type="submit" value="Submit"></form> My question is: I get into the GetQuickbooksOFXService function but my model has all nulls in it instead something useful. Am I doing something wrong?

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  • How can I debug PEAR auth?

    - by croceldon
    I have a directory on my site that I've implemented PEAR's Auth to run my authentication. It is working great. However, I've tried to make a copy of my site (it's going to be translated to a different language), and on this new site, the Auth process doesn't seem to be working correctly. I can login properly, but every time I try to go to a different page in the same directory, and use Auth to authorize, it forces me to login again. Here's my logic: $auth_options = array( 'dsn' => mysql://user:password@server/db', 'table' => 'users', 'usernamecol' => 'username', 'passwordcol' => 'password', 'db_fields' => '*' ); $auth = new Auth("DB", $auth_options, "login_function"); $auth->setFailedLoginCallback('bad_login'); $auth->start(); if (!$auth->checkAuth()) { die('cannot succeed in checkAuth') exit; } else { include("nocache.php"); } This is part of a file that's included in every php page I that I desire to require authentication. I can login properly once, but whenever I then try to go to a different page that requires authentication, it makes me login again (and I see the 'cannot succeed' die message at the bottom of the page). Again, this solution works fine on my original site, I copied all the files, and only changed the db server/password - it still doesn't work. And I'm using the same webhost for both. What am I doing wrong here? Or how can I debug this further?

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  • trouble connecting to MySql DB (PHP)

    - by user332817
    Hi I have the following PHP code to connect to my db. <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); ?> however I get the following error: Warning: mysql_connect() [function.mysql-connect]: [2002] A connection attempt failed because the connected party did not (trying to connect via tcp://localhost:3306) in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Fatal error: Maximum execution time of 30 seconds exceeded in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 I am able to add a db/tables via phpmyadmin but I cant connect using php. here is a screenshot of my phpmyadmin page: http://img294.imageshack.us/img294/1589/sqls.jpg any help would be appreciated, thanks in advance.

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  • PHP Check slave status without mysql_connect timeout issues

    - by Jonathon
    I have a web-app that has a master mysql db and four slave dbs. I want to handle all (or almost all) read-only (SELECT) queries from the slaves. Our load-balancer sends the user to one of the slave machines automatically, since they are also running Apache/PHP and serving webpages. I am using an include file to setup the connection to the databases, such as: //for master server (i.e. - UPDATE/INSERT/DELETE statements) $Host = "10.0.0.x"; $User = "xx"; $Password = "xx"; $Link = mysql_connect( $Host, $User, $Password ); if( !$Link ) ) { die( "Master database is currently unavailable. Please try again later." ); } //this connection can be used for READ-ONLY (i.e. - SELECT statements) on the localhost $Host_Local = "localhost"; $User_Local = "xx"; $Password_Local = "xx"; $Link_Local = mysql_connect( $Host_Local, $User_Local, $Password_Local ); //fail back to master if slave db is down if( !$Link_Local ) ) { $Link_Local = mysql_connect( $Host, $User, $Password ); } I then use $Link for all update queries and $Link_Local as the connection for SELECT statements. Everything works fine until the slave server database goes down. If the local db is down, the $Link_Local = mysql_connect() call takes at least 30 seconds before it gives up on trying to connect to the localhost and returns back to the script. This causes a huge backlog of page serves and basically shuts down the system (due to the extremely slow response time). Does anyone know of a better way to handle connections to slave servers via PHP? Or, is there some kind of timeout function that could be used to stop the mysql_connect call after 2-3 seconds? Thanks for the help. I searched the other mysql_connect threads, but didn't see any that addressed this issue.

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  • Bing search API and Azure

    - by Gapton
    I am trying to programatically perform a search on Microsoft Bing search engine. Here is my understanding: There was a Bing Search API 2.0 , which will be replaced soon (1st Aug 2012) The new API is known as Windows Azure Marketplace. You use different URL for the two. In the old API (Bing Search API 2.0), you specify a key (Application ID) in the URL, and such key will be used to authenticate the request. As long as you have the key as a parameter in the URL, you can obtain the results. In the new API (Windows Azure Marketplace), you do NOT include the key (Account Key) in the URL. Instead, you put in a query URL, then the server will ask for your credentials. When using a browser, there will be a pop-up asking for a/c name and password. Instruction was to leave the account name blank and insert your key in the password field. Okay, I have done all that and I can see a JSON-formatted results of my search on my browser page. How do I do this programmatically in PHP? I tried searching for the documentation and sample code from Microsoft MSDN library, but I was either searching in the wrong place, or there are extremely limited resources in there. Would anyone be able to tell me how do you do the "enter the key in the password field in the pop-up" part in PHP please? Thanks alot in advance.

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  • How can I test a form that requires the entry of two random characters from a security phrase?

    - by lawm
    I need to test a two-stage login system which first asks for your email address and password and then presents the user with two select lists containing [a-zA-Z0-9]. The labels beside the drop down's are of the form 'Select character X from your security phrase', where X is a random character index from a known security phrase. I'd rather not stub the code for an acceptance test, so is it possible to write a matcher in cucumber which will, given that we know the whole phrase, select the required character in each of the two lists? Here is the scenario I have so far and the steps involved: Scenario: valid login email, password and secret phrase takes me to the dashboard Given I am not logged in When I log in as "[email protected]" Then I should be on the dashboard page And I should see "Your Dashboard" When /^I log in as "([^\"]*)"$/ do |login| visit path_to('Login page') fill_in "Email", :with => login fill_in "Password", :with => "Password123" click_button "Log in" response.should contain("Please verify some characters from your security phrase") select "a", :from => "Select character X of your security phrase" select "b", :from => "Select character Y of your security phrase" click_button "Submit" end For example, if the security phrase is 'Secret123', X = 3 and Y = 8, the above would have to produce the equivalent of: select "c", :from => "Select character 3 of your security phrase" select "2", :from => "Select character 8 of your security phrase" The numbers X and Y in the actual page are inside span#svc_1 and span#svc_2 respectively. Thanks,

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  • (Android) Seems like my JSON query is getting double encode

    - by A Gardner
    Hi, I am getting some weird errors with my Android App. It appears that this code is double encoding the JSON string. What should be sent is ?{"email":"[email protected]","password":"asdf"} or ?%7B%22email%22:%22..... what the server is seeing is %257B%2522email%2522:%2522 .... which means the server sees %7B%22email%22:%22 ..... This confuses the server. Any ideas why this is happening? Thanks for your help Code: DefaultHttpClient c = new DefaultHttpClient(); if(cookies!=null) c.setCookieStore(cookies); if(loginNotLogout){ jso.put("email", userData.email); jso.put("password", userData.password); } URI u = null; if(loginNotLogout) u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); else u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); HttpGet httpget = new HttpGet(u); HttpResponse response = c.execute(httpget); ret.jsonString = EntityUtils.toString(response.getEntity());

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  • [Ruby on Rails] complex model relationship

    - by siulamvictor
    I am not sure am I doing these correct. I have 3 models, Account, User, and Event. Account contains a group of Users. Each User have its own username and password for login, but they can access the same Account data under the same Account. Events is create by a User, which other Users in the same Account can also read or edit it. I created the following migrations and models. User migration class CreateUsers < ActiveRecord::Migration def self.up create_table :users do |t| t.integer :account_id t.string :username t.string :password t.timestamps end end def self.down drop_table :users end end Account migration class CreateAccounts < ActiveRecord::Migration def self.up create_table :accounts do |t| t.string :name t.timestamps end end def self.down drop_table :accounts end end Event migration class CreateEvents < ActiveRecord::Migration def self.up create_table :events do |t| t.integer :account_id t.integer :user_id t.string :name t.string :location t.timestamps end end def self.down drop_table :events end end Account model class Account < ActiveRecord::Base has_many :users has_many :events end User model class User < ActiveRecord::Base belongs_to :account end Event model class Event < ActiveRecord::Base belongs_to :account belongs_to :user end so.... Is this setting correct? Every time when a user create a new account, the system will as for the user information, i.e. username and password. How can I add them into correct tables? How can I add a new event? I am sorry for such a long question. I am not very understand the rails way in handling such data structure. Thank you guys for answering me. :)

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  • I need Selenium to open it's web browser in a larger resolution ( preferably maximized)

    - by user1854271
    I am using Selenium WebDriver and coding in Python I have looked all over the place and the best I could find were things written in different languages. I also tried to use the export tool on Selenium IDE but when I look at the data says that the function is not supported for export. EDIT: The reason I need the browser to open up with a larger resolution is because the web application that I am testing is supporting tablet resolution as so elements are different depending on the resolution of the browser window. This is the script I exported from the IDE with a couple of modifications. from selenium import webdriver from selenium.webdriver.common.by import By from selenium.webdriver.support.ui import Select from selenium.common.exceptions import NoSuchElementException import unittest, time, re from Funk_Lib import RS class CreatingEditingDeletingVault(unittest.TestCase): def setUp(self): self.driver = webdriver.Firefox() self.driver.implicitly_wait(30) self.base_url = "http://cimdev-qa40/" self.verificationErrors = [] def test_creating_editing_deleting_vault(self): driver = self.driver driver.get(self.base_url + "/Login?contoller=Home") driver.find_element_by_id("UserName").click() driver.find_element_by_id("UserName").clear() driver.find_element_by_id("UserName").send_keys("[email protected]") driver.find_element_by_name("Password").click() driver.find_element_by_name("Password").clear() driver.find_element_by_name("Password").send_keys("Codigo#123") driver.find_element_by_id("fat-btn").click() driver.get(self.base_url + "/Content/Vaults/") driver.find_element_by_link_text("Content").click() driver.find_element_by_link_text("Vaults").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("New vault").click() driver.find_element_by_name("Name").clear() driver.find_element_by_name("Name").send_keys("Test Vault") driver.find_element_by_xpath("//button[@onclick=\"vault_action('createvault', null, $('#CreateVault [name=\\'Name\\']').val())\"]").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("Rename vault").click() driver.find_element_by_name("Id").click() Select(driver.find_element_by_name("Id")).select_by_visible_text("Test Vault") driver.find_element_by_css_selector("option[value=\"2\"]").click() driver.find_element_by_name("Name").clear() driver.find_element_by_name("Name").send_keys("Test Change") driver.find_element_by_xpath("//button[@onclick=\"vault_action('renamevault', $('#RenameVault [name=\\'Id\\']').val(), $('#RenameVault [name=\\'Name\\']').val())\"]").click() driver.find_element_by_css_selector("button.btn.dropdown-toggle").click() driver.find_element_by_link_text("Delete vault").click() driver.find_element_by_name("Id").click() Select(driver.find_element_by_name("Id")).select_by_visible_text("Test Change") driver.find_element_by_css_selector("option[value=\"2\"]").click() driver.find_element_by_xpath("//button[@onclick=\"vault_action('deletevault', $('#DeleteVault [name=\\'Id\\']').val(), '')\"]").click() def is_element_present(self, how, what): try: self.driver.find_element(by=how, value=what) except NoSuchElementException, e: return False return True def tearDown(self): self.driver.quit() self.assertEqual([], self.verificationErrors) if __name__ == "__main__": unittest.main()

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  • Javascript XMLHttpRequest Post method

    - by user535617
    Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

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  • Login form validation using javascript and php

    - by ipl
    Hi, I have been trying to create a login form using javascript.My login form needs to do the fllowing using javascript validation 1.login field contains only letters with a minimum of 4 and a maximum of 6 letters 2.password is at least 5 characters long and not more than 7 characters and contains only letters and digits with at least 1 letter and at least 1 digit 3.if the data is incorrect, generate an alert window with an appropriate message and set the cursor to the incorrect input field and the form needs to be submitted to a php file which needs to validate against a text file I tried to use regular expression to check for the login fiels and password in the javascript and i have used a login .php but havent done anything in that till now.However my javascript/html file which i have pasted below doesnt seem to work.Can anyone tell me the issue with my file? Rgds ip function validateFormOnSubmit(theForm) { reason += validateUsername(theForm.username.value) reason += validatePassword (theForm.pwd.value) if (reason == "") return true else { alert(reason); return false } } function validateUsername(fld) { if (fld == "") return "No username entered" else if((fld.length 6) || (fld.length 7 ) { return "length shoild be b/w 4 and 7"; } else if (!/[a-z]/.test(fld) || !/[A-Z]/.test(fld) || !/[0-9]/.test(fld)){ return "passwords rewuire one of the letters or digitys"; } } SignupForm Your user name: Your Password:    

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