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  • How to fix this navigation issue in my site?

    - by David
    First off I use webs.com for the creation of my site. I have a very basic layout. List of links of the left and content on the right with a heading up top. Now in my list of links every link is an article that I wrote, I have about 25 links going down the left hand side of my site. Problem is when I try out new themes that support horizontal navigation as opposed to vertical navigation I get either a messy overflow of links Or a link called "more" which lists the rest of the articles in a drop down-list across my site. What I wish I had was a simple horizontal navigation like" "home, about, articles" and when the user clicks on articles it would then bring them to a page containing all my articles there. I would prefer it to be in a table like display. That way is not a long list. Anyways any ideas on how I can fix this issue im having? Please let me know if you need more information.

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  • Which frontend framework/library should I learn to enhance an existing site? [on hold]

    - by Codemonkey
    I have a large site that I've coded by hand over the last couple of years. It's a sports results service, and allows users to view their results, compare themselves to others, buy photographs, that sort of thing. The code base is fairly substantial, and scarily uses no frameworks or libraries. It's a PHP backend, and a clean & compact frontend. I use the Highcharts library, but other than that all of the JS is my own. I'm not a fan of bulk, even if it is CDN-hosted and heavily cachable. Maybe I need to change my outlook on this? I'm wanting to make some significant changes to the site now, and it seems an appropriate time to enhance my skillset by learning AngularJS, or something else of that ilk. A large part of the site is tables of data, and as just one example of the sort of thing I want to achieve, I'd like to let users add/remove/sort columns better than they currently can. Are any of the various frameworks/libraries out there more suitable to shoehorning into an existing project?

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  • Appcache and jquery mobile on a CMS powered site?

    - by user793011
    Has anyone used the cache manifest to make a CMS site work offline? I've made a demo with static html files which seems to work fine, so I'm assuming it wouldn't be too hard to achieve the same thing with a CMS. The way that you tell browsers that files have changed (and so need to be downloaded again) is by adding a comment to the cache manifest file so its byte size changes. I'm not quite sure how to do this with a CMS, but maybe some sort of server cron could run periodically? Personally I'm more interested in having a site that works offline rather than achieving ideal performance, so if the file was modified every hour rather than when content actually changed that would be fine for me. If anyone has used appcache with a CMS, has anyone done so with jquery mobile at the same time? What I'm after is a fully native feel to a site that's accessible offline, in other words I want to mimic a native App. My static demo does this perfectly with jquery mobile, so again I would have thought this would be achievable in a CMS.

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  • Is it okay to just add a page or two PHP page to add some functionality to a Drupal site?

    - by Zaemz
    I'm not familiar with Drupal, really. I can dig around the admin interface and navigate the directories and find the files that I need to just fine as well. What I'm really not familiar with is adding modules or extending modules. The site currently takes an order and sets up recurring payments through Ubercart and uses Authorize.net as a gateway. Right now, when a payment fails, a single e-mail gets sent out to the admin. We'd like to extend it to send an e-mail to the user and let them change their payment information through another page on the site. Authorize has a service called Silent Post URL that basically just posts a carbon copy in XML to whatever URL you give it. We'd like to accept that XML, deserialize it, parse the data, send a notice to the user and give them the page for updating their information. So, I guess it'll be two PHP pages. One for the XML API call from Authorize.net, and then one for the page for the users' to update their payment information. Could I just create two simple pages each handling their own tasks, or should I check out properly extending a module? If it's appropriate for me to write up the pages and not have to hook them into the module, what would be the best way to handle setting up what needs to get done? (The most experience I've had with extending a PHP site has been hacking away at someone else' poorly constructed, custom framework, so if anyone has any good resources perhaps on PHP best practices that they could share through a PM or a comment, I'd appreciate It) (Also, I'm still getting the hang of Stack Exchange, so if this isn't appropriate please let me know. I'll delete it.)

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  • hibernate criteria list problem [migrated]

    - by user1022676
    I have a user dao @Entity @Table(name="EBIGUSERTIM") public class EbigUser { private String id; private Integer source; private String entryscheme; private String fullName; private String email; private Long flags; private String status; private String createdBy; private Date createdStamp; private String modifiedBy; private Date modifiedStamp; @Id @Column(name="ID") public String getId() { return id; } public void setId(String id) { this.id = id; } @Id @Column(name="SOURCE") public Integer getSource() { return source; } public void setSource(Integer source) { this.source = source; } @Column(name="ENTRYSCHEME") public String getEntryscheme() { return entryscheme; } public void setEntryscheme(String entryscheme) { this.entryscheme = entryscheme; } @Column(name="FULLNAME") public String getFullName() { return fullName; } public void setFullName(String fullName) { this.fullName = fullName; } @Column(name="EMAIL") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @Column(name="FLAGS") public Long getFlags() { return flags; } public void setFlags(Long flags) { this.flags = flags; } @Column(name="STATUS") public String getStatus() { return status; } public void setStatus(String status) { this.status = status; } @Column(name="CREATEDBY") public String getCreatedBy() { return createdBy; } public void setCreatedBy(String createdBy) { this.createdBy = createdBy; } @Column(name="CREATEDSTAMP") public Date getCreatedStamp() { return createdStamp; } public void setCreatedStamp(Date createdStamp) { this.createdStamp = createdStamp; } @Column(name="MODIFIEDBY") public String getModifiedBy() { return modifiedBy; } public void setModifiedBy(String modifiedBy) { this.modifiedBy = modifiedBy; } @Column(name="MODIFIEDSTAMP") public Date getModifiedStamp() { return modifiedStamp; } public void setModifiedStamp(Date modifiedStamp) { this.modifiedStamp = modifiedStamp; } i am selecting 2 rows out of the db. The sql works select * from ebigusertim where id='blah'. It returns 2 distinct rows. When i query the data using hibernate, it appears that the object memory is not being allocated for each entry in the list. Thus, i get 2 entries in the list with the same object. Criteria userCriteria = session.createCriteria(EbigUser.class); userCriteria.add(Restrictions.eq("id", id)); userlist = userCriteria.list();

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  • Mimicking the UltraGridColumnChooser's drag & drop ability

    - by Sören Kuklau
    (Infragistics 2008 Vol. 3, CLR 2.0) Infragistics's UltraGrid comes with a column chooser user control, which is simply a vertical arrangement of columns with checkboxes that toggle a column's hidden state. In addition, it allows you to pick a column and drag it directly to the grid so you don't have to manually position it afterwards. (This is particularly handy when you already have a lot of visible columns and have no clue where the new one ended up.) I'm building my own column chooser based on an UltraTree. Getting the checkboxes to behave the same wasn't an issue, but I haven't found a way to drag a column from the tree to the grid and have it accept it. In my tree, each UltraTreeNode has a Tag with the following struct: Private Structure DraggableGridColumn Public NodeKey As String Public NodeName As String Public ParentKey As String Public Column As UltraGridColumn End Structure I then have an event as follows: Private Sub columnsTree_SelectionDragStart(ByVal sender As Object, ByVal e As System.EventArgs) Handles columnsTree.SelectionDragStart If columnsTree.SelectedNodes.Count <> 1 Then Return End If If Not TypeOf columnsTree.SelectedNodes(0).Tag Is DraggableGridColumn Then Return End If Dim column As UltraGridColumn = CType(columnsTree.SelectedNodes(0).Tag, DraggableGridColumn).Column columnsTree.DoDragDrop(column, DragDropEffects.All) End Sub In the DoDragDrop call, neither column (of type UltraGridColumn) nor column.Header (of type ColumnHeader) get accepted by the grid. I assume I'm sending the wrong type, and/or that the grid expects a special struct with some additional information. Unfortunately, I've also failed to catch an event (both on the column chooser side as well as on the grid side) where Infragistics's normal column chooser does this properly; the normal drag & drop events never seem to fire.

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  • How do I create self-relationships in polymorphic inheritance in Elixir and Pylons?

    - by Turukawa
    I am new to programming and am following the example in the Pylons documentation on creating a Wiki. The database I want to link to the wiki was created with Elixir so I rewrote the Wiki database schema and have continued from there. In the wiki there is a requirement for a Navigation table which is inherited by Pages and Sections. A section can have many pages, while a page can only have one section. In addition, each sibling node can be chain-referenced to each other. So: Nav has "section" (OneToMany) and "before" (OneToOne - to reference preceeding node) Page has "section" (ManyToOne - many pages in one section) and inherits "before" Section inherits all from Nav The code I've written looks like this: class Nav(Entity): using_options(inheritance='multi') name = Field(Unicode(30), default=u'Untitled Node') path = Field(Unicode(255), default=u'') section = OneToMany('Page', inverse='section') after = OneToOne('Nav', inverse='before') before = OneToMany('Nav', inverse='after') class Page(Nav): using_options(inheritance='multi') content = Field(UnicodeText, nullable=False) posted = Field(DateTime, default=now()) title = Field(Unicode(255), default=u'Untitled Page') heading = Field(Unicode(255)) tags = ManyToMany('Tag') comments = OneToMany('Comment') section = ManyToOne('Nav', inverse='section') class Section(Nav): using_options(inheritance='multi') Errors received on this: sqlalchemy.exc.OperationalError: (OperationalError) table nav has no column named aftr_id u'INSERT INTO nav (name, path, aftr_id, row_type) VALUES (?, ?, ?, ?)' I've also tried: before = ManyToMany('Nav', inverse='before') on Nav in the hopes this might break the problem, but also not. The original SQLAlchemy code from the tutorial for these declarations is as follows: nav_table = schema.Table('nav', meta.metadata, schema.Column('id', types.Integer(), schema.Sequence('nav_id_seq', optional=True), primary_key=True), schema.Column('name', types.Unicode(255), default=u'Untitled Node'), schema.Column('path', types.Unicode(255), default=u''), schema.Column('section', types.Integer(), schema.ForeignKey('nav.id')), schema.Column('before', types.Integer(), default=None), schema.Column('type', types.String(30), nullable=False) ) page_table = schema.Table('page', meta.metadata, schema.Column('id', types.Integer, schema.ForeignKey('nav.id'), primary_key=True), schema.Column('content', types.Text(), nullable=False), schema.Column('posted', types.DateTime(), default=now), schema.Column('title', types.Unicode(255), default=u'Untitled Page'), schema.Column('heading', types.Unicode(255)), ) section_table = sa.Table('section', meta.metadata, schema.Column('id', types.Integer, schema.ForeignKey('nav.id'), primary_key=True), ) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) Any help is much appreciated.

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  • Populating a Datagrid with variable number of columns and rows in Flex

    - by Rie Mino
    I am trying to figure out how to manage a Datagrid based on an XML object like this: <matrix rows="5" columns="5"> <column> <row>0.5</row> <row>0.21</row> </column> <column> <row>0.6</row> <row>0.9</row> </column> <column> <row>0.5</row> <row>0.5</row> </column> <column> <row>0.8</row> <row>0.4</row> </column> </matrix> I will need to populate the Datagrid column names based on a different XML object and use the above XML to populate each of the column's rows. I currently am able to create the Datagrid and populate its column headers but I am unsure as to how to how to add the rows for each column. The above XML will be update with new row and column elements added and deleted. This, of course, will be bound to the Datagrid to show updates. Thanks in advanced for your help.

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  • jQuery hover menu not disappearing

    - by Nathan Loding
    I have a basic menu using some nested UL's, which is pretty standard I think. When hovering over an LI from the "root" menu, I want the UL within that LI to display. Move the mouse off or to another LI, it shows that submenu. Move down to the submenu and it stays while you hover over each element. I had it working with a simple jQuery.hover() set, but then I ran into issues. When on a page, the "root" menu item is given a class of 'current-page' and if that class exists, I want it to display that submenu statically after a mouseout. Hope I explained that well enough. I just tossed a variable into the hover functions so on the mouseout it ran a .show() on the current-page's submenu. Easy. Except that when I move the mouse between the individual LI's of the submenu, it changes back to the current-page submenu. So I attempted to add a timer element based on another question here. That made things worse -- now the submenus just don't disappear. Here's my CSS, markup, and JS ... how the heck do I make this work properly? Markup: <div id="menu"> <div id="navbar"> <ul id="firstmenu"> <li> <a href="http://localhost/site/pageone">page one</a> <ul class="submenu"> <li><a href="http://localhost/site/pageone/subone">subone</a></li> <li><a href="http://localhost/site/pageone/subtwo">subtwo</a></li> <li><a href="http://localhost/site/pageone/subthree">subthree</a></li> <li><a href="http://localhost/site/pageone/subfour">subfour</a></li> <li><a href="http://localhost/site/pageone/subfive">subfive</a></li> </ul> </li> <li> <a href="http://localhost/site/pagetwo">barely there</a> <ul class="submenu"> <li><a href="http://localhost/site/pageone/subone">subone</a></li> <li><a href="http://localhost/site/pageone/subtwo">subtwo</a></li> <li><a href="http://localhost/site/pageone/subthree">subthree</a></li> <li><a href="http://localhost/site/pageone/subfour">subfour</a></li> <li><a href="http://localhost/site/pageone/subfive">subfive</a></li> </ul> </li> <li class="current-page"> <a href="http://localhost/site/pagetwo">kith & kin</a> <ul class="submenu"> <li><a href="http://localhost/site/pageone/subone">subone</a></li> <li><a href="http://localhost/site/pageone/subtwo">subtwo</a></li> <li><a href="http://localhost/site/pageone/subthree">subthree</a></li> <li><a href="http://localhost/site/pageone/subfour">subfour</a></li> <li><a href="http://localhost/site/pageone/subfive">subfive</a></li> </ul> </li> <li> <a href="http://localhost/site/pagethree">focal point</a> <ul class="submenu"> <li><a href="http://localhost/site/pageone/subone">subone</a></li> <li><a href="http://localhost/site/pageone/subtwo">subtwo</a></li> <li><a href="http://localhost/site/pageone/subthree">subthree</a></li> <li><a href="http://localhost/site/pageone/subfour">subfour</a></li> <li><a href="http://localhost/site/pageone/subfive">subfive</a></li> </ul> </li> <li> <a href="http://localhost/site/pagefour">products</a> <ul class="submenu"> <li><a href="http://localhost/site/pageone/subone">subone</a></li> <li><a href="http://localhost/site/pageone/subtwo">subtwo</a></li> <li><a href="http://localhost/site/pageone/subthree">subthree</a></li> <li><a href="http://localhost/site/pageone/subfour">subfour</a></li> <li><a href="http://localhost/site/pageone/subfive">subfive</a></li> </ul> </li> <li> <a href="http://localhost/site/pagefive">clients</a> </li> </ul> </div></div> And here's the CSS: #navbar { margin: 0; padding: 0; border: 0; text-align: center; } #firstmenu { margin: 6px auto 0 auto; font-size: 16px; list-style-type: none; letter-spacing: -1px; } #firstmenu li { display: inline; position:relative; overflow: hidden; text-align: center; margin-right: 10px; padding: 5px 15px; } #firstmenu a { text-decoration: none; outline: none; color: black; font-weight: 700; width: 75px; cursor: pointer; } .current-page { color: white; background: url(../images/down_arrow.png) bottom center no-repeat; } .current-page a { color: white; border-bottom: 1px solid black; } #firstmenu .current-page a { color: white; } #firstmenu li.hover { color: white; background: url(../images/down_arrow.png) bottom center no-repeat; } #firstmenu li.hover a { color: white; border-bottom: 1px solid black; } #firstmenu li ul li.hover { color: white; background: none; } #firstmenu li ul li.hover a { color: white; border-bottom: none; text-decoration: underline; } #firstmenu li ul { width: 900px; color: white; font-size: .8em; margin-top: 3px; padding: 5px; position: absolute; display: none; } #firstmenu li ul li { list-style: none; display: inline; width: auto; } #firstmenu li ul li a { color: white; font-weight: normal; border: none; } .sub-current-page { font-weight: bold; text-decoration: underline; } #firstmenu li ul li.sub-current-page a { font-weight: bold; } And lastly, my not-at-all-working JS (this is in a $(document).ready(), of course): // Initialize some variables var hideSubmenuTimer = null; var current_page; $('.current-page ul:first').show(); // Prep the menu $('#firstmenu li').hover(function() { // Clear the timeout if it exists if(hideSubmenuTimer) { clearTimeout(hideSubmenuTimer); } // Check if there's a current-page class set if($('li.current-page').length > 0) { current_page = $('li.current-page'); } else { current_page = false; } // If there's a current-page class, hide it if(current_page) { current_page.children('ul:first').hide(); } // Show the new submenu $(this).addClass('hover').children('ul:first').show(); }, function(){ // Just in case var self = this; // Clear the timeout if it exists if(hideSubmenuTimer) { clearTimeout(hideSubmenuTimer); } // Check if there's a current-page class set if($('li.current-page').length > 0) { current_page = $('li.current-page'); } else { current_page = false; } // Set a timeout on hiding the submenu hideSubmenuTimer = setTimeout(function() { // Hide the old submenu $(self).removeClass('hover').children('ul').hide(); // If there's a current-page class, show it if(current_page) { current_page.children('ul:first').show(); current_page.css('color', 'white'); } }, 500); }); So what am I doing so wrong? As a side note, I'm using the $('.current-page ul:first').show() because if I gave .current-page any "display" setting in the CSS, it positioned it really weirdly on the page.

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  • How to use Microsoft.Web.Administration.dll to get the site information the page is running on?

    - by Keith Barrows
    I have a half dozen sites on my server and I would like to get some info from IIS7 to display in the footer of each page (as long as you are an admin of course). I am going through the ServerObject and found Sites but am not finding anything obvious for "this site". What should I do to get at the information for the exact site in IIS7 that the page is running on? For a quick 'hack' style approach I wrote this on my default.aspx page code behind: ServerManager serverMgr = new ServerManager(); foreach (Site site in serverMgr.Sites) { string s = info.Text + site.Name + @"<br/>"; info.Text = s; foreach (Binding binding in site.Bindings) { string t = info.Text + binding.BindingInformation + " | "; string p = t + binding.Protocol + @"<br/>"; info.Text = p; } } TIA

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  • Why & When should I use SPARSE COLUMN? (SQL SERVER 2008)

    - by priyanka.sarkar
    After going thru some tutorials on SQL SERVER 2008's new feature SPARSE COLUMN, I have found that it doesn't take any space if the column value is 0 or null but when there is a value, it takes 4 times the space a regular(non sparse) column holds. If my understanding is correct, then why I will go for that at the time of database design? And if I use that, then at what situation so I be? Also out of curiosity, how come no space get's reserve when a column is defined as sparse column(I mean to say, what is the internal implementation for that) Thanks in advance

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  • Apache config that uses two document roots based on whether the requested resource exists in the first

    - by mattalexx
    Background I have a client site that consists of a CakePHP installation and a Magento installation: /web/example.com/ /web/example.com/app/ <== CakePHP /web/example.com/app/webroot/ <== DocumentRoot /web/example.com/app/webroot/store/ <== Magento /web/example.com/config/ <== Site-wide config /web/example.com/vendors/ <== Site-wide libraries The server runs Apache 2.2.3. The problem The whole company has FTP access and got used to clogging up the /web/example.com/, /web/example.com/app/webroot/, and /web/example.com/app/webroot/store/ directories with their own files. Sometimes these files need HTTP access and sometimes they don't. In any case, this mess makes my job harder when it comes to maintaining the site. Code merges, tarring the live code, etc, is very complicated and usually requires a bunch of filters. Abandoned solution At first, I thought I would set up a new subdomain on the same server, move all of their files there, and change their FTP chroot. But that wouldn't work for these reasons: Firstly, I have no idea (and neither do they remember) what marketing materials they've sent out that contain URLs to certain resources they've uploaded to the server, using the main domain, and also using abstract subdomains that use the main virtual host because it has ServerAlias *.example.com. So suddenly having them only use static.example.com isn't feasible. Secondly, The PHP scripts in their projects are potentially very non-portable. I want their files to stay in as similar an environment as they were built as I can. Also, I do not want to debug their code to make it portable. Half-baked solution After some thought, I decided to find a way to section off the actual website files into another directory that they would not touch. The company's uploaded files would stay where they were. This would ensure that I didn't break any of their projects that needed HTTP access. It would look something like this: /web/example.com/ <== A bunch of their files are in here /web/example.com/app/webroot/ <== 1st DocumentRoot; A bunch of their files are in here /web/example.com/app/webroot/store/ <== Some more are in here /web/example.com/site/ <== New dir; Contains only site files /web/example.com/site/app/ <== CakePHP /web/example.com/site/app/webroot/ <== 2nd DocumentRoot /web/example.com/site/app/webroot/store/ <== Magento /web/example.com/site/config/ <== Site-wide config /web/example.com/site/vendors/ <== Site-wide libraries After I made this change, I would not need to pay attention to anything except for the stuff within /web/example.com/site/ and my job would be a lot easier. I would be the only one changing stuff in there. So here's where the Apache magic would happen: I need an HTTP request to http://www.example.com/ to first use /web/example.com/app/webroot/ as the document root. If nothing is found (no miscellaneous uploaded company projects are found), try finding something within /web/example.com/site/app/webroot/. Another thing to keep in mind is, the site might have some problems if the $_SERVER['DOCUMENT_ROOT'] variable reads /web/example.com/app/webroot/ but the actual files are within /web/example.com/site/app/webroot/. It would be better if the DOCUMENT_ROOT environment variable could be /web/example.com/site/app/webroot/ for anything within the /web/example.com/site/app/webroot/ directory. Conclusion Is my half-baked solution possible with Apache 2.2.3? Is there a better way to solve this problem?

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  • [Django] How to find out whether a model's column is a foreign key?

    - by codethief
    I'm dynamically storing information in the database depending on the request: // table, id and column are provided by the request table_obj = getattr(models, table) record = table_obj.objects.get(pk=id) setattr(record, column, request.POST['value']) The problem is that request.POST['value'] sometimes contains a foreign record's primary key (i.e. an integer) whereas Django expects the column's value to be an object of type ForeignModel: Cannot assign "u'122'": "ModelA.b" must be a "ModelB" instance. Now, is there an elegant way to dynamically check whether b is a column containing foreign keys and what model these keys are linked to? (So that I can load the foreign record by it's primary key and assign it to ModelA?) Or doesn't Django provide information like this to the programmer so I really have to get my hands dirty and use isinstance() on the foreign-key column?

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  • How do I tell Entity Framework that a column in a view is nullable?

    - by Ryan ONeill
    I have a view which has an Int column which is nullable (let's call it StackOverflowCount). When generating an EF model from the database, the EF designer does not recognise it as nullable and creates the column as an Int. The issue I have is that on the EF designer I have set the column to Nullable and the following error then kills the compilation; Error 3031: Problem in mapping fragments starting at line 2327: Non-nullable column MyView.StackOverflowCount in table MyView is mapped to a nullable entity property. I can get round this by opening the .edmx file in XML mode and manually editing the SQL column definition, but there is no way to do this using the designer and it gets overwritten the next time I refresh from the model from the DB. Is this 'by design' or an example of something that slipped through into EF 4.0? I'm using .Net 4.0 with EF 4.0 under VS 2010.

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  • SQL Server 2003: how can I assign a name to the SUM column ?

    - by Patrick
    hi, how can I assign a column name to the SUM column ? i.e. select OwnerUserId, SUM(PostScore) INTO Experts from ... I get this error: An object or column name is missing or empty. For SELECT INTO statements, verify each column has a name. For other statements, look for empty alias names. Aliases defined as "" or [] are not allowed. Change the alias to a valid name. I guess because the column containing the results of SUM has not name. thanks

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  • How to have Excel data validation display different data in drop down than is actually validated

    - by Memitim
    How can I provide a user with a drop-down menu in a cell that displays the contents from one column but actually writes the value from a different column to the cell and validates against the values from that second column? I have a bit of code that very nearly does this (credit: DV0005 from the Contextures site): Private Sub Worksheet_Change(ByVal Target As range) On Error GoTo errHandler If Target.Cells.Count > 1 Then GoTo exitHandler If Target.Column = 10 Then If Target.Value = "" Then GoTo exitHandler Application.EnableEvents = False Target.Value = Worksheets("Measures").range("B1") _ .Offset(Application.WorksheetFunction _ .Match(Target.Value, Worksheets("Measures").range("Measures"), 0) - 1, 1) End If The drop-down displays the values from one column, for example Column B, but when selected actually writes the value on the same row from Column C to the cell. However, data validation is actually validating against Column B, so if I manually enter something from Column C in the cell and try to move to another cell, data validation throws an error.

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  • With NHibernate, how can I add a child object when updating a parent object?

    - by BMZ
    I have a simple Parent/Child relationship between a Person object and an Address object. The Person object exists in the DB. After doing a Get on the Person, I add a new Address object to the Address sub-object list of the parent, and do some other updates to the Person object. Finally, I do an Update on the Person object. With a SQL trace window, I can see the update to the Person object to the Person table and the Insert of the Address record to the Address table. The issue is that, after the update is performed, the AddressId (primary key on the Address object) is still set to 0, which is what it defaults to when you first initialize the Address object. I have verified that when I do an Add, this value is set correctly. Is this a known issue when trying to add sub-objects as part of an NHibernate UPDATE? Sample code and mapping files are below Thanks <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class name="BusinessEntities.Wellness.Person,BusinessEntities.Wellness" table="Person" lazy="true" dynamic-insert="true" dynamic-update="false"> <id name="Personid" column="PersonID" type="int"> <generator class="native" /> </id> <version type="binary" generated="always" name="RecordVersion" column="`RecordVersion`"/> <property type="int" not-null="true" name="Customerid" column="`CustomerID`" /> <property type="AnsiString" not-null="true" length="9" name="Ssn" column="`SSN`" /> <property type="AnsiString" not-null="true" length="30" name="FirstName" column="`FirstName`" /> <property type="AnsiString" not-null="true" length="35" name="LastName" column="`LastName`" /> <property type="AnsiString" length="1" name="MiddleInitial" column="`MiddleInitial`" /> <property type="DateTime" name="DateOfBirth" column="`DateOfBirth`" /> <bag name="PersonAddresses" inverse="true" lazy="true" cascade="all"> <key column="PersonID" /> <one-to-many class="BusinessEntities.Wellness.PersonAddress,BusinessEntities.Wellness" / </bag> </class> </hibernate-mapping> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class name="BusinessEntities.Wellness.PersonAddress,BusinessEntities.Wellness" table="PersonAddress" lazy="true" dynamic-insert="true" dynamic-update="false"> <id name="PersonAddressId" column="PersonAddressID" type="int"> <generator class="native" /> </id> <version type="binary" generated="always" name="RecordVersion" column="`RecordVersion`" /> <property type="AnsiString" not-null="true" length="1" name="AddressTypeid" column="`AddressTypeID`" /> <property type="AnsiString" not-null="true" length="60" name="AddressLine1" column="`AddressLine1`" /> <property type="AnsiString" length="60" name="AddressLine2" column="`AddressLine2`" /> <property type="AnsiString" length="60" name="City" column="`City`" /> <property type="AnsiString" length="2" name="UsStateId" column="`USStateID`" /> <property type="AnsiString" length="5" name="UsPostalCodeId" column="`USPostalCodeID`" /> <many-to-one name="Person" cascade="none" column="PersonID" /> </class> </hibernate-mapping> Person newPerson = new Person(); newPerson.PersonName = "John Doe"; newPerson.SSN = "111111111"; newPerson.CreatedBy = "RJC"; newPerson.CreatedDate = DateTime.Today; personDao.AddPerson(newPerson); Person updatePerson = personDao.GetPerson(newPerson.PersonId); updatePerson.PersonAddresses = new List<PersonAddress>(); PersonAddress addr = new PersonAddress(); addr.AddressLine1 = "1 Main St"; addr.City = "Boston"; addr.State = "MA"; addr.Zip = "12345"; updatePerson.PersonAddresses.Add(addr); personDao.UpdatePerson(updatePerson); int addressID = updatePerson.PersonAddresses[0].AddressId;

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  • SSL error: error:0B080074:x509 certificate routines:X509_check_private_key:key values mismatch

    - by Tiffany Walker
    ERROR: SSL error: error:0B080074:x509 certificate routines:X509_check_private_key:key values mismatch STEPS: openssl genrsa -out SITE.TLD.key 2048 openssl req -new -key SITE.TLD.key -out SITE.TLD.csr (send CSR to SSL site to sign) add CERT to SITE.TLD.crt add CA to SITE.TLD.ca chained them: cat SITE.TLD.crt SITE.TLD.ca > chained.cert Any Idea what I am doing wrong? I am using LiteSpeed HTTPd

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  • Separate "Year" to several worksheets according to one column....

    - by HACHI
    hello! This task is driving me mad... please help! Instead of manually type in the data, i have used VBA to find the year range, put into one column and delete all duplicate ones. But since excel could give more than 20 years, it would be tedious to do all the filtering manually. AND, now i need excel to separate the rows that contain the specific year range in any one the three columns and put them into a new sheet. e.g. The years that excel could find in the three columns(F:H) are ( 2001,2003,2006,2010, 2012,2020.....2033).. and they are pasted in column "S" in sheet 1. How could i tell excel create new sheets for the years ( sheets 2001, sheets 2003, sheet2006....),search through column (F:H) in sheet 1 to see if ANY of those columns contain that year, and paste them into the new sheet. To be more specific, in the newly created "Sheet 2001", the entire row where column(F:H) contains "2001" should be pasted. and in the newly created "Sheet 2033", the entire row where column(F:H) contains "2033" should be pasted.. Enclosed please find the reference. http://www.speedyshare.com/files/23851477/Book32.xls I have got sheet "2002" and "2003" here as results but for the real one i will need more years' sheets (as many as how many excel could extract in the previous stage; as shown in column L ) ...... I think this task should be quite usual (extracting by date), but i couldn't google the result....Pleas help!!I am very clueless about how to do LOOPING.. so please advice and give in more details! Thanks

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  • Reporting Services - It's a Wrap!

    - by smisner
    If you have any experience at all with Reporting Services, you have probably developed a report using the matrix data region. It's handy when you want to generate columns dynamically based on data. If users view a matrix report online, they can scroll horizontally to view all columns and all is well. But if they want to print the report, the experience is completely different and you'll have to decide how you want to handle dynamic columns. By default, when a user prints a matrix report for which the number of columns exceeds the width of the page, Reporting Services determines how many columns can fit on the page and renders one or more separate pages for the additional columns. In this post, I'll explain two techniques for managing dynamic columns. First, I'll show how to use the RepeatRowHeaders property to make it easier to read a report when columns span multiple pages, and then I'll show you how to "wrap" columns so that you can avoid the horizontal page break. Included with this post are the sample RDLs for download. First, let's look at the default behavior of a matrix. A matrix that has too many columns for one printed page (or output to page-based renderer like PDF or Word) will be rendered such that the first page with the row group headers and the inital set of columns, as shown in Figure 1. The second page continues by rendering the next set of columns that can fit on the page, as shown in Figure 2.This pattern continues until all columns are rendered. The problem with the default behavior is that you've lost the context of employee and sales order - the row headers - on the second page. That makes it hard for users to read this report because the layout requires them to flip back and forth between the current page and the first page of the report. You can fix this behavior by finding the RepeatRowHeaders of the tablix report item and changing its value to True. The second (and subsequent pages) of the matrix now look like the image shown in Figure 3. The problem with this approach is that the number of printed pages to flip through is unpredictable when you have a large number of potential columns. What if you want to include all columns on the same page? You can take advantage of the repeating behavior of a tablix and get repeating columns by embedding one tablix inside of another. For this example, I'm using SQL Server 2008 R2 Reporting Services. You can get similar results with SQL Server 2008. (In fact, you could probably do something similar in SQL Server 2005, but I haven't tested it. The steps would be slightly different because you would be working with the old-style matrix as compared to the new-style tablix discussed in this post.) I created a dataset that queries AdventureWorksDW2008 tables: SELECT TOP (100) e.LastName + ', ' + e.FirstName AS EmployeeName, d.FullDateAlternateKey, f.SalesOrderNumber, p.EnglishProductName, sum(SalesAmount) as SalesAmount FROM FactResellerSales AS f INNER JOIN DimProduct AS p ON p.ProductKey = f.ProductKey INNER JOIN DimDate AS d ON d.DateKey = f.OrderDateKey INNER JOIN DimEmployee AS e ON e.EmployeeKey = f.EmployeeKey GROUP BY p.EnglishProductName, d.FullDateAlternateKey, e.LastName + ', ' + e.FirstName, f.SalesOrderNumber ORDER BY EmployeeName, f.SalesOrderNumber, p.EnglishProductName To start the report: Add a matrix to the report body and drag Employee Name to the row header, which also creates a group. Next drag SalesOrderNumber below Employee Name in the Row Groups panel, which creates a second group and a second column in the row header section of the matrix, as shown in Figure 4. Now for some trickiness. Add another column to the row headers. This new column will be associated with the existing EmployeeName group rather than causing BIDS to create a new group. To do this, right-click on the EmployeeName textbox in the bottom row, point to Insert Column, and then click Inside Group-Right. Then add the SalesOrderNumber field to this new column. By doing this, you're creating a report that repeats a set of columns for each EmployeeName/SalesOrderNumber combination that appears in the data. Next, modify the first row group's expression to group on both EmployeeName and SalesOrderNumber. In the Row Groups section, right-click EmployeeName, click Group Properties, click the Add button, and select [SalesOrderNumber]. Now you need to configure the columns to repeat. Rather than use the Columns group of the matrix like you might expect, you're going to use the textbox that belongs to the second group of the tablix as a location for embedding other report items. First, clear out the text that's currently in the third column - SalesOrderNumber - because it's already added as a separate textbox in this report design. Then drag and drop a matrix into that textbox, as shown in Figure 5. Again, you need to do some tricks here to get the appearance and behavior right. We don't really want repeating rows in the embedded matrix, so follow these steps: Click on the Rows label which then displays RowGroup in the Row Groups pane below the report body. Right-click on RowGroup,click Delete Group, and select the option to delete associated rows and columns. As a result, you get a modified matrix which has only a ColumnGroup in it, with a row above a double-dashed line for the column group and a row below the line for the aggregated data. Let's continue: Drag EnglishProductName to the data textbox (below the line). Add a second data row by right-clicking EnglishProductName, pointing to Insert Row, and clicking Below. Add the SalesAmount field to the new data textbox. Now eliminate the column group row without eliminating the group. To do this, right-click the row above the double-dashed line, click Delete Rows, and then select Delete Rows Only in the message box. Now you're ready for the fit and finish phase: Resize the column containing the embedded matrix so that it fits completely. Also, the final column in the matrix is for the column group. You can't delete this column, but you can make it as small as possible. Just click on the matrix to display the row and column handles, and then drag the right edge of the rightmost column to the left to make the column virtually disappear. Next, configure the groups so that the columns of the embedded matrix will wrap. In the Column Groups pane, right-click ColumnGroup1 and click on the expression button (labeled fx) to the right of Group On [EnglishProductName]. Replace the expression with the following: =RowNumber("SalesOrderNumber" ). We use SalesOrderNumber here because that is the name of the group that "contains" the embedded matrix. The next step is to configure the number of columns to display before wrapping. Click any cell in the matrix that is not inside the embedded matrix, and then double-click the second group in the Row Groups pane - SalesOrderNumber. Change the group expression to the following expression: =Ceiling(RowNumber("EmployeeName")/3) The last step is to apply formatting. In my example, I set the SalesAmount textbox's Format property to C2 and also right-aligned the text in both the EnglishProductName and the SalesAmount textboxes. And voila - Figure 6 shows a matrix report with wrapping columns. Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • SQL Server script commands to check if object exists and drop it

    - by deadlydog
    Over the past couple years I’ve been keeping track of common SQL Server script commands that I use so I don’t have to constantly Google them.  Most of them are how to check if a SQL object exists before dropping it.  I thought others might find these useful to have them all in one place, so here you go: 1: --=============================== 2: -- Create a new table and add keys and constraints 3: --=============================== 4: IF NOT EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME = 'TableName' AND TABLE_SCHEMA='dbo') 5: BEGIN 6: CREATE TABLE [dbo].[TableName] 7: ( 8: [ColumnName1] INT NOT NULL, -- To have a field auto-increment add IDENTITY(1,1) 9: [ColumnName2] INT NULL, 10: [ColumnName3] VARCHAR(30) NOT NULL DEFAULT('') 11: ) 12: 13: -- Add the table's primary key 14: ALTER TABLE [dbo].[TableName] ADD CONSTRAINT [PK_TableName] PRIMARY KEY NONCLUSTERED 15: ( 16: [ColumnName1], 17: [ColumnName2] 18: ) 19: 20: -- Add a foreign key constraint 21: ALTER TABLE [dbo].[TableName] WITH CHECK ADD CONSTRAINT [FK_Name] FOREIGN KEY 22: ( 23: [ColumnName1], 24: [ColumnName2] 25: ) 26: REFERENCES [dbo].[Table2Name] 27: ( 28: [OtherColumnName1], 29: [OtherColumnName2] 30: ) 31: 32: -- Add indexes on columns that are often used for retrieval 33: CREATE INDEX IN_ColumnNames ON [dbo].[TableName] 34: ( 35: [ColumnName2], 36: [ColumnName3] 37: ) 38: 39: -- Add a check constraint 40: ALTER TABLE [dbo].[TableName] WITH CHECK ADD CONSTRAINT [CH_Name] CHECK (([ColumnName] >= 0.0000)) 41: END 42: 43: --=============================== 44: -- Add a new column to an existing table 45: --=============================== 46: IF NOT EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS where TABLE_SCHEMA='dbo' 47: AND TABLE_NAME = 'TableName' AND COLUMN_NAME = 'ColumnName') 48: BEGIN 49: ALTER TABLE [dbo].[TableName] ADD [ColumnName] INT NOT NULL DEFAULT(0) 50: 51: -- Add a description extended property to the column to specify what its purpose is. 52: EXEC sys.sp_addextendedproperty @name=N'MS_Description', 53: @value = N'Add column comments here, describing what this column is for.' , 54: @level0type=N'SCHEMA',@level0name=N'dbo', @level1type=N'TABLE', 55: @level1name = N'TableName', @level2type=N'COLUMN', 56: @level2name = N'ColumnName' 57: END 58: 59: --=============================== 60: -- Drop a table 61: --=============================== 62: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME = 'TableName' AND TABLE_SCHEMA='dbo') 63: BEGIN 64: DROP TABLE [dbo].[TableName] 65: END 66: 67: --=============================== 68: -- Drop a view 69: --=============================== 70: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.VIEWS WHERE TABLE_NAME = 'ViewName' AND TABLE_SCHEMA='dbo') 71: BEGIN 72: DROP VIEW [dbo].[ViewName] 73: END 74: 75: --=============================== 76: -- Drop a column 77: --=============================== 78: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS where TABLE_SCHEMA='dbo' 79: AND TABLE_NAME = 'TableName' AND COLUMN_NAME = 'ColumnName') 80: BEGIN 81: 82: -- If the column has an extended property, drop it first. 83: IF EXISTS (SELECT * FROM sys.fn_listExtendedProperty(N'MS_Description', N'SCHEMA', N'dbo', N'Table', 84: N'TableName', N'COLUMN', N'ColumnName') 85: BEGIN 86: EXEC sys.sp_dropextendedproperty @name=N'MS_Description', 87: @level0type=N'SCHEMA',@level0name=N'dbo', @level1type=N'TABLE', 88: @level1name = N'TableName', @level2type=N'COLUMN', 89: @level2name = N'ColumnName' 90: END 91: 92: ALTER TABLE [dbo].[TableName] DROP COLUMN [ColumnName] 93: END 94: 95: --=============================== 96: -- Drop Primary key constraint 97: --=============================== 98: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='PRIMARY KEY' AND TABLE_SCHEMA='dbo' 99: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'PK_Name') 100: BEGIN 101: ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [PK_Name] 102: END 103: 104: --=============================== 105: -- Drop Foreign key constraint 106: --=============================== 107: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='FOREIGN KEY' AND TABLE_SCHEMA='dbo' 108: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'FK_Name') 109: BEGIN 110: ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [FK_Name] 111: END 112: 113: --=============================== 114: -- Drop Unique key constraint 115: --=============================== 116: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' 117: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'UNI_Name') 118: BEGIN 119: ALTER TABLE [dbo].[TableNames] DROP CONSTRAINT [UNI_Name] 120: END 121: 122: --=============================== 123: -- Drop Check constraint 124: --=============================== 125: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='CHECK' AND TABLE_SCHEMA='dbo' 126: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'CH_Name') 127: BEGIN 128: ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [CH_Name] 129: END 130: 131: --=============================== 132: -- Drop a column's Default value constraint 133: --=============================== 134: DECLARE @ConstraintName VARCHAR(100) 135: SET @ConstraintName = (SELECT TOP 1 s.name FROM sys.sysobjects s JOIN sys.syscolumns c ON s.parent_obj=c.id 136: WHERE s.xtype='d' AND c.cdefault=s.id 137: AND parent_obj = OBJECT_ID('TableName') AND c.name ='ColumnName') 138: 139: IF @ConstraintName IS NOT NULL 140: BEGIN 141: EXEC ('ALTER TABLE [dbo].[TableName] DROP CONSTRAINT ' + @ConstraintName) 142: END 143: 144: --=============================== 145: -- Example of how to drop dynamically named Unique constraint 146: --=============================== 147: DECLARE @ConstraintName VARCHAR(100) 148: SET @ConstraintName = (SELECT TOP 1 CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS 149: WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' 150: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME LIKE 'FirstPartOfConstraintName%') 151: 152: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' 153: AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = @ConstraintName) 154: BEGIN 155: EXEC ('ALTER TABLE [dbo].[TableName] DROP CONSTRAINT ' + @ConstraintName) 156: END 157: 158: --=============================== 159: -- Check for and drop a temp table 160: --=============================== 161: IF OBJECT_ID('tempdb..#TableName') IS NOT NULL DROP TABLE #TableName 162: 163: --=============================== 164: -- Drop a stored procedure 165: --=============================== 166: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.ROUTINES WHERE ROUTINE_TYPE='PROCEDURE' AND ROUTINE_SCHEMA='dbo' AND 167: ROUTINE_NAME = 'StoredProcedureName') 168: BEGIN 169: DROP PROCEDURE [dbo].[StoredProcedureName] 170: END 171: 172: --=============================== 173: -- Drop a UDF 174: --=============================== 175: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.ROUTINES WHERE ROUTINE_TYPE='FUNCTION' AND ROUTINE_SCHEMA='dbo' AND 176: ROUTINE_NAME = 'UDFName') 177: BEGIN 178: DROP FUNCTION [dbo].[UDFName] 179: END 180: 181: --=============================== 182: -- Drop an Index 183: --=============================== 184: IF EXISTS (SELECT * FROM SYS.INDEXES WHERE name = 'IndexName') 185: BEGIN 186: DROP INDEX TableName.IndexName 187: END 188: 189: --=============================== 190: -- Drop a Schema 191: --=============================== 192: IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.SCHEMATA WHERE SCHEMA_NAME = 'SchemaName') 193: BEGIN 194: EXEC('DROP SCHEMA SchemaName') 195: END And here’s the same code, just not in the little code view window so that you don’t have to scroll it.--=============================== -- Create a new table and add keys and constraints --=============================== IF NOT EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME = 'TableName' AND TABLE_SCHEMA='dbo') BEGIN CREATE TABLE [dbo].[TableName]  ( [ColumnName1] INT NOT NULL, -- To have a field auto-increment add IDENTITY(1,1) [ColumnName2] INT NULL, [ColumnName3] VARCHAR(30) NOT NULL DEFAULT('') ) -- Add the table's primary key ALTER TABLE [dbo].[TableName] ADD CONSTRAINT [PK_TableName] PRIMARY KEY NONCLUSTERED ( [ColumnName1],  [ColumnName2] ) -- Add a foreign key constraint ALTER TABLE [dbo].[TableName] WITH CHECK ADD CONSTRAINT [FK_Name] FOREIGN KEY ( [ColumnName1],  [ColumnName2] ) REFERENCES [dbo].[Table2Name]  ( [OtherColumnName1],  [OtherColumnName2] ) -- Add indexes on columns that are often used for retrieval CREATE INDEX IN_ColumnNames ON [dbo].[TableName] ( [ColumnName2], [ColumnName3] ) -- Add a check constraint ALTER TABLE [dbo].[TableName] WITH CHECK ADD CONSTRAINT [CH_Name] CHECK (([ColumnName] >= 0.0000)) END --=============================== -- Add a new column to an existing table --=============================== IF NOT EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS where TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND COLUMN_NAME = 'ColumnName') BEGIN ALTER TABLE [dbo].[TableName] ADD [ColumnName] INT NOT NULL DEFAULT(0) -- Add a description extended property to the column to specify what its purpose is. EXEC sys.sp_addextendedproperty @name=N'MS_Description',  @value = N'Add column comments here, describing what this column is for.' ,  @level0type=N'SCHEMA',@level0name=N'dbo', @level1type=N'TABLE', @level1name = N'TableName', @level2type=N'COLUMN', @level2name = N'ColumnName' END --=============================== -- Drop a table --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME = 'TableName' AND TABLE_SCHEMA='dbo') BEGIN DROP TABLE [dbo].[TableName] END --=============================== -- Drop a view --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.VIEWS WHERE TABLE_NAME = 'ViewName' AND TABLE_SCHEMA='dbo') BEGIN DROP VIEW [dbo].[ViewName] END --=============================== -- Drop a column --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.COLUMNS where TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND COLUMN_NAME = 'ColumnName') BEGIN -- If the column has an extended property, drop it first. IF EXISTS (SELECT * FROM sys.fn_listExtendedProperty(N'MS_Description', N'SCHEMA', N'dbo', N'Table', N'TableName', N'COLUMN', N'ColumnName') BEGIN EXEC sys.sp_dropextendedproperty @name=N'MS_Description',  @level0type=N'SCHEMA',@level0name=N'dbo', @level1type=N'TABLE', @level1name = N'TableName', @level2type=N'COLUMN', @level2name = N'ColumnName' END ALTER TABLE [dbo].[TableName] DROP COLUMN [ColumnName] END --=============================== -- Drop Primary key constraint --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='PRIMARY KEY' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'PK_Name') BEGIN ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [PK_Name] END --=============================== -- Drop Foreign key constraint --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='FOREIGN KEY' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'FK_Name') BEGIN ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [FK_Name] END --=============================== -- Drop Unique key constraint --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'UNI_Name') BEGIN ALTER TABLE [dbo].[TableNames] DROP CONSTRAINT [UNI_Name] END --=============================== -- Drop Check constraint --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='CHECK' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = 'CH_Name') BEGIN ALTER TABLE [dbo].[TableName] DROP CONSTRAINT [CH_Name] END --=============================== -- Drop a column's Default value constraint --=============================== DECLARE @ConstraintName VARCHAR(100) SET @ConstraintName = (SELECT TOP 1 s.name FROM sys.sysobjects s JOIN sys.syscolumns c ON s.parent_obj=c.id WHERE s.xtype='d' AND c.cdefault=s.id  AND parent_obj = OBJECT_ID('TableName') AND c.name ='ColumnName') IF @ConstraintName IS NOT NULL BEGIN EXEC ('ALTER TABLE [dbo].[TableName] DROP CONSTRAINT ' + @ConstraintName) END --=============================== -- Example of how to drop dynamically named Unique constraint --=============================== DECLARE @ConstraintName VARCHAR(100) SET @ConstraintName = (SELECT TOP 1 CONSTRAINT_NAME FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS  WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME LIKE 'FirstPartOfConstraintName%') IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE='UNIQUE' AND TABLE_SCHEMA='dbo' AND TABLE_NAME = 'TableName' AND CONSTRAINT_NAME = @ConstraintName) BEGIN EXEC ('ALTER TABLE [dbo].[TableName] DROP CONSTRAINT ' + @ConstraintName) END --=============================== -- Check for and drop a temp table --=============================== IF OBJECT_ID('tempdb..#TableName') IS NOT NULL DROP TABLE #TableName --=============================== -- Drop a stored procedure --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.ROUTINES WHERE ROUTINE_TYPE='PROCEDURE' AND ROUTINE_SCHEMA='dbo' AND ROUTINE_NAME = 'StoredProcedureName') BEGIN DROP PROCEDURE [dbo].[StoredProcedureName] END --=============================== -- Drop a UDF --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.ROUTINES WHERE ROUTINE_TYPE='FUNCTION' AND ROUTINE_SCHEMA='dbo' AND  ROUTINE_NAME = 'UDFName') BEGIN DROP FUNCTION [dbo].[UDFName] END --=============================== -- Drop an Index --=============================== IF EXISTS (SELECT * FROM SYS.INDEXES WHERE name = 'IndexName') BEGIN DROP INDEX TableName.IndexName END --=============================== -- Drop a Schema --=============================== IF EXISTS (SELECT * FROM INFORMATION_SCHEMA.SCHEMATA WHERE SCHEMA_NAME = 'SchemaName') BEGIN EXEC('DROP SCHEMA SchemaName') END

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  • Ways of marking a total match

    - by user331898
    I have two columns of matched data. One column contains the ID and the other column contains if there was a match(1) or no match(0) with that ID. There would be times when the all rows with the same ID will have all matched values of 1 and there would times where there were a mix of 0 and 1. I would like a third column to indicate where I have the same ID and all matched values are 1. Sample of what I have below column number and title of column: COLUMN 1: ID COLUMN 2: Match=1,No Match=0 1 1 1 0 2 1 2 1 3 0 3 0 3 1 This is what I would like: COLUMN # & TITLE COLUMN 1:ID COLUMN 2: Match=1, No Match=0 COLUMN 3: All ID Match & Match=1 1 1 N 1 0 N 2 1 Y 2 1 Y 3 0 N 3 0 N 3 1 N Is there a formula or way in excel 2010 that would make this possible? I would still like to keep the rows intact. Appreciate your help. Thank you in advance.

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  • *UPDATED* help with django and accented characters?

    - by Asinox
    Hi guys, i have a problem with my accented characters, Django admin save my data without encoding to something like "&aacute;" Example: if im trying a word like " Canción ", i would like to save in this way: Canci&oacute;n, and not Canción. im usign Sociable app: {% load sociable_tags %} {% get_sociable Facebook TwitThis Google MySpace del.icio.us YahooBuzz Live as sociable_links with url=object.get_absolute_url title=object.titulo %} {% for link in sociable_links %} <a href="{{ link.link }}"><img alt="{{ link.site }}" title="{{ link.site }}" src="{{ link.image }}" /></a> {% endfor %} But im getting error if my object.titulo (title of the article) have a accented word. aught KeyError while rendering: u'\xfa' Any idea ? i had in my SETTING: DEFAULT_CHARSET = 'utf-8' i had in my mysql database: utf8_general_ci COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\generic\date_based.py" in object_detail 366. response = HttpResponse(t.render(c), mimetype=mimetype) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 173. return self._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 125. return compiled_parent._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 62. result = block.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\sociable\templatetags\sociable_tags.py" in render 37. 'link': sociable.genlink(site, **self.values), File "C:\wamp\bin\Python26\lib\site-packages\sociable\sociable.py" in genlink 20. values['title'] = quote_plus(kwargs['title']) File "C:\wamp\bin\Python26\lib\urllib.py" in quote_plus 1228. s = quote(s, safe + ' ') File "C:\wamp\bin\Python26\lib\urllib.py" in quote 1222. res = map(safe_map.__getitem__, s) Exception Type: TemplateSyntaxError at /noticia/2010/jun/10/matan-domingo-paquete-en-la-avenida-san-vicente-de-paul/ Exception Value: Caught KeyError while rendering: u'\xfa' thanks, sorry with my English

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  • On which crowdsourced design site have you the best experience? (ie, crowdspring, mycroburst, etc)

    - by Darryl Hein
    I wasn't sure which site to ask this on (as Graphic Design hasn't reached beta yet), so I thought I would try here. I'm looking to have a couple logos and website designs done. I've had some great local designers, but each one has moved or gone else where so I keep having to look for new designers. My thought and realization in the last couple days is to go to a crowdsourced design site like crowdspring.com or mycroburst.com. Both of these sites look good, but I'm wondering what else is out there? Are there better ones and how have your experiences been them?

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  • 302 & 503 for temporary site down page: what to use for 'retry-after'?

    - by Miak
    If I want to temporary take down a website but the timeframe could be from 1 day to 1-2 weeks, I know that a 302 redirect (to a down.html page for instance) is best in order to preserve the existing SEO value of the site. I've also read that one should return a 503 status code for these types of situations but they seems to require setting a 'retry-after' time period. What If I don't know how long it will be down for? can I leave out this part of the header http://www.seomoz.org/blog/how-to-handle-downtime-during-site-maintenance

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