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  • Injecting Dependencies into Domain Model classes with Nhibernate (ASP.NET MVC + IOC)

    - by Sunday Ironfoot
    I'm building an ASP.NET MVC application that uses a DDD (Domain Driven Design) approach with database access handled by NHibernate. I have domain model class (Administrator) that I want to inject a dependency into via an IOC Container such as Castle Windsor, something like this: public class Administrator { public virtual int Id { get; set; } //.. snip ..// public virtual string HashedPassword { get; protected set; } public void SetPassword(string plainTextPassword) { IHashingService hasher = IocContainer.Resolve<IHashingService>(); this.HashedPassword = hasher.Hash(plainTextPassword); } } I basically want to inject IHashingService for the SetPassword method without calling the IOC Container directly (because this is suppose to be an IOC Anti-pattern). But I'm not sure how to go about doing it. My Administrator object either gets instantiated via new Administrator(); or it gets loaded via NHibernate, so how would I inject the IHashingService into the Administrator class? On second thoughts, am I going about this the right way? I was hoping to avoid having my codebase littered with... currentAdmin.Password = HashUtils.Hash(password, Algorithm.Sha512); ...and instead get the domain model itself to take care of hashing and neatly encapsulate it away. I can envisage another developer accidently choosing the wrong algorithm and having some passwords as Sha512, and some as MD5, some with one salt, and some with a different salt etc. etc. Instead if developers are writing... currentAdmin.SetPassword(password); ...then that would hide those details away and take care of those problems listed above would it not?

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  • Access denied when trying to access my database.

    - by Sergio Tapia
    Here's my code: <html> <head> </head> <body> <?php $user = mysql_real_escape_string($_GET["u"]); $pass = mysql_real_escape_string($_GET["p"]); $query = "SELECT * FROM usario WHERE username = '$user' AND password = '$pass'"; mysql_connect(localhost, "root", ""); @mysql_select_db("multas") or die( "Unable to select database"); $result=mysql_query($query); if(mysql_numrows($result) > 0){ echo 'si'; } ?> </body> </html> And here's the error I get when I try to run it Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\useraccess.php on line 16

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  • Getting 404 page not found connecting to webDAV

    - by Cragly
    I am trying to connect to a secure webDAV folder and download a file. I am having problems just trying to get a response from the server and as it keeps giving me a 404 page not found error as soon as I call Request.GetResponse(). I can connect to the webDAV folder using Windows Explorer by mapping a drive but cannot seem to do this in code. I have looked at other post on this site and others online but most seem to concentrate on connecting to Outlook. Has anybody else had this issue? The code I am using is as follows: string URI = "https://transfer.mycompany.com/myDirectory/myFile.csv"; string username = "username"; string password = "password"; Request = (HttpWebRequest) WebRequest.Create(URI); Request.Credentials = new NetworkCredential(username, password); Request.Method = WebRequestMethods.Http.Get; Request.Headers.Add("Translate", "f"); Response = (HttpWebResponse) Request.GetResponse(); contentLength = Convert.ToInt64(Response.GetResponseHeader("Content-Length"));

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  • How can I see which shared folders my program has access to?

    - by Kasper Hansen
    My program needs to read and write to folders on other machines that might be in another domain. So I used the System.Runtime.InteropServices to add shared folders. This worked fine when it was hard coded in the main menu of my windows service. But since then something went wrong and I don't know if it is a coding error or configuration error. What is the scope of a shared folder? If a thread in my program adds a shared folder, can the entire local machine see it? Is there a way to view what shared folders has been added? Or is there a way to see when a folder is added? [DllImport("NetApi32.dll", SetLastError = true, CharSet = CharSet.Unicode)] internal static extern System.UInt32 NetUseAdd(string UncServerName, int Level, ref USE_INFO_2 Buf, out uint ParmError); [StructLayout(LayoutKind.Sequential, CharSet = CharSet.Unicode)] internal struct USE_INFO_2 { internal LPWSTR ui2_local; internal LPWSTR ui2_remote; internal LPWSTR ui2_password; internal DWORD ui2_status; internal DWORD ui2_asg_type; internal DWORD ui2_refcount; internal DWORD ui2_usecount; internal LPWSTR ui2_username; internal LPWSTR ui2_domainname; } private void AddSharedFolder(string name, string domain, string username, string password) { if (name == null || domain == null || username == null || password == null) return; USE_INFO_2 useInfo = new USE_INFO_2(); useInfo.ui2_remote = name; useInfo.ui2_password = password; useInfo.ui2_asg_type = 0; //disk drive useInfo.ui2_usecount = 1; useInfo.ui2_username = username; useInfo.ui2_domainname = domain; uint paramErrorIndex; uint returnCode = NetUseAdd(String.Empty, 2, ref useInfo, out paramErrorIndex); if (returnCode != 0) { throw new Win32Exception((int)returnCode); } }

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  • Sample twitter application

    - by Jack
    I have installed WAMP and running PHP scripts on localhost. I have enabled cURL. Here is my code. <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> Here's my output Operation completed without any errors Error: 404 Here's what error 404 means 404 Not Found: The URI requested is invalid or the resource requested, such as a user, does not exists. Please help.

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  • Getting 404 Not Found connecting to webDAV

    - by Cragly
    I am trying to connect to a secure webDAV folder and download a file. I am having problems just trying to get a response from the server and as it keeps giving me a 404 Not Found error as soon as I call Request.GetResponse(). I can connect to the webDAV folder using Windows Explorer by mapping a drive but cannot seem to do this in code. I have looked at other post on this site and others online but most seem to concentrate on connecting to Outlook. Has anybody else had this issue? The code I am using is as follows: string URI = "https://transfer.mycompany.com/myDirectory/myFile.csv"; string username = "username"; string password = "password"; Request = (HttpWebRequest) WebRequest.Create(URI); Request.Credentials = new NetworkCredential(username, password); Request.Method = WebRequestMethods.Http.Get; Request.Headers.Add("Translate", "f"); Response = (HttpWebResponse) Request.GetResponse(); contentLength = Convert.ToInt64(Response.GetResponseHeader("Content-Length"));

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  • Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....

    - by user309381
    **mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56 The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) i have set the password for root and grant privilege all for root.Why it soes show like SYSTEM@localhost i dont have SYSTEM .** class MySQLDatabase { public $connection; function _construct() { $this-open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this-connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this-connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this-connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query($sql) { //$sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //$found_user = mysql_fetch_assoc($result); //echo $found_user; return $found_user; } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); ?

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  • Ant telnet is hanging on a simple task

    - by Sagar
    <?xml version="1.0" ?> <project name="test" default="root"> <target name="telnet"> <telnet server="10.1.1.1"> <read>login:</read> <write>root</write> <read>password:</read> <write>${PASSWORD}</write> <read>#</read> <write>ls</write> <read>#</read> </telnet> </target> </project> That is the code I have in a build.xml file. When I run ant (version 1.8, in bash) (I have downloaded and copied over the jars for commons-net-2.0 and jakarta-oro-2.0.8 already), this is the output I get: Buildfile: /home/sagar/build.xml telnet: and then it just sits there. When I do a "who" on my server, I can see "System" waiting on login. But there is no progress after this. I can telnet into the server using normal telnet means (putty, bash, etc). I even tried the full telnet command instead of read/write: <telnet server="10.1.1.1" userid="root" password="root"> Any help is much appreciated! Note: JRE 1.5, Ant 1.8, commons-net version 2.0, jakarta version 2.0.8

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  • PropertyPlaceholderConfigurer vs Filters -- Spring Beans

    - by John
    Hi there. I've got a question regarding the difference between PropertyPlaceholderConfigurer (org.springframework.beans.factory.config.PropertyPlaceholderConfigurer) and normal filters defined in my pom.xml. I've been looking at examples, and it seems that even though filters are defined and marked to be active by default in the pom.xml they still make use of PropertyPlaceholderConfigurer in Spring's applicationContext.xml. This means that the pom.xml has a reference to a filter-LOCAL.properties while applicationContext.xml has a reference to application.properties and they both contain the same settings. Why is that? Is that how it is supposed to be done? I'm able to run the goal mvn jetty:run without the application.properties present, but if I add settings to the application.properties that differ from the filter-LOCAL.properties they don't seem to override. Here's an example of what I mean: pom.xml <profiles <profile <idLOCAL <activation <activeByDefaulttrue </activation <properties <envLOCAL </properties </profile </profiles applicationContext.xml <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" <property name="locations" <list <valueclasspath:application.properties </list </property <property name="ignoreResourceNotFound" value="true"/ </bean <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" <property name="driverClassName" value="${jdbc.driver}"/ <property name="url" value="${jdbc.url}"/ <property name="username" value="${jdbc.username}"/ <property name="password" value="${jdbc.password}"/ </bean an example of the content of application.properties and filters-LOCAL.properties jdbc.driver=org.postgresql.Driver jdbc.url=jdbc:postgresql://localhost/shoutbox_dev jdbc.username=tester jdbc.password=tester Can I remove the propertyConfigurer from the applicationContext, create a PROD filter and disregard the application.properties file, or will that give me issues when deploying to the production server?

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  • Vertically Aligning Divs

    - by Crays
    Hi, i'm trying to make a small username and password input box. I would like to ask how do you vertically align a div? What i have is a <div id="Login" class="BlackStrip floatright"> <div id="Username" class="floatleft">Username<br>Password</div> <div id="Form" class="floatleft"> <form action="" method="post"> <input type="text" border="0"><br> <input type="password" border="0"> </form> </div> </div> and how can i make the div with id Username and Form to vertically align itself to the center? I tried putting vertical-align: middle; in css for the div with id Login. But doesn't seem to work. Any help would be appreciated. Thanks.

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  • PDO using singleton stored as class properity

    - by Misiur
    Hi again. OOP drives me crazy. I can't move PDO to work. Here's my DB class: class DB extends PDO { public function &instance($dsn, $username = null, $password = null, $driver_options = array()) { static $instance = null; if($instance === null) { try { $instance = new self($dsn, $username, $password, $driver_options); } catch(PDOException $e) { throw new DBException($e->getMessage()); } } return $instance; } } It's okay when i do something like this: try { $db = new DB(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } But this: try { $db = DB::instance(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } catch(DBException $e) { echo $e->getMessage(); } Does nothing. I mean, even when I use wrong password/username, I don't get any exception. Second thing - I have class which is "heart" of my site: class Core { static private $instance; public $db; public function __construct() { if(!self::$instance) { $this->db = DB::instance(DB_TYPE.':hpost='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS); } return self::$instance; } private function __clone() { } } I've tried to use "new DB" inside class, but this: $r = $core->db->query("SELECT * FROM me_config"); print_r($r->fetch()); Return nothing. $sql = "SELECT * FROM me_config"; print_r($core->db->query($sql)); I get: PDOStatement Object ( [queryString] => SELECT * FROM me_config ) I'm really confused, what am I doing wrong?

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  • Values are not returning from MY SQL database to my java class

    - by sam
    Hi, This is my Query DELIMITER $$ DROP PROCEDURE IF EXISTSdiscoverdb.getuser_info$$ # MySQL returned an empty result set (i.e. zero rows). `CREATE PROCEDURE discoverdb.getuser_info ( IN name VARCHAR(100), IN pass VARCHAR(100) ) BEGIN SELECT * FROM ad_user WHERE sLogin = name AND sPassHash=password(pass); END $$ # MySQL returned an empty result set (i.e. zero rows). DELIMITER ; This is my calling method public Authentication getAuthentication (String username,String password) { //TODO write your implementation code here: Authentication ack = new Authentication(); try{ String simpleProc = "{ call getuser_infosam(?,?)}"; java.sql.CallableStatement cs = con.prepareCall(simpleProc); cs.setString(1, username); cs.setString(2, password); java.sql.ResultSet rs = cs.executeQuery(); while (rs.next()) { System.out.println(rs.getString("sLogin")); System.out.println(rs.getString("sPassHash")); System.out.println(rs.getString("sForename")); System.out.println(rs.getString("sName")); System.out.println(rs.getString("company")); System.out.println(rs.getString("sEmail")); rs.close();} }catch ( Exception e) { e.printStackTrace(); System.out.print(e); } return ack; }

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  • Rails 4, not saving @user.save when registering new user

    - by Yuichi
    When I try to register an user, it does not give me any error but just cannot save the user. I don't have attr_accessible. I'm not sure what I am missing. Please help me. user.rb class User < ActiveRecord::Base has_secure_password validates :email, presence: true, uniqueness: true, format: { with: /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i } validates :password, presence: true, length: {minimum: 6} validates :nickname, presence: true, uniqueness: true end users_controller.rb class UsersController < ApplicationController def new @user = User.new end def create @user = User.new(user_params) # Not saving @user ... if @user.save flash[:success] = "Successfully registered" redirect_to videos_path else flash[:error] = "Cannot create an user, check the input and try again" render :new end end private def user_params params.require(:user).permit(:email, :password, :nickname) end end Log: Processing by UsersController#create as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"x5OqMgarqMFj17dVSuA8tVueg1dncS3YtkCfMzMpOUE=", "user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "nickname"=>"example"}, "commit"=>"Register"} (0.1ms) begin transaction User Exists (0.2ms) SELECT 1 AS one FROM "users" WHERE "users"."email" = '[email protected]' LIMIT 1 User Exists (0.1ms) SELECT 1 AS one FROM "users" WHERE "users"."nickname" = 'example' LIMIT 1 (0.1ms) rollback transaction

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  • [Database] How to model this one-to-one relation?

    - by pbean
    I have several entities which respresent different types of users who need to be able to log in to a particular system. Additionally, they have different types of information associated with them. For example: a "general user", which has an e-mail address and "admin user", which has a workstation number (note that this a hypothetical case). Both entities also share common properties like first name, surname, address and telephone number. Finally, they naturally need to have a (unique) user name and a password to log in. In the application, the user just has to fill in his user name and password, and the functionality of the application changes slightly according to the type of the user. You can imagine that the username needs to be unique for this work. How should I model this effectively? I can't just create two tables, because then I can't force a unique constaint on the user name. I also can't put them all in just one table, because they have different types of specific information associated to them. I think I might need 3 seperate tables, one for "users" (with user name and password), one for the "general users" and another one for the "admin users", but how would the relations between these work? Or is there another solution? (By the way, the target DBMS is MySQL, so I don't think generalization is supported in the database system itself).

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  • populate checkboxes with database.

    - by amby
    Hi, I have to poulate checkboxes with data coming from database but no checkbox is showing on my page. please give me correct way to do that. in C# file page_load method i m doing this: public partial class dbTest1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { string Server = "al2222"; string Username = "hshshshsh"; string Password = "sjjssjs"; string Database = "database1"; string ConnectionString = "Data Source=" + Server + ";"; ConnectionString += "User ID=" + Username + ";"; ConnectionString += "Password=" + Password + ";"; ConnectionString += "Initial Catalog=" + Database; string query = "Select * from Customer_Order where orderNumber = 17"; using (SqlConnection conn = new SqlConnection(ConnectionString)) { using (SqlCommand cmd = new SqlCommand(query, conn)) { conn.Open(); SqlDataReader dr = cmd.ExecuteReader(); while (dr.Read()) { if (!IsPostBack) { Interests.DataSource = dr; Interests.DataTextField = "OptionName"; Interests.DataValueField = "OptionName"; Interests.DataBind(); } } conn.Close(); conn.Dispose(); } } } } and in .aspx using this: <asp:CheckBoxList ID="Interests" runat="server"></asp:CheckBoxList> please tell me correct way to do that.

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  • ajax login problem

    - by rdanee
    $(document).ready(function() { $("form#login_form").submit(function() { var login_username = $('#login_username').attr('value'); var login_password = $('#login_password').attr('value'); type: "POST", $.ajax({ url: "login.php", data: "username="+ login_username +"& password="+ login_password, success: function(data){ alert(data); if (data == "ok"){ $('form#login_form').hide(function(){$('div.success').fadeIn();}); } } }); return false; }); Login.php: <?php include("settings.php"); $query = "select * from users where username = '{$_POST['login_username']}' and password = md5('{$_POST['login_password']}')"; $query = mysql_query($query, $connection); if ( mysql_num_rows($query) == 1 ) { print "ok"; $array = mysql_fetch_array($query); if ( $_POST['stay'] ) { $time = time()+2592000; } else { $time = 0; } } else { print "no"; } mysql_close($connection); ?> My problem: In the alert the message always "no" whether username/password is correct, however on the site "ok" appears when username/pw is correct. I have read the other questions in connection with this problem, but I couldn't solve the response problem from login.php with Json. Could you help me how should I response to the ajax calling? ( with a code if it is possible) Thank you very much, and sorry for questioning again.

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  • ASP.NET MVC Membership, Get new UserID

    - by Vishal Bharakhda
    I am trying to register a new user and also understand how to get the new userID so i can start creating my own user tables with a userID mapping to the asp.net membership user table. Below is my code: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Register(string userName, string email, string position, string password, string confirmPassword) { ViewData["PasswordLength"] = MembershipService.MinPasswordLength; ViewData["position"] = new SelectList(GetDeveloperPositionList()); if (ValidateRegistration(userName, email, position, password, confirmPassword)) { // Attempt to register the user MembershipCreateStatus createStatus = MembershipService.CreateUser(userName, password, email); if (createStatus == MembershipCreateStatus.Success) { FormsAuth.SignIn(userName, false /* createPersistentCookie */); return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("_FORM", ErrorCodeToString(createStatus)); } } // If we got this far, something failed, redisplay form return View(); } I've done some research and many sites inform me to use Membership.GetUser().ProviderUserKey; but this throws an error as Membership is NULL. I placed this line of code just above "return RedirectToAction("Index", "Home");" within the if statement. Please can someone advise me on this... Thanks in advance

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  • Usage Rails 3.0 beta 3 without ActiveRecord ORM

    - by Anton
    Hi everybody! Just installed Rails 3.0 beta 3 in Windows 7. And started playing with some easy examples class SignupController < ApplicationController def index @user = User.new(params[:user]) if method.post? and @user.save redirect_to :root end end end class User def initialize(params = {}) @email = params[:email] @passw = params[:password] end def save end end <div align="center"> <% form_for :user do |form| %> <%= form.label :email %> <%= form.text_field :email %><br /> <%= form.label :password %> <%= form.text_field :password %><br /> <%= form.submit :Register! %> <% end %> </div> When I go to /signup I'm getting this error ArgumentError in SignupController#index wrong number of arguments(0 for 1) Is there a problem with constructor or what's wrong?Please, need your help!

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • How to implement a Client-side Ajax Login on Asp.Net MVC (A link to the solution for Asp.Net Webform

    - by Matt
    Hi, I'm trying to implement a client-side ajax login on Asp.Net MVC. I used to have this set up just fine on WebForms, but now that I've moved to MVC it's giving me some troubles. If you'd like a tutorial on Client-side Ajax Login for Asp.Net Webforms, it can be found here -- Easy, A++ Now... for some reason it's not working for Asp.Net MVC. I used the exact same tutorial as for the Webforms, except when it executes the ssa.login() (equivalently: Sys.Services.AuthenticationService.login()) it's not doing anything. I have alerts in both the onLoginComplete() function and the onError() function. As well I have an alert before the ssa.login gets called and right after... function loginHandler() { var username = $("#login_UserName").val(); var password = $("#login_Password").val(); var isPersistent = $("#login_RememberMe").attr("checked"); var customInfo = null; var redirectUrl = null; // Log them in. alert("try login"); ssa.login(username, password, isPersistent, customInfo, redirectUrl, onLoginComplete, onError); alert("made it here"); } The first alert fires but the second one doesn't which means the function is failing. Here's the function I pulled from Asp.Net Ajax to show you: function(c, b, a, h, f, d, e, g) { this._invoke(this._get_path(), "Login", false, { userName: c, password: b, createPersistentCookie: a }, Function.createDelegate(this, this._onLoginComplete), Function.createDelegate(this, this._onLoginFailed), [c, b, a, h, f, d, e, g]); } Anyone have any idea of why it's failing?

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  • how to automate the testing of a text based menu

    - by Reagan Penner
    Hi there, I have a text based menu running on a remote Linux host. I am using expect to ssh into this host and would like to figure out how to interact with the menus. Interaction involves arrowing up, down and using the enter and back arrow keys. For example, Disconnect Data Collection > Utilities > Save Changes When you enter the system Disconnect is highlighted. So simply pressing enter twice you can disconnect from the system. Second enter confirms the disconnect. The following code will ssh into my system and bring up the menu. If I remove the expect eof and try to send "\r" thinking that this would select the Disconnect menu option I get the following error: "write() failed to write anything - will sleep(1) and retry..." #!/usr/bin/expect set env(TERM) vt100 set password abc123 set ipaddr 162.116.11.100 set timeout -1 match_max -d 100000 spawn ssh root@$ipaddr exp_internal 1 expect "*password:*" send -- "$password\r" expect "Last login: *\r" expect eof I have looked at the virterm and term_expect examples but cannot figure out how to tweak them to work for me. If someone can point me in the right direction I would greatly appreciate it. What I need to know is can I interact with a text based menu system and what is the correct method for doing this, examples if any exist would be great. thanks, -reagan

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  • Can't use my form

    - by Alexandr
    I have class with my form in folder /application/forms/Auth.php it looks like class Form_Auth extends Zend_Form { public function __construct() { $this->setName(); parent::__construct(); $username = new Zend_Form_Element_Text('username'); $password = new Zend_Form_Element_Password('password'); $mail = new Zend_Form_Element_Text('mail'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username,$password,$mail,$submit)); } } When i try create object $this->view->form = new Form_Auth(); is see exeption Application error Exception information: Message: Invalid name provided; must contain only valid variable characters and be non-empty Stack trace: D:\WWW\zends\application\Forms\Auth.php(8): Zend_Form-setName() d:\WWW\zends\application\controllers\RegistrationController.php(49): Form_Auth-__construct() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Action.php(513): RegistrationController-indexAction() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action-dispatch('indexAction') D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard-dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front-dispatch() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap-run() D:\WWW\zends\public\index.php(26): Zend_Application-run() {main} Request Parameters: array ( 'controller' = 'registration', 'action' = 'index', 'module' = 'default', ) the version zf is 1.10.3 what i do wrong ?

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  • Parameters lost on login form submitted with post in JBoss

    - by Supowski
    My login page contains two forms: one for logging in and one for signing up. Shorten like this: <form name="LoginForm" id="LoginForm" method="post" action="j_security_check" > <input type="text" name="j_username" /> <input type="text" name="j_password" /> <input type="submit" value="Sing In" /> <form> <form name="SignUpForm" id="SignUpForm" method="post" action="/homepage" > <input type="text" name="loginName" /> <input type="password" name="password1" /> <input type="password" name="password2" /> <input type="submit" value="Sing Up" /> <form> I If 'Sing Up', than values of input are lost during processing and not passed into my Servlet. It works fine with GET, but than there is password in URL, so it's not the right solution :) Similar problem has been posted to community.jboss.org, but with no response: http://community.jboss.org/message/7150#7150. I'm using JBoss 4.3eap. Any help?

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  • Resolving the WMI DNS Host Name

    - by Stephen Murby
    I am trying to make a comparison between a machine name i have retrieved from AD, and the DNS Host Name i want to get using WMI from the machine. I currently have: foreach (SearchResult oneMachine in allMachinesCollected) { pcName = oneMachine.Properties["name"][0].ToString(); ConnectionOptions setupConnection = new ConnectionOptions(); setupConnection.Username = USERNAME; setupConnection.Password = PASSWORD; setupConnection.Authority = "ntlmdomain:DOMAIN"; ManagementScope setupScope = new ManagementScope("\\\\" + pcName + "\\root\\cimv2", setupConnection); setupScope.Connect(); ObjectQuery dnsNameQuery = new ObjectQuery("SELECT * FROM Win32_ComputerSystem"); ManagementObjectSearcher dnsNameSearch = new ManagementObjectSearcher(setupScope, dnsNameQuery); ManagementObjectCollection allDNSNames = dnsNameSearch.Get(); string dnsHostName; foreach (ManagementObject oneName in allDNSNames) { dnsHostName = oneName.Properties["DNSHostName"].ToString(); if (dnsHostName == pcName) { shutdownMethods.ShutdownMachine(pcName, USERNAME, PASSWORD); MessageBox.Show(pcName + " has been sent the reboot command"); } } } } But i get a ManagementException dnsHostName = oneName.Properties["DNSHostName"].ToString(); << here saying not found. Any ideas?

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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